Engineers are using computer models to study train collisions to design safer
train cars. They start by modeling an elastic collision between two train cars
traveling toward each other. Car 1 is traveling east at 6 m/s and has a mass
of 3,154 kg, Car 2 is traveling west at 23 m/s and has a mass of 8,296 kg.
After the collision, car 1 has a final velocity of 7 m/s west. What is the final
velocity of car 2?
A. 18 m/s east
B. 23 m/s west
C. 23 m/s east
D. 18 m/s west
SUN

Answers

Answer 1

Answer:

18 m/s west

Explanation:

Answer 2

The correct option is C. 23 m/s east

What is  law of conservation of momentum ?

Conservation of momentum states that For two or more bodies in an isolated system acting upon each other, their total momentum remains constant unless an external force is applied. Therefore, momentum can neither be created nor destroyed.

using conservation of momentum

m1v1 + m2v2 = m1 v1' + m2 v2'

Given

m1 = 3154 kg

v1= 6m/s

m2 = 8296 kg

v2 = 23 m/s

v1' = 7m/s

v2' = ?

3154 * 6 + 8296 * 23 = 3154 * 7 + 8296 v2'

209732 - 22078 = 8296 v2'

187654 = 8296 v2'

v2' = 22.62 ≈ 23 m/s east

correct option is C. 23 m/s east

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Related Questions

Which correctly describes latent heat?

A. The heat of molecules that are under pressure
B. The heat held inside of ice crystals colder than -2°C
C. The heat absorbed or lost by a substance while it's changing state
D. The heat used to change the temperature of a liquid

Answers

Option C. The heat absorbed or lost by a substance while it's changing state  correctly describes latent heat

Latent heat is the heat absorbed or lost by a substance while it is changing state.

The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.

For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.

Latent heat is not associated with a temperature change; rather, it's associated with a change of state.

For instance, the temperature of water remains at 100°C while boiling.

When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.

When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.

Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.

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A measure of how easily current will pass through a material ?

Answers

Answer:

It is Conductivity because it is the measure of the ease.

what is the full distance when an object is thrown at 35 m/s at an angle of 45 degrees

what is the full distance when an object is thrown at 35 m/s at an angle of 45 degrees

Answers

Okay, here are the steps to calculate the full distance traveled when an object is thrown at a certain speed and angle:

You have the initial velocity (v): 35 m/s

You have the launch angle (θ): 45 degrees

We need to split the initial velocity into its horizontal (vx) and vertical (vy) components.

To calculate vx (horizontal component):

vx = v * cosθ

vx = 35 * cos(45) = 24.7 m/s

To calculate vy (vertical component):

vy = v * sinθ

vy = 35 * sin(45) = 24.7 m/s

We can calculate the horizontal distance (d) traveled using:

d = vx * t (where t is time)

Since there is no air resistance, the vertical velocity (vy) will remain constant. This means the time the object is in the air is:

t = vy / g (where g is acceleration due to gravity, 9.8 m/s^2)

t = 24.7 / 9.8 = 2.52 seconds

Now we can calculate the full horizontal distance traveled:

d = vx * t

d = 24.7 * 2.52

= 62.3 meters

So the full distance the object will travel when thrown at 35 m/s at a 45 degree angle is approximately 62 meters.

Let me know if you have any other questions!

Answer:

To calculate the full distance traveled by an object thrown at a velocity of 35 m/s at an angle of 45 degrees, we need to consider the horizontal and vertical components of the motion separately.

The horizontal component of the motion remains constant throughout the trajectory and is given by:

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

In this case, the initial velocity is 35 m/s, the angle is 45 degrees, and we need to find the time of flight.

The time of flight can be calculated using the vertical component of the motion. The vertical motion can be described using the equation:

Vertical displacement = (Initial velocity * sin(angle))^2 / (2 * acceleration)

Where the initial velocity is 35 m/s, the angle is 45 degrees, and the acceleration is the acceleration due to gravity, approximately 9.8 m/s^2.

The vertical displacement is zero at the highest point of the trajectory since the object comes back down to the same height it was launched from. So we can solve the equation for the time of flight.

Using these calculations, we can find the horizontal distance traveled by the object.

Let's calculate step by step:

Step 1: Calculate the time of flight

Vertical displacement = 0 (at the highest point)

0 = (35 * sin(45))^2 / (2 * 9.8)

0 = (24.75^2) / 19.6

0 = 616.0125 / 19.6

0 = 31.43

Step 2: Calculate the time of flight

Vertical displacement = (Initial velocity * sin(angle)) * time - (1/2) * acceleration * time^2

0 = (35 * sin(45)) * time - (1/2) * 9.8 * time^2

0 = 24.75 * time - 4.9 * time^2

4.9 * time^2 - 24.75 * time = 0

time * (4.9 * time - 24.75) = 0

time = 0 (initial point) or 24.75 / 4.9

time = 5.05 seconds

Step 3: Calculate the horizontal distance

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

Horizontal distance = 35 * 5.05 * cos(45)

Horizontal distance = 35 * 5.05 * (sqrt(2)/2)

Horizontal distance = 88.96 meters

Therefore, when an object is thrown at 35 m/s at an angle of 45 degrees, the full distance traveled is approximately 88.96 meters.

A drum is struck first with little energy. The drum is then struck with a lot of energy. Which sound will be louder? Why?

Answers

Answer:

The drum struck with a lot of energy would be louder than the drum struck with little energy because there is a harder impact on it

Explanation:

How can one sperate particles of different velocities moving in a magnetic field? ​

Answers

Magnetic particle separation is a powerful tool for separating particles based on their velocities in a magnetic field, and it has significant practical applications in various scientific and technological fields.

To separate particles of different velocities moving in a magnetic field, one can utilize a technique called magnetic field separation or magnetic particle separation.

This method takes advantage of the fact that charged particles moving in a magnetic field experience a force called the Lorentz force, which acts perpendicular to both the velocity vector and the magnetic field.

The basic principle behind magnetic particle separation is to apply a magnetic field perpendicular to the motion of the particles. The Lorentz force will then cause the particles to curve in different directions based on their velocities and charges.

By carefully controlling the strength and direction of the magnetic field, particles with different velocities can be steered onto different paths and separated.

One common approach to achieve magnetic particle separation is to use a device called a magnetic separator. This device typically consists of a strong magnet or a series of magnets arranged to create a uniform magnetic field.

The particles to be separated are injected into a chamber or a flow system where the magnetic field is applied. As the particles move through the magnetic field, they experience the Lorentz force and deviate from their original trajectory. The degree of deviation depends on their velocity and charge.

By carefully adjusting the magnetic field strength, particle size, and other parameters, it is possible to optimize the separation process and achieve effective separation of particles with different velocities. This technique has various applications in fields such as biomedical research, environmental monitoring, and materials science.

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If an object on a horizontal frictionless surface is attached to a spring, displaced, and then released, it oscillates. Suppose it is displaced 0.122 m from its equilibrium position and released with zero initial speed. After 0.810 s, its displacement is found to be 0.122 m on the opposite side and it has passed the equilibrium position once during this interval. Find:

a. The amplitude
b. The period
c. The frequency.

Answers

Answer:

a. Amplitude = 0.244 meters

b. Period = 1.62 seconds

c. Frequency = 0.6173 Hz

Explanation:

a.

With the position goes from 0.122 meters to -0.122 meters (negative because it is in the opposite side of the equilibrium point), the amplitude is the maximum value minus the minimum value:

Amplitude = 0.122 - (-0.122) = 0.122 + 0.122 = 0.244 meters

b.

The period is the amount of time the object takes to arrive in the same position again. So, if it takes 0.81 seconds to go to -0.122 m, it will take another 0.81 seconds to come back to 0.122 m, so the period is the sum of these two times:

Period = 0.81 + 0.81 + 1.62 seconds

c.

The frequency of the movement is the inverse of the period:

Frequency  = 1 / Period

So if the period is 1.62 seconds, the frequency is:

Frequency = 1 / 1.62 = 0.6173 Hertz

A cyclist and his bicycle have a combined mass of 85 kg. If he is moving at
12 m/s, how much KE does he have?
Your nour

Answers

Answer:

211.2 kg:m/s

Explanation:

Mark brainily

please help with both questions I’m giving all my points :) it’s 23 and 24

please help with both questions Im giving all my points :) its 23 and 24

Answers

Sorry just need points

If you can run 10.43 m in 14.22 s. How fast are you running?

Answers

Answer:

I am 15th in my state for 55m hurdles with a time of 10.4 seconds

Explanation:

BAM

Answer: 44 m per minute

Explanation:

one point charge -7.70 c is located at coordinate (-6.54, 4.05). a second point charge 0.778 c is located at coordinate (9.75, 0.893). what is the electric potential v in volts produced by these two charges at coordinate (0, 0)? the coordinates are given in meters. make the standard assumption for point charges that v

Answers

Electric potential at point (0, 0) due to the two point charges is \(-6.84 * 10^6 volts\). We can use formula: \(V = k(q1/r1 + q2/r2)\)

To find the Electric potential at point (0, 0) due to the two point charges, we need to use the formula:

\(V = k(q1/r1 + q2/r2)\)

where V: electric potential, k: Coulomb's constant (\(8.99 * 10^9 N m^2/C^2\)), q1 and q2: magnitudes of the charges (-7.70 c and 0.778 c, respectively), and r1 and r2: distances from each charge to the point (0, 0).

Using the distance formula, we can find that r1 = 7.593 m and r2 = 10.342 m. Put values in formula:

V = \((8.99 * 10^9 N m^2/C^2)(-7.70 c/7.593 m + 0.778 c/10.342 m)\)

V = \(-7.52 * 10^6 V + 6.77 * 10^5 V\)

V =\(-6.84 * 10^6 V\)

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1. Take the speed at which the body moves as 10 m/s 2. Calculate the distance travelled by the body every second 3. Take the time on the x-axis and distance travelled on the y-axis 4. Plot the distance vs time graph on a centimeter graph sheet taking 1cm= 1 s 5. Repeat the steps 2-4 for a speed of 50 m/s on the same graph sheet 6. Observe the graphs obtained for different speeds a) Find the nature of the graph obtained b) What kind of motion is obtained- uniform/non-uniform?

Answers

Answer:

a)this graph is also a line     b) in both cases we have a uniform movement

Explanation:

In this exercise we have a uniform movement

     v = d / t

     d = v t

in the table we give some values ​​to make the graph

       t (s)    d (m)

        1         10

        2        20

        3         30

In the attached we can see the graph that is a straight line

we have another vehicle at v = 50 me / S

t (s)     d (m)

1         50

2        100

3         150

this graph is also a line

b) in both cases we have a uniform movement

1. Take the speed at which the body moves as 10 m/s 2. Calculate the distance travelled by the body every

A car with a mass of 1200kg is traveling west at 25 m/s collides head on with highway barrier. The car comes to rest in 0.35 seconds . What is the magnitude of the force and the impulse applied to the car

Answers

The magnitude of the force and the impulse applied to the car are  85714 N and  30000 N-s respectively.

What is force?

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

The magnitude of the force applied to the car = change in momentum/time interval

= (1200 kg × 25 m/s - 1200 kg×0)/0.35 second

= 85714 N.

The impulse applied to the car = change in momentum

= (1200 kg × 25 m/s - 1200 kg×0)

= 30000 N-s.

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A 0.55 kg soccer ball is kicked with a force of 15 N for 0.25 seconds. The ball was at rest before the kick. What is the speed of the soccer ball after the kick?


Answers

Answer:

Check pdf

Explanation:

One component of a magnetic has a magnitude of 0.045T and points along the +r axis, while the other component has a magnitude of 0.065T and points along the -y axis. A 1- gram particle carrying a charge of +2.0 ൈ 10-ହC Cis moving along the +Z and at a speed of 4.2 ൈ 10ଷ/. Determine the angle that the net force makes with respect to the +r axis,

Answers

The angle that the net force makes with respect to the x- axis, is determined as 55.3⁰.

Angle of the net force

The angle that the net force makes with respect to the +x axis, is determined as follows;

F = qvBsinθ

with respect to y-axis

Fy =  qv(By)sinθ

with respect to x-axis

Fx =  qv(Bx)sinθ

The angle that the net force makes with respect to the +x axis;

tanθ = Fy/Fx

tanθ = qv(By)sinθ / qv(Bx)sinθ

tanθ = By/Bx

tanθ = 0.065/0.045

tanθ = 1.444

θ = tan⁻¹(1.444)

θ = 55.3⁰

Thus, the angle that the net force makes with respect to the x- axis, is determined as 55.3⁰.

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the object that emit light when they are hot called.......​

Answers

The object that emits light when it is hot is called luminescent.

How would taping a coin to the balloon affect the overall motion of the balloon?

Answers

Answer:

the motion of the coin taping the balloon is the balloon squshing down

What is the force on a 1,250 kg elevator that is in free fall at 9.8 m/s²? Ignore air
resistance, round your answer to the nearest tenth and use appropriate units.

Answers

Answer:

\(\boxed{12250N}\)

Explanation:

Assuming we disregard air resistance, the only force acting on the elevator will be its weight.

\(F \implies w=m\cdot g\)

where:

\(F=\) force

\(w=\) weight

\(m=\) mass → 1250kg

\(g=\) gravity acceleration  → 9.8m/s^2

Then:

\(F= 1250kg \cdot 9.8m/s^2\\F=12250 kg\cdot m/s^2= 12250N\)

Hope it helps.

\(\text{-B$\mathfrak{randon}$VN}\)

In a resonance tube experiment, a tuning fork of frequency 256Hz gave a resonance when the water level was 30cm below the open end of the tube. If the next position of resonance was 100cm, what is the velocity of sound in air?

Answers

The velocity of sound in air is 358m/s

Calculations and Parameters

Given;

Frequency= 256 HzWater level= 30cmPosition of resonance= 100cmThe velocity of sound in air= ?

v= 2f(L2-L1)

= 2.2.56.(1- 0.3)

=358 m/s

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Which has high momentum, a van weighing 3,500 kg with a velocity of 22 m/s or a van weighing 3,450kg running at the velocity of 23 m/s?​

Answers

By calculating the Momentum of each of the vans and comparing the two values, we find that the second van weighing 3,450 kg with a velocity of 23 m/s has higher momentum, which is 79,350 kgm/s.

Understanding Momementum

To determine which van has higher momentum, we need to calculate the momentum of each van using the formula:

Momentum = mass × velocity

Given:

Mass of Van₁ = 3500 kg

Velocity of Van₁ = 22 m/s:

Momentum = 3500 kg × 22 m/s = 77000 kgm/s

Mass of Van₂ = 3450 kg

Velocity of Van₂ = 23 m/s:

Momentum = 3450 kg × 23 m/s = 79350 kgm/s

Comparing the two values, we find that the second van weighing 3,450 kg with a velocity of 23 m/s has higher momentum, which is 79,350 kg·m/s.

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The work done per unit volume is?

Answers

Answer:

hahsbahbavbsbsbaba avabshshshbabahsjsjajajjajajjajjaja

Work done per unit volume = total work done/ total volume, V =

Which of the following statements is true about the speed at which sound waves travel?


A:Sound travels faster through air

B:Sound travels faster in a vacuum

C:Sound travels faster through water

D:Sound travels faster through a solid

Answers

Answer: sound waves travel faster in solid than water or air.

In vacuum sound waves don't travel at all

Answer:

A: Sound travels faster through air

Explanation:

The speed of sound is the distance travelled per unit of time by a sound wave as it propagates through an elastic medium. At 20 °C, the speed of sound in air is about 343 metres per second, or a kilometre in 2.9 s or a mile in 4.7 s.

5. A projectile is fired in Earth's gravitational field with a horizontal velocity of y = 9.00 m/s.
b. How far does the projectile fall in the vertical direction in 0.550 s?

Answers

Answer:

4.13m

Explanation:

Given

Horizontal velocity = 9.00m/s

time taken = 0.550 s

Required

How far does the projectile fall in the vertical direction

Using the formula for finding the maximum height of the projectile

H = U²sin²θ/2g where;

U = 9.00m/s

θ = 90° (object launched in the vertical direction)

g = 9.81m/s²

Substituting the given parameters into the formula;

H = 9²sin²90/2(9.81)

H = 81(1)/19.62

H = 81/19.62

H = 4.128 m

H ≈ 4.13m

Hence the distance that the projectile fall in the vertical direction is 4.13m

Speed is the rate of change of position expressed as____ Traveled per unit of time

Answers

Answer:

distance

Explanation:

Speed is the rate of change of position expressed as distance travelled per unit of time

Electricity is the flow of electrons. The questions relate to how electricity is quantified. Electrons are charged particles. The amount of charge that passes per unit time is called

Answers

The amount of charge that passes per unit time is called electric current .

Current has dimensions of [Charge] / [Time] .

It's measured and described in units of ' Ampere ' .

1 Ampere means 1 Coulomb of charge passing a point every second.

As light from a star spreads out and weakens, do gaps form between the photons?

Answers

As light from a star spreads out and weakens, there are no  gaps forming between the photons.

What is a photon?

A photon is described as  an elementary particle that is a quantum of the electromagnetic field, including electromagnetic radiation such as light and radio waves, and the force carrier for the electromagnetic force.

No matter how faint the light gets, there are never any spatial gaps in light when we think of photons as waves.

Although a distant star's light does spread out and get weaker as it moves, this just affects the wave intensity and does not cause gaps in the wave.

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conclusion for the oscillation of a simple pendulum for lab reports

Answers

In conclusion, the experiment on the oscillation of a simple pendulum provided valuable insights into the behavior and characteristics of pendulum motion.

The results obtained during the experiment confirmed the expected relationship between the period of a pendulum and its length. It was observed that as the length of the pendulum increased, the period also increased, indicating a direct proportionality between these two variables.

This relationship aligns with the theoretical predictions of a simple pendulum, as stated by the formula T = 2π√(L/g), where T is the period, L is the length, and g is the acceleration due to gravity.

The experiment also demonstrated the effect of changing the angle of displacement on the period of the pendulum. It was observed that for small angles of displacement, the period remained constant, confirming the approximation of small angle oscillations as simple harmonic motion.

However, as the angle of displacement increased, the period deviated from the expected value, highlighting the non-linear nature of the pendulum's motion at larger angles.

Furthermore, the experiment emphasized the importance of minimizing external influences, such as air resistance and friction, to obtain accurate and reliable results. By ensuring a controlled environment and employing proper techniques, the impact of these external factors was minimized.

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Review please help.

Review please help.

Answers

Answer:

1 and 3

Explanation:

because they are going up from 0

Multiple part question Here are the needed details:Five rotations took 5.15 seconds 1 rotation took 1.07s Distance from shoulder to elbow is 29 cm distance from shoulder to middle of the hand is 57cm.7. A. What was the average angular acceleration (degrees/s squared and rad/s squared) of the elbow?B. What was the average centripetal acceleration (m/s squared) of the elbow?C. How do these compare to the hand? Why are they the same and or/ different?

Answers

Given data

One rotation means 360 degree

The angular speed for five rotations is

\(\omega_1=\frac{5\times2\pi}{5.15}=6.09\text{ rad/s}\)

The angular speed for one rotation is

\(\omega_2=\frac{1\times2\pi^{}}{1.07}=5.86\text{ rad/s}\)

(A)

The average angular acceleration is zero here as there is no change in the angular velocity. But, if you consider that first case (A) where the angular velocity is 6.09 rad/s and the second case where the angular velocity is 5.86 rad/s. You can say that there is a change in angular velocity but there is no particular time interval. Hence, you can not calculate the average angular acceleration. For individual cases, there will be no average acceleration.

But, there will be centripetal acceleration which will act towards the center of the circle.

(B)

The length of the elbow is given as

\(r=29\text{ cm=0.29 m}\)

The centripetal acceleration of the elbow is calculated as

\(\begin{gathered} a_e=\omega^2_2r \\ =(5.86)^2(0.29) \\ =9.99m/s^2 \end{gathered}\)

(C)

The length of the hand is given as,

\(\begin{gathered} L=2\times57\operatorname{cm} \\ =114\text{ cm} \\ =1.14\text{ m} \end{gathered}\)

Therefore, the centripetal acceleration on the hand is calculated as

\(\begin{gathered} a_h=\omega^2L \\ =(5.86)^2(1.14) \\ =39.14m/s^2 \end{gathered}\)

Thus, the centripetal acceleration for the hand is different from the elbow

Hendry throws an object vertically upwards at a velocity of 26,5 m⋅s-1 from the
edge of a cliff of height 120m. After some time, the projectile lands on the
ground below the cliff After 1 second, Cathy fires a second object upwards FROM THE
GROUND BELOW with a velocity of 45 m⋅s-1. Calculate the time and
distance will the two objects meet.

Answers

Hendry and Cathy will each throw an object, and the time and location at which they will collide can be determined using the laws of motion. Hendry's item had an initial velocity of 26.5 m/s, whereas Cathy's object had an initial velocity of 45 m/s. Hendry's object's equation of motion is given by: s = u*t + 0.5*a*t*2, where s is the displacement, u*t* is the starting velocity, t* is the time, and a*t* is the acceleration brought on by gravity.

The acceleration caused by gravity is negative since the item is being flung upward. The item that Cathy threw has the following equation of motion: s = u * t - 0.5 * a * t2.where s is the distance travelled, u is the starting speed, t is the passage of time, and an is the acceleration brought on by gravity. The acceleration caused by gravity is negative since the item is being flung upward.

These equations allow us to determine the location and timing of the two items' collision. By figuring out the two equations for t, one may determine the moment when the objects will collide. By changing the value of t in either equation, one may determine the distance at which the objects will collide. Therefore, using the equations of motion, it is possible to determine the moment and distance at which the two objects will collide.

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3. A sprinter leaves the starting blocks with an acceleration of 4.5 m/s2. What is the
final velocity of the sprinter after 4 seconds?
ime=change in

Answers

Hi there! :)

\(\large\boxed{v_{f} = 18 m/s}\)

Use the following kinematic equation to solve for the final velocity:

\(v_{f} = v_{i} + at\)

In this instance, the runner started from rest, so the initial velocity is 0 m/s. We can rewrite the equation as:

\(v_{f} = at\)

Plug in the given acceleration and time:

\(v_{f} = 4.5 * 4 = 18 m/s\)

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