Easy science question please help. Will give brainliest

The force actually being used to push the mower along the ground is 191 N.

When the physics student exerts a force of 250 N along the handle of the push mower, it's important to consider the components of this force that contribute to the actual force used to push the mower along the ground.

To determine the force used to push the mower along the ground, we need to find the horizontal component of the applied force. The angle of 40° indicates that the applied force can be broken down into two components: the horizontal component and the vertical component. The vertical component of the force is perpendicular to the direction of motion and does not contribute to pushing the mower forward.

To find the horizontal component, we can use trigonometry. The horizontal component is given by the formula:

Horizontal component = Applied force * cos(angle)

Plugging in the values, we get:

Horizontal component = 250 N * cos(40°)

Calculating this value, we find that the horizontal component of the applied force is approximately 191 N.

Therefore, the force actually being used to push the mower along the ground is 191 N. This is the component of the applied force that contributes to the forward motion of the mower, while the remaining vertical component is directed perpendicular to the ground and does not assist in pushing the mower forward.

By exerting a force of 250 N along the handle at a 40° angle, the student effectively applies 191 N of force to push the mower along the ground, ensuring efficient use of their effort while considering the environmental impact.

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Answer:

22.505 seconds

Explanation:

V =19.8m/s

V = a*to

t1 = 19.8/3.3

= 6seconds

Distance travelled during acceleration

= 1/2 x 3.3 x 6²

= 59.4m

X_total = x1 + x2

X2 = 373-59.4

X2 = 313.6m

t2 = x2/v

= 313.6/19.8

= 16.505

Total = 16.505 + 6

= 22.505 seconds

the minimum time in which an elevator can travel the 373 m from the ground floor is 22.505 seconds.

Answer:

1.60 s

Explanation:

t² = (2h)/g

t = √(2h)/g

t = \(\sqrt{2(12.6m)/9.80 m/s2}\)

t = 1.60 s

(1) The acceleration of the car is determined as 17.42 m/s².

(2) The acceleration of the crate is determined as 8.89 m/s².

The acceleration of the car is calculated from the net force acting on the car.

∑F = ma

F - Ff = ma

F - μW = ma

where;

m = W/g

m = (9320)/(9.8)

m = 951.02 kg

2(9320) - 0.222(9320) = 951.02a

16,570.96 = 951.02a

a = 17.42 m/s²

F - μW = ma

F - μmg = ma

302 - 0.75(18.6 x 9.8) = 18.6a

165.29 = 18.6a

a = 8.89 m/s²

Thus, the acceleration of the car is determined as 17.42 m/s².

The acceleration of the crate is determined as 8.89 m/s².

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The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.

The equation can be used to determine the average force the nail applies to the hammer.

\(F = \frac{mv}{t}\), where m is the hammer's mass, v is its speed, and t is the time at which it made impact with the nail. The average force in this situation is given by:

\(F = \frac{(2.5 kg)(6 m/s - 2.0 m/s)}{(0.002 s)}\\ F= 4500 N.\)

To solve this problem using force vs. time, you would need to plot a graph of force versus time, with the time of contact between the hammer and the nail representing the x-axis and the force exerted on the hammer by the nail representing the y-axis. The force exerted on the hammer increases from 0 to 4500 N as the hammer moves from rest to its maximum velocity. The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.

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Answer:

use d = r * t for these kinds of problems.. constant speed .. is the key here zero acceleration

Explanation:

d= distance. in meters

r= rate or speed in meters per second

t = time.. in seconds

d= 30 * 5

d=150 meters

The potential energy is at the maximum when you reach the top of your jump on a trampoline. The correct answer is option B.

Potential Energy is the type of energy an object possesses by virtue of its position relative to others, stresses within itself, electric charge, and other factors. Potential energy exists in various forms, including gravitational potential energy, elastic potential energy, chemical potential energy, and electrical potential energy.

This type of energy can be converted into another type of energies. Examples, a charged battery has potential energy and it can be used as electrical potential energy. Petrol, diesel and and gas have chemical potential energy and be used as kinetic energy.

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Answer:

Probably competition with television news-

by 1953 television was becoming common in many houses and people could obtain news from television newscasts

Answer:

force needed for the bus to go round the corner is 50,000 N.

Explanation:

To find the force needed for the bus to go round the corner, we can use the formula for centripetal force:

F = (mv^2)/r

where F is the centripetal force, m is the mass of the object, v is the velocity of the object, and r is the radius of the circular path.

Plugging in the values given in the problem, we get:

F = (2500 kg)(5 m/s)^2 / 50 m

= 50,000 N

So the force needed for the bus to go round the corner is 50,000 N.

The rms voltage measured across the secondary coil is 565.68 V.

The root mean square (RMS) value of an alternating current (AC) or voltage is the equivalent steady direct current (DC) value that produces the same heating effect or power dissipation in a resistor. In other words, it is the DC voltage or current that would produce the same amount of heat as the AC voltage or current over a given time period.

The rms voltage (V_rms) across the secondary coil can be calculated using the formula:

V_rms,secondary = (N_secondary/N_primary) * V_rms,primary

where N_secondary is the number of turns in the secondary coil, N_primary is the number of turns in the primary coil, and V_rms,primary is the rms voltage across the primary coil.

The rms voltage across the primary coil can be found from the given voltage function:

V_rms,primary = (1/√2) * V_peak,primary

where V_peak,primary = 200 V is the peak voltage across the primary coil.

Substituting the values, we get:

V_rms,primary = (1/√2) * 200 V = 141.42 V

Now, using the formula above, we can calculate the rms voltage across the secondary coil:

V_rms,secondary = (700/175) * 141.42 V = 565.68 V

Therefore, the rms voltage measured across the secondary coil is 565.68 V.

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The particle’s acceleration is 0.268 m/s².

The initial velocity of the particle before 13.3 seconds is 3.56 m/s.

The time when the particle is at rest is 32.68 seconds.

The acceleration of the particle is calculated as follows;

a = Δv/Δt

a = (7.95 m/s - 4.38 m/s) / 13.3 s

a = 0.268 m/s²

u = at

u = 0.268 m/s² x 13.3 s

u = 3.56 m/s

s = ut + ¹/₂at²

0 = -4.38t + ¹/₂(0.268)t²

0.134t² = 4.38t

0.134t = 4.38

t = 32.68 seconds

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Answer:

c. covering

Explanation:

covering is just doing defence and is not illegal in basketball

At height h, on the left side of a loop, a stone is let free from its resting position. h = v^2/(2 x g) + r must the stone be at in order to stay on the track at the top of the loop.

For a stone to not fall off the track at the top of a loop, it must be traveling fast enough to follow the track's curvature. This means that the stone must have a certain minimum speed at the top of the loop in order to complete it from resting position. The minimum speed required for the stone to complete the loop can be calculated using the equation v = sqrt(gr), where v is the minimum speed, g is the acceleration due to gravity, and r is the radius of the loop. Therefore, the minimum height h for which the stone will not fall off the track at the top of the loop can be calculated using the equation h = v^2/(2*g) + r, where h is the minimum height, v is the minimum speed, g is the acceleration due to gravity, and r is the radius of the loop.

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The set of all vectors which are scalar multiples of a nonzero vector u is a line through u and 0. a column vector in r₂ is a 1 x 2 matrix. The magnitude of a vector cv is c times the magnitude of v, where c is any scalar. The correct option is Option C.

Vector multiplication may refer to one of several products between two (or more) vectors. Multiplication of vectors is of two types. A vector has both magnitude and direction and based on this the two ways of multiplication of vectors are the dot product of two vectors and the cross product of two vectors. Dot product or "scalar product", is a binary product that takes place with two vectors and returns a scalar quantity. The dot product of two vectors can be defined as the product of the magnitudes of the two vectors and the cosine of the angle between the two vectors. Thus, A ⋅ B = |A| |B| cos θ

Cross product, or the "vector product", is a binary product on two vectors that results in another vector. So, if n is the unit vector perpendicular to the plane determined by vectors A and B,

A × B = |A| |B| sin θ n

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Acceleration is the change in velocity over time. We can calculate the acceleration of the bicyclist during the time 2.0 s to 5.0 s using the formula acceleration = (final velocity - initial velocity) / time.

The initial velocity of the bicyclist at 2.0 s is 2.0 m/s and the final velocity at 5.0 s is 8.0 m/s. The time interval between 2.0 s and 5.0 s is 3.0 s.

Substituting these values into the formula, we get acceleration = (8.0 m/s - 2.0 m/s) / 3.0 s = 6.0 m/s / 3.0 s = 2.0 m/s^2.

So, the acceleration of the bicyclist during the time 2.0 s to 5.0 s was 2.0 m/s^2.

Answer:

Approximately \(28^{\circ}\).

Explanation:

The refractive index of the air \(n_{\text{air}}\) is approximately \(1.00\).

Let \(n_\text{glass}\) denote the refractive index of the glass block, and let \(\theta _{\text{glass}}\) denote the angle of refraction in the glass. Let \(\theta_\text{air}\) denote the angle at which the light enters the glass block from the air.

By Snell's Law:

\(n_{\text{glass}} \, \sin(\theta_{\text{glass}}) = n_{\text{air}} \, \sin(\theta_{\text{air}})\).

Rearrange the Snell's Law equation to obtain:

\(\begin{aligned} \sin(\theta_{\text{glass}}) &= \frac{n_{\text{air}} \, \sin(\theta_{\text{air}})}{n_{\text{glass}}} \\ &= \frac{(1.00)\, (\sin(45^{\circ}))}{1.50} \\ &\approx 0.471\end{aligned}\).

Hence:

\(\begin{aligned} \theta_{\text{glass}} &= \arcsin (0.471) \approx 28^{\circ}\end{aligned}\).

In other words, the angle of refraction in the glass would be approximately \(28^{\circ}\).

Answer:

a) 463.29 K

b) 8065.65 Pa

c) 0 J

Explanation:

The parameters given are;

Volume of the tank, V = 3.72 m³

Number of moles of gas present in the tank, n = 22.1 moles

Temperature of the gas before heating, T₁ = 300 k

Heat added to the gas, ΔQ = 4.5 × 10⁴ J

Specific heat capacity at constant volume, \(c_v\), for monatomic gas = 12.47 J/K/mole

Avogadro's number = 6.022 × 10²³ particles per mole

a) ΔQ = n × \(c_v\) × ΔT

Where:

ΔT = T₂ - T₁

T₂ = Final temperature of the gas

Hence, by plugging in the values, we have;

4.5 × 10⁴ = 22.1 × 12.47 × (T₂ - 300)

\(T_{2} - 300 = \frac{4.5\times 10^{4}}{22.1\times 12.47}\)

T₂ = 300 + 163.29 = 463.29 K

b) The pressure of the gas is found from the relation;

P×V = n×R×T

\(P = \dfrac{n \times R \times T}{V}\)

Where:

P = Pressure of the gas

R = Universal gas constant = 8.3145 J/(mol·K)

T = Temperature of the gas

V = Volume of the gas = 3.72 ³ (constant)

n = Number of moles of gas present = 22.1 moles (constant)

Hence the change in pressure is given by the relation;

\(\Delta P = \dfrac{n \times R \times (T_2 - T_1)}{V} = \dfrac{n \times R \times \Delta T}{V}\)

Plugging in the values, we have;

\(\Delta P = \dfrac{22.1 \times 8.3145 \times 163.29}{3.72} = 8065.65 \, Pa\)

c) Work done, W, by the gas is given by the area under the pressure to volume graph which gives;

W = f(P) × ΔV

The volume given in the question is constant

∴ ΔV = 0

Hence, W =  f(P) × 0 = 0 J

No work done by the gas during the process.

When the liquid cools down, it loses heat energy.

As the liquid cools, it loses heat energy. As a result, its particles slow down in movement and come closer to one another. Attractive forces begin to hold particles and the crystals of a solid form.

If water is cooled, it can change into ice. If ice is warmed, it can change into a liquid state. Heating a substance makes the molecules move very fast whereas cooling a substance makes the molecules move very slowly.

Heating a liquid increases the speed of the molecules present in it. An increase in the molecule's speed competes with the attraction between molecules and results in the molecules moving apart whereas Cooling a liquid decreases the movement of the molecules.

So we can conclude that the liquid cools down when it loses heat energy.

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Answer:

a) 209.3 kilojoules must be removed from two liter of beverage, b) A rate of heat removal of 1.163 kilowatts is required to cool down 10 2-liter bottles, c) Cooling 10 2-L bottles during 30 minutes costs 4.9 cents.

Explanation:

a) How much heat energy must be removed from your two liters of beverage?

At first we suppose that the beverage has the mass and specific heat of water and that there are no energy interactions between the bottle and its surroundings.

From the First Law of Thermodynamics and definition of sensible heat, we get that amount of removed heat (\(Q\)), measured in kilojoules, is represented by the following formula:

\(Q = \rho \cdot V\cdot c\cdot (T_{o}-T_{f})\) (Eq. 1)

Where:

\(\rho\) - Density of the beverage, measured in kilograms per cubic meter.

\(V\) - Volume of the bottle, measured in cubic meters.

\(c\) - Specific heat of water, measured in kilojoules per kilogram-Celsius.

\(T_{o}\), \(T_{f}\) - Initial and final temperatures, measured in Celsius.

If we know that \(\rho = 1000\,\frac{kg}{m^{3}}\), \(V = 2\times 10^{-3}\,m^{3}\), \(c = 4.186\,\frac{kJ}{kg\cdot ^{\circ}C}\), \(T_{o} = 35\,^{\circ}C\) and \(T_{f} = 10\,^{\circ}C\), then:

\(Q = \left(1000\,\frac{kg}{m^{3}}\right)\cdot (2\times 10^{-3}\,m^{3})\cdot \left(4.186\,\frac{kJ}{kg\cdot ^{\circ}C} \right) \cdot (35\,^{\circ}C-10\,^{\circ}C)\)

\(Q = 209.3\,kJ\)

209.3 kilojoules must be removed from two liter of beverage.

b) You are having a party and need to cool 10 of these two-liter bottles in one-half hour. What rate of heat removal, in kW, is required?

The total amount of heat that must be removed from 10 2-L bottles is:

\(Q_{T} = 10\cdot (209.3\,kJ)\)

\(Q_{T} = 2093\,kJ\)

If we suppose that bottles are cooled at constant rate, then, rate of heat removal is determined by this formula:

\(\dot Q = \frac{Q_{T}}{\Delta t}\) (Eq. 2)

Where:

\(Q_{T}\) - Total heat, measured in kilojoules.

\(\Delta t\) - Time, measured in seconds.

\(\dot Q\) - Rate of heat removal, measured in kilowatts.

If we know that \(Q_{T} = 2093\,kJ\) and \(\Delta t = 1800\,s\), we find that rate of heat removal is:

\(\dot Q = \frac{2093\,kJ}{1800\,s}\)

\(\dot Q = 1.163\,kW\)

A rate of heat removal of 1.163 kilowatts is required to cool down 10 2-liter bottles.

c) Assuming that your refrigerator can accomplish this and that electricity costs 8.5 cents per kW-hr, how much will it cost to cool these 10 bottles (in $)?

A kilowatt-hour equals 3600 kilojoules. The electricity cost is equal to the  removal heat of 10 bottles (\(Q_{T}\)), measured in kilojoules, and unit electricity cost (\(c\)), measured in US dollars per kilowatt-hour. That is:

\(C = c\cdot Q_{T}\)

If we know that \(c = 0.085\,\frac{USD}{kWh}\) and \(Q_{T} = 2093\,kJ\), the total cost of cooling 10 bottles is:

\(C = \left(0.085\,\frac{USD}{kWh}\right)\cdot \left(2093\,kJ\right)\cdot \left(\frac{1}{3600}\,\frac{kWh}{kJ} \right)\)

\(C = 0.049\,USD\)

Cooling 10 2-L bottles during 30 minutes costs 4.9 cents.

Answer:

2.0 Hz

Explanation:

2.0 Hz is the most closest to the middle number in between 2.8 and 1.5 Hz. 1.6 Hz would not be suitable as it is too close to 1.5 Hz and 2.7 would also not be suitable as it is too close to 2.8 Hz.

Answer:

D

Explanation:

the answer is d because process of genetic recombination in bacteria in which genes from a host cell (a bacterium) are incorporated into the genome of a bacterial virus (bacteriophage) and then carried to another host cell when the bacteriophage initiates another cycle of infection

The minimal SOP equation that implements the same logic as the given equation is f = ab + ac.

The sum of product (SOP) is a type of logic circuit used to represent a logical expression. It is also known as a canonical sum of products and is a type of canonical form. An SOP expression is composed of one or more product terms. Each product term is the logical AND of one or more literals and is separated from other product terms with a plus sign. The sum of product form of a logic expression is a sum of the product terms of the expression.

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Answer:

Gravitational attraction provides the centripetal force needed to keep planets in orbit around the Sun and all types of satellite in orbit around the Earth. This centripetal force is supplied by gravity. The Earth's gravity keeps the Moon orbiting us. Centripetal force is perpendicular to velocity and causes uniform circular motion. The gravitational attraction of the Sun is an inward force acting on Earth. This force produces the centripetal acceleration of the orbital motion. Centripetal forces are always directed toward the center of the circular path.

Explanation:

Answer: C.

the gravitational pull of the Sun

Explanation: plato :3

Hope this helps!

Answer:

The resistance of 4/0 coated copper conductors is given as 0.0626 ohms per 1000 feet. To find the total resistance of the three 4/0 conductors installed in parallel, we can use the formula for combining resistances in parallel.

Since the total length for each of the three conductors is 323 feet, the resistance of each conductor can be calculated as follows:

Resistance of one conductor = (0.0626 ohms / 1000 feet) * 323 feet

To find the total resistance when the conductors are in parallel, we use the formula:

1/Total Resistance = 1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3

Total Resistance = 1 / (1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3)

Substituting the values, we get:

Total Resistance = 1 / (1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet))

Simplifying the expression will give us the total resistance of the three 4/0 conductors installed in parallel.

The time elapsed between the first splash and the second splash is approximately 0.69 seconds.

To calculate this, we consider the motion of two rocks thrown simultaneously from a bridge. Heather throws a rock straight down with a speed of 14 m/s, while Jerry throws a rock straight up with the same speed.

We use the equation for displacement in uniformly accelerated motion: s = ut + (1/2)at^2.

For Heather's rock, which is thrown downwards, the initial velocity (u) is positive and the acceleration (a) due to gravity is negative (-9.8 m/s^2). The displacement (s) is the height of the bridge (46 m).

Solving the equation, we find two possible values for the time (t): t ≈ -4.91 s and t ≈ 1.91 s.

Since time cannot be negative in this context, we discard the negative value and consider t ≈ 1.91 s as the time it takes for Heather's rock to hit the water.

For Jerry's rock, thrown upwards, we use the same equation with the same initial velocity and acceleration. The displacement is also the height of the bridge, but negative.

Solving the equation, we find t ≈ -5.68 s and t ≈ 1.22 s. Again, we discard the negative value and consider t ≈ 1.22 s as the time it takes for Jerry's rock to reach its maximum height before falling back down.

To find the time difference between the first and second splash, we subtract t ≈ 1.91 s (Heather's rock) from t ≈ 1.22 s (Jerry's rock). This gives us a time difference of approximately 0.69 seconds.

Therefore, the time elapsed between the first splash and the second splash is approximately 0.69 seconds.

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-27.7 x 10⁶ N is the net force on particle q₂..

Define a charged particle

A particle with an electric charge is said to be charged particle. It might be an ion, such as a molecule or atom having an excess or shortage of electrons in comparison to protons. It could also be an elementary particle like as an electron, proton, or another one that is thought to have the same charge (except antimatter).

F₁₂ = kq₁q₂/r²

k is Coulomb's constant

r is the distance between q₁ and q₂

q represent charges

F₁₂ = (9x 10⁹ x 18.1 x 10⁻³ x 11.2 x 10⁻³)/(0.28)²

F₁₂ = -23* 10⁶ N

F₂₃ = kq₂q₃/r²

F₂₃ = -(9 x 10⁹ x 11.3 x 10⁻³ x 5.67 x 10⁻³)/(0.35)²

F₂₃ = 4.7 x 10⁶ N

F(net) = F₁₂ + F₂₃

         = -23* 10⁶ N + -4.7 x 10⁶ N

         =  -27.7 x 10⁶ N

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what are the choices?

Explanation:

\(from \: ohms \: law \\ voltage \: \: V =IR \\ = 1.6 \times 2400 \\ = 3840 \: Volts\)

Answer:

is it 380

Explanation: