During the regular season, a National Basketball Association team plays 82 games and a National Football League team plays 16 games. In simplest form, what is the ratio of NFL regular season games to NBA regular season games?

Answer:

Definition of perpendicular lines

Step-by-step explanation:

Answer:

I believe it would be 1400

Step-by-step explanation:

If it is multiple choice this would probably be the best choice

(a) The probability that a point chosen randomly inside the rectangle is in the square is 0.6.

(b) The probability that a point chosen randomly inside the rectangle is outside the square is 0.4.

The probability that a point chosen randomly inside the rectangle is in each given shape is calculated as follows;

The area of the triangle is calculated as follows;

area = ¹/₂ x base x height

area = ¹/₂ x 4 x 5

area = 10 sq.units

The area of the rectangle is calculated as follows;

area = 4 x 4

area = 16 sq.units

The probability that a point chosen randomly inside the rectangle is in the square is calculated as;

P = outcome / total possible outcome

P = ( 10 ) / 16

P = 0.625 ≈ 0.6

The probability that a point chosen randomly inside the rectangle is outside the square;

P = 1 - p(inside)

P = 1 - 0.6

P = 0.4

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Answer:

The probability that less than 3 road construction projects are currently taking place in this city is 0.06197

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

\(P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}\)

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\(\mu\) is the mean in the given interval.

Poisson distribution with a mean of 6.

This means that \(\mu = 6\)

Find the probability that less than 3 road construction projects are currently taking place in this city.

This is:

\(P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)\)

So

\(P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}\)

\(P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.00248\)

\(P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487\)

\(P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462\)

\(P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.00248 + 0.01487 + 0.04462 = 0.06197\)

The probability that less than 3 road construction projects are currently taking place in this city is 0.06197

For given function function f(x)=-x+3-2, the domain is x > -3 and the range is y ≤ 2. So, correct option is D.

The function f(x)=-x+3-2 is a linear function in the form y=mx+b, where m is the slope and b is the y-intercept. In this case, the slope is -1 and the y-intercept is 1. Therefore, the graph of the function is a straight line that intersects the y-axis at (0,1) and has a slope of -1, meaning that it decreases by 1 for every 1 unit increase in x.

The domain of the function is the set of all possible values of x for which the function is defined. Since there are no restrictions on the value of x in the equation f(x)=-x+3-2, the domain is all real numbers, or (-∞, ∞).

The range of the function is the set of all possible values of y that the function can output. In this case, the lowest possible value of y occurs when x approaches positive infinity, and the highest possible value of y occurs when x approaches negative infinity. Therefore, the range is all real numbers less than or equal to 2, or y ≤ 2.

So, the domain is x ∈ (-∞, ∞) and the range is y ≤ 2. Alternatively, the domain can also be expressed as x > -3, since that is the minimum value of x at which the function is defined.

Correct option is D.

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Complete question is:

What are the domain and range of the function f(x)=-x+3-2?

A) domain: -3 -2

B) domain: -3 -3 range: y<-2

C) domain: x>-3 range:y>-2

D) domain : x>-3 range: y ≤ 2

Answer: 16

Step-by-step explanation:

Find the mean absolute deviation of the data:

X : 92, 88, 90, 96, 84

Find the mean(m) of the data:

m = Σ(X) / n

n = number of samples

(92 + 88 + 90 + 96 + 84) / 5

m = 450 / 5

m = 90

Absolute Deviation of each value of the mean:

|x - m| :

|92 - 90| = 2

|88 - 90| = 2

|90 - 90| = 0

|96 - 90| = 6

|84 - 90| = 6

Σ|x - m| = 2 + 2 + 0 + 6 + 6 = 16

Answer:

3.2

Step-by-step explanation:

Answer:

11:10

Step-by-step explanation:

1h15m + 40m + 25m + 30m = 2h50m

She'd need to start 2h50m before 2:00, which would be 11:10 I think

Answer:

(−∞,∞)

Step-by-step explanation:

Since |x−5| is always positive and −2 is negative, |x−5| is always greater than −2, so the inequality is always true.

All real numbers

So, the answer is (−∞,∞)

Answer:

there’s no image

Step-by-step explanation:

Answer:

The p-value of the test is of 0.0045 < 0.05, which means that there is enough evidence to reject the null hypothesis and accept the alternate hypothesis that the mean net weight is less than advertised.

Step-by-step explanation:

Bags of a certain brand of tortilla chips claim to have a net weight of 14 ounces. A representative of a consumer advocacy group wishes to see if there is any evidence that the mean net weight is less than advertised.

At the null hypothesis, we test that the mean is of 14, that is:

\(H_0: \mu = 14\)

At the alternate hypothesis, we test tha tthe mean is less than advertised, that is, less than 14. So:

\(H_a: \mu < 14\)

The test statistic is:

\(t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}\)

In which X is the sample mean, \(\mu\) is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

14 is tested at the null hypothesis:

This means that \(\mu = 14\)

For this, the representative randomly selects 16 bags of this brand and determines the net weight of each. He finds the sample mean to be 13.82 and the sample standard deviation to be 0.24.

This means that \(n = 16, X = 13.82, s = 0.24\)

Test statistic:

\(t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}\)

\(t = \frac{13.82 - 14}{\frac{0.24}{\sqrt{16}}}\)

\(t = -3\)

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean below 13.82, which is the p-value of t = -3, using a left-tailed test with 16 - 1 = 15 degrees of freedom.

With the help of a calculator, the p-value is of 0.0045.

The p-value of the test is of 0.0045 < 0.05, which means that there is enough evidence to reject the null hypothesis and accept the alternate hypothesis that the mean net weight is less than advertised.

We cannot make a general assumption about whether the mean is greater or less than 3.5 based solely on the fact that the median is 3.5.

The mean is a measure of central tendency that represents the average value of a set of numbers. It is also called the arithmetic mean or simply the average.

We cannot make a general assumption about whether the mean is greater or less than 3.5 based solely on the fact that the median is 3.5.

The mean and the median are two different measures of central tendency, and they can have different values depending on the distribution of the data. In general, if a data set is symmetric and bell-shaped, the mean and the median are close to each other. However, if the data set is skewed, the mean and the median may be different.

For example, consider the following two data sets:

Set 1 data: 1, 2, 3, 4, and 5.

The median is 3.

The mean is (1 + 2 + 3 + 4 + 5) / 5 = 15 / 5 = 3.

Data set 2: 1, 2, 3, 4, 10

The median is 3.

The mean is (1 + 2 + 3 + 4 + 10) / 5 = 20 / 5 = 4.

In data set 1, the mean is the same as the median. In data set 2, the mean is greater than the median because the value 10 is an outlier that pulls the mean up.

Therefore, without additional information about the distribution of the data, we cannot make a general assumption about whether the mean is greater or less than 3.5 based solely on the fact that the median is 3.5.

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Answer:

a. \(z_{1} = \frac{3\sqrt{2}}{2}+j\cdot 3\frac{\sqrt{2}}{2}\), b. \(z_{3} = -j\cdot 2\), c. \(z_{4} = -j\), d. \(z_{5} = 1\)

Step-by-step explanation:

All given complex numbers are in polar form, which are characterized by:

\(z = r\cdot e^{j\cdot \theta}\)

Where:

\(r\) - Magnitude, dimensionless.

\(\theta\) - Direction, measured in radians.

The rectangular form of complex numbers is represented by:

\(z = r\cdot (\cos \theta + j\cdot \sin \theta)\)

Now, each complex number is evaluated:

a. \(z_{1} = 3\cdot e^{j\cdot \frac{ \pi}{4} }\)

\(r = 3\) and \(\theta = \frac{\pi}{4}\)

\(z_{1} = 3\cdot \left(\cos \frac{\pi}{4}+j\cdot \sin \frac{\pi}{4} \right)\)

\(z_{1} = \frac{3\sqrt{2}}{2}+j\cdot 3\frac{\sqrt{2}}{2}\)

b. \(z_{3} = 2\cdot e^{-j\cdot \frac{\pi}{2} }\)

\(r = 2\) and \(\theta = -\frac{\pi}{2}\)

\(z_{3} = 2\cdot \left[\cos \left(-\frac{\pi}{2}\right) + j\cdot \sin \left(-\frac{\pi}{2} \right) \right]\)

\(z_{3} = -j\cdot 2\)

c. \(z_{4} = j^{3}\)

By definition of complex number, \(j = \sqrt{-1}\), which means that \(j^{2} = -1\). Hence:

\(z_{4} = j^{2+1}\)

\(z_{4} = j^{2}\cdot j\)

\(z_{4} = j\cdot j^{2}\)

\(z_{4} = -j\)

d. \(z_{5} = j^{-4}\)

By definition of complex number, \(j = \sqrt{-1}\), which means that \(j^{2} = -1\).

Hence:

\(z_{5} = \frac{1}{j^{4}}\)

\(z_{5} = \frac{1}{j^{2+2}}\)

\(z_{5} = \frac{1}{j^{2}\cdot j^{2}}\)

\(z_{5} = \frac{1}{(-1)\cdot (-1)}\)

\(z_{5} = 1\)

Answer:

Large box = 50 pounds

Small box = 15 pounds

Step-by-step explanation:

Because there are 50 small boxes, the truck is carrying 50 combined large and small boxes. That means the area of those boxes are 50 * 65 = 3250 pounds. There are 10 large boxes left. 3750-3250 = 500. The weight of 10 large boxes is 500 pounds, which means 1 large box is 500/10 which is 50 pounds.

If a large box is 50 pounds, and the combined weight is 65 pounds, 65-50 = 15 pounds for a small box.

The two equations that have the same solution as 2.3p – 10.1 = 6.5p – 4 – 0.01p include the following:

B. 2.3p – 10.1 = 6.49p – 4

C. 230p – 1010 = 650p – 400 – p

From the information provided, we have the following equation:

2.3p – 10.1 = 6.5p – 4 – 0.01p

Next, we would simplify the given equation by collecting like terms as follows;

2.3p - 10.1 = 6.5p - 0.01p - 4 = 6.49p - 4

2.3p - 10.1 = 6.49p - 4

In Mathematics, the multiplication property of equality states that both sides of an equation will remain the same and equal, when both sides of the equations are multiplied by the same number.

By multiplying both sides of the given equation by 100, we have;

100 × (2.3p - 10.1) = 100 × (6.5p - 4 - 0.01p)

230p - 1010 = 650p - 400 - p

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When Seema used compatible numbers to estimate the product of (–25.31)(9.61), her estimate is A. -250.

From the information, it should be noted that Seema used compatible numbers to estimate the product of (–25.31)(9.61).

It should be noted that -25.31 when rounded will be -25.

It should be noted that 9.61 when rounded will be 10.

Therefore, the multiplication will be:

= -25 × 10

= -250.

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Seema used compatible numbers to estimate the product of (–25.31)(9.61). What was her estimate?

-250

-240

240

250

The value of side length x in diagram a) is 4.3mm and side length x in diagram b) is 309.7 m.

The figures in the image are right triangles.

A)

angle D = 17 degree

Adjacent to angle D = 14 mm

Opposite to angle D = x

To solve for the missing side length x, we use the trigonometric ratio.

Note that: tangent = opposite / adjacent

Hence:

tan( 17 ) = x/14

x = tan( 17 ) × 14

x = 4.3mm

B)

angle Z = 82 degree

Adjacent to angle Z = 43.1 m

Hypotenuse = x

Using trigonometric ratio,

cosine = adjacent / hypotenuse

cos( 82 ) = 43.1 / x

x = 43.1 / cos( 82 )

x = 309.7 m

Therefore, the measure of x is 309.7 meters.

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The possible rational zeros of the given polynomial are given by: p/q = ±1, ±2, ±3, ±6

What is a polynomial ?

Polynomial can be defined as expression in which combination of variables and coefficients

A rational zero of a polynomial is a rational number that, when plugged into the polynomial, results in zero. To find all possible rational zeros of a polynomial, we can use the Rational Root Theorem.

According to the Rational Root Theorem, if a rational number "p/q" is a zero of a polynomial, where p and q are integers and q ≠ 0, then p must be a factor of the constant term (in this case, 6) and q must be a factor of the leading coefficient (in this case, 2).

So, the possible rational zeros of the given polynomial are given by:

p/q = ±1, ±2, ±3, ±6

We can then test each of these values to see if they are actually zeros of the polynomial. To do this, we simply plug in the value and simplify. If the result is zero, then the number is indeed a zero of the polynomial.

For example, plugging in p/q = -1, we get:

2(-1)^5 + 4(-1)^4 - 3(-1)^2 + (-1) - 6 = 2 - 4 - 3 + 1 - 6 = -14,

which is not equal to zero, so -1 is not a zero of the polynomial.

By testing each of the possible rational zeros in a similar way, we can determine which ones are actually zeros of the polynomial.

Therefore,  The possible rational zeros of the given polynomial are given by: p/q = ±1, ±2, ±3, ±6

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The possible values for angles 1, 2, and 3 given that lines a and b are parallel lines include the following:

In Mathematics and Geometry, parallel lines are two (2) lines that are always the same (equal) distance apart and never meet or intersect.

Note: Assuming angle 1 is equal to 60 degrees.

In Mathematics and Geometry, the vertical angles theorem states that two (2) opposite vertical angles that are formed whenever two (2) lines intersect each other are always congruent, which simply means being equal to each other:

m∠1 ≅ m∠3 = 60°.

Based on the linear pair postulate, the measure of angle 2 can be determined as follows;

m∠1 + m∠2 = 180°

60° + m∠2 = 180°

m∠2 = 180° - 60°

m∠2 = 120°

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Answer:

Pretty sure its 7 and 8

Step-by-step explanation:

test it out

Answer:

7<sqaure root of 56<8

Step-by-step explanation:

khan

Based on the annuity payment that Marie will make and the number of years, the nt value that she will use in her formula is 360 months.

The nt value is the number of periods that Marie will need to pay her annuity payment. This value can be yearly, monthly, weekly and even daily.

As the mortgage compounds monthly in this instance, the nt value will need to be monthly as well.

To find the nt value, the formula is:
= Number of years x number of compounding periods per year

= 30 x 12 times a year

= 360 months

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Answer:

360

Step-by-step explanation:

i did that and i got it right

Yes, there is statistical evidence that the drug is effective in reducing infarct size because p-value is less than the significance value.

Let us first define the hypotheses;

Null Hypothesis; H₀: µ = 25

Alternative Hypothesis; H₁: µ < 25

Standard Deviation; σ = 10

Sample mean; x' = 16

Sample size; n = 8

z-score is;

z = (16 - 25)/(10/√8)

z = -2.55

From online z-score table, the p-value is 0.005

Since p-value is less than the significance value, then we reject the null hypothesis and conclude that the drug is effective in reducing infarct size.

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Answer:

why won't Ralph show 13/20 then?

Answer:

-90%

Step-by-step explanation:

The scale factor for dilation is 3/4. Therefore, the dilation can be represented below

This means Julie is correct.

Answer:

You can make a table that starts with the cost for one person then add below the cost for 2,3,4 etc

Step-by-step explanation:

Answer:

Option C

Step-by-step explanation:

have a great Day

Answer:

D 0.89275

Step-by-step explanation:

Answer:

Step-by-step explanation:

x - first

x + 12 - second

x + (x + 12) = 44

2x=44-12

x=16

first number is 16

second number is 16+12=28

two numbers are 16 and 28

16 and 28 are the required two numbers when one number exceeds another by 12 and their sum is 44

One number exceeds another by 12 and their sum is 44

We need to find the two numbers

Two expressions with equal sign is called equation.

Let x be the first number

x + 12 be the  second number

x + (x + 12) = 44

2x=44-12

x=16

Therefore first number is 16

second number is 16+12=28

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Answer:

\((x^2+y^2+xy)(x^2+y^2-xy)\)

Step-by-step explanation:

Rewrite the middle term.

\(x^4+2x^2y^2-x^2y^2+y^4\)

Rerrange terms.

\(x^4+2x^2y^2+y^4-x^2y^2\)

Factor first three terms by perfect square rule.

\((x^2+y^2)^2-x^2y^2\)

Rewrite \(x^2y^2\) as \((xy)^2\).

\((x^2+y^2)^2-(xy)^2\)

Since both terms are perfect squares, factor using the difference of squares formula, \(a^2-b^2=(a+b)(a-b)\) where \(a=x^2+y^2\) and \(b=xy\).

\((x^2+y^2+xy)(x^2+y^2-(xy))\)

Remove parentheses.

\((x^2+y^2+xy)(x^2+y^2-xy)\)