Determine whether each relationship represented by the
ordered pairs is a function. Select all that apply.
O (1,1), (2,2), (3,3), (4,4), (5,5)
O (1,2), (2,3), (3,4),(4,5), (5,6)
O (2,2), (3,1), (5,7), (8,9), (9,8)
(1,2), (3,4), (5,6), (7,8), (9,10)
O (2,2), (3,1), (2,7), (8,9), (7,8)

Never true;

The sum of two irrational numbers is irrational

Always true;

The sum of two rational numbers is rational

The product of two rational numbers is rational

Sometimes true;

The product of two irrational numbers is irrational

Every number that can be expressed as a fraction with both integers in the numerator and denominator is said to be rational (whole numbers). Numerator cannot be zero.

Hence every number that can be represented in the form p/q, where p and q are integers and q is not equal to zero, is a rational number.

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The degree of the denominator is 2 + 2 = 4, that is, the degree is 4.

The poles are 1 and the zeros found above.

(a) The degree of the numerator and denominator is as follows; Degree of Numerator

The degree of the numerator is

1 + 0 = 1, that is, the degree is 1. Degree of Denominator

The degree of the denominator is 2 + 2 = 4, that is, the degree is 4.

(b) Finding Zeros and PolesFor the denominator to be equal to zero, we solve the quadratic equation using the quadratic formula thus;s² + 2s +5 = 0, where a = 1, b = 2 and c = 5

Therefore, applying the quadratic formula;`s= \((-b \pm \sqrt(b^2 - 4ac))/2a=(-2 \pm \sqrt(4 - 20))/2= (-1 \pm 2i)\)

Thus, the zeros of the Laplace transform are -1 + 2i and -1 - 2i.

For the poles, the denominator factors to be;(s − 1)2 (s₂ + 2s + 5)

thus, the poles are 1 and the zeros found above.

(c) Find the inverse Laplace transform of F(s)

The inverse Laplace transform of F(s) is given by;`f(t) = \(L^{-1}(F(s))\)`

where `L^{-1}` is the inverse Laplace transform.

We use partial fraction decomposition to obtain the inverse Laplace transform of F(s).

We have;F(s) = `5S/(S-1)²(s^2 + 2s +5)`= `A/(s-1)^2 + (Bs+C)/(s^2 + 2s +5)`where A, B, and C are constants.

To find A, we multiply both sides of the equation by (s-1)^2 and substitute s = 1, thus,

`5 = \(A/(1-1)^2 + (B+C)/(1^2 + 2(1) +5)`= A/1 + (B+C)/8A = 5B + 5C\)

To find B and C, we multiply both sides of the equation by (s^2 + 2s + 5), thus;`

5s = \(A(s^2 + 2s + 5) + (Bs+C)(s-1)^2\)`

We substitute s = -1 + 2i into the equation above to find B and

C`5(-1 + 2i) = \(A((-1 + 2i)^2 + 2(-1 + 2i) + 5) + (B+C)((-1 + 2i) - 1)^2\)`

Substitute s = -1 - 2i into the equation above to find B and C`

5(-1 - 2i) = \(A((-1 - 2i)^2 + 2(-1 - 2i) + 5) + (B+C)((-1 - 2i) - 1)^2\)`

Solving the above equation simultaneously, we find that A = 1, B = -3/4, and C = 7/4

Therefore,F(s) = \(`1/(s-1)^2 - 3/4(s+1)/(s^2 + 2s +5) + 7/4(1-2i)/(s^2 + 2s +5) - 7/4(1+2i)/(s^2 + 2s +5)\)`

The inverse Laplace transform of the above equation is given by;

`\(f(t) = L^{-1}(F(s))\)`

= `\(L^{-1}(1/(s-1)^2) - 3/4 L^{-1}((s+1)/(s^2 + 2s +5)) + 7/4 L^{-1}((1-2i)/(s^2 + 2s +5)) - 7/4 L^{-1}((1+2i)/(s^2 + 2s +5))\)

`Using the table of inverse Laplace transforms, we can solve for each term as follows;

\(L^{-1}(1/(s-1)^2)` = t.e^t L^{-1}((s+1)/(s^2 + 2s +5))\)

= `\(e^{-t/2}sin(5^{0.5}/2 t)` `L^{-1}((1-2i)/(s^2 + 2s +5))\)`

= `\(e^{-t/2}cos(5^{0.5}/2 t) - 2ie^{-t/2}sin(5^{0.5}/2 t)` `L^{-1}((1+2i)/(s^2 + 2s +5))\)`

= `\(e^{-t/2}cos(5^{0.5}/2 t) + 2ie^{-t/2}sin(5^{0.5}/2 t)\)

Therefore,

`\(f(t) = t.e^t - 3/4 e^{-t/2}sin(5^{0.5}/2 t) + 7/4 (e^{-t/2}cos(5^{0.5}/2 t) - 2ie^{-t/2}sin(5^{0.5}/2 t)) - 7/4 (e^{-t/2}cos(5^{0.5}/2 t) + 2ie^{-t/2}sin(5^{0.5}/2 t))\)`

Simplify the above equation`\(f(t) = t.e^t - 1/2 e^{-t/2}sin(5^{0.5}/2 t) - 7/2 ie^{-t/2}sin(5^{0.5}/2 t)\)`

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Answer:

\(x = \frac{(ln8)}{(ln7)} \)

Step-by-step explanation:

Solve for x

Take the logarithm of both sides of the equation to remove the variable from the exponent. We have:

\(ln(7x) = ln(8)\)

Expand

\(ln(7)\)

by moving x outside the logarithm. It becomes:

\(x \: ln(7) = ln(8)\)

Divide each term in

\(x \: ln(7) = ln(8) \: by \: ln(7)\)We have:

\( \frac{x \: ln(7)}{ln(7)} = \frac{ln(8)}{ln(7)} \)

:. Exact form:

\( \frac{ln(8)}{ln(7)} \)

The equation that represents Angel's pay in fees based on their number of ATM withdrawals y = 3 + 5x

Information from the question are

Angel's bank allows them 3 free ATM withdrawals each month

then charges a $5 ATM fee

Angel will pay in fees = y

number of ATM withdrawals = x

The Angel's bank  ATM withdrawals can be modeled as a linear function

A linear function consists of functions where the variables has exponents of 1. The graph of linear functions is a straight line graph and the relationship is expressed in the form.

y = 3 + 5x

Definition of variables to suit Angel's bank  ATM withdrawals

y = Angel will pay in fees

$5 = charges per withdrawal

x = number of ATM withdrawals

3 = free ATM withdrawals each month

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Answer:

im pretty sure it would be 9 bc there are 3 dif colours and 3 dif finishes and u j count the table

Step-by-step explanation:

Answer:

distance = 7.07 units

Step-by-step explanation:

x difference = 7

y difference = -1

using the Pythagorean theorem:

7² + -1² = d²

d² = 49 + 1 = 50

d = 7.07

Answer:

7.1

Step-by-step explanation:

distance between the x is 7 and y is 1

And to find the hypotenuse, you use the quadratic formula, 7^2 + 1^2 = c^2

c=50

and take the square root, which is 7.071, rounds to 7.1

To generate a simple random sample of three books for a literature course, the following processes can be used:

1. Assign a unique identifier number to each book on the list.

2. Use a random number generator to select three numbers between 1 and the total number of books on the list.

3. Identify the books that correspond to the selected numbers to obtain a simple random sample of size three from the list.

A simple random sample is a subset of a population that is selected randomly and without bias. To generate a simple random sample of three books for a literature course, the following processes can be used:

1. Assign a unique identifier number to each book on the list. For instance, if the list of classic works of literature includes 20 books, each book can be assigned a unique number from 1 to 20. This process ensures that each book has an equal chance of being selected.

2. Use a random number generator to select three numbers between 1 and the total number of books on the list. For example, a random number generator can be used to generate three numbers between 1 and 20. The random numbers generated should be unique and without bias. This process ensures that each book combination has an equal chance of being selected.

3. Identify the books that correspond to the selected numbers to obtain a simple random sample of size three from the list. Once the random numbers have been generated, the books that correspond to the selected numbers should be identified. These books will make up the simple random sample of size three from the list.

To obtain a simple random sample of size three from the following list of classic works of literature, the above process can be used:

1. To assign a unique identifier number to each book on the list, each book can be assigned a number from 1 to 9 as follows:

1. Wuthering Heights by Emily Bronte

2. The Great Gatsby by F. Scott Fitzgerald

3. Pride and Prejudice by Jane Austen

4. To Kill a Mockingbird by Harper Lee

5. Jane Eyre by Charlotte Bronte

6. Crime and Punishment by Fyodor Dostoevsky

7. The Catcher in the Rye by J.D. Salinger

8. Frankenstein by Mary Shelley

9. The Picture of Dorian Gray by Oscar Wilde

2. To use a random number generator to select three numbers between 1 and the total number of books on the list, a random number generator can be used to generate three numbers between 1 and 9. Suppose the following numbers are generated: 2, 4, 8.

3. To identify the books that correspond to the selected numbers to obtain a simple random sample of size three from the list, the books that correspond to the selected numbers are:

2. The Great Gatsby by F. Scott Fitzgerald

4. To Kill a Mockingbird by Harper Lee

8. Frankenstein by Mary Shelley

Thus, the simple random sample of size three from the list is The Great Gatsby by F. Scott Fitzgerald, To Kill a Mockingbird by Harper Lee, and Frankenstein by Mary Shelley.

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Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = \(\frac{9}{7+9}\times (x)\)

                                      = \(\frac{9}{16}\times (x)\)

And the weight of zinc = \(\frac{7}{7+9}\times (x)\)

                                      = \(\frac{7}{16}\times (x)\)

If the weight of zinc = 31.5 kg

31.5 = \(\frac{7}{16}\times (x)\)

x = \(\frac{16\times 31.5}{7}\)

x = 72 kgs

Therefore, weight of copper = \(\frac{9}{16}\times (72)\)

                                               = 40.5 kgs

2). i). 2 : 3 = \(\frac{2}{3}\)

        4 : 5 = \(\frac{4}{5}\)

Now we will equalize the denominators of each fraction to compare the ratios.

\(\frac{2}{3}\times \frac{5}{5}\) = \(\frac{10}{15}\)

\(\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}\)

Since, \(\frac{12}{15}>\frac{10}{15}\)

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = \(\frac{11}{19}\)

    19 : 21 = \(\frac{19}{21}\)

By equalizing denominators of the given fractions,

\(\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}\)

And \(\frac{19}{21}\times \frac{19}{19}=\frac{361}{399}\)

Since, \(\frac{361}{399}>\frac{231}{399}\)

Therefore, 19 : 21 > 11 : 19

iii). \(\frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}\)

             \(=\frac{3}{2}\)

     \(\frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}\)

              = \(\frac{4}{3}\)

Now we equalize the denominators of the fractions,

\(\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}\)

And \(\frac{4}{3}\times \frac{2}{2}=\frac{8}{6}\)

Since \(\frac{9}{6}>\frac{8}{6}\)

Therefore, \(\frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4}\) will be the answer.

IV). \(1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}\)

                  \(=\frac{6}{5}\times \frac{3}{4}\)

                  \(=\frac{18}{20}\)

                  \(=\frac{9}{10}\)

Similarly, \(\frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}\)

                       \(=\frac{4}{15}\)                  

By equalizing the denominators,

\(\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}\)

Similarly, \(\frac{4}{15}\times \frac{20}{20}=\frac{80}{300}\)

Since \(\frac{270}{300}>\frac{80}{300}\)

Therefore, \(1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}\)

V). If a : b = 6 : 5

     \(\frac{a}{b}=\frac{6}{5}\)

        \(=\frac{6}{5}\times \frac{2}{2}\)

        \(=\frac{12}{10}\)

  And b : c = 10 : 9

  \(\frac{b}{c}=\frac{10}{9}\)

 Since a : b = 12 : 10

 And b : c = 10 : 9

 Since b = 10 is common in both the ratios,

 Therefore, combined form of the ratios will be,

 a : b : c = 12 : 10 : 9

To find σg(X)^2, we need to calculate the variance of the function g(X) = 4X^2 + 2, where X is a random variable with a given density function. The density function is defined as f(x) = (3/2)(x + 1) for 0 ≤ x and 0 elsewhere. By calculating the variance of g(X), we can determine the value of σg(X)^2.

To calculate the variance of g(X), we first need to find the mean of g(X), denoted as E[g(X)]. For a continuous random variable, the mean is calculated as the integral of the function multiplied by the density function. In this case, we have:

E[g(X)] = ∫(4X^2 + 2) * f(x) dx

Substituting the given density function, we have:

E[g(X)] = ∫(4X^2 + 2) * (3/2)(X + 1) dx

After simplifying and evaluating the integral, we can find the value of E[g(X)].

Next, we calculate the variance of g(X), denoted as Var[g(X)]. The variance is calculated as the expectation of the squared difference between g(X) and its mean, E[g(X)]^2. In mathematical terms:

Var[g(X)] = E[(g(X) - E[g(X)])^2]

By substituting the values of g(X) and E[g(X)], we can evaluate this expression and find the value of Var[g(X)].

Finally, to find σg(X)^2, we take the square root of Var[g(X)], i.e., σg(X) = √Var[g(X)]. After calculating Var[g(X)], we can determine the value of σg(X) to three decimal places as needed.

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The reason for the first and second steps in the equation are Addition Property of Equality and Division Property of Equality respectively

An equation is a mathematical statement that shows that two expressions are equal. It consists of two expressions separated by an equal sign (=) e.g. 2x + 3 = 7

Given: the equation 3x-2=4

Match the reason with the correct step in the equation as follows:

3x-2= 4

Add to 2 to both sides of the equation:

3x-2+2 = 4+2    (Addition Property of Equality)

3x = 6

Divide both sides by 3:

3x/3 = 6/3        (Division Property of Equality)

x = 2

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The value of x from the expression 3/4 x +3-2x = -1/4 +1/2x+5 can be simplified as 45/29.

The concept that will be used is simplification. To simplify simply means to make anything easier. In mathematics, simplifying an equation, fraction, or problem means taking it and making it simpler. Calculations and problem-solving techniques simplify the issue.

3/4x +3-2x = -1/4 +1/2x+5

We can simplify by collecting the like terms,

3/4x - 1/2x - 2x = -1/4 + 5 -3

Then we can simplify further as:

-29x/20 = - 9/4

29x = (20*9)/4

29x= 45

x= 45/29

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When a thesis test is being performed for a population mean, the probability of a type II error isn't dependent on the sample mean. Option B is the right answer.

A type II error occurs when a null thesis isn't rejected despite it being incorrect. It's worth noting that the threat of making a type II error is affected by several factors, including the sample size, the true population mean, the position of significance, and the variability of the data.

As a result, the larger the sample size, the lower the threat of making a type IIerror.The true population mean also has an impact on the liability of a type II error. As the difference between the true mean and the hypothecated mean grows, the threat of a type II error decreases.

The position of significance is also pivotal in determining the threat of a type II error. As the significance position increases, the threat of a type II error decreases.

So, the correct answer is B

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Answer:

\(X=-2\frac{2}{5}\)

Step-by-step explanation:

1/2(x+2)=-1/3(x+3)

1/2x+1=-1/3x-1

           +1/3x

5/6x+1=-1

      -1.  -1

5/6x=-2

/5/6.   /5/6

x=-2*6/5

x=-12/5

x= -2 2/5

Hopes this helps please mark brainliest

Answer: I think its .012

hope this helps

Answer:

0.012

Step-by-step explanation:

Answer:

x=11

Step-by-step explanation:

The sum of the angles of a triangle is 180

We know the angle with a box is 90

90 + 5x-2  + 3x+4 = 180

Combine like terms

8x +92 = 180

Subtract 92 from each side

8x+92-92 = 180-29

8x = 88

Divide each side by 8

8x/8 = 88/8

x = 11

Answer:

The correct answers are;

4 * 3 1/4

3 1/4 + 3 1/4 + 3 1/4 + 3 1/4

13/4 + 13/4 + 13/4 + 13/4

Step-by-step explanation:

Given 4 ropes each 3 1/4 feet long

1 rope = 3 1/4 feet long

4 ropes = x

cross multiply

1 * x = 4 * 3 1/4

x = 4 * 3 1/4

Since 3 1/4 is in 4 places, the total length can also be expressed as;

3 1/4 + 3 1/4 + 3 1/4 + 3 1/4

We can also rewrite as an improper fraction

Since 3 1/4 = 13/4

Total length = 13/4 + 13/4 + 13/4 + 13/4

In T3 and T4, LOCK-EXCLUSIVE(A) is used to acquire an exclusive lock on tuple A for writing. After the write operation, U(A) is used to release the lock on A.

To perform the LOCKING related operations in the given transactions, we need to consider the transactions and their respective operations on the tuples in R(A). Here are the locking operations for each transaction:

Transaction T1:

LOCK-SHARED(A)

READ(A)

U(A)

Transaction T2:

LOCK-SHARED(A)

READ(A)

U(A)

Transaction T3:

LOCK-EXCLUSIVE(A)

WRITE(A)

U(A)

Transaction T4:

LOCK-EXCLUSIVE(A)

WRITE(A)

U(A)

In T1 and T2, LOCK-SHARED(A) is used to acquire a shared lock on tuple A for reading. After the read operation, U(A) is used to release the lock on A.

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a) Using the Euclidean algorithm, we can find gcd (707,413) as follows:707 = 1 · 413 + 294413 = 1 · 294 + 119294 = 2 · 119 + 562119 = 2 · 56 + 71356 = 4 · 71 + 12 71 = 5 · 12 + 11 12 = 1 · 11 + 1

Thus, gcd (707,413) = 1.

We can find the coefficients s and t that solve the equation 707s + 413t

= 1 as follows:1 = 12 - 11 = 12 - (71 - 5 · 12) = 6 · 12 - 71 = 6 · (119 - 2 · 56) - 71

= - 12 · 56 + 6 · 119 - 71

= - 12 · 56 + 6 · (294 - 2 · 119) - 71 = 18 · 119 - 12 · 294 - 71

= 18 · 119 - 12 · (413 - 294) - 71 = 30 · 119 - 12 · 413 - 71

= 30 · (707 - 1 · 413) - 12 · 413 - 71 = 30 · 707 - 42 · 413 - 71

Thus, s = 30, t = -42. So we have found that 707(30) + 413(−42) = 1.

b) Since 707s + 413t = 1 and 9 does not divide 1, the equation 707x + 413y = 9 has no integer solutions. Therefore, we can conclude that there are no such integers x and y.

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Answer:

angle 4 is 47 degrees....

Answer:

not enough information

Side of the cube = 2 cm

Width of the rectangular prism = 9 cm

Length of the rectangular prism = 9cm

Height of the rectangular prism = 4 cm

Now,

The volume of total water (submerged cube)

= width of the rectangular prism x length of the rectangular prism x height of the cube

= 9 x 9 x 2 = 162 cm^3

As we know that 1 cm^3 = 1ml

So,

162 cm^3 = 162 ml

Hence the volume of water required to fill the prism such that the cube is submerged is 162 ml.

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a. Approximately 95.45% of the observations are expected to lie between 125 and 225 in a normal distribution with a mean of 150 and a standard deviation of 25.

b. Approximately 81.85% of the observations are expected to lie between 75 and 200 in the same normal distribution.

a. To find the percentage of observations between 125 and 225, we calculate the z-scores for these values using the formula z = (x - μ) / σ, where x is the value, μ is the mean, and σ is the standard deviation. The z-score for 125 is (125 - 150) / 25 = -1, and the z-score for 225 is (225 - 150) / 25 = 3. We then look up the corresponding area under the normal distribution curve using a z-table or calculator. The area between -1 and 3 is approximately 0.9545, which corresponds to 95.45%.

b. Similarly, to find the percentage of observations between 75 and 200, we calculate the z-scores for these values. The z-score for 75 is (75 - 150) / 25 = -3, and the z-score for 200 is (200 - 150) / 25 = 2. We find the area between -3 and 2 under the standard normal distribution curve, which is approximately 0.8185 or 81.85%.

c. A data value of 107 would be considered unusual if it falls more than a few standard deviations away from the mean. To determine if it is unusual, we calculate the z-score for 107 using the formula (107 - 150) / 25 = -1.72. If we consider values outside the range of ±2 standard deviations as unusual, then 107 falls within this range and would not be considered unusual.

d. Similarly, for a data value of 206, the z-score is (206 - 150) / 25 = 2.24. Since it falls within the range of ±2 standard deviations, it would not be considered unusual.

e. The Range Rule of Thumb suggests that for a small sample size, the estimated standard deviation is approximately the range divided by 4. In this case, the range is 210 - 90 = 120, so the estimated standard deviation would be 120 / 4 = 30.

f. For a large sample size, the estimated standard deviation using the Range Rule of Thumb is approximately the range divided by 6. Therefore, the estimated standard deviation would be 120 / 6 = 20.

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Answer:

(a) $ 7000

(b) $ 5600

Step-by-step explanation:

discount = 20%

20% = $1400

1% = 1400/20

original price = 100%

= 1400/20 × 100

= $7000

sale price = 80%

= 1400/20 × 80

= $5600

The f-value having an area of 0.975 to its left is the critical value of the F-distribution with degrees of freedom (df1 = 1, df2 = infinity) or (df1 = infinity, df2 = 1). This value is approximately 3.84.

The F-distribution is a probability distribution that arises in the analysis of variance (ANOVA) and other statistical tests. It is a continuous distribution that takes values greater than or equal to zero. The distribution has two parameters, the degrees of freedom (df1 and df2), which depend on the sample sizes and the number of groups in the ANOVA.The critical value of the F-distribution is the value that separates the rejection region (where the null hypothesis is rejected) from the non-rejection region (where the null hypothesis is not rejected). The critical value depends on the level of significance (alpha), which is usually set at 0.05 or 0.01, and the degrees of freedom.

In this case, we want to find the critical value of the F-distribution with an area of 0.975 to its left. This means that the area to the right of the critical value is 0.025. Using a table of the F-distribution or a statistical software, we can find that the critical value with (df1 = 1, df2 = infinity) or (df1 = infinity, df2 = 1) is approximately 3.84. Therefore, if the calculated F-value is greater than 3.84, we can reject the null hypothesis with a significance level of 0.05 and conclude that there is a significant difference between the groups in the ANOVA.

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Answer:

BA ≈ 410.1 m

Step-by-step explanation:

using the tangent ratio in the right triangle

tan34° = \(\frac{opposite}{adjacent}\) = \(\frac{BA}{BC}\) = \(\frac{BA}{608}\) ( multiply both sides by 608 )

608 × tan34° = BA , then

BA ≈ 410.1 m ( to the nearest tenth )

Answer:

option A

Step-by-step explanation:

Option A is 1,050 in total

option B is 1,400 in total

option C is 1,100 in total

that's my go at it

Divide both numbers by 2:

34/2 = 17

78/2 = 39

34/78 = 17/39

Answer:

Find GCD (Greatest Common Factor) for both numerator & denominator.

The GCF for 34 & 78 is 2

step 3 divide the numerator & denominator by GCD 2 and rewrite the fraction

= (34/2) / (78/2)

= 17/39

Thus, 17/39 is the simplified fraction for 34/78 by using the GCD or HCF method

Step-by-step explanation:

Answer:

40.21 m is the circle's cirumference.

Decision points

are represented in the flowchart using a diamond symbol. Answer: D. Diamond.

A

flowchart

is a kind of diagram that is used to represent an algorithm, workflow, or process. A flowchart comprises different shapes, which represent distinct steps or activities in a procedure. Flowcharts are used in different fields, such as education,

engineering

, programming, and business, to demonstrate decision making, problem-solving, process control, and project management.

Flowcharts are used to:

Visualize

processes and workflows that need to be organized or improved

Communicate a sequence of steps that are essential to complete a project

Identify the root cause of a problem

Illustrate the steps of a procedure to new employees or staff members

A decision point in a flowchart is a point where the sequence of flowchart changes its direction based on the

outcomes

of the preceding steps. Decision points are represented in the flowchart using a diamond symbol.

Learn more about

flowchart

from:

https://brainly.com/question/19130837

#SPJ11