The domain of the given function is {2, 29, 44, 54} and the range is {-7, 2, 4}.
What are the domain and range of functions?The domain of a function represents the set of input values to the function and the range of a function represents the set of output values for the domain of the function.
Domain - {x coordinates of the points in a function}
Range - {y coordinates of the point in a function}
Calculation:The given function is
f = {(2, 4), (29, -7), (44, 4), (54, 2)}
So, the x coordinates of the function are formulated in a set as {2, 29, 44, 54} and the y coordinates are {-7, 2, 4}
Where output 4 is repeated.
Then, the domain of the function is given by the set {2, 29, 44, 54} and the range of the function is given by the set {-7, 2, 4}.
The mapping of the given function is shown in the figure below.
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                                                Look at this graph:
y
x
1
2
3
4
5
6
7
8
9
10
1
2
3
4
5
6
7
8
9
10
0
What is the slope?
Simplify your answer and write it as a proper fraction, improper fraction, or integer.
The slope of the line on this graph is equal to 1/4.
How to calculate the slope of a line?In Mathematics, the slope of any straight line can be determined by using the following mathematical equation;
Slope (m) = (Change in y-axis, Δy)/(Change in x-axis, Δx)
Slope (m) = rise/run
Slope (m) = (y₂ - y₁)/(x₂ - x₁)
Substituting the given data points into the slope formula, we have the following;
Slope (m) = (50 - 30)/(90 - 10)
Slope (m) = 20/80
Slope (m) = 1/4.
In this context, we can reasonably infer and logically deduce that the slope of the line on this graph is equal to 0.25 or 1/4.
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                                                            13 What is the value of x? х Enter your answer in the box. 12 X =
Answer:
x is the value of 12
Step-by-step explanation:
erfg
 
                                                            Evaluate the following integral using integration by parts. 4 sin-1 4 sin - ¹2x dx [4 sin -¹2x dx =
The complete solution is:
∫4\(sin^{-1}(2x) dx = sin^{-1}(2x)\) x 4x + √(1 - (2x)²) + C, where C is the constant of integration.
We have,
\(u = sin^{-1)}(2x)\)
dv = 4 dx
Taking the derivative of u, we get:
du/dx = 1 / √(1 - (2x)²)
Integrating dv, we get:
v = ∫4 dx = 4x
Now, applying the integration by parts formula:
∫4 \(sin^{-1}(2x) dx\) = uv - ∫vdu
Plugging in the values, we have:
∫4 \(sin^{-})(2x) dx = sin^{-1}(2x) \times\) 4x - ∫(4x / √(1 - (2x)²)) dx
At this point, we need to evaluate the integral on the right side.
Let's perform a substitution to simplify it:
Let u = 1 - (2x)²
Differentiating u with respect to x, we get:
du/dx = -4(2x) = -8x
Solving for dx, we have:
dx = -du / (8x)
Substituting these values, the integral becomes:
∫(4x / √(1 - (2x)²)) dx = ∫(-4x / (8x x √u)) (-du / (8x))
Simplifying, we get:
∫(4x / √(1 - (2x)²)) dx = ∫(-1 / (2√u)) du
= -∫(1 / (2√u)) du
= -√u + C
Substituting back the value of u, we have:
∫(4x / √(1 - (2x)²)) dx = -√(1 - (2x)²) + C
Therefore,
The complete solution is:
∫4\(sin^{-1}(2x) dx = sin^{-1}(2x)\) x 4x + √(1 - (2x)²) + C, where C is the constant of integration.
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The complete question:
a) Evaluate the integral ∫4 sin^(-1)(2x) dx using integration by parts.
find three different vectors that are in the span of the given vectors.
u1 = [-3] ,   u2=[-5]
        [8]            [ 6]
Three different vectors are [-8, 14], [-6, 16], and [15, -18].
To find three different vectors that are in the span of the given vectors \(u_1\) = [-3, 8] and \(u_2\) = [-5, 6], we can use linear combinations of these vectors.
Let's call the three different vectors \(v_1\), \(v_2\), and \(v_3\). We can express them as follows:
\(v_1\) = \(u_1\) + \(u_2\) = [-3, 8] + [-5, 6] = [-3 + (-5), 8 + 6] = [-8, 14]
\(v_2\) = 2\(u_1\) = 2[-3, 8] = [-6, 16]
\(v_3\) = -3\(u_2\) = -3[-5, 6] = [15, -18]
Therefore, three different vectors that are in the span of \(u_1\) and \(u_2\) are \(v_1\) = [-8, 14], \(v_2\) = [-6, 16], and \(v_3\) = [15, -18].
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Taner wants to run a total of 6 kilometers between last week and this week. How far does Taner need to run this week to reach his goal?
Taner will only need to run 3 km this week to complete his 6 km running goal.
Describe the fractional number in detail:If we require a definition, we may start by saying that fractional numbers are numbers that symbolize one or possibly more portions of a unit that has been subdivided into equal parts.
To determine the fractional numbers, two whole numbers (including fraction terms) are separated by a horizontal line (the fraction line). The denominator just below line must be different from zero, whereas the numerator well above line may be any whole number.Given that, Taner's overall running goal is 6 km (including last week and this week)
So,
Taner's 2-week goal is 6 kilometres.
Now,
Taner's goal for the week is 3 kilometres = (6/2).
As the Taner completed 3 km of running last week. Taner can achieve his objective this week by running just 3 miles.
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Select the correct answer. Based on these segment lengths, which group of segments cannot form a triangle? A. 12, 7, 8 B. 8, 7, 13 C. 1, 2, 3 D. 80, 140, 70
Answer:
D. 80, 140, 70
Step-by-step explanation:
80°, 140° and 70° cannot form a triangle as the total number of the three angles is 290° whereby the total number of angles in a triangle is 180°
Answer:
80, 140, 70
Step-by-step explanation:
because
please help asp please
 
                                                Answer:
C) 76 cm²
Step-by-step explanation:
area = (8 x 8 ) + (3 x 8 x 0.5) = 76 cm²
another way is:
area = 1/2(b1 + b2)(h)
area = 1/2(11 + 8)(8) = 76 cm²
Answer:
76
Step-by-step explanation:
Hello There!
The area can be found by using this formula
\(A=\frac{a+b}{2} h\)
where a and b = bases and h = height
we need to find the height before we can find the area
the shape was split into a triangle and a square
because its a square and one of the side lengths is equal to 8cm the height will be equal to 8cm
now we plug in the known information into the formula
\(A=\frac{11+8}{2} 8\\11+8=19\\\frac{19}{2} =8.5\\8.5*8=76\\A=76\)
so we can conclude that the area of the trapezoid is 76 square centimeters
Walter is planning to invest in a savings account which pays annual interest compounded monthly. His projected account balance after
tyears is given by the expression below.
3,570(1 + 0.03/12)^12t
Which of the following statements best describes the expression?
Answer:
b
Step-by-step explanation:
Check
Match the solution set given in inequality notation with the solution set given in interval notation.
17,88
(-0, 7.8)
7.8
(7.8,00)
> 7.8
[7.8,00)
V
7.8
(-0, 7.8)
 
                                                The Matching of the inequality is
x ≤ 7.8 -> (-∞,7.8]
x < 7.8 -> (-∞,7.8).
x > 7.8 -> (7.8,∞)
x ≥ 7.8 -> [7.8,∞).
What is Inequality?Mathematical expressions with inequalities are those in which the two sides are not equal. Contrary to equations, we compare two values in inequality. Less than (or less than or equal to), greater than (or greater than or equal to), or not equal to signs are used in place of the equal sign.
1. x ≤ 7.8
Here the value of is less than equal to 7.8 which means starting from -∞ to 7.8
Thus, the interval is (-∞,7.8]
2. x < 7.8
Here the value of is less than 7.8 which means starting from -∞ to less than 7.8.
Thus, the interval is (-∞,7.8).
3. x > 7.8
Here the value of is greater than 7.8 which means starting from 7.9 to ∞.
Thus, the interval is (7.8,∞)
4. x ≥ 7.8
Here the value of is greater than equal to 7.8 which means starting from 7.8 to ∞.
Thus, the interval is [7.8,∞).
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R-1.3 Algorithm A uses 10n log n operations, while algorithm B uses n2 operations. Determine the value n0 such that A is better than B for n ≥ n0.
R-1.4 Repeat the previous problem assuming B uses n √n operations.
I only need R-1.4!!
For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.
To determine the value of n₀ for which Algorithm A is better than Algorithm B when B uses n√n operations, we need to find the point at which the number of operations for Algorithm A is less than the number of operations for Algorithm B.
Algorithm A: 10n log n operations
Algorithm B: n√n operations
Let's set up the inequality and solve for n₀:
10n log n < n√n
Dividing both sides by n gives:
10 log n < √n
Squaring both sides to eliminate the square root gives:
100 (log n)² < n
To solve this inequality, we can use trial and error or graph the functions to find the intersection point. After calculating, we find that n₀ is approximately 459. Therefore, For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.
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R-1.3: For \($n \geq 14$\), Algorithm A is better than Algorithm B when B uses \($n^2$\) operations.
R-1.4: Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.
R-1.3:
Algorithm A: \($10n \log n$\) operations
Algorithm B: \($n^2$\) operations
We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).
We need to compare the growth rates:
\($10n \log n < n^2$\)
\($10 \log n < n$\)
\($\log n < \frac{n}{10}$\)
To solve this inequality, we can plot the graphs of \($y = \log n$\) and \($y = \frac{n}{10}$\) and find the point of intersection.
By observing the graphs, we can see that the two functions intersect at \($n \approx 14$\). Therefore, for \($n \geq 14$\), Algorithm A is better than Algorithm B.
R-1.4:
Algorithm A: \($10n \log n$\) operations
Algorithm B: \($n\sqrt{n}$\) operations
We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).
We need to compare the growth rates:
\($10n \log n < n\sqrt{n}$\)
\($10 \log n < \sqrt{n}$\)
\($(10 \log n)^2 < n$\)
\($100 \log^2 n < n$\)
To solve this inequality, we can use numerical methods or make an approximation. By observing the inequality, we can see that the left-hand side \($(100 \log^2 n)$\) grows much slower than the right-hand side \($(n)$\) for large values of \($n$\).
Therefore, we can approximate that:
\($100 \log^2 n < n$\)
For large values of \($n$\), the left-hand side is negligible compared to the right-hand side. Hence, for \($n \geq 1$\), Algorithm A is better than Algorithm B when B uses \($n\sqrt{n}$\) operations.
So, for R-1.4, the value of \($n_0$\) is 1, meaning Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.
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                                                            What are the roots of the equation x2 – 10x + 21 = 0?
Answer:
Step-by-step explanation:
H
An account is opened with an initial deposit of $100 and earns 3.0% interest compounded monthly.
What will the account be worth in 25 years?
Round your answer to the nearest cent.
Do NOT round until you have calculated the final answer.
f (n) = -3n -1 what is the common diffrence
The common difference of the function is -3
How to find the common difference?f(n) = -3n - 1
where
n = number of termsA common difference is the difference between consecutive numbers in an arithmetic sequence.
Therefore,
f(1) = -3(1) - 1
f(1) = -3 - 1
f(1) = -4
f(2) = -3 (2) - 1
f(2) = -6 - 1 = -7
f(3) = -3 (3) - 1
f(3) = -9 - 1 = -10
f(4) = -3 (4) - 1
f(4) = -12 - 1 = - 13
The sequence are -4, -7, - 10, - 13.
Hence,
common difference = -7 - (-4) = -3
Therefore, the common difference of the function is -3
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The measure of an angle is 5. What is the measure of its complementary angle?
Answer:
85°
Step-by-step explanation:
90° - 5° = 85°
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
Answer the following (-70) + (-79)
Answer:
-84
Step-by-step explanation:
Answer:
-149
Step-by-step explanation:
-70+(-79)=-149
The signs are the same so you just add normally
Example 3: Random variable X is distributed with the following pdf. sin(x), for 0 < xsa f(x)= 10, otherwise a. What is the value of the constant A? b. What is the corresponding CDF? c. What is E(x)? d. What is Var(x)?
The corresponding CDF is:F(x) = 1 - cos(x) for 0 < x < π/2F(x) = 1 for x ≥ π/2c. The expected value or mean of the given random variable X is 2. d. The variance of the given random variable X is π²/4 + 2π - 6.
The value of the constant A can be obtained by using the normalization condition that the integral of the PDF function over the entire possible range of X must be equal to 1. So, we can write the following integral to solve for
A:(∫f(x) dx) from 0 to π/2=∫A sin(x) dx= A [-cos(x)] evaluated at π/2 and 0= -A(cos(π/2) - cos(0))= A (1 - 0) =1. Therefore, the value of the constant A is 1. b. The CDF of the given random variable X is given as follows:
F(x)=∫f(x)dx from 0 to x, for 0 < x < π/2=∫sin(x) dx from 0 to x= [-cos(x)] evaluated at x and 0= -cos(x) - (-cos(0))= 1 - cos(x) for 0 < x < π/2=1 for x ≥ π/2. So, the corresponding CDF is as follows:
F(x) = 1 - cos(x) for 0 < x < π/2F(x) = 1 for x ≥ π/2c. The expected value or mean of the given random variable X can be obtained using the following formula:
E(X) = ∫xf(x)dx from 0 to π/2=∫x sin(x) dx from 0 to π/2= [-x cos(x)] evaluated at π/2 and 0 - ∫-cos(x) dx from 0 to π/2= -0 + cos(0) - ([-cos(x)] evaluated at π/2 and 0)= 0 + 1 - (-1)= 2. So, the expected value of the given random variable X is 2.
d. The variance of the given random variable X can be obtained using the following formula:
Var(X) = E(X²) - [E(X)]²=∫x² f(x)dx from 0 to π/2 - [E(X)]²=∫x² sin(x)dx from 0 to π/2 - (2)²= [-x² cos(x)] evaluated at π/2 and 0 + ∫2x cos(x)dx from 0 to π/2 - 4= -0 + π²/4 - 4 + (2 sin(x) + 2x cos(x)) evaluated at π/2 and 0= π²/4 - 2 - 4 + 2 + 2π= π²/4 + 2π - 6. So, the variance of the given random variable X is π²/4 + 2π - 6
Hence, the answer is: a. The value of the constant A is 1.b. The corresponding CDF is : F(x) = 1 - cos(x) for 0 < x < π/2F(x) = 1 for x ≥ π/2c. The expected value or mean of the given random variable X is 2. d. The variance of the given random variable X is π²/4 + 2π - 6
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two angles directly across from each other on intersecting lines Is called?
Barb had $55 in her checking account. She spent $12 on makeup and $13 on
socks. How much is in her checking account now?
Answer: Barb now has 30$ left.
Step-by-step explanation:
55-12=43 43-13=30
a builder appoints three construction workers akash, sunil and rakesh on one of his sites. they take 20, 30 and 60 days respectively to do a piece of work. how many days will it take akash to complete the entire work if he is assisted by sunil and rakesh every third day?
It will take 15 days for Akash to complete the entire work if he is assisted by Sunil and Rakesh every third day.
To determine the number of days, we first represent the number of days to do a piece of work by each one of them in fractions as follows;
Fraction of work completed by Akash in 1 day = 1/20
Fraction of work completed by Sunil in 1 day = 1/30
Fraction of work completed by Rakesh in 1 day = 1/60
The total work done in 1 day can be given as;
Total work done by the three in one day = [(1/20) + (1/30) + (1/60)] = 1/10
Work done by Akash in two days = 2 × (1/20) = 2/20 = 1/10
The work done in three days (1 day of all three together + Work done by Akash in two days) = (1/10) + (1/10) = 1/5
Therefore; the total work done in 3 days = 1/5
At this rate, the total number of cycles required to finish the work =
(1) ÷ (1/5) = 5
Since each cycle has three days, the total number of days required to finish the work can be calculated as follows;
5 × 3 = 15 days
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Spoopy doopy doo ill ask a question and first, to get correct I will give the brainiest.
Tim has 789 Oreos Jon has 2x more Oreos than Tim, Pops has 4 times more than Jon how many Oreos does everyone has altogether? ASAP or I won't give brainiest.
4,734 is the answer because I used my calculator XD
Step-by-step explanation:
8679 easy equation all u gotta do is multiply 789 times 2 then take that number and multiply it by 4 and add all the numbers u got up
A cattle farmer wants to save for his daughter's college tuition. He will have to pay P50,000 at the end of every year for the next four years that his daughter attends college. He has 8 years until his daughter starts college to save up for her tuition. Using a 7\% interest rate compounded annually, what is the amount the farmer would have to save every year for the 8 years?
Calculating this expression will give us the amount the farmer needs to save annually over the 8-year period.
Given:
Payment required at the end of each year: P50,000
Number of years until the daughter starts college: 8
Interest rate: 7% (compounded annually)
We can calculate the annual savings using the formula for the present value of an ordinary annuity:
P = \dfrac{PMT \times (1 - (1 + r)^{-n}{r}
Where:
P = Present value (amount to be saved annually)
PMT = Payment amount (P50,000)
r = Interest rate per period (7% or 0.07)
n = Number of periods (8)
Let's substitute the given values into the formula:
\[ P = \dfrac{50,000 \times (1 - (1 + 0.07)^{-8}{0.07} \]
Calculating this expression will give us the amount the farmer needs to save annually over the 8-year period.
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HELP WHAT IS THE ANSWER TO THIS??
 
                                                Answer:
I think it is A
Step-by-step explanation:
Answer:
65
Step-by-step explanation:
A Converse Statement is when you turn the statement into a double negative?
A. True 
B. False 
Answer:
False
Step-by-step explanation:
This is because there is no such thing! A double negative becomes a positive! Plz give brainliest!
Answer:
False if its in double negative.
would it be appropriate to construct a 95% confidence interval with the information in 1(b) through 1(d)? explain why in one sentence.
If a simple random of size n is drawn from a population, then the 95% confidence-interval about "μ", if the sample size "n" is 23 is (101.68 , 110.32).
The population from which a simple random of size "n" is drawn is normally distributed,
We have to construct "95% confidence-interval" when n = 23,
So, c = 0.95, n = 23,
⇒ degree of freedom(df) = 23 - 1 = 22,
from t-distribution table, the critical-value corresponding to c = 0.95 and df = 22 is t = 2.074,
the lower bound is = x' - (t×s)/√n = 106 - (2.074×10)/√23 = 101.68,
the upper bound is = x' + (t×s)/√n = 106 + (2.074×10)/√23 = 110.32,
Therefore, the required 95% confidence interval is (101.68 , 110.32).
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The given question is incomplete, the complete question is
A simple random of size n is drawn from a population that is normally distributed, the sample mean (x') is found to be 106, and the sample standard deviation is 10. Construct a 95% confidence interval about "μ", if the sample size "n" is 23.
Ms. Johnson has three times as many
flowers as Ms. Harris. Ms. Harris has
12 flowers. How many flowers does
Ms. Johnson have?
Answer:
36
Step-by-step explanation:
12 x 3 =36
hope this helped :)
sin X, translated 4 units to the right . y = cos x, translated 5 units to the left and 2 units down
write equation
Answer:
jsbekeiwbwiwuwbwjwjwbwwiwStep-by-step explanation:
jebeuehevehehbejeeuehbejwuwwhbwhenebejeiejeenehehebehejehejeiejenneejejnejeiwiwejejeieieijeeueijejeeuejejejejjeejejejejjejejejejejejejeejjejjejejejejejejJoanna is driving from Orlando, FL to Dallas, TX. The distance between Orlando and Dallas is 1,084 miles. Joanna's average rate of speed is 65 mph. The following function represents how many miles Joanna has left on her trip after t hours, F(t)=1084-65t.
After how many hours of driving will Joanna be 304 miles from Dallas?
_______ hours.
*Hint, the f(t) is given in the word problems as 304 miles. Plug the 304 in place of the f(t) and solve for t using inverse operations.
Answer:
12 hours
Step-by-step explanation:
We are given the function [ F(t) = 1084 - 65t ]
t represents the time so we are going to solve for f(t).
Substitute and solve
304 = 1084 - 65t
~Subtract 1084 to both sides
-780 = -65t
~Divide -65 to both sides
12 = t
Best of Luck!
suppose researchers marked 800 turtles and later were able to trap a total of 300 individuals in that population, of which 200 were marked. what is the estimate for total population size?
Using Marked recapature formula for estimation on population size we get,
the estimate for total population size is 1200.
Marked recaputure Method :
first step is to capture and mark a sample of individuals. The assumption behind mark-recapture methods is that the proportion of marked individuals recaptured in the second sample represents the proportion of marked individuals in the population as a whole. In algebraic terms,
R/S = M/N
where R --> second time marked
S---> size of sample second time
N --> estimate population size
M ---> Marked in start point
We have given that ,
Total marked turtles by researchers (M) = 800
Second time total sample size (S) = 300
second time marked turtles(R) = 200
we have to find out estimate for total population size .
For this , Mark -Recapture method is very efficient to calculate estimate for total population size.
putting all known values in above formula we get, R/S = N/M
=> 200/300 = 800/N
=> 800× 300 = N× 200
=> N × 200 = 240000
=> N = 240000/200
=> N = 1200
so, the estimate for total population size is 1200.
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State translation,reflection or rotation
(x, y) ——-> (x + 9, y + 2)
Answer:
Translation
Step-by-step explanation:
Translation as the x and y are both being moved over the plane.
Select the correct answer. What is the average rate of change of f(x), represented by the graph, over the interval [-1, 1]? A. 2 B. 3 C. 5 D. 6
 
                                                Answer:
C
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is
\(\frac{f(b)-f(a)}{b-a}\)
Here [ a, b ] = [- 1, 1 ] , thus
f(b) = f(1) = 5 ← from graph
f(a) = f(- 1) = - 5 ← from graph , thus
average rate of change = \(\frac{5-(-5)}{1-(-1)}\) = \(\frac{10}{2}\) = 5 → C