does distance have direction? does displacement have direction?

When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.

How do sound waves and earthquakes compare?

The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.

In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.

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The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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Answer:

There is no graph i can aswer it soww

Explanation:

Answer:

2.8 would be the correct answer as 1 rounds down

Answer:

5.67 m/s

Explanation:

The speed of a wave can be calculated as the distance traveled by the wave divided by the time taken:

Speed = Distance/Time

In this case, the distance traveled by the wave is the length of the pool, which is 17 m. The time taken by the wave to travel this distance is 3 seconds.

So, the speed of the wave can be calculated as:

Speed = 17 m/3 s

Speed = 5.67 m/s

Therefore, the speed of the water wave in the 17 m long pool is 5.67 m/s.

Regular exercise and physical activity is responsible for strong muscles and bones.

Exercise and physical activity improves respiratory, cardiovascular, and overall health of an individual. Staying active can help in maintaining a healthy weight, reduce your risk of diabetes, heart disease, and reduce risk for cancers so we can conclude that regular exercise and physical activity is responsible for strong muscles and bones.

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Answer:

The object's acceleration is approximately \(\(1.6875 \, \text{m/s}^2\).\)

Given:

Initial velocity (u) = 0 m/s (as the object is initially at rest)

Final velocity (v) = 45 m/s

Distance (s) = 600 m

Using the kinematic equation:

\(\[v^2 = u^2 + 2as\]\)

Rearranging to solve for acceleration (a):

\(\[a = \frac{v^2 - u^2}{2s}\]\)

Plugging in the values:

\(\[a = \frac{45^2 - 0^2}{2 \cdot 600}\]\[a = \frac{2025}{1200}\]\[a = 1.6875 \, \text{m/s}^2\]\)

The object's acceleration is approximately\(\(1.6875 \, \text{m/s}^2\).\)

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the answer is B

i jus took the assement

Answer:

B

Explanation:

Before she jumped from the cliff, her gravitational potential energy was

GPE = (her weight) x (height of the cliff) .

That's exactly the GPE that she lost on the way down to the water.  So we can write

24,500 J = (her weight) x (44.0 m)

Divide each side by 44.0 m:

Her weight = 24,500 J / 44 m

Her weight = 556.8 Newtons

(about 125 pounds)

Answer:

L = L0 (1 - v^2/c^2)     where L0 is proper length and L the measured length

L = 1.2 (1 - .87^2)^1/2 m = .59 m

Given data;

* The mass of the elevator is 5000 kg.

* The acceleration of the elevator is,

Solution:

The free body diagram of the elevator is,

The weight of the elevator is,

where m is the mass of the elevator and g is the acceleration due to gravity,

Substituting the known values,

The net force acting on the elevator is,

where a is the acceleration of the elevator moving upwards,

Substituting the known values,

From the free body diagram, the tension acting on the cable is,

Substituting the known values,

Thus, the tension acting in the cable is 64 kN.

Answer:

same for all objects

Explanation:

earth pulls every object by same force of gravity

See below

3.15 m

When the Moments around thefulcrum , F , are equal, any increase in 'x' will cause a tip

I placed the weight of the board sections at the middle of the sections ...I think this is correct (?  It has been a long time since I did simple Physics)

L moment = R moment

1.5 * 18   =   100 * x    + 1 * 12

x = .15    m    from the fulcrum or   3.15 m from the L end

(hope it is correct !)

The distinction in top among the pinnacle floor of glycerin and the pinnacle floor of ethyl alcohol is 0.0432 meter or 4.32 centimeter the difference in height between the top surface of glycerin and the top surface of alcohol is 4.32 centimeter.

Given the subsequent data:

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Remember Coulomb's law: the magnitude of the electric force F between two stationary charges q₁ and q₂ over a distance r is

\(F = \dfrac{kq_1q_2}{r^2}\)

where k ≈ 8,98 × 10⁹ kg•m³/(s²•C²) is Coulomb's constant.

8.1. The diagram is simple, since only two forces are involved. The particle at Q₂ feels a force to the left due to the particle at Q₁ and a downward force due to the particle at Q₃.

8.2. First convert everything to base SI units:

0,02 µC = 0,02 × 10⁻⁶ C = 2 × 10⁻⁸ C

0,03 µC = 3 × 10⁻⁸ C

0,04 µC = 4 × 10⁻⁸ C

300 mm = 300 × 10⁻³ m = 0,3 m

600 mm = 0,6 m

Force due to Q₁ :

\(F_{Q_2/Q_1} = \dfrac{k (6 \times 10^{-16} \,\mathrm C)}{(0,3 \, \mathrm m)^2} \approx \boxed{6,0 \times 10^{-5} \,\mathrm N} = 0,06 \,\mathrm{mN}\)

Force due to Q₃ :

\(F_{Q_2/Q_3} = \dfrac{k (12 \times 10^{-16} \,\mathrm C)}{(0,6 \, \mathrm m)^2} \approx \boxed{3,0 \times 10^{-5} \,\mathrm N} = 0,03 \,\mathrm{mN}\)

8.3. The net force on the particle at Q₂ is the vector

\(\vec F = F_{Q_2/Q_1} \, \vec\imath + F_{Q_2/Q_3} \,\vec\jmath = \left(-0,06\,\vec\imath - 0,03\,\vec\jmath\right) \,\mathrm{mN}\)

Its magnitude is

\(\|\vec F\| = \sqrt{\left(-0,06\,\mathrm{mN}\right)^2 + \left(-0,03\,\mathrm{mN}\right)^2} \approx 0,07 \,\mathrm{mN} = \boxed{7,0 \times 10^{-5} \,\mathrm N}\)

and makes an angle θ with the positive horizontal axis (pointing to the right) such that

\(\tan(\theta) = \dfrac{-0,03}{-0,06} \implies \theta = \tan^{-1}\left(\dfrac12\right) - 180^\circ \approx \boxed{-153^\circ}\)

where we subtract 180° because \(\vec F\) terminates in the third quadrant, but the inverse tangent function can only return angles between -90° and 90°. We use the fact that tan(x) has a period of 180° to get the angle that ends in the right quadrant.

40,840.7 kilometers the space shuttle have to travel to complete one orbit. In terms of a circle, this distance is termed as the circumference of the circle.

The circumference of a circle is the length measured around its edge. The diameter of a circle is the distance from the center to the outside.

Here we need to find the distance of the space shuttle that completed one circle, ie, the circumference of the orbit. The Circumference or distance covered by the space shuttle can be denoted by \(C_{SS}\) and can be calculated by application of the below formula,

\(C_{SS}\) = 2πr

where r is the radius of earth ie, 6500Km

Therefore, the equation becomes:

\(C_{SS}\) = 2×π×r

= 2×π×6500

=40,840.7

So, the kilometer required to travel is 40,847.7Km

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Answer:

The characteristics that determine how easily two substances change temperature are:

The volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.

Explanation:

Answer:524 Hz

Explanation:

Approximate frequency, heard in other car, when two car approaches each other, before they cross each other is 524 Hz.

Frequency of wave is the number of waves, which is passed thorough a particular point at a unit time.

For the two cars approaching each other the Doppler formula to find the frequency of second car is given as,

\(f_2=\dfrac{V_s+V_2}{V_s-V_1}f_1\)

Here, \(V_s\) is the speed of the sound.

Two cars approach each other from opposite directions.The velocity of car one is 54 km/h and the velocity of the car two is also 54 km/h.

Convert the unit of velocity of the car as,

\(\rm 54km/s=54\times\dfrac{5}{18}m/s\\\rm 54km/s=15m/s\)

As we know that the speed of the sound is 340 m/s and one of the cars emits a note of frequency 480 Hz.

Thus, putting the values in the above formula to find out the frequency heard in the other car before they cross each other as,

\(f_2=\dfrac{340+15}{340-15}480\\f_2=524.3\rm Hz\)

The approximate frequency heard in the other car before they cross each other is 524 Hz.

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Answer:

The best answer seems to be B because there is a strong positive correlation that the more exercise a person does, the fewer medical problems they have

Explanation:

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!

The more exercise a person takes the fewer medical problems they report. This is an example of a positive correlation. The correct option is B.

When two variables rise or decrease simultaneously, there is a positive correlation; when there is a negative correlation, one variable increases as the other falls.

When two variables behave in unison, rising or falling in lockstep with one another, there is a positive correlation.

When two variables move in opposition to one another—that is, when one rises, the other falls—this is known as a negative correlation.

A person reports fewer medical issues the more activity they get. An illustration of a positive correlation would be this.

Thus, the correct option is B.

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Find refractive index first

\(\\ \rm\Rrightarrow \mu=\dfrac{c}{v}\)

\(\\ \rm\Rrightarrow \mu=\dfrac{1.0003}{1.33}\)

\(\\ \rm\Rrightarrow \mu =0.75\)

Now

\(\\ \rm\Rrightarrow \dfrac{sini}{sinr}=\mu\)

\(\\ \rm\Rrightarrow \dfrac{sin45}{sinr}=0.75\)

\(\\ \rm\Rrightarrow \dfrac{sin45}{0.75}=sinr\)

\(\\ \rm\Rrightarrow sinr=0.94\)

\(\\ \rm\Rrightarrow r=sin^{-1}(0.94)\)

\(\\ \rm\Rrightarrow r=70^{\circ}\)

Answer:

8 blocks.

Explanation:

Given that,

A student walks 3 blocks East, 2 blocks North, 1 block West, and then 2 blocks  South.

We need to find the total distance traveled by the student. The distance covered by an object is equal to the sum of the total path covered. So,

Distance = 3 blocks + 2 blocks + 1 block + 2 blocks

= 8 blocks

So, the distance traveled by the block is 8 blocks.

Answer:

Distance between them after 5 hours is 300 km.

Explanation:

From point A a vehicle leaves at 80 km / h at the same time a cyclist leaves at 20 km / h at what distance is they from each other after 5 hours.

Distance traveled by A in 5 hours = speed x time = 80 x 5 = 400 km

Distance traveled by B in 5 hours = speed x time = 20 x 5 = 100 km

The distance between them after 5 hours =  400 - 100 = 300 km

Answer:

d = 113.6 m

Explanation:

For this exercise, the first thing we must notice is that the speed of the laser beam in the fiber is constant, so we can use the uniform motion relationships to find the necessary distance

          v = d / t

let's reduce to SI units

         t = 557 ns = 557 10⁻⁹ s

         d = v t

         d = 2.04 10⁸ 557 10⁻⁹

         d = 1.136 102 m

         d = 113.6 m

This is the distance of the fiber for the laser to arrive with the desired delay

Explanation: ΔL = τ(average) * Δt
Change in angular momentum = average torque * change in time

solve for average torque for each objects
τ(average) = ΔL / Δt

Object y average torque
τy = ΔLy / Δt = 20 / 5 = 4
τy = 4

Object x average torque
τx = ΔLx / Δt = 10 / 5 = 2
τx = 2

Relates τy and τx
2τx = τy

Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey.

The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. The precise relation between torquey and torquex is torquey = 2 * torquex.

To relate torquey to torquex, we are able to use the concept of angular momentum and torque. Angular momentum is described because the manufactured from the moment of inertia and angular velocity:

L = I * ω

Differentiating this equation with an appreciation of time, we get:

dL/dt = d(I * ω)/dt

Using the product rule of differentiation, we've got:

dL/dt = I * dω/dt + ω * dI/dt

Now, we realize that torque (τ) is described because of the charge of the exchange of angular momentum:

τ = dL/dt

Substituting the expression for dL/dt in terms of angular velocity and second of inertia:

τ = I * dω/dt + ω * dI/dt

Let's denote the common price of torque for item X as torquex. Since object X has a moment of inertia I0, we can write:

torquex = I0 * dω/dt + ω * dI0/dt

Now, let's consider item Y. It has a moment of inertia 2I0. Using the identical expression, we will write:

torquey = (2I0) * dω/dt + ω * d(2I0)/dt

torquey = 2I0 * dω/dt + ω * (2 * dI0/dt)

torquey = 2I0 * dω/dt + 2ω * dI0/dt

Comparing the expressions for torquex and torquey, we will see that:

torquey = 2 * torquex

Therefore, the precise relation between torquey and torquex is;

torquey = 2 * torquex.

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The correct question is;

"Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?"

Answer:

velocity and wavelength likely to change in the process.

Explanation:

When an object passes from one medium to another, refraction occurs. Due to refraction, it changes iits direction. Some of the properties is changed when it undergoes refraction. The velocity of a wave and wavelength change in this process.

Hence, the correct option is (a) "velocity and wavelength".

Given that,

Separated in time t = 3.00 μs

Separated in time t' = 9.00 μs

(a). We need to calculate the speed

Using formula of time dilation

\(t'=\dfrac{t}{\sqrt{1-\dfrac{v^2}{c^2}}}\)

\(\dfrac{t}{t'}=\sqrt{1-\dfrac{v^2}{c^2}}\)

\(\dfrac{v^2}{c^2}=1-\dfrac{t^2}{t'^2}\)

\(v=c\sqrt{1-\dfrac{t^2}{t^2}}\)

Put the value into the formula

\(v=c\sqrt{1-\dfrac{3.00^2}{9.00^2}}\)

\(v=0.942c\)

(b). The separation that Mark sees is just the time he sees between the pulse times the speed of light,

Since the first pulse is moving at that speed

We need to calculate the separation in space of the two pulses

Using formula of separation

\(x=ct'\)

Put the value into the formula

\(x=3\times10^{8}\times9\times10^{-6}\)

\(x=2700\ m\)

Hence, (a). The speed of mark relative to Suzanne is 0.942c.

(b). The separation in space of the two pulses is 2700 m.

The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.

The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.

This observation that electromagnetic radiation behaves like particles is known as the photoelectric effect.

It provides evidence that electromagnetic radiation exhibits particle-like properties. When EMR with sufficient energy (above a certain threshold) interacts with a metal surface, it can cause the ejection of electrons from the metal.

This behavior indicates that EMR behaves as discrete packets of energy called photons, which transfer their energy to the electrons and cause their release. The photoelectric effect supports the particle nature of EMR and is a fundamental concept in the field of quantum mechanics.

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To determine the impulse we use the fact that the impulse is equal to the change in momentum:

Where:

The momentum is the product of the mass and the velocity, therefore, we have:

Since the initial velocity is zero, we have:

Now, we substitute the values:

Solving the operation:

Therefore, the momentum is 1607424 kgm/s

The vehicle accelerates at 3 m/s² when velocity changes from 5 m/s to 2m/s.

Detailed explanations are provided below. Step 1: Determine the initial speed (v). The car's initial speed in this instance is 5 m/s.

Step 2: Determine the final speed (vf). The car's final speed is 2 m/s in this instance.

Step 3: Determine the variation in velocity (v).

In this instance, the change in velocity is 3 m/s (5 m/s – 2 m/s), which is the difference between the initial velocity and the final velocity.

Step 4: Determine the acceleration in a.

The acceleration in this instance is 3 m/s², which is calculated by dividing the change in velocity by the amount of time taken.

The rate at which velocity changes is acceleration. Acceleration typically indicates a change in speed, but not always. Because its velocity is changing in the opposite direction, even if an object moves in a circle at the same speed, it will still accelerate.

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The energy transfer that takes place as the ball changes shape during the contact between the racquet and the ball is due to the changes in shape results in deformation of the ball that converts kinetic energy from the racquet into elastic potential energy in the ball.

When a ball strikes a racquet, the kinetic force of racquet causes the ball to compress, which results in a change in its shape and the energy is transferred from the racquet to the ball, and the work done by the racquet on the ball increases the potential energy stored in the compressed ball, and the ball bounces.

Hence, changes in shape results in deformation of the ball and converts kinetic energy present in the racquet to elastic potential energy in the ball and bounces it.

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The question is incomplete, the complete question is here

State the energy transfer that takes place as the ball changes shape during the contact between the racquet and the ball.