Determine whether the following system with input x[n] and output y[n], is linear or not: y[n] =3ử?[n] +2x[n – 3 Determine whether the following system with input x[n] and output y[n], is time-invariant or not. n y[n] = Σ *[k] k=18

Answer: Can't help

Explanation:

Answer:

Burj Khalifa

Explanation:

The world's tallest artificial structure is the 829.8-metre-tall (2,722 ft) Burj Khalifa in Dubai (of the United Arab Emirates). The building gained the official title of "tallest building in the world" and the tallest self-supported structure at its opening on January 9, 2010.

a brainliest would be appriciated

Answer:

Burj khalifa

Explanation:

829.8 meters tall

Two examples of judgment errors related to anchoring and adjustment are the anchoring effect in pricing and the anchoring effect in negotiations.

The anchoring effect in pricing occurs when consumers base their perception of a product's value on the initial price they see. For example, if a store initially sets a high price for a product and then offers a discount, consumers may perceive the discounted price as a great deal even if it is still higher than the product's actual value. The initial high price acts as an anchor, influencing the consumer's judgment.

The anchoring effect in negotiations occurs when the first offer made in a negotiation sets the reference point for further negotiations. For instance, if a seller sets a high initial asking price, it can anchor the buyer's perception of the item's value and influence subsequent offers. The buyer may adjust their offer based on the initial anchor, potentially leading to higher final prices.

In both examples, the initial anchor (the initial price or offer) influences subsequent judgments or decisions, demonstrating the anchoring and adjustment bias.

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Answer:2%

When the voltages between the three phases are not equal, the current increases dramatically in the motor winding's, and if allowed to continue, the motor will be damaged.

Explanation:

The displacement of end D with respect to end A is \(-0.488 \times 10^{-3}\;m\)

Given the following data:

To determine the displacement of end D with respect to end A:

First of all, we would do a sectional cut of the circular rods at point A and then determine the sum of forces acting on it:

\(\sum F=0\\\\ 10000+N_1=0\\\\N_1 = -10000\;N\)

Mathematically, the displacement of a circular rod is given by this formula:

\(d = \frac{NL}{AE}\)

Where:

Substituting the given parameters into the formula, we have;

\(d_1 = \frac{-10000 \times 0.435}{\frac{3.142 \times 0.02^2}{4} \times 68.9 \times 10^9} \\\\d_1 = \frac{-4350}{0.0003142 \times 68.9 \times 10^9}\\\\d_1 =-0.201 \times 10^{-3}\;meter\)

For section cut BC:

\(\sum F=0\\\\ 10000-20000+N_2=0\\\\N_2 = 10000\;N\)

\(radius = outer\;radius^2 - inner\;radius^2\\\\radius = 0.04^2 -0.03^2=0.0007\;m\)

\(d_2 = \frac{10000 \times 0.435}{\frac{3.142 \times 0.0007^2}{4} \times 68.9 \times 10^9} \\\\d_2 = \frac{4350}{0.00054985 \times 68.9 \times 10^9}\\\\d_2 =0.115 \times 10^{-3}\;meter\)

For section cut D:

\(\sum F=0\\\\ -20000-N_3=0\\\\N_3 =- 20000\;N\)

\(d_3 = \frac{-20000 \times 0.435}{\frac{3.142 \times 0.02^2}{4} \times 68.9 \times 10^9} \\\\d_3 = \frac{-8700}{0.0003142 \times 68.9 \times 10^9}\\\\d_3 =-0.402 \times 10^{-3}\;meter\)

For the total displacement:

The total displacement is equal to the displacement of end D with respect to end A.

\(d_T = d_1 +d_2+d_3\\\\d_T = -0.201 \times 10^{-3} + 0.115 \times 10^{-3}-0.402 \times 10^{-3}\\\\d_T = -0.488 \times 10^{-3}\;m\)

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Answer:

end mill 4 flute

Explanation:

you can simply hook it up

(a) To find the time when the velocity is again zero, we set the velocity equal to 0 and solve for t:

0 = v0 + at = 9t - 3t^3

Solving for t, we find that t = ±1.

(b) To find the position and velocity when t = 4 s, we first need to find the velocity equation by integrating the acceleration equation:

v = ∫a = ∫(9 - 3t^2)dt = 9t - t^3 + C

Using the initial condition v(0) = 0, we find C = 0 and

v(t) = 9t - t^3

Next, we integrate v(t) to find the position equation:

x = ∫v = ∫(9t - t^3)dt = 3t^2 - t^4 + C

Using the initial condition x(0) = 5, we find C = 5 and

x(t) = 3t^2 - t^4 + 5

Evaluating x(t) and v(t) at t = 4 s, we have:

x(4) = 3(4^2) - 4^4 + 5 = 51

v(4) = 9(4) - 4^3 = -36

(c) To find the total distance travelled by the particle from t = 0 to t = 4 s, we need to find the distance between the initial and final positions:

d = x(4) - x(0) = 51 - 5 = 46 ft

So the total distance travelled by the particle from t = 0 to t = 4 s is 46 ft.

Given the involvement of numerous agencies or jurisdictions, the serious risk to the public's safety, and the activation of the Operations and Planning Sections, this incident would be categorised as a Type 3.

Additionally, they handle issues that span several operational periods and demand detailed Incident Action Plans (IAP). In situations like a tornado landing, earthquake, flood, or prolonged hostage or siege, an all-hazard (Type 3) IMT may be used.

A Type 3 Incident Management Team (IMT) or incident command organisation handles initial action incidents that require a significant amount of resources, extended attack incidents that continue until containment or control is achieved, or expanding incidents that continue until a Type 1 or Type 2 team is called in.

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Personal watercraft, also known as water scooters or Jet Skis, are considered a type of recreational vessel.

What is recreational vessel?

A recreational vessel is any type of watercraft that is used for leisure and recreational activities, rather than for commercial or military purposes. Some examples of recreational vessels include sailboats, powerboats, personal watercraft, houseboats, and recreational fishing boats.

Recreational vessels come in a wide range of sizes, from small inflatable rafts to large luxury yachts, and can be powered by different means, such as sail, human power, internal combustion engines, or electric motors.

Personal watercraft, also known as water scooters or Jet Skis, are considered a type of recreational vessel. They are small, lightweight watercraft that are powered by an internal combustion engine or an electric motor and are designed for one or two people.

They are called personal watercraft because of their small size and the fact that they are intended for personal use, typically for recreation and leisure activities such as water skiing, wakeboarding, and leisure cruising. They are operated by standing or sitting on the watercraft, and steering and accelerating are typically done with handlebars, similar to a motorcycle.

Personal watercraft are subject to different regulations compared to other types of vessels, such as larger boats and ships, due to their size, speed, and maneuverability. For example, they may have specific rules regarding minimum age of the operator, required safety equipment, and speed limits in certain areas.

In summary, personal watercraft are considered a type of recreational vessel designed for personal use, with specific regulations and rules due to their unique characteristics.

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Both Technician A and Technician B are correct in their statements.

Technician A is correct in stating that engine vacuum is typically measured in inches of mercury (in. Hg).

Engine vacuum refers to the difference in pressure between the inside and outside of the engine. It is commonly measured using a vacuum gauge, and the unit of measurement is inches of mercury.

The vacuum gauge displays the amount of vacuum present in the engine by measuring how far the pressure deviates below atmospheric pressure, which is typically expressed in inches of mercury.

Technician B is also correct in stating that a pressure gauge labeled psig (pounds per square inch gauge) will read 14.7 psi (pounds per square inch) at sea level.

The abbreviation "psig" indicates that the pressure is measured relative to atmospheric pressure. At sea level, atmospheric pressure is approximately 14.7 psi.

Therefore, a pressure gauge labeled psig will read 14.7 psi when the pressure being measured is equal to atmospheric pressure.

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Answer:

Static Equilibrium.....

Explanation:

When all the forces that act upon an object are balanced, then the object is said to be in a state of equilibrium.....

Answer:

its c

Explanation:

n

e

g

r

o

means black in spanish!

In a case whereby a school bus with its flashing red signals on has stopped on a non-divided highway then  you must stop until the signal lights are no longer flashing and all passengers have cleared the roadway.

The function of red light in traffic rules is to tell the other road user that they should stop for a while to tell them thaqt there is a danger.

It should be noted that In a case whereby a school bus with its flashing red signals on has stopped on a non-divided highway then  you must stop until the signal lights are no longer flashing and all passengers have cleared the roadway.

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You should not back a tractor under a trailer until the whole air system is fully charged and operating properly. This is because the air system is a crucial component of a tractor-trailer combination and is responsible for providing the necessary pressure to operate the brakes on both the tractor and trailer.

Without a properly functioning air system, the brakes may not work properly, which can result in a loss of control of the vehicle and potentially serious accidents.Before backing a tractor under a trailer, it is important to perform a pre-trip inspection to ensure that the air system is working properly. This involves checking the air pressure in the system, inspecting the hoses and connections for damage or leaks, and ensuring that the valves are properly aligned.Once the air system has been inspected and deemed to be in good working order, the tractor can be backed under the trailer. However, it is important to note that the process should be done slowly and carefully to ensure that the trailer is properly aligned with the tractor and that the air lines are properly connected.In conclusion, it is important to never back a tractor under a trailer until the whole air system is fully charged and operating properly. Performing a pre-trip inspection and taking the process slowly and carefully can help ensure a safe and successful backing procedure.

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Answer:

a. The rate of loss of entropy from the high-temperature reservoir is 1.2 MJ/s x (1 - 0.35) = 0.78 MJ/s, and the rate of gain of entropy by the low-temperature reservoir is 1.2 MJ/s x 0.35 = 0.42 MJ/s.

b. The work done by the engine is 1.2 MJ/s x 0.35 = 0.42 MW.

c. The total entropy gain of the system is 0.42 MJ/s x (1000 K - 308 K) = 124.8 MJ/s.

d.  = 83 MJ/s

Explanation:

We can simply convert each final state to a nonfinal state and change each nonfinal state to a final state. In this case the changed automaton recognizes the complement of the set l.

An automaton is a relatively self-operating machine, or control mechanism, created to automatically carry out a set of tasks, or react to predetermined instructions. Some automata, like the bellstrikers in mechanical clocks, are made to appear as though they are driven by their own will to the untrained eye.

The phrase has a long history of being used to describe automatons that are made to amuse or impress people and that move like living, breathing humans or animals.

The portrayal of characters in movies and theme park attractions frequently uses animatronics, a modern type of automata with electronics.

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Answer: Why is even here then.

Explanation:

1) The number of gallons of water lost in a week would be approximately (2.3 m³/s * 604,800 seconds) * (1000 liters/m³) * (0.264172 gallons/liter).

2) The density of the copper sample is approximately 8.32 g/cm³ (347.5 g / 41.8 cm³).

To calculate the number of gallons of water lost in a week, we first need to determine the volume of water that flows through the stream in one week.

Given:

Flow rate of the stream = 2.3 m³/s

To convert the flow rate to the volume of water in one week, we need to convert the time unit from seconds to weeks. There are 60 seconds in a minute, 60 minutes in an hour, 24 hours in a day, and 7 days in a week.

1 week = 7 days * 24 hours * 60 minutes * 60 seconds = 604,800 seconds

Volume of water in one week = Flow rate * Time

Volume of water in one week = 2.3 m³/s * 604,800 seconds

Now, let's convert the volume from cubic meters (m³) to gallons.

1 cubic meter = 1000 liters

1 liter = 0.264172 gallons

Volume in gallons = (Volume in cubic meters) * (1000 liters/m³) * (0.264172 gallons/liter)

Finally, we can calculate the number of gallons of water lost in a week.

Volume in gallons = (2.3 m³/s * 604,800 seconds) * (1000 liters/m³) * (0.264172 gallons/liter)

Please note that the flow rate might change due to various factors, but for the given scenario and assumptions, this calculation provides an estimate.

1b) To calculate the density of the copper sample, we'll use the formula:

Density = Mass / Volume

Given:

Mass of the copper sample = 347.5 g

Volume of the copper sample = 41.8 cm³

Density = 347.5 g / 41.8 cm³

=8.32 g/cm³

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Answer:

what's the question?...........

Answer:

attached below

Explanation:

Applying the state transition Formula

state - next = ( state *2 + in ) % 5

how this works : remainder of previous cycle is doubled to enable the calculation of the new remainder.  

Input of current cycle is represented as either 1 or 0

since the dividing number = 5 . possible remainders = 1,2,3,4,0

each remainder is represented as :

S0 = zero remainder , S1 = 1 remainder , S2 = 2 remainder, S3 = 3 remainder,

S4 = 4 remainder

Answer:

190$-200$

Explanation:

Answer:

z=X=c+J=A

Explanation:

The most widely used anchoring line is nylon three-strand line. A is the best choice. Anchor rodes can be entirely made of rope, entirely of chain, or a combination of the two. In this context, the nylon component of the rode is referred to as the "anchor line."

Anchor rodes typically consist of a short length of galvanized chain shackled to a long length of nylon line with an eye splice and a thimble.

The open frameworks anchor of hierarchical conduct information is an anchor of authoritative conduct information. Understanding, explaining, and ultimately enhancing the attitudes and behaviors of individuals and groups within organizations is the focus of the field of study known as organizational behavior knowledge.

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Answer: Rode

Explanation: I took the quiz

Lossless compression is generally not used for movies.

Lossless compression is a technique used to decrease the size of a file without losing any of its data. This means that once the compressed file is uncompressed, the original file will be completely restored. In general, lossless compression is best used for files that cannot afford to lose any data.

A log file, for example, is a record of all events that have occurred on a system or application. The integrity of a log file is crucial for debugging and troubleshooting. Therefore, it is important to ensure that no data is lost when compressing a log file.

An encrypted email is another example of a file that would benefit from lossless compression. Encryption is a method of protecting the privacy of a message. However, if the file is compressed with lossy compression, some of the data may be lost, which could compromise the integrity of the encryption.

In addition, if the file is compressed with lossy compression, the encryption algorithm may not be able to decrypt the file.

A JPEG image is an example of a file that is typically compressed with lossy compression. This is because images are typically less sensitive to data loss.

A movie, on the other hand, is an example of a file that would benefit from lossy compression. Movies are typically large files, and reducing their size can make them easier to store and transfer.

However, the loss of data can be noticeable, especially in fast-paced scenes.

Therefore, lossless compression is generally not used for movies.

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When it comes to driving a car, braking is a very important skill to have. Braking is the process of slowing down or stopping a moving vehicle. Knowing how to brake effectively can be the difference between avoiding a crash and causing one.

Below are the three levels of braking that precede the need to lock up your wheels:

1. Perception braking: This is the first level of braking that precedes the need to lock up your wheels. Perception braking refers to the driver's ability to recognize the need to brake in response to a situation. This type of braking is necessary when you notice a potential hazard on the road, such as a pedestrian, a cyclist, or another car. Perception braking requires that you react quickly to the situation and apply the brakes as soon as possible.

2. Controlled braking: The second level of braking that precedes the need to lock up your wheels is controlled braking. This type of braking requires that you apply the brakes firmly but smoothly. The idea is to slow down the vehicle without locking up the wheels. Controlled braking is essential when you are driving on a wet or slippery road surface, as it allows you to slow down the car without losing control.

3. Threshold braking: The third level of braking that precedes the need to lock up your wheels is threshold braking. This is the most advanced form of braking and requires a lot of skill and experience. Threshold braking involves applying the brakes to the point just before the wheels start to lock up. At this point, the driver eases off the brakes slightly to maintain traction and control. Threshold braking is the most effective form of braking in emergency situations, as it allows the driver to slow down the vehicle quickly without losing control.

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From the given problem, the initial length of the array is 2 and the allocation size is 3. If an item is added when the allocation size equals the array length, a new array with twice the current length is allocated.

After the first operation, the array numList becomes [31, 30, 14] and the length of the array is 3 which is equal to the allocation size. So, a new array with twice the current length, that is an array of size 2*3 = 6 is allocated to the array numList. This new array looks like [31, 30, 14, 0, 0, 0]. Therefore, the length of the array becomes 3 and the allocation size becomes 6.

Similarly, after the second operation, the array becomes [31, 30, 14, 39] and the length of the array is 4 which is not equal to the allocation size so the array remains the same. Therefore, the length of the array is 4 and the allocation size is 6.

After the third operation, the array becomes [31, 30, 14, 39, 66] and the length of the array is 5 which is not equal to the allocation size so the array remains the same. Therefore, the length of the array is 5 and the allocation size is 6.

After the fourth operation, the array becomes [31, 30, 14, 39, 66, 70] and the length of the array is 6 which is equal to the allocation size. So, a new array with twice the current length, that is an array of size 2*6 = 12 is allocated to the array numList. This new array looks like [31, 30, 14, 39, 66, 70, 0, 0, 0, 0, 0, 0]. Therefore, the length of the array becomes 6 and the allocation size becomes 12.

After the fifth operation, the array becomes [31, 30, 14, 39, 66, 70, 42] and the length of the array is 7 which is not equal to the allocation size so the array remains the same. Therefore, the length of the array is 7 and the allocation size is 12.

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