Explain TWO ways that your body changes waste product levels to maintain an internal
balance?

Answer:

What led him to change his outlook was because in his experiment, when he fired positively charged alpha particles at a piece of gold foil, he observed that some of the alpha particles were deflected to some degree, and some others bounced back directly toward him.

Explanation:

In his experiment, he fired positively charged alpha particles at a piece of gold foil.

Now, after doing that he observed that some of the alpha particles were deflected to some degree, and some others bounced back directly toward him.

After those observations, he felt that for the order of the alpha particles to have been deflected, they would possibly have been hit or come close to being hit by a positively charged particle in the atom. This made him to conclude that an atom consists mostly of empty space, with a very small and dense but positively charged nucleus at the center. And that this nucleus contains most of the mass of the atom, while the electrons orbit the nucleus.

Answer:

390.6 gram

Explanation:

Mass in gram = no of moles × molar mass

Mass in gram = 21.7×18

= 390.6 gram

Answer:

390.931576 grams

Answer:

d is the correct answer and and

According to Euclid's second postulate, a fundamental principle of Euclidean geometry, a line can be drawn to infinity in both directions. Therefore, the correct option is A.

This implies that a line has no end and can go on indefinitely. This indicates that a line is an endless, unobstructed straight path. This postulate, which serves as a cornerstone of Euclidean geometry, establishes the basic properties of lines.

Euclid's second postulate makes it possible to find geometric relationships, angles and figures in an infinite space by allowing lines to be extended indefinitely. It serves as the basis for many geometric constructions and proofs and has important implications for our understanding of the mathematical properties of lines and angles.

Therefore, the correct option is A.

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Answer:

Should be a 15 imo

Explanation:

N is one, 4H = 4, S 2 because of the 2 and O 8 because of the 4 and the 2 before the S.

Answer:

Title: Investigating the Transformation of Energy

Objective: The objective of this experiment is to observe and analyze the transformation of energy between different forms, such as kinetic, potential, thermal, and electrical energy.

Hypothesis: It is hypothesized that energy can be transformed from one form to another, but the total amount of energy in a closed system remains constant (the law of conservation of energy).

Procedures:

Data Analysis:

Conclusion:

The results of this experiment support the hypothesis that energy can be transformed from one form to another, but the total amount of energy in a closed system remains constant. This experiment demonstrated the transformation of energy between kinetic, potential, thermal, and electrical forms, and showed how energy can be transferred and used to do work. Understanding the transformation of energy is important in many fields, including physics, engineering, and environmental science.

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

\(k = \frac{1}{2} m {v}^{2} \\ \)

m is the mass

v is the velocity

From the question we have

\(k = \frac{1}{2} \times 478 \times {15}^{2} \\ = 239 \times 225\)

We have the final answer as

Hope this helps you

Answer:

a) Melting: An example of melting in everyday life is when an ice cube placed on a warm surface starts to melt and turns into liquid water. Melting is the process in which a solid substance absorbs enough heat energy to transition into a liquid state. The heat energy breaks the bonds holding the particles of the solid together, causing them to gain enough kinetic energy to move more freely and transition to a liquid form.

b) Freezing: Freezing can be observed when water is placed in a freezer and transforms into ice. Freezing is the reverse process of melting. It occurs when a liquid substance loses heat energy and its particles slow down, leading to the formation of a solid structure. The decrease in temperature causes the particles to arrange themselves into an organized pattern, creating a solid state.

c) Condensation: When you see water droplets forming on the surface of a cold beverage on a hot day, that is an example of condensation. Condensation is the process by which a gas or vapor cools down and transforms into a liquid state. It happens when the temperature of the gas or vapor reaches a point where its particles lose enough energy to come together and form liquid droplets.

d) Evaporation: When wet clothes or a puddle of water dries up after exposure to sunlight or air, it is an example of evaporation. Evaporation is the process by which a liquid substance, such as water, turns into a gas or vapor. It occurs when the particles near the surface of the liquid gain enough energy from the surroundings to break free from the liquid phase and enter the gaseous phase.

e) Sublimation: An example of sublimation is the direct conversion of solid dry ice (frozen carbon dioxide) into a gas without passing through a liquid phase. Sublimation is the process in which a solid substance transforms directly into a gas without going through the intermediate liquid phase. It occurs when the substance absorbs enough heat energy to break the bonds between its particles, causing them to transition from a solid state to a gaseous state.

Explanation:

Combustion can be defined as the reaction of a compound with oxygen. The enthalpy of combustion of octane is \(\Delta H_{\rm rxn}\) for \(\rm C_8H_{18}\;+\;25\;O_2\;\rightarrow 8\;CO_2\;+\;9\;H_2O\).

The enthalpy of reaction is the amount of heat energy absorbed or lost by the molecules in the chemical reaction.

The enthalpy of combustion is the amount of heat energy released by the compound in the reaction with oxygen.

The reaction in which heat is liberated with the reaction of a compound with oxygen has an enthalpy of combustion, equivalent to the enthalpy of reaction.

The combustion of octane can be given as:

\(\rm C_8H_{18}\;+\;25\;O_2\;\rightarrow 8\;CO_2\;+\;9\;H_2O\)

Thus, the reaction has combustion energy equivalent to the enthalpy of the reaction is \(\rm C_8H_{18}\;+\;25\;O_2\;\rightarrow 8\;CO_2\;+\;9\;H_2O\). Thus, option B is correct.

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Answer:

It helps us to insure what will the current rate will be to those subject or nartual disaster can conquere

Answer:

good electrical conductor

lustre in appearance

The weight of each stopper can vary based on the material, size, and manufacturing process used, so it is not possible to determine the number of rubber stoppers needed without more information.

Weight is a measure of the force of gravity on an object and is typically measured in units of Newtons (N), pounds (lb), or kilograms (kg).

Average weight, on the other hand, refers to the sum of the weights of a group of objects divided by the number of objects in the group. It provides an estimate of the typical or central value of the weights in the group. The units of average weight are the same as the units used to measure weight.

The number of rubber stoppers needed to contain the same number of stoppers as there are corks in 1.0 kg of corks would depend on the average weight of each type of stopper.

The weight of each stopper can vary based on the material, size, and manufacturing process used, so it is not possible to determine the number of rubber stoppers needed without more information.

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The pH after the following volumes of titrant have been added 0 ml 20 mL 59. 1 mL 60. 0 mL 71. 4 mL 73. 4 mL are 11.89, 11.89, 8.45, 8.45, 7.98, 8.95 respectively.

The reaction between NH3 and HCl can be represented by the following equation: NH3 + HCl → NH4+ + Cl-

To calculate the pH after different volumes of titrant have been added, we need to determine the amount of titrant that has reacted with the analyte and the resulting concentration of the products.

A. 0 mL of titrant (initial state)

At the start, there is no titrant added to the analyte, so the concentration of NH3 is 0.050 M. NH3 is a weak base, so we can use the Kb expression to calculate the concentration of OH-:

\(Kb = [NH4+][OH-] / [NH3]\)

\(1.8 * 10^{-5} = x^2 / (0.050 - x)\)

initial concentration of NH3 is much greater than the initial concentration of HCl, we can assume that the concentration of NH3 does not change significantly during the titration.

\(Kb = x^2 / 0.050\\x = \sqrt{Kb * 0.050} = 1.3 * 10^{-3} M\)

The concentration of OH- is equal to \(1.3 * 10^{-3} M\), so we can calculate the pH:

\(pH = 14 - pOH = 14 - (-log[OH-]) = 11.89\)

Therefore, the pH at the start of the titration is 11.89.

B. 20 mL of titrant

After adding 20 mL of 0.025 M HCl, the volume of the solution is 50 mL (30 mL NH3 + 20 mL HCl). The moles of HCl added is:

moles of HCl = volume x concentration = 0.020 L x 0.025 mol/L = 5 x 10^-4 mol

Since the reaction is a 1:1 reaction, the moles of NH3 remaining is equal to the moles of HCl added.

concentration of NH3 = moles of NH3 / volume of NH3 = (0.050 mol/L x 0.030 L - 5 x 10^-4 mol) / 0.030 L = 0.048 mol/L

Since the concentration of NH3 has decreased, we need to recalculate the concentration of OH- using the new concentration of NH3:

\(Kb = [NH4+][OH-] / [NH3]\\1.8 * 10^{-5} = x^2 / (0.048 - x)\)

Solving for x, we get:

\(x = 1.3 * 10^{-3} M\)

The concentration of OH- is still \(x = 1.3 * 10^{-3} M\), so we can calculate the pH:

pH = 14 - pOH = 14 - (-log[OH-]) = 11.89

Therefore, the pH after adding 20 mL of titrant is still 11.89.

Similarly for  C. 59.1 mL of titrant

The pH after adding 59.1 mL of titrant is 8.45.

D. 60 mL of titrant

The pH after adding 60 mL of titrant is 8.45.

E. 71.4 mL of titrant

The pH after adding 71.4 mL of titrant is 7.98.

F. 73.4 mL of titrant

The pH after adding 73.4 mL of titrant is 8.95.

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Answer:

2A =B + 2C hope that helps

Explanation:

Answer:

I would

Explanation:

I would support the change to the metric system only because it allows children to understand smaller forms of units and measurements. Also, it will allow people in the math and science fields to broaden their knowledge of equations and formulas. Meaning that the scientist and mathematicians will be able to solve more problems in the world right now.  Overall, the education system for the children of the United States would benefit from the change in the measurement system.

Answer:

B

CuO

H2

Explanation:

hydrogen will oxidized to form water

Copper(II) oxide reacts with hydrogen.

\(CuO + H_2\) → \(Cu + H_2O\)

Oxidising agent - \(Cuo\)

Reducing agent - \(H_2\)

A chemical reaction that takes place between an oxidizing substance and a reducing substance.

The oxidizing substance loses electrons in the reaction, and the reducing substance gains electrons.

In the reaction  \(CuO + H_2\) → \(Cu + H_2O\)  

\(Cuo\) is the oxidising agent and  \(H_2\) is the reducing agent because \(Cuo\)  is oxidising  \(H_2\) and \(H_2\) is the reducing agent because it is removing oxygen from \(Cuo\).

Hence, option B is correct.

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Atomic models serve as a fundamental framework for our understanding of matter and its behavior. While it is true that scientific knowledge evolves over time, the constant alteration of atomic models can impede our ability to establish a cohesive and reliable understanding of the atomic structure.

1. Stability of Knowledge: Atomic models provide a basis for explaining and predicting various phenomena in the realm of chemistry and physics. Continually changing these models introduces instability and uncertainty, making it difficult to build upon previous knowledge and establish a consistent understanding of the subject matter.

2. Experimental Validation: Atomic models are developed based on experimental evidence and observations. When a model accurately explains experimental results and is supported by substantial evidence, it is crucial to maintain its stability. Constantly modifying the atomic model can undermine the validity of previous experimental data and hinder our ability to make meaningful comparisons and draw reliable conclusions.

3. Simplified Representations: Atomic models are simplified representations of complex phenomena occurring at the atomic level. They are designed to provide a conceptual framework that aids in understanding and explaining observations. Continual changes to these models can lead to confusion and inconsistency, making it harder for students, researchers, and scientists to grasp the fundamental concepts and apply them effectively.

4. Cumulative Progress: Scientific progress is often built upon the existing body of knowledge. By maintaining a stable atomic model, scientists can build upon established theories and models, refining and expanding them over time. Continual changes to the atomic model can disrupt this cumulative progress, forcing scientists to constantly reassess and relearn foundational concepts instead of focusing on new discoveries and advancements.

5. Practicality and Pedagogy: Stability in atomic models is crucial for educational purposes. By presenting a consistent and stable model, educators can effectively teach students the foundational principles of chemistry and physics. Constant changes can lead to confusion among students and hinder their ability to grasp the core concepts.

In conclusion, advocating for the stability of atomic models is essential to foster a coherent and reliable understanding of matter. While scientific knowledge evolves, maintaining a stable foundation allows for cumulative progress, effective education, and a stronger basis for experimentation and discovery.

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Answer:

Input Mask

Explanation:

In this scenario, the best tool for Raul to use would be an Input Mask. When dealing with Microsoft Access or any other database tool, Input Masks are a great way of validating data inputs so that they always match the desired format. In this case, Raul would need to use input mask and apply the desired format while comparing it to the order date, therefore, making sure that it is always a minimum of 2 days after before it is accepted as a valid entry in the database.

A solution prepared by accurately weighing a pure solute is called a "Stock Solution."

The degree to which the average value of an object's displayed weight is near to the object's actual weight is a measure of a scale's accuracy. A scale is accurate to within 0.20 lb in 200 lb, or 0.1%, if it shows that a 200 lb reference weight weighs 200.20 lb on average.

To make a stock solution, weigh out the proper amount of a pure solid or measure out the proper amount of a pure liquid, put it in the right flask, and then dilute it to the desired volume. Depending on the intended concentration unit, many methods can be used to measure the reagent.

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Prairie dogs are a type of squirrels and they are classified in the group of rodents. The family of prairie dog is Sciuridae.

The taxonomical classification of an animal is to indicates its kingdom, phylum, class, order,  family, genus and species. All the known animals, plants and other livings are classified to these 7 categories.

The prairie dogs are ground squirrels usually seen in the prairie grass lands. They are in the mammalian class and in the order of Rodentia.

They are classified  to the family of Sciuridae.

Genus of prairie dogs is cynomys and their species can be of various types such as ludovicianus, gunnisoni, mexicanus etc based on the regions they reside.

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In a reaction sequence involving an alkyne and reagents, step 1) deprotonates the alkyne using a strong base, then forms a new carbon-carbon bond with an electrophilic alkene, and lastly adds an alcohol across the double bond via oxymercuration-demercuration. The major product is an alcohol, but its specific structure depends on the starting materials.

The given reaction sequence involves the following steps:

NaNH₂

Eti H-C=C—H

HgSO₄, H2SO₄, H2O, R-OH

Step 1) involves the treatment of an alkyne with NaNH₂, which is a strong base. The base will deprotonate the alkyne to form an anion.

Step 2) involves the reaction of the alkyne anion with Eti H-C=C—H. The alkyne anion acts as a nucleophile and attacks the electrophilic alkene, forming a new carbon-carbon bond.

Step 3) involves the addition of HgSO₄, H2SO₄, H₂O, and an alcohol (R-OH). This reaction is known as oxymercuration-demercuration and involves the addition of a mercuric acetate (Hg(OAc)₂) across the double bond of the alkene. This forms a mercurinium ion, which is then attacked by water in a nucleophilic addition reaction. Finally, the mercuric acetate is removed by reaction with sodium borohydride, resulting in the formation of the alcohol product.

The major product expected from this reaction sequence is the alcohol formed in step 3). The specific structure of the alcohol cannot be determined without more information about the starting materials.

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Complete question :

Choose the major product that is expected for the following reaction sequence: 1) NaNH₂ 2) Eti H-C=C—H 3) HgSO H₂SO₄ H₂0 R 0. OH

Answer:

1.476 mol molecules

Explanation:

The epimoric carbon where a ring closes is also known as the anomeric carbon. The epimoric carbon is a carbon atom in a sugar molecule that has a different configuration of substituents than another sugar molecule. When a sugar molecule forms a ring, the epimoric carbon where the ring closes is known as the anomeric carbon.

The anomeric carbon is the carbonyl carbon (C=O) that becomes a new chiral center when the ring is formed. Epimoric carbon is the chiral centre due to which two disteriomers are different from each other like glucose and mannose are epimors to each other because they are different at only C1 carbon also galactose and glucose are also C4 epimers to each other. So epimoric carbon can be 1,2,3 or any but anomeric carbon will always be C1 like alpha glucose and beta glucose are anomers to each other also reducing sugars are those which have free anomeric carbon.

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Answer:

I can't see the compound image but the safe guess here is that there is now noble gas config for the molecule so likely X has 7 valence electrons kind of like Na being W and Cl being X

Explanation:

Answer:125ml - volume of phosphoic acid

Explanation:

The equation of the reaction is

H3PO4 + 3 NaOH ---> Na3PO4 + 3H2O

Such that I mole of H3PO4 reacts with 3 moles of  NaOH to produce the products above.

Given that

M1= Molarity of phosphoric acid = 7.48x10^-2 M

n1= number of moles of phosphoric acid = 1

V1=? ml

M2= Molarity  of Sodium hydroxide =0.244 M

V2= volume of sodium hydroxide= 115ml

n2=number of moles of sodium hydroxide = 3

Using the Dilution equation formulae,

M1V1/n1 = M2V2/n2

7.48X10-2 x V1 /1= 0.244M x 115ml/3

V1=0.244Mx115mlx1/0.0748M X 3

V1= 28.06/0.2244= 125.04ml

V1=125.04ml rounded up to 125ml

The energy used to heat a 20kg block initially at 20°C is 792J.

The energy of a substance can be calculated by using the following expression:

Q = mc∆T

Where;

According to this question, 20kg concrete block is at 20 degrees celsius and is heated to 65 degrees celsius. The energy used to heat the block is as follows:

Q = 20 × 0.88 × {65°C - 20°C}

Q = 792J

Therefore, 792J is the energy needed to heat the concrete block.

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Answer:exo becuse it is like temp

Explanation: