The parametric equations that define the curve starting at (6,0) and ending at (7.8) are
\($$(x(t),y(t)) = (t+6,8t)$$\)
where parameter t varies from 0 to 1.
Find parametric equations that define the curve starting at (6,0) and ending at (7.8) as shown. Let parameter t start at 0 and end at 8 y=t (Complete the X= (Complete Dec 10 (78) a 6 5 What is equation of x?
Given information:
Start point is (6, 0).
End point is (7,8).
The curve is linear, hence we can find the slope of the line passing through (6, 0) and (7, 8).
Slope of the line:
\($$m = \frac{y_2 - y_1}{x_2 - x_1}$$$$m = \frac{8 - 0}{7 - 6}$$$$m = 8$$\)
Using point-slope form of equation of line, we get:
\($$y - y_1 = m(x - x_1)$$$$y - 0 = 8(x - 6)$$$$y = 8x - 48$$\)
Therefore, x-coordinate is given by:
\($$x(t) = t + 6$$\)
And, y-coordinate is given by:
\($$y(t) = 8t$$\)
Hence, parametric equations that define the curve starting at (6,0) and ending at (7.8) are
\($$(x(t),y(t)) = (t+6,8t)$$\)
where parameter t varies from 0 to 1.
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6.1.12 Suppose that (x1,..., xn) is a sample from a Geometric(θ) distribution, where θ ∈ [0, 1] is unknown. Determine the likelihood function and a minimal sufficient statistic for this model. (Hint: Use the factorization theorem and maximize the logarithm of the likelihood.)
The likelihood function for the Geometric(θ) distribution is \(L(\theta) = \theta^{n} \times (1 - \theta)^{x_1 + x_2 + ... + x_n - n}\), and the minimal sufficient statistic for this model is the sum of the observations, T(X) = x₁,x₂, ..., xₙ.
To determine the likelihood function and a minimal sufficient statistic for the given model, we can follow these steps:
1. Likelihood function:
The likelihood function is derived from the probability mass function (PMF) of the Geometric distribution, which is defined as:
\(P(X = k; \theta) = (1 - \theta)^{k-1} \times \theta\)
The likelihood function for a sample (x₁, ..., xₙ) is the product of the individual probabilities, assuming the observations are independent and identically distributed:
L(θ) = P(X = x₁; θ) × P(X = x₂; θ) × ... × P(X = xₙ; θ)
\(= \theta^n \times (1 - \theta)^{x_1 + x_2 + ... + x_n - n}\)
2. Logarithm of the likelihood function:
Taking the logarithm of the likelihood function helps simplify calculations and does not affect the maximum likelihood estimate:
\(log L(\theta) = n \times log(\theta) + (x_1 + x_2 + ... + x_n - n) \times log(1 - \theta)\)
3. Factorization theorem:
According to the factorization theorem, a statistic T(X) is a minimal sufficient statistic if and only if the likelihood function can be factored as:
L(θ) = g(T(X), θ) × h(X)
In this case, T(X) can be taken as the sum of the observations, i.e., T(X) = x₁, ..., xₙ.
Therefore, we can factorize the likelihood function as:
\(L(\theta) = \theta^{n} \times (1 - \theta)^{x_1 + x_2 + ... + x_n - n}\\= (\theta^n) \times [(1 - \theta)^{x_1 + x_2 + ... + x_n}] \times (1 - \theta)^{-n}\\= g(T(X), \theta) \times h(X)\)
As a result, the sum of the observations, T(X) = x₁,x₂, ..., xₙ, is a minimal sufficient statistic for this model.
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If both figures have the same perimeter what is the value of x?
You can create an equation since both have the same value of perimeter.
we will now write a function that is the product of our two numbers, where x represents the smaller number and x + 56 represents the larger number as follows. f(x) = x(x + __ )
= x^2 + ( __ ) x
On the planet Yoy, there are 9 boodins to every 14 dubbles. if farmer Pib has 120 boodins on his Frent farm, how many dubbles are on the farm.
Answer:
There are 187 dubbins on the Frent farm
Step-by-step explanation:
Here, we want to find the number of dubbles on the farm;
From the beginning of the question, we are told that there are 9 boodins to every 14 dubbles
So the ratio of boodins to dubbles is 9:14
Now, let the number of dubbles on the farm be x
Mathematically;
9/14 = 120/x
9 * x = 14 * 120
9x = 1680
x = 1680/9
x = 186.67
Since there cannot be a fractional dubbins, we will need to round up
So the number of Dubbins on the farm is 187
6 ft
8 ft
452.16 ft
150.72 ft
48 ft
904.32 ft
Answer:
The answer is 904.778 \(ft^3\).
Step-by-step explanation:
-You first need the formula for the volume of a cylinder:
\(V = \pi r^2h\)
-Take the radius and the height of the cylinder for the formula:
\(V = \pi 6^2 8\)
-Then, you solve the formula:
\(V = \pi 6^2 8\)
\(V = \pi \times 6^2 \times 8\)
\(V = \pi \times 36 \times 8\)
\(V = \pi \times 288\)
\(V = 288\pi \approx 904.778\)
So, the answer is 904.778 \(ft^3\).
I don't understand Division. Can you help?
Answer:
It's a bit hard to explain, in my opinion. but I'll give it a go. Lets say you have 10 full pizzas, and you want to split it upon 5 people. Now 5 2 slices is 10, like 5x2 so basically, it's kind of like backwards multiplying. if that makes sense. Think of it like this. if you see something like 14 ÷ 2, think of what number times 2 would be 14. 7, exactly. So Just write the number thats missing. Thats how i like to think of it. What number is missing.
Step-by-step explanation:
Sorry if this doesnt make sense and sorry if you dont understand.
I just started 6th grade so im not sure if i had the right idea in my noggin
if the actual base of the window is 5 ft, what is the height of the actual window
Answer:
5ft
Step-by-step explanation:
...........................
your professor tells you that all exam scores were transformed to z-scores for the midterm examination. describe the mean and standard deviation of the resulting distribution of z-scores.
If all exam scores are transformed into z-scores, the resulting distribution will have a mean of zero and a standard deviation of one.
The mean of the resulting distribution of z-scores is zero, and the standard deviation is one.
Z-scores, often known as standard scores, are a statistical measure used to assess how far from the mean a raw score is. This approach is used in order to normalize scores for comparison purposes when dealing with data from various samples. Standard deviation (SD) measures how much a set of values, such as exam scores, varies from the mean. The Z-score is the difference between the raw score and the mean divided by the standard deviation, and it can be positive or negative.
A Z-score greater than zero implies that the raw score is greater than the mean, whereas a Z-score less than zero implies that the raw score is less than the mean. In a distribution of z-scores, the mean of the distribution is always zero, and the standard deviation is always one.
As a result, if all exam scores are transformed into z-scores, the resulting distribution will have a mean of zero and a standard deviation of one.
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PLEASE HELP DUE SOON
Answer:
It's B
Step-by-step explanation:
Slope intercept form is Y=mx +b
(b is sometimes there when slope intersects the y axis)
A block of wood has a mass of 6.0 g and a volume of 12.0 cm^3 . What is the density of the block of wood?
Answer:
Answer: Density = 0.5 g/cm³
Explanation: Density is the ratio of mass per unit volume or D = m/V
D = m/V
= 6 g / 12 cm³
= 0.5 g / cm³
What is 3/8 as a mixed number
Answer:
3/8 is a proper fraction which means it can't be written as a mixed number
Step-by-step explanation:
If the numerator is bigger than the denominator then you can convert it to a mixed number.
Answer:
3/8 is equal to 0.375
i dont think this can be turned into a mixed number becuase the fraction isn't over 8
example: 18/8 can be changed into the mixed number 2 3/8
Step-by-step explanation:
What is the limitation period in BC? 7 A B I EEEE I 8 22 ✪ 5
In British Columbia (BC), the limitation period refers to the time within which a legal action must be initiated in order to enforce a claim. The limitation period varies depending on the nature of the claim. Here are some common limitation periods in BC:
1. Personal Injury: Generally, the limitation period for personal injury claims is two years from the date of the incident or discovery of the injury.
2. Contractual Disputes: The limitation period for breach of contract claims is typically two years from the date of the breach.
3. Property Damage: The limitation period for property damage claims is generally two years from the date the damage occurred or was discovered.
4. Professional Negligence: The limitation period for claims related to professional negligence, such as medical malpractice, is typically two years from the date the negligence occurred or was discovered.
5. Debt Recovery: The limitation period for debt recovery varies depending on the type of debt. For most debts, the limitation period is two years.
It is important to note that these are general guidelines and there may be exceptions or specific circumstances that could affect the limitation period. It is advisable to consult with a lawyer or refer to the BC Limitation Act for precise information regarding the limitation period for a particular claim.
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A weight is attached to a spring and reaches its equilibrium position(x=0). It is then set in motion resulting in a displacement of x=8 cos t, where x is measured in centimeters and t is measured inseconds.a) What is the spring
When the weight moves from x = -8 cm to x = 8 cm, the spring moves from its maximum stretched position to its maximum compressed position.Hence, the spring oscillates between its maximum stretched and compressed positions when the weight is set in motion. Therefore, the spring is a simple harmonic oscillator.
Given: Displacement x
= 8 cos t
= Acos(ωt+ φ) where A
= 8 cm, ω
= 1 and φ
=0. To find: What is the spring?Explanation:We know that displacement is given by x
= 8 cos t
= Acos(ωt+ φ) where A
= 8 cm, ω
= 1 and φ
=0.Comparing this with the standard equation, x
= Acos(ωt+ φ)A
= amplitude
= 8 cmω
= angular frequencyφ
= phase angleWhen the spring is at equilibrium position, the weight attached to the spring does not move. Hence, no force is acting on the weight at the equilibrium position. Therefore, the spring is neither stretched nor compressed at the equilibrium position.Now, the spring is set in motion resulting in a displacement of x
= 8 cos t
= Acos(ωt+ φ) where A
= 8 cm, ω
= 1 and φ
=0. The maximum displacement of the spring is 8 cm in the positive x direction. When the weight is at x
= 8 cm, the restoring force of the spring is maximum in the negative x direction and it pulls the weight towards the equilibrium position. At the equilibrium position, the weight momentarily stops. When the weight moves from x
= 8 cm to x
= -8 cm, the spring moves from its natural length to its maximum stretched position. At x
= -8 cm, the weight momentarily stops. When the weight moves from x
= -8 cm to x
= 8 cm, the spring moves from its maximum stretched position to its maximum compressed position.Hence, the spring oscillates between its maximum stretched and compressed positions when the weight is set in motion. Therefore, the spring is a simple harmonic oscillator.
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The displacement of the weight attached to the spring is given by the equation x = 8 cos t. The amplitude of the motion is 8 centimeters and the period is 2π seconds.
Explanation:The equation x = 8 cos t represents the displacement of a weight attached to a spring in simple harmonic motion. In this equation, x is measured in centimeters and t is measured in seconds.
The amplitude of the motion is 8 centimeters, which means that the weight oscillates between x = 8 and x = -8.
The period of the motion can be determined from the equation T = 2π/ω, where ω is the angular frequency. In this case, ω = 1, so the period T is 2π seconds.
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If f −1
is the inverse of f, determine the value of f(f −1
(4)). 1. f(f −1
(4))= 4
1
2. f(f −1
(4))= 16
1
3. f(f −1
(4))=4 4. f(f −1
(4))=16 5. Need to know f
The value of f(f^(-1)(4)) depends on the specific function f and its inverse f^(-1). Without knowing the function f, we cannot determine the exact value of f(f^(-1)(4)). Therefore, correct answer is option 5: Need to know f.
To evaluate the expression f(f^(-1)(4)), we would need to know the explicit form of the function f and its inverse f^(-1). Once we have the function f and its inverse, we can substitute f^(-1)(4) into f to find the corresponding output value. However, without this information, we cannot determine the result of f(f^(-1)(4)).
In summary, the value of f(f^(-1)(4)) cannot be determined without knowing the specific function f and its inverse.
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Which expression represents the possible values of n, in feet? express your answer in simplest terms. x – 1 < n < 3x 5 n = 3x 5 n = x – 1 3x 5 < n < x – 1
The expression represents the possible values of n, in feet
x-1<n<3x+5
If a, b and c are the lengths of the triangle's sides, then
a+b>c
a+c>b
b+c>a
Since,a=2x+2
b=x+3
z=n
2x+2+x+3>n
n<3x+5
2x+2+n>x+3=2x+2
n>x-1
Therefore the simplest form of the answer is x-1<n<3x+5.
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find the sum of the measures of the interior angle of each convex polygon. show work.
To find the sum of the measures of the interior angle of each convex polygon:
The sum of the measures of the interior angle formula for n-gon is,
\((n-2)\times180^{\circ}\)4) Given: 54 gon
\(\begin{gathered} (54-2)\times180^{\circ}=52\times180 \\ =9360^{\circ} \end{gathered}\)5) Given: 19-gon
\(\begin{gathered} (19-2)\times180^{\circ}=17\times180^{\circ} \\ =3060^{\circ} \end{gathered}\)6) Given: 292-gon
\(\begin{gathered} (292-2)\times180^{\circ}=290\times180^{\circ} \\ =52200^{\circ} \end{gathered}\)7) Given: 5-gon
\(\begin{gathered} (5-2)\times180^{\circ}=3\times180^{\circ} \\ =540^{\circ} \end{gathered}\)A large city’s transit department claims that only 10% of city buses run off schedule. To test this claim, a random sample of 10 buses is chosen at random. Five of the buses are running off schedule. To see how unusual this sample of buses is, a simulation of 100 trials was conducted under the assumption that 10% of the buses run off schedule. A dotplot titled city buses has number of buses running off schedule on the x-axis, and frequency on the y-axis. 0, 12; 1, 26; 2, 22; 3, 16; 4, 11; 5, 2; 6, 1. Based on the dotplot of the simulation results and the sample of 10 buses, which conclusion can be drawn? The true probability that a city bus is running off schedule is 3%. If we continued to take more samples of 10 buses, the center of the distribution would shift to 1. It is most likely that exactly one out of 10 buses is running off schedule. There is about a 3% chance that 5 or more buses are running off schedule. This is unusual and is convincing evidence that the true probability that a bus is off schedule is more than 10%.
The dotplot of the simulation results and the sample of 10 buses provides convincing evidence that the true probability of a bus running off schedule is more than the claimed 10%. The data suggests that it is most likely for exactly one bus out of 10 to be running off schedule, and there is a low probability of 5 or more buses being off schedule.
Based on the dotplot of the simulation results and the sample of 10 buses, we can draw the following conclusions:
The true probability that a city bus is running off schedule is more than 10%:
The simulation results show that the frequency of buses running off schedule is concentrated towards the higher end of the spectrum. The dotplot indicates that 5 buses running off schedule is a relatively unusual occurrence, which suggests that the true probability is higher than the claimed 10%.
There is about a 3% chance that 5 or more buses are running off schedule:
Looking at the dotplot, we can see that the frequency of 5 buses running off schedule is quite low, with only 2 occurrences out of the 100 trials. This indicates that it is unlikely for 5 or more buses to be running off schedule under the assumption that only 10% of buses run off schedule.
It is most likely that exactly one out of 10 buses is running off schedule:
The dotplot shows a peak in the frequency at 1 bus running off schedule. This suggests that one bus running off schedule is the most probable scenario among the 10-bus samples.
If we continued to take more samples of 10 buses, the center of the distribution would shift to 1:
Based on the dotplot, the distribution appears to be centered around 1 bus running off schedule. This indicates that as more samples of 10 buses are taken, the average number of buses running off schedule would tend to be closer to 1.
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For what taxable income would a taxpayer have to pay $13,154.00 in taxes?
Answer:
For the tax to be $13154.00, the income has to be around $84991.67 (around because taxes are rounded).
Step-by-step explanation:
Because the tax is over $12962, but under $31322, the income must be between $84200 and $160700.
The tax on the first $84200 is $12962, and the surplus (we'll call it x) is taxed at 24%.
24%*x = $13154 - $12962 = $190
x = $190/(24%) = $791.(6)
So the total income is something close to $84200+$791.(6) = $84991.(6)
Answer:
Step-by-step explanation:
The income must be between $84200 and $160700 because the tax is over $12962 but under $31322.
The first $84200 is taxed at a rate of $12962, and the surplus (we'll call it x) is taxed at a rate of 24 percent.
*x = $13154 - $12962 = $190 (24%)
$190 divided by (24% ) equals $791. (6)
As a result, the total income is around $84200+$791.
(6) = $84991; (7) = $84991; (8) = $84991;
its 6
Solving Inequalities
Algebra 1
Answer:
b\(\geq\)-12
Step-by-step explanation:
Step 1- Subtract 10 from both sides of the inequality.
New inequality:
4b\(\geq\)-48
Step 2- Divide by 4 on both sides of the inequality, to get your answer.
Answer:
b\(\geq\)-12
Solve for x to the nearest tenth.
Answer: 6.9
Step-by-step explanation:
Solve for the hypotenuse in the smaller triangle 5.83
Solve for x²= 9² - 5.83² = 81 - 33.99
X² = 47.01
Express your answer in scientific notation.
8.2.10-5 +0.0004
Scientific notation of the expression 8.2*\(10^{-5}\) + 0.0004 is 4.82 * \(10^{-4}\).
What is Scientific notation ?
Using scientific notation, one can express extremely large or extremely small numbers. When a number between 1 and 10 is multiplied by a power of 10, the result is represented in scientific notation.
What is Expression?
Mathematical expressions consist of at least two numbers or variables, at least one math operation, and a sentence. It's possible to multiply, divide, add, or subtract with this mathematical operation. An expression's structure is as follows: Expression: (Math Operator, Number/Variable, Math Operator)
Given that;
\(8.2\times 10^{-5} + 0.0004\)
Since, 0.0004 is written into scientific notation is 4.0 x 10^(-4)
and \(8.2\times 10^{-5}\) is written as 0.000082
When we add both the nuimber, we get;
0.000082 + 0.0004 = 0.000482
When we conver 0.000482 into scientific notation we get;
4.82 x 10^(-4)
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Type your answer in the box. A normal random variable X has a mean = 100 and a standard deviation = 20. PIX S110) = Round your answer to 4 decimals.
The value of P(X < 120) is also 0.8413.So, the required probability is 0.8413 (rounded to 4 decimals).
Given that a normal random variable X has a mean = 100
Standard deviation = 20 and we have to find P(X < 120).
The z-score formula for the random variable X is given by:
z = (X - µ)/σ
Where,
z is the z-score,
µ is the mean,
X is the normal random variable, and
σ is the standard deviation.
Substituting the given values in the z-score formula,
we get:
z = (120 - 100)/20z
= 1
Now we have to find the value of P(X < 120) using the standard normal distribution table.
In the standard normal distribution table, the value of P(Z < 1) is 0.8413.
Therefore, the value of P(X < 120) is also 0.8413.So, the required probability is 0.8413 (rounded to 4 decimals).
Hence, the answer is 0.8413.
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Determine the minimum sample size required when you want to be onfident that the sample mean is within one unit of the population mean and 13.8 assume the population is normally distributed.
The minimum sample size required when you want to be 99% confident that the sample mean is within one unit of the population mean and σ = 13.8 is 1268
Given: To find the minimum sample size, confidence level = 99%, standard deviation = 13.8, and one unit population mean. [Normally distributed]
Solving the given question:
We know that the formula for Margin of error is:
Margin of error = z-score * (standard deviation) / root (sample size)
E = z * σ / √(n), where
E = Margin of error
z = z-score
n = Sample size
σ = standard deviation
Therefore, sample size = ( z – score * standard deviation / margin of error)²
n = ( z * σ / E )²
First, calculate the z-score for the 99% confidence level.
From the normal distribution curve, the area under 99% confidence level is given as:
Area under 99% confidence level = (1 + confidence level) / 2 = (1 + 0.99) / 2 = 0.995
From the z-score table, we find the value of z with the corresponding area of 0.995
We find the value of the z-score corresponding to 0.995 is 2.58
Also given sample mean is one unit of the population. So the margin of error is 1
E = 1
And given Standard deviation = 13.8
σ = 13.8
Putting the values in the given formula of sample size n =
n = (2.58 * 13.8 / 1 )²
n = 1267.64
n = 1268
Hence the minimum sample size required when you want to be 99% confident that the sample mean is within one unit of the population mean and σ = 13.8 is 1268
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Disclaimer: Determine the minimum sample size required when you want to be 99% confident that the sample mean is within one unit of the population mean and G = 13.8. Assume the population is normally distributed. A 99% confidence level requires a sample size of (Round up to the nearest whole number as needed )
URGENT!!!!! LAST TWO QUESTIONS!!!!!!! WILL GIVE BRANLIEST!!!AT LEAST TAKE A LOOK!!!!!! PLS HELP!!! 1. A cartographer wants to create a map of Seattle. He has designed a key/legend for the map indicating that 1 cm equals 2 miles. If the distance between Woodland Park Zoo and the Seattle Aquarium is 5.2 miles, how long is the distance going to be on the map? A) 2.6 cm B) 8.2 cm C) 6 cm D) 10.4 cm 5. What similarity property, if any, can be used to show that the following two triangles are similar. A) SAS B) SSS C) AA D) Not enough information given
Answer:
1. 5.2 / 2 = 2.6 cm
2. Since 2 angles are congruent the answer is AA.
Round this whole number
Round 4,726 to the nearest hundred.
4,730
4,720
4,800
4,700
Please help! I need explanation on why the answer is what it is.
The graph that matches the given linear inequality is (B) .
In the question ,
it is given that
the linear inequality is y \(>\) -x + 4
on rewriting the inequality
we get
x + y \(>\) 4
to plot the inequality , we need points to plot .
So ,when x = 0 , we have y = 4
and when y = 0 , we have x = 4
so the two points are (0,4) and (4,0) .
For shading the inequality , we put x = 0 and y = 0 ,
and get 0+0 > 4
0>4 , the result is False , So , the shaded region will be away from the origin which is shown in option (b) .
Therefore , The graph that matches the given linear inequality is (B) .
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USE ALL THE WORK IT TAKES TO SOLVE THIS PROBLEM
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Solve the system of equations algebraically. Show all of your steps.
y=+ 2z
y=3z+ 20
Answer:
x^2 + 2x = 3x+20
-3x
x^2 - 1x = 20
- 20
x^2 -1x -20=0
(x-5)(x+4)
x-5 =0 or x+4=0
x = 5 or x= -4
Part A There are 30 students in a class. 17 of the students are boys. What percent of the class are girls. *
Part B If the percentages are the same throughout the grade, how many girls are in the whole seventh grade if there are 150 seventh graders? Please help me answer ;)
Part B: 65
Step-by-step explanation:Part A: Since there are 30 students of the class and 17 are boys, there are 13 girls. 13/30 = 43.33 = 43%.
Part B: Since 43% of the class are girls, we do 150*0.43 for the whole 7th grade which is 64.5 which I rounded to 65.
The number of surfers that visited Sunset Beach and Sandy Point over the last 15 days was recorded on these line plots.
Classify each statement by selecting true or false.
True False
The centers of the data sets are approximately equal.
True – The centers of the data sets are approximately equal.
False – The centers of the data sets are approximately equal.
The degree of overlap is high.
True – The degree of overlap is high.
False – The degree of overlap is high.
The spread of the data sets have overlaps.
True – The spread of the data sets have overlaps.
False – The spread of the data sets have overlaps.
Answer:
True
False
True
Step-by-step explanation:
help me please I'll mark first answer Brainliest
Answer:
a. True
b. True
c. True
d. False
e. False
I hope this helped! Thank You!
Answer:
a. False
b. True
c. True
d. False
e. False