car accelerates at a rate of 4.00 m/s?. How long will it take the car to speed up from 20 m/s to 50 m/s?
The distance that will take the car to speed yup from 20m/s to 50m/s is 262.5 meters
The first step is to write out the parameters given in the question are
acceleration= 4
initial velocity= 20
final velocity= 50
The distance can be calculated as follows
V²= U² + 2as
50²= 20² + 2(4)(s)
2500= 400= 8s
2500-400= 8s
2100= 8s
s= 2100/8
s= 262.5 meters
Hence the distance is 262.5 meters
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From the definition of acceleration, the time it will take the car to speed up is 7.5 seconds
Given that a car accelerates at a rate of 4.00 m/s^2. To calculate how long it will take the car to speed up from 20 m/s to 50 m/s, let us first mark out the needful parameters.
Acceleration a = 4 m/\(s^{2}\)
Initial velocity U = 20 m/s
Final Velocity V = 50 m/s
Time t = ?
From the definition of acceleration, acceleration is the rate of change of velocity. That is,
a = (V - U)/ t
Substitute all the parameters into the formula above.
4 = ( 50 - 20) / t
Cross multiply
4t = 30
Make t the subject of formula
t = 30/4
t = 7.5 t
Therefore, the time it will take the car to speed up is 7.5 seconds
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A convex mirror of focal length 33 cm forms an image of a soda bottle at a distance of 19 cm behind the mirror.If the height of the image is 7.0 cm,where is the object located,and how tall is it? What is the magnification of the image? Is the image virtual or real? Is the image inverted or upright? Draw a ray diagram to confirm your results.
Answer:
Image distance = 44.8cm, Image height = 16.5cm, Magnification = 0.42
The image is a virtual and upright image.
Explanation:
The nature of image formed by an object placed in front of a convex mirror is always diminished, virtual and erect.
The focal length f and the image distance are always NEGATIVE beacause the image is formed behind the mirror.
Given f = -33.0cm, v = -19.0cm
using thr mirror formula to get the object distance u, we have;
\(\frac{1}{f}=\frac{1}{u} + \frac{1}{v}\\ \frac{1}{u}=\frac{1}{f} - \frac{1}{v}\\\frac{1}{u}=\frac{1}{-33} - \frac{1}{-19}\\\frac{1}{u}=\frac{-19+33}{627} \\\frac{1}{u}=\frac{14}{627} \\u=\frac{627}{14} \\u = 44.8cm\)
To calculate the image height, we will use the magnification formula
M = \(\frac{image\ height}{object\ height}=\frac{image\ distance}{object\ distance} \\\)
M = \(\frac{Hi}{HI}=\frac{v}{u}\)
Given Hi = 7.0cm
v = 19.0cm
u = 44.8cm
HI = 7*44.8/19
HI = 16.5cm
The object height is 16.5cm
Magnification = v/u = 19.0/44.8 = 0.42
SInce the image is formed behind the mirror, the image is a VIRTUAL and UPRIGHT image
Universal Gravitational Concepts and Mathematics
10 of 16
POSSIBLE POINTS: 6.25
A 35 kg object is on the surface of Venus. Venus has a mass of 4.87x10^24 kg and a radius of 6.05x10^6
m. What is the weight of the object on Venus?
35 N
35 kg
0 343 kg
311 N
5
6
7
8
9
10 11 12 13 14
Next
First of all, weight is a force typically measured in Newtons. So right away, you can eliminate 35 kg and 343 kg from the given choices.
The object's weight F on Venus as given by the universal law of gravitation is
F = G (35 kg) (4.87 x 10²⁴ kg) / (6.05 x 10⁶ m)²
where G = 6.67 x 10⁻¹¹ N•m²/kg² is the gravitational constant. You would find the weight of the object to be
F ≈ 310.8 N
so the closest answer is 311 N.
Galileo was the first scientist to do which of the following?
Galileo Galilei was an Italian physicist, mathematician, astronomer, and philosopher who made significant contributions to the scientific revolution during the Renaissance. He is often referred to as the "father of modern observational astronomy" and the "father of modern science."
Galileo made a number of important discoveries and contributions to science. Some of his most significant contributions include:
1- The law of falling bodies: Galileo is credited with developing the concept of free-fall and the mathematical relationship between distance and time for objects in free-fall. He conducted a series of experiments in which he dropped objects of different masses from the Leaning Tower of Pisa to demonstrate that all objects fall at the same rate in a vacuum, regardless of their mass.
2- The telescope: Galileo is credited with building the first practical telescope, which he used to observe the heavens and make a number of important discoveries. He observed the phases of Venus, the lunar surface, and the Galilean moons of Jupiter, among other things.
3- The laws of motion: Galileo is credited with developing the concept of inertia and the laws of motion that later formed the basis of classical mechanics. He also developed the concept of momentum and introduced the idea of a mathematical relationship between force, mass, and acceleration.
4- The scientific method: Galileo is credited with pioneering the scientific method, which involves making observations, developing hypotheses, testing hypotheses through experiments, and drawing conclusions based on the results. This approach to science is still used today and is fundamental to the scientific process.
do fish get thirsty????
Complete the following statement: Different types of collisions between interacting bodies
are categorized on the basis of
a. linear momentum conservation
b. mechanical energy conservation.
c. kinetic energy conservation.
d. the magnitude of the forces
involved
what is renewable and non-renewable energy?
Renewable resources:
A renewable resource is one that can be used repeatedly and does not run out because it is naturally replaced.
Nonrenewable resource:
A nonrenewable resource is a natural substance that is not replenished with the speed at which it is consumed. It is a finite resource.
Thenks and pls mark me brainliestt :))
Answer:
Renewable energy includes solar, hydro, and wind energy. Non-renewable energy includes coal, gas, and oil.Explanation:
Renewable energy is useful energy that is collected from renewable resources, which are naturally replenished on a human timescale. A non-renewable resource is a natural resource that cannot be readily replaced by natural means at a pace quick enough to keep up with consumption.
Electrons orbit the nucleus. They have a very ___ mass and do not contribute to atomic mass
Answer:
Electrons orbit the nucleus. They have a very small mass and do not contribute to atomic mass
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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I need 6 things to save energy or increase energy efficiency in any part of a house
Here are six things that can help save energy or increase energy efficiency in any part of a house:
Install energy-efficient light bulbs: Replace traditional incandescent light bulbs with energy-efficient LED light bulbs. LED bulbs consume less electricity and last much longer.
Use a programmable thermostat: Installing a programmable thermostat can help you control the temperature of your home more efficiently. You can set it to automatically lower the temperature when you're away from home or sleeping.
Air leaks should be sealed with weatherstripping or caulk around windows and doors. By doing so, you can keep your house more pleasant and prevent draughts.
Install ceiling fans: Ceiling fans can help circulate air and keep your home cool in the summer and warm in the winter. They use less energy than air conditioners or heaters.
Upgrade to energy-efficient appliances: When it's time to replace appliances, choose ones with an Energy Star label. These appliances are designed to use less energy and can help you save money on your energy bills.
Use power strips: Plug electronics and appliances into power strips, which can be turned off when not in use. This can prevent phantom energy use, which occurs when electronics and appliances continue to draw power even when turned off.
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molality is a common unit of concentration which is used when temperature changes are a factor since its value will not change with temperature. molality is calculated by determining the number of moles of the solute, or the substance being dissolved, in 1 kilogram of solvent. this is summarized as follows: what is the molality of a solution prepared from 5.25 g lif and 45.0 g h2o?
The molality of a solution prepared from 5.25 g LiF and 45.0 g H2O is 4.49 m LiF.
Molality is useful in many chemical applications, particularly in the study of colligative properties of solutions. Colligative properties are properties of solutions that depend only on the concentration of solute particles and not on their chemical identity. Examples of colligative properties include boiling point elevation, freezing point depression, and osmotic pressure.
Molality is often used in laboratory settings where accurate measurement of concentration is important. It is also used in industrial processes such as the production of pharmaceuticals, where precise control of concentration is critical. In summary, molality is an important measure of concentration that is widely used in chemistry to describe the properties and behavior of solutions.
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Complete Question: -
Molality is a common unit of concentration which is used when temperature changes are a factor since its value will not change with temperature.
Molality is calculated by determining the number of moles of the solute, or the substance being dissolved, in 1 kilogram of solvent. This is summarized as follows:
Molality (m) = moles of solute/1 kg of solvent
What is the molality of a solution prepared from 5.25 g LiF and 45.0 g H2O?
vertical columns in the periodic table represent a group or family of elements that have the same number of valence electrons by having similar electron configurations elements in the same group have similar properties list elements that have similar properties
The examples of elements with similar properties in the same group are fluorine, chlorine, bromine and iodine.
What is group of elements in a periodic table?
The groups in periodic table is the same as vertical columns in the periodic table
These groups represent a group or family of elements that have the same number of valence electrons by having similar electron configurations elements in the same group have similar properties.
Examples of elements found in the same group with similar chemical properties include;
group 7 elements.
FluorineChlorineBromineIodineThe valence electron of elements found in the group 7 of periodic table is negative 1 (-1).
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A top fuel dragster is designed to go from 0 to100 miles per hour in a mere 0.8 seconds. Calculate its acceleration. Show your work and include units.
The acceleration of the dragster is 2.01 * 10^5 m/s^2
What is the acceleration?The term acceleration refers to the change in velocity with time. Hence the formula for acceleration is given as;
a = v - u/t
a = acceleration
v = final velocity
u = initial velocity
t = time taken
Now;
v = 100 miles or 160934 meters
u = 0 miles or 0 meters
t = 0.8 seconds
a = 160934 - 0/ 0.8
a = 2.01 * 10^5 m/s^2
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Two bodies separated from
each other at a certain distance
started moving simultaneously
to meet each other - one with ar
acceleration of 2.4 m/s, and the
other with an acceleration of 4.8
m/s2. Determine the ratio of the
displacement module of the first
body to the displacement
module of the second body at
the moment of their meeting.
The result of the ratio of the displacement module of the second body at the point of meeting is 0.5.
How to find displacement ratio?To determine the ratio of the displacement of the first body to the displacement of the second body at the moment of their meeting, use the equation of motion:
d = vt + 1/2at²
where d is the displacement, v is the initial velocity, t is the time, and a is the acceleration.
Since the bodies are moving simultaneously towards each other, then assume that their initial velocities are zero. Also, at the moment of their meeting, their displacement will be the same, d₁ = d₂.
Assume that the time at which they meet is t, then:
d₁ = 1/2 * 2.4t²
And the equation for the displacement of the second body:
d₂ = 1/2 * 4.8t²
If d₁ = d₂
then, 1/2 * 2.4t² = 1/2 * 4.8t²
Solving this equation for t and substituting it into the equation for d₁ or d₂, the ratio of the displacement of the first body to the displacement of the second body: d₁/d₂ = 2.4/4.8 = 0.5 or 1/2
So, at the moment of their meeting, the displacement of the first body is half of the displacement of the second body.
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What is the magnitude of the resultant vector? Round your answer to the nearest tenth. m
The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.
In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.
When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.
In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.
For example, if the answer is 12.345, we would round it to 12.3.
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a An object is tarown up with a velocity v = 6.02 +7.0j. Calculate the (1) time taken reach the maximum height (ii) the horizontal range (s = 10m/s2).
Answer:
(i) 0.6s (ii) 8.42m
Explanation:
U² = 6.02² + 7²
U = 9.23
angle of projection
tanø = 6.02/7
ø = 40.7
Time of fligt
t = Usinø/g
t = 9.23 sin 40.7/10
t = 0.6
H range = U²sin2ø/g
H = 9.23²sin 81.4/10
H = 8.42m
The time taken reach the maximum height is 0.6s and the horizontal range is 8.42m.
What is Velocity?Velocity is defined as the directional motion of an object which is indicated by the rate of change of position as observed from a particular frame of reference. It is measured by a particular standard of time. It is a vector quantity as it has both magnitude and direction.
It can be expressed as:
v= d/t
Where. v is the velocity in m/s
d is the displacement measured in meter 'm'
t is the time measured in seconds 's'
For above given information,
v = 6.02 +7.0j, so the initial velocity will be u
u² = 6.02² + 7²
u = 9.23m/s
Angle of projection, tanø = 6.02/7
ø = 40.7
Time taken= t = u sinø/g
t = 9.23 sin 40.7/10
t = 0.6s
Horizontal range = u²sin2ø/g
H = 9.23²sin 81.4/10
H = 8.42m
Thus, the time taken reach the maximum height is 0.6s and the horizontal range is 8.42m.
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Suppose that you measure the length of a spaceship, at rest relative to you, to be 400 m. How long will you measure it to be if it flies past you at a speed of u=0.75c?
The spaceship from Part A has a large clock attached to its side. This clock ran at the same rate as your watch when you were in the same reference frame. How much time ?t will pass on your watch as 80 s passes on the clock attached to the ship?
If the captain of ship A fires a missile, counts 10.0 s on his watch, and then fires a second missile, how much time ?t will the captain of ship B measure to have passed between the firing of the two missiles?
The captain of ship B knows that ship A uses 2-m-long missiles. She measures the length of the first missile, once it has finished accelerating, and finds it to be only 0.872 m long. What is the speed u of the missile, relative to ship B?
Answer:
The importance of learning is that it helps the individual to acquire the necessary skills through learning and knowledge so that he can achieve his set goals. An important fact about learning is that it is a means to improve knowledge and gain skills that will help in reaching specific goals.
Explanation:
The importance of learning is that it helps the individual to acquire the necessary skills through learning and knowledge so that he can achieve his set goals. An important fact about learning is that it is a means to improve knowledge and gain skills that will help in reaching specific goals.
Anybody what cloud is this
If the cloud is transparent, milky, thin layers, rain within the next 2 hours, then the cloud you are seeing is most likely a type of altocumulus cloud.
What is altocumulus clouds?Altocumulus clouds are generally characterized by their white or gray color, and can sometimes appear milky or translucent. They often form in layers, and can be thin or thick depending on the conditions.
Altocumulus clouds are typically found at medium altitudes, between 6,500 and 20,000 feet and are often associated with unsettled weather conditions.
While they don't necessarily indicate that rain is imminent, altocumulus clouds can be a sign that a change in the weather is on the way.
Thus, if it is likely to rain in the next 2 hours, then the cloud must be altocumulus clouds.
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WILL GIVE BRAINLESS IF U ANSER ALL CORECTLY
1 What does wind do as it goes up and over a mountain range?
2 What is the climate on the windward side of a mountain range like?
3 What is the climate on the leeward side of a mountain like?
4 What are rain shadow deserts?
5 What are the characteristics (wind, precipitation, vegetation) seen on the windward side of the Sierra Nevada Mountains?
6 What are the characteristics (wind, precipitation, vegetation) seen on the leeward side of the Sierra Nevada Mountains?
Answer:
1-As winds rise up the windward side of a mountain range, the air cools and precipitation falls.
2-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls.
3-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks.
4-Rain shadow deserts are formed because tall mountain ranges prevent moisture-rich clouds from reaching areas on the lee, or protected side, of the range.
5-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks. So there is very little precipitation on the leeward side of a mountain range.
6-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks. So there is very little precipitation on the leeward side of a mountain range.
Explanation:
#6 and 5 are the same
Propose an experiment that could be used to demonstrate that friction is a contact force?
Pls help
help me
Write your answer on the lines below.
4. Are the light waves reflecting off a red stop sign longer or shorter than the waves reflecting off a violet-colored jacket? Explain how you know.
The light waves reflecting off a red stop sign would be longer than the light waves reflecting off a violet-colored jacket. This is because red light has a longer wavelength than violet light.
Light waves and reflectionLight waves, like all waves, are characterized by their wavelength. The wavelength of a wave determines its color, with shorter wavelengths appearing as blue and violet, and longer wavelengths appearing as red and orange.
Because the wavelength of red light is longer than the wavelength of violet light, the light waves reflecting off the red stop sign would be longer than the light waves reflecting off the violet-colored jacket.
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a)
F E
60. The temperature of source and sink of cannot engine are 400K
and 300K respectively. What is its efficiency?
h) 75%
c) 33.3% d) 25%
Answer: 25%
Explanation:
From the question, we are informed that the temperature of source and sink of cannot engine are 400K
and 300K respectively.
The efficiency will be calculated as:
= 1 - t/T
= 1 - 300/400
= 1 - 3/4
= 1/4
= 25%
Question 1
When you stand on a floor the electrons surround your shoes and the floor. What is the force that prevents you from falling through a floor?
a) atomic direction
b) potential energy
c) atomic speed
d) electrical repulsion
Answer:
d) electrical repulsion
Explanation:
When you stand on a floor, the two different bodies i.e your shoes and the floor on which you stand, are in a very close contact, the electrons that surround your shoes and that of the floor exert a repulsive force on each other, also known as Coulomb's force of repulsion or electrical repulsive force.
This electrical repulsive force prevents you from falling through the floor.
A spring stretches 5 cm when a 300-N mass is suspended from it. Calculate the spring constant in N / m .
Answer:
Spring constant in N / m = 6,000
Explanation:
Given:
Length of spring stretches = 5 cm = 0.05 m
Force = 300 N
Find:
Spring constant in N / m
Computation:
Spring constant in N / m = Force/Distance
Spring constant in N / m = 300 / 0.05
Spring constant in N / m = 6,000
A box proceeds along the x-axis and the figure below shows a record of its velocity as a function of time. Every grid line along the vertical axis corresponds to 2.00 m/s and each gridline along the horizontal axis corresponds to 0.500 s. (Enter your answer in m/s^2. Indicate the direction with signs of your answers. Note that t=0 at the intersection of the axes.) a) Determine the average acceleration of the box in the time interval t=0 to t=2.50 s. b) Determine the average acceleration of the box in the time interval t=2.50 s to t=7.50 s. c) Determine the average acceleration of the box in the time interval t=0 to t=10.0 s
Answer:
The answer is "\(\bold{0, 12.8 \ \frac{m}{s^2}, and \ 6.4 \ \frac{m}{s^2}}\)"
Explanation:
For point a:
The average time interval acceleration for the box \(t = 0\ to\ t = 250 \ s:\)
\(\to \alpha_{0 \ to \ 2.50}=\frac{v_f - v_i}{t_f-t_i}=\frac{0-0}{2.50-0}=0\)
For point b:
The average time interval acceleration for the box
\(t = 250 \ s\ to\ t = 750 \ s :\)
\(\to \alpha_{2.50 \ to \ 7.50}=\frac{v_f - v_i}{t_f-t_i}=\frac{32-(-32)}{7.50-2.50}=12.8 \ \frac{m}{s^2}\)
For point c:
The average time interval acceleration for the box \(t = 0\ to \ t = 10 \ s :\)
\(\to \alpha_{2.50 \ to \ 7.50}=\frac{v_f - v_i}{t_f-t_i}=\frac{32-(-32)}{10-0}=6.4 \ \frac{m}{s^2}\)
Chris is in the process of moving to a new house, and he needs to carry out a lot of boxes from the second floor to his pickup truck. The mass of each box is 53 kg. Instead of carrying boxes out one by one, he has set up a smooth, frictionless slope from the second floor to the first floor so that he can slide down boxes one by one. When a box slides down to the first floor, it continues sliding by a distance of 7.8 m toward the entrance of the house, where the pickup truck is parked. There is a small, frictionless ramp connecting to the bed of the pickup truck so the box can be loaded to the truck effortlessly.
See attached image
The first floor is carpeted, and there is a frictional force of magnitude 140 N on the box as it slides on the carpet. The height difference between the first and second floor is 3.2 m, and the height difference between the first floor and the bed of the pickup truck is 0.90 m.
A box is initially at rest on the second floor, and Chris pushes the box toward the slope so that the speed of the box is 2.1 m/s right before it starts sliding down the slope. The second floor is smooth, and the frictional force between the second floor and the box is negligible.
Use g = 10 m/s2 for the acceleration due to gravity.
(1)
What is the work done by Chris on the box when the speed of the box reaches 2.1 m/s?
(2)
What is the speed of the box when it reaches the bottom of the slope (Point B in the diagram)?
(3)
To what speed does the box slow down when it reaches to the bottom of the ramp to the pickup truck?
(4)
What is the speed of the box when it reaches the bed of the pickup truck?
(5)
If instead Chris just pushes the box off the slope from rest (i.e., initial speed is 0 m/s), does the box make it to the bed of the truck? Assume that the magnitude of the frictional force is still 140 N. Show your calculation to support your answer.
To solve the given problems, we'll use the principles of work-energy and conservation of energy. Let's address each question one by one:
(1) What is the work done by Chris on the box when the speed of the box reaches 2.1 m/s?
The work done by Chris on the box is equal to the change in the box's kinetic energy. Since the box starts from rest, the initial kinetic energy is zero. The final kinetic energy can be calculated using the formula:
Kinetic energy = (1/2) * mass * velocity^2
Plugging in the values:
Mass of the box (m) = 53 kg
Final velocity (v) = 2.1 m/s
Kinetic energy = (1/2) * 53 kg * (2.1 m/s)^2
Calculate the value of the kinetic energy, which represents the work done by Chris on the box.
(2) What is the speed of the box when it reaches the bottom of the slope (Point B in the diagram)?
To determine the speed at the bottom of the slope, we'll use the principle of conservation of energy. The total mechanical energy of the box is conserved as it moves from the top to the bottom of the slope.
The initial potential energy at the top of the slope is converted into kinetic energy at the bottom of the slope, neglecting any energy losses due to friction.
Potential energy at the top = m * g * h1
Where:
Mass of the box (m) = 53 kg
Acceleration due to gravity (g) = 10 m/s^2
Height difference between floors (h1) = 3.2 m
Calculate the initial potential energy.
The final kinetic energy at the bottom is given by:
Kinetic energy at the bottom = (1/2) * m * v^2
Where:
Mass of the box (m) = 53 kg
Velocity at the bottom (v) = ?
Equating the initial potential energy to the final kinetic energy, solve for v to find the speed of the box at the bottom of the slope.
(3) To what speed does the box slow down when it reaches the bottom of the ramp to the pickup truck?
Since the ramp connecting the first floor to the bed of the pickup truck is frictionless, there is no external force doing work on the box. Thus, the mechanical energy of the box is conserved as it moves from the bottom of the slope to the bottom of the ramp.
Using the same principle of conservation of energy, equate the final kinetic energy at the bottom of the slope to the initial potential energy at the bottom of the ramp.
Potential energy at the bottom of the ramp = m * g * h2
Where:
Mass of the box (m) = 53 kg
Acceleration due to gravity (g) = 10 m/s^2
Height difference between the first floor and the truck bed (h2) = 0.90 m
Calculate the potential energy at the bottom of the ramp.
Equating the potential energy at the bottom of the ramp to the final kinetic energy, solve for the speed of the box at the bottom of the ramp.
(4) What is the speed of the box when it reaches the bed of the pickup truck?
Since the ramp connecting the first floor to the truck bed is frictionless, there is no external force doing work on the box. The mechanical energy of the box is conserved as it moves from the bottom of the ramp to the truck bed.
Using the same principle of conservation of energy, equate the final potential energy at the bottom of the ramp to the final kinetic energy at the truck bed.
Potential energy at the truck bed = m * g * h
a ballon holds 24L at 45 k . find the volume if the temperature is increased to 911 k
A solid lead sphere of radius 10 m (about 66 feet across!) has a mass of about 57 million kg. If two of these spheres are floating right next to each other (centers 20 m apart) in deep space, the gravitational attraction between the spheres is only 540 N (about 100 pounds). How large would this gravitational force be if the distance between the centers of the two spheres were quadrupled?
If the distance between the centres of the two spheres were doubled, there would be a gravitational force of 60 N.
What is an example of gravitational attraction?The force affecting the Sun and Earth. the cause of the Moon's orbital rotation around the Earth. The ocean's tides are controlled by the force of the Moon. the force that confines all gases to the Sun.
Mass of the lead sphere F = 57 million kg
Initial center distance r = 20m
The gravitational constant of spacetime G = 6.67 * 10⁻¹¹ Nm²/ kg²
Gravitational force of attraction F₁ = 540 N
Newton's law of gravity says that we have;
F = Gm₁m₂ / r
F₁ / F₂ = r₂² / r₁²
F₂ = F₁r₁² / r₂²
F₂ = F₁r₁₂ / (3r₁)²
F₂ =F1 / 9
F₂ = 540 N / 9
F₂ = 60 N
If the space between the centres of the two spheres were to be quadrupled, the gravitational force of attraction would be 60 N.
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what role do control groups play
Answer:
Control groups let the one who is expermenting compare the effect of the varibles in the expermental group.
Explanation:
Use the dimensional analysis and check the correctness of given equation:-
PV= nRT
PV=nRT
Here
P=Pressure
V=Volume
n=Molarity
R=universal gas constant
T=Temperature.
LHS
\(\\ \tt\bull\leadsto PV\)
\(\\ \tt\bull\leadsto [ML^2T^{-2}][M^0L^3T^0]\)
\(\\ \tt\bull\leadsto [ML^5T^{-2}]\)
RHS
\(\\ \tt\bull\leadsto nRT\)
\(\\ \tt\bull\leadsto [M^0L^{3}T^0][M^1 L^2 T^{-2}K^{-1}][M^0L^0T^0K^1]\)
\(\\ \tt\bull\leadsto [ML^5T^{-2}]\)
LHS=RHS
hence verified