During catalytic hydrogenation, the alkene complexes to the metal catalyst and two H atoms are transferred to the ______ face(s) of the pi bond, resulting in ______ addition.

The atomic number is 4.

The atomic number of the given atom is equal to 4.

The atomic number (symbol Z) of a chemical element can be defined as the charge number of an atomic nucleus. For an ordinary atom, the atomic number is equal to the number of protons found in the nucleus of an atom of that element.

The atomic number helps to uniquely identify ordinary chemical elements. In an ordinary uncharged atom or neutral atom, the atomic number of that atom is also equal to the number of electrons.

For a neutral atom, the sum of the atomic number and the neutron number gives the atomic mass. The protons and neutrons have approximately the same mass. Atoms that have the same atomic number but different numbers of neutrons or different mass numbers are known as isotopes.

Given the number of electrons in the atom is 4. Therefore, the atomic number of that atom will be equal to 4.

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2,5 are the two phrases describing the synthesis of amino acids are accurate.

Alpha-ketoglutarate is transaminated in the human body to produce lysine, an important amino acid. The precursor is reduced during the amino acid alanine's synthesis, and oxidation occurs during alanine's breakdown.

The precursor is reduced during the amino acid alanine's synthesis, while oxidation occurs during alanine's breakdown. Metabolic pathway intermediates and alpha-keto acids are the carbon sources for the production of non-essential amino acids.

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Answer:  123×10−7m.

Explanation:

Answer:

What?

Explanation:

Answer:where are the statements

Explanation:

Approximately 6.63 grams of sulfide can be converted into zinc oxide using 2.64 L of oxygen gas measured at 21°C and 101 kPa.

The balanced equation is:2 ZnS(s) + 3 \(O_2\)(g) → 2 ZnO(s) + 2 S\(O_2\)(g)

The stoichiometric coefficient of ZnS is 2, while that of \(O_2\)is 3. So, the number of moles of \(O_2\)required to react with 1 mole of ZnS is given by (3/2) moles (i.e. 1.5 moles).

At STP (i.e. standard temperature and pressure), 1 mole of any gas occupies a volume of 22.4 L.

So, at 21°C and 101 kPa, the volume of 2.64 moles of oxygen gas is given by:

V = (n x R x T)/P= (2.64 x 8.31 x 294)/101= 62.7 L

Approximately 62.7 L of oxygen gas is needed to react completely with the sulfide and convert it into zinc oxide.

Therefore, to find the mass of sulfide that can be converted into zinc oxide using 2.64 L of oxygen gas measured at 21°C and 101 kPa, we first convert 2.64 L to moles of \(O_2\):

PV = nRTn = PV/RTn = (101 kPa)(2.64 L) / (8.31 L kPa/mol K)(294 K)= 0.102 moles of \(O_2\)

Since 3 moles of \(O_2\)re needed to react with 2 moles of ZnS, then the moles of ZnS required would be:

(2/3)(0.102 mol) = 0.068 mol ZnS.

To find the mass of ZnS, we use its molar mass:MM of ZnS = 97.47 g/molmass of ZnS

= (0.068 mol)(97.47 g/mol)mass of ZnS = 6.63 g

Hence, approximately 6.63 grams of sulfide can be converted into zinc oxide using 2.64 L of oxygen gas measured at 21°C and 101 kPa.

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Though not entirely accurate, 'A' is the best possible answer.

Water is considered the universal solvent.  Water is polar and has a partially positive and negative charge, it readily dissolves ions and polar molecules. When an ionic substance is added to water, individual ions interact with the polar regions of the water molecules during the dissociation process, disrupting their ionic bonds. The charges associated with these molecules form hydrogen bonds with water, surrounding the particle with water molecules. This is referred to as a sphere of hydration, or a hydration shell, and serves to keep the particles separated or dispersed in the water.

Several physical and chemical factors also influence disinfectant procedures: temperature, pH, relative humidity, and water hardness.

Sanitizers can usually function properly in temperatures between 75°F and 120°F. Some metal objects may corrode when exposed to chlorine compounds at higher temperatures. Higher temperatures may also cause chlorine and iodine chemicals to evaporate from the solutions.

Number of microbes: If the microbial load is large, a stronger concentration of disinfectant or a longer exposure period is required to reach a specific level of disinfection.

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These charts typically guide you through a series of questions based on the physical and chemical properties of the mineral, such as color, hardness, cleavage, and reaction to acid.

By answering each question, you can narrow down the possibilities and eventually identify the mineral. Another helpful tool is a handheld mineral identification kit, which includes common minerals and their properties for comparison to the unknown mineral. Observe the physical properties of the mineral, such as color, luster, hardness, cleavage, and fracture, using a magnifying glass or a microscope.

Test the mineral's hardness using a mineral hardness scale, such as Mohs scale, which ranks minerals based on their ability to scratch one another.Test the mineral's streak, which is the color of the powdered mineral, by rubbing the mineral against an unglazed porcelain plate.

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Answer:

C: was once buried underground

Explanation:

Hope this helps!

Answer:

The correct answer you are looking for is B i have got 100% on this test.

Explanation:

hop this helps! └(^o^)┘  ↖(^ω^)↗

Amount of heat lost by the hot water535.5 J,Amount of heat gained by the cold water -451.4 J ,Correction factor of the calorimeter 1406.4 J/deg C .

Water is a transparent, tasteless, odorless, and nearly colorless chemical substance, which is the main constituent of Earth's hydrosphere and the fluids of all known living organisms. It is vital for all known forms of life, even though it provides no calories or organic nutrients. Its chemical formula is H2O, meaning that each of its molecules contains one oxygen and two hydrogen atoms, connected by covalent bonds.

Heat lost by the hot water = mass × specific heat capacity × (initial temperature final temperature)= 50ml×4.2 J/g/deg C ×(64.3 ₋ 46.5)= 535.5 J

Heat gained by the cold water = mass ×specific heat capacity × (final temperature ₋ initial temperature)=Heat gained by cold water=50ml × 4.2 J/g/deg C × (22.2 - 34.0) = ₋451.4 J

Calorimeter Correction Factor = (Heat gained by cold water - Heat lost by hot water) / (final mixed temperature - initial mixed temperature)

= ( -451.4 ₋535.5 ) / (33.3₋34.0) = -986.9 / -0.7= 1406.4 J/deg C

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Answer:

Cinder cone-made of pieces of lava

caldera-bowl-shaped depression

volcanic soil-rich in nutrients

lava plateau-material fills in valleys

shield volcano-wide summit, gentle slope

Explanation:

Just did it

Answer: See image

Explanation: match the landform to its description

In a saturated solution of calcium phosphate with a solubility of 2.21 x 10^{-4} g/L, the molar concentration of the calcium ion (Ca^{+2}) is approximately 7.13 x \(10^{-7}\) M, and the molar concentration of the phosphate ion (PO_{4}^{-3}) is approximately 3.38 x 10^{-7} M.

To determine the molar concentrations of the calcium ion and the phosphate ion in the saturated solution of calcium phosphate, we need to use the given solubility and the molecular weight of calcium phosphate.

The solubility of calcium phosphate is given as 2.21 x10^{-4} g/L. We can convert this to moles per liter by dividing by the molar mass of calcium phosphate (310.18 g/mol):

2.21 x 10^{-4}g/L / 310.18 g/mol = 7.12 x 10^{-7} mol/L

Since calcium phosphate has a 1:1 ratio of calcium ions (\(Ca^{+2}\)) to phosphate ions (PO43-), the molar concentrations of both ions in the saturated solution will be the same. Therefore, the molar concentration of the calcium ion and the phosphate ion is approximately 7.13 x 10^{-7}M.

In conclusion, in a saturated solution of calcium phosphate with a solubility of 2.21 x 1\(10^{-4}\) g/L, the molar concentration of the calcium ion (Ca^{+2}) and the phosphate ion (\(PO_{4}^{-3}\)) is approximately 7.13 x10^{-7} M.

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The molecular formula of the given compound is CH₅N.

The ideal gas law has defined the product of the volume and pressure as equal to the product of the gas constant (R) and absolute temperature of the gas.

The mathematical equation of the ideal gas law is as follows:

PV = nRT

The temperature of the compound, T =  22° C = 295 K

The pressure of the compound, P = 99.5 KPa = 0.982 atm

The volume of the compound, V = 125 ml = 0.125 L

0.125 × 0.982 = (0.157 g/M) × 0.082 ×295

M = 31 g/mol

A number of moles of C = 0.157 ×0.37/12  = 0.00484

A number of moles of N = 0.157 ×0.45/14  = 0.00504

A number of moles of H = 0.157 ×0.16/1  = 0.0251

The simplest ratio of C: N: H is 1 : 1 : 5

The empirical formula of the given compound is CH₅N.

The molecular formula of the compound is CH₅N as the molecular mass is equal to 31 g/mol.

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The mass of each salt which will be added to the mixture is:

NaH₂PO₄ =  1.876 g

Na₂HPO₄ =  4.879 g

To make this buffer, phosphoric acid and/or its salts can also be combined in the following ways:

H₃PO₄ and Na₂HPO₄;

H₃PO₄ and Na₃HPO₄

The acid must be in the second ionisation if we are to have a buffer at 7.540, thus we would pick pKa2 = 7.198 for the buffer capacity.

7.540 = 7.198 + log[A⁻]/[HA]

log[A⁻]/[HA] = 0.342

[A⁻]/[HA] =

[A⁻]/[HA] = 2.198

[A⁻] = 2.198*[HA]

The concentration of the acid is conjugated to base and must be equal to the concentration of the buffer 0.0500 M, so:

[A⁻] + [HA] = 0.0500

2.198*[HA] + [HA] = 0.0500

3.198*[HA] = 0.0500

[HA] = 0.01563 M

[A⁻] = 0.0500 - 0.01563

[A⁻] = 0.03436 M

The mixed reaction is: NaH₂PO₄ + Na₂HPO₄ → HPO₄⁻² + 3Na + H₂PO₄⁻

The second ionization is:

H₂PO₄⁻ ⇄ HPO₄⁻² + H⁺

Because H₂PO₄⁻ is the acid form, its concentration is the same as NaH₂PO₄, and HPO₄⁻² is the conjugated base, and its concentration is the same as Na₂HPO₄ (stoichiometry is 1:1 for both).

If you want to prepare something for buffering, you must first have a solution of the species H2PO4 and HPO42, so that you can mix the mixture of:

H3PO4 and Na2HPO4 (the acid is tricrotic, forming H2PO4 as a result),

The dissociation of the salt Na2HPO4 into Na+ and HPO42);

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The concentration of the iodine at equilibrium from the calculation is 5.33 M

The equilibrium constant allows for the prediction of the direction in which a reaction will proceed to establish equilibrium when concentrations or pressures of reactants and products change.

We know that;

       H₂(g) +  \(I_{2}\)(g)     ⇄2HI(g)

I        4           m              0

C      -x          -x              +2x

E      4 - x      m - x         2

It the follows that;

2x = 2

x = 1

Then equilibrium concentration of hydrogen = 3 M

Thus we have that;

4 = 3 * [ \(I_{2}\)]/\(2^2\)

16 = 3 * [ \(I_{2}\)]

[ \(I_{2}\)] = 5.33 M

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The average kinetic energy of a gas is given by the formula: KEavg = (3/2) kT. Average kinetic energy for fluorine, chlorine and bromine are found as \(6.56 × 10^-21 J, 6.56 × 10^-21 J and 6.56 × 10^-21 J\) respectively.

Where KEavg is the average kinetic energy of the gas, k is the Boltzmann constant (\(1.38 × 10^-23 J/K\)), and T is the temperature in Kelvin.

For F2:

\(KEavg = (3/2) kTKEavg = (3/2) (1.38 × 10^-23 J/K) (310 K)KEavg = 6.56 × 10^-21 J\)

For Cl2:

\(KEavg = (3/2) kTKEavg = (3/2) (1.38 × 10^-23 J/K) (310 K)KEavg = 6.56 × 10^-21 J\)

For Br2:

\(KEavg = (3/2) kTKEavg = (3/2) (1.38 × 10^-23 J/K) (310 K)KEavg = 6.56 × 10^-21 J\)

It is worth noting that the average kinetic energy of a gas is directly proportional to its temperature. As the temperature increases, the average kinetic energy of the gas increases.

This is because as the temperature increases, the molecules move faster and collide more frequently, resulting in an increase in kinetic energy.

Additionally, the formula assumes that the gas molecules are ideal, meaning that they have no intermolecular forces and occupy no volume. In reality, gas molecules do have intermolecular forces and occupy some volume, but these assumptions are valid for most gases under normal conditions.

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When pieces of two ionic compounds switch places to create two new compounds, it is called a double replacement reaction also known as a double displacement, exchange, or metathesis reaction

One in which one reactant is only partially replaced by another is referred to as a twofold displacement reaction.

A list of double reactions is provided below:

AB = CD + CB + CD + AD

A twofold replacement process involves exchanging the same ions from two reactant ionic bonds for two new product compounds.

Two reactants transfer cations or anions to create two new products in a double replacement reaction.

Metathesis reactions double and displacement reactions are additional names for dual replace procedures.

Double replacement reactions include, but are not limited to, precipitation, gas production, and neutralization.

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The word that best fits the definition of "people who do not work for a formal business" is informal sector.

A formal definition can be defined as a process which typically involves providing all of the information (details) pertaining to a particular word or phrase, especially in a concise and standard format.

An informal sector can be defined as a word which is used to describe a group of workers that do not work for a formal business (regulated economic activities), including entrepreneurs, self-employed persons, and small family businesses.

In conclusion, some examples of persons working in the informal sector are car repairs, graphic designers, home renovations, etc.

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The things classified as energy can not be classified as matter based on the description of both.

From these definitions, it is clear that the things classified as energy can not also be classified as matter. Energy is just a property or a concept.

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The non-contact forces portfolio includes Gravitational force, Magnetic force and Electrostatic force.

Non contact forces are those forces which are applied on any object without any physical interference or contact.

Some non-contact forces are:

Hence Gravitational force, Magnetic force and Electrostatic force are the non-contact forces.

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Answer:

Glucose will enter the cell through osmosis.

Explanation:

Diffusion causes molecules to move from high concentration to low concentration, so the glucose molecules outside the cell will move through the membrane to inside of the cell.

There are 0.666 moles present in 120 g of glucose that consists of Carbon, Hydrogen, and Oxygen atoms.

The molar mass of glucose can be calculated by adding up the atomic masses of all the atoms in its chemical formula.

Carbon =  6 atoms × atomic mass of carbon = 6 × 12.01 g/mol

Hydrogen =  12 atoms × atomic mass of hydrogen = 12 × 1.01 g/mol

Oxygen = 6 atoms × atomic mass of oxygen = 6 × 16.00 g/mol

Molar mass of glucose = (6 × 12.01) + (12 × 1.01) + (6 × 16.00) g/mol

Molar mass of glucose = 72.06 + 12.12 + 96.00 g/mol

Molar mass of glucose = 180.18 g/mol

The total number of moles in glucose is:

Number of moles = Mass of substance / Molar mass

Number of moles = 120 g / 180.18 g/mol

Number of moles = 0.666 moles

Therefore, we can conclude that there are 0.666 moles present in  120 g of glucose.

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Answer:

Chemical bonds hold molecules together and create temporary connections that are essential to life.

Explanation:

Chemical Bonding refers to the formation of a chemical bond between two or more atoms, molecules, or ions to give rise to a chemical compound. These chemical bonds are what keep the atoms together in the resulting compound.

Answer:

Chemical bonds hold molecules together and create temporary connections that are essential to life.

Explanation :

A chemical bond is a lasting attraction between atoms, ions or molecules that enables the formation of chemical compounds. The bond may result from the electrostatic force between oppositely charged ions as in ionic bonds or through the sharing of electrons as in covalent bonds.

There are approximately 0.4495 moles of methane in a 7.21 gram sample. To calculate the number of moles of methane in a given sample, you need to divide the mass of the sample by the molar mass of methane.

The molar mass of methane (CH4) can be calculated by summing up the atomic masses of its constituent elements:

Molar mass of C (carbon) = 12.01 g/mol

Molar mass of H (hydrogen) = 1.008 g/mol

Molar mass of methane (CH4) = (1 × Molar mass of C) + (4 × Molar mass of H)

= (1 × 12.01 g/mol) + (4 × 1.008 g/mol)

= 16.04 g/mol

Now, we can calculate the number of moles of methane using the following formula:

Number of moles = Mass of sample / Molar mass

Plugging in the values:

Number of moles = 7.21 g / 16.04 g/mol

≈ 0.4495 mol (rounded to four decimal places)

Therefore, there are approximately 0.4495 moles of methane in a 7.21 gram sample.

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Answer:

4 sun , planet, moon are the components in the correct order

Answer:

A) Shaken is the correct answer

Explanation:

The other three don't fit in with the solution if you think about it. When you shake something with lemonade crystals (Like a lemonade flavor packet in poured in a water bottle) it dissolves faster when you shake it rather than it sit on the bottom for 15 minutes! :) .

Hope this helps! :)

Answer:

The Person above me is correct

Explanation:

I got it right first try 100%

The difference between the saturation envelope of the following mixtures is Methane and ethane, where methane is 90% and ethane is 10%. Methane and pentane, where methane is 50% and pentane is 50%.

In a saturation envelope of two-component systems, the bubble point temperature, and the dew point temperature is crucial. In mixtures of methane and ethane, where methane is 90%, and ethane is 10% the saturation envelope can be calculated by considering the bubble and dew point of both components, as the final saturation envelope will be a combination of both components.

When the bubble point and dew point of each component is calculated, the saturation envelope can be plotted, as shown below: Figure 1: Saturation envelope for methane and ethane (90:10). As shown above, the saturation envelope for methane and ethane (90:10) is a combination of both components, where the dew point and bubble point of methane is at a lower temperature compared to ethane, as methane is the majority component, and it will have more significant effects on the final saturation envelope.

For mixtures of methane and pentane, where methane is 50%, and pentane is 50%, the saturation envelope is shown below: Figure 2: Saturation envelope for methane and pentane (50:50).As shown above, the saturation envelope for methane and pentane (50:50) is a combination of both components, where the dew point and bubble point of both components are very close, due to the balanced composition of the mixture. In summary, the saturation envelope for a mixture of methane and ethane (90:10) will have a lower dew point and bubble point compared to a mixture of methane and pentane (50:50).

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