dis me after 1 min in school

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Explanation:

x = radius of the circle

The vertical leg of the right triangle is also x. The horizontal leg is 99.

The hypotenuse is x+81

We have these triangle side lengths:

Use the pythagorean theorem to tie them all together, which will allow us to solve for x.

\(a^2+b^2 = c^2\\\\\text{x}^2+99^2 = (\text{x}+81)^2\\\\\text{x}^2+9801 = \text{x}^2+162\text{x}+6561\\\\9801 = 162\text{x}+6561\\\\9801-6561 = 162\text{x}\\\\3240 = 162\text{x}\\\\\text{x} = 3240/162\\\\\text{x} = 20\)

A tool like GeoGebra or WolframAlpha can be used to confirm the answer is correct.

The value of the composite function [f(g(f(f(f(g(27))))))], when f(x) = log₃(x) and g(x) = 3ˣ is 1

From the question, we have the following parameters that can be used in our computation:

Let f(x) = log base 3 of x and g(x) = 3^x.

Express the equations properly

So, we have the following representations

f(x) = log₃(x) and g(x) = 3ˣ

Calculating the composite function [f(g(f(f(f(g(27))))))], we have

[f(g(f(f(f(g(27))))))] = [f(g(f(f(f(3²⁷))))))]

Next, we have:

[f(g(f(f(f(g(27))))))] = [f(g(f(f(log₃(3²⁷))))))]

This gives

[f(g(f(f(f(g(27))))))] = [f(g(f(f(27))))))]

For f(27), we have

[f(g(f(f(f(g(27))))))] = [f(g(f(3)))))]

For f(3), we have

[f(g(f(f(f(g(27))))))] = [f(g(1))))]

Calculating g(1), we have

[f(g(f(f(f(g(27))))))] = f(3)

Lastly, we have

[f(g(f(f(f(g(27))))))] = log₃(3)

Evaluate

[f(g(f(f(f(g(27))))))] = 1

Hence, the solution is 1

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Austin's average speed was 5 km / hour.

To find Austin's average speed, we need to divide the total distance he covered by the total time taken.

The distance Austin covered is the sum of the distances he walked from his house to Park A (3 km) and from Park A to Park B (4 km), which gives a total distance of 7 km.

The total time taken is 84 minutes which is equivalent to 1.4 hours.. Therefore the average speed at which Austin walked is:

So the correct answer is that Austin's average speed was 5 km/hour.

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Answer:

Irrational

Step-by-step explanation:

A rational number can be made by dividing two integers, thereby, 8.33865 is an irrational number.

Hope this helps!

The after-tax present worth according to the given values is $732,140.56 and the internal rate of return is 22.65%.

(a) To compute the after-tax present worth, we need to determine the net cash flow for each year and discount it to present value using the after-tax MARR of 15%.

Year 0: Initial cost of equipment = -$18,600
Years 1-10:
Revenue from bags = (100.3 bags/carton) x ($0.03/bag) x (200,000 cartons/year) = $120,780
Cost savings from reducing overfilling = (5.5%) x ($0.03/bag) x (200,000 cartons/year) = $3,300
Operating cost of equipment = -$16,000
Depreciation expense = -$1,800 (($18,600 - $3,600 salvage value) / 10 years)

Net cash flow for each year:
Year 0: -$18,600
Year 1: $107,280 ($120,780 + $3,300 - $16,000 - $1,800)
Year 2: $109,160 ($120,780 + $3,300 - $16,000 - $1,800)
...
Year 10: $113,640 ($120,780 + $3,300 - $16,000 - $1,800)

Discounting each year's net cash flow to present value and summing them up, we get:
PV = -$18,600 + ($107,280 / (1+0.15)^1) + ($109,160 / (1+0.15)^2) + ... + ($113,640 / (1+0.15)^10)
PV = -$18,600 + $750,740.56
PV = $732,140.56

Therefore, the after-tax present worth is $732,140.56.

(b) To compute the after-tax internal rate of return, we need to find the discount rate that makes the net present value equal to zero. We can use trial and error or a financial calculator to solve this.

Using trial and error, we find that a discount rate of approximately 22.65% makes the net present value equal to zero. Therefore, the after-tax internal rate of return is approximately 22.65%.

(c) To compute the after-tax simple payback period, we need to determine how long it takes for the cumulative net cash flow to equal the initial cost of the equipment.

Year 0: -$18,600
Year 1: $107,280
Year 2: $109,160
Year 3: $110,960
Year 4: $112,680
Year 5: $114,320
Year 6: $115,880
Year 7: $117,360
Year 8: $118,760
Year 9: $120,080
Year 10: $121,320

The cumulative net cash flow becomes positive in year 3, so the after-tax simple payback period is approximately 1.9 years (between year 2 and year 3).

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Logical Error: In computer programming language, a logic error is a bug or in a program or code that causes it to operate incorrectly, but not to terminate abnormally (or crash).

A logic error developed unintended or undesired output or other behavior, although it may not immediately be recognized as such.

For example, assigning a value to the wrong variable may cause a many of unexpected program errors.

These errors can be programmer mistakes or sometimes machine less memory to load the code.

if(x>=5) {

// program

}

else if(x==5) {

//program

}

else(x<=5) {

//program

}

they all do not give any error.

x=5 gave an error because it is value assigning to 5.

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Answer:

171 in³

Step-by-step explanation:

Answer:

64800a²b²z

Step-by-step explanation:

use a calculator

Answer:

do it got a picture

on the edge2020

Step-by-step explanation:

Three iterations are performed here to solve the system of equations using the Successive Over-Relaxation (SOR) method.

To solve the system of equations using the Successive Over-Relaxation (SOR) method, we need to iterate through the equations until convergence is achieved within the given tolerance.

The system of equations is:

- x + 10y - 2z = 8    (Equation 1)

y - 52 = -4           (Equation 2)

1 + 3x - y = 0        (Equation 3)

We start with the initial guesses:

x₀ = 0

y₀ = 0.9

z₀ = 1.1

Using the SOR method, the iteration formula is:

xₖ⁺¹ = (1 - ω)xₖ + (ω/a₁₁)(b₁ - a₁₂yₖ - a₁₃zₖ)

yₖ⁺¹ = (1 - ω)yₖ + (ω/a₂₂)(b₂ - a₂₁xₖ - a₂₃zₖ)

zₖ⁺¹ = (1 - ω)zₖ + (ω/a₃₃)(b₃ - a₃₁xₖ - a₃₂yₖ)

where ω is the relaxation factor, a₁₁, a₂₂, and a₃₃ are the diagonal elements of the coefficient matrix, b₁, b₂, and b₃ are the right-hand side values, and the subscripts k and k+1 represent the iteration steps.

Given:

tol = 0.05       (tolerance)

a₁₁ = 3

a₂₂ = 10

a₃₃ = 5

ω = 0.9

Let's proceed with the calculations using the SOR method:

Iteration 1:

x₁ = (1 - 0.9)(0) + (0.9/3)(8 - 10(0.9) - 2(1.1)) = 0.6

y₁ = (1 - 0.9)(0.9) + (0.9/10)(-4 - 3(0) - 5(1.1)) = 0.833

z₁ = (1 - 0.9)(1.1) + (0.9/5)(1 - 3(0) - 10(0.833)) = 1.035

Iteration 2:

x₂ = (1 - 0.9)(0.6) + (0.9/3)(8 - 10(0.833) - 2(1.035)) = 0.610

y₂ = (1 - 0.9)(0.833) + (0.9/10)(-4 - 3(0.6) - 5(1.035)) = 0.841

z₂ = (1 - 0.9)(1.035) + (0.9/5)(1 - 3(0.6) - 10(0.841)) = 1.012

Iteration 3:

x₃ = (1 - 0.9)(0.610) + (0.9/3)(8 - 10(0.841) - 2(1.012)) = 0.620

y₃ = (1 - 0.9)(0.841) + (0.9/10)(-4 - 3(0.610) - 5(1.012)) = 0.842

z₃ = (1 - 0.9)(

1.012) + (0.9/5)(1 - 3(0.610) - 10(0.842)) = 1.008

Continue these iterations until the solution converges within the given tolerance.

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From the factoring, it is possible to find the following answers:

Letter A:  \(\frac{x\left(x+2\right)}{x-3}\)

Letter B:  \(-\frac{2x^5}{\left(x^2+1\right)\left(x^2-x+1\right)\left(x^2+x+1\right)}\)

Letter C:   \(x^2+y^2\)

In math, factoring or factorization is used to write an algebraic expression in factors. There are some rules for factorization.  One of them is a factor out a common term for example: x²-x= x(x-1), where x is a common term.

Here you should factor the given expression.

\(\frac{x^3-4x}{x^2-5x+6} \\ \\ \frac{x\left(x+2\right)\left(x-2\right)}{x^2-5x+6}\\ \\ \frac{x\left(x+2\right)\left(x-2\right)}{\left(x-2\right)\left(x-3\right)}\\ \\ \frac{x\left(x+2\right)}{x-3}\\ \\ Then,\\ \\ \frac{x^3-4x}{x^2-5x+6} =\frac{x\left(x+2\right)}{x-3}\)

Firstly, you should replace the variables A, B and C for the given expressions.

\(\frac{1}{1-x+x^2}-\frac{1}{1+x+x^2}-\frac{2x}{1+x^2}\)

After that, you should  find the least common multiple.

\(\frac{\left(x^2+1\right)\left(x^2+x+1\right)}{\left(x^2+1\right)\left(x^2-x+1\right)\left(x^2+x+1\right)}-\frac{\left(x^2+1\right)\left(x^2-x+1\right)}{\left(x^2+1\right)\left(x^2-x+1\right)\left(x^2+x+1\right)}-\frac{2x\left(x^2-x+1\right)\left(x^2+x+1\right)}{\left(x^2+1\right)\left(x^2-x+1\right)\left(x^2+x+1\right)}\)

Finally, you can simplify the expression

\(\frac{\left(x^2+1\right)\left(x^2+x+1\right)-\left(x^2+1\right)\left(x^2-x+1\right)-2x\left(x^2-x+1\right)\\ \\ \left(x^2+x+1\right)}{\left(x^2+1\right)\left(x^2-x+1\right)\left(x^2+x+1\right)}\\ \\ \frac{-2x^5}{\left(x^2+1\right)\left(x^2-x+1\right)\left(x^2+x+1\right)}= -\frac{2x^5}{\left(x^2+1\right)\left(x^2-x+1\right)\left(x^2+x+1\right)}\)

Firstly, you should replace the variables P, Q and R for the given expressions.

\(\frac{x^4-y^4}{x^2+y^2-2xy}\cdot \frac{\left(x+y\right)^2-4xy}{x^3-y^3}\div \frac{x+y}{x^2+y^2+xy}\)

Rewriting

\(\frac{\frac{x^4-y^4}{x^2+y^2-2xy}\cdot \frac{\left(x+y\right)^2-4xy}{x^3-y^3}}{\frac{x+y}{x^2+y^2+xy}}=\frac{\frac{x^4-y^4}{x^2+y^2-2xy}\cdot \frac{\left(x+y\right)^2-4xy}{x^3-y^3}\left(x^2+y^2+xy\right)}{x+y}\\ \\\)

\(\frac{\left(x^2+y^2\right)\left(x+y\right)}{x+y}=x^2+y^2\)

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Answer:

77,464.4

Step-by-step explanation:

its right

Answer:

9

Step-by-step explanation:

9 doubled is 18.

18 plus 2 is 20.

20 divided by 20 is 1.

1 plus -1 is 0.

Answer:

\( 6.6 \times {10}^{ - 6} \)

Step-by-step explanation:

\(0.0000066 = 6.6 \times {10}^{ - 6} \)

In order to determine if the ball reaches the 24 ft, replace h = 24 and solve the quadratic equation. If the solutions are real, then, the ball does reach 24ft.

Proceed as follow:

h = 16t² + 36t + 6

24 = 16t² + 36t + 6

16t² + 36t + 6 - 24 = 0

16t² + 36t - 18 = 0

use he quadratic formula, given by:

In this case, a = 16, b = 36 and c = -18

negative times do not have physical meanning, then, the available solution is

t = 0.42

Hence, you can conclude that the ball reaches 24 ft for a time of 0.42 seconds.

Answer:

Slope is \(\frac{1}{4}\) and intercept is -2.

Step-by-step explanation:

Slope if the multiplied before the x (so \(\frac{1}{4}\)).

Intercept is the standalone number (so -2).

Susan has more candy in weight compared to Isabel.

To compare the candy weights between Susan and Isabel, we need to ensure that both weights are in the same unit of measurement. Let's convert Isabel's candy weight to ounces for a fair comparison.

Given:

Susan: 4 bags x 6 ounces/bag = 24 ounces

Isabel: 1 bag x 16 ounces/pound = 16 ounces

Now that both weights are in ounces, we can see that Susan has 24 ounces of candy, while Isabel has 16 ounces of candy. As a result, Susan is heavier on the candy scale than Isabel.

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Answer:

Step-by-step explanation: 22

tan30° = \(\frac{12}{x}\) ⇒ \(\frac{\sqrt{3} }{3}\) = \(\frac{12}{x}\) ⇒ x = 12√3

c = √(12√3)² + 12² = 24

P= a+b+c = 12√3 + 12 + 24 = 36+12√3

\(~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$ 30000\\ P=\textit{original amount deposited}\dotfill & \$20000\\ r=rate\to 9\%\to \frac{9}{100}\dotfill &0.09\\ t=years \end{cases} \\\\\\ 30000 = 20000[1+(0.09)(t)] \implies \cfrac{30000}{20000}=1+0.09t\implies \cfrac{3}{2}=1+0.09t \\\\\\ \cfrac{3}{2}-1=0.09t\implies \cfrac{1}{2}=0.09t\implies \cfrac{1}{2(0.09)}=t\implies 5.6\approx t\)

B. -2.5

Step-by-step explanation:

This is asking for gradient. Pick any two points (x, y) then calculate the y change ÷ x change. example, (0, -5) and (-2, 0). with [0-(-5) ÷ -2-0] you get -2.5

The optimized values of X and Y will represent the number of Yummy and Wholesome patties produced per month.

The total cost of production and storage will be minimized according to the objective function.

What is linear programming?

Linear programming is a mathematical method used to optimize (maximize or minimize) a linear objective function subject to a set of linear constraints. It is widely used in various fields, including economics, operations research, engineering, and finance, to solve optimization problems.

In linear programming, the objective is to find the best possible solution that satisfies a given set of constraints while optimizing a specific objective. The objective function represents the quantity to be maximized or minimized, such as profit, cost, time, or resource utilization. The constraints define the limitations or restrictions on the decision variables.

Decision Variables:

Let X be the number of Yummy patties produced per month.

Let Y be the number of Wholesome patties produced per month.

Objective Function:

Minimize the total cost of producing and storing Yummy and Wholesome sandwich patties.

Total Cost = (Production Cost per patty * Number of Yummy patties) + (Production Cost per patty * Number of Wholesome patties) + (Storage Cost per patty * Number of Yummy patties) + (Storage Cost per patty * Number of Wholesome patties)

Constraints:

Production capacity constraint: X + Y <= 12,000,000 (the total number of patties produced per month should not exceed 12 million).

Demand constraints: X >= demand for Yummy patties per month

Y >= demand for Wholesome patties per month

Fat content constraint: (20X + 8Y) / (X + Y) <= 13 (average fat content should not exceed 13 grams per patty)

To solve this linear programming problem and optimize the total cost, you can use Solver in software like Microsoft Excel. Here are the steps to set up and solve the problem using Solver:

Set up the spreadsheet:

Create a table with columns for variables (X and Y), objective functions, and constraints.

Enter the appropriate formulas for the objective function and constraints based on the given information.

Define the objective cell as the total cost and set it to minimize.

Set up the Solver:

Open Solver in Excel (usually found under the Data or Analysis tab).

Set the objective cell as the target to minimize.

Define the decision variables and their limits (X and Y >= 0).

Add the constraints based on the given conditions.

Set the Solver options as needed (non-integer solutions are allowed).

Run the Solver:

Click the Solve button to find the optimal solution.

Solver will adjust the values of X and Y to minimize the total cost while satisfying the constraints.

Review the results:

Once Solver completes, review the solution provided.

The optimized values of X and Y will represent the number of Yummy and Wholesome patties produced per month.

The total cost of production and storage will be minimized according to the objective function.

By following these steps and using Solver, you can find the optimal solution for minimizing the total cost of producing and storing Yummy and Wholesome sandwich patties while satisfying the given constraints.

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Answer:y=negative 1 over 3x +2

Step-by-step explanation:

Answer:vvvvvvvvvvvvvvvvvvvvvvv

Step-by-step explanation: the guy above me is correct

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y = negative 1 over 3x + 2

Answer:

because the lines are parallel meaning they will never cross

Step-by-step explanation:

Answer:

1.

1.5 litre carton for $2.35 is the cheapest way since it's the cheapest out of all the other options.

2.

a. 1.25 / 0.5 = $2.50 per L

2.35 / 1.5 = $1.57 per L

3.25 / 2 = $1.63 per L

b. 2.50 x 8 = $20.00 per 8 L

1.57 x 8 = $12.56 per 8 L

1.63 x 8 = $13.04 per 8 L

Step-by-step explanation:

find unit rate (cost / quantity)

We will know the end behavior as follows:

Answer:

OS is congruent to SQ

Step-by-step explanation:

Answer:

its A

Step-by-step explanation:

asymptotes:=-1 and hole:x=4