Figure 1 shows the internal circuitry for a charger prototype. You, the development engineer, are required to do an electrical analysis of the circuit by hand to assess the operation of the charger on different loads. The two output terminals of this linear device are across the resistor, RL. You decide to reduce the complex circuit to an equivalent circuit for easier analysis. i) Find the Thevenin equivalent circuit for the network shown in Figure 1, looking into the circuit from the load terminals AB. (9 marks) R1 A R2 ww 40 30 20 V R460 RL B Figure 1 ii) Determine the maximum power that can be transferred to the load from the circuit. (4 marks) 10A R3 30

The energy generated by Honda CBR1000RR with an inline four-cylinder spark-ignition engine is 154.8 kW when it is at a speed of 270 km/h on the highway.

Speed of the superbike = 270 km/hPower generated by the engine of superbike = 7.8 kW/cylinderNumber of cylinders in the engine = 4We can find the total energy generated by the engine of superbike using the formula:Power = Energy / timeWe can rewrite the formula as:Energy = Power x timeWe know that the power generated by the engine is 7.8 kW/cylinder and there are 4 cylinders. So the total power generated by the engine can be given by:Total power = Power per cylinder x Number of cylinders= 7.8 kW/cylinder x 4= 31.2 kWWe need to convert the speed of superbike to meters per second to calculate the time taken by it to cover a certain distance.

Now, we need to find the power generated by the engine when the superbike is at a speed of 270 km/h on the highway.We can use the formula:Power = Energy / timeWe can rewrite the formula as:Energy = Power x timeWe have already found the time taken by the superbike to cover a certain distance. It is 3600 seconds.Now, we can substitute the values in the formula:Power = Energy / time= 112320 kJ / 3600 s= 31.2 kWThe energy generated by Honda CBR1000RR with an inline four-cylinder spark-ignition engine is 154.8 kW when it is at a speed of 270 km/h on the highway.

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Answer:

I have attached the diagram for this question below. Consult it for better understanding.

Find the cross sectional area AB:

A = (1.6mm)(12mm) = 19.2 mm² = 19.2 × 10⁻⁶m

Forces is given by:

F = 2.75 × 10³ N

Horizontal Stress can be found by:

σ (x) = F/A

σ (x) = 2.75 × 10³ / 19.2 × 10⁻⁶m

σ (x) = 143.23 × 10⁶ Pa

Horizontal Strain can be found by:

ε (x) = σ (x)/ E

ε (x) = 143.23 × 10⁶ / 200 × 10⁹

ε (x) = 716.15 × 10⁻⁶

Find Vertical Strain:

ε (y) = -v · ε (y)

ε (y) = -(0.3)(716.15 × 10⁻⁶)

ε (y) = -214.84 × 10⁻⁶

For L = 0.05m

Change (x) = L · ε (x)

Change (x) = 35.808 × 10⁻⁶m

For W = 0.012m

Change (y) = W · ε (y)

Change (y) = -2.5781 × 10⁻⁶m

For t= 0.0016m

Change (z) = t · ε (z)

where

ε (z) = ε (y) ,so

Change (z) = t · ε (y)

Change (z) = -343.74 × 10⁻⁹m

A = A(final) - A(initial)

A = -8.25 × 10⁻⁹m²

(Consult second picture given below for understanding how to calculate area)

The resulting change in the 50-mm gauge length; the width of portion AB of the test coupon; the thickness of portion AB; the cross- sectional area of portion AB are respectively; Δx = 35.808 × 10⁻⁶ m; Δy = -2.5781 × 10⁻⁶m; Δ_z = -343.74 × 10⁻⁹m; A = -8.25 × 10⁻⁹m²

Let us first find the cross sectional area of AB from the image attached;

A = (1.6mm)(12mm) = 19.2 mm² = 19.2 × 10⁻⁶m

We are given;

Tensile Load; F = 2.75 kN = 2.75 × 10³ N

Horizontal Stress is calculated from the formula;

σₓ = F/A

σₓ = (2.75 × 10³)/(19.2 × 10⁻⁶)m

σₓ = 143.23 × 10⁶ Pa

Horizontal Strain is calculated from;

εₓ = σₓ/E

We are given E = 200 GPa = 200 × 10⁹ Pa

Thus;

εₓ = (143.23 × 10⁶)/(200 × 10⁹)

εₓ = 716.15 × 10⁻⁶

Formula for Vertical Strain is;

ε_y = -ν * εₓ

We are given ν = 0.30. Thus;

ε_y  = -(0.3) * (716.15 × 10⁻⁶)

ε_y  = -214.84 × 10⁻⁶

A) We are given;

Gauge Length; L = 0.05m

Change in gauge length is gotten from;

Δx = L * εₓ

Δx = 0.05 × 716.15 × 10⁻⁶

Δx = 35.808 × 10⁻⁶ m

B) From the attached diagram, the width is;

W = 0.012m

Change in width is;

Δy = W * ε_y

Δy = 0.012 * -214.84 × 10⁻⁶

Δy = -2.5781 × 10⁻⁶m

C) We are given;

Thickness of plate; t = 1.6 mm = 0.0016m

Change in thickness;

Δ_z = t * ε_z

where;

ε_z = ε_y

Thus;

Δ_z = t * ε_y

Δ_z = 0.0016 * -214.84 × 10⁻⁶

Δ_z = -343.74 × 10⁻⁹m

D) The change in cross sectional area is gotten from;

ΔA = A_final - A_initial

From calculating the areas, we have;

A = -8.25 × 10⁻⁹ m²

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The 1/7-power-law velocity profile is a better representation of the velocity profile in a turbulent boundary layer than the parabolic laminar boundary-layer velocity profile.

What is velocity?
Velocity is the rate at which an object moves in a certain direction. It is a vector quantity, meaning it has both magnitude (the speed) and direction. Velocity is often expressed as the rate of change of displacement, which is the distance an object travels in a certain direction. Velocity is the change in position over time; the faster an object moves, the greater the velocity. Velocity is important in physics because it is used to calculate the acceleration of an object, the force of gravity, and the momentum of a moving object. It is also used to measure the speed of sound and the speed of light. Velocity is a fundamental concept in physics, and it is used to describe and measure a variety of physical phenomena.

This is because the former has a higher velocity near the wall and a lower velocity near the centerline, which is more representative of the actual velocity profile in a turbulent boundary layer.
The 1/7-power-law velocity profile is represented by the equation u/U = (y/delta)1/7 and the parabolic laminar boundary-layer velocity profile is represented by the equation u/U = (y/delta)2.
When these two equations are plotted on the same graph, with y/delta on the ordinate and u/U on the abscissa, the 1/7-power-law velocity profile is seen to have a higher velocity near the wall and a lower velocity near the centerline, which is more representative of the actual velocity profile in a turbulent boundary layer.

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Note that between 1960 and 2000, per capita generation of solid waste, increased. After 2000, per capita generation declined.

Note that per capital waste generation is the amount of waste generated by each individual. It is computed by dividing the total amount of waste in tones by the total number of people in that area.

Waste generation encompasses all items abandoned, whether recycled or disposed of in a landfill. Residential and commercial trash generation rates can be used to evaluate the impact of new projects on the local waste stream.

Waste Generated was estimated as the sum of Waste Diverted plus Waste Disposed of (in tonnes).

The frequency with which solid garbage is collected. Population characteristics include, for example, income and education levels, as well as occupational classifications. The extent to which garbage can be salvaged and recycled. Legislation governing the creation, collection, and disposal of solid waste.

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Specifications are an opportunity for the designer to outline and communicate their design requirements and objectives.

This includes detailing the materials, dimensions, and overall design aesthetic of the project. By providing clear and concise specifications, the designer is able to ensure that their vision is accurately reflected in the final product. Additionally, specifications can serve as a reference for the designer to make sure that their design meets any necessary regulations or standards. Overall, the specifications of the designer are a crucial tool for the designer to effectively and communicate their design intentions and ensure that their project is successfully executed.

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Answer:

  0.42 kg

Explanation:

Heat is proportional to mass by way of the conversion factor that is the inverse of the specific heat.

  \(\dfrac{63000\text{ J}}{\dfrac{3000\text{ J}}{\text{kg$\cdot$K}}\cdot(65-15)\text{ K}}=0.42\text{ kg}\)

The mass of the liquid is about 0.42 kg.

Technical practice incorporates build-time identification of security vulnerabilities in the code is  Penetration testing.

A penetration test, sometimes referred to as a pen test or ethical hacking, is a legitimate simulated cyberattack on a computer system that is carried out to analyze the system's security. This is distinct from a vulnerability assessment.

In order to identify and illustrate the financial effects of a system's vulnerabilities, penetration testers employ the same tools, strategies, and procedures as attackers. Reconnaissance, scanning, vulnerability assessment, exploitation, and reporting are the five stages of a penetration test.

Penetration testing is a technical activity that includes build-time discovery of security vulnerabilities in the code.

Penetration tests are essential to an organization's security because they teach staff members how to respond to any kind of intrusion from a malicious party. Pen tests are a method of determining whether a company's security procedures are actually effective.

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Answer:

No. of transistors = \($4.1524 \times 10^{10}$\) transistors

Explanation:

Given that:

N = \($1920 \times 10^{0.163(Y-1980)}$\)

Y = 2025

N = \($1920 \times 10^{0.163(2025-1980)}$\)

N = \($4.1524 \times 10^{10}$\) transistors

Now at Y = 1980

Number of transistors N = 1920

Therefore,

\($1000 = 10^{0.163(Y-1980)}$\)

\($\log_{10} 1000=0.163(Y-1980)$\)

\($\frac{3}{0.163}=Y-1980$\)

18 ≅ 18.4 = Y - 1980

Y = 1980 + 18

   = 1998

So, to increase multiples of 1000 transistors. it takes 18 years.

Technician A is right due to the fact if one facet is exceptional in peak it'll motive a pull. Ride height motive camber and need to be corrected earlier than any alignment adjustments.

To check ride height you could observe those steps:

Ride height or floor clearance may be defined as the quantity of area among the bottom of an vehicle tire and the bottom factor of the vehicle (normally the axle); or, greater properly, to the shortest distance among a flat, stage surface, and the bottom a part of a automobile apart from the ones elements designed to touch the floor.

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Answer:

approaching a lady or a man

Answer:fall arrest harness

Explanation:cuz it’s just right

Answer:

I can help but I need to know what it looking for

The correct option for a class of decision-making shortcuts built from learning and experience in the world is a. Heuristics. Heuristics are mental shortcuts that help us make decisions quickly and efficiently.

Heuristics are cognitive strategies that simplify complex decision-making processes by using shortcuts based on previous experiences, knowledge, or patterns we have observed. These shortcuts allow us to quickly make decisions in various situations without having to analyze all the available information thoroughly.

While heuristics can be helpful in many cases, they can also lead to biases and errors in judgment. It's important to recognize when using heuristics might be appropriate and when more careful analysis is needed.

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Answer:

Explanation:

1. The PDU (Protocol Data Unit) at layers 2, 3, and 4 used to transmit an HTTP GET packet are as follows:

- Layer 2: Ethernet II frame (Ethernet PDU)

- Layer 3: Internet Protocol (IP) packet (IP PDU)

- Layer 4: Transmission Control Protocol (TCP) segment (TCP PDU)

To locate the specific PDUs for an HTTP GET packet in Wireshark:

1. Open Wireshark and load the captured packet trace.

2. Find the HTTP GET packet in the Packet List.

3. Click on the HTTP GET packet to select it.

4. In the Packet Detail window, navigate to the "Frame" section to view the Ethernet II frame details (Layer 2).

5. Scroll down to the "Internet Protocol" section to see the IP packet information (Layer 3).

6. Further down, in the "Transmission Control Protocol" section, you will find details about the TCP segment (Layer 4).

2. To determine the number of different HTTP GET packets sent by a browser, inspect the captured packets. Look for packets with the "GET" method in the "Info" column of the Packet List. Counting the unique occurrences of such packets will give you the number of different HTTP GET packets sent by the browser.

3. Five other protocols that Wireshark may display in the Packet List window, after clearing the filter, include:

- DNS (Domain Name System)

- ICMP (Internet Control Message Protocol)

- ARP (Address Resolution Protocol)

- TLS (Transport Layer Security)

- DHCP(Dynamic Host Configuration Protocol)

By reviewing the Packet List window, you can identify and list at least these five additional protocols displayed alongside HTTP.

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The type of thinking are you engaging in when you ask about the pay and benefits of a job you are considering is known as constructive. Thus, the correct option for this question is A.

The different types of thinking may include convergent or analytical thinking, divergent thinking, critical thinking, and creative thinking. Each of these types has specific attributes and a set of functions in order to make a specific criterion for individuals.

Constructive Thinking refers to a set of cognitive productive and counterproductive automatic habitual thoughts that affects one's ability to think in a manner that solves problems. It basically includes the ability to solve problems in everyday life with minimal stress.

Therefore, constructive thinking is the type of thinking that are you engaging in when you ask about the pay and benefits of a job you are considering. Thus, the correct option for this question is A.

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Programming for generalization of a behavior involves teaching the behavior in a variety of contexts, settings, and with different people or stimuli.

This helps ensure that the behavior will be displayed in a variety of situations and not just in the specific context in which it was originally taught. For example, if you are teaching a child to say "please" when asking for something, you would want to practice this behavior in different settings (e.g., at home, at school, at the grocery store) and with different people (e.g., parents, teachers, friends).

Programming for maintenance of a behavior involves providing reinforcement for the behavior over time to ensure that it continues to be displayed. This can be done through intermittent reinforcement, in which the behavior is reinforced on a variable schedule (e.g., sometimes the behavior is reinforced, sometimes it is not). For example, if you are teaching a child to clean up their toys, you might provide reinforcement (e.g., praise, a small treat) every time they clean up for the first few weeks, but then gradually switch to providing reinforcement only occasionally. This helps ensure that the behavior will continue to be displayed even when reinforcement is not always provided.

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Programming for generalization of a behavior involves teaching the behavior in a variety of contexts, settings, and with different people or stimuli.

This helps ensure that the behavior will be displayed in a variety of situations and not just in the specific context in which it was originally taught. For example, if you are teaching a child to say "please" when asking for something, you would want to practice this behavior in different settings (e.g., at home, at school, at the grocery store) and with different people (e.g., parents, teachers, friends).

Programming for maintenance of a behavior involves providing reinforcement for the behavior over time to ensure that it continues to be displayed. This can be done through intermittent reinforcement, in which the behavior is reinforced on a variable schedule (e.g., sometimes the behavior is reinforced, sometimes it is not). For example, if you are teaching a child to clean up their toys, you might provide reinforcement (e.g., praise, a small treat) every time they clean up for the first few weeks, but then gradually switch to providing reinforcement only occasionally. This helps ensure that the behavior will continue to be displayed even when reinforcement is not always provided.

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Answer:

zsxdcffffusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernameusernamev

Explanation:

Answer:

Explanation: Changing Lanes Tip 1: scan Explanation: When scanning you check all your mirrors while looking at the road in between, this keeps you aware of your surroundings. Tip 2: check blind spotExplanation: When checking your blind spot you quickly glance to which way you want to change lanes for no more than 2 seconds. Your peripheral vision will pick up any lights or movement. Tip 3: use signals Explanation: When changing lanes use you signal to alert others around you even if no ones around

A delocalised electron is an electron in an atom, ion, or molecule that is not connected to a single atom or covalent bond.

Instead of single and double bonds, a circle is used to represent delocalized electrons in ring structures. This implies that the chemical bond and electrons are both movable. The conductivity of the atom, ion, or molecule is influenced by delocalized electrons. Typically, materials containing a lot of delocalized electrons are particularly favorable. Pi bonds comprised of loosely held electrons are found in double bonds; as a result, the pi bonds move, leading to the delocalization of the loosely held electrons. More energy stabilization in the molecule results from delocalization.

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(a) To determine the Schmid factor for all slip systems in a single crystal of iron (bcc) pulled in tension along the [120] direction, we need to consider the valid slip systems and their corresponding Schmid factors.

In bcc crystals, slip occurs on specific slip systems characterized by a combination of crystallographic planes and directions. The valid slip systems in iron (bcc) include {110}<111>, {112}<111>, and {123}<111>.

To calculate the Schmid factor for each slip system, we need to determine the dot product between the slip direction and the applied tensile stress direction, as well as the dot product between the slip plane normal and the tensile stress direction.

For example, for the {110}<111> slip system:

Slip direction: [110]

Slip plane normal: [111]

Tensile stress direction: [120]

Schmid factor = (Dot product of slip direction and tensile stress direction) * (Dot product of slip plane normal and tensile stress direction)

By calculating the dot products for each slip system and applying the formula, we can determine the Schmid factors.

(b) The tensile stress at which the crystal will flow plastically depends on the critical resolved shear stress (CRSS) for the slip system with the highest Schmid factor. The CRSS represents the stress required to initiate slip in a particular slip system.

Once we identify the slip system with the highest Schmid factor, the corresponding CRSS value can be obtained from experimental data or material properties. The tensile stress at which plastic flow will occur is equal to or greater than the CRSS for that slip system.

It's important to note that the exact values for Schmid factors, CRSS, and the tensile stress required for plastic flow can vary depending on the specific crystallographic orientation and material properties of the iron (bcc) single crystal.

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Answer:

The classification of the concern is listed in the interpretation segment below.

Explanation:

(a)...

Simple cubic lattice

\(a=2r\)

Now,

The unit cell volume will be:

\(=a^3\)

\(=(2r)^3\)

\(=8r^3\)

At one atom per cell, atom volume will be:

\(=(1)\times (\frac{4 \pi r^3}{3})\)

Then the ratio will be:

\(Ratio=\frac{\frac{4 \pi r^3}{3}}{8r^3}\times 100 \ percent\)

        \(=52.4 \ percent\)

(b)...

Diamond lattice

The body diagonal will be:

\(d=8r=a\sqrt{3}\)

       \(a=\frac{8}{\sqrt{3}}r\)

The unit cell volume will be:

\(=a^1\)

\(=(\frac{8r}{\sqrt{3}})^1\)

At eight atom per cell, the atom volume will be:

\(=8(\frac{4 \pi r^1}{3})\)

Then the Ratio will be:

\(Ratio=\frac{8(\frac{4 \pi r^1}{3})}{(\frac{8r}{\sqrt{3}})^1}\times 100 \ percent\)

        \(=34 \ percent\)

Note: percent = %

Answer:

30that is the answer . . . . . . . . . .. . . . .

The gage pressure of a water column 30 m high is 294 kPa.

The gage pressure of a water column is directly proportional to its height and the density of water. In this case, the density of water is assumed to be 1000 kg/m3.

To find the gage pressure of a water column 30 m high, we can use the following equation:

P = ρ * g * h

Where:

P is the gage pressure,

ρ is the density of water,

g is the acceleration due to gravity, and

h is the height of the water column.

First, let's calculate the gage pressure of the water column 10 m high using the given information:

P1 = ρ * g * h1

= 1000 kg/m3 * 9.8 m/s2 * 10 m

= 98,000 N/m2

Since 1 N/m² is equal to 1 Pascal (Pa), the gage pressure of the water column 10 m high is 98,000 Pa or 98 kPa.

Now, let's find the gage pressure of the water column 30 m high using the same formula:

P2 = ρ * g * h2

= 1000 kg/m3 * 9.8 m/s2 * 30 m

= 294,000 N/m2

Converting the gage pressure to kPa:

P2 = 294,000 N/m2

= 294 kPa

Therefore, the gage pressure of a water column 30 m high is 294 kPa.

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Answer:

ICC

Explanation:

The International Building Code (IBC) is a model building code developed by the International Code Council (ICC). It has been adopted for use as a base code standard by most jurisdictions in the United States.

With a rated 240 V, a 10 kW heating element would unsurprisingly yield approximately 34,121.42 BTU/h.

To determine the power of a 10 kW heating element functioning at a constant 240 V in BTU/h (British Thermal Units per hour), we must initially convert from kilowatts to watts and then use an appropriate conversion factor.

1 kW = 1,000 W

So, 10 kW equates to 10,000 W

To arrive at BTU/h, we can apply the following conversion factor:

1 W = 3.412142 BTU/h

Thus, by multiplying the wattage amount with the conversion rate, we come up with the total BTU/h output:

BTU/h = 10,000 W * 3.412142 BTU/h/W = 34,121.42 BTU/h

To conclude, with a rated 240 V, a 10 kW heating element would unsurprisingly yield approximately 34,121.42 BTU/h.

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Answer:

24.52% efficiency

Explanation:

Knowns:

Mass = 50 kg

Height = 6 m

Time = 3 s

Indicated Power = 4 kW = 4000 W

Acceleration Due to Gravity = 9.81 m/s^2

Actual Power = Potential Energy / Time = mgh / t

Actual Power = (50 kg * 9.81 m/s^2 * 6 m) / 3 s = 981 W

Motor Efficiency = (Actual Power / Indicated Power) * 100 = (981 W / 4000 W) * 100 = 24.52%

The ideal response for the age standard deviation would be zero.

A standard deviation (or σ) is a measure of how distributed the data is in reference to the mean. When the standard deviation is low, the data are concentrated around the mean, and when it is large, the data are widely dispersed.

They invited 25 persons who recently turned 100 years old, so the majority of attendees will be between the ages of 100 and 102. There is extremely little likelihood that anyone will be older than 102.

Since the majority of the data are centered at 100, the standard deviation will be zero or very close to it.

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Which of the following best represents the standard deviation for the ages of the new centenarians?

0

100

30

25

For moving muons in the given scenario, the values of β, K, and p are 0.824, (pc² / 104.977 MeV/c²), and √[(K + m0c²)²/c⁴ - m0²c²/c⁴] / c, respectively. These values are obtained through calculations using the provided data and relevant formulas.

The mass of a muon is 207 times the electron mass; the average lifetime of muons at rest is 2.20 μs. In a certain experiment, muons moving through a laboratory are measured to have an average lifetime of 6.85 μs.

The rest energy of the electron is 0.511 MeV. Formulas:Total energy of the particle: E = (m²c⁴ + p²c²)¹/², Where,

To calculate the value of β for moving muons, we need to calculate the velocity of the muons. To calculate the velocity of the muons, we can use the concept of the lifetime of the muons. The average lifetime of muons at rest is 2.20 μs.

The moving muons have an average lifetime of 6.85 μs. The time dilation formula is given byt = t0 / (1 - β²)c², where,

Hence,t0 = t / (1 - β²)c²t0 = 2.20 μs / (1 - β²)c²t = 6.85 μs. From these two equations, we can calculate the value of β.6.85 μs / t0 = 6.85 μs / (2.20 μs / (1 - β²)c²)β² = 1 - (2.20 μs / 6.85 μs)β² = 0.679β = 0.824. Hence, the value of β is 0.824.

To calculate the value of K for moving muons, we need to calculate the total energy of the muons. The rest mass of the muon is given bym0 = 207 × 0.511 MeV/c²m0 = 104.977 MeV/c².

The total energy of the muon is given byE = (m²c⁴ + p²c²)¹/²E = (104.977 MeV/c²)²c⁴ + (pc)²K = E - m0c²K = [(104.977 MeV/c²)²c⁴ + (pc)²] - (104.977 MeV/c²)c²K = pc² / (104.977 MeV/c²). Hence, the value of K for moving muons is pc² / (104.977 MeV/c²).

To calculate the value of p for moving muons, we can use the value of K calculated in p = √(E²/c⁴ - m0²c²/c²) / cHere,E = (m²c⁴ + p²c²)¹/²E²/c⁴ = m²c⁴/c⁴ + p²p²c²/c⁴ = (K + m0c²)²/c⁴p = √[(K + m0c²)²/c⁴ - m0²c²/c⁴] / c. Hence, the value of p for moving muons is √[(K + m0c²)²/c⁴ - m0²c²/c⁴] / c.

Therefore, the values of β, K, and p are 0.824, (pc² / 104.977 MeV/c²), and √[(K + m0c²)²/c⁴ - m0²c²/c⁴] / c respectively.

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Both cultures imposed rigid moral standards. Sometimes works of art and architecture challenge our perceptions of what was formerly thought to be feasible and what our forefathers were capable of.

An excellent example is the defunct megalithic capital of Nan Madol, which is situated in a lagoon next to the island of Pohnpei in the Federated States of Micronesia in the Pacific Ocean. By stating that over a period of four centuries, the people of Pohnpei moved an average of 1,850 tons of basalt per year—and no one is quite sure how they did it—archaeologist Rufino Mauricio helps us put these enormous amounts into perspective.

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The allowable normal strength in the c-section is 48000 pounds per square inch.

The allowable stress depends on both the factor of safety imposed on the object and the yield strength or stress at which an object will be permanently damaged. To calculate the allowable normal strength we can divide the yield strength by the factor of safety.

To determine the allowable normal strength output we can use this equation below:

The allowable normal strength = The number yield strength : A stress-concentration factor

The number yield strength is 84 kpsi.

Then convert kpsi to psi : 84 kpsi = 84000 psi

A stress-concentration factor is 1.75

The formula to find allowable normal strength output is:

84000 psi : 1.75 = 48000

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Answer:

Placement.

Explanation:

SAE is an acronym for Supervised Agricultural Experience programs and it is typically a planned, practical-based program designed to help students develop competent skills and experience in their various career choice. Basically, it enhances the academic knowledge and agricultural skills acquired by the students in the classroom.

Generally, there are four (4) main types of Supervised Agricultural Experience Programs;

1. Entrepreneurship SAE.

2. Exploratory SAE.

3. Research and Experimentation SAE.

4. Placement SAE.

A non-entrepreneurship, work-based, agricultural type of Supervised Agricultural Experience program (SAE), in which a student learns and gains skills in a paid or unpaid position describe a placement.

Some examples of organizations or businesses that provide placement SAE to students includes; lawn services, veterinary clinics, soil conservation firms, livestock farms, floral shops, grain farms etc.

Answer:

Placement

Explanation: