Differentiate between Interchangable and Selective Assembly manufacturing. Explain the Taylor's Priciple of designing the Limit Guages ? Briefly explain different types of Optical Comparators ?

Social engineering is considered as both an art and a science. It is a form of hacking that involves the manipulation of victims through social interaction instead of directly breaking into a computer system.

The logic behind social engineering is simple, if one knows how to trick a person into giving out the data they need, they can easily access all the information and access they need with the least resistance possible. This makes social engineering a crucial part of hacking since it allows hackers to gain access to devices, accounts, or applications without making any additional effort.

By using social engineering tactics, a hacker can access a system without having to go through all the other hijacking tactics up their sleeve.The most challenging part of social engineering is securing trust, which is only possible by getting someone's trust. Hackers use various tactics to predict possible responses from a person whenever they are triggered to perform any action in relation to their security system.

The ability to read possible responses from a person is a significant skill for hackers since it enables them to predict passwords and other valuable computer assets without having to use too many tools. Successful hackers use social engineering as a powerful tool to penetrate a system.

In conclusion, social engineering is an essential component of hacking, and a significant part of its success lies in the art of manipulation.

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Answer:

Under cold air standard conditions, the thermal efficiency of this cycle is 56.9 percent.

Explanation:

From Thermodynamics we remember that thermal efficiency of the ideal Otto cycle (\(\eta_{th}\)), dimensionless, is defined by the following formula:

\(\eta_{th} = 1-\frac{1}{r^{\gamma-1}}\) (Eq. 1)

Where:

\(r\) - Compression ratio, dimensionless.

\(\gamma\) - Specific heat ratio, dimensionless.

Please notice that specific heat ratio under cold air standard conditions is \(\gamma = 1.4\).

If we know that \(r = 8.2\) and \(\gamma = 1.4\), then thermal efficiency of the ideal Otto cycle is:

\(\eta_{th} = 1-\frac{1}{8.2^{1.4-1}}\)

\(\eta_{th} = 0.569\)

Under cold air standard conditions, the thermal efficiency of this cycle is 56.9 percent.

The company should go with the out-house treatment option, as it has a lower annual worth value and will result in lower costs over the 11-year period.

GivenDataAn oil refinery finds that it is necessary to treat the waste liquids from a new process before discharging them into a stream. The treatment will cost $40,000 the first year, but process improvements will allow the costs to decline by $4,000 each year.An outside company will process the wastes for the fixed price of $20,000/year throughout the 11 year period, payable at the beginning of each year.MARR = 7%FormulaAnnual Worth (AW) = (P/A, i%, n)Annual Worth (AW) = Present Worth (PW) + Future Worth (FW)Where,P = Initial Cost (Present Worth)A = Capital Recovery Factori = InterestRaten = Life of the ProjectCalculationFirst of all, we calculate the AW of in-house treatment. The cash outflow would be $40,000 in year 0, then $36,000 ($40,000 – $4,000) in year 1, then $32,000 ($36,000 – $4,000) in year 2, and so on until year 10, and the cash inflow would be $0 as there is no salvage value.Annual Worth (AW) = (P/A, i%, n)Present Worth (PW) = $40,000Future Worth (FW) = $0Capital Recovery Factor (CRF) = (i(1 + i)n)/((1 + i)n – 1) = (0.07(1 + 0.07)11)/((1 + 0.07)11 – 1) = 0.122053Annual Worth (AW) = (P/A, i%, n)= ($40,000/0.122053)= $327,814.53Therefore, the AW of in-house treatment is $327,814.53.Now, we calculate the AW of out-house treatment. The cash outflow would be $20,000 in each year from year 0 to year 10, and the cash inflow would be $0 as there is no salvage value.Annual Worth (AW) = (P/A, i%, n)Present Worth (PW) = $20,000Capital Recovery Factor (CRF) = (i(1 + i)n)/((1 + i)n – 1) = (0.07(1 + 0.07)11)/((1 + 0.07)11 – 1) = 0.122053Annual Worth (AW) = (P/A, i%, n)= ($20,000/0.122053)= $163,907.27Therefore, the AW of out-house treatment is $163,907.27. AW in-house treatment = $327,814.53 AW out-house treatment = $163,907.27.

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Answer: metal inert gas (MIG) welding

Explanation:

Gas metal arc welding (GMAW), also called metal inert gas (MIG) welding, is an arc welding process in which the heat for melting the metal is generated by an electric arc between a consumable electrode and the metal (Fig.

Answer:

B) the liquid accelerated to high velocities.

I hope this helps

Answer:

d. To Murrow, Hitler was a threat to all of civilization

Explanation:

For Murrow, Hitler's rise was a serious problem and a major threat to the entire civilization. For this reason, he believed that covering news about Hitler's advance and the battles of Nazi Germany was essential, even if the American population did not see Hitler as a threat and the European population, believed that these reprotations were only a way to denigrate the image of the continent to the world.

For Murrow reporting on Hitler's actions was as important as reporting on natural disasters.

Answer:Just multiply 90 by itself 46 times

Explanation:

do it

The question is incomplete. The complete question is --

An aluminum rod is press fitted onto an aluminum collar. The collar has an inner radius of 1 cm and an outer radius of 2 cm. Given the rod has a diameter of 1.01 cm and the young's modulus of aluminum is 69 GPa, determine the following :

1. the interference value, i

2. the radial pressure at the interference of the collar and the rod

3. the maximum effective stress in the collar

4. if the yield strength of aluminium is 200 MPa and assume a safety factor of 1.5, will the aluminium collar break

Solution:

Given :

Inner radius of the collar = 1 cm

So, inner diameter, \($d_1$\) = 2 cm

Outer radius of the collar = 12 cm

So, outer diameter, \($d_2$\) = 4 cm

The aluminium rod diameter, d = 1.01 cm

Now, from the figure, we can see that there will be no interference and so the rod will easily insert inside the collar.

1. So, the interference , i =0

2. The radial pressure is also 0.

3. There will be no stress developed. So the maximum effective stress is 0

4. The collar will not break

Answer:

A

Explanation:

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The correct response is c. straight-up seating position. Standard-type motorcycles apply to straight-up seating position.

Keeping the feet flat while seated or placing them on the ground or a footrest. Do not cross your ankles or knees. keeping a modest distance between the chair and the back of the knees. putting the knees at the same height as the hips or just a little lower. Sit upright with your shoulders back and your back straight. When sitting, try to leave two inches between the back of your knees and the edge of the seat. Puleio advises adjusting your seat so that your thighs are parallel to the floor and your feet are flat on the ground (or on a footrest if your feet cannot rest comfortably).

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Answer:

Blue

Explanation:

You want me to overthink it which is why I think the answer should be the most obvious and not the most complicated

Answer and Explanation:

Your favorite primary color is blue because 1. blue is a primary color, 2. There is a lot of blue in the picture, and 3. You outlined the circle in blue.

Ty for the points lol.

#teamtrees #WAP (Water And Plant)

Answer:

Cite two important additional refinements that resulted from the Wave-mechanical

atomic model.

Answer:

Mass flow rate = 15.96kg/s

Explanation:

From

P1V1=mRT1

V1=RT1/P1

V1=0.0492m³/kg

M=A(U)/V1

Where u is the velocity

A=πd²/4

M=π(0.2²)/4×25/0.0492

M=15.96kg/s

The MMC of the hole diameter is 10.10 mm. The least material condition (LMC) is the smallest size limit of a part that is acceptable for use.  LMC is the smallest allowable size limit that will still allow the part to function as intended. In this case, we will calculate the LMC for a part with a length of \(35.00 ± 0.15 mm.\)

To calculate the LMC, we must subtract the tolerance from the nominal value. The nominal value is the target value of the part dimension. In this case, the nominal value is 35.00 mm.

LMC = Nominal Value - Tolerance LMC = \(35.00 - 0.15LMC = 34.85 mm\)

Therefore, the LMC for the given part is 34.85 mm.

The Maximum Material Condition (MMC) is the largest size limit of a part that is acceptable for use. In other words, MMC is the largest allowable size limit that will still allow the part to function as intended. In this case, we will calculate the MMC of the hole diameter with dimension \(10.0 ± 0.10 mm\).

To calculate the MMC, we must add the tolerance to the nominal value. The nominal value is the target value of the part dimension. In this case, the nominal value is 10.0 mm.

MMC = Nominal Value + Tolerance MMC = \(10.0 + 0.10MMC = 10.10 mm.\)

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$v0 is the sum of the odd positive integers 1 + 3 + 5 + … which are less than or equal to n.

#t0=sum=0
#t1=i=1
# (n<i)? or (i>n)?
# exit loop if (i>n)
# sum = sum + i
# i = i + 2
# repeat loop
# result = sum

What is positive integers?
A number with a decimal (or fractional) portion equal to zero is referred to as an integer, also known benefit of the entire number, in algebra. The positive whole numbers, negative whole numbers, and the number zero make up the set of integers. Positive whole numbers will be the main topic of this lesson. A whole number that is greater than zero is what is meant by the term "positive integer." All counting numbers are included in the set of positive integers (that is, the natural numbers). A collection (collection of objects) whose components are numbers is known as a number set. All whole numbers on the number line to the right of zero are included in the set of positive integers.

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Answer:

A

Explanation:

Answer:

A

Explanation:

The fuse breaks the circuit if a fault in an appliance causes too much current to flow. The fuse contains a piece of wire that melts easily. If the current going through the fuse is too great,the wire heats up until it melts and breaks the circuit

Based on the Chvorinov's rule, the diference in the solidification times of the two castings is 14.092 times the solidification time of the prism casting.

The Chvorinov's rule is an empirical method to estimate the cooling time of a casting in terms of a reference time. This rule states that cooling time (t) is directly proportional to the square of the volume (V), in cubic meters, divided to the surface area (A), in square meters. Now we proceed to model each casting:

t = C · [0.25π · D² · L/(0.5π · D² + π · D · L)]²

t = C · [0.25 · D · L/(0.5 · D + L)]²    (1)

t' = C · [3 · T² · L/(6 · T · L + 2 · T · L + 6 · T²)]²

t' = C · [3 · T · L/(8 · L + 6 · T)]²     (2)

3 · T² = 0.25π · D²     (3)

Where:

If we know that D = 0.3 m, then the thickness of the prism casting is:

\(T = \sqrt{\frac{\pi}{12} }\cdot D\)

T ≈ 0.153 m

And (1) and (2) simplified into these forms:

t = C · {0.25π · (0.3 m) · (0.5 m)/[0.5 · (0.3 m) + 0.5 m]}²

t = 0.0329 · C     (1b)

t' = C · {3 · (0.153 m) · (0.5 m)/[8 · (0.5 m) + 6 · (0.153 m)]}²

t' = 0.00218 · C     (2b)

Lastly we find the percentual difference in the solidification times of the two castings by using the following expression:

r = (1 - t'/t) × 100 %

r = (1 - 0.00218/0.0329) × 100 %

r = 93.374 %

The cooling time of the prism casting is 6.626 % of the solidification time of the cylindrical casting. The diference in the solidification times of the two castings is 14.092 times the solidification time of the prism casting. \(\blacksquare\)

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The option that BEST identifies a contrast in these two passages is option D) The actions taken by the bird in the poem are ineffective, but the actions taken by Ms. Truth, Ms. Griffling, and Ms. Haviland in the account have a great impact.

The term contrast is known to be a word that tends to show some noticeable differences between two things.

Note that it is liken to a cause and its effect. The option that BEST identifies a contrast in these two passages is option D) The actions taken by the bird in the poem are ineffective, but the actions taken by Ms. Truth, Ms. Griffling, and Ms. Haviland in the account have a great impact.

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Choose a resistor with a wattage rating that can handle the power dissipation (P = VI) without overheating or causing damage to the circuit.

We have to give that,

The output voltage across the load is twice that needed and there are signs of amplifier saturation.

Now, Based on the description, it sounds like you may need to add a resistor in parallel with the load in order to achieve the desired output voltage.

Hence, For the value of the resistor you would need to add, first need to know the resistance of the load and the output voltage you're trying to achieve.

Once you have that information, you can use Ohm's Law (V = IR) to calculate the necessary value of the resistor:

R = (Vsupply - Vload) / Iload

Where:

Vsupply is the voltage of your power supply

Vload is the output voltage you're trying to achieve

Iload is the current through the load

Since adding a resistor in parallel with the load will change the overall resistance of the circuit, so you'll need to recalculate the current (Iload) and adjust the value of the resistor accordingly.

Also, be sure to choose a resistor with a wattage rating that can handle the power dissipation (P = VI) without overheating or causing damage to the circuit.

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Answer:

Doing associative brainstorming

Allow all members who have an opinion or comment to contribute

You cannot criticize someone or there judgment on a topic

Always encourage someone if they need help with something and give input

Let everyone talk and share there solutions

Explanation:

Overall it’s good to do the things I have listed above because it can help you in planning.

Answer:

We often call these prewriting strategies “brainstorming techniques.” Five useful strategies are listing, clustering, freewriting, looping, and asking the six journalists' questions. These strategies help you with both your invention and organization of ideas, and they can aid you in developing topics for your writing.

In a scenario where network performance is degraded, the appropriate network device to improve the situation would depend on the specific issue and requirements of the network. Let's consider a scenario where a network is experiencing high network congestion and slow data transfer speeds. In this case, a combination of routers and switches can help alleviate the degraded performance.

Routers: Routers are essential network devices that connect multiple networks and facilitate the efficient routing of data packets. They analyze network traffic and determine the most optimal path for data transmission. In our scenario, routers can help by implementing intelligent routing algorithms to redirect network traffic and avoid congested routes. This can distribute the traffic load across different network paths, reducing congestion and improving overall network performance.

Switches: Switches are used to create a local area network (LAN) by connecting multiple devices within a network. They provide dedicated bandwidth for each connected device, allowing simultaneous and efficient data transmission. In our scenario, switches can be strategically placed to create separate network segments, reducing the scope of congestion. By dividing the network into smaller segments, switches can prevent unnecessary data collisions and improve the overall network performance.

Network Media: The appropriate network media for routers and switches would typically be Ethernet cables, such as Cat5e or Cat6 cables. These cables provide reliable and high-speed data transmission, ensuring efficient communication between the devices in the network. Ethernet cables are suitable for these devices as they offer sufficient bandwidth and low latency, supporting fast data transfer and minimizing network congestion.

Hubs and Repeaters: Hubs and repeaters are not suitable in this scenario of degraded network performance. Hubs operate at the physical layer of the network and simply broadcast data to all connected devices, resulting in network collisions and reduced performance. Repeaters, on the other hand, regenerate and amplify signals to extend the network distance but do not address congestion issues. In the case of degraded network performance due to congestion, using hubs or repeaters would not alleviate the issue but rather exacerbate it by increasing network collisions and signal degradation.

By using routers and switches in our scenario, we can intelligently route network traffic, distribute the load, and create separate network segments to address congestion issues. This helps optimize the network performance by improving data transfer speeds and reducing latency.

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Answer:

2.187 inches

hope it would be helpful

Answer:

2.187 in.

Explanation:

Answer:

Waste stream

Explanation:

trust

Answer:

a) 600°F  days

b) 103°F  days

Explanation:

Given data :

overall heat loss coefficient = 400 Btu/h.oF

Furnace efficiency = 0.78

applying the degree- day method the heating energy requirement per day can be obtained by subtracting the average temperature for a particular day from the acceptable mid/balance point temperature

lets assume the mid/balance point temperature = 65°F

a) heating energy requirement in Denver Colorado

 we will have 600°F days  ; considering the  the average temperature - balance point temperature

= 665 - 65 = 600°F

b) heating energy requirement in Little Rock Arkansas

 we will have 103°  days

Answer:

It's easier to buy one, but you can search for a tutorial on how to make one on Yuotube.

There are quite a few videos on how to make one.

Graduates of Mihaylo College of Business and Economics majoring in b)Business analytics are the best fit to fill the role of leveraging data and statistics in decision-making processes in today's digitalized world.

Business analytics is a field that combines data analysis, statistical modeling, and predictive analytics to extract meaningful insights and drive strategic decision making within organizations.

With the explosion of data and the need to make data-driven decisions, businesses require professionals who can effectively analyze large datasets, identify patterns, and derive actionable insights.

By majoring in Business analytics, students gain a solid foundation in statistical analysis, data mining, data visualization, and predictive modeling techniques.

They learn how to handle and interpret complex data sets, apply statistical methods to uncover meaningful relationships, and use data-driven insights to inform business strategies.

Moreover, graduates with a Business analytics major possess a strong understanding of various statistical tools and software, allowing them to efficiently process and analyze data.

They are equipped with the skills to design and implement data-driven solutions, optimize business processes, and drive innovation within organizations.

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A prefix expression is an expression where the operator comes before the operands. It is evaluated by starting from the left and performing the operation specified by each operator.

The prefix expression "+3+313 333" can be evaluated as follows:

The operator "+" is encountered.

The next operand is "3". The current result is 3.

The operator "+" is encountered again.

The next operand is "3". The current result is added to 3, resulting in 6.

The operator "+" is encountered once more.

The next operand is "313". The current result is added to 313, resulting in 319.

The final operand is "333". The current result is added to 333, resulting in 652.

Therefore, the value of the prefix expression "+3+313 333" is 652.

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Answer:

Shelf life.

Explanation:

In Business, an inventory is a term used to describe a list of finished goods, goods still in the production line and raw materials that would be used for the manufacturing of more goods in a bid to meet the unending consumer demands.

Simply stated, an inventory can be classified into three (3) main categories; finished goods, work in progress, and raw materials.

An inventory is recorded as a current asset on the balance sheet because it's primarily the most important source of revenue for a business entity.

Also, the three (3) main cost concept associated with an inventory are;

1. First In First Out (FIFO).

2. Last In First Out (LIFO).

3. Weighted average cost.

Shelf life can be defined as a measure of the length of time that a particular product could be kept or stored without it getting bad or becoming unsuitable for use by the consumers. Thus, the shelf life of a product is largely dependent on its expiration date.

Hence, merchandise without an expiration date like electronics, tools and home goods typically have a longer shelf life.