Determine the components of all forces acting on member ABCD when ? = 0. Take P = 110 lb. (Round the final answers to their nearest whole number.)
The components of all forces acting on member ABCD when ? = 0, are
A = lb ?
Bx = lb ?
By = lb ?
D = lb ?
C = lb ?

Answers

Answer 1

Without an accompanying diagram or image, it is difficult to provide a precise answer to this question.

However, it appears to be a problem involving the analysis of forces in a truss or a similar structure. To solve the problem, you would need to use the principles of statics and apply them to the given scenario.

In general, to determine the components of all forces acting on member ABCD, you would need to resolve the forces into their horizontal and vertical components.

This involves using trigonometry and the laws of physics to analyze the forces acting on the structure.

To calculate the specific values of the forces, you would need to know the angles and magnitudes of the various forces involved. Once you have these values, you can use trigonometric functions like sine and cosine to determine the horizontal and vertical components of each force.

Finally, you would add up all the components to determine the net force acting on member ABCD.

Again, without more specific information about the problem, it is difficult to provide a precise answer.

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Related Questions

An astronaut is 1.83 m tall. She is lying in a spaceship parallel to the direction of its motion at 0.9 c relative to the space station. What is her height as measured from the space station?

Answers

The astronaut's height, as measured from the space station, will appear contracted due to relativistic effects. Due to relativistic length contraction, the astronaut's height, as measured from the space station, appears to be approximately 3.52 meters.

According to the theory of special relativity, objects in motion relative to an observer will experience length contraction along the direction of motion. In this case, the spaceship is moving at a speed of 0.9 times the speed of light (0.9 c) relative to the space station.

The length contraction factor, denoted by γ, can be calculated using the Lorentz factor:

γ = 1 / √(1 - v²/c²)

Where v is the velocity of the spaceship and c is the speed of light. Plugging in the values, we have:

γ = 1 / √(1 - 0.9²)

γ ≈ 1.92

To determine the astronaut's height as measured from the space station, we multiply her actual height by the length contraction factor:

Height (as measured from the space station) = Actual height × γ

Height (as measured from the space station) = 1.83 m × 1.92

Height (as measured from the space station) ≈ 3.52 m

Therefore, due to relativistic length contraction, the astronaut's height, as measured from the space station, appears to be approximately 3.52 meters.

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If the displacement of a body is proportional to square of time state weather the body is moving with uniform velocity or uniform acceleration?​

Answers

Answer:

If the displacement of an object is proportional to the square of the time taken then the body is moving with uniformly accelerated motion as it will follow Newton's second equation of motion for a particular initial velocity, which can be given by, s=ut+21at2.

A pressure regulator must be connected to an oxygen cylinder to provide a safe working pressure of:_______.

Answers

A pressure regulator must be connected to an oxygen cylinder to provide a safe working pressure typically around 50 psi (pounds per square inch) or 3.5 bar.

This pressure is commonly used for various medical applications where controlled and precise oxygen delivery is required, ensuring the safety and well-being of the patient.

It's important to note that specific pressure requirements may vary depending on the specific use case and regulations in different regions or medical facilities.

Therefore, it is advisable to consult the manufacturer's guidelines and relevant safety standards to determine the appropriate working pressure for a particular oxygen cylinder and its intended application.

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If it is 2:00 AM at 90 East longitude, what time is it at 75 East longitude? 11. If it is 8:00 PM at 15 East, what time is it at 135 East longitude? 12. How many hours difference is there between 105 West longitude and the Prime Meridian? 13. If it is 9:30 AM in New York which is located 41 North Latitude, and 75 West Longitude, what t is it in Lima Peru which is located at 15 South latitude, and 75 West Longitude?
Previous question

Answers

11.The time at 75° East longitude would be 1 hour and 20 minutes behind. 12.The time at 135° degrees East longitude would be 4 hours ahead. and 13. the time in Lima, Peru (15° South latitude, 75° West longitude) would also be 9:30 AM.

At 2:00 AM at 90° East longitude, the time at 75° East longitude would be 1 hour and 20 minutes behind. This is because for every 15 degrees of longitude, there is a time difference of approximately 1 hour. Since the two longitudes in question have a difference of 15 degrees, we can divide this by 15 to calculate the time difference.

If it is 8:00 PM at 15° East longitude, the time at 135° East longitude would be 4 hours ahead. Similarly, for every 15 degrees of longitude, there is an approximate time difference of 1 hour. Since the two longitudes in question have a difference of 120 degrees, we can divide this by 15 to calculate the time difference.

There is a 7-hour difference** between 105° West longitude and the Prime Meridian (0° longitude). The Prime Meridian, passing through Greenwich, England, serves as the reference point for determining time zones. As one moves westward from the Prime Meridian, each 15 degrees of longitude corresponds to a time difference of approximately 1 hour. Therefore, the time at 105° West longitude would be 7 hours behind the time at the Prime Meridian.

If it is 9:30 AM in New York (41° North latitude, 75° West longitude), the time in Lima, Peru (15° South latitude, 75° West longitude) would also be 9:30 AM. The latitude does not affect the time difference between the two locations. However, since both locations have the same longitude (75° West), they would experience the same local time. The time difference between different latitudes is primarily significant for determining time zones rather than the actual time within a specific time zone.

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If an object starts accelerating from rest at a rate of 35 m/s2, then how far does it travel during the first second?

Answers

using s= 1/2 a t^2
s = 1/2 x 35 x 1 = 17.5 m

what is photosynthesis ?​

Answers

Answer:

Photosynthesis is the process by which plants use sunlight, water, and carbon dioxide to create oxygen and energy in the form of sugar.

Explanation:

Answer: Photosynthesis is something that a plant goes through. It takes the sunlight from the sun and turns it into oxygen, emitting it out into the atmosphere and giving us air to breathe.

Explanation:

Which of the below is an action-oriented objective in a SMART goal setting system?
A) Increase my running speed to an 8 1/2-minute mile pace.
B) Run on the trail 4 times a week.
C) Complete the Rock 'n Roll marathon next year.
D) Increase my distance by one-half mile every other week

Answers

The action-oriented objective in a SMART goal setting system is option D) Increase my distance by one-half mile every other week.

This objective is specific, measurable, achievable, relevant, and time-bound. It is specific because it defines a clear action to be taken (increasing distance), measurable because it includes a specific metric (one-half mile), achievable because it is realistic to increase distance gradually, relevant because it aligns with the goal of completing a marathon, and time-bound because it specifies a regular interval (every other week) for progress tracking. Options A, B, and C are also specific and measurable but lack the regular interval and gradual progression aspects of a SMART goal.


In a SMART goal setting system, an action-oriented objective is one that focuses on specific actions to achieve the desired outcome. Among the given options, B) Run on the trail 4 times a week is the most action-oriented objective. This objective clearly outlines the action (running on the trail) and the frequency (4 times a week), making it easier to track progress and achieve the goal. The other options focus more on outcomes or results, which are important aspects of a goal, but they do not explicitly state the specific actions needed to reach those outcomes.

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Give 3 examples of momentum used in everyday life.

Answers

Answer:

waking up,eat,sleep

Explanation:

notice how i didn't say math :)

Physics class, need hell

Physics class, need hell

Answers

Answer:

325.76 revolutions

Explanation:

The tire radius is diameter/2: 42/2 = 21

And now we can discover the lenght of the tire circumference. The lenght of a circumference is given by 2×radius×π, and let's consider π=3.14, and let's use the radius in meter (21 cm = 0.21 m):

2•0.21•3.14 = 1.32 m of lenght

Now, you divide the distance the car moved by the lenght of the tire circumference and you will find how many revolutions the tire makes:

420/1.32 = 325.76

Which questions would help determine whether an article is scientifically accurate? Group of answer choices Is the author stating an opinion or a fact? Does the author have evidence for the given facts? Does the author like music? How many articles has the author written before? Does the author have a balanced diet?

Answers

0.08 gram mass of magnesium oxide will be formed.

What is mass?

Mass is an intrinsic property in the mass of a body. It was the  traditionally believed to the  be related to the quantity of matters in the  physical body, until it is  discovery of the atom and  particle in physics.

Mass is quantitative measure of inertia a fundamental quantity of all matters.

2Mg + O 2→2MgO

Molar mass of Mg =24 g

Molar mass of MgO =40 g

No. of moles of O2=6.022×10^20/6.022×10^23

=0.001 mole of O2

No. of moles of Mg=0.486/24

=0.02 moles  of Mg

As moles of O 2

​ are less than 0.01, O 2

 is limiting reagent and it is  0.002 moles of MgO is formed.

⇒0.002×40=0.08 g of MgO

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What is the magnitude of the largest net force that can be produced by combining a force of 6.0 N
and a force of 8.0 N? What is the magnitude of the smallest such force?

Answers

Answer:

10N

Explanation:

The formula for calculating the resultant is expressed as;

R = √F1²+F2²

F1 and F2 are the forces

Given

F1 = 6.0N

F2 = 8.0N

R = √6²+8²

R = √36+64

R = √100

R = 10.0N

Hence the magnitude of the net force is 10N

What does a larger interquartile range mean.

Answers

IQR measures the spread of the middle half of your data. It is the range of the middle 50% of your sample
Larger values indicate that the central portion of your data spread out further.

A person of weight 600n at the bottom of a mountain climbs to the top. the gravitational field strength changes from 10.00n/kg at the bottom to 9.97n/kg at the top.his mass is unchanged as he climbs. what are his mass and his weight at the top of the mountain

Answers

At the summit of the mountain, the mass is 60.18 kg, the weight is 600 N, and the mass is unaltered.

What is Mass?Weight is the force of gravity acting on an item, whereas mass is the amount of matter that makes up the object. Weight varies from place to place yet mass is constant everywhere you are in the cosmos. Kilograms are used to measure mass.

Let the mass on earth be m.

Given, W= 600N, g= 9.97 N/kg(top of mountain)

As we know:

The formula for Weight = mass x acceleration due to gravity at place W=m*g

Now, calculate as follows:

m = W/g= 600*9.97mass = 60.18 kgW= m*g= 60.18 * 9.97= 600NWeight = 600N

Therefore, at the summit of the mountain, the mass is 60.18 kg, the weight is 600 N, and the mass is unaltered.

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Help! will give brainliest!

Help! will give brainliest!

Answers

Answer:

I would say increasing the balls kinetic energy

Explanation:

Because she is moving the ball and increasing kinetic energy

Now that you’ve verified that you know how to make a measurements from this video. Let’s analyze both carts. Use the roller and stopwatch to measure the velocity of each car for the first 30 cm of motion immediately after their hands are no longer in contact. 3. Calculate the momentum of Christine and her cart Asher rules immediately after they are no longer in contact. p=mv 4. Calculate the momentum of Deamon and his cart as he rules immediately after they are no longer in contact. 5. Calculate the total war mentum of the system comprising The two cards and the two people.

Data given: Christines cart has a mass of 60 kg Daemon cart has a mass of 66.5 kg The carts have a mass of 22 kg each The velocity closest to daemons cart is V= 1.2 m/s Measured with a ruler at 30 cm apart the time is 0.8875 s.

Answers

Christines Velocity = 30 cm / 0.8875 s = 33.8 cm/s.

What is Christines Velocity ?

Christine's velocity is the rate at which she moves through space. It is a measure of her speed and direction and is typically measured in meters per second. Velocity is a vector quantity, meaning it has both magnitude (or numerical value) and direction. Christine's velocity at any given moment is determined by her direction and speed of motion, and it can change if her speed or direction changes. Velocity can also be affected by external forces, such as gravity, friction, or air resistance. The magnitude of velocity is always positive, since it is a measure of speed and direction. If Christine's velocity is zero, then she is not moving at all.

2. Daemons Velocity = 30 cm / 0.8875 s = 33.8 cm/s

3. Christine's Momentum = 60 kg * 33.8 cm/s = 2,028 kg·cm/s

4. Daemons Momentum = 66.5 kg * 33.8 cm/s = 2,237.7 kg·cm/s

5. Total Momentum = (60 kg + 66.5 kg + 22 kg + 22 kg) * 33.8 cm/s = 4,322.7 kg·cm/s

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A 14 kg boulder is pushed off a cliff with velocity v = ( 14.0 m/s ) + ( 2.0m/s ) y . Will the object experience a larger vertical or horizontal acceleration?

Answers

The object will eventually experience a large vertical acceleration since the vertical velocity increases as the object moves downwards.

What is horizontal motion of a projectile?

The horizontal motion of a projectile is the motion of the projectile along a horizontal path.

The horizontal distance of a projectile is not affected by gravity and hence the horizontal speed of a projectile remains constant. That is the initial horizontal velocity is equal to the final horizontal velocity of the projectile.

However, the during the vertical motion an object, the vertical velocity decreases as the object moves upwards and eventual becomes zero when the object reaches the maximum height.

As the object begins to move downwards the vertical velocity increase and eventually become maximum before the object hits the ground.

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Please check if number 1 and a and b correct or not thx

Please check if number 1 and a and b correct or not thx

Answers

Number 1 and A are correct, but B is not correct

B ---> Distance = 1/2*(Velocity)*(Time)

Distance = 1/2(5s)*(-12m/s)

Distance = 5(s)*(-6m/s)

Distance = -30m

String and nylon thread will stretch when pulled with a moderate force, but only a small amount. if you apply the same force to a spring and it stretches much further than the string and thread, how do the spring constants of the string and thread compare to the spring?

Answers

The spring constants of the string and nylon thread are: higher compared to the spring, as they demonstrate greater resistance to stretching under the same applied force.


When a moderate force is applied, both string and nylon thread stretch but only a small amount, whereas a spring stretches much further. To compare their spring constants, we need to understand Hooke's Law, which states that the force applied is proportional to the displacement of the object (F = kx). Here, k is the spring constant and x is the displacement.

A higher spring constant (k) means that the object is more resistant to stretching, while a lower spring constant indicates that the object is more easily stretched. In this case, the string and nylon thread have higher spring constants compared to the spring since they stretch less under the same force. The spring, which stretches much further, has a lower spring constant.

In conclusion, the spring constants of the string and nylon thread are higher compared to the spring, as they demonstrate greater resistance to stretching under the same applied force. This is evident in the smaller displacements observed when pulling the string and thread compared to the more significant stretching of the spring.

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What is the use of a hydrometer​

Answers

Answer:

A hydrometer is an instrument used to determine specific gravity

Answer:

it is used determine specific gravity

Explanation:

and u can see them in use by measuring proof of moonshine

Pls give full explanation!

Pls give full explanation!

Answers

1. The part that shows the body is accelerating is the first 2 hours (ABE). The acceleration is 20 Km/h²

2. The part that shows the body is coming to rest the last 2 hours (CDF)

3. The distance travelled in the first 2 hours is 40 Km

1. How to determine the accelerated motion

Acceleration is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a is the acceleration v is the final velocity u is the initial velocity t is the time

From the diagram (ABE), we can see that the body starts from rest and attain a final velocity (40 Km/h) within the first 2 hours. This clearly indicates that the body is accelerating.

The acceleration can be obtained as followed:

Initial velocity (u) = 0 Km/hFinal velocity (v) = 40 Km/hTime (t) = 2 hoursAcceleration (a) = ?

a = (v – u) / t

a = (40 – 0) / 2

a = 20 Km/h²

2. How to determine the part showing the body is coming to rest

From the diagram (CDF), we can see that the object velocity changes from 40 to 0 within the last 2 hours. This clearly indicates that the object caming to rest.

3. How to determine the distance travelled in the first 2 hours Initial velocity (u) = 0 Km/hFinal velocity (v) = 40 Km/hTime (t) = 2 hoursAcceleration (a) = 20 Km/h²Distance (s) = ?

v² = u² + 2as

v² = 2as

s = v² / 2a

s = 40² / (2 × 20)

s = 40 Km

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A man stands in front of a vertical plane mirror which is fixed on a
wall as shown in the diagram below. The image formed by the
mirror is also shown.
The man looks at the image of his feet.
a. Complete the ray diagram to show how the man is able to see the
image of his feet in the mirror.
b. What is the purpose of the normal line in the diagram?
c. State which angle does x represent.
d. What's the type and direction of the image formed by the mirror?

A man stands in front of a vertical plane mirror which is fixed on awall as shown in the diagram below.

Answers

Answer:

a) ray horizontal and ray leaves his feet

b) The normal line respect to which the angles are measured,

c) The angle x is the reflected angle

d) virtual image,  right image

Explanation:

a) To complete the rays, you must draw a horizontal ray at the height of the man's head, this ray touches the mirror perpendicularly, therefore it bounces in the same direction.

The other ray leaves his feet and touches the mirror at one point, it is reflected with the same angle, by the law of reflection and reaches the eyes of man, the brain creates an extension of this ray and at the point of the floor creates the image point.

b) The normal line is a line perpendicular to the surface with respect to which the angles are measured,

c) The angle x is the reflected angle, which is equal to the incident angle according to the law of reflection

d) The image is formed by the prolongation of the rays of light, therefore it is a virtual image and as it has the same direction of the man it is a right image

A car with two passengers traveling at 15 m/s collides with a tree. One of the passengers who is not wearing a seat belt strikes the windshield head first and comes to rest in 0.03 s. The area of contact between the head and the windshield is approximately 5x10 m² and the mass of the head is 5.4 kg. The other passenger who is wearing his seat belt comes to rest in 0.50 s. The mass of this passenger is 75 kg. The area of the seat belt in contact with this passenger is about 0.12 m². Find the average force and the force per unit area exerted on the two passengers.

Answers

In the absence of friction, a force applied to a body for a given amount of time, changes the momentum of the body

The average force per unit area exerted on the passenger with no seatbelt 5,400,000 N/m²

The average force per unit area for the passenger with seat belt 18,750 N/m²

The known parameters are;

The velocity of the car, v₀ = 15 m/s

The time it takes the passenger not wearing seat belt to strike the windshield, \(t_{ns}\) = 0.03 s

Area of contact between the head and the windshield, \(A_{ns}\) = 5 × 10⁻⁴ m²

The mass of the head, \(m_{h}\) = 5.4 kg

Time taken for the passenger wearing seat belt to come to rest, \(t_s\) = 0.50 s

The mass of the passenger wearing seatbelt, \(m_s\) = 75 kg

Area of the seat belt in contact with the passenger, \(A_s\) = 0.12 m²

Required:

To find the average force per unit area exerted on the two passengers

Solution:

According to Newton's second law on motion, force is equal to the product of mass and acceleration

\(Acceleration, \overline a = \dfrac{Change \ in \ velocity}{Elapsed \ time} = \dfrac{v - v_0}{t}\)

Therefore, the acceleration, force and average force per unit area of the passenger with no seat belt;

\(Acceleration, \overline a_{ns} = \dfrac{0 - 15 \, m/s}{0.03 \, s} = 500 \, m/s^2\)

\(F_{ns}\) = \(m_{h}\) × \(\overline a_{ns}\)

Which gives;

\(F_{ns}\) = 5.4 kg × 500 m/s² = 2,700 N

Force per unit area = Force/Area

The average force per unit area, for the passenger with no seat belt is given as follows:

\(P_{ns} = \dfrac{2,700 \, N}{5 \times 10 ^{-4} \ m^2} = 5,400,000 \ N/m^2\)

The average force per unit area exerted on the passenger with no seatbelt, \(P_{ns}\) = 5,400,000 N/m²

The acceleration, force and average force per unit area of the passenger with seat belt:

\(Acceleration, \overline a_{s} = \dfrac{0 - 15 \, m/s}{0.5 \, s} = 30 \, m/s^2\)

\(F_{s}\) = \(m_{b}\) × \(\overline a_{s}\)

Which gives;

\(F_{s}\) = 75 kg × 30 m/s² = 2,250 N

Force per unit area = Force/Area

The average force per unit area, for the passenger with seat belt is therefore;

\(P_{s} = \dfrac{2,250\, N}{0.12 \ m^2} = 18, 750\ N/m^2\)

The average force per unit area for the passenger with seat belt, \(P_s\) = 18,750 N/m²

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Kieran ran 8 laps of the track in 18 minutes. Jevon ran 6 laps of the track. Who had a greater average speed

Answers

Kieran had a greater average speed than Jevon. Let us go into more detail in the explanation below. To compare the average speeds of Kieran and Jevon, we need to find out the speed of each person.

We can use the formula speed = distance/time. Kieran ran 8 laps in 18 minutes, which means he ran 8/18 = 0.44 laps per minute. To find out Kieran's speed, we need to multiply this by the length of one lap. If we assume that the length of one lap is 400 meters, then Kieran's speed is:0.44 laps per minute × 400 meters per lap = 176 meters per minute Jevon ran 6 laps of the track, but we don't know how long it took him.

Therefore, we can't calculate his speed directly. However, we can still compare his speed to Kieran's by using ratios. If we assume that Jevon ran the same length of track as Kieran, then we can write the following equation: Kieran's speed/Jevon's speed = Jevon's time/Kieran's time.

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Ferris wheel has a diameter of 76 m and completed one revolution every 20 min.


a)Calculate the tangential speed the car


b) Calculate the magnitude to the centripetal acceleration of one of the car

Answers

The tangential speed of a point on the Ferris wheel is approximately 2.01 m/s.  the magnitude of the centripetal acceleration of a point on the Ferris wheel is approximately 0.106 m/s².

The tangential speed of a point on the Ferris wheel is given by the formula:

v = (2πr) / T

where v is the tangential speed, r is the radius of the Ferris wheel (half the diameter), and T is the time taken to complete one revolution.

In this case, the diameter of the Ferris wheel is 76 m, so its radius is 38 m. It completes one revolution every 20 min, so the time taken is T = 20 min = 1200 s. Substituting these values in the formula, we get:

v = (2π × 38 m) / 1200 s

≈ 2.01 m/s

The centripetal acceleration of a point on the Ferris wheel is given by the formula:

a = v² / r

where a is the magnitude of the centripetal acceleration, v is the tangential speed, and r is the radius of the Ferris wheel.

In this case, we have already calculated the tangential speed to be approximately 2.01 m/s, and the radius of the Ferris wheel is 38 m. Substituting these values in the formula, we get:

a = (2.01 m/s)² / 38 m

≈ 0.106 m/s²

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A person weighing 645 N climbs up a ladder to a height of 4.55 m what is the increase in gravitational energy

Answers

Answer: 2934.75 Joules

Explanation:

Potential energy can be defined as energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

P.E = mgh

Where P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per second square.

h represents the height measured in meters.

Given the following data;

Weight =645

Height = 4.55

P.E = mgh

But we know that weight = mg = 645N

Substituting into the equation, we have;

P.E = 645 • 4.55

P.E = 2934.75J

Potential energy, P.E = 2934.75 Joules.

How is the duration and intensity of daylight related to the suns apparent path?

Answers

Answer:

I dont know but ask a tutor

Explanation:

MOnkey Srry

What happens when you place a light source exactly at the focal point of a concave mirror

Answers

When a light source is placed exactly at the focal point of a concave mirror, the light rays emitted from the source become parallel after reflecting off the mirror.

What happens when you place a light source exactly at the focal point of a concave mirror

This phenomenon is known as collimation. The light rays converge towards the focal point upon reflection but, since the source is already at the focal point, the reflected rays become parallel to the mirror's principal axis.

This creates a beam of collimated light that can travel long distances without significant divergence. Precise positioning at the focal point is necessary for this effect to occur.

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In tae-kwon-do, a hand is slammed down onto a target at a speed of 10 m/s and comes to a stop during the 5.0 ms collision. Assume that during the impact the hand is independent of the arm and has a mass of 0.70 kg. What are the magnitudes of the (a) impulse and (b) average force on the hand from the target

Answers

a. Therefore, the magnitude of the impulse on the hand is 7.0 Ns.

b. Therefore, the magnitude of the average force on the hand from the target is 1400 N.

(a) The impulse on the hand is given by the change in momentum of the hand during the collision. Since the hand comes to a stop, its final momentum is zero. Therefore, the impulse is equal in magnitude to the initial momentum of the hand:

p = mv = (0.70 kg)(10 m/s) = 7.0 Ns

Therefore, the magnitude of the impulse on the hand is 7.0 Ns.

(b) The average force on the hand during the collision can be found by dividing the impulse by the duration of the collision:

F = Δp/Δt

here Δp is the change in momentum and Δt is the duration of the collision. The change in momentum is the same as the impulse, which we found in part (a):

Δp = 7.0 Ns

The duration of the collision is given as 5.0 ms, which we need to convert to seconds:

Δt = 5.0 x \(10^{-3} s\)

Substituting these values into the formula for average force, we get:

F = (7.0 Ns)/(5.0 x \(10^{-3} s\) ) = 1400 N

Therefore, the magnitude of the average force on the hand from the target is 1400 N.

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Why fossil fuel has been used more in the existing world? ​

Answers

Answer:

Fossil fuels are of great importance because they can be burned (oxidized to carbon dioxide and water), producing significant amounts of energy per unit mass. The use of coal as a fuel predates recorded history. Coal was used to run furnaces for the smelting of metal ore.

if the combined force f1 the mass i m, and the accleration is a, write a mathmatical relationship that relates these three

Answers

The mathematical relationship that relates the combined force (F1), mass (m), and acceleration (a) is Newton's second law of motion. This law states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. The formula for this relationship is:
F1 = m * a

In this equation, F1 represents the combined force acting on the object, m represents the mass of the object, and a represents the acceleration of the object. This law is fundamental in classical mechanics and is used to describe the motion of objects under various forces.

When a force is applied to an object, it causes the object to accelerate. The larger the mass of the object, the more force is required to achieve the same acceleration. Similarly, the greater the force applied, the more the object will accelerate. This relationship helps us understand how forces and masses affect the motion of objects in the physical world.

In conclusion, Newton's second law of motion establishes a mathematical relationship between the combined force, mass, and acceleration of an object. By using the formula F1 = m * a, you can calculate the force acting on an object or the resulting acceleration when you know the mass and the applied force. This law plays a crucial role in understanding and predicting the motion of objects in various scenarios.

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