During the Vector Addition lab, Mac and Tosh start at the classroom door and walk 35. 0 m, north, 65. 0 m east, 54. 5 m south, 30. 5 m west, and 4. 5 m, north. Determine the magnitude and direction of the resultant displacement of Mac and Tosh

Answers

Answer 1

The magnitude of the resultant displacement of Mac and Tosh is 107.0 m, and the direction is northeast (45°).

What is displacement?

Displacement is a vector quantity that describes the change in position of an object over time. It is the difference between the initial and final positions of an object, measured in a given direction. Displacement is a measure of the distance moved, regardless of the direction in which the object is traveling. In physics, displacement is a fundamental concept used to describe the motion of particles and objects. It is used to calculate the change in position of an object over a certain period of time and is used to describe the motion of objects in one-dimensional motion. It is also used to calculate the velocity and acceleration of an object.

North-South component = 35.0 m - 54.5 m = -19.5 m
East-West component = 65.0 m - 30.5 m = 34.5 m
Next, we use the Pythagorean theorem to calculate the magnitude of the resultant displacement:
Magnitude = √(-19.5 m)² + (34.5 m)² = √758.25 m = 107.0 m
Finally, we calculate the direction of the displacement from the ratio of the North-South component to the East-West component:
Direction = tan-1(-19.5 m/34.5 m) = -45°
Therefore, the magnitude of the resultant displacement of Mac and Tosh is 107.0 m, and the direction is northeast (45°).


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Related Questions

With modulus of elasticity, MoE - 7,920 N/mm2 at 12% mo, what would be the expected MoE at 23% mc? Assume FSP = 30 % Give your answer in N/mm² to the nearest whole number.

Answers

to find the modulus of elasticity MoE at 23% of moisture content based on the already given modulus of elasticity of 12% moisture content we need to consider a shrinkage behavior of material. the expected MoE comes out to be approximately \(6,836 N/mm².\)

given information:

Modulus of elasticity at 12% moisture content =7,920 N/mm²

resultant shrinkage or final shrinkage percentage FSP = 30%

To calculate the expected MoE at 23% moisture content we have the following equation:

MoE-23% =   \(MoE-12%\) \((1 - FSP (23 - 12) / (100 - 12))\)

MoE-23% = \(7,920 N/mm² × (1 - 0.30 × (23 - 12) / (100 - 12))\)

MoE-23% =\(7,920 N/mm² × (1 - 0.30 × 11 / 88)\)

MoE-23% = \(7,920 N/mm² × (1 - 0.1364)\)

MoE-23% = \(7,920 N/mm² × 0.8636\)

MoE-23% =  \(6,836 N/mm²\)

therefore the expected modulus of elasticity at 23% moisture content comes out to be approx \(6,836 N/mm²\).

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1. Hearing is also known as
?

Answers

I’m not sure what your quite asking for, but some people say auditory perception instead of hearing

a man weighs 600 n while on the surface of earth. if he is transported to the planet mythos, which has the same mass as earth but a radius that is five times larger than earth's, his weight would be group of answer choices

Answers

Human body weight is equal to 600 N. Gravitational acceleration on earth: g = 10 m s 2 Man's weight on Earth is 600 kg. 10 sq . ft = 60 kg Since mass is consistent everywhere, we are aware of this.

What does gravity mean?

The attraction of items by the earth is known as gravitation. The earth's gravity causes objects that are hurled upward to reach a specific height before falling to the ground. 2. Space objects may be drawn to one another by gravity. the attraction force between the sun and the other planets.

Gravitational interaction: What is it?

The weakest of the four basic forces of nature, attraction between physical things having mass or energy is a natural phenomena. also known as gravity. the process or act of moving while being drawn to something. check out gravitational interaction. a movement in the direction of a source of desire: the middle classes' attraction.

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3. A solar panel has an area of
1.25 m² and an efficiency of
21.0 percent. Find its output
to power if the insolation is
650 W/m².

Answers

Output power of the solar panel is 170.6 W.

What is solar panel?

Solar panels are those tools that take the sun's rays and turn them into heat or power.

An array of solar (or photovoltaic) cells make up a solar panel, which can be used to produce power thanks to the photovoltaic effect. On the surface of solar panels, these cells are organized in a grid-like configuration.

Given parameters:

Area of the solar panel: A = 1.25 m²

Efficiency of the solar panel; η = 21.0%

The insolation of it = 650 W/m².

Hence, input power of the solar panel: I =  insolation × area

= 650 × 1.25 W

= 812.5 W.

Output power of the solar panel: O = efficiency × input power

= 21.0% ×821.5 W

= 170.6 W.

Hence, its output power is 170.6 W.

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Which of the following changes would result in a clockwise emf in the loop? When you consider each option, assume that no other changes occur.
Check all that apply.
a) The magnitude of B increases.
b) The magnitude of B decreases.
c) The loop rotates through 45 degrees about the vertical axis (vertical dotted line) shown in the diagram.
d) The loop rotates through 45 degrees about the horizontal axis (horizontal dotted line) shown in the diagram.
e) The loop moves to the right while remaining in the plane of the page.
f) The loop moves toward you, out of the page, while remaining parallel to itself.

Answers

The conditions which would result in clockwise emf in loop are

a) The magnitude of B increases

c)The loop Rotates through 45 degrees about vertical axis

This all happens according to the right-hand thumb rule of electromagnetics. The EMF (Electro Motive Force) changes according to the movement of Loop as it is dependent on the motion which further connects to the right hand thumb rule as shown in the figure attached.

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Which of the following changes would result in a clockwise emf in the loop? When you consider each option,

Question 50 Marks: 1 The amount of heat required to lower one pound of a product one degree Fahrenheit isChoose one answer. a. exothermal extraction b. the specific heat c. the coolant factor d. important to know

Answers

The correct answer is Specific heat.

The amount of energy required to raise the temperature of one pound of water by one degree Fahrenheit at standard atmospheric pressure is called specific heat in BTU (British Thermal Unit) which is a unit of measurement for energy used as per the British system.

BTU is used for measuring the heating or cooling capacity of an appliance as per the FPS system. For example, the BTU rating of a furnace or air conditioner indicates how much heat or cooling it can produce in a given period of time.

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A helicopter flies over the arctic ice pack at a constant altitude, towing an airborne 130-kg laser sensor that measures the thickness of the ice (see the drawing). The helicopter and the sensor both move only in the horizontal direction and have a horizontal acceleration of magnitude 2.57 m/s2. Ignoring air resistance, find the tension in the cable towing the sensor.

Answers

Answer:T=1316.21 N

Explanation:

The tension has two components: Vertical and Horizontal. The

horizontal component is ma, the vertical component is mg. Using

Pythagoras theorem, we can find the tension as:

T=((ma)^2 (mg)^2)^(1/2)

So

T=((129*2.84)^2 (129*9.8)^2)^(1/2)

T=1316.21 N

A truck has a momentum of 5,000 units. What happens to the truck's momentum if the mass is cut in half?

Answers

If the truck is moving with the same velocity, if the mass is cut in half then the momentum of the truck will also reduce to half.

What is momentum?

The momentum of a body can be described as the function of the object's mass and velocity. Momentum (p) can be determined as kinetic energy and is the product of velocity (v) and mass (m).

The momentum of an object can be determined from the mathematical formula:

p = m×v

The momentum of an object is conserved and can be equal to zero if the object is stationary and its velocity of an object is zero.

Given, the truck has a momentum, p = 5000 units

Given that the mass of the truck is reduced to half. Then the new mass of the truck is equal m/2.  If the truck is still moving with the same velocity then the momentum is equal to:

p' = m' ×v

p' = (m/2) ×v

p' = mv/2

p' = p/2

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To prepare homemade ice cream, a crank must be turned with a torque of 3.95N*m. How much work is required for each complete turn of the crank?

Answers

To determine the work required for each complete turn of the crank when preparing homemade ice cream with a torque of 3.95 N*m, you can follow these steps:

1. Identify the given values: torque (τ) = 3.95 N*m.
2. Remember that work (W) is calculated by multiplying the torque (τ) by the angle in radians (θ): W = τ * θ.
3. Since we want the work required for each complete turn of the crank, the angle (θ) should be in radians for a full rotation, which is 2π radians.
4. Plug the values into the equation: W = 3.95 N*m * 2π radians.

Your answer: To prepare homemade ice cream, if a crank must be turned with a torque of 3.95 N*m, the work required for each complete turn of the crank is approximately 24.83 J (joules).

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Which type of force is the weakest?

A. Van der Waals forces
B. Hydrogen bonds
C. Metallic bonds
D. lonic bonds

Answers

Answer:

D

Explanation:

I think those are weakest

Answer:

D. ionic bonds

Explanation:

ionic bonds are the weakest as its between ions

hydrogen bonds are stronger as it is electrostatic force so its strong

metallic bonds are the sharing of many detached electrons between many positive ions they call it a glue because they are hardly breakable

What is the characteristic that allows an object to have kinetic energy?

Answers

kinetic energy is movement, thus movement would be a characteristic that allows an object to have kinetic energy

what would you do to increase resistance

Answers

Answer:

If this is electrical currents , make the wire longer, smaller diameter wires, heat it up

Yes...... ........... because it’s reusable

Describe how you could show that the Earth has a magnetic field.​

Answers

Answer:

Earth's magnetic field aligns the magnet in the compass with its north pole. A second method is to observe the night sky in the polar regions. Northern and Southern Lights are produced by the interaction of the Earth's magnetic field with solar radiation.

Hope this helps!!!

a rectangular loop of wire has sides a = 0.085 m and b = 0.095 m, and resistance r = 35 ω. it moves with speed v = 9.5 m/s into a magnetic field with magnitude b = 0.75 t.

Answers

The total force acting on the loop is given by: F total = 4F = 4(0.0823) = 0.3292 N The direction of the force is perpendicular to the plane of the loop.  As the loop moves into the magnetic field, the force acting on the loop will cause the loop to rotate.

The force (F) experienced by a charged particle moving in a magnetic field can be expressed as: F = qvBsinθwhere F is the force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength, and θ is the angle between v and B. The magnetic force is given by F = BILsinθ. Since the loop has a rectangular shape, we can break it into four equal segments and compute the magnetic force acting on each segment.

The magnetic force on each of the four equal segments can be computed as: F = BILsinθ = B(0.085)(0.095)(35)/4 sin(90) = 0.0823 N The total force acting on the loop is the sum of the forces acting on the four segments. Therefore, the total force acting on the loop is given by: F total = 4F = 4(0.0823) = 0.3292 N The direction of the force is perpendicular to the plane of the loop.

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The induced current in the rectangular loop of wire is approximately 0.1914 A.

To determine the induced current in the rectangular loop, we can use Faraday's law of electromagnetic induction, which states that the induced electromotive force (emf) is equal to the rate of change of magnetic flux through the loop.

The magnetic flux is given by the product of the magnetic field strength (B) and the area of the loop (A).

Area of the rectangular loop:

A = a * b = (0.085 m) * (0.095 m) = 0.008075 m²

Rate of change of area:

ΔA/Δt = v * b = (9.5 m/s) * (0.095 m) = 0.9025 m²/s

Induced electromotive force (emf):

emf = B * ΔA/Δt = (0.75 T) * (0.008075 m²) / (0.9025 m²/s)

Induced current:

I = emf / r = [(0.75 T) * (0.008075 m²) / (0.9025 m²/s)] / (35 Ω) = 0.1914 A.

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find the energy released when there is a decrease of 0.3kg of material in a nuclear reaction

Answers

Answer:

E = 2.7 x 10¹⁶ J

Explanation:

The release of energy associated with the mass can be calculated by Einstein's mass-energy relation, as follows:

\(E = mc^2\)

where,

E = Energy Released = ?

m = mass of material reduced = 0.3 kg

c = speed of light = 3 x 10⁸ m/s

Therefore,

\(E = (0.3\ kg)(3\ x\ 10^8\ m/s)^2\)

E = 2.7 x 10¹⁶ J

explain the arrangements of molecular magnets in a magnet and in a magnetic substance ​

Answers

: Molecular magnet can refer to : molecular based magnet . An unconventional magnetic material that consists of organic molecules cordination compounds and combination

What is the centripetal acceleration acting on a 19 kg ball if it is being spun around by a tension force of 125 N?

Answers

Answer:

Explanation:

The centripetal acceleration:

aₙ = F /m = 125 /19 ≈ 6.6 m/s²

Your plant wants to order new machines for a process that totals 22.6 minutes. the demand for a typical 8 hour day is 98. what is the minimum number of machines to be ordered?

Answers

According to the question the minimum number of machines to be ordered would be 111 machines to meet the demand of 98 units for a process that totals 22.6 minutes in a typical 8-hour workday.

To determine the minimum number of machines to be ordered for a process that totals 22.6 minutes and has a demand of 98 units for a typical 8-hour day, we need to calculate the production rate and then determine the number of machines required.

First, let's convert the 8-hour workday into minutes:

8 hours * 60 minutes = 480 minutes

Next, we can calculate the production rate per minute:

Production Rate = Demand / Total Time

Production Rate = 98 units / 480 minutes

Production Rate ≈ 0.2042 units per minute

Now, let's calculate the number of machines required using the production rate and the process time per machine:

Number of Machines = Total Time / Process Time per Machine

Number of Machines = 22.6 minutes / (0.2042 units per minute)

Number of Machines ≈ 110.8 machines

Since we cannot have fractional machines, we need to round up the number of machines to the nearest whole number.

Therefore, the minimum number of machines to be ordered would be 111 machines to meet the demand of 98 units for a process that totals 22.6 minutes in a typical 8-hour workday.

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how to find average velocity on a velocity time graph

Answers

To find the average velocity on a velocity-time graph, you need to calculate the slope of the line connecting two points on the graph. The average velocity represents the change in velocity divided by the change in time between those two points.

To calculate the average velocity, you can use the formula:

Average velocity = (change in velocity) / (change in time)

You can determine the change in velocity by finding the difference between the final velocity and the initial velocity. The change in time is the difference in the time coordinates of the two points.

Select two points on the velocity-time graph, typically denoted by (t₁, v₁) and (t₂, v₂), where t represents time and v represents velocity. Then, substitute the values into the formula mentioned above to calculate the average velocity.

It's important to note that the average velocity provides information about the overall change in velocity over a specific time interval, rather than instantaneous velocity at a particular moment.

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a rod 16.0 cm long is uniformly charged and has a total charge of -23.0 µc. determine the magnitude and direction of the electric field along the axis of the rod at a point 42.0 cm from its center.

Answers

The magnitude of the electric field along the axis of the rod at a point 42.0 cm from its center is approximately 7.42 × 10^4 N/C directed away from the rod.

To determine the electric field at a point along the axis of a uniformly charged rod, we can use the equation for the electric field due to a charged rod:

E = (k * λ) / (2πε₀ * r),

where E is the electric field, k is Coulomb's constant (9 × 10^9 N m²/C²), λ is the linear charge density of the rod (charge per unit length), ε₀ is the permittivity of free space (8.85 × 10^-12 C²/N m²), and r is the distance from the center of the rod.

First, we need to calculate the linear charge density (λ) of the rod. Given that the total charge of the rod is -23.0 µC (microcoulombs) and the length of the rod is 16.0 cm, we can find λ:

λ = Q / L,

where Q is the total charge and L is the length of the rod. Converting the length to meters and the charge to coulombs, we have:

λ = (-23.0 × 10^-6 C) / (0.16 m).

Now, we can substitute the values into the electric field equation:

E = (9 × 10^9 N m²/C²) * [(-23.0 × 10^-6 C) / (2π * 8.85 × 10^-12 C²/N m² * 0.42 m)].

Calculating this expression yields E ≈ 7.42 × 10^4 N/C. The negative sign indicates that the electric field is directed away from the rod, as the rod has a negative charge.

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Consider an aircraft powered by a turbojet engine that has a pressure ratio of 12. The aircraft is stationary on the ground, held in position by its brakes. The ambient air is at 300 K and 95 kPa and enters the engine at a rate of 10 kg/s. The jet fuel has a heating value of 42,700 kJ/kg, and it is burned completely at a rate of 0. 2 kg/s. Neglecting the effect of the diffuser and disregarding the slight increase in mass at the engine exit as well as the inefficiencies of engine components, determine the force that must be applied on the brakes to hold the aircraft stationary, in kN

Answers

The force that must be applied on the brakes to hold the aircraft stationary is 84.51 kN (approx).

The force that must be applied on the brakes to hold the aircraft stationary is 84.51 kN.

Step 1:We can determine the exhaust gas temperature using the formulaT4 = T3 + (qin / (cp * m_dot)).Where,T3 = 1191.7 K (Given)qin = heating value of fuel × mass flow rate of fuel = 42,700 × 0.2 = 8,540 kJ/kgcp = specific heat at constant pressure = 1.005 kJ/kg.Km_dot = mass flow rate of air + mass flow rate of fuel = 10 + 0.2 = 10.2 kg/s

Putting all the values,T4 = 1191.7 + (8,540 / (1.005 * 10.2)) = 1191.7 + 84.85 = 1276.55 K

Step 2:The static thrust produced by the engine can be found out by the formula:

F = m_dot * (V2 - V1) + A2 * (P2 - P1)

Where,m_dot = mass flow rate of airA2 = area of the exhaust nozzleV1 = velocity of air at the engine inletV2 = velocity of air at the engine exitP1 = pressure of air at the engine inletP2 = pressure of air at the engine exitWe can use the simplified form of the above formula, which neglects the increase in the kinetic energy of the air in the combustor, the increase in the potential energy of the air from the inlet to the exhaust, and the change in the kinetic energy of the air from the inlet to the exhaust.F = m_dot * (Ve - V1) + Ae * (Pe - P1)

Where,Ve = velocity of air at the engine exitAe = area of the exhaust nozzlePe = pressure of air at the engine exitWe can calculate the value of Ve using the formula:Ve = sqrt(2 * cp * T4 * (1 - (P2 / P1)^((γ - 1) / γ))))Where,γ = ratio of specific heats = 1.4Putting all the values,Ve = sqrt(2 * 1.005 * 1276.55 * (1 - (1 / 12)^0.4))) = 724.23 m/sNow, we can calculate the static thrust,F = m_dot * (Ve - V1) + Ae * (Pe - P1)= 10.2 * (724.23 - 0) + (0.785 * (0.25)^2 * (12 * 10^3 - 95) * 10^3)= 74,044.47 N

Step 3:The force that must be applied on the brakes to hold the aircraft stationary is equal and opposite to the static thrust, that is, 74,044.47 N.

The value in kN will be: 74.04447/1000 = 74.04 kN.

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A specified volume of space contains an electric field for which the magnitude is given by E=E0cos(ωt). Suppose that E0 = 20 V/m and ω = 1.0 × 107 s−1. What is the maximum displacement current through a 0.40 m2 cross-sectional area of this volume?

Answers

Answer: \(0.708\ mA\)

Explanation:

Given

\(E_o=20\ V/m\)

\(\omega =10^7\ s^{-1}\)

Cross-sectional area \(A=0.40\ m^2\)

Current density is given by

\(J=\epsilon_o \dfrac{dE}{dt}\)

Displacement current

\(\Rightarrow I=JA\\\Rightarrow I=8.854\times 10^{-12}\times 20\times 10^7\times 0.4\\\Rightarrow I=0.708\times 10^{-3}\ A\)

The required value of the maximum displacement current of the given space is  \(7.08 \times 10^{-4} \;\rm A\).

Given data:

The intensity of electric field is, \(E_{0}=20 \;\rm V/m\).

The angular frequency of electric field is, \(\omega=1.0 \times 10^{7} \;\rm s^{-1}\).

The cross-sectional area of space is, \(A =0.40 \;\rm m^{2}\).

In the given problem, the instantaneous electric field is given by \(E = E_{0} \times cos(\omega t)\)

So, the expression for the current density is,

\(J= \epsilon_{0} \times \dfrac{dE}{dt}\)

Here, \(\epsilon_{0}\)  is the permittivity of free space. Solving as,

\(J= \epsilon_{0} \times \dfrac{d(E_{0} \times cos(\omega t))}{dt}\\\\J= -\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)\)

And the expression for the maximum displacement current is,

\(I = J \times A\)

And the maximum displacement current is possible only when, J is positive and J will be positive for  \(sin(\omega t)=-1\).

Then solving as,

\(I = (-\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)) \times A\\\\I = (-8.85 \times 10^{-12} \times 20 \times (1.0 \times 10^{7}) \times (-1)) \times 0.40\\\\I = 7.08 \times 10^{-4} \;\rm A\)

Thus, we can conclude that the required value of the maximum displacement current of the given space is  \(7.08 \times 10^{-4} \;\rm A\).

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Two coils A and B are wound side by side. Coil A has 8120 turns and coil B has 11842 turns. 54% of flux produced by coil A links coil B. A current of 6 A in coil A produces 0.02 mWb, while the same current in coil B produces 0.078 mWb. a) Calculate the mutual inductance and the coupling coefficient. b) Calculate the emf induced in coil B when the current is reversed in 0.015 seconds.

Answers

a) Mutual inductance = 0.108 H; Coupling coefficient = 0.482. b) - 4.95 V.


a) Mutual inductance, M between coil A and coil B can be given as:

M = k√(L_AL_B) here, k is the coupling coefficient, L_A and L_B are the inductances of the coil A and coil B respectively. Since 54% of flux produced by coil A links coil B,

So, K = 0.54

L_A = N_A Φ/I_AL_A

= 8120 × 0.02/6

= 27.07 mH

L_B = N_B Φ/I_BL_B

= 11842 × 0.078/6

= 154.63 mH

M = k√(LALB) = 0.482 × √(27.07 × 0.15463) = 0.108 H

b) The emf induced in coil B can be given as:-

ε = M (dI_B/dt)/L_B

ε = 0.108 × (-6/0.015) / 0.15463 = -4.95 V

Thus, the emf induced in coil B when the current is reversed in 0.015 seconds is -4.95 V.

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in The unit of power is a
derived unite
The unit of power is
a derived unit be con
CAY​

Answers

Answer:

Watts

Explanation:

The SI unit for power is the watt (W), where 1 watt equals 1 joule/second (1 W=1 J/s).

Which of the motion variables is the same in both thex and y axis?
A) velocity
B) acceleration
C) time
D) displacement

Answers

Answer:

Acceleration (b) not sure tho

Explanation:

a skater extends her arms horizontally, holding a 2 kg mass in each hand. she is rotating about a vertical axis with an angular velocity of 1 rev/s. if she pulls her hands in towards the center of her body, approximately what will the final angular velocity be if her own moment of inertia remains approximately constant at 5 kg m2, and the distance of the masses from the axis changes from 1 m to 0.2 m?

Answers

The final angular velocity will be 10.96 rad/sec.

What are some instances of the law of conservation of angular momentum?

According to the rule of conservation of angular momentum, an object's angular momentum won't change when no external tension is applied to it. Several instances of momentum: The speed at which the Earth spins hasn't changed in billions of years.

How to solve the question?

Given, mass in each hand, m = 2 kg

        initial angular velocity, ω₁ = 1 rev/s = 1×2π = 6.28 rad/sec

        moment of inertia of skater, I = 5 kgm²

        initial distance of the masses from the axis, d₁ = 1m

        final distance of the masses from the axis, d₂ = 0.2m

    According to conservation of angular momentum,

 Linitial = Lfinal

 I₁ω₁ = I₂ω₂

I₁ = 5+2×2×1 = 9 kgm²

I₂ = 5+2×2×(0.2)² = 5.16 kgm²

9×6.283 = 5.16×ω₂

ω₂ = 9×6.2833/5.16

ω₂ = 10.96 rad/s

So, the final angular velocity will be 10.96 rad/s.

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A cricket batsman hits a ball at a speed of 27m/s at an angle of 60 degrees to the horizontal. How far away would you have to stand in order to catch it (assuming you want to catch it just before it hits the ground)?

Answers

Answer:

64.4 m

Explanation:

First, find how long it takes to land.  Given in the y direction:

Δy = 0 m

v₀ = 27 m/s sin 60° ≈ 23.4 m/s

a = -9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

0 m = (23.4 m/s) t + ½ (-9.8 m/s²) t²

t = 4.77 s

Next, find how far it travels in that time.  Given in the x direction:

v₀ = 27 m/s cos 60° = 13.5 m/s

a = 0 m/s²

t = 4.77 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (13.5 m/s) (4.77 s) + ½ (0 m/s²) (4.77 s)²

Δx = 64.4 m

A boy on board a cruise ship drops a 30. 0 gm marble into the ocean. If the resistive force proportionality constant is 0. 500 kg/s. What is the terminal speed of the marble in m/s?.

Answers

The terminal speed of the marble is 0.588 m/s.

Calculation:

We know that,

F = mg                                                   ......(1)

where,

F = force

m = mass

g = acceleration due to gravity

Also,

v = F/k                                                       ......(2)

where,

v = terminal speed

k = proportionality constant

Substituting the value of F from equation (1) in equation (2)

v = mg/k                                                         .......(3)

Given,

m = 30 g = 0.030 kg

k = 0.500 kg/s

g = 9.8 m/s²

To find,

v =?

Put the values in equation (3)

v = mg/k              

v = 0.03(9.8)/ 0.500

  = 0.294/0.500

  = 0.588 m/s

Hence, the terminal speed of the marble is 0.588 m/s.

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.

0.588 m/s

0.588 m/s is the terminal speed of the marble.

Calculation:

We know that,

F = mg  ----> eq(1)

where,

F = force

m = mass

g = acceleration due to gravity

We also know,

v = F/k ----> eq(2)

where,

v = terminal speed

k = proportionality constant

On substituting the value of F from eq(1) in eq(2)

v = mg/k  

Given,

m = 30 g = 0.030 kg

k = 0.500 kg/s

g = 9.8 m/s²

we need to find,

v =?

substitute the values in equation (3)

v = mg/k            

v = 0.03(9.8)/ 0.500

 = 0.294/0.500

 = 0.588 m/s

Hence, the terminal speed of the marble is 0.588 m/s.

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The distance from the Earth to the Sun equals 1 AU. Neptune is 30 AU from the Sun. How far is Neptune from the Earth? AU

Answers

Answer:

The answer is 29 AU

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Answer:

29

Explanation:

part a if the speed of the magnet is doubled, the induced voltage is ________ . view available hint(s)for part a twice as great four times as great half as great unchanged

Answers

If the speed of the magnet is doubled, the induced voltage will be four times as great.

According to Faraday's Law of Electromagnetic Induction, the magnitude of the induced voltage in a coil is directly proportional to the rate of change of magnetic flux through the coil. When the speed of the magnet is doubled, the rate of change of magnetic flux through the coil also doubles, resulting in a doubling of the induced voltage.

However, since the induced voltage is directly proportional to the rate of change of magnetic flux, a doubling of the speed of the magnet results in a fourfold increase in the rate of change of magnetic flux, which leads to a fourfold increase in the induced voltage. Therefore, if the speed of the magnet is doubled, the induced voltage will be four times as great. This effect is important in many applications, such as electrical generators, where the speed of the rotor is used to control the output voltage of the generator.

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