The average power output of the sun will be 3.8 x 10²⁶ W
As
Power = energy / time eq (1)
And, Intensity = energy / area x time eq (2) From eq (1) & eq (2), we get
Intensity= Power / Area
So Power =intensity x area
And the area is 4πr²
i.e = surface area of sphere and radius of earth = r = 149.6 × 10⁹ m
A = 4 x 3.14 x (149.6 x 10⁹)²
A = 2.81 x 10²³ m²
And Power will be
P = 1350 x 2.81 x 10²³
So we will get
P = 3.8 x 10²⁶ W
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4. A carousel has a radius of 4 meters & turns at a rate of 1 revolution every 10 seconds. Allen is riding a horse on the edge of the carousel. Beth is riding a horse 2 meters from the center of the carousel.
a) What is Allen’s angular speed in rad/s?
b) What is Beth’s angular speed in rad/s?
c) What is Allen’s linear speed in m/s?
d) What is Beth’s linear speed in m/s?
plz answer on each a,b,c,d Questions
thanks
(a) The angular speed of Allen is 0.628 rad/s.
(b) The angular speed of Beth is 0.628 rad/s.
(c) The linear speed of Allen is 2.512 m/s.
(d) The linear speed of Beth is 1.256 m/s.
The given parameters;
radius of the carousel, r = 4 mspeed, ω = 1 rev per 10 secondsposition of Allen from the center of the carousel, r = 4 mposition of Beth from the center of the carousel, r = 2 mThe angular speed of Allen is calculated as follows;
\(\omega = \frac{1 \ rev}{10 \ s} \times \frac{2\pi \ rad}{1 \ rev} \\\\\omega = 0.628 \ rad/s\)
The angular speed of Beth is calculated as follows;
\(\omega = \frac{1 \ rev}{10 \ s} \times \frac{2\pi \ rad}{1 \ rev} \\\\\omega = 0.628 \ rad/s\)
Allen and Beth make the same number of revolutions every 10 seconds, hence their angular speed is the same.
The linear speed of Allen is calculated as follows;
\(v = \omega r\\\\v = 0.628 \ rad/s \times 4 \ m\\\\v = 2.512 \ m/s\)
The linear speed of Beth is calculated as follows;
\(v = \omega r\\\\v = 0.628 \ rad/s \times 2 \ m\\\\v = 1.256 \ m/s\)
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This is the energy needed to drive photosynthesis.
SOMEONE HELP ME!!!!!!
Answer: The process of photosynthesis is broken up into two main groups of reactions: the "light reactions" which require light energy to operate, and the "Calvin cycle" which specifically takes carbon dioxide and turns it into organic molecules.
Explanation: Hope it helped you! :)
the thermodynamic processes that occur in nature ____________.
Answer:
The thermodynamic processes that occur in nature convert thermal energy into mechanical energy.
The thermodynamic processes that occur in nature are according to the law of thermodynamics.
The thermodynamics processes seen in nature are guided by the law of thermodynamics. The role of energy and heat transmission in physical systems is guided by these laws.
The laws are:
(1) Energy cannot be created nor destroyed in a system, according to the first law of thermodynamics, Also, referred to as the law of energy conservation. Only from one form to another, the energy can be transmitted or altered. Energy is conserved through natural processes, keeping the overall amount constant.
(2) Second law of thermodynamics: states that the overall entropy of an isolated system tends to increase over time in any natural process. This suggests that processes progress towards a state of increasing disorder.
Hence, the thermodynamic processes are guided by the law of thermodynamics.
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you walk 5 mi south, 12mi west 15mi north and 7mi north of west at 20 degrees. graphically find the resultant vector
Net ebony x-axis. ∅ ≈ 2° west of north.
= Rx = 5+ 7 cos 20° - 12
= -0.42 mi
Now, -axis y axis
Ry = 7 Sin 20° +15 - 5
= 12.39 mi
= \(\sqrt{Rx^{2} + R}y^{2}\) = \(\sqrt{(0.42)^{2} + (12.39)^{2} }\)
IRI = 12.40 mi
Its direction:
tan ∅ = Rx/Ry west of North Ry
∅ = \(tan^{-1}\)(0.42/12.39)
∅ = 1.94° west of north
∅ ≈ 2° west of north.
In the graphical method of adding vectors A and B, the vectors are drawn on the graph and added from head to tail. The resulting vector R is defined as A + B = R. The magnitude and direction of R are determined using a ruler and protractor, respectively. Draw the vectors so that their starting points coincide. Then draw a line to make a perfect parallelogram.
The diagonal from the starting point of the parallelogram to the opposite vertex is the result. GRI allows users to graphically display the detailed results of technical and economic analysis of a project. Hybrid2 uses two types of simulation models. One is for long-term performance prediction called the logistic model.
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Why is it important to have a closed circuit?
A. It prevents a circuit from working.
B. It prevents components from overheating.
C. It increases the resistance in the circuit.
D. It allows an electric current in the circuit.
D. It allows the flow of an electric current in the circuit.
Why is it important to have a closed circuit?Closed circuit allows the flow of current in the circuit from the battery to the bulb. If the circuit is open then the current will not reach to the bulb or other appliances.
So we can conclude that It is important to have a closed circuit because it allows the flow of an electric current in the circuit.
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Help! will give brainliest!
Answer:
I would say increasing the balls kinetic energy
Explanation:
Because she is moving the ball and increasing kinetic energy
PLEASE HELP AND HURRRRY
A package is dropped from a plane flying at a constant speed. Neglecting air resistance, when the package hits the ground the horizontal location of the plane will....
A. Be behind the package
B. Depend on speed of package
C. Be directly over the package
D. Be in front of the package
Answer:
A. Be behind the package
What is the equation that shows the inverse relationship between wavelength and frequency?
Answer:
V = f * λ velocity equals frequency * wavelength
If f is increased then λ must decrease for the velocity to remain constant.
A small car and a large heavier bus are traveling at the same speed. Which has more momentum?
Answer:
small car since they weigh less than a bus
Explanation:
A force of 24 N will stretch a rubber band 12 cm(0.12 m) Assuming that Hooke's faw applies, how lar will a 20 - N lorce stretch the rubber band? How much wokk does if take fo stretch the nubber band this far? How lar will a 20.N torce stretch the rubber band? B) (Sirnplify your answed) How mach work does ia take la stretch the rubber band this far? (Stmplify your answer)
Work required to stretch the rubber band by 0.10 meters will be negative, indicating that work needs to be done against the force applied to stretch the rubber band.
To determine how much the rubber band will stretch under a 20 N force and the work required to stretch it, we need to apply Hooke's Law. Hooke's Law states that the force applied to a spring or elastic material is directly proportional to the displacement it undergoes.
We can set up a proportion to find the stretch under Force 2:
(F1 / S1) = (F2 / S2)
Substituting the given values:
(24 N / 0.12 m) = (20 N / S2)
To find S2, we can rearrange the equation:
S2 = (20 N * 0.12 m) / 24 N
Simplifying:
S2 = 0.10 m
Therefore, a 20 N force will stretch the rubber band by 0.10 meters.
Now, let's calculate the work required to stretch the rubber band this far. The work (W) can be calculated using the formula:
W = (1/2) * k * (S2^2 - S1^2)
Where k is the spring constant.
However, we don't have the spring constant (k) given in the problem. So, we cannot determine the exact work without that information.
But, if we assume that the rubber band behaves as a linear spring and Hooke's Law applies, we can simplify the equation. Hooke's Law states that the force applied to a spring is equal to the spring constant (k) multiplied by the displacement (S).
F = k * S
Rearranging the equation:
S = F / k
Since the stretch (S) is directly proportional to the force (F), we can approximate the work required by assuming a constant k value:
W ≈ (1/2) * k * (S2^2 - S1^2)
W ≈ (1/2) * k * [(0.10 m)^2 - (0.12 m)^2]
Simplifying:
W ≈ (1/2) * k * (0.01 m^2 - 0.0144 m^2)
W ≈ (1/2) * k * (-0.0044 m^2)
Without the exact value of the spring constant, we cannot calculate the work precisely. However, we can still conclude that the work required to stretch the rubber band by 0.10 meters will be negative, indicating that work needs to be done against the force applied to stretch the rubber band.
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if you 235lb traviling north at 75mph and strike a 150 lb deer going 35mph east what is the force
We need to use the formula: Force = Mass × Acceleration Let's use the given values to calculate the force exerted on the deer when it is hit by the car. The car weighs 235 lb and it is traveling north at 75 mph. The deer weighs 150 lb and it is going 35 mph east. Force = 44045 lbSince the force is a vector quantity, it has both magnitude and direction.
Step 1: Convert the velocities into feet per second.1 mile = 5280 feet1 hour = 3600 seconds So, the velocity of the car is:75 mph = (75 × 5280) ÷ 3600 = 110 feet/secondThe velocity of the deer is:35 mph = (35 × 5280) ÷ 3600 = 51.3 feet/second
Step 2: Find the components of velocity of the deer. The velocity of the deer is in the east direction, so we need to find its horizontal component, vx, and its vertical component, vy. If the angle between the deer's velocity and the x-axis is θ, then: vx = v × cosθandvy = v × sinθv = 51.3 feet/secondθ = 90° - arctan(0 / 110) = 90°So,vx = 51.3 × cos90° = 0 feet/second vy = 51.3 × sin90° = 51.3 feet/second
Step 3: Find the net velocities of the car and the deer. Since the car is moving north and the deer is moving east, the net velocity of the car and deer together can be found using the Pythagorean theorem. Net velocity = √[(vx + 110)² + vy²]Net velocity = √[(0 + 110)² + (51.3)²]Net velocity = √(12100 + 2631.69)Net velocity = √14731.69Net velocity = 121.3 feet/second
Step 4: Find the net momentum of the car and the deer. Net momentum = (mass of car × velocity of car) + (mass of deer × velocity of deer)Net momentum = (235 × 110) + (150 × 121.3)Net momentum = 25850 + 18195Net momentum = 44045 lb ft/second
Step 5: Find the force exerted on the deer. Force = Net momentum ÷ time Here, time is the duration of the collision which is not given in the problem. We will assume it to be 1 second. Force = 44045 ÷ 1
Force = 44045 lb Since the force is a vector quantity, it has both magnitude and direction. The direction of force is along the line of impact which is not given in the problem.
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A cassette player is said to have a signal-to-noise ratio of 62 dB, whereas for a CD player, it is 98 dB. What is the ratio of intensities of the signal and the background noise for each device?
1. 1.6 x 10^6
2. 6.3 x 10^9
For the cassette player, the ratio of intensities of signal and noise is approximately 1.6 x 10^6, while for the CD player, it is about 6.3 x 10^9.
Signal-to-noise ratio (SNR) is a measure of the relative amount of desired signal and unwanted background noise in a system. It is usually expressed in decibels (dB). The higher the SNR, the better the quality of the signal.
To calculate the ratio of intensities of signal and noise for each device, we first need to convert the SNR from decibels to a ratio. This can be done using the following formula:
SNR (in dB) = 10 log (signal-to-noise ratio)
Using this formula, we get:
For the cassette player:
62 dB = 10 log (signal-to-noise ratio)
Signal-to-noise ratio = 10^(62/10) = 1.6 x 10^6
For the CD player:
98 dB = 10 log (signal-to-noise ratio)
Signal-to-noise ratio = 10^(98/10) = 6.3 x 10^9
The ratio of intensities of signal and noise is simply the signal-to-noise ratio expressed as a ratio, rather than in decibels. Therefore, the ratio of intensities for the cassette player is approximately 1.6 x 10^6, while for the CD player, it is about 6.3 x 10^9. This means that the CD player has a much higher ratio of signal to noise, which results in a better quality sound compared to the cassette player.
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Write 5 advantages of electricity.
Answer:
Quick, Efficient, Reliable, Safe and Continous
Answer:
Five advantages of electricity are :Advantages
It is transportable over long distances
It is silent
It can be used produce magnetic fields, which can be used to propel motors
It is very transformable
It is very fast, virtually the speed of light
It can be used to produce other forms of radiant energy, such as radio waves, microwaves, radiant heat and light
List 2 examples of physical properties that don't
change if the sample size changes.
Answer:
Temperature, density
Explanation:
Physical properties of a substance are those properties that do not change the chemical composition of the substance. There are two types of physical properties namely: intensive property and extensive property.
Intensive properties are those physical properties that does not depend on the sample size of the substance involved. Examples of intensive physical properties are temperature, density, boiling point. For example, the size or amount of a substance does not determine the the TEMPERATURE or BOILING POINT of the substance.
An alien spaceship is 300 m above the ground and moving at a constant velocity of 250 m/s upwards. How high above the ground is the ship after 3 seconds?
Answer: 1050 m
Explanation: 300 + 250x3 = 1050.
A plant expansion is planned for City of Beaumont. The new design flow rate is 1.2 m³/s. A deep bed monomedia filter with a design loading rate of 575 m³/d. m² of filter is to be used. If each filter box is limited to 50 m² of surface area, how many filter boxes will be required? Check the design loading with one filter box out of service. Propose an alternative design if the design loading rate is exceeded with one filter box out of service.
One filter box will be required for the plant expansion, but an alternative design needs to be proposed if the design loading rate is exceeded with one filter box out of service.
To determine the number of filter boxes required, we need to calculate the total surface area required and divide it by the maximum surface area per filter box.
Calculate the total surface area required:
Total surface area = Design flow rate / Design loading rate
Total surface area = 1.2 m³/s × 24 × 3600 s / (575 m³/d × 1 d/24h)
Total surface area = 18.67 m²
Determine the number of filter boxes required:
Number of filter boxes = Total surface area / Maximum surface area per filter box
Number of filter boxes = 18.67 m² / 50 m²
Number of filter boxes = 0.37 (round up to the nearest whole number)
Number of filter boxes = 1 (since we cannot have a fraction of a filter box)
Therefore, one filter box will be required to meet the design loading rate.
To check the design loading with one filter box out of service, we need to recalculate the loading rate:
Calculate the new design loading rate:
New design loading rate = Design flow rate / (Number of filter boxes - 1)
New design loading rate = 1.2 m³/s / (1 - 1)
New design loading rate = Undefined
Since the new design loading rate is undefined when one filter box is out of service, an alternative design should be proposed to ensure that the design loading rate is not exceeded. This could involve increasing the number of filter boxes or redesigning the filtration system to accommodate the required flow rate.
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You drop a 5 kg ball from a height of 2 m. Just
before it reaches the ground, how much kinetic
energy does it have?
Answer:
Kinetic energy = 98 N
Explanation:
Given:
Mass = 5 kg
Height = 2 m
Find:
Kinetic energy
Computation:
K(e) = P(e)
So,
P(e) = mgh
So,
K(e) = (5)(9.8)(2)
Kinetic energy = 98 N
For steady isothermal flow of a compressible gas in a pipeline, the mass flow rate is proportional to the pressure drop
T/F
The statement "For steady isothermal flow of a compressible gas in a pipeline, the mass flow rate is proportional to the pressure drop" is false because it is not directly proportional as it also depends on the density, cross-sectional area, and velocity of the gas.
This relationship can be better understood through the application of the continuity equation and the ideal gas law.
The continuity equation states that the mass flow rate (m_dot) is equal to the product of the density (ρ), cross-sectional area (A), and velocity (v) of the gas:
m_dot = ρAv
In compressible flow, the gas density changes along the pipeline, and the ideal gas law (PV=nRT) is used to describe the relationship between pressure (P), volume (V), and temperature (T) for a given amount of gas (n) and the gas constant (R). Since the flow is isothermal, the temperature remains constant throughout the process.
By combining the continuity equation and the ideal gas law, the relationship between the mass flow rate and pressure drop can be determined. However, this relationship is not directly proportional, as it also depends on the density, cross-sectional area, and velocity of the gas. The pressure drop in the pipeline will affect the gas density, and therefore influence the mass flow rate, but the two are not directly proportional.
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A jet airliner moving initially at 103 mph (with respect to the ground) to the east moves into a region where the wind is blowing at 441 mph in a direction 19° north of east. What is the new speed of the aircraft with respect to the ground?
The new speed with respect to the ground is 512 m/h.
What is speed?We can tell that is speed is the rate at which the velocity changes with respect to time. In this case, we can see that the jet airliner moving initially at 103 mph (with respect to the ground) to the east moves into a region where the wind is blowing at 441 mph in a direction 19° north of east.
Hence;
→ The east component = 103 + 441 cos(52) = 375 m/h
→ The north component = 441 sin(52) = 348 m/h
We can now get the new velocity by the use of;
√( 375)^2 + (348)^2 =
= 512 m/h
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What are the energy transformations that occur during a roller coaster ride? 1 paragraph
Answer:
The movement of a roller coaster is accomplished by the conversion of potential energy to kinetic energy. The roller coaster cars gain potential energy as they are pulled to the top of the first hill. As the cars descend the potential energy is converted to kinetic energy. Roller coasters rely on gravity to take them to the end of the track. This involves two types of energy, potential energy and kinetic energy.
Explanation: my mom told me lol ..
Answer:
The movement of a roller coaster is accomplished by the conversion of potential energy to kinetic energy. The roller coaster cars gain potential energy as they are pulled to the top of the first hill. As the cars descend the potential energy is converted to kinetic energy.
Explanation:
That's gonna help right?
When solute is actively transported across epithelium, what usually follows?A) water movement in the opposite directionB) water movement in the same directionC) active transport of the solute in the opposite directionD) passive transport of the solute in the opposite directionE) passive transport of solute in the same direction
When a solute is actively transported across epithelium, the usual follow-up is A) water movement in the opposite direction.
Active transport refers to the process in which substances, such as ions or molecules, are moved across a cell membrane against their concentration gradient, requiring the expenditure of energy. When solute is actively transported across an epithelium, it creates an osmotic gradient across the membrane.
Osmosis is the movement of water molecules across a selectively permeable membrane from an area of lower solute concentration to an area of higher solute concentration. In this case, since the solute is actively transported, it is being moved from an area of lower concentration to an area of higher concentration. As a result, water tends to move in the opposite direction, from an area of higher water concentration (lower solute concentration) to an area of lower water concentration (higher solute concentration).
Therefore, when a solute is actively transported across epithelium, the usual consequence is water movement in the opposite direction, as indicated by option A.
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A constant unbalanced force is applied to an object for a period of time. What will happen to the objects acceleration?
a. It will accelerate in the direction of the net force.
b. It will accelerate opposite the direction net force.
c. There is no acceleration.
d. Not enough information to answer
Answer:
A
Explanation:
The moving object will accelerate as long as a net force is applied. If a net force is not applied, the object will continue to move at a constant speed along the same path in curved spacetime (due to gravity). If the net force continues the velocity of the object will continue to increase until nearly reaching the limit (speed of light).
an iron ball with mass 180 g is attached to a chain that is 1.2 m long, suspended at an angle of 55 degrees. the iron ball is then released from this position and at the very bottom of its swing, it strikes a 450 g block of wood that is resting on a frictionless surface. to what angle does it rebound
The iron ball will rebound at an angle of approximately 55 degrees.
When the iron ball is released and swings downward, it gains kinetic energy as it moves towards the bottom of its swing. At the very bottom, this kinetic energy is transferred to the block of wood, causing it to move. According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision.
Initially, the iron ball and the block of wood are at rest, so their initial momentum is zero. At the bottom of the swing, when the iron ball collides with the block of wood, their combined momentum will still be zero. Since the iron ball is much heavier than the block of wood, its velocity will decrease significantly after the collision, while the block of wood will acquire some velocity.
Now, let's consider the angles involved. The initial angle of suspension, 55 degrees, represents the angle between the chain and the vertical direction. When the iron ball reaches the very bottom of its swing, it will be momentarily at rest before the collision. At this point, the direction of its velocity is perpendicular to the chain, forming a right angle with the vertical direction. Therefore, the angle at which it rebounds will be the same as the angle of suspension, approximately 55 degrees.
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Gabriella is moving toward her at 8m/s
Gabriella is moving away from her at 4 m/s
Gabriella is moving toward her at 4 m/s
Gabriella is not moving
It took the bike messenger 36 minutes to ride from the school to
the blue house. If they are 2160 meters apart, what was the
messenger's velocity?
a. 1.2 m/s
b. 1 m/s south
c. 2 m/s south
d. 1.2 m/s south
A man pushes on a 75.0 kg box such that his force of 225 N is exerted at an angle of 27.0 to the horizontal as shown
a) If the floor exerts a frictional force of 44.0 N on the box, what is the net force acting on the box?
b) If the box is initally at rest, how far will it have been pushed in 5.00 s assuming thise forced continued
a) The net force acting on the box is 181 N at an angle of 17.3 degrees below the horizontal.
b) The box will have been pushed 2.26 m assuming the force is constant.
a) To find the net force, we need to resolve the applied force vector into horizontal and vertical components. The horizontal component is 225cos(27.0) = 196 N and the vertical component is 225sin(27.0) = 102 N. The frictional force acts in the opposite direction to the horizontal component, so the net force in the horizontal direction is 196 - 44 = 152 N.
The net force in the vertical direction is 102 N - 750 N (weight of the box) = -648 N. Using the Pythagorean theorem, the magnitude of the net force is sqrt((152 N)² + (-648 N)²) = 670 N. The angle between the net force and the horizontal is arctan(-648 N/152 N) = -17.3 degrees below the horizontal.
b) We can use the kinematic equation d = 1/2at² to find the distance the box travels in 5.00 s, where a is the acceleration of the box and t is the time. The net force in the horizontal direction is responsible for the acceleration of the box, so we can use F = ma to find the acceleration: a = F/m = 152 N/75.0 kg = 2.03 m/s².
Substituting into the kinematic equation, we get d = 1/2 * 2.03 m/s² * (5.00 s)² = 25.3 m. However, this assumes that the force is constant, which may not be true in reality.
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Round the following off to required number of significant figures.
137 (2 significant figures)
Answer:
140
hope this helps
have a good day :)
Explanation:
dis science stuff getting on my nerves , anyways can y'all help me ?
Answer:
Elements in the same group have similar reactivity properties because they have the same number of valence electrons.
how is the crest of a wave reflected off of a fixed end?
When a crest of a wave reaches a fixed end or boundary, such as a wall or a rigid barrier, it is reflected back. The reflection of a wave occurs due to a change in the medium or a boundary that the wave encounters.
In the case of a fixed end, the reflection is known as "specular reflection" because the wave reflects off the surface in a predictable manner. Here's what happens:
1. Upon reaching the fixed end, the wave encounters a change in the medium or a boundary. In this case, the medium on one side of the boundary is different from the medium on the other side.
2. At the boundary, the wave encounters an abrupt change in the properties of the medium, such as density or elasticity. This change causes the wave to reverse its direction.
3. The crest of the wave is reflected back from the fixed end in such a way that the angle of incidence (the angle between the incident wave and the normal to the boundary) is equal to the angle of reflection. This principle follows the law of reflection.
4. The reflected wave carries the same characteristics (frequency, wavelength, amplitude) as the incident wave, but it travels in the opposite direction.
In summary, when a wave crest reaches a fixed end, it undergoes specular reflection, bouncing back from the boundary with the same frequency, wavelength, and amplitude, but traveling in the opposite direction.
The law of reflection ensures that the angle of incidence is equal to the angle of reflection.
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Making rough estimates of physical quantities is usefulA. So that you can see if the answer to a problem makes physical sense.B. Because we only use approximate numbers in problems.C. Because the laws we use are not exact, so using exact numbers is not crucial.D.So that you can compute answers doing simpler math.
Answer:
A. So that you can see if the answer to a problem makes physical sense.
Explanation:
Science can be defined as a branch of intellectual and practical study which systematically observe a body of fact in relation to the structure and behavior of non-living and living organisms (animals, plants and humans) in the natural world through experiments.
An experiment can be defined as an investigation which typically involves the process of manipulating an independent variable (the cause) in order to be able to determine or measure the dependent variable (the effect).
This ultimately implies that, an experiment can be used by scientists to show or demonstrate how a condition causes or gives rise to another i.e cause and effect, influence, behavior, etc in a sample.
Measurements refers to the process which typically involves the process of identifying and determining the dimensions of a physical object. The dimensions include important parameters such as width, height, length, area, volume, circumference etc.
In Science, making rough estimates of physical quantities is useful so that you can see if the answer to a problem makes physical sense.
For example, you could make a rough estimate of a storage tank and deductively determine whether or not it's in tandem with its physical size in reality.