Don’t know how to get the answer

If A = 0, then the matrix (I - A)^-1 is equal to (I - 0)^-1 = I^-1 = I, where I is the identity matrix. Therefore, the correct option is (c) I - A.

When A = 0, the matrix (I - A) becomes (I - 0) = I, where I is the identity matrix. The inverse of the identity matrix is also the identity matrix itself, so (I - A)^-1 = I^-1 = I. Therefore, option (c) I - A is equal to (I - A)^-1.

The other options (a) I + A, (b) I + A + A², (d) I - A - A², and (e) I - A + A² do not yield the identity matrix when A = 0. Thus, they are not equal to (I - A)^-1.

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The answer is d. While it is possible for a parallelogram to be a square, it is not a valid conclusion given only the information that ABCD is a parallelogram and has diagonals AB and BD.

A parallelogram is a four-sided plane figure with two pairs of parallel and equal sides. Opposite sides of a parallelogram are of equal length and the opposite angles are of equal measure. The area of a parallelogram is determined by multiplying the length of one side with the height of the parallelogram. Parallelograms are quadrilaterals, which means they have four sides, and are classified by their angles and sides.

To determine if the parallelogram is also a square, additional information such as the length of the sides or angles of the parallelogram would need to be known.

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Complete questions as follows-

Which of the following is not a valid conclusion given parallelogram ABCD with diagonals AB and BD?
a
AB=CD
b
AC=BD
c
d
m

Answer: 135

Step-by-step explanation:

Counting by 5 The last point at the end of the box and whisker plot is 135

Step-by-step explanation:

20 - x = -5

-x = -25

x = 25

the temperature fell by 25°F.

Answer:

.............. ................

To multiply the monomials (-5xy') and (6x²y5), you can use the following formula:

(ax^m)(by^n) = abx^(m+n)y^(m+n)

Where:

- a and b are constants

- x and y are variables

- m and n are the exponents of x and y, respectively

- Plugging in the values for a, b, m, and n, you get:

(-5xy')(6x²y5) = (-5)(6)x^(1+2)y^(1+5)

This simplifies to:

(-5xy')(6x²y5) = (-30)x^3y^6

So, the product of (-5xy') and (6x²y5) is (-30)x^3y^6, which is option (d).

Answer:

i think its a mirror

Step-by-step explanation:

mark as brainliest if its crct

The horizontal distance between the base of the ladder and the wall is approximately 8.892 feet.

Here, we have,

To find the horizontal distance between the base of the ladder and the wall, we can use trigonometric functions.

In this case, the ladder forms an angle of 69 degrees with the ground. We can label this angle as θ.

We know the length of the ladder is 26 feet. We can label the horizontal distance as x.

Using trigonometric functions, specifically cosine, we have:

cos(θ) = adjacent/hypotenuse

cos(69) = x/26

To find x, we can rearrange the equation:

x = 26 * cos(69)

Using a calculator, we can calculate:

x ≈ 26 * 0.3420

x ≈ 8.892

Therefore, the horizontal distance between the base of the ladder and the wall is approximately 8.892 feet.

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Two lines are perpendicular if:

For the line:

We can see that its slope is 2/3, so:

Let:

m1 = 2/3

Therefore:

Now, we have the slope and a point P(6,6), let's use the slope point equation:

The area of the sector is 72f

The given parameters are:

Angle = f

Diameter = 24

Start by calculating the radius

r = Diameter/2

r = 24/2

r = 12

The area of the sector is

A = (θ/2) × r^2

So, we have

A = (f/2) * 12^2

Evaluate

A = 72f

Hence, the area of the sector is 72f

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Answer:

\(5 + 12 > x\)

\(5 + x > 12\)

\(7 < x < 17\)

Answer:

- 14

Step-by-step explanation:

4x + 6 = - 62

4x = - 62 + 6

4x = - 56

x = - 56 / 4

x = - 14

The value of x in this equation will be; x = -14

An equation is an expression that shows the relationship between two or more numbers and variables.

We are given that  the equation 4x + 6 = - 62

Here, we need to solve for x

4x + 6 = - 62

4x = - 62 + 6

4x = - 56

x = - 56 / 4

x = - 14

Therefore, the solution will be as;

x = -14,

The value of x in this equation will be; x = 14

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Assuming that we have two data sets, a and b, with means of 20 and 30, respectively, and the same standard deviation of 5, we can conclude that neither data set is more spread out than the other.

Suppose you have two data sets A and B, with means of 20 and 30, respectively, and the same standard deviation of 5. To determine which data set is more spread out, we need to compare the variance of the two data sets. Since the variance is the square of the standard deviation, we can compare the variances of the two data sets. Using the formula, Var = s², we can calculate the variances of data set A and B.

\(Var(A) = (5)^2 = 25\\Var(B) = (5)^2 = 25\)

Both data sets have the same variance, indicating that they have the same amount of spread, or convergence. Therefore, we can conclude that no data set is more spread out than the other.

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Answer:

Jackson: 8p + 2c = 58

Cooper: 4p + 5c = 49

Step-by-step explanation:

p= popcorn

c= candies

When you write this equation, have the cost on one side of the equation and the coefficients on the other.

Answer:

Jackson is walking an average of 1.5 blocks per minute.

Step-by-step explanation:

6 divided by 4 is 1.5

The speed at Jackson for walking 6 blocks in 4 minutes will be equal to 1.5 blocks per minute.

The four basic mathematical operations are the addition, subtraction, multiplication, and division of two or even more integers. Among them is the examination of integers, particularly the order of actions, which is crucial for all other mathematical topics, including algebra, data organization, and geometry.

As per the instructions provided in the question,

The distance (d) traveled by Jackson = 6 blocks

The time (t) taken to travel 6 blocks by Jackson = 4 minutes

\(Speed(s)=\frac{Distance(d)}{Time(t)}\)

Put values in the above equation,

s = 6/4

s = 1.5 blocks per minute.

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Solution

Step 1

To convert seconds to hours, divide the seconds by 3600.

Step 2

1 million seconds = 1000000 seconds

Answer:

Step-by-step explanation:

four times the sum of a number and 9 is 16

4 *(x + 9) = 16

4x + 36 = 16

4x = 16 - 36

4x = -20

x = -5

---------------

4 * (-5 + 9) = 16

16 = 16

true

A) Approx. 1067 is the required sample size to ensure 95% confidence that the sample proportion will not differ from the true proportion by more than 3%.

B) When the previous estimate is 65%, approx. 971 is the sample size needed to achieve 95% confidence that the sample proportion will not differ by more than 3% from the true proportion.

To determine the sample size needed for estimating the proportion of drivers exceeding the speed limit, we can use the formula for sample size calculation for proportions:

n = (Z² * p * (1 - p)) / E²

where:

n = the sample size.

Z = the Z-value associated with the confidence level of 95%.

p = the estimated proportion or previous estimate.

E = the maximum allowable error, which is 3% or 0.03.

We calculate as follows:

A. No previous estimate for p is available:

Here, we will assume p = 0.5 (maximum variance) since we don't have any prior information about the proportion. So, adding the values into the formula:

n = (Z² * p * (1 - p)) / E²

n = ((1.96)² * 0.5 * (1 - 0.5)) / 0.03²

n= (3.842 * 0.5 * (0.5))/0.03²

n = (1.9208*0.5)/0.0009

n ≈ 1067.11

Thus, to be 95% confident that the sample proportion will not differ from the true proportion by more than 3%, a sample size of approximately 1067 is required.

B. Supposing previous studies found that the sample percentage of drivers who exceeded the speed limit is 65%:

Here, we have a previous estimate of p = 0.65:

Putting the values into the formula:

n = (Z²* p * (1 - p)) / E²

n = ((1.96)² * 0.65 * (1 - 0.65)) / 0.03²

n= (3.842 * 0.65 *(0.35))/0.0009

n ≈ 971

Hence, with the previous estimate of 65%, a sample size of approximately 971 is necessary to be 95% confident that the sample proportion will not differ from the true proportion by more than 3%.

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Answer:

C. Acute

Step-by-step explanation:

Pythagorean theorem can be used to determine the type of triangle any 3 given sides can form.

This,

A right ∆ is formed if a² + b² = c²

An acute ∆ is formed if a² + b² > c²

An obtuse ∆ is formed if a² + b² < c²

Note: c is the longest side of any triangle.

Using the side lengths given:

9.2² + 15.1² ? 17.4²

84.64 + 228.01 ? 302.76

312.65 > 302.76

An acute triangle is formed because a² + b² > c²

Equilibrium is the term refers to coordination, balance, and balance in three dimensional space.

The equilibrium condition of an object exists when Newton's first law is valid. An object is in equilibrium in a reference coordinate system when all external forces (including moments) acting on it are balanced. This means that the net result of all the external forces and moments acting on this object is zero.

There are three types of equilibrium: stable, unstable, and neutral.

Examples of equilibrium in everyday life:

A book kept on a table at rest. A car moving with a constant velocity. A chemical reaction where the rates of forward reaction and backward reaction are the same.

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The absolute value function for this problem is given as follows:

g(x) = |x - 1| - 2.

An absolute value function of vertex (h,k) is defined as follows:

y = a|x - h| + k.

In which a is the leading coefficient.

The coordinates of the vertex for this problem are given as follows:

(1, -2).

As the slope of the line is of 1, the leading coefficient is given as follows:

a = 1.

Hence the absolute value function for this problem is given as follows:

g(x) = |x - 1| - 2.

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The total work done by the worker is approximately 4346.32 J, and the power developed by the worker is approximately 24.14 W.

To calculate the total work done by the worker, we need to consider both the horizontal pushing work and the vertical lifting work.

Horizontal pushing work:

Work (W) = Force (F) × Distance (d) × cos(θ)

where θ is the angle between the force and the displacement.

Since the force is applied horizontally and the displacement is also horizontal, the angle between them is 0 degrees, and cos(0) = 1.

Vertical lifting work:

To calculate the work done in lifting the load vertically, we first need to find the force required to lift the load. The force required to lift the load is equal to the weight of the load:

Weight (Wt) = Mass (m) × Acceleration due to gravity (g)

where g ≈ 9.81 m/s² (approximately, on Earth's surface).

Wt = 60 kg × 9.81 m/s²

Wt ≈ 588.6 N

Now, we can calculate the work done in lifting the load:

W_vertical = Wt × h × cos(0)

where h is the vertical height.

W_vertical = 588.6 N × 1.2 m × 1

W_vertical ≈ 706.32 J

Now, we can find the total work done:

Next, we'll calculate the power developed by the worker. Power is the rate of doing work, and it can be calculated as:

Power (P) = Work (W) / Time (t)

The worker does the work in 3 minutes, so we need to convert this time to seconds:

t = 3 min × 60 s/min = 180 s

Now, we can calculate the power:

P = W_total / t

P ≈ 4346.32 J / 180 s

P ≈ 24.14 W (watts)

So, the total work done by the worker is approximately 4346.32 J, and the power developed by the worker is approximately 24.14 W.

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The question in English is:

A construction worker pushes a 60-kg load across the floor a distance of 14 m by applying a force of 260 N, then lifts the load vertically to a platform that is 1.2 m above the floor. I do this work in a total of 3 minutes. What is the total work and power developed by the worker?

The boundaries of the class 1.87-3.43 are D) 1.865-3.435. The lower boundary is 1.865 and the upper boundary is 3.435.

The boundaries of the class 1.87-3.43 can be determined by subtracting and adding half of the smallest possible unit of measurement to the given class limits. In this case, since the given class limits are 1.87 and 3.43, we need to find the boundaries by subtracting and adding half of the smallest possible unit of measurement.

Let's assume the smallest possible unit of measurement is 0.01.

To find the lower boundary:

Lower Boundary = Lower Limit - (0.01/2)

Lower Boundary = 1.87 - 0.005

Lower Boundary = 1.865

To find the upper boundary:

Upper Boundary = Upper Limit + (0.01/2)

Upper Boundary = 3.43 + 0.005

Upper Boundary = 3.435

Therefore, the boundaries of the class 1.87-3.43 are:

D) 1.865-3.435

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A field trip will be taken by 204 children. One cheoparne must be assigned to every four students. 4  buses will be required if a bus can seat 50 people.

Two hundred and four kids are going on a field trip.

if a bus can hold 50 people

1 bus= 50 people

4 bus = 50* 4 = 200 people

A field trip or excursion is a travel taken by a group of people to a location that is different from their typical habitat. When done for kids, as it is in many school systems, it is referred to as a school trip in the United Kingdom, Australia, New Zealand, and Bangladesh, and a school tour in Ireland.

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Answer:

28 :)

Step-by-step explanation:

Answer:

6 black pieces

10 red pieces

Step-by-step explanation:

The way to interpret ratios is like so:

Adding up both parts of the ratio gives 8, i.e. 3 + 5

So for every 8 pieces, 3 are black and 5 are red;

There are 16 pieces, which is 2 × 8;

So, there are (2 × 3) black pieces and (2 × 5) red pieces, i.e. 6 black and 10 red

So, to solve:

Add all parts of the ratio (3 + 5);

Divide the number of pieces (16) by this sum of ratio parts (8);

Multiply the value from the division (2) by each part of the ratio

Tip:

It is important to take note of the order in the ratio, so the ratio of black to red means the number that comes first in the ratio represents parts black and the one that comes second represents parts red;

If the wording was the ratio of red to black, the number that comes first would represent parts red and the second would represent parts black

The median (the value 33.5). Finally, we add "whiskers" extending from the box to the minimum value (4) and the maximum value (110).

Q1 is 30, Q3 is 52.5, and the IQR is the difference between them (22.5). We draw a line segment inside the box at the median (the value 33.5). Finally, we add "whiskers" extending from the box to the minimum value (4) and the maximum value (110).

For this data, the lower fence is -6.75, and the upper fence is 89.25. None of the values from the list (-2.1, -10, 6.3, 3, 48, 87, 99) lie outside these fences. Hence, there are no outliers within the 5-number summary or in the given list of values.

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