determine whether each of these pairs of sets are equal

a) (1, 3, 3, 3, 5, 5, 5, 5, 5}, {5, 3, 1} b) {{1}}, {1, {1}} c) Ø, {0}​

The general solution u(t,x) of the boundary value problem for the heat equation with homogeneous Neumann boundary conditions would be   \(u(t,x) = \sum Cn * sin(n * \pi * x / L) * e^(-n^2 * \pi ^2 * k * t / L^2)\)

What is homogeneous Neumann boundary conditions?

For example, d2ydx2+4y=0 if your differential equation is homogeneous (it equals zero and not any function). y(x=0)=0 and y(x=2)=0 were given as the boundary conditions, and you were requested to answer the equation. Then the aforementioned boundary conditions are homogenous boundary conditions.

To find the general solution of the boundary value problem for the heat equation with homogeneous Neumann boundary conditions, we can start by considering the form of the general solution for the heat equation with homogeneous boundary conditions.

The general solution of the heat equation with homogeneous boundary conditions is given by:

\(u(t,x) = \sum Cn * f(n,x) * g(n,t)\)

Cn are constants, f(n,x) and g(n,t).

In the case of homogeneous Neumann boundary conditions, we have \(d_u(t,0)\) = 0 and \(d_u(t,L) = 0\), which means that the normal derivative of the solution at the boundaries is zero. This suggests that we can use the functions\(f(n,x) = sin(n * \pi * x / L)\)and \(g(n,t) = e^(-n^2 * \pi ^2 * k * t / L^2)\) in the general solution, where k is the thermal conductivity of the material and L is the length of the domain.

Therefore, the general solution of the boundary value problem for the heat equation with homogeneous Neumann boundary conditions is given by:

\(u(t,x) = \sum Cn * sin(n * \pi * x / L) * e^(-n^2 * \pi ^2 * k * t / L^2)\)

where the constants Cn can be determined from the initial conditions of the problem.

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Answer:

Step-by-step explanation:

y= 3x

x            y

0           0

1             3

2            6

3             9

-1            -3

-2             -6

The sum of the given polynomial is 5x²- 5x +9

Polynomials are expressions with a degree of 3 and above. Given the equation shown;

(3x + 4) + ((5x²-1) + (2x + 6))

Expand

(3x + 4) + ((5x²-1) + (2x + 6))

3x + 4 + 5x²-1 + 2x + 6

Collect the like terms

5x² + 5x + 4 - 1 + 6

5x²- 5x +9

Hence the sum of the given polynomial is 5x²- 5x +9

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Answer:

Both A and B

Step-by-step explanation:

Both a and b. A three-way intersection can be referred to as a T-intersection or a Y-intersection, depending on the shape of the intersection. In a T-intersection, one road intersects another road perpendicularly, forming a T-shape. In a Y-intersection, one road splits into two branches, forming a Y-shape.

Answer:

the future value is $5,750.01

Step-by-step explanation:

The computation of the future value is shown below;

As we know that

Future value = Present value × (1 + rate of interest)^number of years

= $5,000 × (1 + 0.035 ÷ 12)^4 × 12

= $5,000 × (1 + 0.2916%)^48

= $5,750.01

Hence, the future value is $5,750.01

On solving the provided question, we can say that from the graphs, line segment should you remove to make the relation a function of x  the line segment with endpoints (-3,2) and (-4,-2)

Mathematicians use graphs to logically convey facts or values using visual representations or charts. A graph point will typically reflect a relationship between two or more things. Nodes, or vertices, and edges make form a graph, a non-linear data structure. Glue together the nodes, often referred to as vertices. This graph has vertices V=1, 2, 3, 5, and edges E=1, 2, 1, 3, 2, 4, and (2.5), (3.5). (4.5). Statistical charts (bar charts, pie charts, line charts, etc.) graphical representations of exponential growth. a logarithmic graph in the shape of a triangle

from the graphs,

line segment should you remove to make the relation a function of x

the line segment with endpoints (-3,2) and (-4,-2)

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Answer:

AB and CD

Step-by-step explanation:

Given

Shape: Parallelogram

Parallel Side: AB and CD

Required

Determine the opposite sides

From the given parameters, we understand that:

AB is parallel to CD

Since they are parallel, then AB is opposite to CD

Hence, the opposite sides are AB and CD

288 ounces of water are left in the water tank.

What is arithmetic?

Arithmetic is an elementary part of mathematics that consists of the study of the properties of the traditional operations on numbers—addition, subtraction, multiplication, division, exponentiation, and extraction of roots

Here, we have

Given: Tom has a water tank that holds 5 gallons of water. tell me this is water for my footing to fill six bottles they each hold 16 ounces and a picture that holds one over 2 gallons.

1 gallon = 128 ounces, 2 gallon = 256 ounces

6 bottles × 16 ounces = 96 ounces

2 gallon + 96 ounces = 256 + 96 ounces = 352 ounces

5 gallon = 5 × 128 = 640 ounces

= 640 - 352 = 288 ounces

Hence,  288 ounces of water are left in the water tank.

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Answer:

124.8

Step-by-step explanation:

120*.04=124.8

Answer:

Answer: B. 24

Step-by-step explanation: 60 divided by 5 is 12. Twelve times two (the amount of girls) is 24. Twelve times 3 (the amount of boys) is 36. Since 24 + 36 = 60, there are 24 girls and 36 boys.

Answer:

45

scalene

acute

Step-by-step explanation:

Answer: The triangle classified by the sides is 59 degrees.  The triangle is classified by the angel is 1

Step-by-step explanation:

Answer:

x = 4b / (2 + a - b)

Step-by-step explanation:

Given :

Distribute the terms on both sides :

Bring the x terms to one side :

Take x as a common factor on the left side :

Divide both sides by (2 + a - b) :

Answer:

x = \(\frac{4b}{2+a-b}\)

Step-by-step explanation:

x(2 + a) = b(x + 4) ← distribute parenthesis on both sides )

2x + ax = bx + 4b ( subtract bx from both sides )

2x + ax - bx = 4b ← factor out x from each term on the left side

x(2 + a - b) = 4b ← divide both sides by (2 + a - b)

x = \(\frac{4b}{2+a-b}\)

Answer:

The 95% confidence interval to determine the true proportion of all patrons who would be interested in attending the showing is (0.2121, 0.4671).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \(\pi\), and a confidence level of \(1-\alpha\), we have the following confidence interval of proportions.

\(\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}\)

In which

z is the z-score that has a p-value of \(1 - \frac{\alpha}{2}\).

Of the 53 patrons, 18 said that they would come to see the film.

This means that \(n = 53, \pi = \frac{18}{53} = 0.3396\)

95% confidence level

So \(\alpha = 0.05\), z is the value of Z that has a p-value of \(1 - \frac{0.05}{2} = 0.975\), so \(Z = 1.96\).

The lower limit of this interval is:

\(\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3396 - 1.96\sqrt{\frac{0.3396*0.6604}{53}} = 0.2121\)

The upper limit of this interval is:

\(\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3396 + 1.96\sqrt{\frac{0.3396*0.6604}{53}} = 0.4671\)

The 95% confidence interval to determine the true proportion of all patrons who would be interested in attending the showing is (0.2121, 0.4671).

First question seems incomplete :

Answer:

40 ways

Step-by-step explanation:

Question B:

Number of boys = 6

Number of girls = 4

Number of people in committee = 3

Number of ways of selecting committee with atleast 2 girls :

We either have :

(2 girls 1 boy) or (3girls 0 boy)

(4C2 * 6C1) + (4C3 * 6C0)

nCr = n! ÷ (n-r)!r!

4C2 = 4! ÷ 2!2! = 6

6C1 = 6! ÷ 5!1! = 6

4C3 = 4! ÷ 1!3! = 4

6C0 = 6! ÷ 6!0! = 1

(6 * 6) + (4 * 1)

36 + 4

= 40 ways

Answer:

$524.30

Step-by-step explanation:

70+60+25+350+30= 535

535*.02(20%)

10.7

535-10.7=

524.3

Answer:

$107

Step-by-step explanation:

First you have to add up the costs and you get a total of $535

Then you need to make 535 equivalent to 100 then divide by 20 to get 107

Hope that helps and have a great day!

Answer:

Lucid dreams i relate too much to it

Step-by-step explanation:

juice wrld :( fly high

Answer

Explanation

Mathematically, if a point R(x, y) divides the coordinates S (x₁, y₁) and T (x₂, y₂) internally in the ratio m:n then point R(x, y) is given as

x = [(mx₂ + nx₁)/(m + n)]

y = [(my₂ + ny₁)/(m + n)]

For this question, we are given that

R (x, y) = R(-2, -1)

S (x₁, y₁) = S (-14, 3)

T (x₂, y₂) = ?

Since it is divided equally into two parts (As per the midpoint), m : n = 1 : 1

x = -2

y = -1

x₁ = -14

y₁ = 3

x₂ = ?

y₂ = ?

m = 1

n = 1

x = [(mx₂ + nx₁)/(m + n)]

-2 = [(1 × x₂) + (1 × -14)]/(1 + 1)

-2 = [x₂ - 14]/2

y = [(my₂ + ny₁)/(m + n)]

-1 = {

Answer:

2,400 miles in 5 minutes

Step-by-step explanation:

60 seconds in 1 minute.

60x8=480

480x5=2400

The equivalent fractions of 7/11 are 14/22, 21/33, 28/44 and 35/55

There are infinitely many numbers equivalent to 7/11

since 7/11 is a fraction that can be simplified in different ways.

We can multiply the numerator and denominator with the same number to get the equivalent fractions

7/11×2/2 = 14/22

7/11×3/3= 21/33

7/11×4/4 =28/44

7/11×5/5 =35/55

Hence, the equivalent fractions of 7/11 are 14/22, 21/33, 28/44 and 35/55

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The marketing strategy described above in which case, new food service operators price their food too low because it short-changes the operators and leaves their competitors with a competitive advantage.

It follows from the task content that the concept embraced by most new food service operators is; low pricing.

However, this strategy short-changes the operators as cutting prices has a chain effect whose end result is a low quality product and renders the customers only one-time patronage ones.

This leaves the competitors with an advantage provided their products are of better quality.

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Answer:

a) Z = 2.575.

b) Z = 2.327.

c) Z = 1.96.

d) Z = 1.645.

e) Z = 1.88.

Step-by-step explanation:

Question a:

We have that to find our \(\alpha\) level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\(\alpha = \frac{1 - 0.99}{2} = 0.005\)

Now, we have to find z in the Z-table as such z has a p-value of \(1 - \alpha\).

That is z with a pvalue of \(1 - 0.005 = 0.995\), so Z = 2.575.

Question b:

We have that to find our \(\alpha\) level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\(\alpha = \frac{1 - 0.98}{2} = 0.01\)

Now, we have to find z in the Z-table as such z has a p-value of \(1 - \alpha\).

That is z with a pvalue of \(1 - 0.01 = 0.99\), so Z = 2.327.

Question c:

We have that to find our \(\alpha\) level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\(\alpha = \frac{1 - 0.95}{2} = 0.025\)

Now, we have to find z in the Z-table as such z has a p-value of \(1 - \alpha\).

That is z with a pvalue of \(1 - 0.025 = 0.975\), so Z = 1.96.

Question d:

We have that to find our \(\alpha\) level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\(\alpha = \frac{1 - 0.9}{2} = 0.05\)

Now, we have to find z in the Z-table as such z has a p-value of \(1 - \alpha\).

That is z with a pvalue of \(1 - 0.05 = 0.95\), so Z = 1.645.

Question e:

We have that to find our \(\alpha\) level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\(\alpha = \frac{1 - 0.94}{2} = 0.03\)

Now, we have to find z in the Z-table as such z has a p-value of \(1 - \alpha\).

That is z with a pvalue of \(1 - 0.03 = 0.97\), so Z = 1.88.

Answer: I think the answer is B

Step-by-step explanation:

Answer:

Hey, I think you've done this already!

Step-by-step explanation:

Answer:

brainliest

Step-by-step explanation:

Answer:7 x 2 − 14 x + 5

Step-by-step explanation:

1 In general, given a{x}^{2}+bx+cax  

2

+bx+c, the factored form is:

a(x-\frac{-b+\sqrt{{b}^{2}-4ac}}{2a})(x-\frac{-b-\sqrt{{b}^{2}-4ac}}{2a})

a(x−  

2a

−b+  

b  

2

−4ac

​

​

)(x−  

2a

−b−  

b  

2

−4ac

​

​

)

2 In this case, a=7a=7, b=-14b=−14 and c=5c=5.

7(x-\frac{14+\sqrt{{(-14)}^{2}-4\times 7\times 5}}{2\times 7})(x-\frac{14-\sqrt{{(-14)}^{2}-4\times 7\times 5}}{2\times 7})

7(x−  

2×7

14+  

(−14)  

2

−4×7×5

​

​

)(x−  

2×7

14−  

(−14)  

2

−4×7×5

​

​

)

3 Simplify.

7(x-\frac{14+2\sqrt{14}}{14})(x-\frac{14-2\sqrt{14}}{14})

7(x−  

14

14+2  

14

​

​

)(x−  

14

14−2  

14

​

​

)

4 Factor out the common term 22.

7(x-\frac{2(7+\sqrt{14})}{14})(x-\frac{14-2\sqrt{14}}{14})

7(x−  

14

2(7+  

14

​

)

​

)(x−  

14

14−2  

14

​

​

)

5 Simplify  \frac{2(7+\sqrt{14})}{14}  

14

2(7+  

14

​

)

​

  to  \frac{7+\sqrt{14}}{7}  

7

7+  

14

​

​

.

7(x-\frac{7+\sqrt{14}}{7})(x-\frac{14-2\sqrt{14}}{14})

7(x−  

7

7+  

14

​

​

)(x−  

14

14−2  

14

​

​

)

6 Simplify  \frac{7+\sqrt{14}}{7}  

7

7+  

14

​

​

  to  1+\frac{\sqrt{14}}{7}1+  

7

14

​

​

.

7(x-(1+\frac{\sqrt{14}}{7}))(x-\frac{14-2\sqrt{14}}{14})

7(x−(1+  

7

14

​

​

))(x−  

14

14−2  

14

​

​

)

7 Remove parentheses.

7(x-1-\frac{\sqrt{14}}{7})(x-\frac{14-2\sqrt{14}}{14})

7(x−1−  

7

14

​

​

)(x−  

14

14−2  

14

​

​

)

8 Factor out the common term 22.

7(x-1-\frac{\sqrt{14}}{7})(x-\frac{2(7-\sqrt{14})}{14})

7(x−1−  

7

14

​

​

)(x−  

14

2(7−  

14

​

)

​

)

9 Simplify  \frac{2(7-\sqrt{14})}{14}  

14

2(7−  

14

​

)

​

  to  \frac{7-\sqrt{14}}{7}  

7

7−  

14

​

​

.

7(x-1-\frac{\sqrt{14}}{7})(x-\frac{7-\sqrt{14}}{7})

7(x−1−  

7

14

​

​

)(x−  

7

7−  

14

​

​

)

10 Simplify  \frac{7-\sqrt{14}}{7}  

7 7−  14  to  1-\frac{\sqrt{14}}{7}1−  7 14

7(x-1-\frac{\sqrt{14}}{7})(x-(1-\frac{\sqrt{14}}{7}))

7(x−1−  7 /14 )(x−(1−  7 14 )) 11 Remove parentheses.

7(x-1-\frac{\sqrt{14}}{7})(x-1+\frac{\sqrt{14}}{7})

7(x−1−  7/ 14 .7(x−1+ 7 14 )