find ds in terms of dv and approximate the change in the surface when the volume change from 1,000 m3 to 999 m3 .

Answers

Answer 1

Terms of dv and approximate the change in the surface when the volume change from 1,000 m3 to 999 m3 is 2.9 M2.

What is volume?

Volume is a measure of the amount of three-dimensional space occupied by a solid, liquid, gas, or plasma. It is measured in cubic meters, liters, or milliliters. Volume is an important measurement when dealing with liquids and other substances since it determines the amount of material that can fit in a given container. Volume also has an effect on pressure and temperature, as the pressure and temperature of a substance increase when its volume decreases.

The change in the surface of a given volume can be found by taking the derivative of the volume in terms of the surface. The derivative of V (volume) with respect to S (surface) is S = 3√V. Therefore, the change in surface when the volume changes from 1000 m3 to 999 m3 is approximately 3√999 - 3√1000 = 2.9 m2.

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Related Questions

Conservation of Energy Roller Coaster A roller coaster cart of mass 100kg travels on a track with one loop. Fill in blanks A-H. А. KE=OJ PE=120000J h= А. V= B B KE=___CE PE=60000J h= _D V= E KE=__F PE=40000J h=__G_ V= KE= PE= h=Om v= K D E F G H K​

Answers

(a) The height of the roller coaster at 120,000 potential energy is 122.45 m.

(b) The velocity of the roller coaster at 0 J kinetic energy is 0.

(c) The height of the roller coaster at 60,000 potential energy is 61.23 m.

(d) The velocity of the roller coaster at 60,000 J kinetic energy is 34.64 m/s.

(e) The height of the roller coaster at 40,000 potential energy is 40.82 m.

(f) The velocity of the roller coaster at 80,000 J kinetic energy is 40 m/s.

The given parameters:

mass of the roller coaster, m = 100 kg

When the kinetic energy = 0 and potential energy = 120,000 J

The height of the roller coaster is calculated as follows;

P.E = mgh

\(h = \frac{P.E}{mg}\\\\h = \frac{120,000}{100 \times 9.8} \\\\h = 122.45 \ m\)

Since the kinetic energy = 0, the velocity of the roller coaster = 0

When the potential energy, P.E = 60,000 J, the kinetic energy, K.E is calculated as;

P.E + K.E = M.A

P.E + K.E = 120,000

60,000 + K.E = 120,000

K.E = 120,000 - 60,000

K.E = 60,000 J

The height of the roller coaster at 60,000 potential energy is calculated as follows;

\(h = \frac{P.E}{mg} \\\\h = \frac{60,000}{100 \times 9.8} \\\\h =61.23 \ m\)

The velocity of the roller coaster at 60,000 J kinetic energy is calculated as follows;

\(K.E = \frac{1}{2} mv^2\\\\v^2 = \frac{2K.E}{m} \\\\v = \sqrt{ \frac{2K.E}{m}} \\\\v = \sqrt{ \frac{2\times 60,000}{100}}\\\\v = 34.64 \ m/s\)

When the potential energy, P.E = 40,000 J, the kinetic energy, K.E is calculated as;

P.E + K.E = M.A

40,000 + K.E = 120,000

K.E = 120,000 - 40,000

K.E = 80,000

The height of the roller coaster at 40,000 potential energy is calculated as follows;

\(h = \frac{P.E}{mg} \\\\h = \frac{40,000}{100 \times 9.8} \\\\h = 40.82 \ m\)

The velocity of the roller coaster at 80,000 J kinetic energy is calculated as follows;

\(v = \sqrt{\frac{2K.E}{m} } \\\\v = \sqrt{\frac{2\times 80,000}{100} } \\\\v = 40 \ m/s\)

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Two loudspeakers face each other, vibrate in phase, and produce identical 406 Hz tones. A listener walks from one speaker toward the other at a constant speed and hears the loudness change (loud-soft-loud) at a frequency of 2.86 Hz. The speed of sound is 343 m/s. What is the walking speed

Answers

Answer:

1.21 m/s

Explanation:

Given :

2 loudspeakers

F2 - F1 = 2.86 Hz

Speed of sound, V = 343

Fo = frequency when listener is at rest = 406Hz

To obtain the walking speed Vo, speed as observer moves away from speaker ;

Vo = [(F2 - F1) * V] ÷ 2 * Fo

Vo = [2.86 * 343] ÷ (2 * 406)

Vo = 980.98 / 812

Vo = 1.2081034

Vo = 1.21 m/s

A 66 kg driver gets into an empty taptap to start the day's work. The springs compress 2.3×10−2 m
. What is the effective spring constant of the spring system in the taptap?
Enter the spring constant numerically in newtons per meter using two significant figures

Answers

Explanation:

You want  N/m

 N = 66 * 9.81

 m = 2.3 x 10^-2 m

66* 9.81 / 2.3 x 10^-2  = 28150 =  28 000 N/m    to two S D

⚠️I need help with the last question!⚠️

I need help with the last question!

Answers

Answer:

I can't do your work for you but I can explain the last question;

The want you to tell them (In at least 3 sentences) Why you think your answers are correct or how your answer's match your hypothesis.

A hypothesis (for a little more help)  is an idea or explanation that you then test through study and experimentation.

Outside science, a theory or guess can also be called a hypothesis. A hypothesis is something more than a wild guess but less than a well-established theory. Anyone who uses the word hypothesis is making a guess.

Explanation:

Sorry I didnt give you the exact answer but I hope this helps :)

Scientists monitor the ozone layer by taking air samples by airplane or weather balloons. What atmospheric layer do the scientists collect the ozone samples from?

Answers

Scientists typically collect ozone samples from the stratosphere, which is the atmospheric layer located between about 10 and 50 kilometers (6 to 30 miles) above the Earth's surface.

What is the stratosphere?

The stratosphere is the layer of the Earth's atmosphere located above the troposphere and below the mesosphere. It extends from about 10 kilometers (6 miles) to about 50 kilometers (30 miles) above the Earth's surface.

The stratosphere is characterized by a gradual increase in temperature with altitude, due to the absorption of ultraviolet radiation by ozone in the stratosphere.

This is where most of the Earth's ozone is found and where the ozone layer is located. The ozone layer absorbs harmful ultraviolet (UV) radiation from the sun, protecting life on Earth from its harmful effects. Scientists collect air samples from this layer using airplanes or weather balloons equipped with specialized instruments.

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in a typical cop movie we see the hero pulling a gun firing that gun straight up into the air and shouting

Answers

It is not recommended to fire a gun straight up into the air.

When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.

Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.

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92. The velocity of longitudinal waves in a metallic rod depends upon its ?​

Answers

The velocity of longitudinal waves in a metallic rod depends on its elastic modulus, density, atomic structure, and temperature. These factors collectively determine the ability of the rod to transmit and propagate longitudinal waves.

1. Elastic modulus: The velocity of longitudinal waves is directly proportional to the elastic modulus of the material. Elastic modulus refers to the stiffness or rigidity of the material. In metals, a higher elastic modulus corresponds to a higher velocity of longitudinal waves.

2. Density: The density of the metal also affects the velocity of longitudinal waves. Generally, higher density metals tend to have slower wave velocities.

3. Atomic structure: The arrangement and bonding between atoms in a metal impact the velocity of longitudinal waves. The crystal structure, grain boundaries, and defects in the metal can influence wave propagation.

4. Temperature: Temperature affects the speed of sound in a material, including the velocity of longitudinal waves in a metallic rod. As temperature increases, the atomic vibrations within the metal increase, leading to a higher velocity of longitudinal waves.

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The most commonly accepted theory of muscle growth states that ______________ ________ within a muscle activate a(n) ________________ response process that causes dormant cells to build and regenerate muscle tissue.
A. contractions; inhibitory
B. tension; neurological
C. microscopic tears; inflammatory
D. stress; cytokines

Answers

Answer:

C

Explanation:

The most commonly accepted theory of muscle growth states that microscopic tears within a muscle activate an inflammatory response process that causes dormant cells to build and regenerate muscle tissue; this is option c.

What is the significance of the microscopic tears in muscle?

It has negative consequences on the muscle, and it is also known as "microtrauma," which occurs as a result of muscle contraction and is a normal part of the muscle repair and growth process. Here, the fibers in the muscle are damaged, and in response, the body initiates a repair process. This leads to muscle growth and increased strength and is helpful for muscle repair.

Hence, the most commonly accepted theory of muscle growth states that microscopic tears within a muscle activate an inflammatory response process that causes dormant cells to build and regenerate muscle tissue; this is option c.

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If a catalyst was added to the reaction below, which values would be affected? Check all that apply

If a catalyst was added to the reaction below, which values would be affected? Check all that apply

Answers

If a Catatlyst was added the values affected would be 2, 3, 4

What is a cata;lyst?

A catalyst is a substance that speeds up the rate of a chemical reaction without undergoing any permanent change itself. It facilitates the reaction by providing an alternative pathway with lower activation energy, which allows the reaction to occur more readily.

Catalysts work by interacting with the reactant molecules and weakening the existing bonds or creating new ones, making it easier for the reaction to proceed.

Catalysts are typically specific to certain reactions and can be used in small amounts relative to the reactants. They play a crucial role in many industrial processes and are essential for efficient chemical transformations.

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what is a shargaff rule

Answers

According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.

Who is Chargaff ?

Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.

Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.

He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.

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Question 5 0/1pts Scalar (dot) product: If=41-1+4k and B-xÎ +27-5X find x so B will be perpendicular to​

Answers

Refer to the photo taken.
Question 5 0/1pts Scalar (dot) product: If=41-1+4k and B-x +27-5X find x so B will be perpendicular to

If an airplane is accelerating down a runway at 2.5 m/s^2, how much is it’s velocity changing each second?

If an airplane is accelerating down a runway at 2.5 m/s^2, how much is its velocity changing each second?

Answers

If an airplane is  is accelerating down a runway at 2.5 m/s². It's velocity changes 2.5 m/s in each second.

What is acceleration?

Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.

Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.

Hence, the velocity of the airplane changes 2.5 m/s in each second  when it  is accelerating down a runway at 2.5 m/s².

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QUESTION 12
A cannonball is launched with initial speed 56 m/s, and hits a target at speed 35 m/s. Which of the following is correct?
The target was higher than the cannon
O The target was below the height of the cannon
O The target was at the same height as the cannon

Answers

Answer:

The target was higher than the cannon

Explanation:

Given that a cannon ball is launched with initial speed 56 m/s, and hits a target at speed 35 m/s.

The initial velocity must be 56 m/s, while the final velocity will be 35 m/s.

When an object is thrown upward with an initial velocity, the object continues to move upwards with decreasing in magnitude of velocity till it reaches the maximum height where the final velocity will be equal to zero.

In this question, since the final velocity is less than the initial velocity, we can conclude that the target is higher.

Therefore, the target was higher than the cannon.

Why does the moon block the Sun during a solar eclipse

Answers

Answer:

In a solar eclipse, the sun is completely blocked because the moon moves between the earth and the sun. Although the moon is much smaller than the sun because it is located so far away from the earth, the moon can completely block sunlight from the earth's point of view.

You leave Fort worth ,Texas,at 2:41 p.m. and arrive in Dallas at 3:23 p.m. , covering a distance of 58km. what is your average speed in metres per second ?​

Answers

Answer:

Explanation:

The time taken to travel from Fort Worth to Dallas is:

t = 3:23 pm - 2:41 pm = 42 minutes = 0.7 hours

The distance covered is:

d = 58 km

The average speed is:

v = d/t = 58 km / 0.7 hours = 82.86 km/h

To convert km/h to m/s, we can use the conversion factor:

1 km/h = 0.2778 m/s

Therefore, the average speed in m/s is:

v = 82.86 km/h × 0.2778 m/s/km = 23.06 m/s (rounded to two decimal places)

So the average speed is 23.06 m/s.

How is hydrogen obtained and separated from other nearby substances?
How is Hydrogen used?
What products are made from Hydrogen?
Where might Hydrogen be seen or used in everyday life
Any environmental concerns about the use of Hydrogen?

IF YOU ANSWER ALL I WILL MARK YOU BRAINLIEST AND BE REALLY HAPPY

IF YOU DON'T ANSWER ALL THE QUESTIONS I WILL REPORT
I AM GIVING A LOT OF POINTS FOR THIS, SO I WANT THE BANG FOR MY BUCK

Answers

Answer:

How is hydrogen obtained and separated from other nearby substances?

photoelectrolysis, a photoelectrochemical cell submerged in water uses sunlight to separate the water into hydrogen and oxygen bubbles. In the thermochemical cycle, water is heated to 800 to 1,000 °C, with the molecule. splitting to release hydrogen. The main drawback of this method is that it requires nuclear power

How is Hydrogen used?

Hydrogen can be used in fuel cells to generate electricity, or power and heat. Today, hydrogen is most commonly used in petroleum refining and fertilizer production, while transportation and utilities are emerging markets

What products are made from Hydrogen?

Hydrogen is a very useful element. It is used to make ammonia for fertilizers, refining metals, and methanol for making artificial material like plastics. Hydrogen is also used as a rocket fuel where liquid hydrogen is combined with liquid oxygen to produce a powerful explosion.

Any environmental concerns about the use of Hydrogen?

Emissions of hydrogen lead to increased burdens of methane and ozone and hence to an increase in global warming. Therefore, hydrogen can be considered as an indirect greenhouse gas with the potential to increase global warming.

What is the momentum of an object with a mass of 750 kg and a velocity of 15 m/s?
A 50 kg-m/s
B
0.02 kg-m/s
C
765 kg-m/s
D 11,250 kg.m/s

Answers

Answer:D

The momentum of an object is defined as the product of its mass and velocity. So, to calculate the momentum of an object with a mass of 750 kg and a velocity of 15 m/s, we can use the following formula:

Momentum = mass x velocity

Momentum = 750 kg x 15 m/s

Momentum = 11,250 kg m/s

Therefore, the momentum of the object is 11,250 kg m/s.

Please help me solve From a previous question, the index of refraction of the liquid is 1.37

Please help me solve From a previous question, the index of refraction of the liquid is 1.37
Please help me solve From a previous question, the index of refraction of the liquid is 1.37

Answers

ANSWER

EXPLANATION

From the previous part, we have that the index of refraction of the liquid is 1.37, so we have to replace this in the equation and solve,

\(\sin\theta_c=\frac{n_{air}}{n_{liquid}}=\frac{1.00}{1.37}\approx0.73\)

And then, take the inverse of the sine to find the critical angle,

\(\theta_c=\sin^{-1}0.73\approx46.9\degree\)

Hence, the critical angle is 46.9°, rounded to the nearest tenth.

Please help me solve From a previous question, the index of refraction of the liquid is 1.37

You throw a ball off of a cliff at t = 0. Its motion is described by this position vector r = 40mj^ + (10m/s)ti^ - (4.9m/s^2)t^2j^ . How far from the bottom of the cliff will it hit water?

Answers

Therefore, the ball hits the water 30.1 meters from the bottom of the cliff.

What is vector?

A vector is a mathematical object that has both magnitude (size) and direction. It can be used to represent physical quantities that have both a numerical value and a direction, such as velocity, force, or acceleration. A vector can be represented graphically as an arrow, with its length representing its magnitude and its direction indicating its direction. The tail of the arrow represents the starting point of the vector, while the head represents the endpoint. In addition to their graphical representation, vectors can also be described algebraically using components.

Here,

To find the distance from the bottom of the cliff where the ball hits the water, we need to find the time it takes for the ball to hit the water and then use this time to find the vertical displacement of the ball at that time.

First, we can find the time it takes for the ball to hit the water by setting the y-coordinate of its position vector equal to zero (since the water is at ground level):

-4.9t² + 40 = 0

Solving for t, we get:

t = √(40/4.9) = 2.03 seconds

So the ball hits the water after 2.03 seconds.

Next, we can use this time to find the vertical displacement of the ball at that time by plugging in t = 2.03 seconds into the y-component of its position vector:

r_y = -4.9(2.03)² + 40 = 30.1 meters

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A box is released from rest and allowed to slide down a ramp with friction. Which statement most accurately describes the energy transformations during this motion?
a) The box’s initial kinetic energy is transformed into potential energy.
b) The box’s initial potential energy and thermal energy is transformed into
kinetic energy.
c) The box’s initial kinetic energy is transformed into potential energy and
thermal energy.
d) The box’s initial potential energy is transformed into kinetic energy and
thermal energy.

Answers

Answer:

d) The box’s initial potential energy is transformed into kinetic energy and

thermal energy.

Explanation:

Let us analyze the situation first. Initially we have a box at rest placed at some height on a ramp. So, the three energies associated with the box will be:

Kinetic Energy = 0 (due to zero velocity)

Thermal Energy = 0 (due to not temperature change)

Potential Energy = Greater than zero value (due to height)

Now, when the box is released to slide down the ramp with friction, the energies become:

Kinetic Energy = Increasing (due to increase in velocity)

Thermal Energy = Increasing (due to increase in temperature, because of friction)

Potential Energy = Decreasing (due to decrease in height)

So, from Law of Conservation of Energy, we can write:

Loss of Potential Energy = Gain in Kinetic Energy + Gain in Thermal Energy

So, the correct option is:

d) The box’s initial potential energy is transformed into kinetic energy and  thermal energy.

How much is a ball that is tethered to a post accelerating if its linear speed is 3.5 m/s and the ball is 0.91 meters away from the pole? a = v^2 / r

Answers

Answer:

\(a_{c} = 13.46\ m/s^2\)

Explanation:

The motion of the tethered ball around the pole can be modeled as uniform circular motion. The acceleration of the objects executing uniform circular motion is due to the change in direction of their velocity. This is called centripetal acceleration. It is given by the following formula:

\(a_{c} = \frac{v^2}{r}\)

where,

ac = centripetal acceleration = ?

v = speed of ball = 3.5 m/s

r = distance of ball from center of rotation = 0.91 m

Using these values in equation, we get:

\(a_{c} = \frac{(3.5\ m/s)^2}{0.91\ m}\\\\a_{c} = 13.46\ m/s^2\)

What is the momentum of a 1.5 × 103 kilogram van that is moving at a velocity of 32 meters/second

Answers

The momentum of the Van whose velocity and mass has been given would be =4.8×10⁴kgm/s

How to calculate the momentum of a moving object?

To calculate the momentum of a moving object, the formula that should be used is given below as follows:

p = MV

where;

M = mass = 1.5×10³kg

V = Velocity= 32 m/s

P = momentum = 32×1.5×10³ = 4.8×10⁴kgm/s

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Which description accurately describes the tide represented by the image below? (4 points)
Image of the sun and moon at a 90 degree angle to Earth. An oval is around Earth that points toward and away from the moon to show the tidal bulges.

High tides occur when the sun and moon are at right angles to one another.
Low tides occur when the sun and moon are at right angles to one another.
The gravitational pull of the sun and moon combined creates larger than normal tides.
The gravitational pull of the sun reduces the moon's gravitational pull to create moderate tides.

Answers

High tides occur when the sun and moon are at right angles to one another. This is because the gravitational pull of the moon and the sun combine to create larger-than-normal tides, known as spring tides. The correct option is A.

Gravitational pull is the force of attraction that exists between two objects with mass. The greater the mass of an object, the greater its gravitational pull.

Option B, "Low tides occur when the sun and moon are at right angles to one another," is incorrect. Low tides occur when the sun and moon are at a 90-degree angle (or "quarter moon") to each other, but this position also results in high tides on the opposite side of the Earth.

Option C, "The gravitational pull of the sun and moon combined creates larger than normal tides," is partially correct. The gravitational pull of both the sun and moon does contribute to the tides, but the specific position depicted in the image (sun and moon at right angles to each other) does not necessarily create larger than normal tides.

Option D, "The gravitational pull of the sun reduces the moon's gravitational pull to create moderate tides," is also incorrect. The sun's gravitational pull does have an effect on the tides, but it does not reduce the moon's gravitational pull. Rather, the combined gravitational pull of the sun and moon creates the tides we observe.

Therefore,The accurate description of the tide represented by the image below is option A: "High tides occur when the sun and moon are at right angles to one another."

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explanation of the 3 newtons laws? at least 2 paragraphs please

Answers

Isaac Newton's three laws of motion are the foundation of classical mechanics and describe how objects move and interact with one another. Each of the laws provides a fundamental insight into the behavior of objects and their relationship with the forces that act on them.

Newton's first law of motion, also known as the law of inertia, states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force. In other words, objects tend to maintain their current state of motion unless a force acts upon them. This law helps to explain why it is more difficult to move a heavy object than a light one and why objects in motion tend to stay in motion.

Newton's second law of motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, this law can be expressed as F=ma, where F is the net force acting on an object, m is its mass, and a is its acceleration. This law helps to explain how forces affect the motion of objects and why heavier objects require more force to move or accelerate than lighter ones.

Newton's third law of motion states that for every action, there is an equal and opposite reaction. This law means that when two objects interact, the forces they exert on each other are equal in magnitude and opposite in direction. This law helps to explain why rockets work and why we are able to walk or run on the ground - the ground pushes back with an equal and opposite force to the force we apply to it.

Overall, these three laws of motion provide a comprehensive framework for understanding how objects move and interact with one another in the physical world. They are essential for describing and predicting the behavior of everything from tiny particles to massive celestial bodies.

A cart of mass 0.5 kg sits at rest on a table on which it can roll without friction. It is attached to an unstretched spring. You give the mass a push with a constant force over a distance of 5 cm in the direction that compresses the spring, after which the mass starts undergoing simple harmonic motion with a frequency of 0.5 complete oscillations per second and an amplitude of 15 cm.
A) What is the spring constant of the spring?
B) How fast was the cart moving at the instant when you finished pushing it?
C) What force did you exert on the cart?

A cart of mass 0.5 kg sits at rest on a table on which it can roll without friction. It is attached to

Answers

(A) The spring constant of the spring is 4.94 N.

(B) The speed of the cart after pushing it is 0.47 m/s.

(C) The force applied to the cart is 0.75 N.

Spring constant

ω = √k/m

where;

ω is angular frequencyk is spring constantm is mass

0.5 rev/s = 0.5(2π) rad/s = π rad/s = 3.142 rad/s

ω² = k/m

k = mω²

k = 0.5 x (3.142)²

k = 4.94 N/m

Energy stored in the spring

E = ¹/₂kA²

where;

A is amplitude

E = ¹/₂(4.94)(0.15)²

E = 0.056 J

Speed of the cart

E = ¹/₂mv²

2E = mv²

v² = 2E/m

v² = (2 x 0.056)/(0.5)

v² = 0.224

v = √0.224

v = 0.47 m/s

Force exerted on the cart

E = ¹/₂FA

2E = FA

F = 2E/A

F = (2 x 0.056)/(0.15)

F = 0.75 N

Thus, the spring constant of the spring is 4.94 N. The speed of the cart after pushing it is 0.47 m/s. The force applied to the cart is 0.75 N.

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A tadpole swims across a pond at 8.50 cm/s. The tail of the tadpole exerts a force of 28.0 mN to overcome drag forces exerted on the tadpole by the water.
What is the power output?

Can someone explain me, please!

Answers

Answer:

  2.38 mW

Explanation:

Power is work per unit time. Work is the product of force and distance. That means ...

  \(\text{power}=\dfrac{\text{force}\times\text{distance}}{\text{time}}=\text{force}\times\dfrac{\text{distance}}{\text{time}}\\\\\text{power}=\text{force}\times\text{velocity}\)

Using the given values of force and velocity, the tadpole's power output is ...

  P = (0.028 N)(0.085 m/s) = 0.00238 W = 2.38 mW

The tadpole's power output is about 2.38 mW.

. A 5cm tall object is placed perpendicular to the principal axis of a convex lens of focal
length 10 cm. The distance of the object from the lens is 15 cm. Find the nature, position
and size of the image. Also find its magnification

Answers

The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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At an accident scene on a level road, investigators measure a car's skid mark to be 78 m long. It was a rainy day, so the coefficient of friction was estimated to be 0.30. Use this data to determine the speed of the car (in m/s) when the driver slammed on the brakes?

Answers

Answer:

KE=1/2 mv² = FD

where FD =umgd , thus,

1/2mv²= umgd

1/2v² =ugd

v² = 2 ugd

v =√2ugd

v=√2(0.3)(9.81)(78)

v=21.4m/s

Imagine you made a little pendulum by tying a 6.0 gram washer to a thin piece of thread and dangled it from your hand as you were given a test drive in a sports car. If the driver floored the engine and the car went from 0 to 60 mph down a straight level road in 3.2 seconds, how far off vertical would the washer hang as the car accelerated

Answers

Answer:

The displacement of the pendulum from equilibrium position is 0.855 of the length of the pendulum.

Explanation:

A pendulum's motion can be modelled as a simple harmonic motion and the differential equation describing simple harmonic motion is given as

(d²x/dt²) + (k/m)x = 0

(d²x/dt²) = acceleration of the pendulum

x = displacement of the pendulum from equilibrium position

k = spring constant of the pendulum = (mg/L) = (0.006×9.8/L) = (0.0588/L)

L = length of the pendulum

m = mass of the pendulum = 6 g = 0.006 kg

(k/m) = (g/L) = (9.8/L)

To calculate the pendulum's acceleration

Initial velocity of the car = 0 mph = 0 m/s

Final velocity of the car = 60 mph = 26.822 m/s

Time taken for velocity change = 3.2 s

Acceleration = (Δv/Δt) = (26.822/3.2) = 8.382 m/s²

(d²x/dt²) + (k/m)x = 0

Becomes

8.383 + (9.8/L)x = 0

(9.8x/L) = -8.382

9.8x = -8.382L

x = -(8.382/9.8) = -0.855 L (the minus sign shows the direction of movement of the pendulum)

Ignoring the sign and only focusing on the magnitude of the pendulum's displacement from equilibrium position, the displacement of the pendulum from equilibrium position is 0.855 of the length of the pendulum.

Hope this Helps!!!

A car and driver weighing 5060N passes a sign stating "Bridge out 27.5 meters ahead." She slams on the brakes and the car decelerates at a constant rate of 14 m/s^2. The acceleration of gravity is 9.8 m/s^2. What is the magnitude of the work done stopping the car if the car just stops in time to avoid diving into the water?
Answer in units of J.

Answers

Answer:

198785.714286 Joules

Explanation:

\(W=f*d\)

\(F=ma\\F=516.326530612*-14\\F=-7228.57142857 N\\\)

To find work:

Now that the force and the distance are known, plug and chug:

\(W=f*d\\W=-7228.57142857*27.5\\W=-198785.714286J\)

Note that the question is asking for the magnitude of work, so the negative can be discarded as it is a directional component.

So, your answer is

198785.714286 Joules

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