The energy transferred to the α particle is 10.5 MeV. The calculation involves using conservation of momentum and energy equations.
To solve this problem, we need to use conservation of momentum and conservation of energy principles.
Let's start by calculating the initial and final masses
Initial mass = mass of neutron + mass of helium-3
= 1.008665u + 3.016029u
= 4.024694u
Final mass = mass of helium-4
= 4.002603u
The mass difference is ∆m = 0.022091u.
Using Einstein's famous equation E = ∆mc², we can calculate the energy released
E = ∆mc²
= (0.022091u)(931.5 MeV/u)(c²)
≈ 20.6 MeV
Now, let's use conservation of momentum to find the velocity of the α particle. Since the initial system is at rest, the total initial momentum is zero. Therefore, the total final momentum must also be zero.
Let v be the velocity of the α particle. Then we have:
0 = mv + \(m_av_a\)
where m and \(m_a\) are the masses of the neutron and helium-3, respectively, and \(v_a\) is the velocity of the α particle.
Solving for vα, we get
\(v_a\) = - (mv) / \(m_a\)
= - [(1.008665u)(3.016029u)v] / (4.002603u)
= - (3.016029/4.00260 3) v
≈ - 0.754 v
This tells us that the α particle is moving in the opposite direction with a speed of 0.754v. Using conservation of energy, we can find v
Initial energy = Final energy
(1/2)mv² = (1/2)\(m_a\)(0.754v)² + E
Substituting the values and solving for v, we get
v ≈ 0.185c
where c is the speed of light.
Therefore, the amount of energy transferred to the α particle is
(1/2)\(m_a\)(0.754v)²
= (1/2)(4.002603u)(0.754)(0.185c)²(931.5 MeV/u)
≈ 10.5 MeV
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When learning a new exercise what is the first thing you should focus on?
A
how much weight you can lift
B
if your form is correct
Dc
how many sets you can complete
D
if you can get done first
Answer:
If your form is correct (b)
Answer:
The answer is B if your form is correct
How was this canyon most likely from Ed
Answer:
a
Explanation:
the river over time will eroded the rock
Pls help me with science
As the earth rotates on its own axis every 24 hours the hemisphere facing the sun will experience summer while the other hemisphere will experience winter in addition the earth rotates around the sun every 365.25 days with an axis tilt of 23.5 degrees.This allows for the hemisphere tilting towards from the sun to experience daylight while the area of the earth tilting away from the sun to experience night while the area of the earth tilting towards the sun to experience summer
infrared radiation falls in the wavelength region of to meters. what is the wavelength of infrared radiation that has an energy of kj.
energy
The wavelength of the infrared radiation is: λ=1258nm.
how do you know if your converter dolly is equipped with antilock brakes
To determine if your converter dolly is equipped with antilock brakes (ABS), you can check for the presence of certain indicators or features:
1. Look for ABS Warning Light: Most vehicles with ABS have a warning light on the dashboard that illuminates when the ABS system is engaged or when there is a malfunction. Check if your converter dolly has an ABS warning light on the dashboard or instrument panel.
2. Inspect the Brake Components: Check the converter dolly's brake components, such as the wheel assemblies or brake control module, for any visible ABS-related components. Look for sensors, wiring harnesses, or additional valves that are commonly associated with ABS systems.
3. Review Manufacturer Specifications: Consult the manufacturer's documentation or user manual for your converter dolly. It should provide information about the features and specifications of the dolly, including whether it is equipped with ABS. Look for specific mentions of ABS or antilock braking system in the documentation.
4. Consult with the Manufacturer or Dealer: If you are still unsure, contact the manufacturer or dealer from whom you acquired the converter dolly. They should be able to provide information about the dolly's features, including whether it is equipped with ABS.
It's important to note that ABS is a safety feature that helps prevent wheel lock-up and maintain control during braking. If your converter dolly is equipped with ABS, it can enhance braking performance and stability, especially in slippery or emergency situations.
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how does aluminum react in the ocean for the following?
(a) resist corrosion in marine environment?
(b) resist UV?
(c) necessary toughness?
(d)function from -40 °C to 40 °C?
(f) must not fail in high winds?
(g)last for 30 years with minimal maintenance?
(h)how much would it cost per sqt ft?
Aluminum resists corrosion in the marine environment due to the formation of a protective oxide layer on its surface.
Aluminum exhibits good resistance to UV radiation, making it suitable for outdoor applications.
Aluminum possesses necessary toughness for various structural and functional purposes.
Aluminum functions effectively in a temperature range from -40 °C to 40 °C.
Aluminum is capable of withstanding high winds without failure, making it suitable for construction in windy areas.
With minimal maintenance, aluminum can last for 30 years or more.
) The cost per square foot of aluminum varies depending on factors such as thickness, finish, and specific application.
Aluminum naturally forms a thin layer of aluminum oxide on its surface, which acts as a protective barrier against corrosion. This oxide layer prevents further oxidation and corrosion, even in the harsh marine environment where exposure to saltwater and moisture is high.
Aluminum has excellent resistance to UV radiation, thanks to its oxide layer. This protective layer helps to shield the metal from the damaging effects of ultraviolet light, making aluminum suitable for outdoor applications such as windows, doors, and roofing.
Aluminum possesses a desirable combination of strength and toughness. It is lightweight yet durable, making it useful for various structural and functional purposes. Its toughness allows it to withstand mechanical stresses and impacts, making it a reliable material for a wide range of applications.
Aluminum exhibits good performance across a wide temperature range. It maintains its mechanical properties and functionality from extremely cold temperatures of -40 °C to moderately hot temperatures of 40 °C, making it suitable for various environments and climates.
Aluminum's strength-to-weight ratio and inherent flexibility allow it to withstand high wind loads without failure. Its lightweight nature reduces the stress on structures, and its high strength enables it to resist the forces imposed by strong winds, making it an excellent choice for buildings and structures in windy areas.
Aluminum is known for its durability and resistance to corrosion, especially when properly maintained. With regular cleaning and minimal maintenance, aluminum structures can last for 30 years or more, providing long-term performance and value.
The cost per square foot of aluminum varies based on factors such as the thickness of the aluminum sheet or profile, the specific finish or coating applied, and the intended application. Additionally, market factors, such as supply and demand, can influence aluminum prices. It is advisable to consult with suppliers or contractors to obtain accurate pricing information for specific projects.
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Need This ASAP
What is true about protein?
A.
Your body needs it to build and repair tissue.
B.
It is best to get it from the food you eat.
C.
Too much can damage your kidneys.
D.
All of the above
Answer:
D
Explanation:
Calculate V1 and V2 ( V = voltage )
Given that Vs = 16V, R1 = 330Ω, and R2 = 470Ω
Please do not answer if you don't know how to do this
Calculate V1 and V2 ( V = voltage )
Given that Vs = 16V, R1 = 330Ω, and R2 = 470Ω
Solution:Given that,
Vs = 16VR1 = 330ΩR2 = 470Ω.°.
V1&V2↷
Firstly, we'll find the Total resistance of the circuit=> 330Ω + 470Ω =800Ω
Now, we'll use the ohm's law to calculate the current flow in the circuitVˢ= IRᵀ
\(I= \frac{16}{800} = > \frac{1}{50}\)
= 1/50 Ampere
Now,
V1 = IR
\(v1 = \frac{1}{50} \times 330 = > 6.6 \: Volt\ \\ v2 = \frac{1}{50} \times 470 = > 9.4 \: Volt\)
______
Hope it helps
-------☆゚.・。゚ᵴɒƙυᴚᴀ_ƨȶäᴎ❀
How does the force of gravity change between two planets when the masses ofBOTH planets are doubled?
Fg=G m1m2
d2
O A
2 times the gravity
B.
4 times the gravity
O
C
no change in gravity
Oo
1/2 the gravity
Answer:
B. 4 times
Explanation:
Fg'=G(2m1)(2m2)/d²
Fg'=4Gm1m2/r²
at the top of the loop, what is the direction of the force exerted on a 55 kgkg rider by the roller-coaster seat ?
At the top of the loop, the direction of the force exerted on a 55 kg rider by the roller-coaster seat is downward.
A roller coaster is a theme park ride where passengers travel in cars attached to a track, typically in the form of a roller coaster's archetypal loop-the-loop.The roller coaster is an example of a system that obeys the laws of physics. Inertia, gravity, and energy are the three key principles involved in roller coaster physics. Gravity is the most important force at work on a roller coaster.
At the top of the loop, the direction of the force exerted on a 55 kg rider by the roller-coaster seat is downward. This is due to the centripetal force that acts on the rider and causes them to travel in a circle. At the top of the loop, the force of gravity is pulling the rider downwards, while the centripetal force provided by the seat is pushing them upwards and inwards towards the center of the loop.
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a 10cm wire carrying a current of 20a is placed in a uniform magnetic field of 0.3t. if the wire makes an angle of 40 degrees with the vector of magnetic field, find the magnitude of the force on the wire.
The force on a current carrying wire in a magnetic field will be 0.6sin40 N.
Whenever there is a current carrying wire is placed in a uniform magnetic field, The wire will experience a force onto it. The magnitude of the force will be ,
F = BILSinΘ
where,
B = magnetic field strength
I = Amount of current flowing
L = length of wire
Θ = angle of wire with respect to magnetic field
So, using above expression and putting the appropriate values, we can get,
F = 0.3x20x0.1xsin40
F= 0.6sin40 N
Hence the force applied on the wire is 0.6sin40 N.
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Which of the following is measured by temperature?
Type of atoms in matter
Type of molecules in matter
Average kinetic energy of particles
Average potential energy of particles
Answer:C:Average kinetic energy of particles
what is characteristics of mineral
Answer:
A.MINERAL HAVE THEIR OWN COLOURB.MINERALS HAVE CRSTAL
PLEASE ANSWER!!! WILL GIVE BRAINLIEST!!!!!
What is energy?
anything that has mass and takes up space
the ability to do work
all the "stuff" in the universe
phases: solids, liquids, and gases
Answer:
the ability to do work.
EXPLAINATION: .
in other words "the potential for causing changes" or "energy is the cause of any change" or "a work that a certain force *eg: gravitational* can do.
sorry if this is not the answer that you wanted but I couldn't understand your question that's why I wrote what I understood.
A roller coaster goes from 10 m/s to 30 m/s in 5 seconds. What is it's acceleration?
Vf-Vi/T
Find the force required to do 25 joule work when the force causes a displacement of 0.5m
Answer: Force required to 25 joule work when the force causes a displacement of 0.5m is 50N
Explanation: To calculate the work done we use the formula
W=F.s (1)
W= work done
F= force applied s= displacement
Given, work done W= 25 joules= 25 J
displacement s= 0.5m
∴From equation (1) we get the force required when work is done and displacement is given, that is
F\(=\frac{W}{s}\) (2)
∴Force required \(F=\frac{W}{s}= \frac{25J}{0.5m}=50N\)
(1 J is the work done by a force of 1 N acting over a displacement of 1 m and so 1 J= 1 Nm⇒ 1 N = 1 J/m)
ANS: Force required to do 25 J work when a force causes displacement of 0.5m = 50 N
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PLEASE HELP, WILL MARK BRAINLIEST
What objects exert the attractive force of gravity?
(1 Point)
Anything that has mass
Only planets, moons and stars
Only the Earth and the Sun
Only objects the size of the Earth or larger.
Answer:
Anything that has mass.
Explanation:
Answer: Anything that has mass.
Explanation:
A frog leaps from flat ground at 6.32 m/s
at a 36.3 angle. What maximum height
does it reach?
(Unit = s)
At hmax, Vy=0
vy=v0y-gt
0=6.32sin(36.3)-9.81t
t=.381 seconds
Δy=v0yt-.5gt^2
Δy=6.32sin(36.3)*.381-.5(9.81)(.381)^2
maximum height=.714 m
Questions
1. From your data, what factor(s) affect the speed of a wave? Explain your reasoning.
2. The pitch made by a musical instrument is dependent on the frequency of the wave. Frequency is the inverse of period. What impact do you think the frequency of a wave has on the wave speed?
3. What happens to wave speed as it moves from a medium of low density to one of high density? Explain your response with respect to this lab.
4. When a stringed instrument is out of tune, the player with tighten or loosen the string. If the instrument is initially flat, should they tighten or loosen the string? In the context of this experiment, explain your reasoning.
Present Your Findings or Questions
Using data and observations, answer the questions and provide your data tables in the essay box below.
Answer:
Initial velocity describes how fast an object travels when gravity first applies force on the object. On the other hand, the final velocity is a vector quantity that measures the speed and direction of a moving body after it has reached its maximum acceleration.
Explanation:
Answer:
1. The speed of the wave is affected by wavelength frequency because waves travel through a medium and sound, ocean waves and seismic waves, etc. are the physical properties of the medium that determines the speed of the mechanical waves.
2. I think the frequency of the wave doesn't have any effect on the wave speed. Only the characteristics of the medium the wave is traveling through determines its speed.
3. As a wave moves from a medium of low density to a higher density the wave speed increases and when a wave moves from a higher density to a medium density the wave speed decreases because the wave length shortens causing the wave speed to lower.
4.If the instrument is initially flat they should tighten it because once it is tightened there is going to be force applied to the gears, and after you've reached the correct pitch the gears won't be able to move. So ultimately, you will be able to meet the intended pitch you were going for.
what device was used to measure the magnetic field intensity, allowing scientists to study the magnetic properties of rocks?
In geophysical surveys, to measure the Earth's magnetic field, to find different kinds of magnetic anomalies, and to calculate the dipole moment of magnetic materials, magnetometers are frequently used.
How can magnetic field strength be determined?You can measure the magnetic field at a specific location in space using a magnetometer, also known as a gaussmeter. The direction of the magnetic field can also be measured by some devices. Midway through the 1800s, these devices were created, and they have since developed into precise, accurate measurement tools.
Every type of aircraft and spacecraft needs a magnetometer, also referred to as a magnetic sensor, to measure magnetic induction (magnetic field intensity).
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which term describes weathering?breaks down rockcauses heating and coolingmakes pebbles and rocks largercarries away fragments
The term that describes weathering breaks down the rock. Weathering is the breakdown of rocks, soil, and other geological material under the influence of physical, chemical, or biological agents.
The term weathering refers to a variety of processes that wear away or weaken rocks over time. Weathering is classified into two categories: chemical and physical. Chemical weathering occurs when rock is chemically broken down by reactions with acid rain or other chemicals.
Physical weathering, on the other hand, occurs when rock is broken down into smaller pieces by water, wind, ice, or other forces that do not change the chemical composition of the rock. In conclusion, the term that describes weathering is breaking down the rock.
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pls help 15 pointssss
Answer:
4.d 5.c
Explanation:
Information about mars' moons.
Answer:
mars is a fourth planet of the sun and the second planet in the solar system
moon is a natural satellite of the earth it isthe fifth largest moon in the solar system
How does the law of conservation of matter apply to atoms?
why do changes to temperature or ph change enzyme activity?
Changes to temperature or pH can change enzyme activity due to the fact that enzymes are sensitive to their environment. As the temperature or pH of the environment is altered, the structure of the enzyme molecule can be affected, leading to changes in enzyme activity.
Modification of enzyme activity by changes in temperature or pH.Changes to temperature or pH can affect enzyme activity because they can alter the structure of the enzyme. Enzymes are proteins, and their structure is crucial to their function. Changes to temperature can cause enzymes to denature, or lose their structure, which in turn affects their ability to catalyze reactions. Similarly, changes to pH can also affect the structure of the enzyme, as it can change the charges on the amino acids that make up the enzyme. This can also lead to a loss of function. Therefore, it is important for enzymes to be in an environment with the optimal temperature and pH for them to function properly.
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Which of the following is an example of heat transfer by convection?
A. A heat lamp shining infrared light on French fries.
B The fan on a space heater blowing warm air into a cold room.
C. When one end of a metal rod is in a fire, the other end gradually becomes
D. The transfer of energy from the sun, across the vacuum of space.
Answer:
C
Explanation:
a 59 kg k g person is in a head-on collision. the car's speed at impact is 16 m/s m / s . estimate the net force on the person if he or she is wearing a seat belt and if the air bag deploys.
According to Newton's second law, F = ma and F2 (= (60)(22500) (= 1350000 N. The total force needed to stop an unbuckled or air bag-using person is 135000 N.
How do airbags and seatbelts impact a car accident's force?They make it harder for cars to stop quickly after collisions (like an airbag). The passengers feel less force as a result. Because the car's distortion (crumpling) absorbs from the accident, less energy is transferred to the occupants.
What's the equation for force applied?What is the secret of using force, Newton's second laws of motion provides the definition of the force formula: An object's force is equal to its mass times its acceleration. F = m ⨉ a. To apply this formula, you must use SI units for force (newtons), mass (kilogrammes), and acceleration (metres per second squared).
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m
A player kicks a ball with a force of 25 N for 0.02 seconds that has an initial momentum of -0.4 kg.
to change its direction.
S
external force
of 25 N for
0.02 seconds
-.4 kg'm/s
What is the final momentum of the object in the figure above?
Your answer should have one significant figure.
m
kg
S
Answer: 1
Explanation:
Q1=-4. 60 *10^-6 C, q2=+3. 75*10^-5 C and q3= -5. 30*10^-6 C. Find the x-component of the net force on q2. Include the correct + or - sign to indicate direction.
The x-component of the net force on q2 is -1.439 × 10^-10 N.
The given charges are Q1 = -4.60 * 10^-6 C, q2 = +3.75 * 10^-5 C, and q3 = -5.30 * 10^-6 C. We need to find the x-component of the net force on q2.
The formula for force is F = K(q1 * q2) / r^2, where K is Coulomb's constant = 8.99 × 10^9 Nm^2/C^2, q1 and q2 are the charges in Coulombs, and r is the separation distance in meters.
The force between q2 and Q1 on the x-axis can be calculated as:
F1 = K(Q1 * q2) / r^2 ... (i)
Here, K = 8.99 × 10^9 Nm^2/C^2, Q1 = -4.60 × 10^-6 C, q2 = 3.75 × 10^-5 C, and r = 0.05 m.
Calculating F1:
F1 = (8.99 × 10^9) * (-4.60 × 10^-6) * (3.75 × 10^-5) / (0.05)^2
F1 = -1.242 × 10^-10 N
Similarly, the force between q2 and q3 on the x-axis can be calculated as:
F2 = K(q2 * q3) / r^2 ... (ii)
Here, K = 8.99 × 10^9 Nm^2/C^2, q2 = 3.75 × 10^-5 C, q3 = -5.30 × 10^-6 C, and r = 0.06 m.
Calculating F2:
F2 = (8.99 × 10^9) * (3.75 × 10^-5) * (-5.30 × 10^-6) / (0.06)^2
F2 = -1.971 × 10^-11 N
The net force can be calculated by adding F1 and F2, considering their x-components:
Fnet = F1 + F2
Fnet = (-1.242 × 10^-10) + (-1.971 × 10^-11)
Fnet = -1.439 × 10^-10 N
As both forces act in opposite directions along the x-axis, the net force is in the negative x-direction.
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find the t-value such that the area in the right tail is 0.10 with 25 degrees of freedom. (b) find the t-value such that the area in the right tail is 0.05 with 30 degrees of freedom. (c) find the t-value such that the area left of the t-value is 0.01 with 18 degrees of freedom. [hint: use symmetry.]
To find the t-values for the given areas and degrees of freedom, we can use the t-distribution table or a statistical calculator. Here are the answers:
(a) Finding the t-value for an area of 0.10 in the right tail with 25 degrees of freedom:
Using symmetry, we know that the area in the left tail is also 0.10. Therefore, we need to find the t-value that corresponds to an area of 0.10 in the left tail with 25 degrees of freedom.
Using a t-distribution table or a calculator, we find that the t-value for an area of 0.10 in the left tail with 25 degrees of freedom is approximately -1.711.
Since the t-distribution is symmetric, the t-value for an area of 0.10 in the right tail with 25 degrees of freedom is the negative of the t-value for an area of 0.10 in the left tail. Therefore, the t-value we are looking for is approximately 1.711.
(b) Finding the t-value for an area of 0.05 in the right tail with 30 degrees of freedom:
Similar to part (a), using symmetry, we can find the t-value for an area of 0.05 in the left tail with 30 degrees of freedom.
Using a t-distribution table or a calculator, we find that the t-value for an area of 0.05 in the left tail with 30 degrees of freedom is approximately -1.699.
Again, due to symmetry, the t-value for an area of 0.05 in the right tail with 30 degrees of freedom is the negative of the t-value for an area of 0.05 in the left tail. Therefore, the t-value we are looking for is approximately 1.699.
(c) Finding the t-value for an area of 0.01 in the left tail with 18 degrees of freedom:
To find the t-value for an area of 0.01 in the left tail with 18 degrees of freedom, we can directly use a t-distribution table or a calculator.
Using a t-distribution table or a calculator, we find that the t-value for an area of 0.01 in the left tail with 18 degrees of freedom is approximately -2.898.
Since we are looking for the t-value that corresponds to the area left of it, the t-value we are looking for is approximately -2.898.
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