Exactly one of the following five numbers is not prime.


Which is it?

Step-by-step explanation:

a1 = 27

r = -9/27 = -⅓

the formula :

an = a1. r^(n-1)

= 27. (-⅓)^(n-1)

= 3³(-3`¹)^(n-1)

= 3³(-3)^(1-n)

We need a sample size of 35 to reduce the margin of error to $25 for a 95% confidence interval, given that we have reason to believe that the population standard deviation of credit card debts for this group is $150.

To determine the sample size needed to reduce the margin of error to $25 for a 95% confidence interval, we can use the following formula:
n = (z * σ / E)²
Where:
n = sample size
z = z-score corresponding to the desired confidence level (1.96 for 95% confidence)
σ = population standard deviation
E = desired margin of error
Substituting in the given values:
n = (1.96 * 150 / 25)²
n = 34.57
Rounding up to the nearest whole number, we get a sample size of 35. Therefore, we need a sample size of 35 to reduce the margin of error to $25 for a 95% confidence interval, given that we have reason to believe that the population standard deviation of credit card debts for this group is $150.

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The object A is in only translational equilibrium, object B is in only rotational equilibrium about axis a, and object C is in both translational and rotational equilibrium about axis a. The correct answer is both translational and rotational equilibrium.

Translational equilibrium occurs when the net force acting on an object is zero. Rotational equilibrium occurs when the net torque acting on an object is zero. An object can be in both types of equilibrium simultaneously.

Object A: The forces acting on object A are balanced, so the net force acting on it is zero. Therefore, object A is in only translational equilibrium.

Object B: Object B is being acted upon by a force that is perpendicular to the axis of rotation, which generates torque. Since the object is in equilibrium, the torque generated by the force must be balanced by the torque generated by an opposing force. Therefore, object B is in only rotational equilibrium about axis a.

Object C: Since the net force acting on object C is zero, it is in translational equilibrium. In addition, since the torques generated by the forces acting on it balance each other, it is also in rotational equilibrium about axis a. Therefore, object C is in both translational and rotational equilibrium about axis a.

In conclusion, object A is in only translational equilibrium, object B is in only rotational equilibrium about axis a, and object C is in both translational and rotational equilibrium about axis a. Therefore, the correct answer is both translational and rotational equilibrium.

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Answer:

19.20

Step-by-step explanation:

P.S im not a genius

Answer:

It is D

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

The endpoints of a line segment graphed on the coordinate system are (−7, 3) and (2, 5). What is the range of the graph? the x values are the domains which are the first numbers so in this case the domains would be -7 and 2 but this question is talking about range which is the y in other words its the second numbers which is 3 and 5

For any price of h and k = -12, the system x + 3y = h and -4x + ky = -9 will haven't any answer.

To determine the values of h and okay for which the device of equations has no answer, we want to locate the situations underneath which the equations are inconsistent or parallel.

The given system of equations is:

Equation 1: x + 3y = h

Equation 2: -4x + ky = -9

For the gadget to haven't any answer, the lines represented with the aid of these equations should be parallel and in no way intersect. In different phrases, the slopes of the traces need to be equal, but the y-intercepts should be specific.

Let's first discover the slopes of the traces. The slope-intercept form of Equation 1 is y = (-1/3)x + (h/3), wherein the slope is -1/3. The slope-intercept shape of Equation 2 is y = (4/k)x - (9/k), wherein the slope is 4/k.

For the strains to be parallel, the slopes should be equal. Therefore, we have the condition: -1/3 = 4/k.

To locate the values of h and okay for which the gadget has no answer, we need to locate the values of h that satisfy the situation -1/3 = 4/k.

Solving this equation for ok, we've got:

-1/3 = 4/k

-1 = 12/k

k = -12

Substituting k = -12 returned into the equation -1/3 = 4/k, we've:

-1/3 = 4/(-12)

-1/3 = -1/3

Since the equation holds real for any value of h, there aren't any restrictions at the price of h.

Therefore, for any price of h and k = -12, the system x + 3y = h and -4x + ky = -9 will haven't any answer.

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The system of equations has no solution when k is equal to 12. The value of h can be any real number.

To determine the values of h and f for which the system has no solution, we need to analyze the coefficients of the variables and the constants in the equations.

The given system of equations is:

x + 3y = h

-4x + ky = -9

We can rewrite the second equation as:

-4x + ky = -9

Dividing both sides of the equation by -4, we get:

x - (k/4)y = 9/4

Comparing the coefficients of x and y in the two equations, we can see that the slopes of the lines represented by the equations are different when k is not equal to 12.

Therefore, for the system to have no solution, k must be equal to 12.

As for the value of h, it can be any real number since it does not affect the slopes of the lines.

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Answer:

Here to help! See explanation

Step-by-step explanation:

Hey there! It's really simple once you get the hang of it, I'll show you!

Example:

\(\frac{1}{3} + \frac{3}{4}\)

First, we have to remember that we can't add fractions with different denominators. So we have to look for the least common denominator, also known as the least common multiple.

In this case, the smallest number that both 3 and 4 make is 12.

Now, we have to multiply both fractions by what it takes to get to twelve. 3 has to be multiplied by 4, and 4 by 3.

\(( \frac{1}{3} )*4 = \frac{4}{12} \\\\\)

\((\frac{3}{4} ) *3= \frac{9}{12}\)

Now that we have the same denominator, all we have to do is add the numerators.

\(\frac{4}{12} + \frac{9}{12} =\frac{13}{12} = 1\frac{1}{12}\)

I hope this helped!

The value of u is not provided, we cannot determine the exact value of y. None of the given options (a, b, c, d) can be chosen as the approximate value of y.

For the first question, you are given the model yhat = 2.1 + 1.0x^2 and you want to find the estimated marginal effect of x on y when x = 1.3. To find the estimated marginal effect, you need to take the derivative of yhat with respect to x. In this case, the derivative would be 2.0x.

Now, substitute x = 1.3 into the derivative:

2.0(1.3) = 2.6.

Therefore, the estimated marginal effect of x on y when x = 1.3 is 2.6.

For the second question, you are given the model \(lny = β₁ + β₂x^2 + u\), with parameter estimates

β₁ = 2 and

β₂ = 1.

To predict the value of y when x = 2, substitute the given values into the model:
\(lny = 2 + 1(2^2) + u\)
lny = 2 + 1(4) + u
lny = 2 + 4 + u
lny = 6 + u

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Answer:

Independent variable is the measurement that that changes and the dependent variable is the result of the independent variable (aka the one that is being measured).

Step-by-step explanation:

Based on the given information, we can determine whether it is unusual for a school bus to arrive late. To do this, we need to calculate the probability of a school bus arriving late and compare it to the threshold of 0.05.

To determine if it is unusual for a school bus to arrive late, we need to calculate the probability of a school bus arriving late and compare it to the threshold of 0.05. In this case, out of the 300 randomly selected school bus routes, 274 arrived on time. This means that the number of school buses arriving late would be 300 - 274 = 26. To calculate the probability of a school bus arriving late, we divide the number of buses arriving late by the total number of buses:

P(arriving late) = 26/300 = 0.0867

The probability of a school bus arriving late is 0.0867, which is greater than the threshold of 0.05. Therefore, it is not considered unusual for a school bus to arrive late based on this sample.

To further explain, we can interpret the probability of 0.0867 as the likelihood of randomly selecting a school bus route from the population and it is late. Since this probability is greater than 0.05, we conclude that the event of a school bus arriving late is not considered unusual based on the given sample.

It's important to note that this conclusion is based on the assumption that the sample is representative of the population of school bus routes. If there are specific factors or circumstances that may affect the timeliness of the buses in the population, further analysis and consideration of those factors would be necessary to make a more accurate determination.

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C. May or may not increase in size even if the added variable has statistical significance.

The R-squared value measures the proportion of variance in the dependent variable that is explained by the model, including the independent variable.

Therefore, if an independent variable is added to the model and it is statistically significant, then it will increase the R-squared value. However, if the variable added is not statistically significant, then it will not have an effect on the R-squared value.

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The slope is the change in y over the change in x.

The first number in the parentheses is the x value, the second number is the y value.

Slope = (0-3) / (4-0)

Slope = -3/4

The y intercept is the y value when x is 0.

The given point (0,3) has x as 0, so the y intercept would be 3

Answers: slope = -3/4, y intercept = 3

Answer:

y intercept = 3 slope = -3/4

Step-by-step explanation:

I did this on edganuity :)

Answer:

whats the question sir

Step-by-step explanation:

can you show me it like type it for me

Using Algebraic expression solution ,

The cost of three hats is $18 .

We have given that,

A hat company charge for design fee $4 per hat .

i.e design fee of one hat = $4

total cost of 5 hats = $30

let the cost of one hat without design fee be $x and total cost of one hat is $(x+4) .

using the above statement, we get an algebraic expression,

5( x+ 4)= 30

we solve the above algebra expression,

=> 5x + 20 = 30

=> 5x = 10

=> x = 2

so, cost of a hat without design fee is $2

and total cost of one hat is $6.

we have to calculate cost of 3 hats .

cost of one hat in hat company= $ 6

cost of three hats in hat company= $(6×3)

= $18

Hence, the total cost of 3 hats is $18.

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Answer: B

Step-by-step explanation:

\((f+g)(x)=f(x)+g(x)\\\\=\frac{x}{2}-3+4x^2 +x-4\\\\=4x^2 +\frac{3x}{2}-7\)

Yes, it is possible for a plot of a partial expansion of f[x] to share ink with the plot of f[x] all the way from -[infinity] to + [infinity].

Explanation:

We can approximate f(x) as a Fourier series, as follows:

\($$f(x) = \sum_{n=0}^{\infty}a_n\cos\left(\frac{n\pi x}{L}\right)+\sum_{n=1}^{\infty}b_n\sin\left(\frac{n\pi x}{L}\right)$$\)

If f(x) is an odd function, the cosine terms are gone, and if f(x) is an even function, the sine terms are gone.

We can create an approximation for f(x) using only the first n terms of the Fourier series, as follows:

\($$f_n(x) = a_0 + \sum_{n=1}^{n}\left[a_n\cos\left(\frac{n\pi x}{L}\right)+b_n\sin\left(\frac{n\pi x}{L}\right)\right]$$\)

For any continuous function f(x), the Fourier series converges uniformly to f(x) on any finite interval, as given by the Weierstrass approximation theorem.

However, if f(x) is discontinuous, the Fourier series approximation does not converge uniformly.

Instead, it converges in the mean sense or the L2 sense. The L2 norm is defined as follows:

\($$\|f\|^2 = \int_{-L}^{L} |f(x)|^2 dx$$\)

Hence, it is possible for a plot of a partial expansion of f(x) to share ink with the plot of f(x) all the way from -[infinity] to + [infinity].

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Answer:

13.85kg

Step-by-step explanation:

7 3/4=7.75

2 1/2=2.5

3 3/5=3.6

7.75+2.5+3.6

=13.85kg

Answer: 42 gallons

Step-by-step explanation:

given data:

average gas mileage/day = 29miles/gallon

distance travelled each day by James = 87miles

How much gas does he use in 14days drive.

solution:

james drives 87miles daily, so in 14 days he would have travelled

= 87miles * 14

= 1218miles travelled.

gas used in 14days

1218miles distance traveled in 14 days

29miles/gallon

= 1218miles / 29miles

= 42gallons of gas have been used by janew to fuel his truck in 14days.

Answer:

Multiplying by

\( \frac{4}{3} \)

Step-by-step explanation:

\( \frac{4}{5} \div \frac{3}{4} \)

\( = \frac{4}{5} \times \frac{4}{3} \)

Answer:

multiplying by 4/3

Step-by-step explanation:

"keep-change-flip"

1. "keep" the 4/5

2. change the division sign to multiplication sign

3. flip the fraction 3/4, to 4/3

Answer 60?

Step-by-step explanation:

edmentum

The approximate angle of elevation if Brendan looks up at the tower is 20.03°

The angle of elevation if Brendan looks up is as follows;

using trigonometric ratios,

sin x° = opposite / hypotenuse

sin x° = 50 / 146

sin x° = 0.34246575342

x = sin⁻¹ 0.34246575342

x = 20.0271724581

x = 20.03°

Therefore, the approximate angle of elevation if Brendan looks up at the tower is 20.03°

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The parametric equations of the line of intersection between the planes x - y + z = 0 and x + 2y + 3z = 6 are x = 2t + 6, y = t, and z = -t - 6.



To find the parametric equations of the line of intersection between two planes, we need to determine a point on the line and find its direction vector.

First, we solve the system of equations formed by the two planes: x - y + z = 0 and x + 2y + 3z = 6. By eliminating x, we get -3y - 2z = -6.Setting y = t and z = s as parameters, we can express the point on the line as (x, y, z) = (2t + 6, t, s).Now, substituting these values into the first equation, we obtain 2t + 6 - t + s = 0, which simplifies to t + s = -6.

Therefore, the parametric equations for the line of intersection are:

x = 2t + 6

y = t

z = -t - 6, where t and s are parameters.

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The expression 2^n - 5^n is indeed a solution to the recurrence relation an = 7an-1 - 10an-2. To use it as the closed formula for the sequence, the initial conditions need to be specified. The initial values for a0 and a1 would need to be determined based on the sequence being generated. Once the initial conditions are established, the expression 2^n - 5^n can be used to find the nth term of the sequence directly without having to rely on the recurrence relation.

To demonstrate that 2^n - 5^n satisfies the given recurrence relation, we need to substitute it into the relation and verify that it holds true for all n.

Given recurrence relation: an = 7an-1 - 10an-2

Substituting 2^n - 5^n into the recurrence relation:

7(2^(n-1) - 5^(n-1)) - 10(2^(n-2) - 5^(n-2))

Expanding and simplifying the expression:

7 * 2^(n-1) - 7 * 5^(n-1) - 10 * 2^(n-2) + 10 * 5^(n-2)

Rearranging the terms:

2 * 7 * 2^(n-2) - 2 * 7 * 5^(n-2) - 10 * 2^(n-2) + 10 * 5^(n-2)

Combining like terms:

2(7 * 2^(n-2) - 7 * 5^(n-2) - 5 * 2^(n-2) + 5 * 5^(n-2))

Factoring out 2 from the expression:

2(7 * 2^(n-2) - 5 * 2^(n-2) - 7 * 5^(n-2) + 5 * 5^(n-2))

Simplifying further:

2(2^(n-2)(7 - 5) - 5^(n-2)(7 - 5))

The expression simplifies to:

2(2^(n-2)(2) - 5^(n-2)(2))

2 * 2^(n-1) - 2 * 5^(n-1)

Which is equal to 2^n - 5^n.

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Answer:

The owners' cost of the candy bar is $1

Step-by-step explanation:

Assume that the owners' cost of the candy bar is 100%

∵ The owners' cost of the candy bar is 100%

∵ The candy store uses a 50% markup on cost

∵ The selling cost = owners' cost + markup

∴ The selling cost = 100% + 50% = 150%

∵ The candy bar sells for $1.50

→ That means 1.50 is 150% of the owners' cost

∴ 1.50 = 150% × owners' cost

→ Change 150% to decimal by divide it by 100

∵ 150% = 150 ÷ 100 = 1.50

∴ 1.50 = 1.50 × owners' cost

→ Divide both sides by 1.50

∴ 1 = owners' cost

∴ The owners' costs = $1

∴ The owners' cost of the candy bar is $1

The rank of the matrix A is equal to the dimension of its column space. Therefore, the rank of A cannot be determined solely based on the given characteristic polynomial.

The rank of a matrix is a measure of the linear independence of its columns. It represents the maximum number of linearly independent columns in the matrix.

On the other hand, the characteristic polynomial of a matrix is a polynomial equation obtained by subtracting the identity matrix multiplied by the scalar variable λ from the given matrix A, and then taking the determinant.

The characteristic polynomial provides information about the eigenvalues of the matrix, which are the values of λ that satisfy the equation αλ^5 + βλ^4 + γλ^3 = 0.

While there may be some connections between the rank of the matrix and the characteristic polynomial, it is not possible to determine the rank of the matrix A solely based on the given characteristic polynomial equation.

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Answer:

\(x = 25.9\)

Step-by-step explanation:

Apply law of sines.

\( \frac{23}{ \sin(22) } = \frac{x}{ \sin(25) } \)

\( \frac{23}{ \sin(22) } \times \sin(25) = x\)

\(x = 25.9\)

Answer:

25.9

Step-by-step explanation:

By sine rule:

\( \frac{BC}{ \sin 25 \degree} = \frac{23}{ \sin 22 \degree} \\ \\ BC = \frac{23 \sin 25 \degree}{ \sin 22 \degree} \\ \\ BC = \frac{9.72022002}{ \sin 22 \degree} \\ \\BC = 25.947808156 \\ \\ BC \approx \: 25.9\)

Answer:

B. supplementary angles

Step-by-step explanation:

Answer:

512x+1 over 2^x ........................

Step-by-step explanation:

:)

Answer:

y = \(\frac{5}{4} x - 7\)

Step-by-step explanation:

Step 1: Add -5x to both sides.

5x − 4y + −5x = 28 + −5x

−4y = −5x + 28

Step 2: Divide both sides by -4.

\(\frac{-4y}{-4} =\frac{-5x +28}{-4}\)

y = \(\frac{5}{4}x -7\)

Answer:

y=-  -5/4x-7 go to question 7

Step-by-step explanation:

y=-  (-5x+28)

         4

then simplify if you need more steps i will show