during a solar eclipse, the moon, earth, and sun all lie on the same line, with the moon between the earth and the sun.

Answers

Answer 1

The negative sign means the Moon is being pulled by the Sun more than it is being pulled by the Earth. Net force on Moon is  -2.237×10^26 N

F = G * (M1 * M2) / R^2

G = 6.67×10^-11 m^3/(kg*s)

M = Mass of object

R = Distance between objects

F = force

Force between Moon and Earth

G * (7.35×10^22 kg * 5.97×10^24 kg) / (3.84×10^5 km)^2 = 1.98×10^26 N

Force between Moon and Sun

G * (7.35×10^22 kg * 1.99×10^30 kg) / (1.50×10^8 km - 3.84×10^5 km)^2 = 4.36×10^26 N

Net force on Moon

1.98×10^26 N - 4.36×10^26 N = -2.237×10^26 N

The negative sign means the Moon is being pulled by the Sun more than it is being pulled by the Earth.

Only the Moon orbits Earth naturally. With a diameter around one-fourth that of Earth, it is the largest and most massive satellite in relation to its home planet and the fifth largest satellite in the Solar System overall[f] (comparable to the width of Australia). [16] According to geophysical definitions of the term, the Moon qualifies as a satellite planet and is larger than other known dwarf planets of the Solar System because it is a planetary-mass object with a differentiated rocky body. [17] It has no major magnetic field, atmosphere, or hydrosphere. The only satellite in the Solar System known to have a higher surface gravity and density is Jupiter's moon Io, which has a gravity and density around one-sixth that of Earth (0.1654 g).

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Related Questions

When is an object positively charged?

Answers

Answer:

when it has a fewer amount of electrons than protons

The angular speed of Earth is 1.99 x 10-7 radians /seconds.

Answers

Yes, that is correct. The angular speed of Earth is 1.99 x 10-7 radians per second. This is equal to 2π radians per year, or 1 revolution per 365.25 days.

The angular speed of the Earth is the rate at which it rotates around its own axis. It is measured in radians per second, and is typically expressed as 2π radians per day, or 7.27 x 10-5 rad/s. The angular speed of the Earth is constant, meaning that it does not change over time. This is important, as it allows us to measure the length of a day and use this to calculate the rate of other processes such as the seasons and the passage of time.

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Suppose three forces are acting on a model rocket launching into the air. The force of gravity is 1.2 N acting downward. The rocket engine has a force of 12.3 N acting at an angle of 65⁰ above the horizontal to the right. The wind pushes the rocket with a force of 2.5 N to the left. Find the magnitude and direction of the resultant force on the rocket.

Please answer!!! Offering 50 points for answer and explanation

Answers

Answer:

can you include a picture

Decompose the forces acting on the rocket in horizontal and vertical components.

• net horizontal force:

F = (12.3 N) cos(65°) - 2.5 N ≈ 2.7 N

(notice we're taking "to the right" to be the positive direction)

• net vertical force:

F = (12.3 N) sin(65°) - 1.2 N ≈ 9.9 N

The resultant force then has magnitude

√((2.7 N)² + (9.9 N)²) ≈ 10.3 N

Since the horizontal and vertical components of the resultant are both positive, it points at an angle between 0° and 90° from the positive horizontal, so that

tan(θ) ≈ (9.9 N) / (2.7 N) ≈ 3.69

===>   θ ≈ arctan(3.69) ≈ 75°

When a pitcher throws a baseball, it reaches a top speed of 39 m/s. If thebaseball takes 1.5 seconds to travel from the pitcher to the catcher, what isits acceleration? (Assume the ball is moving at 0 m/s right before it leavesthe pitcher's hand.)A. 23 m/s2B. 17 m/s2C. 11 m/s2D. 26 m/s2

Answers

Given,

The final velocity of the ball, v=39 m/s

The initial velocity of the ball, u=0 m/s

The time duration, t=1.5 s

The final velocity of an object upon which an accleration, a, acts for a duration of t seconds is given by one of the equations of motion as

\(v=u+at\)

By substituting the known values and simplifying the resulting equation we will get the acceleration of the ball.

Thus,

\(\begin{gathered} 39=0+a\times1.5 \\ \Rightarrow a=\frac{39}{1.5} \\ 26m/s^2 \end{gathered}\)

Thus the acceleration of the ball is 26 m/s²

Therefore the right answer is option 4.

A Student 330 m 990m from another tall flip between the the Student stands Sound Interval beteeen cliff is cliff from of 1 st and 630 tall Hip which speed of 330 if the 330 m/s 2nd eh what is echo?​

Answers

The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.

Let's break down the distances and calculate the time for each part of the journey:

Distance from the student to the first cliff: 330 meters

Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second

Distance from the first cliff to the second cliff: 990 meters

Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds

Distance from the second cliff back to the student: 990 meters

Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds

Now, we can calculate the total interval between the first and second echo by adding up the individual times:

Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds

Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.

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Note the complete questions is:

A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?

A horizontal force of 50 N is required to push a wagon across a sidewalk at a constant speed.

What is the net (unbalanced) force acting on the wagon?

What forces are acting on the wagon?

If the mass on the wagon increased, use Newton's law to explain what must change to get the object moving at constant speed.

Answers

The forces acting on the wagon are the applied horizontal force, gravitational force and the friction. To maintain a constant speed after the mass is changed, the acceleration must be reduced to move in a constant speed.

What is net force?

Force is an external agent acting on a body to change its motion or to deform it. There are various kind of forces such as friction, gravitational force, magnetic force etc.

The net force on an object is dependent on the magnitude and direction of all the forces acting on it. Here, the gravitational force will balance the applied horizontal force if the weight is greater.

The forces acting on the wagon are  applied horizontal force, gravitational force and the friction.  According to Newton's second law of motion, the force is the product of mass and acceleration.

If the mass is increased, the force applied must be balanced to make the acceleration unchanged with a constant velocity.

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PLEASE HELP WILL MARK BRAINLIEST!!
A 4.0-kg mass is moving to the right at 3.0 m/s. An 8.0 kg mass is moving to the left at 2.0 m/s. If after collision the two
masses join together, what is their velocity after collision?
O-0.33 m/s
O-0.20 m/s
O +1.4 m/s
O +2.3 m/s

Answers

Answer:

- 0.33 m/s

Explanation:

An illustration is shown above,

In this case, since the two objects move in opposite directions before collision, then move together, the formula to be used is,

m1u1 - m2u2 = (m1 + m2)v

Where,

m1 = mass of the first object

u1 = initial velocity of the first object

v1 = final velocity of the first object

m2 = mass of the second object

u2 = initial velocity of the second object

v2 = final velocity of the second object

Therefore,

(4.0 • 3.0) - (8.0 • 2.0) = (4.0 + 8.0)v

12 - 16 = 12v

-4 = 12v

Divide both sides by 12,

-4 / 12 = 12v / 12

-1 / 3 = v

v = -0.33 m/s

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Thanks

PLEASE HELP WILL MARK BRAINLIEST!! A 4.0-kg mass is moving to the right at 3.0 m/s. An 8.0 kg mass is

How long will it take to heat 0.71kg of water (c=4200J/kgK) from room temperature (20°C) to its boiling point if it were put in a 600W microwave

Answers

6.64 minutes to heat 0.71kg of water from 20°C to its boiling point using a 600W microwave.

To calculate the time it takes to heat the water, we can use the formula:

Q = mcΔT

where Q is the heat energy absorbed by the water, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

First, let's find the change in temperature:

ΔT = boiling point - room temperature = 100°C - 20°C = 80°C

Next, we can calculate the heat energy absorbed:

Q = mcΔT = (0.71kg)(4200J/kgK)(80°C) = 239,040J

Now, let's find the time it takes to supply this amount of energy using a 600W microwave:

Power (P) = Energy (Q) / Time (t)

t = Q / P = 239,040J / 600W = 398.4 seconds

Therefore, it will take approximately 398.4 seconds or 6.64 minutes to heat 0.71kg of water from room temperature to its boiling point using a 600W microwave.

It's worth noting that this calculation assumes all the microwave's power is effectively transferred to the water and that there are no heat losses during the process. In practice, factors like heat transfer efficiency and losses should be considered, which may slightly affect the actual heating time.

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HELP ASAP!
on the screenshot.

HELP ASAP!on the screenshot.

Answers

6-A
7-B
8-A
Hope this helps

This is for Lipor only.

This is for Lipor only.
This is for Lipor only.
This is for Lipor only.
This is for Lipor only.
This is for Lipor only.

Answers

Answer:

im here\

Explanation:

26. Which member of the carbon family is a non-metal?

Please help

Answers

Explanation:

Check out the Periodic Table attached here. The Carbon family is the vertical group starting with Carbon, Group 14. Nonmetals are in green, which element there is a nonmetal?

26. Which member of the carbon family is a non-metal?Please help

in a generator as the magnet spins opposite poles of the magnet push the electrons in opposite directions this back and forth movement of electrons is called

Answers

Answer: In a generator, the back and forth movement of electrons as the magnet spins and opposite poles of the magnet push the electrons in opposite directions is called Alternating Current (AC).

Explanation:

Answer:

alternating current and direct current

Explanation:

yall some of these questions arent that hard, use common sense

in a friendly game of handball, you hit the ball essentially at ground level and send it toward the wall with a speed of 16 m/s at an angle of 37 degree above the horizontal. (a) What amount of time is required for the ball to reach the wall if it is 3.3m away? (b) How high is the ball when it hits the wall?

Answers

A. The time required for the ball to reach the wall is 0.26 s

B. The height of the ball when it hits the wall is 2.17 m

How to determine the speed of the ball in the horizontal directionInitial velocity (u) = 16 m/sAngle of projection (θ) = 37 degreeSpeed in the horizontal direction (uₓ) =?

uₓ = uCosθ

uₓ = 16 × Cos37

Speed in horizontal direction = 12.78 m/s

A. How to determine the timeSpeed in horizontal direction (uₓ) = 12.78 m/sDistance (s) = 3.3 mTime (t) =?

s = uₓ × t

3.3 = 12.78 × t

Divide both sides by 12.78

t = 3.3 / 12.78

t = 0.26 s

B. How to determine the heightAcceleration due to gravity (g) = 9.8 m/s²Initial velocity (u) = 16 m/sAngle of projection (θ) = 37 degreeVertical velocity (vᵧ) = uSineθ = 16 × Sine 37 = 9.63 m/sHeight (H) = ?

H = vᵧt - 1/2gt²

H = (9.63 × 0.26) - (1/2 × 9.8 × 0.26²)

H = 2.17 m

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What’s SI units and SigFigs???

Answers

Answer:

Significant figures have a few rules about 0s and you should research but simply, for example say round 27.879 to 3 significant figures you round up until you have 3 numbers that aren't 0s so it would be 27.9.

SI units are the international system of units.

Answer:

SI units refer to the International System of Units. These are the standard units that measurements are typically given in. For example, the SI unit for time is seconds, meters for distance, kg for mass, etc.

Significant figures are the number of notable digits given for a measurement. For example, let's say you measured a piece of metal to be exactly 3.00 meters long. The value 3.00 has three significant figures, where as 3 only has one significant figure. Larger amounts of significant figures indicate a more precise measurement. In this case, by writing 3.00 instead of 3, you're telling me that you measured that piece of metal to be precisely 3.00 meters long.

How does methodology in natural science influence knowledge produced​

Answers

Methodology in natural science influences knowledge produced by the scientific method.

Two objects (42.0 and 21.0 kg) are connected by a massless string that passes over a massless, frictionless pulley. The pulley hangs from the ceiling. Find (a) the acceleration of the objects and (b) the tension in the string.

Two objects (42.0 and 21.0 kg) are connected by a massless string that passes over a massless, frictionless

Answers

Answer:

a = 3.27 m/s²

T = 275 N

Explanation:

Given that:

Mass m₁ = 42.p0 kg

Mass m₂ = 21.0 kg

Consider both masses to be in a whole system, then:

The acceleration can be determined as:

\((m_1+m_2)a = g(m_1-m_2)\)

Making acceleration the subject in the above formula;

\(a =\dfrac{g(m_1-m_2)}{(m_1+m_2)}\)

\(a =\dfrac{9.8(42.0-21.0)}{(42.0+21.0)}\)

\(a =\dfrac{9.8(21.0)}{(63.0)}\)

\(a =\dfrac{205.8}{(63.0)}\)

a = 3.27 m/s²

in the string, the tension is calculated using the formula:

\(T = \dfrac{2m_1m_2g}{(m_1+m_2)}\)

\(T = \dfrac{2(42)(21)(9.81)}{(42+21)}\)

\(T = \dfrac{17304.84}{63}\)

T = 274.68 N

T ≅ 275 N

The speed of light is 3×10^8 meters per second, which means that light can travel 300 million meters in just one second. How far can light travel in one minute?

Answers

Answer:

(1.8 × 10^9) meters in one minute

Explanation:

To determine how far light can travel in one minute, we need to multiply its speed by the number of seconds in a minute.

The speed of light is 3 × 10^8 meters per second.

There are 60 seconds in a minute.

Therefore, the distance light can travel in one minute is:

Distance = Speed × Time

Distance = (3 × 10^8 meters per second) × (60 seconds)

Calculating this, we get:

Distance = 3 × 10^8 meters/second × 60 seconds

Distance = 18 × 10^8 meters

Distance = 1.8 × 10^9 meters

So, light can travel approximately 1.8 billion (1.8 × 10^9) meters in one minute.

Explain the concept of an inverse squared relationship?

Answers

The concept of an inverse squared relationship explains the behavior of intensity of light and distance of the light source. As the distance of the light source increases, the intensity of light decreases.

What is concept of an inverse squared relationship?

The law of inverse square law says that intensity equals the inverse of the square of the distance from the source.

Mathematically, the formula for the inverse square law is given as;

I ∝ 1/r²

where;

I is the intensity of lightr is the distance from the light source

What is intensity of light?

The intensity of light can be defined as the measure of the amount of power emitted by a given surface or reflected by the surface.

Thus, the inverse square law is all about the inverse relation between the  intensity of light or power output of a given surface to the distance of the light source.

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Particles q1 = -53.0 uc, q2 = +105 uc, and q3 = -88.0 uc are in a line. Particles qı and q2 are separated by 0.50 m and particles q2 and q3 are separated by 0.95 m. What is the net force on particle q3?

Answers

The net force on particle q3 is 112.11 N

What is electrostatic force?

The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.

F = kq₁q₂/r²

where k = 9 x 10⁹ N.m²/C²

The Particles q1 = -53.0 uc, q2 = +105 uc, and q3 = -88.0 uc are in a line. Particles qı and q2 are separated by 0.50 m and particles q2 and q3 are separated by 0.95 m.

The net force F3 = F13 + F23

Substitute the values, we get the force F on q3 as

F3 = 9 x 10⁹x53.0 x 10⁻⁶x 88.0 x 10⁻⁶ / (0.5+0.95)² + 9 x 10⁹x105.0 x 10⁻⁶x 88.0 x 10⁻⁶ / (0.95)²

F3 = 112.11 N

Thus, the magnitude of the force on charge q3 is 112.11 N.

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7. Using the idea of Impulse, explain why a field goal kicker should 'kick through the ball', meaning extend their foot
as high up as possible at the end of the kick.

Answers

Answer:

Impulse is the amount of force put on an object in a certain amount of time. Therefore when kicking a ball and "kicking through it" it extends the period of time this force is applied in turn increasing its impulse. Impulse is equal to change in momentum. momentum is equal to mass times velocity and since mass of the ball doesn't change therefore the velocity is increased and performance increased.

a b) what is the Change of density due to a rise in temperature OF 500k. The Coefficient of linear expansion of the material is 12x10-6​

Answers

The coefficient of linear expansion of a metal rod is 12 * 10 ^ 1 - 6/100 The value in per ^O Fplease mark as brainliest


40 m north west
50m Northwest
120 m southeast
40 m south east

Which answer

40 m north west 50m Northwest 120 m southeast 40 m south eastWhich answer

Answers

Answer:

120 north west

Explanation:

100 POINTS PLS HELP ASAP


FIND THE AVERAGE SPEE FOR BOTH CARS !


Average time for car 1 is 3.01 sec the distance is 4 feet


Average time for car 2 is 2.99 sec the distance is 4feet

PLS HELP

Answers

Answer:

4/3 ft/s

Explanation:

(3.01+2.99)/2 = 3.00

(4 ft)/(3.00 s) = 4/3 ft/s

Refer to a long, straight wire carrying constant current I. What can be concluded about the magnitude of the magnetic field at distance a from the wire?

Answers

Answer:

"the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"

Explanation:

The magnitude of the magnetic field from a long straight wire (A approximately a finite length of wire at least for close points around the wire.) decreases with distance from the wire. It does not follow the inverse square rule as is the electric field from a point charge. We can then say that "the magnitude of the magnetic field at a point of distance a around a wire, carrying a constant current I, is inversely proportional to the distance a of the wire from that point"

From the Biot-Savart rule,

B = μI/2πR

where B is the magnitude of the magnetic field

I is the current through the wire

μ is the permeability of free space or vacuum

R is the distance between the point and the wire, in this case is = a

If a bus is traveling at 12m/s and a passenger on the bus is walking to the back of the bus at a velocity of 5m/s, what is the relative velocity of the passenger relative to the ground?​

Answers

The relative velocity is 17m/s.

The relative velocity of the passenger relative to the ground can be found by applying the concept of relative motion.

speed of bus (vb)=12m/s

speed of passenger inside the bus(vp)= 5m/s opposite to the speed of bus

speed of passenger relative to the ground = v

v= vb+vp

v= 12+(-5), since passenger is traveling in opposite direction

v=7m/

Therefore, the velocity of passenger relative to the ground is 7m/s.

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5. To push a box up an inclined plane, is the force required smaller if you push horizontally
or if you push parallel to the incline? Why?

Answers

To push a box up an inclined plane, the force required is smaller if you push parallel to the incline.

What is an Inclined plane?

This is also referred to as a ramp and is a flat surface which is tilted at an angle.

Pushing parallel to the plane doesn't generate friction which means a smaller amount of force will be required.

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What type of atomic radiation will most deeply penetrate matter?
Multiple Choice
Beta radiation
Gamma radiation
Alpha radiation

Answers

ANSWER IS gamma radiation

Gamma rays can be emitted from the nucleus of an atom during radioactive decay. They are able to travel tens of yards or more in air and can easily penetrate the human body. Shielding this very penetrating type of ionizing radiation requires thick, dense material such as several inches of lead or concrete.

The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?

Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.

Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!

Answers

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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3. A stuntman jumps off a building (into a safety mat). If he falls for 5 seconds, what
will his velocity be right before he hits the mat? (please include direction)
Givens (include all variables and units. Ex. vi=5m/s, d=60miles)

Answers

the answer is vi=47m/s, d=7miles

Which two options are forms of potential energy?
A. Chemical energy
B. Sound energy
c. Electrical energy
D. Thermal energy
E. Nuclear energy

Answers

The two options that are forms of potential energy are:

A. Chemical energy
E. Nuclear energy

Therefore, options A and E are the correct answers.
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