Answer:
Yes, She is
Step-by-step explanation:
There are 36 possible outcomes of rolling two dice cubes once. For every roll, the probability that she would get the sum of 3 twice. So for 75 rolls, The probability of getting a sum of 3 = 2 * 75 = 150
a company's _______ function is the money generated by selling x units of its product. the difference between this function and the company's cost function is called its ________ function.
Solve. x/2 - 7/6 < 4/3
x < -5
x > -5
x < 5
x > 5
Answer:
x<5
Step-by-step explanation:
x/2-7/6<4/3
x/2<4/3+7/6
x/2<8/6+7/6
x/2<15/6
x<15/6*2
x<30/6
x<5
Sumita buys a set of earphones for £13.42.
She pays with £15.
How much change does she get?
Give your answer in £.
Answer:
Okay the answer is £1.56
Step-by-step explanation:
£15.00
-£13.42
£01.58
Brainliest if you liked the answer.
Formulate but do not solve the following exercise as a linear programming problem.
National Business Machines manufactures two models of portable printers: A and B. Each model A costs $120 to make, and each model B costs $140. The profits are $25 for each model A and $40 for each model B portable printer. If the total number of portable printers demanded per month does not exceed 3000 and the company has earmarked not more than $600,000/month for manufacturing costs, how many units of each model should National make each month to maximize its monthly profits P in dollars?
To formulate this problem as a linear programming problem, we need to identify the decision variables, objective functions, and constraints.
Decision Variables:
Let x be the number of model A printers manufactured per month, and y be the number of model B printers manufactured per month.
Objective Function:
The objective is to maximize monthly profits, which can be expressed as P = 25x + 40y.
Constraints:
1. The total number of printers demanded per month cannot exceed 3000, so we have the constraint x + y ≤ 3000.
2. The company has earmarked not more than $600,000/month for manufacturing costs, so the cost constraint is 120x + 140y ≤ 600,000.
3. The number of printers manufactured must be non-negative, so x ≥ 0 and y ≥ 0.
Therefore, the linear programming problem is:
Maximize P = 25x + 40y
Subject to:
x + y ≤ 3000
120x + 140y ≤ 600,000
x ≥ 0, y ≥ 0
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find the distance between the points (-5.4,-9.5) and (-5.4, -5.5)
Answer:
4 units
Step-by-step explanation:
formula
d = √(x2-x1)^2 + (y2-y1)^2
then fill in the spots
d = √(-5.4+5.4)^2 + (-5.5+9.5)^2
the subtraction sign became an addition sign due to it being a double negative
Hope this helped
What is 5+2 x 1-3+8 and 2+5 x 1
Answer:
Step-by-step explanation:
1) 5+2*1-3+8 = 5+2-3+8 = 7-3+8 = 4+8 = 12
2) 2+5*1 = 2+5 = 7
Answer:
a) 5+2 x 1-3+8
5+2-3+8
=12
b) 2+5 x 1
2+5
=7
Step-by-step explanation:
Convert the complex number 4 (cos 0° + i sin 0°) into rectangular (standard) form.
Express your answer in simplest radical form.
The rectangular (standard) form of the complex number is simply 4.
What is trigonometry?
Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles. It focuses on the study of trigonometric functions, which are functions that relate the angles of a triangle to the ratios of the lengths of its sides.
The rectangular (standard) form of a complex number is typically written as a + bi, where a and b are real numbers, and i is the imaginary unit (√-1). However, in the case of the given complex number 4(cos 0° + i sin 0°), it can be simplified to 4(1 + 0i), since cosine and sine of 0° are equal to 1 and 0 respectively.
The complex number 4(cos 0° + i sin 0°) can be simplified as:
4(cos 0° + i sin 0°) = 4(1 + 0i)
= 4
Therefore, the rectangular (standard) form of the complex number is simply 4.
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Consider what you know about the sampling distribution of the sample proportion. This sampling distribution will?
a. become more variable as the sample size increases.
b. will be Normal in shape only if the sample size is at least 100.
c. will have a center equal to the population proportion, or p
d. has a shape that is skewed to the right, regardless of sample size.
e. is a collection of the parameters of all possible samples of a particular size taken from a particular population
Option C is the correct option.
The sampling distribution of proportion have center equal to population proportion.
As per the details share in the above question are as follow,
The details are as follow,
Only if: Is the proportion sampling distribution regularly distributed.
\(\mathrm{np} > 5 \text { and } \mathrm{n}(1-\mathrm{p}) > 5\)
The survey proportion's anticipated value is \(\mathrm{E}(\hat{\mathrm{p}})=\mathrm{p}\).
As a result, the center of the proportional sampling distribution is equal to the population percentage.
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how many 7 digit phone numbers are there in which the digits are non-increasing? that is, every digit is less than or equal to the previous one.
Using the combination, 1716 are 7 digit phone numbers in which the digits are non-increasing and every digit is less than or equal to the previous one.
In the given question,
We have to find how many 7 digit phone numbers are there in which the digits are non-increasing and that is, every digit is less than or equal to the previous one.
We have to write 7 digit phone number.
Let the 7 digit are
A, B, C, D, E, F, G
Every digit is less than or equal to the previous one.
A ≥ B ≥ C ≥ D ≥ E ≥ F ≥ G
The sum of these number is 7.
So |A| + |B| + |C| + |D| + |E| + |F| + |G| = 10
We always have precisely one non-increasing digit for any given set of seven digits. Therefore, the solution to our problem is to make it simpler to calculate the total number of combinations where 7 digits must be chosen from a set of 7 digits where each digit is repeatable.
So the solution should be
= \(^{7+7-1}C_{7}\)
= \(^{13}C_{7}\)
We know that \(^nC_{r}=\frac{n!}{r!(n-r)!}\)
= \(\frac{13!}{7!(13-7)!}\)
= \(\frac{13!}{7!6!}\)
Simplifying
= \(\frac{13\times12\times11\times10\times9\times8\times7!}{7!\times6\times5\times4\times3\times2\times1}\)
Simplifying
= 13×11×2×3×2
= 1716
Hence, 1716 are 7 digit phone numbers in which the digits are non-increasing and every digit is less than or equal to the previous one.
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you want to make a confidence interval for the true average humidity at noon on uf campus in september. a random sample of 5 days reveals the following numbers: 55 62 63 63 76 what is the standard error of the sample mean, x-bar? important: keep all significant digits in your calculator until the very end.
The standard error of the sample mean is 1.1793
The approximate standard deviation of a statistical sample population is known as the standard error (SE). By utilizing standard deviation, the standard error is a statistical concept that assesses how accurately a sample distribution represents a population.
The given humidities are 55 62 63 63 76
Do we have to find the standard error of the sample mean =?
The formula for the standard error is
SE = σ/n
The mean value is
x = (∑i\(x_{i}\) )/n
= (55+62+63+63+76)/5
= 319/5
= 63.8
Now the standard deviation is
σ = √((∑i〖(\(x_{i}\) -μ)〗^2 )/(n-1))
= √(〖(53-63.8)〗^2+〖(62-63.8)〗^2+...........+〖(76-63.8)〗^2 )/(5-1)
= √((-116.64-3.24-0.64-0.64+148.84)/4)
= √(27.86/4)
= √6.92
= 2.630
The value of standard error is
SE = σ/√n
= 2.630/√5
= 2.630/2.230
= 1.1793
Therefore the standard error is 1.1793
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Question 14 1pts A store manager studied the relationship between the number of umbrellas sold each month (y) and the monthly rainfall (x,mm) obtained the least square regression line based on the data of the past two years: 9-11.5+0.36x. If he also obtains the standard deviations for X andy as X-30.5, _Y-24.4,find the linear correlation r betweenx andy: r-0450 r-0.288 r-0.715 r-0.680
The formula for the linear correlation coefficient (r) between two variables x and y is given by: r = cov(x,y) / (std(x) * std(y)). Answer : we don't know the value of cov(x,y), we can't calculate r.
r = cov(x,y) / (std(x) * std(y))
where cov(x,y) is the covariance between x and y, and std(x) and std(y) are the standard deviations of x and y, respectively.
From the given information, we have:
Regression line: y = 9 - 11.5x + 0.36x
Standard deviations: std(x) = 30.5, std(y) = 24.4
To find the covariance between x and y, we need to know the values of x and y for the past two years. Assuming we don't have that information, we can use the regression line to estimate the values of y based on the given values of x.
Using the regression line, we have:
y = 9 - 11.5x + 0.36x
Substituting x with x - mean(x) and y with y - mean(y), we get:
y - mean(y) = 9 - 11.5(x - mean(x)) + 0.36(x - mean(x))
Expanding and simplifying, we get:
y - mean(y) = -11.14x + 344.7
Now we can use this equation to estimate the values of y for the given values of x, and then calculate the covariance and correlation coefficient.
Using the given values of x, we have:
x = [unknown values for the past two years]
Using the regression line to estimate the corresponding values of y, we get:
y = [9 - 11.5x + 0.36x for the unknown values of x]
Calculating the covariance between x and y, we get:
cov(x,y) = sum((x - mean(x)) * (y - mean(y))) / (n - 1)
where n is the number of observations. Since we don't have the actual values of x and y, we can't calculate the covariance directly.
Finally, using the formula for r, we get:
r = cov(x,y) / (std(x) * std(y))
Since we don't know the value of cov(x,y), we can't calculate r. Therefore, the answer is indeterminate.
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FILL THE BLANK. The average time a molecule spends in its reservoir is known as ________.
The average time a molecule spends in its reservoir is known as the residence time.
Residence time is an important concept in environmental science, particularly in the study of water quality and pollution. It refers to the average amount of time that a substance, such as a molecule or a pollutant, spends in a particular environment before it is either removed or transformed. For example, in a river, the residence time of a pollutant would be the amount of time it takes for that pollutant to be either broken down by natural processes or transported downstream to another location. By understanding residence time, scientists can better predict how pollutants will move through the environment and where they are likely to accumulate.
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Help me pls i need help ‼️‼️‼️
Answer:
C. 3x+2=4
Step-by-step explanation:
6x+4=8
Subtract 4 from both sides.
6x=4
Divide both sides by 6
x=4/6
Simplify it
x=2/3
3x+2=4
Subtract both sides by 2
3x=2
Divide both sides by 3
x=2/3
Hope this helps
Answer and Step-by-step explanation:
The correct answer choice is answer choice 3. [ 3x + 2 = 4 ]
6x + 4 = 8
6x = 4
x = 2/3
_________________________________________________________
3x + 2 = 4
3x = 2
x = 2/3
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A circle has a radius of 7 m what is its circumference. Use 3.14 pi and do not round your answer be sure to include the correct units in your answer
good luck and good luck on your search new
Answer:
43.96
Step-by-step explanation:
Circumference formula = 2πr
2*3.14*7 = 43.96
Yw.
2.
A relay race lasts 12. 72 miles. There are 4
runners on the relay team. If each runner
runs the exact same distance, how many
miles does each team member run during
the race?
Your answer
Answer:
The answer is 3.18 miles/runner.
Step-by-step explanation:
To solve this problem, we need to find the distance that each member of the team runs. To do this, we have to divide the total distance of the race (12.72 miles) by the number of runners on the team (4 runners).
If we perform this operation, we get:
12.72 miles/4 runners
= 3.18 miles/runner
Therefore, the correct answer is that each team member runs 3.18 miles during the race.
Hope this helps!
Which answer shows 1. The mean of the distribution of x ii. The standard deviation of the distribution of ii. The mean of the distribution of iv. The standard deviation of the distribution of o A. i. Wz= np 24 P(-2) 2 iv. ww(1-P) O B. iM = 10 ii. 9 = (1-2) iii. -pl Dil iv. = n O C. 1.5 - (1-2) ivo, a PC 22 O D. i. Px= iii. 6 = 0(1-P) iv. Op O E. i./ ii.d = P() 2 iv. 8 = Jn
The mean of the distribution of \(\bar{x}\) and \(\bar{p}\) are \(\mu_{\bar{x}}=\mu\) and \(\mu_{\bar{p}}=p\). The standard deviation of the distribution of \(\bar{x}\) and \(\bar{p}\) are \(\sigma_{\bar{x}}=\frac{\sigma}{\sqrt{n}}\) and \(\sigma_{\bar{p}}=\sqrt{\frac{p(1-p)}{n}}\). So a suitable option is option D.
A distribution is the collection of all potential values for terms that reflect specified events in statistics. It is possible to calculate the expected value or mean of a statistical distribution by integrating the product of the variable's probability and the distribution's definition of that probability. This is represented by the symbol μ.
The term "standard deviation" refers to a measurement of the data's dispersion from the mean. A low standard deviation implies that the data are grouped around the mean and a higher standard deviation shows that the data are more dispersed. This is represented by the symbol σ.
Here, the expected value for \(\bar{x}\) is written as \(\mu_{\bar{x}}=\mu\) , and the standard deviation for \(\bar{x}\) is written as \(\sigma_{\bar{x}}=\frac{\sigma}{\sqrt{n}}\). Similarly, the expected value for \(\bar{p}\) is written as \(\mu_{\bar{p}}=p\), and the standard deviation for \(\bar{p}\) is written as \(\sigma_{\bar{p}}=\sqrt{\frac{p(1-p)}{n}}\). Therefore, the correct option for this will be D.
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The complete question is -
Which answer shows
i. The mean of the distribution of \(\bar{x}\).
ii. The standard deviation of the distribution of \(\bar{x}\).
iii. The mean of the distribution of \(\bar{p}\).
iv. The standard deviation of the distribution of \(\bar{p}\).
A.
i. \(\mu_{\bar{x}}=np\)
ii. \(\sigma_{\bar{x}}=\sqrt{\frac{p(1-p)}{n}}\)
iii. \(\mu_{\hat{p}}=np\)
iv. \(\sqrt{np(1-p)}\)
B.
i. \(\mu_{\hat{p}}=np\)
ii. \(\sigma_{\bar{x}}=\sqrt{np(1-p)}\)
iii. \(\mu_{\hat{p}}=\sqrt{np(1-p)}\)
iv. \(\sigma_{\bar{p}}=\sqrt{\frac{p(1-p)}{n}}\)
C.
i. \(\mu_{\bar{x}}=p\)
ii. \(\sigma_{\bar{x}}=\frac{\sigma}{\sqrt{n}}\)
iii. \(\mu_{\hat{p}}=\bar{x}\)
iv. \(\sigma_{\hat{p}}=\sqrt{\frac{p(1-p)}{n}}\)
D.
i. \(\mu_{\bar{x}}=\mu\)
ii. \(\sigma_{\bar{x}}=\frac{\sigma}{\sqrt{n}}\)
iii. \(\mu_{\bar{p}}=p\)
iv. \(\sigma_{\bar{p}}=\sqrt{\frac{p(1-p)}{n}}\)
E.
i. \(\mu_{\bar{x}}=\mu\)
ii. \(\sigma_{\bar{x}}=\sqrt{\frac{p(1-p)}{n}}\)
iii. \(\mu_{\bar{p}}=p\)
iv. \(\sigma_{\hat{p}}=\frac{\sigma}{\sqrt{n}}\)
Mrs. Williams made her homemade chicken soup she made 6 3⁄4 cups of soup each servings was 1 1⁄8 cup how many servings are there trying to explain to her how to do it not just give her the answer that it's 6
Answer:
Mrs. Williams made her homemade chicken soup. She made 6 3/4 cups of soup. Each serving size was 1 1/8 cup. = 6
Step-by-step explanation:
this picture below shows how to solve the problem step by step hope this really helps !
each month maria earns $225 plus $5 for each newspaper subscription she sells. which equation can be used to best determine x, the number of subsciptions maria must sell, if she wants to earn at least $400 next month? need help ASAP
Ruben put an empty cup underneath a leaking faucet. After 1 ½ hours, Ruben had collected ¼ cup of water. What is the rate, in cups per hour, at which the water is leaking from the faucet? (Write your answer as a fraction)
Given :
Ruben put an empty cup underneath a leaking faucet.
After 1 ½ hours, Ruben had collected ¼ cup of water.
To Find :
The rate, in cups per hour, at which the water is leaking from the faucet.
Solution :
Rate in which cup is filling with water.
\(R=\dfrac{Portion\ of \ water \ filled }{Time\ taken}\\\\R = \dfrac{\dfrac{1}{4}}{1\dfrac{1}{2}}\\\\R= \dfrac{1\times 2}{4\times 3}\\\\R = 0.167 \ cup/hour\)
Therefore, the rate is 0.167 cup/hour.
Thirteen out of 20 emails in your inbox are junk emails. What is the experimental probability that your next email is junk? Give your answer as a fraction, decimal and percent (in this order).
Fraction =
Decimal =
Percent = %
Answer:
Fraction = 13/20
Decimal = 0.65
Percent = 65%
Step-by-step explanation:
Given:
13 out of 20 emails in mail inbox are junk emails
Solve for:
The experimental probability that next email is junk
Solution:
Step 1: Define the formula for calculating the probability
P = number of elements/total number of elements
Step 2: Perform the calculation
The number of elements (junk emails) = 13
The total number of elements (all emails) = 20
=> P(obtain odd number in experiment) in fraction form = 13/20
=> P(obtain odd number in experiment) in decimal from = 0.65
=> P(obtain odd number in experiment) in percent form = 0.65 x 100 = 65%
Hope this helps!
:)
What is an equation of the line that passes through the points (4, 3) and (7, 3)?
T/F. All first order linear differential equations should be solved by using the method of integrating factors.
The statement "T/F. All first order linear differential equations should be solved by using the method of integrating factors" is False.
Explanation:First-order linear differential equations are those equations which are of the form y' + p(t)y = q(t). The Integrating factor method is one way of solving such differential equations. However, it is not the only method that can be used. There are other methods that can be used to solve such differential equations as well.It is not true that all first-order linear differential equations should be solved using the method of integrating factors. However, this method can be useful in many cases.
Differential equations are mathematical equations that involve derivatives. They are used to describe and model a wide range of phenomena in science, engineering, and other fields. A differential equation typically relates a function or a set of functions to their derivatives.
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The correct answer is False, not all first order linear differential equations should be solved by using the method of integrating factors.
Linear differential equations are types of differential equations that have only one independent variable and its derivatives.
Linear differential equations can be expressed in the following form:
y' + p(x)y = q(x)where y is the dependent variable, p(x) and q(x) are continuous functions of x.
There are several methods of solving linear differential equations, one of which is the method of integrating factors. This method is used when the coefficient of the y term is not constant.
The method of integrating factors involves multiplying both sides of the differential equation by an integrating factor to transform the equation into a form that can be easily solved by integration.
However, not all first order linear differential equations require the method of integrating factors for their solution. Some can be solved using separation of variables, while others can be solved using other methods.
Therefore, the statement "All first order linear differential equations should be solved by using the method of integrating factors" is false.
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(Competing patterns among coin flips) Suppose that Xn, n 2 1 are i.i.d. random variables with P(X1 = 1) = P(X1 = 0) = }. (These are just i.i.d. fair coin flips.) Let A = (a1, a2, a3) = (0,1, 1), B = (b1, b2, b3) = (0,0, 1). Let TA = min(n 2 3: {X,-2, Xn-1, Xn) = A} be the first time we see the sequence A appear among the X, random variables, and define Tg similarly for B. Find the probability that P(TA < TB). (This is the probability that THH shows up before TTH in a sequence of fair coin flips.)
The probability of A appearing before B is \(\frac{4}{7}\).
To find the probability that TA < TB, we can use the fact that the probability of a certain pattern appearing in a sequence of coin flips is independent of the position in the sequence. In other words, the probability of A appearing at time n is the same as the probability of A appearing at time n+k for any k.
Using this fact, we can set up a system of equations to solve for the probability of TA < TB. Let p be the probability of A appearing before B, and q be the probability of B appearing before A. Then we have:
\(p = \frac{1}{2} + \frac{1}{2q}\) (since the first flip can be either 0 or 1 with equal probability)
\(q= \frac{1}{4p} + \frac{1}{2q} + \frac{1}{4}\) (if the first two flips are 0, the sequence B has appeared; if the first flip is 1 and the second is 0, the sequence is neither A nor B and we start over; if the first flip is 1 and the second is 1, we have a new chance for A to appear before B)
Solving for p, we get:
\(p=\frac{4}{7}\)
Therefore, the probability of A appearing before B is \(\frac{4}{7}\).
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Solve the inequality. 15 < 4 + x
Answer:
x > 11
Step-by-step explanation:
15 < 4 + x
Subtracting 4 from both sides (to get rid of the 4 on the right side) gives us:
15 - 4 < 4 + x - 4
11 < x
Answer:
x>11
Step-by-step explanation:
15<4+x
Simplify both sides of the inequality.
15<x+4
Flip the equation.
x+4>15
Subtract 4 from both sides.
x+4−4>15−4
x>11
1. What is m
A 51
B 129
C 134
D 141
Rewrite the Expressions using Distributive Property
(2+3)6
Answer:
Step-by-step explanation:
If you distribute 6 to the numbers inside the parenthesis, it means that you multiply both number by 6
2 x 6 = 12
3 x 6 = 18
the expression can be rewritten like the following:
12 + 18 = 30
Please help, I have trouble with this-
The value of b in the triangle is 10.6 units.
How to find the side of a triangle?A triangle is a a polygon with three sides. Therefore, the sides of the triangle can be found using the sine law.
Hence,
a / sin A = b / sin B = c / sin C
Therefore,
b / sin 27° = 15 / sin 40
cross multiply
b sin 40 = 15 sin 27
divide both sides by sin 40°
b = 15 sin 27 / sin 40
b = 15 × 0.45399049974 / 0.64278760968
b = 6.795 / 6.795
b = 10.5841121495
Therefore,
b = 10.6 units
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A company makes wax candles shaped like rectangular prisms. Each candle is 4 cm long, 3 cm wide, and 10 cm tall. If the company used 4080 cm of wax, how many candles did they make?
Answer:
34
Step-by-step explanation:
You can solve this problem by finding the volume of the candle first. The formula for rectangular prism is multiplying all three of its dimension. In this case, you would multiply 3, 10, and 4 together to get 120 cm^3. Assuming the question meant "the company used 4080 cm^3 of wax", divide 4080 by 120 to see the number of candles the company made, which is 34.
which point is a solution to the inequality shown in this graph? (0, 1) (3, -1)
options:
a (0, -5)
b (5, -5)
c (3, -1)
d (0, 0)
Answer:
the answer is (3, -1)
Step-by-step explanation: Ap3X
At the end of 1st Quarter of 2009 the median price of a single-family home in Charleston/No. Charleston was $184,990. Single-family home prices in Charleston/No. Charleston decreased from the 1st Qtr of 2008 by 8.15%. NOTE: Depreciation means a negative value for r. (a). Estimate the median price of a single-family home in the 1st Qtr of 2008.
(b). If the median price of a single-family home falls at the same rate for the next 2 years, estimate the median price of a single-family home in the 1st Qtr of 2011.
The estimated median price of a single-family home in Charleston/No. Charleston in the 1st Quarter of 2008 is $201,048. If the median price continues to decrease at the same rate for the next two years, the estimated median price of a single-family home in the 1st Quarter of 2011 would be $144,458.
(a) To estimate the median price of a single-family home in the 1st Quarter of 2008, we need to calculate the original price before the 8.15% decrease. Let's assume the original price was P. The price after the decrease can be calculated as P - 8.15% of P, which translates to P - (0.0815 * P) = P(1 - 0.0815). Given that the end of 1st Quarter of 2009 median price was $184,990, we can set up the equation as $184,990 = P(1 - 0.0815) and solve for P. This gives us P ≈ $201,048 as the estimated median price of a single-family home in the 1st Quarter of 2008.
(b) If the median price of a single-family home falls at the same rate for the next two years, we can calculate the price for the 1st Quarter of 2011 using the estimated median price from the 1st Quarter of 2009. Starting with the median price of $184,990, we need to apply an 8.15% decrease for two consecutive years. After the first year, the price would be $184,990 - (0.0815 * $184,990) = $169,805.95. Applying the same percentage decrease for the second year, the price would be $169,805.95 - (0.0815 * $169,805.95) = $156,012.32. Therefore, the estimated median price of a single-family home in the 1st Quarter of 2011 would be approximately $144,458.
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