estimate the number of neutron stars black holes in the cluster relative to the number of main-sequence stars in the cluster.

Answer:

A denser object will usually have a high index of

refraction.

A denser object will usually have a high index of refraction.

The refractive index is the ratio of the speed of light in vacuum and speed of light in any medium.

n = c/v

The density is greater for the denser medium (water, oil, mercury, etc) then the rarer medium (any gas or air).

When a light ray travels through denser medium, its velocity is reduced and the refracted ray bends towards normal.

As, the index of refraction is inversely proportional to the velocity of light in the medium, index of refraction will be high for denser object.

Thus, denser object have high index of refraction.

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The work done by a force can be calculated with the formula below:

Where W is the work in Joules, F is the force in Newtons and d is the displacement in meters.

So, for a force of 830 N and a displacement of 25 meters, the work is:

Therefore the correct option is A.

Answer:

Ethnomethodology theory

Explanation:

Take note of the fact that we are told Kevin worries that the police will stop and question him even though he has not done anything wrong.

This statement shows us that Kevin already understood his society from past experiences, and thus he tries to avoid social interactions with particular member of his society (the police) who may be show discrimination towards him.

Answer:

I only know answer A and it's 2825.28 N/m, with rounding it's 2825.5

Explanation:

Use the m*g*h=1/2*k*x^2 equation

96*9.81*60=1/2*k*2^2

5650.56=2k

5650.56/2=2825.28N/m

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

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The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.

This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.

Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.

The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.

Angles will always be expressed in degrees in the solution.

The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.

The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.

Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.

The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.

The angle between the two is (180 - 53 - 17) = 110 degrees.

The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.

Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.

Distance Travelled East/WestThe hiker walked East for the second part of the hike.

To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.

The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.

Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.

To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.

The angle between the second vector and the Eastern direction is 17 degrees.

Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.

The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.

Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

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Based on the information, we can infer that A. represents a Mitochondria.

Mitochondria is a term to refer to the eukaryotic cell organelles responsible for supplying most of the energy necessary for cell activity through the process called cellular respiration.

Based on the information, we can infer that the element that is labeled with the letter A is a mitochondrion because its location is that of a mitochondrion. In this case, the mitochondria is red, although in other models it can be represented with another color. In general, it is given this shape and this color to distinguish it from other elements of the cell.

Note: This question is incomplete. Here is the complete information:

Attached image

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Answer:

The equation for speed is simple: distance divided by time. You take the distance traveled (for example 3 meters), and divide it by the time (three seconds) to get the speed (one meter per second).

Explanation:

Answer:

un café y a seguir pensando porque no se la respuesta xd

Answer:

The ambient temperature is 35°C.

It takes 15 minutes to cool the substance from 40°C to 35°C.

Explanation:

Using Newton's Law of Cooling to answer the given problem.

\(\boxed{\left\begin{array}{ccc}\text{\underline{Newton's Law of Cooling:}}\\\\ \frac{dT}{dt} =-k(T-T_a)\end{array}\right}\)

Given:

The time it takes to cool from 50°C to 45°C = 3 minutes

The time it takes to cool from 45°C to 40°C = 5 minutes

Find:

Time ambient temperature and the time it takes to cool the substance from 40°C to 35°C

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

(1) - Using first initial condition:

\(\text{Avg temp =} \ \frac{50+45}{2}=\boxed{47.5 \textdegree C}\\\\\Longrightarrow \frac{50-45}{3}=-k(47.5-T_a) \\\\\Longrightarrow \boxed{ \frac{5}{3}=-k(47.5-T_a)}\)

(2) - Using the second initial condition:

\(\text{Avg temp =} \ \frac{45+40}{2}=\boxed{42.5 \textdegree C}\\\\\Longrightarrow \frac{45-40}{5}=-k(42.5-T_a) \\\\\Longrightarrow \boxed{1=-k(42.5-T_a)}\)

(3) - Now we have a system of equations.

\(\left \{ \frac{5}{3}=-k(47.5-T_a)}} \atop {1=-k(42.5-T_a)}}} \right.\)

(4) - Solve the system by dividing the top equation by the bottom equation.

\(\Longrightarrow \frac{\frac{5}{3}=-k(47.5-T_a)}{1=-k(42.5-T_a)} \\\\\Longrightarrow\frac{5}{3}=\frac{47.5-T_a}{42.5-T_a}\\ \\ \Longrightarrow 5(42.5-T_a)=3(47.5-T_a)\\\\\Longrightarrow 212.5-5T_a=142.5-3T_a\\\\\Longrightarrow 2T_a=70\\\\\therefore \boxed{T_a=35 \textdegree C}\)

Thus, the ambient temperature is 35°C.

(5) - Find the value of "k" using either of the two previous equations

\(1=-k(42.5-T_a)\\\\\Longrightarrow 1=-k(42.5-35)\\\\\Longrightarrow 1=-7.5k\\\\\Longrightarrow \boxed{ k \approx -0.133}\)

(6) - Now finding "dt"

\(\text{Avg temp =} \ \frac{40+35}{2}=\boxed{37.5 \textdegree C}\\\\\Longrightarrow \frac{40-35}{dt}=0.133(37.5-35) \\\\\Longrightarrow \frac{5}{dt}=0.3325\\\\\therefore \boxed{dt \approx15 \ min}\)

Thus, it take 15 minutes to cool the substance from 40°C to 35°C.

Answer:

uADHTiszA?kv

Explanation:

The object's kinetic energy changes according to

dK/dt = 15 J/s

If v is the object's initial speed, then its initial kinetic energy is

K (0) = 1/2 (5 kg) v ²

Use the fundamental theorem of calculus to solve for K as a function of time t :

\(K(t) = K(0) + \displaystyle\int_0^t \left(15\frac{\rm J}{\rm s}\right)\,\mathrm du = \dfrac12 (5\,\mathrm{kg}) v^2 + \left(15\dfrac{\rm J}{\rm s}\right)t\)

After t = 13 s, the object's kinetic energy is

K (13 s) = 1/2 (5 kg) (13 m/s)² = 422.5 J

Put this as the left side in the equation above for K(t) and solve for v :

\(422.5\,\mathrm J = \dfrac12 (5\,\mathrm{kg}) v^2 + \left(15\dfrac{\rm J}{\rm s}\right)(13\,\mathrm s)\)

==>   v ≈ 9.5 m/s

Answer:

Portland normally had rainy, but mild winters. Yesterday it rained 0.75 inches in Portland.

Explanation:

This talks about the weather

Answer:

How does Buddhism differ from Hinduism?

A.

Hindus believe in the notion of karma, while Buddhists reject it.

B.

Hinduism originated in India, while Buddhism originated in Sri Lanka.

C.

Hindus believe in the process of reincarnation, while Buddhists don't.

D.

Hinduism is polytheistic, while Buddhism doesn’t have gods and goddesses.

Explanation:

The distance travelled during this inattentive period is 61.12 meters.

Distance traveled defines how much path an object has covered to reach its destination in a given period.

The distance traveled by an object is calculated from the product of speed and time of motion of an object.

The distance traveled by the car is calculated as follows;

distance = speed x time

The speed at which the car was travelling is given 110 km/h.

Convert the speed in kilometer per hour (km/h) to meter per second (m/s).

110 km/h -----> m/s

= 110/3.6

= 30.56 m/s

Distance = 30.56 m/s x 2.0 s

Distance = 61.12 m

Thus, the distance travelled during this inattentive period is 61.12 meters.

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The net electric field at point P is 3.2×10^6 N/C, directed towards the left.

To calculate the net electric field at point P due to charges A and B, we need to consider the vector sum of the electric fields produced by each charge individually.

Given:

Electric field due to charge A: E_A = 8.7×10^6 N/C

Electric field due to charge B: E_B = 5.5×10^6 N/C

Since electric field is a vector quantity, we need to consider both magnitude and direction. Let's assume that the electric field due to charge A points to the left and the electric field due to charge B points to the right.

To find the net electric field at point P, we can subtract the magnitudes of the electric fields since they are acting in opposite directions:

Net electric field at point P = |E_A| - |E_B|

Substituting the given values, we get:

Net electric field at point P = 8.7×10^6 N/C - 5.5×10^6 N/C

                           = 3.2×10^6 N/C

Therefore, the net electric field at point P is 3.2×10^6 N/C, directed towards the left.

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Answer: Conduction

Explanation: Conduction is the process by which heat energy is transmitted through collisions between neighboring atoms or molecules. Conduction occurs more readily in solids and liquids, where the particles are closer to together, than in gases, where particles are further apart.

There are 36 ounces of yellow paint.

Both blue and yellow paint reflect intermediate wavelengths. Therefore, if you mix blue and yellow paint the mixture will appear green. I have found that blues and greens produce predominantly cyan or turquoise tones but mixing colors is never the right thing to do with darker or lighter grays.

Mixing blue and green makes him a tertiary color on the color wheel, teal. Blue-green is similar to turquoise or the color of the sea. This is one of the most common and popular tertiary colors. For a light aqua color mix cobalt blue with white. The primary colors are red blue and yellow. Primary colors cannot be mixed with other colors. They are the source of all other colors.

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Answer:

the distance x increases as the student increase the mass of the cannon.

Explanation:

a) From the question ; we get to understand that for each launch, the students use a different mass which is launch at  speed v relative to the ground.

This changes in the mass used brought about a change in the momentum at the same speed v ; perhaps an increase in momentum. However; since the conservation of the momentum is considered at each launching.

The momentum of the marble = momentum of the cannon

But since the momentum of the cannon increase ; therefore the same equivalent changes takes place in its kinetic energy . Therefore , the kinetic energy will increase and the distance will also increase in the bid to quench the amount of energy generated. Thus, the distance x increases as the student increase the mass of the cannon.

b)We all know that  conservation of the momentum will definitely  takes place after launching of the cannon.

Let assume that \(\rho\) is the momentum of the cannon with mass \(M_C\)

The kinetic energy of the canon will be:

\(\frac{\rho ^2 }{2 M_C}\)

Also the frictional force acting on the cannon is :

\(f = \mu mg\)

If the cannon move at an  additional distance x; the frictional force acting at this area quench the amount of the energy generated and consume the kinetic energy of the cannon;

So;

\(fx = K.E\)

\(fx = \frac{\rho ^2 }{2 M_C}\)

\(\mu mg x = \frac{\rho ^2 }{2 M_C}\)

\(x = \frac{\rho ^2 }{2 \mu mg M_C}\)

\(x = \frac{m_m^2 V^2 }{2 \mu mg M_C}\)

Thus; it is consistent with the answer in (a) as increase in the mass of the marble will bring about an increase in distance x

The increase in the mass of the marble increase the distance of the cannon.

Momentum:

Momentum of an object is equal to the product of the mass and the velocity of the object.

The kinetic energy of the cannon

\(K_C = \dfrac {\rho^2}{2 M_C}\)

Where,

\(\bold{\rho}\) - momentum of the cannon

Mc -  mass

The frictional force on cannon

\(\bold{F_f = \mu mg}\)

Cannon move a distance x,

Hence,

\(\bold {F_f \times x = K_C}\\\\\bold {\mu m g \times x = \dfrac {\rho^2}{2 M_C }}\\\\\bold {x = \dfrac {\rho^2}{2\mu m g M_C }} }\\\\\bold {x = \dfrac {m^2 V^2}{2\mu m g M_C } }\)

Therefore, The increase in the mass of the marble increase the distance of the cannon.

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(a) The ball goes up to the height of 31.89 m. (b) The ball stays for 5.1 s in the air. (c) The acceleration due to gravity and wind resistance can affect the estimation.

Acceleration owing to gravity is the term used to describe the rate at which a body's velocity changes as a result of the earth's gravitational pull. In general, it is assumed that the acceleration caused by gravity is in the downward direction.

The acceleration caused by gravity has been calculated as, however as it changes from location to location, it may have an impact on the estimation.

You may have thought that the wind has no impact, but it can actually generate drag and even cause the ball to shift course.

Therefore, (a) The ball goes up to the height of 31.89 m. (b) The ball stays for 5.1 s in the air. (c) The acceleration due to gravity and wind resistance can affect the estimation.

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Answer:

Explanation:

Given that:

mass of water = 2kg

Pressure P₁ = 10 bar

temperature T₁ = 200⁰ C

Obtaining the following value from superheated tables at P₁ = 10 bar and T₁ = 200⁰ C

v₁ = 0.2060 m³/kg

h₁ = 2827.9 kJ/kg

The heat transfer Q₁₋₂ = 1740 kJ

Using the energy balance equation:

Q₁₋₂ = m(h₂ - h₁)

1740 = 2(h₂ - 2827.9)

1740 = 2h₂ - 5655.8

1740 + 5655.8 = 2h₂

7395.8 = 2h₂

h₂ = 7395.8/2

h₂ = 3697.9 kJ/kg

Since P₁ = P₂ = 10 bar

Using the superheated table at P₂ = 10 bar and h₂ = 3697.9 kJ/kg;

v₂ = 0.4011 m³/kg

The temperature at final state = 600 °C

The work done \(W_{1-2} = \int P dv\)

\(W_{1-2} = P\times m (V_2-V_1)\)

= (10×10² kPa)×2kg (0.4011 - 0.2060) m³/kg

= (10×10² kPa)×2kg × 0.1951 m³/kg

= 390.2 kJ

The density of the rod is 3.0 kg/m at the origin,then the center of mass of the rod is located 2.15 m from the origin.

The center of mass is the point in an object or system of objects where the mass of the object or system can be considered to be concentrated. In other words, it is the point in which an object or system can be balanced and behaves as if all the mass is concentrated at that point.

To find the center of mass of the rod, we need to integrate the product of the density and position of each infinitesimal element of the rod, divided by the total mass of the rod.

We can express the position of each element as x, where x=0 at the origin and x=4.5 m at the other end of the rod.

Let's start by finding the total mass of the rod. We can divide the rod into two parts: one from the origin to the midpoint, and the other from the midpoint to the other end. The mass of each part can be found by integrating the density over its length:

m₁ = ∫(0 to 2.25) 3x² dx = 15.19 kg

m₂ = ∫(2.25 to 4.5) (22.5x - 45.375) dx

                                = 95.63 kg

The total mass of the rod is then derived as follows:

                 m = m₁ + m₂ = 110.82 kg

We can now evaluate the location of the centre of mass. We can express the position of the center of mass as xcm, where x=0 at the origin and x=4.5 m at the other end of the rod.

We can use the formula:

xcm = (1/m) ∫(0 to 4.5) ρ(x) x dx

where (x) represents the density at position x.

We can express the density as a quadratic function of x:

                          ρ(x) = ax² + bx + c

Using the given values of density at the origin, midpoint, and other end, we can solve for the coefficients a, b, and c:

                               c = 3

                         a + b + c = 11/4.5

                           = 2.44

4a + 2b + c = 3

Solving these equations gives:

a = -1.96 kg/m³

b = 7.33 kg/m²

Now we can plug in the expression for ρ(x) and evaluate the integral:

xcm = (1/m) ∫(0 to 4.5) (-1.96x⁴ + 7.33x³ + 3x) dx

Evaluating this integral gives:

                                       xcm = 2.15 m

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Initial position, u = 10 m

Final position, v = 5 m

Change in time, ∆t = 5 s

We know that, velocity = ∆x / ∆t

where, ∆x is the displacement and ∆t is the change in time.

∆x = v - u

∆x = 5 m - 10 m

∆x = -5 m

Velocity = ∆x / ∆t

Velocity = -5 m / 5 s

Velocity = -1 m/s

Therefore, B: -1 m/s is the correct answer. A negative velocity means the object is traveling in the other direction.

Answer:

60 w

Explanation:

Given :

V= 120V

I=0.5 A

Now,

power can be calculated as :

P=VI

where,

V is voltage

I is current

Now,

P=(120)(0.5)

P=60 W

Therefore, 60w power is delivered to a light

The tension in the connecting string is 14.7 N.

The net force of the masses is calculated as follows;

\(F_{net} = Mgsin(\theta)+ Mg\)

The acceleration of the masses is calculated as follows;

\(a = \frac{F_{net}}{M+ M} = \frac{M(gsin\theta + g)}{2M} = \frac{gsin\theta + g}{2} \\\\a = \frac{9.8sin(30) \ + \ 9.8}{2} = 7.35 \ m/s^2\)

The tension in the connecting string is calculated as follows;

\(mg - T = ma\\\\T = mg - ma\\\\T = m(g - a)\\\\T = 6(9.8 - 7.35)\\\\T = 14.7 \ N\)

Thus, the tension in the connecting string is 14.7 N.

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Answer:

A calorie is defined as the amount of energy needed to raise the temperature of one gram of water one degree Celsius.

Explanation:

The other unit used to measure heat is the joule. The joule is the SI (System International) unit

The radii of the first five Fresnel zones is 3.6 mm.

Distance from the light source to the wave surface, d₁ = 1 m

Distance from the wave surface to the observation point, d₂ = 1 m.

Wavelength of the light used, λ = 5 x 10⁻⁶m = 5 μm

The expression for the radius of the Fresnel zones is given by,

rₙ = √[nλd₁d₂/(d₁ + d₂)]

Therefore, the radii of the first five Fresnel zones is,

r₅ = √[5 x 5 x 10⁻⁶x 1 x 1/(1 + 1)]

r₅ = √(25 x 10⁻⁶/2)

r₅ = 3.6 x 10⁻³m

r₅ = 3.6 mm

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Answer:

Convection

Explanation:

Definition:

An ocean current is a continuous, directed movement of sea water generated by a number of forces acting upon the water