Find the length of the hypotenuse of a right triangle whose legs are 5 and 12

Answer: $1.65

Step-by-step explanation: 19.80 / 12 = 1.65

Answer:

20

Step-by-step explanation:

8 is near to 10 so +1

Answer:

y=2.50+175*(x-1)

$4727.50

Step-by-step explanation:

y=2.50+175*(x-1)

The first km costs 2.50 which is why you add it. You do x-1 because the 175 is charged for each additional km. So, if you traveled one km it would cost 2.50.

y=2.5+175*(28-1)

y=2.5+175*27

y=2.5+4725

y=$4727.50

Answer:

(-6, -2)

Step-by-step explanation:

We can represent the translation of a point 4 units to the left and 5 units up as addition of its coordinates:

"4 units to the left" can be represented as (x - 4, y)

"5 units up" can be represented as (x, y + 5)

on the point (x, y).

Applying this to the given vertex (-2, -7):

(-2 - 4, -7 + 5)

(-6, -2)

Answer:

the equation used to determine the number of dimes in his pocket is an "algebraic equation" (3/4)x = 5.25

and the value of x = 7

Step-by-step explanation:

We are being told that:

Alex has 3 more quarters than dimes in his pocket, for a total of $5.25.

Let the value for the dimes in his pocket be x:

So he has 3 more quaters than x

We know that a quarter is 1/4

3 more quaters than x = (3/4) x

(3/4)x = 5.25

3x = 5.25 * 4

3x = 21

x = 21/3

x = 7

Thus, the equation used to determine the number of dimes in his pocket is an "algebraic equation" (3/4)x = 5.25

and the value of x = 7

Answer:

its C. do you need an explanation? i could give one if you want

Step-by-step explanation:

Calculate each interquartile: subtract the upper quartile to the lower quartile

1. 9-7 = 2

2. 105-97 = 8

3. 17-7.5= 9.5

4. 7 -4 = 3

The greatest interquartile is 9.5 (option 3)

a) To find the number of students getting more than 45 marks, we count the students whose marks are greater than 45 in the given list.

In the given list, the students with marks greater than 45 are: 50, 49, 47, 48, 49, 48, 47, 49, 48, 50, 47, 49, 48, 46, 47, 48, 47.

Counting these numbers, we find that there are 17 students who obtained more than 45 marks.

b) To find the number of students getting less than 45 marks, we count the students whose marks are less than 45 in the given list.

In the given list, the students with marks less than 45 are: 44, 44, 42, 41, 41, 42, 41, 44, 44, 42, 45, 45, 45, 44, 45.

Counting these numbers, we find that there are 15 students who obtained less than 45 marks.

c) To find the maximum number of students getting the same marks, we look for the mark that appears most frequently in the given list.

In the given list, the marks obtained by the students are: 44, 50, 44, 49, 42, 47, 45, 42, 44, 48, 49, 48, 47, 49, 47, 41, 45, 48, 41, 48, 41, 42, 47, 49, 49, 48, 50, 47, 49, 48, 46, 44, 45, 45, 46, 44, 42, 47, 48, 45.

Counting the frequency of each mark, we find that the marks 47 and 48 appear most frequently, with a count of 6 each. Therefore, the maximum number of students getting the same marks is 6.

d) To find the average marks obtained by the students in the class, we sum up all the marks and divide by the total number of students.

Total marks = 44 + 50 + 44 + 49 + 42 + 47 + 45 + 42 + 44 + 48 + 49 + 48 + 47 + 49 + 47 + 41 + 45 + 48 + 41 + 48 + 41 + 42 + 47 + 49 + 49 + 48 + 50 + 47 + 49 + 48 + 46 + 44 + 45 + 45 + 46 + 44 + 42 + 47 + 48 + 45

           = 1912

Total number of students = 40

Average marks = Total marks / Total number of students

                 = 1912 / 40

                 = 47.8

Therefore, the average marks obtained by the students in the class is 47.8.

e) To find the number of students getting more than the average marks, we count the students whose marks are greater than 47.8.

In the given list, the students with marks greater than 47.8 are: 50, 50, 49, 48, 49, 48, 49, 48, 50, 49, 49, 48, 48, 50, 49, 49, 48, 48, 47, 49, 49, 48, 50, 47,

49, 49, 48, 50, 47, 49, 49, 48, 48, 49, 48, 47, 48, 49, 49, 48, 50, 49.

Counting these numbers, we find that there are 40 students who obtained more than the average marks.

Answer:

It would cost Jeremy $66 for 6 CDs

Step-by-step explanation:

3 CDs for $33

3(2)=6

$33(2)=$66

Answer:

6 miles

Step-by-step explanation:

You Can make a proportion

\(\frac{26/3 miles}{60 minutes}\)=\(\frac{x}{45 minutes}\)

Now cross multiply

45*26/3 is 360

and 60*x is 60x

make an equation

60x=360

x=6

So 6 miles

Answer:

6 miles

Step-by-step explanation:

Answer:

For the raging river you multiply

X * 9 = Y

And for paddlers the equation is

X + 40 = Y

a.The probability distribution table for the first six attempts is shown below:

X P(X=k)

1 0.44

2 0.56 ×0.44

3 0.56²×0.44

4 0.56³ × 0.44

5 0.56⁴ ×0.44

6 0.56⁵×0.44

b.  the probability is 0.1399.

c. the quarterback can expect to throw about 2.27 passes before completing one.

d. the probability is 0.1865.

e. the probability is 0.7349.

The possibility or chance of an event occurring is measured by probability. The expression is given as a number between 0 and 1, with 0 denoting impossibility and 1 denoting certainty. Compared to occurrences with a probability closer to 0, those with a probability closer to 1 are more likely to occur.

a. To construct a probability distribution table for the number of passes attempted before the quarterback has a completion, we can use the geometric probability distribution, which is given by:

P(X=k) = \((1-p)^{k-1}\)×p

where X is the number of attempts before the completion, p is the probability of completion on each attempt, and k is the number of attempts.

The probability distribution table for the first six attempts is shown below:

X P(X=k)

1 0.44

2 0.56 ×0.44

3 0.56²×0.44

4 0.56³ × 0.44

5 0.56⁴ ×0.44

6 0.56⁵×0.44

b. The probability that the quarterback throws 3 incomplete passes before he has a completion is given by:

P(X=3) = (1-0.44)³⁻¹× 0.44 × (1-0.44)⁰

= 0.56²×0.44

= 0.1399

Therefore, the probability is 0.1399.

c. The expected number of passes that the quarterback can throw before he completes a pass is given by the formula:

E(X) = 1/p

where p is the probability of completion on each attempt.

In this case, p = 0.44, so the expected number of passes is:

E(X) = 1/0.44

= 2.27

Therefore, the quarterback can expect to throw about 2.27 passes before completing one.

d. The probability that it takes more than 5 attempts before the quarterback completes a pass is given by:

P(X > 5) = 1 - P(X <= 5)

= 1 - [P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)]

= 1 - [0.44 + (0.56 × 0.44) + (0.56² ×0.44) + (0.56³ × 0.44) + (0.56⁴×0.44)]

= 0.1865

Therefore, the probability is 0.1865.

e. If the quarterback throws 8 passes on the opening drive, the probability that he completes at least half of them is given by the binomial probability distribution, which is given by:

P(X ≥ 4) = 1 - P(X < 4)

where X is the number of completed passes and the probability of completion on each attempt is p = 0.44.

Using the binomial probability distribution table or calculator, we can find:

P(X≥4) = 1 - [P(X=0) + P(X=1) + P(X=2) + P(X=3)]

= 1 - [0.56⁸ + (8× 0.56⁷×0.44) + (28 × 0.56⁶ × 0.44²) + (56× 0.56⁵×0.44³)]

= 0.7349

Therefore, the probability is 0.7349.

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The Function that has a range of {y|y ≤ 5} is  mathematically given as

f(x) = –(x – 4)2 + 5

This is further explained below.

Generally, the equation for the function is  mathematically given as

f(x)=-(x-4)^2+5

Where

f(x)=-(x-4)^2+5 is a quadratic function. Its graph looks like a parabola. One of the vertices in the graph is (4,5) and opens in a downward direction.

Proving that f(x)=-(x-4)^2+5≤  5 for all x

\(x^2 \geq 0 \Rightarrow(x-4)^2 \geq 0 \\\\-(x-4)^2 \leq 0 \\\\-(x-4)^2+5 \leq 5 \text {. }\)

In conclusion, The Function that has a range of {y|y ≤ 5} is  mathematically given as

f(x) = –(x – 4)2 + 5

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The median is B. 2.5

Step-By-Step Explanation:

The dot plot goes by the data

1 2 2 3 3 4

those are six numbers in total!

Since 6 is an even number we'd need to find out the number in between the two numbers in the middle.

In this case that would be 2 and 3.

The number in the middle of 2 and 3 is 2.5

- - - - -

IN CONCLUSION

Your answer is B. 2.5

- - - - -

I hope I helped! :)

Required two transformations are translated according to the rule (x, y) → (x + 8, y + 2) reflected across the x-axis.

How to find the two transformations applied to pentagon ABCDE to create A″B″C″D″E″?

To find the two transformations applied to pentagon ABCDE to create A″B″C″D″E″, we can compare the coordinates of corresponding vertices of both pentagons.

Starting with point A, we see that it has been translated 8 units to the right and 2 units up to become A″. Therefore, the first transformation is a translation according to the rule (x, y) → (x + 8, y + 2).

Next, we can compare the y-coordinates of point A and A″ to see if a reflection has been applied. We see that the y-coordinate of A has changed from 5 to -7 in A″, indicating that a reflection has been applied across the x-axis.

Therefore, the two transformations applied to pentagon ABCDE to create A″B″C″D″E″ are:

Translated according to the rule (x, y) → (x + 8, y + 2)

Reflected across the x-axis.

The other options can be ruled out as they do not correctly reflect the transformation that was applied.

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The given function will be represented by a straight line graph, as shown below in the attachment.

On a coordinate plane, functions can be graphed. To graph a function, first select several input values and compute the outputs. The x value is the independent variable, and the y value is the dependent variable. Plot the points and connect them with a line or a curve, depending on whether the function is linear or curvilinear.

Linear functions are written as y = mx + b, where m is the slope of the line and b is the y-intercept. A linear function's graph is a straight line that represents a constant rate of change between two variables. All other functions are curvilinear or non-linear.

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Answer:

D, 12 units, j and L, 25.3 units

Step-by-step explanation:

Hop3 it helps :)

Answer:

a) the mean is $53.50

b) it is a statistic

Step-by-step explanation:

mean = ∑fx/∑f

∑f = 20

mean = (sum of the terms) ÷ (number of terms)

mean = (53+49+54+50+21+46+75+45+63+76+61+63+36+34+54+63+37+62+66+62) ÷ 20 = 1070/20

=$53.50

b) it is statistics because it is a random sample of 20 residential customers not the actual population

The ratio which is equivalent to 30:20 is option C, 3:2.

Suppose the  real measurements were "a" and "b"

Then their ratio will be formed as

\(\dfrac{a}{b} = \dfrac{p \times x}{q \times x} = \dfrac{p}{q}\)

where is a common factor (not 1)? This shows that to get the real measurements from the given ratio, we need to assume to have some factor possibly canceled from both the numerator and the denominator.

Thus, a = px, b = qx

We have given that a 2-column table has 2 rows. Column 1 is labeled

The Total with entries 30, and 15. Column 2 is labeled Red with entries 20, and 10.

Given ratio is 30:20

Or

3:2

Therefore, we can conclude that the ratio which is equivalent to 30:20 is option C, 3:2.

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Part (a)

Answer: Constant of proportionality = 5/8

Reason:

The general template equation is y = kx where k is the constant of proportionality. It is the slope of the line.

The direct proportion line must pass through the origin. In other words, the y intercept must be zero.

=====================================

Part (b)

Answer: Not Proportional

Reason:

The y intercept isn't zero.

Plug x = 0 into the equation to find y = 1 is the y intercept. This graph does not pass through the origin.

Answer:

First picture: SAS and not existent, so not congruent

Second picture: AAA does not exist, so not congruent

Third picture: SAS for both (yes)

Forth picture: AAS for both (yes)

Step-by-step explanation:

Sorry for no long explanation, but if you have any specific questions, feel free to ask in the comments

Hope this helps! If you found my answer helpful, please consider marking me brainliest. Thank you!

The Intel pays $7,760 to Bally Manufacturing on August 14.

The first step in calculating what Intel Corporation pays Bally on August 14 is to determine the net price of the machinery after the trade discount and the return of $100 due to defects.

The trade discount of 40% is calculated as follows:

Discount = List price × Discount rate

Discount = $13,100 × 0.40 = $5,240

So the net price of the machinery after the trade discount is:

Net price = List price - Discount

Net price = $13,100 - $5,240 = $7,860

After Intel returns $100 of machinery, the cost of the machinery is further reduced to:

Net price after return = Net price - Return

Net price after return = $7,860 - $100 = $7,760

Since the payment terms are 3/10 EOM (end of month), Intel receives a discount of 3% if payment is made within 10 days. The 10-day period begins on August 1 and ends on August 10 (the payment due date). Since Intel pays the bill on August 14, payment is late and the 3% discount does not apply.

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Answer:

43.6 has 3 significant figures.

Answer:

a

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

I might be wrong but i'm pretty sure it's right

Length of gz = 12 units

Length of ot = 14.4 units

Given,

Triangle EGD with centroid at Z .

Now,

As we know that centroid divides the line segment in the ratio 2:1 .

Firstly calculate the length of gz,

gu = 18 unit

gz:zu = 2:1

gz = 2/3  * 18

gz = 12 units .

Secondly calculate the length of ot,

zt = 4.8 units

oz:zt = 2:1

oz = 4.8 * 2

oz = 9.6 units

ot = 9.6+ 4.8

ot = 14.4 units

Hence with the centroid length of ot and gz can be found out .

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Answer:

its B

Step-by-step explanation:

please like my answer . brainliest please

Real numbers can be expressed using the following interval,

\(\mathbb{R}=(-\infty,\infty)\)

Of course infinities are not just normal infinities but thats out of the scope of this question.

Real numbers less than two can be expressed with,

\((-\infty,\infty)\cap(-\infty,-2)=\boxed{(-\infty,-2)}\)

The \(\cap\) is called intersection ie. where are both intervals valid. First we took real numbers then we intersected them with real numbers valued less than -2 and we got real numbers which are less than -2.

Similarly we can perform with "greater than or equal to 3" real numbers,

\((-\infty,\infty)\cap[3,\infty)=\boxed{[3,\infty)}\)

So we have one interval stretching from negative infinity to (but not including) -2, and another interval stretching from including 3 to positive infinity.

If we want numbers in both intervals we can express this two ways,

First way is to use \(\cup\) union operator to denote we want numbers from two intervals,

\(\boxed{(-\infty,2)\cup[3,\infty)}\)

The second way is to specify which numbers we do not want, we do not want -2 and everything up to but not including 3, which is expressed with the following interval

\([-2,3)\)

Now we just take out the not wanted interval from real numbers and we will remain with all wanted numbers,

\(\boxed{(-\infty,\infty)-[-2,3)}\)

Hope this helps.

Answer:  Jenny was faster by 116.17

Step-by-step explanation: Jenny: 809.03 meters a minute

Johnny: 692.86 meters a minute