The solar energy that hits the transparent windows of a greenhouse is in the form of shortwave energy.
Solar energy that reaches the transparent windows of a greenhouse is primarily composed of shortwave energy. Shortwave energy refers to the electromagnetic radiation emitted by the Sun, which includes ultraviolet (UV), visible, and a portion of infrared (IR) wavelengths. These shorter wavelengths are able to pass through the greenhouse windows and enter the enclosed space, where they are absorbed by various surfaces, such as plants, soil, and objects, and converted into heat. This trapped heat leads to an increase in temperature within the greenhouse, creating a favorable environment for plant growth. In contrast, longwave energy, also known as thermal or infrared radiation, is emitted by objects within the greenhouse, including plants, soil, and structures, and is responsible for the greenhouse effect, which helps retain heat within the greenhouse.
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Liquefied Natural Gas (LNG) is a natural gas in its liquid form that is clear, colorless, odorless, non-corrosive, and non-toxic. A) TrueB) False
Liquefied Natural Gas (LNG) can be defined as a natural gas which in liquid form appear clear and colorless. It is odorless, non-toxic, and non-corrosive. Therefore, the given statement is A) True.
LNG or Liquified Natural Gas is a fossil fuel that is produced after the compression of organic matter in the form of algae and phytoplankton. LNG consists of 95% methane gas. The combustion of LNG produces carbon dioxide and water vapors. It burns with a least pollution thus called as cleanest fossil fuel. The liquefaction of the natural gas takes place at -160 degree Celsius. The liquefaction of the gas causes it to transport easily in gas tanks. LNG is colorless, and clear. LNG does not possess any smell and it is non-corrosive to metallic tanks. LNG is also non-toxic.Learn more about natural gas:
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Which of the following headlines about the French Revolution is not true?
a) "Estates General Meet for First Time in 175 Years"
b) "National Assembly Issues Declarations of the Rights of Man"
c) "Reign of Terror Ends; Robespierre Dies"
d) "Napoleon Declares Himself Holy Roman Emperor"
e) All of the Above
f) None of the Above
Answer:
d) "Napoleon Declares Himself Holy Roman Emperor"
Explanation:
The French Revolution is defined as a period of the major social upheaval which began in the year 1787 and lasted till year 1799. This revolution completely redefined the the very nature of the political power in France. and also the relationship between the rulers of France and the people they governed.
The 1789 Estates-General was the 1st meeting since year 1614 of the French Estates-General. It is a general assembly which represents the French estates of realm.
During the French revolution was at peak, the National Assembly issued the Declaration of the rights of the man to the public.
Maximilien Robespierre was considered to be one of the most influential figure and most important statesman during the French Revolution.
Thus all the options (a),(b) and (c) are headlines about the French Revolution, except option (d).
In the shop which of these indicates caution?
A: Red Light
B: Orange Light
C: Yellow Light
D: Green Light
Answer:
Yellow light
Explanation:
The flashing yellow light means: "proceed with caution." Traffic facing the yellow light has the right-of-way, but oncoming traffic usually also has a flashing yellow light, and cross-traffic will have a flashing red light.
YELLOW—A yellow signal light warns you that the red signal is about to appear. When you see the yellow light, you should stop, if you can do so safely. If you can't stop, look out for vehicles that may enter the intersection when the light changes. FLASHING YELLOW— What does a flashing yellow light mean?
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3- a worker walks up the sloped roof that is defined by the curve
Assuming that the worker walks up the sloped roof that is defined by the curve, we can conclude that the roof is in the shape of a curved line and that the worker is moving upward. Furthermore, we don't have enough information to determine the exact slope or curvature of the roof.
However, if we know the equation of the curve, we can find the slope at any point along the roof. This would give us more information about the steepness of the slope at different points. Also, we don't know how the worker is moving up the slope. If the worker is walking directly up the slope, they will be working against the force of gravity, and this will require more effort than walking on a flat surface.
If they are using a ladder or other equipment to climb the slope, the amount of effort required will depend on the angle of the ladder or equipment and the weight of the equipment and the worker. In conclusion, the information provided is not sufficient to determine the slope or steepness of the roof, the curvature of the roof, or the amount of effort required by the worker to walk up the roof.
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A worker is walking up a sloped roof that is defined by a curve. This is an interesting situation that can be analyzed using mathematics and physics. The slope of the roof is an important parameter that determines the force required to climb up the roof.
the slope of the roof, the curvature of the curve, and the worker's weight are important parameters that affect the force needed to climb up the sloped roof.
The slope of the roof is defined by the curve. The curvature of the curve is another important parameter that affects the force needed to climb up the roof. The worker needs to apply a force to counteract the force of gravity and move in the upward direction.
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A circuit has two resistors in parallel, each resistor is 6 ohms. This circuit is connected to a single resistor of 6 ohms, to form a series-parallel circuit. What is the total resistance of the circuit?
The tatal resistance of the series-parallel circuit with two resistor connected in parallel which combination is connected in series to a single resistor is 9 ohms.
What is a resistance?
This can be defined as the opposition to current flow in a circuit.
To calculate the total resistance, first we need to find the total resistance of the parallel resistor.
For parallel,
R' = (R₁R₂)/(R₁+R₂)............Equation 1Where:
R' = Total resistance of the parallel resistor.
From the question,
Given:
R₁ = 6 ohmsR₂ = 6 ohmsSubstitute these values into equation 1
R' = (6×6)(6+6)R' = 3 ohms.Finally, we combine the effective parallel resistance in series to the single resistance to the the total resistance of the circuit.
Rt = R'+R₃.................. Equation 2Where:
Rt = Total resistance of the circuit.From the question,
R' = 3 ohmsR₃ = 6 ohmsSubstitute these values into equation 2
Rt = 3+6Rt = 9 ohms.Hence, the total resistance of the circuit is 9 ohms.
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To change a logic gate to its alternate representation, a simple three-step process is followed. true or false
Given sentence: ''To change a logic gate to its alternate representation'' is False. Because to replace the gate with its opposite type (e.g. replace an AND gate with an OR gate, or a NAND gate with a NOR gate).
Logic is the study of correct reasoning. It includes both formal and informal logic. Formal logic is the science of deductively valid inferences
To change a logic gate to its alternate representation, a simple two-step process is followed:
Invert the output of the gate (change 1 to 0 or 0 to 1).
Replace the gate with its opposite type (e.g. replace an AND gate with an OR gate, or a NAND gate with a NOR gate).
There is no need for a third step.
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performing the drawing-in maneuver or bracing can do what?
The drawing-in maneuver and bracing techniques are used in various exercises such as squats, deadlifts, and overhead presses, to maintain proper form and alignment. They are also helpful for people with weak or injured core muscles, as they can help improve core strength, stability, and function.
Performing the drawing-in maneuver or bracing can activate the muscles of the transversus abdominis, multifidus, and pelvic floor. This will help increase intra-abdominal pressure, which is essential in maintaining a stable spine and reducing the risk of lower back pain and injury.
The drawing-in maneuver or bracing is a technique used to activate the deep core muscles that surround and stabilize the spine. It is an essential exercise for preventing and managing lower back pain.
The drawing-in maneuver works by activating the transversus abdominis, which is the deepest layer of abdominal muscles that lies beneath the rectus abdominis, internal oblique, and external oblique muscles. This muscle plays a crucial role in stabilizing the spine and pelvis, and improving posture and balance.
The bracing technique, on the other hand, involves contracting all the muscles around the midsection, including the transversus abdominis, multifidus, and pelvic floor muscles. This technique increases intra-abdominal pressure, which stabilizes the spine and reduces the risk of injury to the lower back.
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5. (5 points) Select ALL statements that are TRUE A. For flows over a flat plate, in the laminar region, the heat transfer coefficient is decreasing in the flow direction B. For flows over a flat plate, in the turbulence region, the heat transfer coefficient is decreasing in the flow direction C. For flows over a flat plate, the transition from laminar to turbulence flow only happens for rough surface D. For flows over a flat plate, if the length of the plate in the flow direction is long enough, the flows will inevitably become turbulent E. In general, turbulence flows have a larger heat transfer coefficient compared to laminar flows 6. (5 points) Select ALL statements that are TRUE A. For the flow in a pipe with constant cross-section area, both hydrodynamic and thermal boundary layer thicknesses increasingly grow in the flow direction B. In the hydrodynamic fully developed region, the mean velocity of the flow becomes constant C. In the thermally fully developed region, the mean temperature of the flow becomes constant D. For internal flows, if Pr>1, the flows become hydrodynamically fully developed before becoming thermally fully developed E. For internal flows, if Pr>1, the flows become thermally fully developed before becoming hydrodynamically fully developed
Answer:
The following statements are true:
A. For flows over a flat plate, in the laminar region, the heat transfer coefficient is decreasing in the flow direction
C. For flows over a flat plate, the transition from laminar to turbulence flow only happens for rough surface
E. In general, turbulence flows have a larger heat transfer coefficient compared to laminar flows 6.
Select ALL statements that are TRUE
B. In the hydrodynamic fully developed region, the mean velocity of the flow becomes constant
D. For internal flows, if Pr>1, the flows become hydrodynamically fully developed before becoming thermally fully developed
Explanation:
A carbon steel helical compression spring with squared and ground ends has an outside diameter of 0.85 in and a wire diameter of 0.074 in. The free length is 2 in, and the solid length is 0.618 in. Find the spring constant and the load required to compress the spring to the solid length.\
Solution :
Given :
d = diameter of the wire of the spring = 0.074 in
= 0.188 cm
R = mean radius of coil \($=\frac{0.85}{2}$\)
= 1.08 cm
G = modulus of rigidity of carbon steel wire = \($79 \ GN/m^2$\)
L = length of wire of spring = 2 inch
∴ L = 5.08 cm
k = spring constant
k = axial load/ axial deflection
\($k= \frac{Gd^4}{64R^3}$\) ..................(1)
This is taken from the Torsion equation,
\($\frac{T}{I_P}=\frac{\tau_{max}}{d/2}=\frac{G \theta}{2 \pi R}$\)
\($\frac{WR}{\frac{\pi}{32} d^4} = \frac{\tau_{max}}{d/2} =\frac{G \theta}{2 \pi R}$\)
∴ From equation (1)
\($k =\frac{79 \times 10^9 \times (0.188)^4 \times 10^{-8}}{64 \times (1.08)^3 \times 10^{-6}}$\)
\($k = 11334 \ N/m $\)
So the axial compression is \($ \delta =0.618 \ inch$\) = 1.57 cm
Axial load required W= k x δ
= 11334 x 1.57
= 177.95 N
deduce the relationship between e.m.u and e.s.u in technology .
In the CGS system, the unit of charge is the charging unit (ESU). Also known as "Statistical Pendant" (StatC). In the CGS system, the load unit is the electromagnetic unit (E.M.E.).
The e.s.u. of charge, also known as franklin or statcoulomb, is the charge such that two similar q=1statC charges at a space of 1cm from each other exert an electrostatic force of 1dyn on each other.
The e.m.u. of current, also called the biot or abampere, is the current such that two infinitely-long straight, parallel conductors carrying 1abA of current and separated by 1cm exert a magnetostatic force of 2dyn on each other.
The relations between these units are such that
\(\frac{1 statC}{1 abA * 1s} = \frac{1 statC}{1abC} = \frac{1}{C} = \frac{1 statA}{1abA} = \frac{\frac{1 statC}{s} } {1 abA}\)
where c is the speed of light.
The ESU and EMU systems of electromagnetic units are different and they should generally be considered separate and independent (if relatively similar), and they do not coincide with the gaussian set of electromagnetic units.
For example, since the electrical displacement vector D is defined as \(E + 4\pi P\) in the ESU system and \(\frac{1}{c^{2} } E + 4\pi P\) the EMU system, it is not possible to exchange the formulas of one system for another without using a formula dictionary like the one at Jackson's end. There is not. classical electrodynamics.
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The main processes of precipitation includes
A. The relative humidity and dewpoint processes
B. Collision Coalescence and Evaporation process
C. Collision/Coalescence and ice crystal process
Cloud types are categorized by height and time of day of occurrence.
A. True
B. False
The temperature of the air surrounding a water droplet and an ice crystal is the same.
To maintain equilibrium, the saturation vapor pressure surrounding the water droplet must be ___ the saturation vapor pressure surrounding the ice crystal.
A. impossible to determine
B. higher than
C. lower than
D. the same as
The main processes of precipitation include C) collision/coalescence and ice crystal processes.
Cloud types are categorized by height, but not necessarily time of day of occurrence.
In the collision/coalescence process, cloud droplets collide and combine to form larger droplets, which eventually become heavy enough to fall as precipitation. In the ice crystal process, ice crystals form in clouds at high altitudes and grow larger by collecting water vapor and other smaller ice crystals as they fall towards the ground.
Cloud types are primarily categorized by height, such as low clouds, mid-level clouds, and high clouds. While the time of day can affect cloud formation and development, it is not a primary factor in categorizing cloud types.
The temperature surrounding a water droplet and an ice crystal can be different, especially in a mixed-phase cloud where both water and ice coexist.
To maintain equilibrium, the saturation vapor pressure surrounding the water droplet must be higher than that surrounding the ice crystal, as the saturation vapor pressure over ice is lower than that over liquid water at the same temperature.
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A sinusoidal voltage source of v(t) = 170 cos (2 pi 60 t) V is applied to a nonlinear load, resulting in a nonsinusoidal current that is expressed in Fourier series form as i(t) = 10 cos(2 pi 60 t + 30 degree) + 6cos(4 pi 60 t + 45 degree) + 3cos(8 pi 60t + 20 degree) A. Determine (a) the power absorbed by the load. (b) the power factor of the load, (b) the distortion factor, and (d) the total harmonic distortion of the load current.
A) The power absorbed by the load is 1025.76 W. (b) The power factor of the load is 0.828, (c) The distortion factor is 0.849, and (d) The total harmonic distortion of the load current is 0.963.
What is harmonic distortion?Harmonic distortion is a form of distortion that occurs when an audio signal is amplified or played back through a system that is not capable of accurately reproducing the original signal. This distortion results in the addition of extra frequency components to the original signal, which are known as harmonics.
a) The power absorbed by the load is given by the equation:
P = Vrms × Irms, where Vrms and Irms are the root mean square values of the voltage and current respectively.
Vrms = 170/√2 = 120.71 V
Irms = √(10² + 6² + 3²)/2 = 8.49 A
P = 120.71 × 8.49 = 1025.76 W
b) The power factor of the load is the ratio of the real power to the apparent power.
Real power = 1025.76 W
Apparent power = 120.71 × √(10² + 6² + 3²) = 1235.73 VA
Power factor = 1025.76/1235.73 = 0.828
c) The distortion factor is the ratio of the root mean square value of the current to the fundamental component of the current.
Irms = 8.49 A
Fundamental component = 10 A
Distortion factor = 8.49/10 = 0.849
d) The total harmonic distortion (THD) is given by the equation:
THD = √((a2 + b2 + c2 + ...)/a2)
Where a, b and c are the amplitudes of the harmonic components.
THD = √((10² + 6² + 3²)/10²) = 0.963
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A rectangular wing of aspect ratio 10 is flying at a Mach number of 0.6. What is the approximate value of 〖dC〗_L/da? Compare the result with that of Problem 6.7.3, which applied to the same wing in incompressible flow.
The approximate value of 〖dC〗_L/da for the rectangular wing of aspect ratio 10 flying at a Mach number of 0.6 is around 0.6. This is because at this Mach number, the flow over the wing begins to compress, causing changes in the lift coefficient.
When compared to Problem 6.7.3, which applies to the same wing in incompressible flow, the value of 〖dC〗_L/da will be different. In incompressible flow, the value of 〖dC〗_L/da is solely dependent on the wing's geometry and is not affected by the Mach number. Therefore, the value of 〖dC〗_L/da in incompressible flow will be different from that in compressible flow.
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The approximate value of \(〖dC〗_L/da is 0.146.\) The result with that of Problem 6.7.3, of \(〖dC〗_L/da\) in compressible flow is significantly lower than that in incompressible flow. This is due to the reduction in lift coefficient caused by the compressibility effects at high speeds.
To calculate the value of \(〖dC〗_L/da\), we can use the Prandtl-Glauert rule, which accounts for the effects of compressibility on lift. This rule states that the lift coefficient in compressible flow is related to the lift coefficient in incompressible flow (denoted by C_L) by the following equation:
\(C_L = C_L,incompressible / √(1 - M^2)\)where M is the Mach number.
The derivative of lift coefficient with respect to angle of attack is given by:
\(dC_L/da = d(C_L,incompressible/√(1-M^2))/da\)
Using the chain rule of differentiation, we get:
\(dC_L/da = 1/√(1-M^2) * dC_L,incompressible/da + C_L,incompressible/(2*(1-M^2)^(3/2)) * d(1-M^2)/da\)
Since the wing has an aspect ratio of 10, we can use the formula for the lift coefficient of a rectangular wing in incompressible flow:
\(C_L,incompressible = π*AR/(1+√(1+(AR/2)^2))\)
where AR is the aspect ratio.
Substituting the given values, we get:
AR = 10
M = 0.6
\(C_L,incompressible = π*10/(1+√(1+25)) ≈ 1.23\)
Differentiating the formula for C_L,incompressible with respect to angle of attack, we get:
\(dC_L,incompressible/da = π/(2*(1+√(1+25))^2)\)
Substituting the values in the expression for\(dC_L/da\), we get:
\(dC_L/da ≈ 1/√(1-0.6^2) * π/(2*(1+√(1+25))^2) + 1.23/(2*(1-0.6^2)^(3/2)) * (-2*0.6)≈ 0.146\)
Therefore, the approximate value of \(〖dC〗_L/da is 0.146.\)
Comparing this with Problem 6.7.3, which applied to the same wing in incompressible flow, we can see that the value of \(〖dC〗_L/da\)in incompressible flow is simply given by the formula:
\(dC_L/da = 2π/AR\)
Substituting the given values, we get:
\(dC_L/da = 2π/10 = 0.628\)
Thus, we can see that the value of \(〖dC〗_L/da\) in compressible flow is significantly lower than that in incompressible flow. This is due to the reduction in lift coefficient caused by the compressibility effects at high speeds.
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4. Which type of duct undergoes more rigorous testing before it's labeled?
Answer:
Flexible duct
Explanation:
it is flexible duct due to current flow
Select all the correct answers. What are two reasons why the terrestrial planets formed closer to the sun after a supernova event that initiated the formation of the solar system?
What can be defined as the planning, coordination, and communications functions that are needed to resolve an incident in an efficient manner?
Incident handling can be defined as the planning, coordination, and communications functions that are needed to resolve an incident efficiently.
What is incident handling?In the areas of computer protection and transmission technology, computer safety incident surveillance involves the monitoring and detection of security occurrences on a computer or computer network and the execution of proper answers to those circumstances. Especially, a happening reaction process is an assemblage of strategies aimed at identifying, analyzing, and responding to potential security happenings in a way that underestimates impact and supports rapid comeback. Incident handling is a systematic set of recovery tactics for the restoration of organizational security. Given that adversaries have already damaged the institution's protection, this healing is always time-critical and usually stressful.To learn more about Incident handling, refer to:
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2.5 a young engineer is asked to design a thermal protection barrier for a sensitive electronic device that might be exposed to irradiation from a high-powered infrared laser. having learned as a student that a low thermal conductivity material provides good insulating characteristics, the engineer specifies use of a nanostructured aerogel, characterized by a thermal conductivity of ka
The engineer chooses nanostructured aerogel with a low thermal conductivity to create an effective thermal protection barrier that can insulate the sensitive electronic device from the irradiation of the high-powered infrared laser.
The young engineer has been tasked with designing a thermal protection barrier for a sensitive electronic device that may be exposed to irradiation from a high-powered infrared laser.
The engineer has learned that materials with low thermal conductivity provide good insulation.
In this case, the engineer specifies the use of a nanostructured aerogel with a thermal conductivity of "ka".
Nanostructured aerogel is an excellent choice for thermal insulation due to its low thermal conductivity.
This means that it can effectively reduce the transfer of heat from the laser irradiation to the sensitive electronic device. The "ka" value represents the specific thermal conductivity of the aerogel, which indicates how well it can resist the flow of heat.
The lower the "ka" value, the better the insulation properties of the aerogel.
By using nanostructured aerogel as the thermal protection barrier, the engineer ensures that the sensitive electronic device is shielded from the potentially damaging effects of the laser's irradiation.
This helps to maintain the device's performance and integrity, preventing any potential overheating or malfunction.
In summary, the engineer chooses nanostructured aerogel with a low thermal conductivity to create an effective thermal protection barrier that can insulate the sensitive electronic device from the irradiation of the high-powered infrared laser.
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Which of the following sensors is used to provide suspension control module with feedback regarding vehicle cornering forces?
Question content area bottom
Part 1
A.
lateral accelerometer sensor
B.
vehicle speed sensor
C.
yaw rate sensor
D.
pressure sensor
Answer:
A
Explanation:
Define the limitations in the operation conditions of a P-N junction
Answer:
1. Maximum forward current
2. Peak inverse voltage
3. Maximum power rating
Explanation:
The limitations in the operations of a P-N junction are as stated below.
Every P-N junction has limiting values and will give better performance if operated within this values, and if this values are exceeded the P-N junction may be destroyed
1. Maximum forward current: the highest instantaneous current the P-N junction can conduct without being destroyed
2. Peak inverse voltage: the maximum reserve voltage that can be applied without destroying the P-N junction
3. Maximum power rating: the maximum power that can be dissipated at the junction without damaging it
An organization sets its standards for quality according to the best product it can produce.
True
False
Answer:
True!! took the test
Explanation:
5. The maximum scaffold height not requiring toeboards is 20 feet.
A. True
B. False
A continuous function y = ƒ(x) is known to be negative at x = 0 and positive at x = 1. Why does the equation ƒ(x) = 0 have at least one solution between x = 0 and x = 1? Illustrate with a sketch
Answer:
69
Explanation:
69420=420659782
fjkdod
Large wind turbines with blade span diameters of over 100 m are available for electric power generation. Consider a wind turbine with a blade span diameter of 100 m installed at a site subjected to steady winds at 8 m/s. Taking the overall efficiency of the wind turbine to be 32 percent and the air density to be 1.25 kg/m3 , determine the electric power generated by this wind turbine. Also, assuming steady winds of 8 m/s during a 24-hour period, determine the amount of electric energy and the revenue generated per day for a unit price of $0.09/kWh for electricity
Answer:
The wind turbine generates \(19297.222\) kilowatt-hours of electricity daily.
The wind turbine makes a daily revenue of 1736.75 US dollars.
Explanation:
First, we have to determine the stored energy of wind (\(E_{wind}\)), measured in Joules, by means of definition of Kinetic Energy:
\(E_{wind} = \frac{1}{2}\cdot \dot m_{wind}\cdot \Delta t \cdot v_{wind}^{2}\) (Eq. 1)
Where:
\(\dot m_{wind}\) - Mass flow of wind, measured in kilograms per second.
\(\Delta t\) - Time in which wind acts in a day, measured in seconds.
\(v_{wind}\) - Steady wind speed, measured in meters per second.
By assuming constant mass flow and volume flows and using definitions of mass and volume flows, we expand the expression above:
\(E_{wind} = \frac{1}{2}\cdot \rho_{air}\cdot \dot V_{air} \cdot \Delta t \cdot v_{wind}^{2}\) (Eq. 1b)
Where:
\(\rho_{air}\) - Density of air, measured in kilograms per cubic meter.
\(\dot V_{air}\) - Volume flow of air through wind turbine, measured in cubic meters per second.
\(E_{wind} = \frac{1}{2}\cdot \rho_{air}\cdot A_{c}\cdot \Delta t\cdot v_{wind}^{3}\) (Eq. 2)
Where \(A_{c}\) is the area of the wind flow crossing the turbine, measured in square meters. This area is determined by the following equation:
\(A_{c} = \frac{\pi}{4}\cdot D^{2}\) (Eq. 3)
Where \(D\) is the diameter of the wind turbine blade, measured in meters.
If we know that \(\rho_{air} = 1.25\,\frac{kg}{m^{3}}\), \(D = 100\,m\), \(\Delta t = 86400\,s\) and \(v_{wind} = 8\,\frac{m}{s}\), the stored energy of the wind in a day is:
\(A_{c} = \frac{\pi}{4}\cdot (100\,m)^{2}\)
\(A_{c} \approx 7853.982\,m^{2}\)
\(E_{wind} = \frac{1}{2}\cdot \left(1.25\,\frac{kg}{m^{3}} \right) \cdot (7853.982\,m^{2})\cdot (86400\,s)\cdot \left(8\,\frac{m}{s} \right)^{3}\)
\(E_{wind} = 2.171\times 10^{11}\,J\)
Now, we proceed to determine the quantity of energy from wind being used by the wind turbine in a day (\(E_{turbine}\)), measured in joules, with the help of the definition of efficiency:
\(E_{turbine} = \eta\cdot E_{wind}\) (Eq. 4)
Where \(\eta\) is the overall efficiency of the wind turbine, dimensionless.
If we get that \(E_{wind} = 2.171\times 10^{11}\,J\) and \(\eta = 0.32\), then the energy is:
\(E_{turbine} = 0.32\cdot (2.171\times 10^{11}\,J)\)
\(E_{turbine} = 6.947\times 10^{10}\,J\)
The wind turbine generates \(6.947\times 10^{10}\) joules of electricity daily.
A kilowatt-hours equals 3.6 million joules. We calculate the equivalent amount of energy generated by wind turbine in kilowatt-hours:
\(E_{turbine} = 6.947\times 10^{10}\,J\times\frac{1\,kWh}{3.6\times 10^{6}\,J}\)
\(E_{turbine} = 19297.222\,kWh\)
The wind turbine generates \(19297.222\) kilowatt-hours of electricity daily.
Lastly, the revenue generated per day can be found by employing the following:
\(C_{rev} = c\cdot E_{turbine}\) (Eq. 5)
Where:
\(c\) - Unit price, measured in US dollars per kilowatt-hour.
\(C_{rev}\) - Revenue generated by the wind turbine in a day, measured in US dollars.
If we know that \(c = 0.09\,\frac{USD}{kWh}\) and \(E_{turbine} = 19297.222\,kWh\), then the revenue is:
\(C_{rev} = \left(0.09\,\frac{USD}{kWh} \right)\cdot (19297.222\,kWh)\)
\(C_{rev} = 1736.75\,USD\)
The wind turbine makes a daily revenue of 1736.75 US dollars.
What materials were used in the construction of Colorado Capitol HIll?
Answer Designed by Elijah E. Myers, it was constructed in the 1890s from Colorado white granite, and opened for use in November 1894. The distinctive gold dome consists of real gold leaf, first added in 1908, commemorating the Colorado Gold Rush.
Location: 200 East Colfax Avenue; Denver, Co...
Part of: Denver Civic Center (ID12001017)
Built: 1886–1901
Added to NRHP: October 16, 2012
Explanation:
\(2x - 14x = 10\)
Answer:
-10/12 = -5/6
Explanation:
2x - 14x = 10
- 12x = 10
x = -10/12
x = -5/6
Consider a carbon fiber reinforced epoxy composite. The fibers are continuous, unidirectionally aligned and 40% by volume. The tensile strength of carbon fibers is 2998 MPa, and the Young's modulus is 214 GPa. The tensile strength of the epoxy matrix is 100 MPa, and its Young's modulus is 3 GPa.
Required:
a. Compute the Young's modulus and the tensile strength of the composite in the longitudinal direction.
b. What is Young's modulus in the longitudinal direction?
Answer:
- the Young's modulus of the composite in the longitudinal direction = 87.4GPa.
- The tensile strength of the composite in the longitudinal direction = 1.26 × 10⁹.
Explanation:
The following parameters or data were given in this particular question/problem;
1. "The fibers are continuous, unidirectionally aligned and 40% by volume."
2." The tensile strength of carbon fibers is 2998 MPa, and the Young's modulus is 214 GPa."
3. " The tensile strength of the epoxy matrix is 100 MPa, and its Young's modulus is 3 GPa."
So, let us delve right into the solution to this question:
[ kindly note that part b. of this problem is the same as the part a. of the problem
Also, in point 2. above 2998MPa = 2.998 =GPa, approximately 3GPa].
40% = 40/100 = 0.4. Therefore, 1 - 0.4 = 0.6. Hence, the Young's modulus of the composite in the longitudinal direction = 3 × 0.6 + 214 × 0.4 = 1.8 + 85.6 = 87.4GPa
The tensile strength of the composite in the longitudinal direction = 100 × 10⁶ × 0.6 + 3 × 10⁹ ₓ 0.4 = 1.26 × 10⁹.
air carries face _____ competition from surface modes for either freight or passengers.
Air carriers face stiff competition from surface modes for either freight or passengers.
Surface modes of transportation, such as road and rail, pose significant competition to air carriers in terms of both freight and passenger transportation. These surface modes offer their own advantages, including lower costs, extensive networks, and accessibility to various locations.
For freight transportation, surface modes provide cost-effective options for shipping goods over shorter distances or to destinations with well-developed road and rail networks. Many businesses opt for surface transportation for their freight needs, especially when time-sensitive delivery is not a primary concern.
Similarly, for passenger travel, surface modes offer viable alternatives to air travel, particularly for shorter distances or when the destination is well-connected by road or rail. Commuters and travelers often choose surface transportation for its convenience, affordability, and flexibility in terms of routes and schedules.
While air transportation has its unique advantages, such as speed and long-distance connectivity, it faces fierce competition from surface modes due to their lower operating costs and accessibility to a wider range of destinations. Air carriers must continuously innovate and improve their services to remain competitive and attract customers who prioritize the speed and convenience of air travel.
In conclusion, air carriers encounter significant competition from surface modes of transportation for both freight and passenger services. The choice between air and surface transportation depends on various factors, including distance, cost considerations, time constraints, and the specific needs of shippers and travelers.
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True or false To fasten a duct hanger to a gypsum board wall, the best fastener would be an anchor shield
The given statement of "To fasten a duct hanger to a gypsum board wall, the best fastener would be an anchor shield" is false.
Why is the above statement false?Anchor shields are typically used to secure objects to concrete or masonry walls.
For fastening a duct hanger to a gypsum board wall, the best fastener would be a toggle bolt or a self-drilling drywall screw. These fasteners are specifically designed for use in drywall and can provide a secure hold for the duct hanger.
Therefore, one can say that Anchor shields may not provide a secure hold in drywall, as they are designed for use in masonry or concrete.
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Greek engineers had the unenviable task of moving largecolumns from the quarries to the city.One engineer,Chersiphron, tried several different techniques to do this. Onemethodwas to cut pivot holes into the ends of the stone andthen use oxen to pull the column. The 5-ft diameter columnweighs 14,000 lbs, andthe team of oxen generates a constantpull force of 2,000 lbs on the center of the cylinder,G. Knowingthat the column starts from rest and rolls without slipping,determine:(a) the velocity of its center,G,after it has moved7ft,and (b) the minimum static coefficient of friction that will keepit from slipping.
Answer:
yea
Explanation:
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One kilogram of air as an ideal gas executes a Carnot power cycle having a thermal efficiency of 50%. The heat transfer to the air during the isothermal expansion is 50 kJ. At the end of the isothermal expansion, the pressure is 574 kPa and the volume is 0.3 m3. Determine
(a) the maximum and minimum temperatures for the cycle in K;
(b) the pressure and volume at the beginning of the isothermal expansion in bar and m3 respectively;
(c) the work and heat transfer for each of the four processes in kJ.
Answer:
(a) the maximum and minimum temperatures for the cycle in K;
Maximum temprature = T1 = 600.05K
Minimum temprature = 300.03K
(b) the pressure and volume at the beginning of the isothermal expansion in bar and m3 respectively;
Pressure (P4) = 0.67842 bar
Volume (V4) = 1.2693\(m^{3}\)
(c) the work and heat transfer for each of the four processes in kJ.
\(W_{4-1}\) = -215.25 kJ
The answers are clearly explained in the below mentioned document.
Explanation:
Kindly download the below mentioned document, I have explained in quite detail in it. I hope it will help. Thanks.