Determine the grams of potassium chloride produced when 505 grams of potassium
phosphate react with 222 grams of HCI. Refer to the balanced equation below.
K3PO4 (aq) + 3HCI (aq) --> 3KCI (1) + H3PO4 (aq) (balanced)

Answer:

A small amount of chemical splashes in Frank's eye. What should happen next? Frank should go to the eyewash station while his lab partner tells the teacher what happened.

Explanation:

Brainlist

Answer:

Work Done= Force×Displacement

Thus

Work Done = 20×10

Work Done = 200Joules

Answer:

Explanation:

The objective here is to draw the Lewis structure for the polyatomic trisulfide anion and to be sure all resonance structures that satisfy the octet rule are included.

The Lewis structure for  Polyatomic trisulfide anion

The first step is to the layout the skeleton of the Polyatomic trisulfide anion

         S           S           S

However, the next step is to make sure we fill in the bonding pairs of electrons on the central atom.

Then , we move over to filling the lone pairs electrons before we finally have the Lewis structure for  Polyatomic trisulfide anion as shown in the image below.

\(▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)

The charge on an electron is ~

" - " symbol is used to show that its negative.

Answer:

c

Explanation:

Answer:

a) \(CH_3CH_2CH_2CH_3\)

Explanation:

In this question we have the following answer choices:

a) \(CH_3CH_2CH_2CH_3\)

b) \(CH_3CH_2OH\)

c) \(HF\)

d) \(CH_3Cl\)

e) \(HOCH_2CH_2OH\)

We have to remember the relationship between intermolecular forces and vapor pressure. If we have stronger intermolecular forces we will have less vapor pressure because the molecules have more interactions between them, so, the molecules will prefer to stay in a liquid state rather than a gaseous state. Now, we have to check each molecule:

a) \(CH_3CH_2CH_2CH_3\) (Van der waals interactions)

b) \(CH_3CH_2OH\) (Hydrogen bonding)

c) \(HF\) (Hydrogen bonding)

d) \(CH_3Cl\) (Dipole-dipole interaction)

e) \(HOCH_2CH_2OH\) (Hydrogen bonding)

For molecules b, c and e we have hydrogen bond to a heteroatom (O, N, S, or P). In this case oxygen, therefore we will have hydrogen bonding interactions (a very strong interaction). So, we can discard these ones.

In molecule e, we have "Cl" bond to a "C" therefore we will have the presence of a dipole (due to the electronegativity difference). If we have a dipole, we will have a dipole-dipole interaction (a strong interaction, less than hydrogen bonding but still is a strong interaction).

In molecule a, we have only Van der Waals interactions because in this molecule we have only carbon and hydrogen atoms bonded by single bonds. So, we will have a non-polar molecule. These interactions are the weakest interactions of all the molecules given. So, if we have weaker interactions the molecules can be converted to a gas state more easily and we have more vapor pressure.  

Answer: I think 82.46

Explanation: The atomic number for strontium, or Sr on the periodic table, is 38. With knowing the atomic number, I multiplied that by the number of moles given.

38 × 2.17 = 82.46

I hope this helps!!

The number of atoms present in 2.17 moles of strontium are  \(1.306774 \times 10^{24}\).

An atom is the smallest indivisible unit of a chemical element that retains the chemical properties of that element. It is the basic building block of matter.

To determine the number of atoms in a given number of moles, we can use Avogadro's number, which is approximately \(6.022 \times 10 ^{24}\) atoms per mole.

In this case, we have 2.17 moles of strontium. To find the number of atoms, we multiply the number of moles by Avogadro's number:

Number of atoms = \(2.17 moles\times6.022\times 10^{23}\)\(atoms/mole\)

On calculating this expression:

Number of atoms =\(1.306774 \times 10^{24}\)

Therefore, there are approximately \(1.306774 \times 10^{24}\) atoms in 2.17 moles of strontium.

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The amount of Iron-59 remaining after 3 half-lives, given an initial amount of 2.5 grams is 0.3125 grams

The original amount of a subtance, the number of half lives and the amount of the substance remaining are related according to the following formula:

N = N₀ / 2ⁿ

Where

Now, with the above formula, we shall determine the amount that will remain after 3 half lives. This is shown below:

N = N₀ / 2ⁿ

N = 2.5 / 2³

N = 2.5 / 8

N = 0.3125 grams

Thus, from the above calculation, we can conclude that the amount remaining is 0.3125 grams

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Complete question:

Given that you originally have 2.5 g of iron-59. Calculate the amount of Iron-59 remaining after 3 half-lives.

Answer:

Explanation:

As the measurements are given to us in centimeters, let's start by calculating the surface area in square centimeters:

Now we convert 100.75 cm² to m², as follows:

Finally we convert 0.010075 m² to nm², as follows:

Explanation:

SO2 comprises a double Covalent bond with one oxygen atom as well as a coordinate bond with another oxygen atom. The SO2 comprises 1s and 2p orbitals hybridized. Owing to the double Covalent bond of the molecule Sulphur Dioxide, it has 2 sigma and 2 pi bonds.

Answer:

Asteroids are made of rock, metals, and other elements. Some even contain water. Asteroids that are mostly stone sometimes are more likely to lose piles of rubble. Asteroids that are mostly iron are more rock-solid.

Explanation:

Answer:

asteriods are made of rocks.   asteroids that are mostly iron are more, well, rock-solid

Explanation:

Answer:

172 g

Explanation:

Let's consider the reduction of Au³⁺ to Au.

Au³⁺(aq) + 3 e⁻ → Au(s)

In order to find the mass of gold produced, we will use the following relations.

The mass of gold produced when 15.1 A of current are passed through a gold solution for 31.0 min is:

\(31.0min \times \frac{60s}{1min} \times \frac{15.1C}{s} \times \frac{1mole^{-} }{96,468C} \times \frac{3molAu}{1mole^{-} } \times \frac{196.97gAu}{1molAu} = 172 gAu\)

The compound contains approximately 0.1486.02210^23 carbon atoms, or about 8.9*10^22 carbon atoms. Thus, the number of carbon atoms in the compound is approximately 15.

The molecular formula of a compound is a representation of the number and types of atoms that constitute one molecule of that compound.

To solve this problem, we can use the isotopic distribution of carbon in the compound to determine the molecular formula. The relative abundance of each isotope is related to the number of atoms of that isotope in the molecule.

Let's assume the molecular formula of the compound is CxHy, where x is the number of carbon atoms and y is the number of hydrogen atoms. We can use the following equation to relate the relative abundance of each isotope to the number of carbon atoms:

(0.9893)x(0.4475) + (0.0107)x(0.02904) = 0.02904

Simplifying this equation, we get:

0.443x + 0.00031268x = 0.02904

0.44331268x = 0.02904

x = 0.06556/0.44331268

x = 0.148

Therefore, the compound contains approximately 0.1486.02210^23 carbon atoms, or about 8.9*10^22 carbon atoms. Thus, the number of carbon atoms in the compound is approximately 15.

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The number of carbon atoms in the compound can be determined by calculating the ratio of C12 to C13 isotopes present.

Carbon atoms are the building blocks of life. They are the most abundant element in the human body and make up the molecules that create all living things. Carbon atoms are found in proteins, carbohydrates, and lipids, and are essential for the functioning of all living organisms. Carbon atoms are made up of six protons, six neutrons, and six electrons, and are the backbone of organic chemistry.

Since the relative abundances of C12 and C13 are 44.75% and 2.904% respectively, the ratio of C12 to C13 can be calculated as follows:

C12/C13 = (44.75/2.904) = 15.39

We can then compare this ratio to the natural abundance of C12 and C13, which is 98.93% and 1.07%, respectively.

If the ratio of C12 to C13 in the compound is equal to the natural abundance of these isotopes, then the number of carbon atoms in the compound must be 12.

C12/C13 = (98.93/1.07) = 92.52

Since the ratio of C12 to C13 in the compound is not equal to the natural abundance of these isotopes, then the number of carbon atoms in the compound must be 13.

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To balance the equation we start by counting the number of atoms we have of each element on each side of the reaction.

Reagents side:

Fe = 1 atom

Cl= 3 atoms

Na=1 atom

O=1 atom

H= 1atom

Products side:

Fe = 1 atom

Cl= 1 atom

Na=1 atom

O= 3 atoms

H= 3 atoms

Let's start with chlorine, we have 3 chlorine atoms on the reactant side and 1 on the product side. So we will put the coefficient 3 in the NaCl molecule to balance the chlorine.

Now, we will have:

Reagents side:

Fe = 1 atom

Cl= 3 atoms

Na=1 atom

O=1 atom

H= 1atom

Products side:

Fe = 1 atom

Cl= 3 atom

Na= 3 atom

O= 3 atoms

H= 3 atoms

Now, we balance the Na, we have 1 atom of Na in the reactants and 3 in the products. We then put coefficient 3 in the NaOH molecule.

We have now the equation balanced:

Reagents side:

Fe = 1 atom

Cl= 3 atoms

Na=3 atoms

O=3 atoms

H= 3 atoms

Products side:

Fe = 1 atom

Cl= 3 atom

Na= 3 atom

O= 3 atoms

H= 3 atoms

We have the same number of atoms of each element on both sides of the reaction.

Now, in the reaction we can notice that Cl and OH happen to substitute the place of the other, therefore, this reaction will be a double replacement reaction.

The volume of the solution is 24.8 milliliters (mL).

To solve this problem, we can use the formula:

Molarity (M) = moles of solute / liters of solution

We are given the mass of CuNO3 and the molarity of the solution, so we can first calculate the number of moles of CuNO3:

moles of CuNO3 = mass / molar mass

molar mass of CuNO3 = 63.55 + 14.01 + 3(16.00) = 187.56 g/mol (using atomic weights from the periodic table)

moles of CuNO3 = 3.90 g / 187.56 g/mol = 0.0208 mol

Next, we can rearrange the formula for molarity to solve for the volume of the solution:

liters of solution = moles of solute / Molarity

liters of solution = 0.0208 mol / 0.840 M = 0.0248 L

Finally, we can convert liters to milliliters:

volume of solution = 0.0248 L x 1000 mL/L = 24.8 mL

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Based in the data provided, the percentage by mass of K2SO4 is 60.55 %.

The mass of K2SO4 in the mixture is obtained from the data given as follows:

Total mass of sample = 0.649 g

Let the mass of K2SO4 in the mixture be X g

Mass (NH4)SO4 = (0.649 - X )g

Moles of K2SO4 = X g/174.25 g/mol

= 0.00574X mol

Moles of (NH4)2SO4 = (0.649 - X)g / 132.13 g/mol

= (0.00491 - 0.00757X) mol

Total number of moles SO42- ions precipitated = 0.00574X mol + (0.00491 - 0.00757X)mol

= (0.00491-0.00183X) mol

Mole ratio of SO42- ions to Ba2+ ions = 1:1

Thus, moles of Ba2+ ions = (0.00491 - 0.00183X)mol

Moles of BaSO4 precipitated = 0.977 g/233.38 g/mol = 0.00419 moles

1 mole of BaSO4 produces 1 mole of Ba2+ ions

Therefore,

(0.00491 - 0.00183X) mol = 0.00419mol

0.00183X = 0.00491 - 0.00419mol

0.00183X = 0.00072

X = 0.00072/0.00183 = 0.393 g

Mass of K2SO4 = 0.393 g

Percentage by mass of K2SO4 = (0.393/0.649) × 100

Percentage by mass of K2SO4 = 60.55 %

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Ammonium sulfide nh4s is the name-formula pair that is incorrectly matched.

The formula is a fact or a rule that is expressed using mathematical symbols. Normally, three or more values are connected by an equal sign. When you know the value of one quantity, you may apply the formula to determine how much the other quantity is worth.

Following that, demand fell as households decided not to make purchases and instead made do about what they already had. When a result, formula producers would have to produce less as the market changed. Delays: Supply chain bottlenecks brought on by the epidemic continue to affect the production of baby formula. With the maker Abbott, delays brought on by the weather have also happened.

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Answer:

First of all list the given before starting to solve

GIVEN:

C= 66.7%

H=11.1%

O= 100-66.7-11.1= 22.2%

In any empirical formula problem you must first find

look u should memories the steps all to find it but if ur given the percentage already so no need to find the mass bcz in the first place we find the mass just to find the percentage.

now change the percentage we have in each element to 100grams now u would ask why 100g and not 1g well , we chose 100 bcz it's percentage and easier to calculate.

after converting all to grams

follow another formula

\(n = \frac{mass}{molar \: mass} \)

n represents number of moles

so apply to each , but for the molar mass u either should be given

H= 1 g/mol

C=12g/mol

O=16g/mol

apply it for each

HOPE U UNDERSTOOD IT

Explanation:

First, we need to calculate the number of moles of heptane that are burned:

0.470 kg heptane × (1 mol heptane / 100.2057 g heptane) = 0.004696 mol heptane

According to the balanced chemical equation, 1 mol of heptane produces 7 mol of CO2. Therefore, the number of moles of CO2 produced is:

0.004696 mol heptane × (7 mol CO2 / 1 mol heptane) = 0.032872 mol CO2

The ideal gas law relates the number of moles of a gas to its volume, pressure, and temperature:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

We can rearrange the ideal gas law to solve for the volume:

V = nRT / P

where V is in liters, n is in moles, R is 0.08206 L·atm/mol·K (the ideal gas constant), T is in Kelvin, and P is in atm.

We need to convert the temperature to Kelvin:

17.0°C + 273.15 = 290.15 K

Substituting the values into the equation, we get:

V = (0.032872 mol CO2)(0.08206 L·atm/mol·K)(290.15 K) / 1 atm = 0.758 L

Therefore, the volume of carbon dioxide gas produced is 0.758 L. Rounded to 3 significant digits, the answer is 0.758 L.

Answer:

I don't know what the hell is going on with the this.

The temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

To determine the temperature of the gas in Kelvin after its volume is reduced, we can use the combined gas law, which relates the initial and final conditions of pressure, volume, and temperature for a given amount of gas.

The combined gas law equation is:

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

Where P₁ and P₂ are the initial and final pressures, V₁ and V₂ are the initial and final volumes, T₁ is the initial temperature in Kelvin, and T₂ is the final temperature in Kelvin.

Given that the initial volume V₁ is 3,480 mL, the initial temperature T₁ is -70.0 °C (which needs to be converted to Kelvin), and the final volume V₂ is 2,450 mL, we can substitute these values into the equation.

To convert -70.0 °C to Kelvin, we add 273.15 to it, resulting in T₁ = 203.15 K.

Now we can solve for T₂:

(T₂ * V₁) / T₁ = V₂

T₂ = (V₂ * T₁) / V₁ = (2,450 mL * 203.15 K) / 3,480 mL

Simplifying the equation, we find:

T₂ ≈ 143.27 K

Therefore, the temperature of the gas in Kelvin, after its volume is reduced to 2,450 mL, is approximately 143.27 K.

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The de Broglie wavelength of an electron traveling at 1.59×105m/s is  0.4547 x 10⁻⁹ m.

The elementary electric charge of the electron is a negative one, making it a subatomic particle. Due to their lack of known components or substructure, electrons, which are part of the first generation of the lepton particle family, are typically regarded to be elementary particles.

The length scale at which a particle's wave-like characteristics are significant is indicated by its de Broglie wavelength. The symbol or dB is typically used to indicate the De Broglie wavelength. The de Broglie wavelength for a particle with momentum p is given by dB = hp.

λ = h/mv

Where,

λ = wavelength of electron

m = mass of electron = 9.11e-31 kg

v = speed of electron = 1.59 × 10⁵ m/s

h = constant

Therefore,

λ = (6.626x10⁻³⁴J-s) ÷  [(9.11e-31 kg) (1.59 x 10⁵ m/s)]

λ = 0.4547 x 10⁻⁹ m

Thus, The de Broglie wavelength of an electron traveling at 1.59×105m/s is  0.4547 x 10⁻⁹ m.

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Answer:

Explanation:

physical substance in general, as distinct from mind and spirit; (in physics) that which occupies space and possesses rest mass, especially as distinct from energy.

Answer:

Anything that takes up space.

Explanation:

Anything that has both volume and mass.

Answer:

16.2mL of 0.1111M NaOH are used

Explanation:

volumetric flask of 250.0mL

As first, the HCl reacts with CaCO3 as follows:

2HCl + CaCO3 → H2O + CaCl2 + CO2

Where 2 moles of HCl react with 1 mole of CaCO3

To solve this question we must find the moles of each reactant in order to determine the moles of HCl that remains:

Moles HCl:

0.01800L * (2.125mol / L) = 0.03825 moles HCl

Moles CaCO3 -Molar mass: 100.09g/mol-

0.4104g * (1mol / 100.09g) = 0.00410 moles CaCO3

Moles HCl that reacts:

0.00410 moles CaCO3 * (2 mol HCl / 1 mol CaCO3) =

0.00820 moles HCl

Moles HCl that remains:

0.03825 moles HCl - 0.00820 moles HCl:

0.03005 moles HCl remains

The HCl reacts with NaOH as follows:

HCl + NaOH → H2O + NaCl

That means, to reach the equivalence point, the moles of NaOH that must be added = Moles HCl, in a sample of 15.00mL, the moles of HCl are:

0.03005 moles HCl * (15.0mL / 250.0mL) = 0.001803 moles HCl = Moles NaOH. The volume of 0.1111M NaOH is:

0.001803 moles NaOH * (1L / 0.1111moles) = 0.016L 0.1111M NaOH are required, that is:

Answer:

C

Explanation:

Answer:

you need to state the options

Answer:

a measure of the suitability of water for a particular use based on selected physical, chemical, and biological characteristics.

Water quality is a parameter to qualify based on several key factors. Some of these factors are:

• Conceptration of dissolved oxygen;

• Bacteria levels;

• Amount of salt (salinity);

• Amount of material suspended in the water (turbidity).

Other elements that might be measured to determine water quality are:

• Concentration of algae;

• Pesticides;

• Herbicides;

• Heavy metals.

When sodium hydroxide is dissolved in water within a beaker, it is observed that the beaker becomes warm due to chemical reaction.

A chemical reaction is a type of reaction that involves the rearrangement of atoms to form new substances.

The indications that a chemical reaction has occurred is:

Therefore, When sodium hydroxide is dissolved in water within a beaker, it is observed that the beaker becomes warm due to chemical reaction.

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