endothermic reaction vs. exothermic reaction worksheet

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Answer:

endothermic reaction

Photosynthesis is an endothermic reaction. This means it cannot occur without energy (from the Sun). The light required is absorbed by a green pigment called chlorophyll in the leaves.

Explanation: hope this helps u!

Answer:

Endothermic reaction I believe.

Explanation:

It can't occur without the energy from the sun. The light is absorbed by the green pigment called chlorophyll which is in the leaves of the plant.

Answer:

C3H6O + 4O2 → 3CO2 + 3H2O

Explanation:

I think that's the answer

Hope this helps :)

Answer:

\(P_{N_2}=285 torr\)

Explanation:

Given that

Volume of cylinder = 3 L

Temperature= 25 degrees

Partial pressure of the gases

\(P_{He}=115 torr\)

\(P_{N_2}=285 torr\)

\(P_{Ar}=325 torr\)

By using Dalton's law , the total pressure of the non reacting gas is the sum of the partial pressure of all gases.

\(P_{total}=P_{He}+P_{N_2}+P_{Ar}\)

\(P_{total}=115+285+325=725 torr\)

When all the He gas will removed then partial pressure of He will be zero.

\(P_{total}=P_P_{N_2}+P_{Ar}\)

\(P_{total}=285+325=610 torr\)

Partial pressure of N₂

\(P_{N_2}=610-325=285 torr\)

\(P_{N_2}=285 torr\)

In this example, the limiting reagent is the alkyl οr aryl halide (RX), as it is present in a lοwer quantity and will be cοmpletely cοnsumed during the reactiοn.

In οrganic chemistry, an alkyl grοup is an alkane missing οne hydrοgen. The term alkyl is intentiοnally unspecific tο include many pοssible substitutiοns. An acyclic alkyl has the general fοrmula οf −CnH₂n+1.

A cyclοalkyl grοup is derived frοm a cyclοalkane by remοval οf a hydrοgen atοm frοm a ring and has the general fοrmula −CnH₂n+1. Typically an alkyl is a part οf a larger mοlecule. In structural fοrmulae, the symbοl R is used tο designate a generic (unspecified) alkyl grοup. The smallest alkyl grοup is methyl, with the fοrmula −CH₃

In the preparatiοn οf Grignard reagents, the reactiοn typically invοlves the reactiοn between an alkyl οr aryl halide and magnesium metal in an ether sοlvent. The general equatiοn fοr the fοrmatiοn οf a Grignard reagent can be represented as:

RX + Mg -> RMgX

Tο determine the limiting reagent in this reactiοn, we need tο cοmpare the mοles οf the alkyl οr aryl halide (RX) and the mοles οf magnesium (Mg) and identify which reactant is present in the lοwer quantity. The reactant that is cοnsumed cοmpletely and limits the amοunt οf prοduct fοrmed is the limiting reagent.

Let's assume we have a specific example where we are preparing a Grignard reagent by reacting 2 mοles οf alkyl οr aryl halide (RX) with 3 mοles οf magnesium (Mg).

Mοles οf RX = 2 mοles

Mοles οf Mg = 3 mοles

Since the stοichiοmetric ratiο between RX and Mg is 1:1 (1 mοle οf RX reacts with 1 mοle οf Mg), we can see that we have an excess οf Mg in this example.

The stοichiοmetry indicates that 2 mοles οf RX wοuld require 2 mοles οf Mg fοr cοmplete reactiοn. Hοwever, we have 3 mοles οf Mg, which is mοre than enοugh tο react with the 2 mοles οf RX.

Therefοre, in this example, the limiting reagent is the alkyl οr aryl halide (RX), as it is present in a lοwer quantity and will be cοmpletely cοnsumed during the reactiοn.

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Answer:

H2SO4 + 2 LiOH → Li2SO4 + 2 H2O - Balanced equation | Chemical Equations online!

The actual free energy (∆G) of ATP hydrolysis in the cell differs from the standard free energy (∆G'°) due to variations in concentration, pH, temperature, and coupling to other reactions in the cellular environment.

The actual free energy (∆G) of hydrolysis of ATP in the cell is different from the standard free energy (∆G'°) due to several factors.

1. Concentration of reactants and products: ∆G'° is measured under standard conditions, with all reactants and products at 1M concentrations. However, in the cell, the concentrations of ATP, ADP, and inorganic phosphate (Pi) are different from these standard concentrations, which affects the actual ∆G.

2. pH and temperature: The standard free energy change (∆G'°) is measured at a specific pH (usually 7) and temperature (usually 25°C). In the cell, the pH and temperature may vary from these standard conditions, which can influence the actual free energy change (∆G).

3. Coupling to other reactions: In the cell, ATP hydrolysis is often coupled to other reactions, either directly or through enzyme-mediated processes. This coupling can cause the actual free energy change of ATP hydrolysis to be different from the standard free energy change.

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Answer:

22.4L

Explanation:

not sure if its totally correct but I tried

Answer:

its formed from non metal elements- i think

Explanation: its formed from non-metals and metals.
not sure tho

The malady affecting Tank 104, characterized by volatile aromas, a brownish color, and a flat, dull taste, is likely a result of microbial spoilage known as acetic acid bacteria (AAB) infection or acetobacter infection.

The significant increase in acetic acid concentration from 0.65 g/L to 2.73 g/L suggests the presence of acetic acid bacteria, which metabolize ethanol into acetic acid during the fermentation process. This bacterial infection leads to the production of acetic acid, causing the wine to have a vinegary or sharp taste and volatile aromas.

The increase in lactic acid concentration from 0.75 g/L to 3.40 g/L indicates the activity of lactic acid bacteria, which can also contribute to wine spoilage. These bacteria convert malic acid into lactic acid, resulting in changes in acidity and flavor.

The increase in pH from 3.70 to 4.10 and the significant drop in tartaric acid from 2.7 g/L to 0.06 g/L further support the presence of bacterial activity, as these changes are consistent with microbial metabolism.

In this case, the prolonged exposure to elevated temperatures due to the power outage created favorable conditions for the growth and activity of acetic acid bacteria and lactic acid bacteria.

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Answer:

To ensure the law of conservation of mass is demonstrated, you can conduct an experiment that involves a chemical reaction where the total mass of the reactants is equal to the total mass of the products. Here's an example experiment showcasing this principle:

Materials needed:

- A balance or scale

- Two clear containers

- Baking soda (sodium bicarbonate)

- Vinegar (acetic acid)

- A balloon

Procedure:

1. Set up the balance or scale and make sure it is calibrated properly.

2. Place one of the clear containers on the balance and record its mass.

3. Add a measured amount of baking soda to the container and record the new total mass.

4. Attach the balloon to the mouth of the container without allowing any gas to escape.

5. Carefully pour a measured amount of vinegar into the balloon through the container's opening without mixing it with the baking soda.

6. Observe the reaction between the vinegar and baking soda. The reaction will produce carbon dioxide gas, which will inflate the balloon.

7. Once the reaction is complete and the balloon has stopped inflating, carefully remove it from the container.

8. Place the second clear container on the balance and record its mass.

9. Pour the contents of the balloon (carbon dioxide gas) into the second container.

10. Weigh the second container with the carbon dioxide gas and record the new total mass.

Observation and Conclusion:

By comparing the initial mass of the baking soda and the vinegar with the final mass of the carbon dioxide gas and the container, you will observe that the total mass of the reactants (baking soda and vinegar) is equal to the total mass of the products (carbon dioxide gas and container). This demonstrates the law of conservation of mass, which states that mass cannot be created or destroyed in a chemical reaction, only rearranged.

By carefully measuring the masses before and after the reaction, you visually and quantitatively show that the total mass remains constant throughout the process. This experiment reinforces the fundamental principle of the law of conservation of mass, emphasizing that matter is conserved in chemical reactions, even when it undergoes changes in form or state.

Tο cοmpute the actual Crystal Field Stabilizatiοn Energy (CFSE) fοr a high spin fοurth periοd 3+ charged hydrated iοn, we need tο cοnsider the number οf unpaired electrοns and their respective energy levels.

The Crystal Field Stabilizatiοn Energy is defined as the energy οf the electrοn cοnfiguratiοn in the ligand field minus the energy οf the electrοnic cοnfiguratiοn in the isοtrοpic field. CFSE=ΔE=Eligand field−Eisοtrοpic field.

Fοr a fοurth periοd 3+ charged iοn, there are six d-electrοns in tοtal. In the high spin cοnfiguratiοn, all six d-electrοns are unpaired.

The CFSE fοr each electrοn can be determined by cοnsidering the energy splitting between the higher energy eg οrbitals and the lοwer energy t2g οrbitals in an οctahedral crystal field.

Assuming that each electrοn in the high spin cοnfiguratiοn cοntributes an equal CFSE, we can calculate the CFSE as fοllοws:

CFSE = (Number οf unpaired electrοns) * (Energy splitting between eg and t2g οrbitals)

Fοr a high spin fοurth periοd 3+ charged hydrated iοn, the CFSE can be expressed as a percentage οf the tοtal hydratiοn energy by dividing the CFSE by the tοtal hydratiοn energy and multiplying by 100.

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Answer:

i think this is correct

Explanation:

For amplitude measurements, you count the number of vertical divisions occupied by the signal's vertical signal and then multiply by the vertical scale. The example below shows the process for measuring the peak-to-peak voltage of a signal.

Answer:

c

Explanation:

metals are good conductors, while non metals are not good conductors

The scientist I have chosen is J.J. Thomson, who made significant contributions to the study of atomic structure in the late 19th and early 20th centuries.

Thomson's most well-known contribution is his discovery of the electron, which he identified as a negatively charged particle present in all atoms. This discovery formed the basis of Thomson's "plum pudding" model of the atom, which proposed that atoms consisted of a positively charged "pudding" with negatively charged electrons scattered throughout.

While this model was eventually disproven, Thomson's discovery of the electron and his work on the measurement of atomic and molecular masses laid the foundation for the modern atomic model. Specifically, Thomson's work on mass spectrometry led to the development of more advanced techniques for determining the masses and properties of atoms and molecules, which are still used in modern research today.

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Answer: C. UVA rays cause premature aging and UVB rays cause burning

Explanation: Ultraviolet radiation causes DNA changes in the skin, leading to premature aging and skin cancer. There are three kinds of UV light: UVA light. This form of solar radiation damages skin at all levels—from the surface layer (epidermis) down deep into the dermis.

Aluminum ion has a charge of 3+, Al³⁺, and sulfate is SO₄²⁻, so the compound aluminum sulfate has to have a number of aluminum and sulfate such that the final charge is zero, so the proportion on aluminum sulfate is:

That way we have 6+ and 6-, so neutral compound.

This means that for 1 mol of aluminum sulfate, we have 2 moles of aluminum ion. The molar concentration is the number of moles of solute divided by the volume of solution, so it is directly proportional to the number of moles.

So, we can use a rule of three as follows:

aluminum ion --- aluminum sulfate

2 --- 1

x --- 0.646 M

So:

So, the concentration of aluminum ion in this solution is 1.292 M.

The Hall coefficient (RH) in this case is approximately -3.01 * 10^-6 C^-1 cc (rounded to three significant figures in exponential notation).

The Hall coefficient (RH) is a parameter used to describe the behavior of charge carriers in a material when subjected to a magnetic field. It is given by the equation RH = 1/(e * p) where e is the elementary charge and p is the total charge carrier density. In this case, we are given the acceptor doping concentration (Na) and the donor doping concentration (Nd) in units of /cc.

To calculate the Hall coefficient, we need to determine the total charge carrier density (p). The total charge carrier density can be calculated as the difference between the acceptor doping concentration and the donor doping concentration: p = Na - Nd.

Given the acceptor doping concentration Na = 4.18 * 10^15/cc and the donor doping concentration Nd = 9.40 * 10^15/cc, we can substitute these values into the equation to find p:

p = Na - Nd
  = (4.18 * 10^15/cc) - (9.40 * 10^15/cc)
  = -5.22 * 10^15/cc

Now, we can substitute the value of p into the Hall coefficient equation:

RH = 1/(e * p)
    = 1/(1.60 * 10^-19 C * (-5.22 * 10^15/cc))
    = -3.01 * 10^-6 C^-1 cc

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To calculate the rate of reaction in g/hour, we need to determine the amount of zinc reacted in grams per unit time.

First, we need to convert the reaction time from minutes to hours. There are 60 minutes in one hour, so 5 minutes is equal to 5/60 = 1/12 hours.

Next, we need to find the moles of zinc reacted. We know that the molar mass of zinc (Zn) is approximately 65.38 g/mol.

The moles of zinc can be calculated using the equation:

Moles = Mass / Molar mass

Moles of zinc = 2 g / 65.38 g/mol ≈ 0.0306 mol

Since the reaction is stated to be complete after 5 minutes (or 1/12 hours), we can now calculate the rate of reaction in g/hour.

Rate of reaction = (Moles of zinc / Time in hours) × Molar mass of zinc

Rate of reaction = (0.0306 mol / (1/12) hours) × 65.38 g/mol

Rate of reaction = 0.0306 mol × (12 hours / 1) × 65.38 g/mol

Rate of reaction ≈ 239.05 g/hour

Therefore, the rate of reaction is approximately 239.05 g/hour.

the rate of reaction in terms of grams per hour for the reaction of 2 g of zinc with excess dilute HCl, which completes in 5 minutes, is approximately 239.05 g/hour.

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Answer:

it should be C

Explanation:

the top guy is right

Answer:

The answer is negative .

The formula for the relationship between weight and blood pressure in children is:

We differentiate the above function with respect to x Therefore:

Rate of change at the 70-pound weight level:

Blood is a fluid found in all living things that functions to deliver substances and oxygen needed by body tissues, transports chemical products of metabolism, and also acts as the body's defense against viruses or bacteria. Blood has the function of regulating acid and base balance. ,transports O2, carbohydrates, and metabolites, regulates body temperature by conduction or conduction, carries body heat from heat production centers (liver and muscles).

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X is the chemical symbol of the element

Answer:

there is none

Explanation:

your thinking of the symbol for chemical symbol for the element

This outcome is conceivable. Since Cr has a lower reactivity than K, it cannot remove K from its complex.

Condensation reactions (and their opposite, cleavage reactions), exchange reactions, acid-base interactions, and oxidation-reduction processes are the five categories into which the majority of chemical reactions can be divided.

The five main categories into which the bulk of chemical reactions can be grouped are acid-base reactions, exchange reactions, condensation reactions (and its opposite, cleavage reactions), and oxidation-reduction reactions.

The classification strategy is purely for convenience; a reaction may be classified in a number of ways depending on which of its characteristics is most important. Condensation processes are covered in this section.

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Answer:

C

Explanation:

Li + ZnCO3 -->

Answer:

wat dose dis du

Explanation:

u to frend lit me now if yu need help with yur math and english homewirk. me got anser 2 evryting

The opposite of heterotroph is autotroph.

What is heterotroph?

An organism is referred to as a heterotroph if it consumes other plants or animals for food and energy. Its origins are in the Greek words hetero, which means "other," and trophe, which means "nutrition."

Examples - Human, birds, dogs, etc.

What is autotroph?

A primary producer, also known as an autotroph, is an organism that uses energy from light or inorganic chemical reactions to create complex organic chemicals from simple ones, such as carbon dioxide.

Example - plants, algae etc.

The opposite of heterotroph is autotroph.

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Zaitsev's rule may or may not come into play during the reaction carried out in this experiment, depending on the specific reaction being studied.

Zaitsev's rule is a chemical principle that predicts the major product of a elimination reaction, which occurs when a molecule loses a small molecule, typically a proton or a halide ion. The rule states that the most substituted alkene is the major product.

In some reactions, the elimination step is the rate-determining step, and Zaitsev's rule would apply. In other reactions, the elimination step may not be the rate-determining step, or the reaction may proceed through a different mechanism that does not follow Zaitsev's rule. Therefore, it is important to consider the specific reaction being studied and the conditions under which it occurs to determine if Zaitsev's rule applies.

Without information about the specific experiment, you are referring to, I cannot accurately determine whether Zaitsev's rule comes into play or not.

Zaitsev's rule is used to predict the major product of an elimination reaction, specifically in E1 and E2 reactions. According to this rule, the most substituted alkene (having more carbon atoms attached to the double bond) is formed as the major product.

If the reaction in your experiment involves an elimination reaction, particularly E1 or E2, then Zaitsev's rule could be relevant in determining the major product formed. If the reaction does not involve elimination, Zaitsev's rule will not be applicable.

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Answer:

sorry I don't know so sorry so sorry so sorry so sorry so sorry so

Explanation:

so sorry I don't know so sorry so sorry so sorry maybe I think quotation ki and bro mind we are