Answer: Voltage
Explanation: EDGE 2020
Answer: Voltage
Explanation:
Please help me
27. A 20 kg object is at rest. A 6 N force pulls to the right on
the object for 10 seconds.
A) Find the impulse on the object.
B) Find the final momentum of the object.
C) What is its final velocity?
Answer:
a. 60 N*s
b. 60 (kg*m)/s
c. 3 m/s
Explanation:
Givens:
m = 20 kg
v_i = 0 m/s
t = 10 s
F = 6 N
a) Impulse:
I = F*t
I = 6 N*10 s
I = 60 N*s
b) Momentum:
p = v*m
F = m(a)
a = F/m
a = 6 N/20 kg
a = 0.3m/s^2
a = (v_f -v_i)/t
v_f = (0.3 m/s^2)*10 s
v_f = 3.0 m/s
p = 3 m/s*20 kg
p = 60 (kg*m)/s
c. Final velocity
a = (v_f -v_i)/t
v_f = (0.3 m/s^2)*10 s
v_f = 3.0 m/s
The impulse, momentum and final velocity can all be obtained from Newton's second law.
Let us recall that the impulse is obtained as the product of force and time.
Impulse = Force × time
Impulse = 6 N × 10 s = 60 Ns
From Newton's second law of motion;
F.t = mv - mu
Since the object was initially at rest;
F.t = mv
Hence, the final velocity of the object is 60 Kgms-1
The final velocity is obtained from;
F.t = mv
v = F.t/m
v = 6 × 10/20
v = 3 m/s
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Jenny puts a book on her desk. Jenny’s book has an area of 200 cm2.It exerts a pressure of 0.05 N/cm2 on the desk. What is the weight of the book? *
light traveling in diamond is incident on a 3 cm thick piece of sapphire. it enters the sapphire at an angle of 50 degrees as shown. when it reaches a third material, it undergoes total internal reflection. (a) what is the incident angle theta1 of the light in the diamond?
The incident angle θ1 of the light in the diamond is approximately 7.91 degrees.
The incident angle θ1 of the light in the diamond can be calculated using the Snell's law, which states that the ratio of the sine of the incident angle to the sine of the refracted angle is equal to the ratio of the speed of light in the medium of incidence (diamond) to the speed of light in the medium of refraction (air).
Using the values given in the question:
The angle of incidence θ1 = 50 degrees
The refractive index of diamond (n1) = 2.419
The refractive index of air (n2) = 1.000
The speed of light in a vacuum (c) = 299,792,458 meters per second
We can calculate the incident angle θ1 using the Snell's law:
sin(θ1) / sin(θ) = (c/n1) / (c/n2)
sin(θ1) = (c/n1) / (c/n2) * sin(θ)
θ1 = (c/n1) / (c/n2) * sin(theta)
Since the sine of an angle is always between -1 and 1, we can solve for θ1:
0.5 = (299,792,458 / 2.419) / (299,792,458 / 1.000) * sin(theta)
sin(θ1) = 0.5 / (299,792,458 / 1.000) * sin(θ)
sinθ1) = 0.5 / (2.998 x \(10^6\)) * sin(θ)
sin(θ1) = 0.5 / 7.91 x \(10^-5\) * sin(theta)
θ1= 7.91 x \(10^-5\) * sin(theta)
Therefore, the incident angle θ1 of the light in the diamond is approximately 7.91 degrees.
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The author of a textbook starts to describe the motion of an object thrown horizontally from a cliff in the following way. " The horizontal velocity and the vertical velocity of the objects motion are independent and ....'
A) Explain the meaning of the three phrases printed in italics.
B) State how the two velocities mentioned would vary as the object fell.
C) If the object described above is thrown horizontally at 15ms-1 and the vertical Cliff is 80 m high calculate:
I) the time taken for the object to reach the ground
ii) The distance from the foot of the cliff to where the object strikes the ground.
Use g= 10ms-2
Answer:
Hope I helped!`
Explanation:
A) The phrase "horizontal velocity" refers to the speed at which the object is moving horizontally, while the phrase "vertical velocity" refers to the speed at which the object is moving vertically. The phrase "independent" means that one velocity does not affect the other.
B) The horizontal velocity would remain constant, while the vertical velocity would increase due to the acceleration due to gravity.
C)
I) The time taken for the object to reach the ground can be calculated using the equation:
t = sqrt(2h/g)
where h is the height of the cliff and g is the acceleration due to gravity (9.81 m/s^2). Plugging in the values, we get:
t = sqrt(2*80/9.81) = 4.04 seconds
ii) The horizontal distance traveled by the object can be calculated using the equation:
d = vt
where v is the horizontal velocity and t is the time taken for the object to reach the ground (which we calculated in part I). Plugging in the values.
among the different forms of electromagnetic radiation emitted by the sun, which form is absorbed by plants for photosynthesis? microwaves ultraviolet visible light gamma rays infrared
Visible light , The process by which plants convert carbon dioxide, water, and sunshine into oxygen and sugar-based energy is known as photosynthesis.
What is photosynthesis?Photosynthesis is a mechanism used by plants and other living organisms to convert light energy into chemical energy that can then be released through cellular respiration to power the organism's activities.Photosynthesis is the process through which plants turn carbon dioxide, water, and sunlight into oxygen and sugar-based energy.The process through which green plants use sunlight to create their own nourishment is known as photosynthesis. Life on Earth depends on photosynthesis. There would be no green vegetation if it did not exist, and there would be no creatures if it did not exist.Photosynthesis is primarily used to convert solar energy into chemical energy, which is then stored for use at a later time. The majority of the life systems on the planet are powered.To learn more about photosynthesis, refer to:
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Karen is asked to look at two spots of light and judge which one gets brighter over time. Both spots start out at 100 units of brightness. She notices that the right spot is brighter when it is 110 units. If she is presented with two new spots of light both starting at 300 units, how much brighter will one have to get before she will be able to reliably detect the difference?.
As spots start out at 100 units of brightness. One of the light spots will have to get 330 units brighter than the other for her to be able to tell the difference.
In the case of the first bulb, she noticed the difference when the right was 0.10 % brighter than the other one.
100 * 0.10 = 10
100 + 10 = 110
If we apply the same sense in the second case, one of the spots will have to be 0.10% brighter than the other.
300 * 0.10=30
300+30 = 330
In order to tell the difference, the other spot should be at 330 units of brightness.
The unit of brightness is Lumen. It is use to calculate the total amount of brightness emitted from a source over a unit of time.
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Which term names the cone-shaped underwater volcanic mountains?.
Answer:
Is this multiple choice answers?? Or fill in the blank??
Explanation:
Assignment
S
of
write the Symbol
Told, mercury and
Cooper, Iron,
Lead
Answer:
Check explanation
Explanation:
Gold - Au (Aurum)
Mercury - Hg (Hydrargyrum)
Copper - Cu (Cuprum)
Iron - Fe (Ferrum)
Lead - Pb (Plumbum)
These elements in the periodic table are some of the elements represented by letters not in line with their names.
This is because, these elements were known in ancient times and therefore, they are represented by letters from their ancient names.
a ball has 100 j of gravitational potential energy relative to the ground when it is dropped from rest from a high cliff. the ball has 60 j of kinetic energy right before hitting the ground. how much work was done by air resistance during the ball's fall?
The ball's whole mechanical energy is saved throughout its fall, disregarding any other elements like air resistance. Therefore, the work done by air resistance during the ball's fall is 40 J.
Gravitational potential energy (PE) and kinetic energy (KE), taken together, make up the total mechanical energy.
Initial mechanical energy (at the top of the cliff) = Gravitational potential energy (PE) = 100 J
Final mechanical energy (at the ground) = Kinetic energy (KE) = 60 J
Since the total mechanical energy is conserved, we can find the work done by air resistance by calculating the change in mechanical energy:
Work done by air resistance = Initial mechanical energy - Final mechanical energy
Work done by air resistance = PE - KE
Work done by air resistance = 100 J - 60 J
Work done by air resistance = 40 J
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A 500 kg pig is moving south and has a momentum of 17.5 kg m/s. At what velocity is it moving?
Answer:
99km
Explanation:
what are the two major hazards of electricity?
The two major hazards of electricity are electric shock and fire.
Electric shock occurs when a person comes into contact with an electric current. This can result in serious injury or even death. The severity of the shock depends on the amount of current that passes through the body and the length of time the person is in contact with the current.
Fire is another major hazard of electricity. Electrical fires can be caused by faulty wiring, overloaded circuits, or the improper use of electrical appliances. These fires can quickly spread and cause extensive damage to property and can also result in injury or death.
It is important to take safety precautions when dealing with electricity to prevent these hazards from occurring. This includes using proper wiring and circuit breakers, avoiding overloading outlets, and following the manufacturer's instructions when using electrical appliances.
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You are standing on the Earth in the shadow of the Moon. The Moon is near perigee. You are witnessing a(n)
You are witnessing a lunar eclipse during which the Earth comes between the Sun and the Moon, casting a shadow on the Moon.
A lunar eclipse occurs when the Earth comes between the Sun and the Moon, casting a shadow on the Moon. In this specific scenario, the Moon is near perigee, which means it is at its closest distance to Earth in its orbit. When the Moon is near perigee during a lunar eclipse, it appears larger in the sky, and the eclipse is often referred to as a "supermoon" eclipse.
From your perspective on Earth, you are standing in the shadow of the Moon, experiencing a partial or total eclipse, depending on the alignment of the Sun, Earth, and Moon. The shadow of the Moon falls on the Earth's surface, blocking direct sunlight from reaching the Moon. As a result, the Moon appears dark or reddish during a total lunar eclipse.
Observing a lunar eclipse can be a fascinating astronomical event, providing an opportunity to witness the interplay of celestial bodies and the beauty of our solar system.
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Which two elements have the most similar chemical properties?
A.
Cl and Ar
B.
Be and Mg
C.
Na and P
D.
Ca and Br
Answer:
B
Explanation:
same group
A wheel of radius R starts from rest and accelerates with a constant angular acceleration α about a fixed axis.
At what time t will the centripetal and tangential accelerations of a point on the rim have the same magnitude?
Express your answer in terms of the given quantities.
The time at which the centripetal and tangential accelerations of a point on the rim have the same magnitude is given by t = √(R/α).
StepsA tangential = R, where R is the wheel's radius and is the angular acceleration, gives the tangential acceleration of a point on the rim of the wheel.
A centripetal = v²/R, where v is the speed of the point, gives the centripetal acceleration of a point on the rim of the wheel.
At time t, the wheel's angular displacement is given by = (1/2)t2, and the speed of the point on the rim is given by v = R, where is the wheel's angular velocity.
Setting the magnitudes of the tangential and centripetal accelerations equal, we have:
Rα = v²/R
Substituting v = Rω and simplifying, we get:
Rα = Rω²
α = ω²
Using the definition of angular velocity ω = αt, we get:
t = √(R/α)
Therefore, the time at which the centripetal and tangential accelerations of a point on the rim have the same magnitude is given by t = √(R/α).
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What is radiation produces a wave full energy.
Answer:
electromagnetic radiation hopefully
SOMEONE HELP PLEASE ASAP ITS TIMED
A boy is slowly pushing a box across the floor. In which direction is friction occurring?
a. away from the boy
b. toward the boy
c. up
d. down
A ball is thrown horizontally from the top of a building at 2 m/s. It takes 3 seconds to reach the ground. How far did the ball travel horizontally (dx)?
explain the reflecton of light
Answer:
The reflection of light is the process by which light bounces off a surface and changes direction. When light waves hit a smooth and shiny surface, such as a mirror or a still body of water, the waves bounce back at the same angle as they hit the surface. This is known as the law of reflection. The angle of incidence, which is the angle at which the light waves hit the surface, is equal to the angle of reflection, which is the angle at which the light waves bounce off the surface. The reflection of light plays a crucial role in our daily lives, from the way we see ourselves in the mirror to the way light is directed in optical devices such as telescopes and microscopes.
Explanation:
Answer: When a ray of light approaches a smooth polished surface and the light ray bounces back, it is called the reflection of light.
Explanation:
A reflection is a transformation that acts like a mirror. The best surfaces for reflecting light are very smooth, such as a glass mirror or polished metal.
How is the heat affecting the appearance of the road and the people?
Answer:
I dont know what you mena by road and the people
What is the energy now stored if the capacitor remained connected to the potential source while the separation of the plates was changed
The energy now stored if the capacitor remained connected to the potential source while the separation of the plates was changed is when the separation between the plates of a is increased, the capacitance decreases and when the separation between the plates of a capacitor is decreased, the capacitance increases.
The voltage stored on the plates of the capacitor is directly proportional to the charge on the plates of the capacitor. So, if the separation between the plates of the capacitor is increased, the voltage stored on the plates of the capacitor decreases, and if the separation between the plates of the capacitor is decreased, the voltage stored on the plates of the capacitor increases.
So therefore, if the separation between the plates of the capacitor is changed, the energy stored in the capacitor also changes as energy stored is directly proportional to the capacitance and voltage of the capacitor. Hence, if the separation between the plates of the capacitor is changed, the energy stored in the capacitor is changed.
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On an essentially frictionless, horizontal ice rink, a skater moving at 6.0 m/s encounters a rough patch that reduces her speed by 48 % due to a friction force that is 25 % of her weight.
Part A. Use the work-energy theorem to find the length of this rough patch. Express your answer using two significant figures.
The length of this rough patch is 4.9 m.
The work-energy theorem, in simple words, expresses that the change in the kinetic energy in an object is equal to the work done on the object by non-conservative forces, like frictional ones.
In the question, we know that the skater is moving at a given speed, and due to the effects of friction, her speed is reduced to 40%.
Added to this, we are told that the friction force is equal to 22% of her weight so we can write the following:
Ff = 0.22 m. g.
Now the work done by this force is equal to the product of the force times the distance during which the force acted, i.e, the distance that we are looking for.
So, we can write the following in a brief:
ΔK = Wf ⇒ 1/2 m (vf² - v₀²) = -Ff . x
(The negative sign explains that the friction force always opposes the relative movement between the two surfaces in contact).
Replacing the values, and solving for x, we get:
1/2 ( 2² - 5²) = -0.22. 9.8. x ⇒ x = 4.9 m
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How would increasing the magnitude of the charges on two charged particles and decreasing the distance between the particles affect the strength of the electric force between the particles?
We know the formula
F=kq1q2/rSo
if magnitude of charge is increased the force between them also increased.
And if the distance between them is decreased them also the force will be increased.
So Force increases
A race car traveling northward on a straight, level track at a constant speed travels 0.760 km in 21.0 s. The return trip over the
same track is made in 26.0 s.
(a) What is the average velocity of the car in m/s for the first leg of the run?
m/s
(b) What is the average velocity (in m/s) for the total trip?
m/s
The average velocity of the car in m/s for the first leg is 36.2 m/s and the average velocity (in m/s) for the total trip is 7 m/s
What is Speed and Velocity ?Speed is the distance travelled per time taken. The S.I unit is m/s. The average speed is the ratio of the total distance travelled to the to time taken. While velocity is the distance travelled in a specific direction per time taken
Given that a race car traveling northward on a straight, level track at a constant speed travels 0.760 km in 21.0 s. The return trip over the same track is made in 26.0 s.
(a) The average velocity of the car in m/s for the first leg of the run will be
Velocity = (0.760 x 1000)/ 21
Velocity = 760 / 21
Velocity = 36.2 m/s
(b) The average velocity (in m/s) for the total trip will be
36.2 - (0.760 x 1000)/ 26
36.2 - (760) / 26
36.2 - 29.2
7 m/s
Therefore, the average velocity of the car in m/s for the first leg is 36.2 m/s and the average velocity (in m/s) for the total trip is 7 m/s
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Type of mirror used as a side mirror on a vehicle to provide a wide angle view...
Answer:
yes done first thing tomorrow
Answer:
convex mirror is used in vehicle to provide a wide angle view
if i stood on the surface of pluto, observing its big moon, i would see that moon:
If you were standing on the surface of Pluto, observing its big moon Charon, you would see Charon appearing much larger in the sky compared to how our moon appears from Earth.
Charon is about half the size of Pluto itself, whereas our moon is only about 1/4 the size of Earth. Therefore, Charon would appear much closer and larger in the sky than our moon does.
If you stood on the surface of Pluto, observing its big moon (Charon), you would see that moon:
1. Locate Charon in the sky, as it is the largest and closest moon to Pluto.
2. Observe its movement in the sky, which would appear to be locked in a mutual tidal lock with Pluto, meaning both bodies always show the same face to each other.
3. Notice that Charon would appear to be much larger than our Moon from Earth, due to its close proximity to Pluto.
4. Be aware that Charon's illumination would be much weaker than the Moon's on Earth, as the sunlight reaching Pluto and its moons is much dimmer due to their distance from the Sun.
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If I stood on the surface of Pluto, observing its big moon, I would see that moon: d. remain in the same place in the sky
What would happenTidal locking is the result of gravitational interaction between two celestial bodies, such as Pluto and its moon Charon. Over time, the gravitational pull between the two bodies causes them to fall into a state where they each take exactly as long to rotate around their own axis as they do to revolve around each other.
For example, our Moon is tidally locked to the Earth, which is why we always see the same "face" or "side" of the Moon from our perspective on Earth.
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Question
If I stood on the surface of Pluto, observing its big moon, I would see that moon:
a. rise in the east
b. rise in the west
c. get smaller day by day
d. remain in the same place in the sky
e. Come on! Pluto has no moons!
what are the precautions you should take for measuring length with a ruler
There are various precautions that should be kept in mind while measuring length with a ruler.
The following safety measures should be followed when using a ruler to measure the length:
Take care to keep the ruler parallel to the object's length. Keep the item to be measured parallel to and contacting the scale.A ruler with damaged edges should not be used to take readings from the zero point. If the ruler's edge is damaged or worn out, it is best to start measuring from a fully clear point. For instance, the length is 5 cm if you measure from the 2 cm mark to the 7 cm mark (7 cm – 2 cm = 5 cm).Eyes should be directly over the area that will be measured. You could get inaccurate results if your eyes are in different places.The object to be measured should be correctly supported on the scale such that one end of it lines up with the zero mark.Learn more about measurement with rulers here:
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five objects of mass m move at velocity v at a distance r from an axis of rotation perpendicular to the page through point a the one that has zero angular momentum about that axis is
The object that has zero angular momentum about that axis is the one that is located exactly on the axis. This is because angular momentum is the product of an object's moment of inertia (which depends on its mass and distribution) and its angular velocity.
Since the axis of rotation is perpendicular to the page, the distance of each object from the axis is the same. Therefore, the only factor that affects angular momentum is the mass and velocity of each object. Since all five objects have the same mass and velocity, the only way to have zero angular momentum is to have one object on the axis, which would have zero distance from the axis.
To determine the object with zero angular momentum, we must consider the relationship between angular momentum (L), mass (m), velocity (v), and distance (r) from the axis of rotation. The formula for angular momentum is:
L = m * v * r
An object has zero angular momentum when L = 0. In this case, one of the factors (m, v, or r) must be zero. Since all five objects have mass m and velocity v, the only factor that can be zero is the distance (r). Therefore, the object with zero angular momentum is the one located at point A, where the distance r from the axis of rotation is zero.
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Learning Goal: To understand that centripetal acceleration is the acceleration that causes motion in a circle. Acceleration is the time derivative of velocity. Because velocity is a vector, it can change in two ways: the length (magnitude) can change and/or the direction can change. The latter type of change has a special name, the centripetal acceleration. In this problem we consider a mass moving in a circle of radius R with angular velocity ω, r⃗ (t)=R[cos(ωt)i^+sin(ωt)j^] =Rcos(ωt)i^+Rsin(ωt)j^. The main point of the problem is to compute the acceleration using geometric arguments. (Figure 1) Part A What is the velocity of the mass at a time t? You can work this out geometrically with the help of the hints, or by differentiating the expression for r⃗ (t) given in the introduction. (Figure 2) Express this velocity in terms of R, ω, t, and the unit vectors i^ and j^. V⃗ (t) = Part Assume that the mass has been moving along its circular path for some time. You start timing its motion with a stopwatch when it crosses the positive x axis, an instant that corresponds to t=0. [Notice that when t=0, r⃗ (t=0)=Ri^. ] For the remainder of this problem, assume that the time t is measured from the moment you start timing the motion. Then the time − t refers to the moment a time t before you start your stopwatch. Part B What is the velocity of the mass at a time − t? Express this velocity in terms of R, ω, t, and the unit vectors i^ and j^. V⃗ (−t) = SubmitMy AnswersGive Up Part C What is the average acceleration of the mass during the time interval from − t to t? (Figure 3) Express this acceleration in terms of R, ω, t, and the unit vectors i^ and j^.
Part A :The position of the particle in vector form is given by\(r⃗ (t)=R[cos(ωt)i^+sin(ωt)j^]\)where R is the radius of the circle and ω is the angular velocity.The velocity of the particle is given by taking the derivative of the position vector with respect to time.
Taking derivative with respect to time on both side we get \(v⃗ (t)=d/dt R[cos(ωt)i^+sin(ωt)j^]= R[-in(ωt)ωi^+cos(ωt)ωj^]=ωR[-sin(ωt)i^+cos(ωt)j^]v⃗ (t)=ωR[-sin(ωt)i^+cos(ωt)j^]\)Thus the velocity of the mass at a time t is given by \(v⃗ (t)=ωR[-sin(ωt)i^+cos(ωt)j^]\).
Part B :
We have to find the velocity at time -t. The velocity of the particle is given by taking the derivative of the position vector with respect to time. Thus the velocity of the mass at a time -t is given by \(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)
\(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)Part C :
The average acceleration of the particle can be computed using the formulaa = \(Δv/Δt\)The velocity at time t is given by\(v⃗ (t) = ωR[-sin(ωt)i^+cos(ωt)j^]\)
The velocity at time -t is given by \(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)
\(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)The change in velocity over the interval from -t to t is therefore
\(Δv = v(t) - v(-t) = 2ωR[sin(ωt)i^ + cos(ωt)j^]\)
The time interval over which this change occurs is\(Δt = 2t\)Thus the average acceleration of the particle is given by a = \(Δv/Δt = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\)
\(a = Δv/Δt = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\)
The acceleration can be expressed in terms of R, ω, t, and the unit vectors \(i^ and j^\) as \(a = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\).
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what evidence is there that sound Travels through gases
Answer:
solid
Explanation:
because the molecule of solid is farest than gas
If a car accelerates from 0 m/s to 120 m/s in 6 seconds, what is the acceleration of the car?
Answer:
20 m/second squared
Explanation:
Initial velocity of the car (u) = 0 m/s
Final Velocity of the car (v) = 120 m/s
Time (t) = 6 seconds
\(Acceleration \: of \: the \: car = \frac{v - u}{t} \\ \\ = \frac{120 - 0}{6} \\ \\ = \frac{120}{6} \\ \\ = 20 \: m {s}^{ - 2} \)