According to the question we have the angular velocity of link BC at the instant shown is 0.06 rad/s.
Given, Angular velocity of link AB, ωAB = 18 rad/s Angular velocity of link BC, ωBC = ?We know that,For link AB:ωAB = θ˙1For link BC:ωBC = θ˙2For link CD:ωCD = θ˙3 .
We know that, Velocity analysis by instantaneous center method for mechanism given below: Velocity of link AB = Velocity of link BC Relative velocity of links AB and BC is given by:VAB/BC = NCWhere, NC is the perpendicular from the instantaneous center to the path of link BC.
VAB/BC = rA/RBC∴ rAωAB = RBCωBCrA/RBC = L1/L2 = 75/150 = 0.5 ∴ rA = 0.5RBCThe link BC moves downwards. Therefore, the perpendicular to the link BC will be in the upward direction and the perpendicular to link AB will be in the downward direction. Angular velocity of link BC = ωBC= rAωAB/RBC= 0.5×18/150= 0.06 rad/s
Therefore, the angular velocity of link BC at the instant shown is 0.06 rad/s.
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On a hike you walk 5,000 m East, 3,000 m North, and 1,000 m West at a constant speed of 1 m/s. Calculate your velocity
your velocity during the journey is 5,000 m/s
The given parameters;
the initial position = 5,000 m Eastsecond position, = 3,000 m Northfinal position, = 1,000 m WestThe horizontal displacement = 5,000 m East - 1,000 m West = 4000 m
The vertical displacement = 3,000 m North
The resultant displacement is calculated as;
\(D^2 = 4000^2 + 3000^2\\\\D^2 = 25,000,000\\\\D = \sqrt{25,000,000} \\\\D = 5,000 \ m\)
The velocity is the change in displacement per change in time;
\(V = \frac{5000}{1} \\\\V = 5,000 \ m/s\)
Thus, your velocity during the journey is 5,000 m/s
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Considering the symmetry of the charge distribution, choose one of the following options as the most appropriate choice of Gaussian surface to use in this problem. A) a finite closed cylinder whose axis coincides with the axis of the rod and whose cross section has radius r0
B) a finite closed cylinder whose axis coincides with the axis of the rod and whose cross section has radius r1
C) a sphere of radius r
D) a finite closed cylinder whose axis coincides with the axis of the rod and whose cross section has radius r
E) an infinite cylinder whose axis coincides with the axis of the rod and whose cross section has radius r
One of the options that are the most appropriate choice of Gaussian surface to use in this problem is a finite closed cylinder whose axis coincides with the axis of the rod and whose cross section has radius r.
This is because the charged cylinder which is of infinite length as mentioned and hence there won't be any electric flux coming out of the top and bottom flat surfaces.
Now, to find out the magnitude of the electric field, we shall have to apply Gauss's law,
\(\int\limits^ _ {} \,\)Eda= Q enclosed/E
Gaussian surfaces would be the simplest to use to determine the electric field intensity near a long, straight, charged wire, is a cylinder whose axis coincides with the wire.
The Gaussian surface is primarily known as a closed surface in a three-dimensional space (3-D) such that the flux of a vector field is calculated.
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Set sampling period Ts=1/1000 (sec), and time axis 0 ~ 5 (sec).
Generate signals: x1(t)=10cos(ω1t); x2(t)=6sin(ω2t); x3(t)=cos(ω3t)+ 10sin(ω3t);
where ω1=50 Hz; ω2=95 Hz; ω3=120 Hz;
plot x1(t) within the maximum amplitude and time of 0~0.5 second,
Let y1(t)= x1(t)+ x2(t)+ x3(t), plot y1(t) within the maximum amplitude and time of 0~0.5 second.
ndicate the labels in x-axis and y-axis
The x-axis should be labeled with the time values in seconds from 0 to 0.5, and the y-axis should be labeled with the values of x1(t) ranging from -10 to 10, considering the maximum amplitude of the signal.
To plot the signal x1(t) within the time range of 0 to 0.5 seconds, we need to determine the corresponding values of x1(t) for that time range.
Given that x1(t) = 10cos(ω1t) with ω1 = 50 Hz, we can calculate the values of x1(t) using the formula.
For the time range of 0 to 0.5 seconds:
- At t = 0 seconds, x1(t) = 10cos(ω1 * 0) = 10cos(0) = 10 * 1 = 10.
- At t = 0.5 seconds, x1(t) = 10cos(ω1 * 0.5) = 10cos(25π) ≈ -7.071.
Plotting these values on the y-axis against the corresponding time values on the x-axis will give us the graph of x1(t) within the time range of 0 to 0.5 seconds.
The x-axis should be labeled with the time values in seconds from 0 to 0.5, and the y-axis should be labeled with the values of x1(t) ranging from -10 to 10, considering the maximum amplitude of the signal.
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The input preure on a hydraulic lift i 1200 Pa. If the output force on the other ide i 800 N, what i the output urface area?
A hydraulic lift's input pressure is 1200 Pa. If the output force on the other side is 800 N, the output surface area is 0.67m^2
Given the input pressure (P1) = 1200Pa
Output force (F2) = 800N
We know that P= F/A where A is area of cross section
Let the input force be F1 and area is A1
Then by pascals law we say that:
F1/A1 = F2/A2
1200 = 800/A2 (since P1= F1/A1)
A2 = 8/12 = 0.67m^2
Hence the area of other side = 0.67m^2
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What are 4 ways you can determine if a website is reliable?
Answer:
Identify the name of the individual, group or institution that created the website. A reliable website should clearly state the name of its creator. Generally, websites created by government institutions (.gov) and educational institutions (.edu) are considered more reliable.
If the skater has a mass of 55 kg and the maximum height the skater can reach is 10 m, then what will be the velocity of the skater if they skate down a height of 5 m? Ignore all friction and thermal energy and show all work
Answer:
10m/s
Explanation:
Data
mass=55kg, Maximum height (h1) =10m
Height reached when going down (h2)= 5m
final velocity (v)=?
At Maximum height the velocity is zero
hence intial velocity is 0m/s
The change in Potential energy = change in kinetic energy
mgh1-mgh2=1/2mv²-1/2mu²
But (u)= 0m/s
mgh2-mgh1=1/2mv²
mg(h1-h2)=1/2mv²
2g(h1-h2)=v²
v²=2(10m/s²)(10m-5m)
v²=100m²/s³
v=10m/s
Use the vocabulary in the Word Bank to complete the following explanation.
A small sports car collides head-on with a massive truck. The greater impact force (in magnitude) acts on? a) the car, b) the truck, c) neither, the force is the same on both
The greater impact force (in magnitude) acts on a) the car
Since , both the objects that is the car and a massive truck is coming and colliding with a certain speed , which means they are acquiring some momentum because of mass and speed , since they are coming with certain momentum when collided must have impacted each other.
Momentum is the measure of product of mass and velocity , if both of them are coming with same velocity then total dependency of impact will be on their masses , since truck is massive and car is small sports car , that means truck must have greater mass than the car , hence the greater impact force act on a) the car
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what recreational benefits did you get out of doing the task
How did the Japanese Tsunami (2011) happen and explain why it did happen?
just ask safari
Explanation:
A spring scale shows a net force of 0. 8 n acting on a 1. 5-kg mass. What happens to the acceleration of the object if the net force is decreased to 0. 2 n?.
A spring scale shows a net force of 0. 8 n acting on a 1. 5-kg mass, here the acceleration of the object if the net force is decreased to 0.2N. The acceleration of the object if the net force is decreased is 0.13 m/s².
Given data to find the acceleration,
A net force of 0.8 N acting on a 1.5-kg mass.
The net force is decreased to 0.2 N
What is Newton's second law?The second law says that the acceleration of an object is related to the net force applied in the object divided by the mass of the object.
This can be written as:
F = m*a
Where F is force, m is mass of the object and a is the acceleration of the object.
Here, the mass used in state 1 and 2 remains the same, at 1.5 kg
In the state 1 ,
ΣF=0.8 N
m=1.5 kg
The acceleration, a:
a =∑F/m
= 0.8 /1.5
= 0.53 m/s².
In the state 2,
ΣF=0.2 N
m=1.5 kg
The acceleration, a:
a =∑F/m
= 0.2 /1.5
= 0.13 m/s².
The acceleration of the object if the net force is decreased to 0. 2 n is 0.13m/s².
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A 51 cm diameter wheel accelerates uniformly about its center from 150 rpm to 290 rpm in 4.0 s. (A)Determine the radial component of the linear acceleration of a point on the edge of the wheel 1.1 s after it has started accelerating.
Radial component of the linear acceleration = 99.47 m/s^2
Explanations:The diameter of the wheel, d = 51 cm
The radius, r = d/2 = 51/2 = 25.5 cm
r = 25.5/100 = 0.255 m
r = 0.255 m
\(\begin{gathered} N_{i\text{ }}=\text{ 150 rpm} \\ w_i=\text{ 150}\times\frac{2\pi}{60} \\ w_i=\text{ }15.71\text{ rad/s} \end{gathered}\)\(\begin{gathered} N_f=\text{ 290 rpm} \\ w_f=\text{ 290}\times\frac{2\pi}{60} \\ w_f=\text{ }30.37\text{ rad/s} \end{gathered}\)\(\begin{gathered} w_f=w_i+\alpha t \\ 30.37=15.71+4\alpha \\ 4\alpha=30.37-15.71 \\ 4\alpha=\text{ }14.66 \\ \alpha=\frac{14.66}{4} \\ \alpha\text{ = }3.67rad/s^2 \end{gathered}\)At t = 1.1, first calculate the new angular velocity
\(\begin{gathered} w=w_1+\alpha t \\ w\text{ = 15.71+3.67(1.1)} \\ w\text{ = 15.71+}4.04 \\ w\text{ = }19.75\text{ rad/s} \end{gathered}\)The radial component of the linear acceleration is given as:
\(\begin{gathered} a_r=w^2r \\ a_r=19.75^2\times0.255 \\ a_r=\text{ }99.47\text{ m/}s^2 \end{gathered}\)A car is going on a flat road (meaning the road is horizontal) and is increasing speed. Assuming, as usal, that the car's velocity is in the x-direction and gravity is in the y-direction, which of the following is a true statement? The x-components of the individual forces add to zero while the y-components do not. The y-components of the individual forces add to zero while the x components do not. Both the x-components and the y-components of the individual forces add to zero. Neither the x-components nor the y components of the individual forces add to zero.
When a car is traveling on a flat road and is increasing speed, the correct statement is "The y-components of the individual forces add to zero while the x-components do not".
Since the road is horizontal, the force of gravity acting on the car will act vertically downward, i.e., in the y-direction, and the car's velocity will be horizontal, i.e., in the x-direction.
Since there are no other forces acting on the car other than gravity, the only force acting on the car is gravity.
Therefore, the y-components of the individual forces add up to zero while the x-components do not.
Hence the correct statement is: The y-components of the individual forces add to zero while the x-components do not.
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will an object have the same weight on moon as it does ?
Answer:
The mass of an object is the same everywhere either on earth or moon.
The weight of an object depends on a gravitational acceleration and it's different from one on earth and that on moon.
therefore the weight changes but the mass is the same.
Explanation:
Hope this helps
Two objects have the same kinetic energy, but the speed of object 1 is half
of object 2 speed, if object 1 mass is 12 kg, what is the mass of object 2?
Explanation:
The kinetic energy (KE) of an object is given by the formula KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity.
Let's call the mass of object 2 "M". We know that both objects have the same kinetic energy, so we can set up the equation:
1/2 * 12 kg * (v1)^2 = 1/2 * M * (v2)^2
where v1 is the velocity of object 1 and v2 is the velocity of object 2.
We also know that the speed of object 1 is half of object 2 speed, so v1 = 1/2 * v2. We can substitute this into the equation above and simplify:
1/2 * 12 kg * (1/2 * v2)^2 = 1/2 * M * v2^2
3 kg * (1/4 * v2^2) = 1/2 * M * v2^2
3/4 * M * v2^2 = 3 kg * 1/4 * v2^2
3/4 * M = 3 kg
M = 4 kg
Therefore, the mass of object 2 is 4 kg.
Which statement best describes an isolated system? (1 point)
Answer:
An isolated system is a single object that doesn't interact with any other objects. An isolated system has constantly changing energy. As a member, you'll also get unlimited access to over 79,000 lessons in math, English, science, history, and more.
Explanation:
An isolated system is a system in which the mass and energy are not allowed to escape.In open system, energy and mass can transfer and in closed system, only energy can transfer but the mass is conserved.
For an isolated system, the statement "total energy and mass are conserved" should be correct.
In an isolated system:total energy of the system is conserved or it doesn't change.The mass of the system remains constant or it doesn't change.Therefore, for an isolated system, the statement "total energy and mass are conserved" should be correct.
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Explain relation between work and energy
Answer:
Work is directly proportional to energy.
Explanation:
Work is said to be done when a body is displaced from one position to another. A force is required to make this displacement. This force applied is a kind of energy that is kinetic in nature. So when we displace an object by applying force, we are changing its kinetic energy to do the work.
This clarifies the relation between work and energy as :-Work Done = Change in Kinetic Energy.
Which situation provides the best evidence that a chemical reaction is taking place?
Help please !!!!
Answer:
A new product is formed
Explanation:
Physical reactions generally result in a change of state (solid, liquid, gas). Chemical reactions generally result in the production of a new product/ substance (structure/ properties are different than the intial reactants'... example= burning wood)
a carnot heat engine operates between a source at 1000 k and a sink at 300 k. if the heat engine is supplied with heat at a rate of 800 kj/min, determine (a) the thermal efficiency and (b) the power output of this heat engine. answers: (a) 70 percent, (b) 9.33 kw
The heat engine thermal efficiency is 70%, at which the engine has 9.33 kW of Power output.
What is heat engine?A heat engine refers to a device that converts heat into work. It absorbs heat from a tank, performs tasks such as moving a piston or lifting a weight, and finally releases thermal energy into a sink. So a heat engine can be defined as: A machine that converts the chemical energy of fuel into thermal energy used for useful work. Heat engines are classified into two types: Internal combustion engine and internal combustion engine. A heat engine can be defined as a device that converts heat energy into work.Thermal energy comes from the temperature difference provided by hot and cold reservoirs. Heat engines exploit this difference in their thermodynamic cycles.To learn more about heat engine from the given link :
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Which one is greater 2.62 , 2 2/5 , 26.8 , 2.26 , 271%.
In order to compare the numbers, let's put all of them into the decimal form:
\(\begin{gathered} 2.62 \\ \\ 2\frac{2}{5}=2+\frac{2}{5}=\frac{10}{5}+\frac{2}{5}=\frac{12}{5}=2.4 \\ \\ 26.8 \\ \\ 2.26 \\ \\ 271\text{\%}=\frac{271}{100}=2.71 \end{gathered}\)We can see that the greater one is 26.8 (all other numbers are close to 2, and this one is close to 27).
The numbers in decrescent order are:
26.8, 271%, 2.62, 2 2/5, 2.26.
Answer:
26.8
Explanation:
2.26 < 2.4 < 2.62 < 271/100 = 2.71 < 26.8
A car of 10 kg is moving at a speed of 5 m/s collides with a
stationary car of 25 kg. If the two cars lock together on impact,
what's the combined velocity of the two cars after the collision?
Explanation:
M1U1+m2u2 = (m1+m2)vf
m1= 10kg
u1=5
m2=25
u2=0
vf=?
10×5+25×0=35 vf
50+0=35Vf
Vf=1.4m/s
The function s(t) = 9 – 15t + 8t² describes the distance s from the origin at time t of an object in rectilinear motion. Find the velocity v of the object at any time t. (Use symbolic notation and fractions where needed.) v(t) = When is the object at rest? (Use symbolic notation and fractions where needed.) t = The function s(t) = 9 – 15t + 8t² describes the distance s from the origin at time t of an object in rectilinear motion. Find the velocity v of the object at any time t. (Use symbolic notation and fractions where needed.) v(t) = When is the object at rest? (Use symbolic notation and fractions where needed.) t =
At time t = 15/16, the object reaches a state of zero velocity, indicating a momentary pause in its motion. Prior to this time, the object moves in one direction, while after this time, it changes direction and moves in the opposite direction. The value t = 15/16 represents the specific moment when the object transitions from one direction to another and experiences a brief period of rest.
To find the velocity v(t) of the object at any time t, we differentiate the given distance function s(t) = 9 - 15t + 8t² with respect to time:
v(t) = d/dt (9 - 15t + 8t²)
Applying the power rule of differentiation, we obtain:
v(t) = -15 + 16t
Therefore, the velocity v(t) of the object at any time t is given by v(t) = -15 + 16t.
To determine when the object is at rest, we set the velocity v(t) equal to zero and solve for t:
-15 + 16t = 0
Adding 15 to both sides of the equation, we have:
16t = 15
Finally, dividing both sides by 16, we find
t = 15/16
Hence, the object is at rest when t = 15/16.
This means that at time t = 15/16, the object's velocity is zero, indicating that it is momentarily stationary. Before this time, the object is moving in one direction, and after this time, it is moving in the opposite direction. The value t = 15/16 represents the specific point in time when the direction of motion changes, and the object is at rest for an instant.
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what is the power of a student that has done a work of 10 joules in 10 seconds
Answer:
1 Watt
Explanation:
P=W/t
P=10/10
P=1 Watt
Usain Bolt accelerates at a rate of 3.7
m/s2 and his top speed is 12.7 m/s. How
long does it take for him to run the 100m
dash based on these numbers
Answer:
Explanation:
I think that you to run more than 12 miles
A concave lens creates a virtualimage at -47.0 cm with amagnification of +1.75. What isthe object distance?(Mind your minus signs.)(Unit = cm)
Object distance = 26.86 cm
Explanation:Given:
Image distance, v = -47.0 cm
Magnification, M = 1.75
Object distance, u = ?
\(\begin{gathered} M=\frac{|v|}{|u|} \\ \\ 1.75=\frac{47.0}{u} \\ \\ u=\frac{47.0}{1.75} \\ \\ u=26.86\text{ cm} \\ \end{gathered}\)Object distance = 26.86 cm
Why do rocks on the ocean floor form a patter of magnetized strpes?
Answer:
The striped magnetic pattern develops because, as the oceanic crust pulls apart, magma rises to the surface at mid-ocean ridges and spills out to create new bands of the ocean floor.
Explanation:
Answer:
The sea-floor spreading starts when the magma rises and erupts from the cracks along the mid-ocean ridges. Once the molten material solidifies, the older rock gets pushed away from the ridge and the new rock forms in the centre of the mid-ocean ridge. According to scientists, the Earth’s magnetic field is involved in this process. Since the oceanic crust contains iron, the way the rocks on the ocean floor hardened on both sides of the mid-ocean ridges are influenced by the direction of the magnetic field. As a result, it forms a pattern that resembles stripes that are alternately pointed north and south.
Or if you want a small answer:
The rock of the ocean floor contains iron. As molten material cools and hardens, the iron particles inside lines up in the direction of Earth's magnetic poles, creating a pattern of magnetized stripes.
Predict the product, if any, of reaction between methyl propanoate and aniline.
The product of the reaction between methyl propanoate and aniline is N-methylphenylpropanamide.
The reaction between methyl propanoate and aniline is a nucleophilic substitution reaction. Aniline is a nucleophile, which attacks the carbonyl group in methyl propanoate. The carbonyl group undergoes nucleophilic addition and an intermediate is formed. The intermediate is an imine. The imine is unstable and gets hydrolyzed immediately.
The hydrolysis of the imine intermediate gives N-methylphenylpropanamide. The hydrolysis of the imine is the addition of water to the imine. It is catalyzed by an acid or a base.
N-methylphenylpropanamide is the product formed as a result of the reaction between methyl propanoate and aniline.
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Hey you know these safety barriers you see on the freeway all the time? Explain the physics behind how the safety barriers help save lives during car accidents.
In the event of an accident or a car crash, road safety barriers and fences prevent automobiles from running off the road.
Which laws explain the physics behind the safety barriers and their use ?Newton's Three Laws of Physics can help explain what these safety barriers are and how they help to save lives during car accidents :
I. Unless acted upon by an imbalanced force, an object at rest will remain at rest, and an object at constant velocity will remain at constant velocity.
II. If an imbalanced force occurs, a mass will experience acceleration proportional to its magnitude.
III. When you apply a force to an object, you will feel a force that is equal in magnitude but opposite in direction.
What are the reasons for installing road safety barriers ?To protect and prevent out-of-control automobiles from entering other vehicles' lanes. As a result, the safety road barriers are installed in the middle of the road.To keep the automobiles from sliding down an incline. If there is a drop of 5 meters or more along the road, the road safety barriers should be put at one end of the road.To keep an out-of-control car from collapsing and colliding with a roadside obstacle. If there are numerous items along the road, such as large traffic signs, bridge piers, poles, and so on, safety road barriers should be built on one end of the road.Can learn more about safety barriers from https://brainly.com/question/17086354
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a traveler first drives 21.0 km east, then 28.8 km southeast, and finally 10 km south. what is the magnitude
The magnitude of the traveler's displacement is approximately 39.5 km.
To find the magnitude of the traveler's displacement, we can combine the individual displacements in a vector sum.
The first leg of the journey is a displacement of 21.0 km east. We can represent this as a vector in the positive x-direction: (21.0 km, 0 km).
The second leg of the journey is a displacement of 28.8 km southeast. We can break down this displacement into its x and y components. The southeast direction is a combination of east and south. The angle between the southeast direction and the positive x-axis is 45 degrees. Using trigonometry, we can find the x and y components:
x-component = 28.8 km * cos(45°) = 20.4 km
y-component = 28.8 km * sin(45°) = 20.4 km
So, the second displacement can be represented as a vector: (20.4 km, -20.4 km).
The third and final leg of the journey is a displacement of 10 km south. We can represent this as a vector in the negative y-direction: (0 km, -10 km).
To find the total displacement, we add the individual displacements:
(21.0 km, 0 km) + (20.4 km, -20.4 km) + (0 km, -10 km) = (41.4 km, -30.4 km)
The magnitude of the displacement is given by the Pythagorean theorem:
Magnitude = √((41.4 km)² + (-30.4 km)²) ≈ 39.5 km
Therefore, the magnitude of the traveler's displacement is approximately 39.5 km.
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what is the unit of destiny what are the basic unit involve in it