Design a single-stage common emitter amplifier with a voltage gain 40 dB that operates from a DC supply voltage of +12 V. Use a 2 N2222 transistor, voltage-divider bias, and 330Ω swamping resistor. The maximum input signal is 25mVrms.

Answers

Answer 1

In designing a single-stage common emitter amplifier, the following steps are to be followed;Choose the DC operating point.Set the voltage gain and estimate the collector resistance.

Set the input and output impedance.Set the coupling capacitor .Select the value of the bypass capacitor.The AC analysis of the amplifier circuitThe DC operating point is fixed by the choice of two biasing resistors R1 and R2 connected in a voltage divider network across the supply voltage. In this case, the DC operating point is +6V. Hence, R1 = 4.7 kΩ and R2 = 10 kΩ.

The voltage gain (Av) can be found using the formula Av = -RC/RE. Hence, Av = 40 dB, -100 = -RC/1000. RC = 10 kΩ.The input and output impedance are set to 1 kΩ and 4 kΩ, respectively. This is done by placing a 2.2 μF capacitor at the input side and a 10 μF capacitor at the output side. The coupling capacitor is selected based on the cutoff frequency. In this case, it is set to 16 Hz.

The bypass capacitor Cc is chosen to provide low-frequency amplification. In this case, the value of Cc is 22 μF.Finally, the AC analysis of the amplifier circuit is done by determining the voltage gain and input and output impedance of the circuit at the operating frequency.

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Related Questions

: Explain why testing can only detect the presence of errors, not their absence?

Answers

Answer:

The goal of the software is to observe the software behavior to meet its requirement expectation. In software engineering, validating software might be harder since client's expectation may be vague or unclear.

Explanation:

Assume this attempted implementation of a lock: void init(lock_t∗mutex) \{ mutex-> flag=0; // 0 -> lock is available, 1 -> held \} void lock(lock_t∗mutex) \{ while (mutex->flag==1) mutex-> flag = 1 \} void unlock(lock_t *mutex) \{ mutex->flag=0\} Assume 5 threads are competing for this lock. How many threads can possibly acquire the lock? Note: More than one answer. a.1 b.2 c.3 d.4 e.5 Given the following command:prog1 < file1.txt ∣ prog 2 prog3 > file3.txt Please describe the FDs (file descriptors) for each of the programs.

Answers

In the case of the student question provided, we are asked to assume an attempted implementation of a lock and determine how many threads can possibly acquire the lock.

The implementation includes three functions: init(), lock(), and unlock(). The init() function initializes the lock to be available with a flag value of 0. The lock() function waits while the flag value is 1, indicating that the lock is currently held by another thread. The unlock() function sets the flag value back to 0, indicating that the lock is available againGiven that 5 threads are competing for the lock, it is possible for up to 4 threads to acquire the lock. The reason for this is that one thread can initialize the lock to be available (flag = 0), and then up to three additional threads can acquire the lock before the flag is set back to 0 by the first thread to release the lock.In the second part of the question, we are given a command (prog1 < file1.txt | prog2 prog3 > file3.txt) and asked to describe the file descriptors (FDs) for each of the programs. File descriptors are used by Unix-like operating systems to represent file-like objects such as input/output files, pipes, sockets, and devices.
In this command, prog1 is being run with input from file1.txt and its output is being piped to prog2. The file descriptor for file1.txt is 0 (standard input), and the file descriptor for the pipe is 1 (standard output). The output of prog2 is being piped to prog3, with the file descriptor for the input pipe being 0 and the file descriptor for the output pipe being 1. Finally, the output of prog3 is being redirected to file3.txt, with the file descriptor for the output file being 1. In summary, when answering questions on Brainly, it is important to be accurate, professional, and concise in your answers. This includes using the correct terminology and concepts related to the topic at hand, and avoiding irrelevant information or typos.

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In paragraph 23, the word magnate means —

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Answer:

Read the passage. Then, answer the questions about the metaphor in boldface in the text.

Lately, I've been so overwhelmed with school and sports. There was a time when I enjoyed going to classes and going to practice every afternoon. Now, everything is piling up and wearing me down. Thankfully, I get to see you every day. You are truly the sunshine of my life. Thank you for making me laugh when I'm feeling down.

What is the context of the passage?

What is being compared in the metaphor?

What is the meaning of the metaphor?

Explanation:

Design a 3-bit synchronous counter that counts odd numbers using J-K Flip-Flops? For example, the output
of your counter will be 001-->011-->101->111.
Given the following logic circuit below, you are asked to analyze the following clocked sequential circuit with
one input x, and two output bits (A and B)
a- write output equation with Qa and Qb
b- write the truth table for circuit with X=1 and X=0

Answers

a) The output equations can be given by:Qa = Q2'Q1Q0' + Q2'Q1'Q0Qb = Q2Q1'Q0' + Q2'Q1Q0.

b) The  truth table:  X Qa Qb 0 0 0 0 1 1 1 1 0 1 1 1 0 0 1 1

a )Output equations are the Boolean expressions that describe the state of each output of a sequential circuit in terms of its input and state at the previous clock.

The output equations for a 3-bit synchronous counter that counts odd numbers using J-K Flip-Flops are given below:

Q0 = J0'Q0'K0 + J0Q0'K0'Q1 = J1'Q1'K1 + J1Q1'K1'Q2 = J2'Q2'K2 + J2Q2'K2'Qa and Qb are two output bits, thus their output equations can be given by:Qa = Q2'Q1Q0' + Q2'Q1'Q0Qb = Q2Q1'Q0' + Q2'Q1Q0

b)The truth table of the given circuit with X = 1 and X = 0 can be represented in the form below:

X Qa Qb 0 0 0 0 1 1 1 1 0 1 1 1 0 0 1 1

The output Qa and Qb can be obtained using the above output equations and the respective values of Q2, Q1 and Q0.

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Determine the horsepower required to compress 1 lbm/min of ethylene oxide from 70 oF and 1 atm to 250 psia. The compressor has an efficiency of 75%. The molar heat capacity of ethylene oxide is given by Cp

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Complete Question:

Problem 8 Determine the horsepower required to compress 1 lbm/min of ethylene oxide from 70 °F and 1 atm to 250 psia. The compressor has an efficiency of 75%. The molar heat capacity of ethylene oxide is given by

C_p=10.03+0.0184T  C_p[=]Btu/lbmole- "F ; T[=] °F C,

Answer:

\(P'=0.377hp\)

Explanation:

From the question we are told that:

Initial Temperature T_1=70 F

Final Temperature \(T_2=250pisa =114.94F\)

Efficiency \(E=75\%=0.75\)

Generally the equation for Work-done  is mathematically given by

 \(W=\int C_pT\)

 \(W=10.03(114.94-70 )+0.0184((114.94)^2-70^2 )\)

 \(W=527.21btu/ibmole\)

 \(W=11.982btu/ibm\)

Generally the equation for Efficiency  is mathematically given by

 \(E=\frac{isotropic Power}{Actual P'}\)

 \(E=\frac{P}{P'}\)

Since

Isotropic Power

  \(P=0.0167*11.982btu/ibm\)

 \(P=0.2btu/s\)

Therefore

 \(P'=\frac{0.2}{0.75}\)

 \(P'=0266btu/s\)

Since

 \(1btu/s=1.4148hp\)

Therefore

 \(P'=0.377hp\)

4. When the ESC system senses oversteer,
A) the brake at the inner rear or front wheel is applied to neutralize the oversteering
B) the brake at the outer corner rear or front wheel is applied to neutralize the oversteering

Answers

I’m pretty sure the answer is b I’m not 100% but I think


Multiple Select
Two main types of research studies are

Answers

Answer:

1. observational

2. clinical trial

*3. meta analysis*

Explanation:

Hopefully this is correct but if its not I apoligize

What is the driving force behind evolving technology?
is the main factor that drives the evolution of technology.

Answers

Creativity and Innovation.

Communication, Innovativeness, knowledge, quality of the product, and motivation...

what's the best way to plan an organized​

Answers

Answer:

Get ready and comfortable.

List all of the tasks you need to accomplish over the next week. .

Next schedule everything.

Get a planner/calender.

Cut those tasks that do not fit into your

A test bar of nonferrous material has a diameter of 0.253 inches. Upon applying a tensile load, the sample exhibited 0.002 plastic strain at 3400 lb and the maximum load during testing was 6200 lb and occurred at an engineering strain of 0.65; and breaking occurred at 4400 lb. The sample diameter at fracture was measured to be 0.15 inches.

Required:
a. The yield strength of the material is :________
b. The UTS of the material is:________

Answers

Answer:

a. 67607.9psi

b. 123278.33

Explanation:

to get the yield strength of the material

= load/ cross sectional area

cross sectional area = π * 0.253²/4

= 0.0502927

The yield strenght

= 3400/0.0502927

= 67609.9 psi

b. the uts of the material

= maximum load/cross sectional area

= 6200/0.0502927

= 123278.33

Terminal 2 on a Potential Relay goes to _______ ?

Answers

Answer:

Terminal 2 on a potential relay typically goes to the start winding of a motor.

Explanation:

The potential relay is an electromechanical device used in some types of motors to provide a temporary boost to the starting torque. Terminal 2 is connected to the start winding to assist in starting the motor.

(b) Briefly explain how the following three (3) technological advancements, have revolutionized the field of Mechanical Engineering by mentioning the deviations from the traditional practices. Computer Aided Design (CAD), i) ii) 3D printing and iii) Simulation​

Answers

Here’s a brief explanation of how these three technological advancements have revolutionized the field of Mechanical Engineering.

What is the explanation for the above response?

Computer Assisted Design (CAD): One of the most widely utilized software design tools is CAD. It is used by engineers and designers to model, validate, and convey ideas prior to production. CAD software models are frequently utilized as inputs to various mechanical engineering and design tools1.

ii) 3D printing: Extra tools for producing goods on a CNC machine or 3D printer are available and are occasionally incorporated into the CAD program. This has enabled quick prototyping and the creation of complicated geometries that were previously impossible with typical manufacturing methods1.

iii) Simulation: Computer-Aided Engineering (CAE) encompasses a wide variety of studies. Before building physical prototypes, it conducts complicated tasks like as finite element analysis (FEA) and computational fluid dynamics (CFD).

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A retail business, owned by share holders and having centralized decision making for their multiple store locations is called:

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the answer is home depot because it’s affordable

. Sucralose (the ingredient in Splenda) is a zero calorie artificial sweetener and sugar substitute that has been accepted as safe by the US Food and Drug Administration (FDA) and the European Union's Scientific Committee on Food. Sucralose readily dissolves in water to form an aqueous solution. Sucralose has a chemical formula of C
12

H
19

Cl
3

O
8

and a molar mass of 397.64 g/mol. Water has a chemical formula of H
2

O, a molar mass of 18.015 g/mol, and a density of 1.00 g/mL. If the mass of one "yellow packet" of Splenda, containing 12mg sucralose, is dissolved in 8 oz of water (equivalent to 236.6 mL water), calculate the concentration of sucralose in the aqueous solution (total volume of 236.9 mL ) in each of the below indicated units of concentration. Molarity (in units of millimolar or mM ): Molality (in units of molality, or m ): Mass percentage (in units of \%): Parts per million (in units of ppm): Parts per billion (in units of ppb):

Answers

The concentration of sucralose in the aqueous solution, after dissolving one "yellow packet" of Splenda (12mg sucralose) in 8 oz of water (236.6 mL), can be calculated as follows:

a) Molarity: 0.394 mM (millimolar)

b) Molality: 5.07 m (molality)

c) Mass percentage: 0.0506%

d) Parts per million (ppm): 50.6 ppm

e) Parts per billion (ppb): 50,600 ppb

To calculate the concentration of sucralose in the aqueous solution, we need to consider the mass of sucralose and the volume of the solution. The mass of one "yellow packet" of Splenda is given as 12mg. We dissolve this amount of sucralose in 236.6 mL of water, which is equivalent to 236.6 grams (since the density of water is 1.00 g/mL).

a) Molarity is calculated by dividing the moles of solute (sucralose) by the volume of the solution in liters. In this case, we convert the mass of sucralose to moles and divide it by the total volume of the solution in liters (236.6 mL converted to 0.2366 L), giving us a molarity of 0.394 mM.

b) Molality is calculated by dividing the moles of solute by the mass of the solvent (water) in kilograms. In this case, we convert the mass of sucralose to moles and divide it by the mass of water in kilograms (236.6 grams converted to 0.2366 kg), resulting in a molality of 5.07 m.

c) Mass percentage is calculated by dividing the mass of sucralose by the mass of the solution and multiplying by 100. In this case, we divide the mass of sucralose (12mg) by the total mass of the solution (12mg + 236.6g) and multiply by 100, giving us a mass percentage of 0.0506%.

d) Parts per million (ppm) represents the number of parts of sucralose per million parts of the solution. To calculate this, we divide the mass of sucralose (12mg) by the mass of the solution (12mg + 236.6g) and multiply by 1,000,000, resulting in a value of 50.6 ppm.

e) Parts per billion (ppb) represents the number of parts of sucralose per billion parts of the solution. Similar to ppm, we divide the mass of sucralose (12mg) by the mass of the solution (12mg + 236.6g) and multiply by 1,000,000,000, giving us a value of 50,600 ppb.

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CE-3610
Design Basic
1. The building is to be designed according to the provisions for structural requirement for LRFD
for steel as set forth in ASCE 7/IBC.
2. Material Specifications:
2.1 Light weight Concrete floor over deck
2.2 ASTM A992 (Gr.50) for all W shape Beams, Girders and Columns
2.3 Braces HSS (ASTM A500) or W shapes (ASTM A992, Gr.50)
3. Dead Loads:
3.1 Roof:
3.1.1 Roofing Materials (Water Proofing etc.) = 4 psf
3.1.2 18" Gage deck= 3 psf
3.1.3 Light weight concrete 5 in thick
3.1.4 Framing & Fire proofing= 8 psf
3.1.5 Suspended ceiling= 4 psf
3.1.6 Mechanical & Electrical= 4 psf
3.1.7 Solar panels & assembly= 9 psf
3.2 Floor:
3.2.1 Tile including assembly= 9.5 psf
3.2.2 18" Gage deck
3.2.3 Light weight concrete 6 1/4 "= 3 psf
3.2.4 Framing & Fire proofing = 15 psf
3.1.5 Suspended ceiling= 5 psf
3.1.6 Mechanical & Electrical= 5 psf
3.3 Wall:
3.3.1 Parapets on roof (outer boundary only) = 25 psf (3.5 ft high)
3.3.2 Glazed walls (outer boundary only) = 18 psf (ground to roof level)
Floors require 2 hour fire rating.
Live Load considers partition loads as appropriate.
4. The deflection requirements are as follows:
4.1 L/360 due to live load deflection in all interior Beams and Girders
4.2 L/180 due to total load for all spandrel Beams and Girders
5. For Seismic design, the values of spectral response acceleration parameters for the given location should be found using the USGS website

Answers

The primary objective of this project is to design a building in accordance with the structural requirements for LRFD for steel as defined in ASCE 7/IBC. The building's materials are defined in the following terms:

Light-weight concrete flooring over deck with a thickness of 5 inches.
ASTM A992 (Gr.50) for all W shape Beams, Girders, and Columns.
HSS Braces (ASTM A500) or W shapes (ASTM A992, Gr.50).

Dead Loads: The building's dead load will be made up of a variety of elements, including:

Roof: Roofing Materials (Water Proofing, etc.) = 4 psf.

18" Gage deck = 3 psf.
Light-weight concrete 5 in thick.
Framing & Fire proofing = 8 psf.
Suspended ceiling = 4 psf.
Mechanical & Electrical = 4 psf.
Solar panels & assembly = 9 psf.

Floor: Tile including assembly = 9.5 psf.
18" Gage deck.
Light-weight concrete 6 1/4 "= 3 psf.
Framing & Fire proofing = 15 psf.
Suspended ceiling = 5 psf.
Mechanical & Electrical = 5 psf.

Wall: Parapets on roof (outer boundary only) = 25 psf (3.5 ft high).
Glazed walls (outer boundary only) = 18 psf (ground to roof level).

The live load of partitions is taken into consideration as appropriate. Flooring requires a two-hour fire rating. The following deflection requirements are in effect:
L/360 due to live load deflection in all interior Beams and Girders.

L/180 due to total load for all spandrel Beams and Girders.
the building's seismic design should consider the values of spectral response acceleration parameters for the given location, which can be found using the USGS website.

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what effect, if any, would a change in ambient temperature or air density have on gas turbine engine performance?

Answers

A change in ambient temperature or air density can have a significant effect on gas turbine engine performance. These factors influence the engine's efficiency, power output, and fuel consumption.


1)Firstly, an increase in ambient temperature causes a decrease in air density. As air density decreases, the mass of air entering the engine per unit time (mass flow rate) also decreases. This leads to a reduction in the engine's power output since less air is available for combustion with fuel. Conversely, a decrease in ambient temperature increases air density, resulting in a higher mass flow rate and increased power output.

2)Secondly, a change in ambient temperature affects the engine's thermal efficiency. Higher temperatures cause an increase in the temperature difference between the inlet air and the hot gases exiting the combustion chamber, which can lead to decreased thermal efficiency. Lower ambient temperatures, on the other hand, increase thermal efficiency as the temperature difference is greater.

3)Lastly, variations in air density can also affect fuel consumption. When air density is low, the engine requires more fuel to maintain a specific power output, leading to increased fuel consumption. Conversely, higher air density allows the engine to achieve the desired power output with less fuel, resulting in improved fuel efficiency.

4)In conclusion, changes in ambient temperature and air density significantly impact gas turbine engine performance by influencing power output, thermal efficiency, and fuel consumption. Understanding these effects is crucial for optimal engine operation and management.

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A series circuit has individual resistor values of 200 Ω, 86 Ω, 91 Ω, 180 Ω, and 150 Ω. What is the total resistance of the circuit?

Answers

Answer:

\(\boxed{R_T_s=707 \Omega}\)

Explanation:

The following formula gives the total resistance of a series circuit:

\(R_T_s=R_1+R_2+R_3...+R_n\)

Therefore:

\(R_T_s= 200+86+91+180+150 \\R_T_s=707 \Omega\)

\(\text{-B$\mathfrak{randon}$VN}\)

A traditional children's riddle concerns a farmer who is traveling with a sack of rye, a goose, and a mischievous dog. The farmer comes to a river that he must cross from east to west. A boat is available, but it only has room for the farmer and one of his possessions. If the farmer is not present, the goose will eat the rye or the dog will eat the goose. We wish to design a circuit to emulate the conditions of this riddle. A separate switch is provided for the farmer, the rye, the goose and the dog. Each switch has two states, depending on whether the corresponding object is on the east bank or the west bank of the river. The rules of play stipulate that no more than two switches be moved at a time and that the farmer must move (to row the boat) each time switch are moved. The switch for the farmer provides logic signal F, which is high if the farmer is on the east bank and low if he is on the west bank. Similar logic signals (G for the goose, D for the dog and R for the rye) are high if the coilresponding object is in the east bank and low if it is on the west bank. The logic signal A (Alarm), which is the output, is high any time the rye or the goose are in danger of being eaten. [15] i) Prepare the truth table listing all combinations of the input signals F, G, D and R. Also show the desired value of the output, A, for each row in the truth table. Hence determine the SOP and POS expressions from your table. ii)

Answers

i) Truth table listing all combinations of the input signals F, G, D and R:Given: Switch for the farmer provides logic signal F, which is high if the farmer is on the east bank and low if he is on the west bank. Similar logic signals (G for the goose, D for the dog, and R for the rye) are high if the corresponding object is in the east bank and low if it is on the west bank.

The logic signal A (Alarm), which is the output, is high any time the rye or the goose is in danger of being eaten.F  G  D  R  A0  0  0  0  00  0  0  1  10  0  1  0  10  1  0  0  10  1  1  0  10  1  1  1  1Now, the desired value of the output, A, for each row in the truth table is shown below: 0000 0001 0010 0100 1000 1111ii) SOP (Sum of Products) and POS (Product of Sums) expressions from the truth table:The sum of products (SOP) is A = F' G' D' R + F' G' D R' + F G' D' R' + F G' D R' + F G D' R'The product of sums (POS) is A = (F + G + D' + R')(F + G' + D + R')(F' + G + D + R')(F + G' + D' + R')(F + G + D' + R')Therefore, the SOP expression from the truth table is A = F' G' D' R + F' G' D R' + F G' D' R' + F G' D R' + F G D' R' and the POS expression from the truth table is A = (F + G + D' + R')(F + G' + D + R')(F' + G + D + R')(F + G' + D' + R')(F + G + D' + R').Explanation:This problem is related to the logic circuit that should be designed to replicate the conditions of a riddle that involves a farmer who has a sack of rye, a goose, and a mischievous dog. When the farmer comes across a river, he must cross it from east to west. A boat is available, but it only has space for the farmer and one of his possessions. If the farmer is not present, the goose will eat the rye or the dog will eat the goose. A circuit is required to replicate this riddle's conditions, with four switches provided for the farmer, the rye, the goose, and the dog.

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During this experiment, it was important to keep some parameters constant so we can compare the efficiency of different alcohols. Which one of the parameter was not constant?.

Answers

The purification of a wide range of materials involves the use of distillation, a significant commercial procedure.

The purification of a wide range of materials involves the use of distillation, a significant commercial procedure. However, it would definitely be helpful to clarify the terms that describe the procedure and related qualities before we start a discussion of distillation.

Although you may be familiar with several of these terms, you might not be aware of their precise definitions. Let's start by outlining the procedure for changing a material from its condensed phase to its gas phase. This process is known as sublimation for solids and vaporization for liquids. Both procedures call for heat.

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BurgerBay is a newcomer in the fast-food industry. With several restaurants scattered across the bay, the owner decides that it is time to invest in developing a database to help manage various aspect of the company. You have been hired to develop such database.
The following represents a description of the company and the various elements of the database.
One of the main components of BurgerBay are its restaurants. Each of them can be uniquely identified using individual Business License Number. With 20 restaurants scattered across the bay, it is essential to keep track of each restaurant address using street name, city, state and zip code. We also want to keep track of the size (square footage) of each restaurant.
BurgerBay realized that working with advertisement agencies is essential for marketing purposes and therefore requires each of its restaurant to work with one local advertisement agency. To avoid conflicts, restaurants do not work with more than a single advertisement agency at a time, but it is not unusual for an advertisement agency to work with multiple restaurants. BurgerBay wants to keep track of these advertisement agency, even if some of them do not work with any restaurant at the moment. They can be identified using a unique identification number and, for each of them, the company keeps data about their name, city, state, zip code and fixed contract fee.
Another important component of BurgerBay are its employees. Each of its restaurant requires several employees to run properly and it is not uncommon for some of the most experienced employees to work across multiple restaurants. For this reason, it is important for the company to keep track of the day, start time and end time that a given employee worked at a specific restaurant. Note that only currently working employees are kept in the database, with data about their unique employee number, employee name, and number of years employed.
1) Based on the information above:
a. List all the entities required in your database (1 pts) b. Provide a list of business rules you can derive. (3 pts)
2) Using the information given and the derived business rules, draw a Entity Relationship Diagram of your database. (8 pts)

Answers

Entities required in the database:Restaurant  Advertisement Agency Employee  b. Derived business rules:

Each restaurant can be uniquely identified by its Business License Number.

Each restaurant has an address consisting of street name, city, state, and zip code.

The size (square footage) of each restaurant needs to be tracked.

Each restaurant works with one local advertisement agency, and an advertisement agency can work with multiple restaurants.

Each advertisement agency can be uniquely identified by a unique identification number.

The advertisement agency's data includes name, city, state, zip code, and fixed contract fee.

Each employee works at a specific restaurant and can work across multiple restaurants.

The employee's data includes a unique employee number, employee name, and number of years employed.

The database only includes currently working employees.

For each employee working at a specific restaurant, the database stores the day, start time, and end time of their work.

(Note: The provided business rules are based on the given information and may be further refined or expanded based on specific requirements and constraints.)

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A heating system must maintain the interior of a building at TH = 20 °C when the outside temperature is TC = 2 °C. If the rate of heat transfer from the building through its walls and roof is 16.4 kW, determine the electrical power required, in kW, to heat the building using (a) electrical-resistance heating, (b) a heat pump whose coefficient of performance is 3.0, (c) a reversible heat pump operating between hot and cold reservoirs at 20 °C and 2 °C, respectively.

Answers

Answer:

a)\(Q_H=16.4kW\)

b) \(w=5.467\)

c)  \(w=1.2345\)

Explanation:

From the question we are told that:

Interior temperature \(TH = 20 °C\)

outside temperature is \(TC = 2 °C\)

Rate \(H=16.4kW\)

a)

Generally electric resistance heating is the heat transfer from interior building

Therefore

\(Q_H=R\)

\(Q_H=16.4kW\)

b)

COP =3

Generally the equation for coefficient of performance is mathematically given by

\(COP=\frac{Q_H}{w}\)

Therefore

\(w=\frac{Q_H}{COP}\)

\(w=16.4/3\)

\(w=5.467\)

c)

Generally the equation for coefficient of performance is mathematically given by

\(COP_r=\frac{TH}{TH-TC}\)

\(COP_r=\frac{20+273}{(20+273)-(2+273)}\)

\(COP_r=16.2\)

Therefore

\(w=1.2345\)

\(w=20/16.2\)

\(w=1.2345\)

PLSSSSS Help !!!!!!!!!!!. It's due today.
I will give brainliest to correct answer

PLSSSSS Help !!!!!!!!!!!. It's due today. I will give brainliest to correct answer

Answers

Answer:

b

Explanation:

Answer:

b

Explanation:

what is the part of a drill that holds the drill bit in place is called the ?

Answers

The part of a drill that holds the drill bit in place is called the chuck.

The chuck is a key component of a drill, as it securely holds the drill bit in place during operation. It is typically located at the end of the drill, and can be opened and closed to insert or remove the drill bit.

The chuck is usually operated by either a key or a lever, depending on the type of drill. It is important to make sure that the chuck is properly tightened when the drill bit is inserted, as this will ensure that the bit is secure and will not slip or come loose during drilling.

Additionally, it is important to make sure that the bit is compatible with the size of the chuck, as an improper fit could cause the bit to become stuck or damaged.

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1. A thin-walled cylindrical pressure vessel is capped at the end and is subjected to an internal pressure (p). The inside diameter of the vessel is 6 ft and the wall thickness is 1.5 inch. The vessel is made of steel with tensile yield strength and compressive yield strength of 36 ksi. Determine the internal pressure required to initiate yielding according to (a) The maximum-shear-stress theory of failure, and (b) The maximum-distortion-energy theory of failure, if a factor of safety (FS) of 1.5 is desired.

Answers

I DONT KNOW OKAY UGHHH

Folds are an example of ________. Group of answer choices brittle deformation shear deformation elastic deformation ductile deformation

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Folds are an example of ductile deformation. Ductile deformation is a type of solid-state deformation that occurs when a material undergoes plastic deformation. It occurs at high temperatures and pressures. Folds are an example of ductile deformation because they result from the plastic deformation of rocks in response to compressional forces.

They form in areas where rocks are subjected to compressional stresses over a long period of time, causing them to bend and fold.The process of folding involves the bending of rocks into a series of curves or undulations. This occurs as a result of the plastic deformation of the rocks, which allows them to deform without breaking. Folds are classified based on their shape, size, and orientation. They can be symmetrical, asymmetrical, or overturned, and they can occur on a small or large scale.

Folds are an important geological feature because they provide clues about the history of the rocks and the tectonic forces that have acted on them. By studying the orientation and shape of folds, geologists can learn about the direction and intensity of the forces that caused them to form. This information can be used to reconstruct the geologic history of an area and to predict the behavior of rocks under different stress conditions.

In conclusion, folds are an example of ductile deformation, which is a type of solid-state deformation that occurs when a material undergoes plastic deformation. Folds form in response to compressional forces and are an important geological feature that provides clues about the history of the rocks and the tectonic forces that have acted on them.

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When an electron in a valence band is raised to a conduction band by sufficient light energy, semiconductors start conducting ________.

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Answer:

This band gap also allows semiconductors to convert light into electricity in photovoltaic cells and to emit light as LEDs when made into certain types of diodes. Both these processes rely on the energy absorbed or released by electrons moving between the conduction and valence bands.

Explanation:

On the internet

People tend to self-disclose to others that are in age, social status, religion, and personality.

Answers

Answer:people tend to do this when they are in a different environment they lose something or just have something going on in their life

Explanation:

At steady state, air at 200 kPa, 325 K, and mass flow rate
of 0.5 kg/s enters an insulated duct having differing inlet
and exit cross-sectional areas. The inlet cross-sectional area is
6 cm26cm
2. At the duct exit, the pressure of the air is 100 kPa and the velocity is 250 m/s. Neglecting potential energy
effects and modeling air as an ideal gas with constant cp=1.008 kJ/kg⋅Kc
p =1.008kJ/kg⋅K, determine
(a) the velocity of the air at the inlet, in m/s.
(b) the temperature of the air at the exit, in K.
(c) the exit cross-sectional area, in cm2
(a) the velocity of the air at the inlet, in m/s.
(b) the temperature of the air at the exit, in K.
(c) the exit cross-sectional area, in cm

Answers

Letra A

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Thank

A reinforced concrete column 600 mm diameter has 6 steel rods of 25 mm embedded in it and carries a load of 800 kN. Find the stresses in steel and concrete. Take E = 200GPa for steel and for concrete, E = 25 GPa. Also find the extension of column due to the load.

Answers

The stresses in steel and concrete are 1,631.29 MPa and 0.2535 MPa respectively.

The extension of column due to the load is 0.0017mm

How do we find the values of stresses?

To find the stresses in the steel and concrete, we need to use the principle of stress-strain proportionality. The formula for stress is:

Stress (σ) = Load (P) / Area (A)

The area of the steel rods is:

A = (π/4) * (25 mm)^2 = 490.87 mm^2

The area of the concrete is:

A = (π/4) * (600 mm)^2 = 314,159 mm^2

The stress in the steel is:

σ_steel = P / A = 800 kN / 490.87 mm^2 = 1,631.29 MPa

The stress in the concrete is:

σ_concrete = P / A = 800 kN / 314,159 mm^2 = 0.2535 MPa

To find the extension of the column, we need to use the formula for strain:

Strain (ε) = Extension (ΔL) / Original length (L)

We can use the principle of linear elasticity to find the extension of the column due to the load, which states that:

Stress = Young's modulus * Strain

We can use the formula of stress and strain to find the extension of the column:

ΔL = (PL)/(AE)

L = 600mm, P = 800kN and A =314,159 mm^2

ΔL = (80010^310^-360010^-3)/(314,1592510^9) = 0.0017 mm

So the extension of column due to the load is 0.0017mm

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Which part of a machine control unit interacts with the machine tools through electric signals?=]

A machine control unit is the electronic hardware that stores information and controls the machine tools. This unit contains a data processing unit that stores and manipulates data, and a ___________ that interacts with the machine tools through electrical signals.

Answers

Answer:

control loop unit

Explanation:

Edmentum/Plato

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