Find the intensity III of the sound waves produced by four 60-WW speakers as heard by the driver. Assume that the driver is located 1.0 mm from each of the two front speakers and 1.5 mm from each of the two rear speakers.

Answer:

c h i c k e n n u g g e t s . . . . . .

jk its 2.6

1. The substance equation for water is \(H_2O\).

2. The compound name for table salt is sodium chloride \((NaCl)\).

3. The synthetic equation for carbon dioxide is \(CO_2\).

4. The substance name for baking soft drink is sodium bicarbonate \((NaHCO_3)\).

5.  The substance recipe for methane is \(CH_4\).

6. The compound name for vinegar is acidic corrosive \((CH_3COOH)\)

7.  The compound equation for smelling salts is \(NH_3\).

8. The compound name for blanch is sodium hypochlorite \((NaClO)\).

9.  The synthetic equation for hydrogen peroxide is \(H_2O_2\).

10. The synthetic name for rust is iron oxide \((Fe_2O_3)\).

11.  The compound recipe for sodium hydroxide is \(NaOH\).

12. The substance name for lye is sodium hydroxide \((NaOH)\).

13. The synthetic equation for sulfuric corrosive is \(H_2SO_4\).

14. The compound name for gypsum is calcium sulfate dihydrate \((CaSO_4.2H_2O)\).

15. The substance equation for table sugar is \(C_1_2H_2_2O_1_1\).

16. The synthetic name for anti-inflamatory medicine is acetylsalicylic corrosive \((C_9H_8O_4)\).

17. The compound recipe for calcium carbonate is \(CaCO_3\).

18. The substance name for baking powder is a combination of sodium bicarbonate \((NaHCO_3)\) and an acidic fixing like cream of tartar \((KC_4H_5O_6)\).

19. The synthetic equation for sodium chloride is \(NaCl\).

20. The substance name for hydrogen gas is \(H_2\).

The questions are:

1. What is the synthetic recipe for water?

2. What is the substance name for table salt?

3. What is the compound equation for carbon dioxide?

4. What is the synthetic name for baking pop?

5. What is the substance equation for methane?

6. What is the synthetic name for vinegar?

7. What is the substance equation for alkali?

8. What is the substance name for blanch?

9. What is the compound recipe for hydrogen peroxide?

10. What is the synthetic name for rust?

11. What is the synthetic equation for sodium hydroxide?

12. What is the synthetic name for lye?

13. What is the substance recipe for sulfuric corrosive?

14. What is the substance name for gypsum?

15. What is the synthetic recipe for table sugar?

16. What is the substance name for anti-inflamatory medicine?

17. What is the synthetic equation for calcium carbonate?

18. What is the synthetic name for baking powder?

19. What is the substance equation for sodium chloride?

20. What is the substance name for hydrogen gas?

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The claimed efficiency of the power plant is 78%, which is significantly higher than the theoretical maximum efficiency of 29.2%. Further information is required to evaluate the claim.

The greatest conceivable proficiency of the consolidated cycle power plant can be determined involving the Carnot productivity recipe as follows:

η_Carnot = (1373 K - 973 K)/1373 K = 29.2%

This implies that the hypothetical greatest proficiency of the power plant is 29.2%.

The guaranteed proficiency of the power plant is 78%. This is fundamentally higher than the hypothetical most extreme proficiency of 29.2%, which recommends that the case isn't precise. There might be different elements that are adding to the guaranteed effectiveness, like the utilization of further developed innovation, yet minus any additional data, assessing the claim is troublesome.

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Answer:

1.6e20

Explanation:

Answer:

Recall the formula,

\({v_f}^2-{v_i}^2=2a\Delta x\)

where \(v_i\) and \(v_f\) are the rock's initial and final velocities, respectively; \(a\) is its acceleration; and \(\Delta x\) is the displacement it undergoes.

At any point during its motion, the rock is subject to gravity, so \(a=-g\), where \(g=9.80\frac{\rm m}{\mathrm s^2}\). At its maximum height, the rock has zero vertical velocity, and if we take its starting height to be the origin, we have \(\Delta x=x_{\rm max}\).

So,

\(0^2-{v_i}^2=-2gx_{\rm max}\implies-{v_i}^2=-2\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(40\,\mathrm m\implies\boxed{v_i=28\dfrac{\rm m}{\rm s}}\)

The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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Answer:

Wavelength

Explanation:

Answer:

What Is Moral Subjectivism? Moral subjectivism is based on an individual person's perspective of what is right or wrong. An individual can decide for themselves that they approve or disapprove of a certain behavior, and that is what determines if the behavior is right or wrong.

Answer:

kinsey sexuailty doesn't matter because that is his or her  

Explanation:

The elastic potential energy stored in the spring is 0.375 J.

The formula for elastic potential energy is:

E = 1/2 * k * x^2

where:

* E is the elastic potential energy in Joules

* k is the spring constant in N/m

* x is the distance the spring is stretched or compressed from its equilibrium position in meters

In this problem, we have:

* k = 3 N/m

* x = 0.5 m (50 cm)

Substituting these values into the formula, we get:

E = 1/2 * 3 * 0.5^2 = 0.375 J

Therefore, the elastic potential energy stored in the spring is 0.375 J.

We wll have the ollowing:

Specific heat is the quantity of heat that is required to reaise the temperature of a gram of a substance by 1 degree celsius. It's unit is Joules in the SI.

Following are the answers:

1. To calculate the pressure exerted by the water column on the surface of the mercury, we can use the formula:

Pressure = force/area

The force is the weight of the water column and the area is the cross-sectional area of the container.

The weight of the water column is given by the mass of the water times the acceleration due to gravity:

mass = density x volume

volume = area x height

So, mass = density x area x height = 1000 kg/m^3 x pi x (0.025 m)^2 x 0.25 m = 0.196 kg

Weight = mass x acceleration due to gravity =\(0.196 kg * 9.8 m/s^2\) = 1.92 N

The cross-sectional area of the container is pi x (0.025 m)^2 =\(0.196 m^2.\)

So, Pressure = force/area = \(1.92 N/0.196 m^2 = 9.79 N/m^2\) or 9.79 Pa

2. To calculate the density of the oil, we can use the formula:

density = mass/volume

Since the height of the oil column is 0.92 m and the cross-sectional area of the container is 0.196 m^2, the volume of the oil column is 0.196 m^2 x 0.92 m = 0.18012 m^3.

We do not know the mass of the oil, but we can calculate it using the pressure exerted by the oil column on the surface of the mercury:

Pressure = force/area = density x acceleration due to gravity x height

So, density = Pressure/ (acceleration due to gravity x height) = 9.79 N/m^2 / (9.8 m/s^2 x 0.92 m) = 1060 kg/m^3.

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The change in momentum for the baseball, which is hit back in the opposite direction by the batter, is -10.36 kg·m/s. This change in momentum is obtained by subtracting the initial momentum of 4.2 kg·m/s from the final momentum of -6.16 kg·m/s. The negative sign indicates the opposite direction of the momentum.

To find the change in momentum for the baseball, we can use the formula:

Change in momentum = Final momentum - Initial momentum

Momentum is defined as the product of mass and velocity.

Given data:

Mass of the baseball (m) = 0.140 kg

Initial velocity of the baseball (\(v_i_n_i_t_i_a_l)\) = 30.0 m/s

Final velocity of the baseball (\(v_f_i_n_a_l_\)) = -44.0 m/s (negative sign indicates opposite direction)

To calculate the initial momentum, we multiply the mass by the initial velocity:

Initial momentum = m * \(v_i_n_i_t_i_a_l\) = 0.140 kg * 30.0 m/s = 4.2 kg·m/s

To calculate the final momentum, we multiply the mass by the final velocity:

Final momentum = m * \(v_f_i_n_a_l_\) = 0.140 kg * (-44.0 m/s) = -6.16 kg·m/s

Now we can find the change in momentum:

Change in momentum = Final momentum - Initial momentum

Change in momentum = (-6.16 kg·m/s) - (4.2 kg·m/s)

Change in momentum = -10.36 kg·m/s

Therefore, the change in momentum for the baseball is -10.36 kg·m/s. The negative sign indicates a change in direction, as the ball is hit back in the opposite direction.

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The part of a road vehicle which must be tested to ensure that there is sufficient friction to stop the vehicle in an emergency is the tyre.

This is referred to as a force that resists the motion of one object against another when they roll or slide against each other.

When dealing with braking, the main factor is to have sufficient friction between the road surface and tyre to bring the vehicle to a standstill. If the tyres are wornout there won't be enough friction to make the vehicle stop during emergencies which is therefore the reason why it was chosen as the correct choice.

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Answer:

585lb

Explanation:

Given the following

F1 = 235lb

F2 = 350lb

The resultant is expressed as;

FR = F1+F2

Substitute the given values

FR = 235+350

FR = 585lb

Hence the magnitude of the resultant is 585lb

Answer:

Let I and j be the unit vector along x and y axis respectively.

Electric field at origin is given by

E= kq1/r1^2 i + kq2/r2^2j

= 9*10^9*1.6*10^-19*/10^-6*(2i+ j)

= (2.88i + 1.44j)*10^-3 N/C

Force on charge= qE= 3*10^-19*1.6*(2.88i +1. 44 j) *10^-3

F= (1.382 i + 0.691 j) *10^-21

 Goodluck

Explanation:

Answer:

Explanation:

Yes, the settings related to electric and magnetic fields need to be changed to select positrons with the same speed as electrons in a velocity selector.

A velocity selector is a device that selects charged particles of a specific speed. It consists of perpendicular electric and magnetic fields. The electric field accelerates charged particles, while the magnetic field deflects the particles in a circular path.

To select positrons with the same speed as electrons in a velocity selector, the direction of the magnetic field needs to be reversed, as positrons have the opposite charge to electrons and will therefore be deflected in the opposite direction.

The diagram below shows the setup of a velocity selector for electrons and how it needs to be modified to select positrons with the same speed:

Velocity Selector Diagram

In the original setup for electrons, the magnetic field is directed into the page, while the electric field is directed upwards. Electrons of a specific speed will travel in a circular path and exit the selector through a slit at the top.

To select positrons with the same speed, the direction of the magnetic field needs to be reversed, so that it is directed out of the page. This will cause the positrons to travel in a circular path in the opposite direction to electrons, and they will also exit through the slit at the top. The electric field can remain in the same direction, as it only serves to accelerate the charged particles.

The expression for the initial velocity at point A is:

0 = (velocity at point A - 0) / time

Simplifying the equation, we find:

Velocity at point A = 0

The initial velocity at point A is zero, indicating that the object starts from rest before sliding on the horizontal plane AB.

To write an expression for the initial velocity at point A, we need to analyze the forces acting on the object and apply the principles of motion.

Given:

Mass of the object, m

Radius of the semi circle, R

Coefficient of kinetic friction, μ\(_k\) = 0.5

Force applied at point C, F = 3mg

The object is initially at rest.

Let's break down the motion into two parts: the motion on the horizontal plane AB and the motion along the semi circle BCD.

1. Motion on the horizontal plane AB:

The only force acting on the object on the horizontal plane is the force of kinetic friction. The frictional force can be calculated using:

Frictional force, f = μ\(_k\)* Normal force

The normal force is equal to the weight of the object, which is mg.

Normal force, N = mg

Frictional force, f = μ\(_k\) * mg

The frictional force acts in the opposite direction to the motion, so its magnitude is negative. Thus, the net force on the object on the horizontal plane is:

Net force = -f = -μ\(_k\)* mg

Using Newton's second law, we can relate the net force to the acceleration:

Net force = mass * acceleration

-μ\(_k\) * mg = m * acceleration

The acceleration can be expressed as the rate of change of velocity:

Acceleration = (final velocity - initial velocity) / time

Since the object is initially at rest, the initial velocity is zero.

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The x and y component of the ball's final velocity are respectively 7.35 m/s and  4.90 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given that:

Mass of the ball: M = 6.35 kg.

Initial velocity of ball: U = 8.49 m/s.

Mass of the pin at rest: m = 1.59 kg.

Final velocity of pin: v = 20.1 m/s at a -77.0° angle.

Let the x and y component of the ball's final velocity are respectively V₁ m/s and  V₂ m/s.

Appling conservation of momentum along x axis:

MU + m.0 = MV₁ + mvcos(-77.0°)

⇒ V₁ = u - (m/M) v cos(-77.0°)

After putting the values we get:

V₁ = 7.35 m/s.

Appling conservation of momentum along y-axis:

M.0 + m.0 = MV₂ + mvsin(-77.0°)

⇒ V₂ = - (m/M) vsin(-77.0°)

After putting the values we get:

V₂ = 4.90 m/s.

Hence, the x and y component of the ball's final velocity are respectively 7.35 m/s and  4.90 m/s.

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180kg is mass of metal .

The definition of specific heat capacity

The amount of heat per unit mass needed to raise the temperature by one degree Celsius is known as the heat capacity or specific heat. The ability to distinguish between two polymeric composites using specific heat can be useful in calculating the processing temperatures and volume of heat required.

The heat capacity per unit mass of a material is known as the specific heat capacity (or simply the specific heat). The results of experiments indicate that three variables affect the amount of heat that is transferred: (1) the temperature change, (2) the mass of the system, and (3) the substance and phase of the material.

Eo is 9.9*10^6 J

ΔT is 55K

c is 1*10^3 J/kg.K

Eo = Mo. c. ΔT

Mo = Eo/ c. ΔT

Mo = 9.9*10^6/ 5 5*1*10^3

Mo = 180kg

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The current that flows through the 75 ohm resistor in the circuit shown below is 0.12A.

The current flowing through a circuit can be calculated using the Ohm's law equation as follows;

V = IR

Where;

According to this question, a circuit is shown in the above image. A 75 ohm resistor is given alongside a voltage of 9V. The current can be calculated as follows;

9 = I × 75

I = 0.12A

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Answer: 4.214 N

Explanation:

Since the ball reaches a constant terminal velocity, then the net force = 0 because the acceleration = 0

If we draw a free body diagram, we will find that all forces acting on the ball are:

If F(net) = 0, then gravitational force = air resistance = Mass * free-fall acceleration = 0.43*9.8 = 4.214 N

Answer:

(a) The power of this pulse is 399.5 W

(b) The total energy of this pulse is 0.3995 J

(c) The total charge that flows during the pulse is 8.5 x 10⁻⁴ C

Explanation:

Given;

potential difference developed by the eel, V = 470 V

current, I = 0.85 A

time, t = 1 ms = 1 x 10⁻³ s

(a) the power of this pulse.

P = IV

P = 0.85 x 470

P = 399.5 W

(b) the total energy of this pulse

E = Pt

E = 399.5 x 1 x 10⁻³

E = 0.3995 J

(c) the total charge that flows during the pulse

Q = it

Q = 0.85 x 1 x 10⁻³

Q = 8.5 x 10⁻⁴ C

Answer:

A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.

Explanation:

just took test

A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Balanced force is when the net force applied on the object is zero than said to be balanced.

A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.

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Answer:

a) >26.7 N

b)  >13.3 N

Explanation:

a)  Fg = (17 kg)(9.8 m/s²) = 166.6 N

Fnormal = Fg = 166.6 N

Ff = μFn = 0.16(166.6 N) = 26.7 N

Janitor needs to push >26.7 N to overcome the Force of friction (Ff) on a horizontal floor.

b)  You have to determine Fn on the object by figuring out the y-component of Fg.

Fn/Fg = sin30

Fn = sin30(166.6 N) = 83.3 N

Now you can find Ff.

Ff = μFn = 0.16(83.3 N) = 13.3 N

Janitor needs to push >13.3 N down the incline to overcome Ff

Makes sense that he has to push less down an incline.