Answer:
A
Explanation:
refer to textbook
What volume of 4.50M hydrochloric acid can be made by diluting 250.0mL of 5.65M HCl?
Answer:
314mL OR 0.314L
Explanation:
this requires the dilution formula M1V1 = M2V2 where
M1 = initial concentration
V1 = initial volume
M2 = final concentration
V2 = final volume
In this case, we are solving for V1 where M1 = 5.65M, V1 = 250.0 mL, and M2 = 4.50M
Plugged into the equation we get:
(5.65M)(250.0mL) = (4.50M)V2
divide both sides by 4.50M and it becomes (M cancel)
V2 = 314mL
Which of the following describes wind direction?
How fast the wind is moving
Where the wind is coming from
How strong the wind is
Where the wind is going
Answer:
where the wind is going
Explanation:
direction is where something is going hope it helps
Answer: number 4 Where the wind is going
Explanation:hope this helps u
2. What must be Final temperature of 200 g of water if it was heated from 30 degree Celsius and
absorbed 400 Joules of energy?
Answer:
400 joules sisisiss
Explanation:
Consider the reaction. 2HF(g)—H2(g)+F2(g). What is the value of Keq for the reaction expressed in scientific notation
Answer:
A). 2.1 × \(10^{-2}\)
Explanation:
Given reaction,
2\(HF\) (g) ⇄ \(H_{2}\) (g) + \(F_{2}\) (g)
The concentrations are as following;
\(HF\) = 5.82 × \(10^{-2}\) M
\(H_{2}\) = 8.4 × \(10^{-3}\) M
\(F_{2}\) = 8.4 × \(10^{-3}\) M
So,
\(K_{eq}\) = [(\(H_{2}\) ) × (\(F_{2}\))] ÷ [\(HF\)]^2
Now,
We can determine the value of \(K_{eq}\) by substituting the values in above formula:
\(K_{eq}\) = [ (8.4 × \(10^{-3}\) M) × (8.4 × \(10^{-3}\) M)] ÷ [(5.82 × \(10^{-2}\))^2
= 2.08 * \(10^{-2}\)
= 2.1 × \(10^{-2}\)
∵ \(K_{eq}\) = 2.1 × \(10^{-2}\)
Thus, option A is the correct answer.
A student walks 100 meters north and then turns around and walks 75 meters back to the south.
A)-What is the student's distance travelled?
B)-What is their displacement?
a) 100 + 75 = 175
b) 100- 75 = 25
If I have an unknown quantity of gas at a pressure of 1.2 atm, a volume of 77 liters, and a temperature of
87 °C, how many moles of gas do I have? 3.12mol
Answer:
I NEED HELP ANSWER MY QUESTIONS PLS
Explanation:
What does the statement mean: "You are as safe as the least safe person in the laboratory"?
Based on laboratory safety protocols, statement "You are as safe as the least safe person in the laboratory" means that the person is not completely safe.
What is safety?Safety refers to the state where an individual or a person is free from danger or harm.
Safety is essential to all individuals in order to ensure that the individual is thriving.
There are several forms of safety that is related to an individual being safe.
The forms of safety may include:
Workplace or occupational safetySafety in the homeSafety at schoolLaboratory safety.In order to ensure that an individual is safe, safety procedures and protocols are put in place which people must follow in order to be safe in their environment.
In the laboratory, because of the presence of hazardous chemical, it is important that safety protocols are followed. Some safety protocols in the laboratory include:
always wear lab coatswear safety gogglesdo not eat in the laboratoryTherefore, the statement "You are as safe as the least safe person in the laboratory" means that the individual is not safe.
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you conducted your amide synthesis of acetophenetidin starting with 6.48 g p-phenetidine (137.18 g/mol), and you isolated 5.72 g of acetophenetidin (179.22 g/mol) at the end of the reaction. assuming that p-phenetidine was the limiting reagent, what is the percent yield for this reaction? report your answer to one decimal place (i.e., 78.4).
The percent yield for this reaction is 50.8%.
First, we need to determine the moles of p-phenetidine used:
Moles of p-phenetidine = mass / molar mass
Moles of p-phenetidine = 6.48 g / 137.18 g/mol
Moles of p-phenetidine = 0.0472 mol
Since p-phenetidine is the limiting reagent, the moles of acetophenetidin produced should be equal to the moles of p-phenetidine used.
The theoretical yield of acetophenetidin can be calculated using the stoichiometry of the reaction:
Theoretical yield = Moles of p-phenetidine × (molar mass of acetophenetidin / molar mass of p-phenetidine)
Theoretical yield = 0.0472 mol × (179.22 g/mol / 137.18 g/mol)
Theoretical yield = 0.0616 mol
Now we can calculate the percent yield:
Percent yield = (actual yield / theoretical yield) × 100
Percent yield = (5.72 g / (0.0616 mol × 179.22 g/mol)) × 100
Percent yield = (5.72 g / 11.2512 g) × 100
Percent yield = 50.8%
Therefore, the percent yield for this reaction is 50.8%.
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What trend does electronegativity follow, going down the periodic table?
A. Electronegativity increases because there are more total electrons
in the atom.
B. Electronegativity increases because there are more valence
electrons in the atom.
C. Electronegativity decreases because the valence electrons are
farther from the nucleus.
D. Electronegativity decreases because the size of the nucleus is
bigger.
Electronegativity decreases because the valence electrons are farther from the nucleus. Hence, option C is correct.
What is electronegativity?Electronegativity is a chemical property that describes the tendency of an atom or a functional group to attract electrons toward itself.
From top to bottom down a group, electronegativity decreases. This is because atomic number increases down a group, and thus there is an increased distance between the valence electrons and nucleus, or a greater atomic radius.
Important exceptions to the above rules include the noble gases, lanthanides, and actinides.
Electronegativity decreases because the valence electrons are farther from the nucleus. Hence, option C is correct.
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if a substance has a mass of 8 grams what is its volume
3) What is the mass of 1 mole of selenium (Se)?
Answer:
78.96 grams
Explanation:
I looked it up and that's what I found
hope it helps
Answer:
78.96 g mol
Explanation:
78.96 g mol
in the period table the mass of Se is 78.96 g mol
Using the following balanced equation: 4(NH4)3PO4 + 3Pb(NO3)4 -> Pb3(PO4)4 + 12NH4NO3 given 6.64 grams of (NH4)3PO4 how many moles of Pb(NO3)4 will also be required
0.0334 moles of Pb(NO₃)₄ are required to react with 6.64 grams of (NH₄)₃PO₄.
We will be following the given balanced chemical equation and starting by finding the number of moles of Pb(NO₃)₄ reacted with (NH₄)₃PO₄,
mass of (NH₄)₃PO₄ = 6.64 g
molar mass of (NH₄)₃PO₄ = 149.086g/mol
number of moles of (NH₄)₃PO₄ = mass/molar mass
= 6.64 g / 149.086g/mol
= 0.0445mol
According to the balanced equation, 4 moles of (NH₄)₃PO₄ react with 3 moles of Pb(NO₃)₄. So, to find the number of moles of Pb(NO₃)₄ required, we can use the following ratio,
x = (3/4)0.0445mol
= 0.0334mol
Therefore, 0.0334 moles of Pb(NO₃)₄ will be required to react completely with 6.64 grams of (NH₄)₃PO₄.
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C. If you were to measure out 0.0237 moles of potassium nitrate into a clear, dry cup. How
many grams are in this sample? Show your work in the space below.
Molar mass of KNO3:.
If you were to measure out 0.0237 moles of potassium nitrate into a clear, dry cup. 2.4 grams are in this sample. Molar mass of KNO₃ is 101.11g/mol.
What is molar mass ?The term molar mass is defined as the mass in grams of one mole of the compound.
Molar mass of KNO₃ = 39.10 + 14.01 + 16 (3)
= 101.11g/mol
Mass (m) = ?
Molar mass (M) = 101.11g/mol
Number of moles (N) = 0.0237 moles
n = m / M
m = 0.0237 × 101.11
= 2.4 grams
Thus, If you were to measure out 0.0237 moles of potassium nitrate into a clear, dry cup. 2.4 grams are in this sample. Molar mass of KNO₃ is 101.11g/mol.
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the carbon-nitrogen-oxygen (cno) cycle in high-mass main-sequence stars burns __________ to __________ in their cores.
The carbon-nitrogen-oxygen (CNO) cycle in high-mass main-sequence stars burns hydrogen to helium in their cores.
In high-mass main-sequence stars, such as massive stars with a mass greater than about 1.5 times that of the Sun, the primary nuclear reaction that powers their cores is the carbon-nitrogen-oxygen (CNO) cycle. This cycle converts hydrogen nuclei (protons) into helium nuclei (alpha particles) through a series of fusion reactions.
The CNO cycle involves the catalytic action of carbon, nitrogen, and oxygen isotopes. In the first step of the cycle, a proton fuses with a carbon-12 nucleus to produce nitrogen-13 and release a gamma ray. Nitrogen-13 then undergoes beta decay, converting a proton into a neutron and transforming into carbon-13. Carbon-13 can capture another proton, forming nitrogen-14. Nitrogen-14 can further undergo fusion reactions with other protons to produce oxygen-15 and eventually return back to carbon-12, completing the cycle.
Overall, the CNO cycle allows high-mass main-sequence stars to convert hydrogen into helium, releasing energy in the process and sustaining the star's energy production.
What elements does the carbon-nitrogen-oxygen (CNO) cycle in high-mass main-sequence stars burn in their cores?
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most chemical reactions in organisms are regulated by organic catalysts known as
Answer:
An enzyme is a substance that acts as a catalyst in living organisms, regulating the rate at which chemical reactions proceed without itself being altered in the process. The biological processes that occur within all living organisms are chemical reactions, and most are regulated by enzymes.
Explanation:
Hope this helps...
What mass of iron should be produced if 11.0g of aluminum react with 30.0g of iron (III) oxide?
The mass of iron produced when 11.0 g of aluminum reacts with 30.0 g of iron (III) oxide is approximately 10.48 grams.
To determine the mass of iron produced when 11.0 g of aluminum reacts with 30.0 g of iron (III) oxide, we need to balance the chemical equation and perform stoichiometric calculations.
The balanced chemical equation for the reaction between aluminum and iron (III) oxide can be written as follows:
2 Al + Fe₂O₃ → 2 Fe + Al₂O₃
From the balanced equation, we can see that 2 moles of aluminum react with 1 mole of iron (III) oxide to produce 2 moles of iron and 1 mole of aluminum oxide.
Convert the given masses of aluminum and iron (III) oxide into moles.
Using the molar mass of aluminum (26.98 g/mol) and iron (III) oxide (159.69 g/mol), we can calculate the number of moles for each substance.
Number of moles of aluminum = mass of aluminum / molar mass of aluminum
= 11.0 g / 26.98 g/mol
= 0.408 moles
Number of moles of iron (III) oxide = mass of iron (III) oxide / molar mass of iron (III) oxide
= 30.0 g / 159.69 g/mol
= 0.188 moles
Determine the limiting reactant.
To determine the limiting reactant, we compare the stoichiometric ratio of aluminum to iron (III) oxide. From the balanced equation, we see that 2 moles of aluminum react with 1 mole of iron (III) oxide.
Given that we have 0.408 moles of aluminum and 0.188 moles of iron (III) oxide, we can calculate the moles of iron that can be produced from each reactant.
Moles of iron from aluminum = 2 * 0.408 moles = 0.816 moles
Moles of iron from iron (III) oxide = 0.188 moles
Since the moles of iron from aluminum (0.816 moles) is greater than the moles of iron from iron (III) oxide (0.188 moles), we can conclude that iron (III) oxide is the limiting reactant.
Calculate the mass of iron produced.
To calculate the mass of iron produced, we use the molar mass of iron (55.85 g/mol) and the number of moles of iron from the limiting reactant.
Mass of iron = moles of iron from iron (III) oxide * molar mass of iron
= 0.188 moles * 55.85 g/mol
= 10.48 g
Therefore, the mass of iron produced when 11.0 g of aluminum reacts with 30.0 g of iron (III) oxide is approximately 10.48 grams.
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An unknown substance has a density of 0. 983 g/cm3. What is this density in ng/µm3?
The density of the unknown substance in ng/µm³ is 0.000983 ng/µm³.
Density refers to the amount of mass contained in a given volume of a substance. It is a physical property of matter that describes how closely packed the particles are in a substance. Mathematically, density is calculated by dividing the mass of an object by its volume, and is expressed in units of mass per unit volume (such as grams per cubic centimeter, or kilograms per liter).
To convert the density from g/cm³ to ng/µm³, we need to use the following conversion factors:
1 g = 1,000,000,000 ng (or 1 x 10⁹ ng)
1 cm³ = 1,000,000,000,000 µm3 (or 1 x 10¹² µm³)
So, we can multiply the density by these conversion factors to get the density in ng/µm³:
0.983 g/cm³ x (1 x 10⁹ ng / 1 g) x (1 cm³ / 1 x 10¹² µm³) = 0.000983 ng/µm³
Therefore, the density of the unknown substance in ng/µm³ is 0.000983 ng/µm³.
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Adenine has a molecular mass of 135. 1 and consist of 44. 45%c, 3. 73%h, and 52. 82%n by mass. Determine its molecular formula
The molecular formula for Adenine with molecular mass of 135.1 and consist of 44. 45% C, 3. 73% H, and 52. 82% N by mass is C₃H₃₆N₂.
The molecular formula expresses the number of atoms of each element in one chemical molecule.
The definition of a molecular formula is the formula that shows the exact number of atoms in a molecule.
The empirical formula is used to derive the Molecular Formula when the molar mass value is known.
n=empirical formula molar mass/mass
The molecular formula is frequently the same as or an exact multiple of an empirical formula.
We have molecular formula = 135.14
so we need to find each atoms contribution so,
C = 135.14 /44.45 = 3.03
H = 135.14 /3.73 = 36.21
N = 135.14 / 52.82 = 2.55
So we have molecular formula as,
C₃H₃₆N₂.
Adenine is a nucleic acid component, specifically the nitrogenous base in the structure. Adenine is a nitrogenous base present on both DNA and RNA molecules (examples of nucleic acids). Adenine is a compound of Carbon, Hydrogen, and Nitrogen atoms, and elemental analysis can assist in determining the chemical formula.
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How much energy, in joules per mole (J/mol), does a photon in the microwave region of the EM spectrum, contain?
The photons have been calculated to contain about 4.97 * 10^-47 J/mol of energy.
What is the energy?We know that a photon is a unit of light. Better put, we can see the photon as a bundle of light and we are able to obtain the energy of that bundle of light as we can see.
Given that;
E = hf
E = energy of the photon
h = Plank's constant
f = frequency of the photon
Then
E = 6.6 * 10^-34 Js * 4.53 x 10^10 s-1
E = 2.99 * 10^-23 J
A mole would have to contain about 6.02 * 10^23 molecules so;
Energy per mole = 2.99 * 10^-23/6.02 * 10^23
= 4.97 * 10^-47 J/mol
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Missing parts;
How much energy, in joules per mole (J/mol), does a photon in the microwave region of the EM
spectrum, contain? Assume the microwave has a frequency of 4.53 x 1010 s-1. Your answer should
have 3 significant figures.
_____ is the process of converting the language of nucleic acids (nucleotides) to the language of proteins (amino acids).
Translation is the process of converting the language of the nucleic acids that is nucleotides to the language of proteins that is amino acids.
The process of the conversion of the nucleic acids that is nucleotides to the language of proteins that is amino acids is called as the translation. In the translation process , the strands of the protein is produced from mRNA molecule. The mRNA is the nucleic acid molecule which formed by the help of the multiple nucleotides that is present together.
The formation of the protein strands is the process of the protein synthesis. It is based on the sequence of mRNA molecule.
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The number of protons is equal to
a the number of neutrons.
b the atomic mass.
c the number of electrons.
d the atomic number.
Answer:
c the number of electrons
which system has a higher entropy? (a) 1 g of solid au at 1064k of 1 g of liquid au at 1064k
The system with a higher entropy would be 1 g of liquid gold at 1064 K, as it has a more disordered arrangement of particles than 1 g of solid gold at the same temperature.
The system with higher entropy would be the one with more disorder or randomness. Entropy is a measure of the number of possible arrangements of the system's particles or molecules, and it increases with increasing disorder.
In this case, we can consider the entropy of 1 g of solid gold at 1064 K versus the entropy of 1 g of liquid gold at the same temperature. At the melting point of gold, 1064 K, both the solid and liquid phases can coexist in equilibrium.
While both phases have the same temperature, the liquid phase has higher entropy than the solid phase. This is because the particles in the liquid phase are less ordered and more randomly distributed than those in the solid phase, which are arranged in a regular crystalline structure.
Therefore, the system with a higher entropy would be 1 g of liquid gold at 1064 K, as it has a more disordered arrangement of particles than 1 g of solid gold at the same temperature.
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What is the periodic table?
Answer:
The periodic table, also known as the periodic table of chemical elements, is a tabular display of the chemical elements. It is widely used in chemistry, physics, and other sciences, and is generally seen as an icon of chemistry.
Explanation:
The periodic table is a tabular arrangement of chemical elements that classifies elements according to repeating qualities and is structured by increasing atomic number. Metals are located on the left side of the table, whereas nonmetals are located on the right. The columns are referred to as groupings.
in pic
____________________________________________________
(Hope this helps can I pls have brainlist (crown)
which model of an atom is correctly labeled?
Answer:
B
DUH
The nucleus is made up of the protons (which have a positive charge) and neutrons and surrounded by a cloud of electrons ( which have a negative charge ).
Calculate the concentrations of hydronium ion and hydroxide ion at 25°C in: (a) 0.10 M HCl, (b) 1.4 × 10–4 M Mg(OH)2, a strong base. answer with steps please
Ai. The concentration of hydronium ion, [H₃O⁺], is 0.10 M
Aii. The concentration hydroxide ion, [OH⁻] is 1×10⁻¹³ M
Bi. The concentration of hydronium, ion [H₃O⁺], is 3.57×10⁻¹¹ M
Bii. The concentration hydroxide ion, [OH⁻] is 2.8×10¯⁴ M
A. How do i determine [H₃O⁺] and [OH⁻] of 0.10 M HCl?i. The concentration of hydronium ion, [H₃O⁺] can be obtained as follow:
HCl(aq) + H₂O <=> H₃O⁺(aq) + Cl⁻(aq)
From the above equation,
1 mole of HCl contains 1 mole of H₃O⁺
Therefore,
0.10 M HCl will also contain 0.10 M H₃O⁺
Thus, the concentration of hydronium ion, [H₃O⁺] is 0.10 M
ii. The concentration of hydroxide ion, [OH⁻] can be obtained as follow:
Concentration of hydronium, ion [H₃O⁺] = 0.10 MConcentration hydroxide ion, [OH⁻] =?[H₃O⁺] × [OH⁻] = 10¯¹⁴
0.10 × [OH⁻] = 10¯¹⁴
Divide both side by 3.02×10⁻¹⁰
[OH⁻] = 10¯¹⁴ / 0.10
[OH⁻] = 1×10⁻¹³ M
Thus, concentration of hydroxide ion, [OH⁻] is 1×10⁻¹³ M
B. How do i determine [H₃O⁺] and [OH⁻] for 1.4×10¯⁴ M Mg(OH)₂?First, we shall obtain concentration hydroxide ion, [OH⁻]. Details below:
Mg(OH)₂(aq) <=> Mg²⁺(aq) + 2OH⁻(aq)
From the above equation,
1 mole of Mg(OH)₂ is contains 2 mole of OH⁻
Therefore,
1.4×10¯⁴ M Mg(OH)₂ will contain = 1.4×10¯⁴ × 2 = 2.8×10¯⁴ M OH⁻
Thus, concentration hydroxide ion, [OH⁻] is 2.8×10¯⁴ M
Now, we shall obtain the concentration of hydronium, ion [H₃O⁺]. Details below:
Concentration of hydroxide ion, [OH⁻] = 2.8×10¯⁴MConcentration of hydronium, ion [H₃O⁺] = ?[H₃O⁺] × [OH⁻] = 10¯¹⁴
[H₃O⁺] × 2.8×10¯⁴ = 10¯¹⁴
Divide both side by 2.8×10¯⁴
[H₃O⁺] = 10¯¹⁴ / 2.8×10¯⁴
[H₃O⁺] = 3.57×10⁻¹¹ M
Thus, the concentration of hydronium, ion [H₃O⁺], is 3.57×10⁻¹¹ M
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Which image shows a foliated metamorphic rock?
light colored rock with fine grains and metallic luster.
Smooth green rock.
dark color rock with coarse grains in parallel layers.
Answer:
C
Explanation:
The answer is in the image.
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Walk in faith and trust in God!
2 03(g) → 3 0₂(8) AH=-285 kJ/mol,
The bond enthalpy of the oxygen-oxygen bond in O, is 498 kJ/mol. Based on the enthalpy of the reaction represented above, what is the average bond enthalpy, in kJ/mol, of an oxygen-oxygen bond in 03?
Explanation:
=> The simplest form of
56
:
98
56:98 is
4
:
7.
4:7.
Step-by-step explanation:
Given ratio -
56
:
98
56:98
We have to reduce it to its simplest form,
For that, we have to find the GCD of the numerator as well as the denominator:
So, the GCD for
56
56 and
98
98 is
14.
14.
Now, divide both the numerator and denominator by the GCD:
=
>
56
÷
14
98
÷
14
=>
98÷14
56÷14
=
>
4
7
=>
7
4
Hence, the simplest form is
4
:
7.
4:7.QUESTION 4 [5 MARKS] Table 5 (a) Assume the consumption function takes the form \( \mathrm{C}=\mathrm{Ca}+(\mathrm{c}) \mathrm{Y} \), then the consumption function based on the information in Table 5
The consumption function based on the information in Table 5 is as follows: C = 2577 + 0.75Y. It is given, Consumption function, C = Ca + cY Where, Ca is autonomous consumption expenditure, c is marginal propensity to consume (MPC)Y is disposable income
The consumption function based on the information in Table 5 is: Table 5Income(¥ billions)
Consumption(¥ billions)100025020007526000102772750120301.
Write the consumption function in the given format. Ca = Autonomous consumption expenditure c = MPCY = Disposable Income Calculation:
We can obtain the value of Ca as follows: C = Ca + cY
Put the given values, C = 2577Ca + 0.75YAt Y = 1000 billion, C = 2577(1) + 0.75(1000)
= 8327 billion
At Y = 2000 billion, C = 2577(1) + 0.75(2000)
= 13277 billion
At Y = 3000 billion, C = 2577(1) + 0.75(3000)
= 18277 billion
At Y = 4000 billion, C = 2577(1) + 0.75(4000)
= 23277 billion
At Y = 5000 billion, C = 2577(1) + 0.75(5000)
= 28277 billion
Therefore, the consumption function based on the information in Table 5 is as follows: C = 2577 + 0.75Y.
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A CaCl2 solution with a mass of 50.0 grams contains 30.0% CaCl2. This solution reacts with 35.0 grams of AgNO3, one of the products is the precipitate AgCl. Calculate the following: a.) The excess material and the grams of excess material b.) The moles of AgCl produced c.) The grams of Ca(NO3)2 produced
a. AgNO3 is the reaction's surplus ingredient. The amount of AgNO3 utilised in the process, 35.0 grammes, is represented by the surplus material.
Therefore, 35.0 grammes of extra material are present. b.) The molar mass of AgCl may be used to compute the moles of AgCl that were created. AgCl has a molar mass of 143.32 g/mol. As a result, 0.245 moles of AgCl were created.
c.) The molar mass of Ca(NO3)2 may be used to compute the grammes of Ca(NO3)2 produced. Ca(NO3)2 has a molar mass of 164.09 g/mol. As a result, 3.91 grammes of Ca(NO3)2 were generated.
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Help me please fast
(c) Ethene and but-2-ene are alkenes
0) Draw the displayed formula of but 2 ene
Answer:
Alkenes are those organic compound which have double carbon bond
Formula of but-2-ene = C4H8