The complete question is;
Find the moment of inertia about each of the following axes for a rod that is 0.36 cm in diameter and 1.70m long, with a mass of 5.00 × 10 ^(−2) kg.
A) About an axis perpendicular to the rod and passing through its center in kg.m²
B) About an axis perpendicular to the rod and passing through one end in kg.m²
C) About an axis along the length of the rod in kg.m²
Answer:
A) I = 0.012 kg.m²
B) I = 0.048 kg.m²
C) I = 8.1 × 10^(-8) kg.m²
Explanation:
We are given;
Diameter = 0.36 cm = 0.36 × 10^(−2) m
Length; L = 1.7m
Mass;m = 5 × 10^(−2) kg
A) For an axis perpendicular to the rod and passing through its center, the formula for the moment of inertia is;
I = mL²/12
I = (5 × 10^(−2) × 1.7²)/12
I = 0.012 kg.m²
B) For an axis perpendicular to the rod and passing through one end, the formula for the moment of inertia is;
I = mL²/3
So,
I = (5 × 10^(−2) × 1.7²)/3
I = 0.048 kg.m²
C) For an axis along the length of the rod, the formula for the moment of inertia is; I = mr²/2
We have diameter = 0.36 × 10^(−2) m, thus radius;r = (0.36 × 10^(−2))/2 = 0.18 × 10^(−2) m
I = (5 × 10^(−2) × (0.18 × 10^(−2))^2)/2
I = 8.1 × 10^(-8) kg.m²
how much KE does the car have if it weighs 450kg and moves at the speed of 23 m/s?
Answer:-The formula of to calculate KE = 1/2 m v^2
so we,
KE = 1/2 (450kg)(23m/s)^2
KE = 1/2 ×238050
KE = 119025
Explanation: In Physics Formulas mean everything.
Newer vehicles are designed with crumple zones at the front and rear ends. Crumplezones consist of materials that deform more easily than the other regions of the car.The purpose of these zones is to increase the safety of the passengers in case of acollision. Which statement correctly explains how crumple zones reduce the impactof a collision?They extend the distance over which the impact force slows the car's motion.They convert the nature of the collision from more inelastic to more elastic.They reduce the total momentum of the system involving the colliding vehicle.They increase the mass of the vehicle relative to that of other involved objects.
They extend the distance over which the impact force slows down the car's motion
Explanations:The essence of the crumpling zone in newer cars is to convert part of the Kinetic energy of the car into a controlled deformation.
This will reduce the motion of the car at impact so that it takes a considerably longer time to stop, extend the distance over which the impact force slows down the car's motion, and reduce the shock on the passengers. This is essentially because the impact force will be reduced
A 0.032 g plastic bead hangs from a lightweight thread. Another bead is fixed in position beneath the point where the thread is tied. If both beads have charge q, the moveable bead swings out to the position shown in (Figure 1).
The magnitude of the charge of the given moveable beads is 9.33 nC.
What is the tension in the string?
The tension in the string is calculated as follows;
Tcos45 = mg
where;
T is the tensionm is the massF = Tsin45
\(\frac{kq^2}{r^2} = Tsin(45)\\\\\frac{kq^2}{r^2} = \frac{mg}{cos45} \times sin(45)\\\\\frac{kq^2}{r^2} = mg\\\\q = \sqrt{\frac{mgr^2}{k} }\)
Magnitude of the charge\(q = \sqrt{\frac{(0.032 \times 10^{-3})(9.8)(0.05)^2}{9\times 10^9} } \\\\q = 9.33\times 10^{-9} \ C\\\\q = 9.33 \ nC\)
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URGENT HELP PLS
(a) Find the frequency ratio between the two frequencies f1 = 320 Hz and
½2 = 576 Hz.
S) If we go down from / by an interval of a fourth, find the frequency ratio filfi.
(c) Find the frequency of f3.
The frequency of f3 is approximately 716 Hz.
What is frequency?The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.
a. Given two frequencies, f1 and f2, the frequency ratio is as follows:
frequency ratio= \(\frac{f2}{f1}\)
Inputting the values provided yields:
frequency ratio = \(\frac{576}{320Hz}\) =1.8.
As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.
b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by \(2^{(4/12)}\). Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:
frequency ratio= \(\frac{f}{ (f1 /f2 ) }\)= \(\frac{f}{ (f1 / 1.3348) }\)
By dividing the numerator and denominator by 1.3348, we may make this more straightforward:
frequency ratio= (f × 1.33348)/f1
As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.
c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: \(2^{(7/12)}\) = 1.49831
Therefore, the frequency of f3 is:
f3 = f1 × (\(2^{(7/12)}\)) × (\(2^{(7/12)}\)) = 320 Hz × 1.49831 ×1.49831 = 716 Hz
Therefore, the frequency of f3 is approximately 716 Hz.
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PLEASEEEEE!!!!
A cube has a mass of 100 g and a volume of 50 mL. What is the density of the cube?
Answer:
The answer is 2.0 g/mLExplanation:
The density of a substance can be found by using the formula
\(density = \frac{mass}{volume} \\\)
From the question
mass = 100 g
volume = 50 mL
We have
\( density = \frac{100}{50} = \frac{10}{5} \\ \)
We have the final answer as
2.0 g/mLHope this helps you
What type of tv uses a VfL for backlighting
A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.
LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.
The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.
Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.
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6. As you drive your car along a country road at night, a deer jumps out of the woods and stands in
the middle of the road ahead of you. This occurs just as you are passing from a 55-mi/h zone to a 50-
mi/h zone. At the 50-mi/h speed-limit sign, you slam on the car's brakes, causing them to lock up,
and skid to a stop inches from the startled deer. As you breathe a sigh of relief, you hear the sound
of a police siren. The policeman proceeds to write you a ticket for driving 56 mi/h in 50-mi/h zone.
Because of your preparation in physics, you are able to use the 25-m-long skid marks that your car
left behind as evidence that you were not speeding. What evidence do you present? You must use
work/energy methods to solve this problem! The coefficients of friction between car tires and dry
concrete are (u=1.0, μ=0.80).
As the speed of the car was less than the posted speed limit of 50 mi/h when the brakes were applied, skid marks provide evidence that driver was not speeding at the time of incident.
What is meant by coefficient of friction?Measure of the amount of friction existing between the two surfaces is called as coefficient of friction.
Change in kinetic energy is: ΔK = 0 - 1/2mv²
W = fd
As f = μN
N = mg
fd = ΔK
μN d = 1/2mv²
μmgd = 1/2mv²
v = √(2μgd/m)
v = √(20.8025*0.45/1) ≈ 29.9 mi/h
Since the car's speed was less than the posted speed limit of 50 mi/h when the brakes were applied, the skid marks provide evidence that the driver was not speeding at the time of the incident.
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(Will give Brainliest) Some scientists calculated that a whale can develop 150 kW of power when it is swimming under the water surface at a constant speed 7.77 m/s. Find the resistance force of the water exerted on the whale.
The resistance force of the water exerted on the whale is 19305 Newton.
What is power?
The quantity of energy moved or converted per unit of time is known as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in ancient writings. A scalar quantity is power.
Power = 150 kW = 150,000 Watt.
Constant speed = 7.77 m/s.
Now, Power = the resistance force × speed
150000 Watt = the resistance force × 7.77 m/s
Hence, the resistance force = 150000 Watt/ 7.77 m/s
= 19305 Newton.
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how long in seconds would it take a rock to fall 450 feet and what would be the final velocity of the rock in miles per hour when it hit the ground
Answer:
S = Vy t + 1/2 g t^2 = 1/2 g t^2 vertical speed with zero initial speed
t = (2 S / g)^1/2 with g = 32 ft/sec^2
t = (900 / 32)^1/2 = 5.30 sec time to reach ground
V = a t = 32 ft/s^2 * 5.30 s = 170 ft/sec
170 ft/sec / (88 ft/sec / 60 mph) = 116 mph since 88 ft/sec = 60 mph
er 1
DOCS
3. A ball is thrown vertically upward from a window that is 3.6 m above the ground. The ball's initial speed is
2.8 m/s and the acceleration due to gravity is 9.8 m/s2
[ 6 marks]
(a) What is the ball's speed when it hits the ground?
to in
er 1
terit
er 1 TL
er 1 TE
comm
I
(b) How long after the first ball is thrown should a second ball be simply dropped from the same window so
that both balls hit the ground at the same time?
55.com
er 1 TE
nsubmi
Answer:
?
Explanation:
A particle with mass 3×10−2 kg
k
g
and charge +3 μC
μ
C
enters a region of space where there is a magnetic field of 1 T
T
that is perpendicular to the velocity of the particle. When the particle encounters the magnetic field, it experiences an acceleration of 12 m/s2
m
/
s
2
. What is the speed of the particle when it enters the magnetic-field region?
The speed of the particle when it enters the magnetic-field region is 120,000 m/s.
Speed of the particle
Magnetic force on the particle is given as;
F = qvB
where;
q is magnitude of the chargev is speed of the particleB is magnetic field strengthFrom Newton's second law, force on an object is given as;
F = ma
where;
m is mass of the particlea is accelerationma = qvB
v = ma/qB
v = (3 x 10⁻² x 12)/(3 x 10⁻⁶ x 1)
v = 120,000 m/s
Thus, the speed of the particle when it enters the magnetic-field region is 120,000 m/s.
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How much current is running through a circuit powered by a 1.5 volt battery wit 18
ohms of resistance? How much power would this circuit generate?
How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro's number of electrons from an initial point where the electric potential is 9.20 V to a point where the electric potential is -6.90 V
Answer:
-1486 KJ
Explanation:
The work done by an electric field on a charged body is:
W = ΔV * q
where ΔV = change in voltage
q = total charge
The total charge of Avogadro's number of electrons is:
6.0221409 * 10^(23) * -1.6023 * 10^(-19) = -9.65 * 10^(4)
The change in voltage, ΔV, is:
9.20 - (6.90) = 15.4
Therefore, the work done is:
W = -9.65 * 10^(4) * 15.4 = -1.486 * 10^6 J = -1486 KJ
The negative sign means that the motion of the electrons is opposite the electrostatic force.
Brown is currently producing only corn; if he wants to produce some tobacco, in what order would he switch his fields from corn to tobacco production? What law does this represent? Explain.
Hello some data related to your question is missing attached below is the missing data
From the Table If Brown produces only Corn he will produce 50 but to produce some tobacco Brown will produce 40 Corn and 10 Tobacco to ensure the efficiency of production.
PPF ( production possibility frontier ) is a curve that shows/represent the production of various quantities of two(2) different commodities with the same limited amount of resource. In PPF the efficiency of production is not affected because the Increase in the production of a certain commodity will be balanced with a decrease in production of the other commodity. and The slope of PPF is the Marginal rate of transformation. and opportunity cost is kept constant.
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One point charge +Q is placed at the center of a square, and a second point charge -Q is placed at the upper-left corner of the square. It is observed that an electrostatic force of magnitude 2.0 N acts on the positive charge at the center. Now a third charge -Q is placed at the lower-left corner of the square, as shown in the figure. What is the magnitude of the net force that acts on the center charge now? The figure shows one positive charge labeled + Q placed at the center of a square and two negative charges labeled -Q placed at the upper left and the bottom left corners of the square.
a) 0.0 N
b) 2.8 N
c) 5.3 N
d) 4.0 N
Answer:
One should draw a diagram showing the placement of the charges.
When both charges of -Q are placed there will be no force in the vertical direction because of cancellation of forces.
A line from one corner of the square to the other makes an angle of 45 degrees,
2 cos 45 deg will be the force due to one charge.
2 * .707 = 1.41 N
So for both charges the force is (horizontal, vertical is zero)
2 * 1.41 = 2.82 N
b) is correct
The magnitude of the net force that acts on the center charge will be 2.82 N.Option B is correct.
what is the charge?
When the matter is put in an electromagnetic field, it has an electric charge, which causes it to experience a force. A positive or negative electric charge can exist.
Charges that are similar repel each other, whereas charges that are dissimilar attract each other. The term "neutral" refers to an item that has no net charge.
Case 1 ;
One point charge +Q is placed at the center of a square, and a second point charge -Q is placed at the upper-left corner of the square.
When both charges of -Q are placed there will be no force in the vertical direction because of the cancellation of forces.
A line from one corner of the square to the other makes an angle of 45 degrees,
The force due to the one charge at the angle of the 45° will be;
\(\rm F_1 = 2 \times cos 45^0 \\\\ \rm F_1 =1.41 \ N\)
For both the charge the net force is the double the force due to the one charge;
\(\rm F = 2 \times F_1 \\\\ \rm F = 2 \times 1.41 \\\\ F=2.82 \ N\)
The magnitude of the net force that acts on the center charge will be 2.82 N.
Hence option B is correct.
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Question 5 (4 points)
Piedra Vista High School is 35 degrees north of east, 3.31 miles away from FHS. How many miles north and east is it? Round to the nearest
tenth of a mile.
North:
miles
East:
miles
Blank 1:
Blank 2:
Answer:
ayussssaasssassbfjdbskgsvdksbjabsdvsjvsjhjsjajbdnjsjnsnsnsnbfndksbsjjjsjdhjjsjjsjkjsjsjbdhsjabdhdhksbshsjsjisisisjdbbdjsjsjjebwnnwjbsnbhejshvjrebbdjndnebensjHELLONODNDIDBIDDBDUDBDIjsjsExplanation:
jshshjabsjbrnejdjdhjsndjdhfisjshsidsnsndgjsbdjdvsjsvdudhwjgdusbsuwgshidsbhsgsuydisksvdudh
Calculate the force exerted on a thresher shark's eye by the hydrostatic pressure in ocean water at a depth of 380 m. (Assume the water's mass density at this depth is 1000 kg/m3k.)
Answer:
Explanation:
Hydrostatic pressure due to a water column of height h can be given by the following expression.
P = hρg
where ρ is density of water and g is acceleration due to gravity .
Substituting the values.
P = 380 x 1000 x 9.8
= 3.72 x 10⁶ Pa.
Answer:
\(F=\dfrac{3.72\times 10^6\ Pa}{A}\ N\)
Explanation:
Given that,
The density of water, d = 1000 kg/m³
Depth, h = 380 m
We need to find the force exerted on a thresher shark's eye by the hydrostatic pressure in ocean water. The force exerted by the hydrostatic pressure is given by :
\(P=\rho gh\)
Put all the values,
\(P=1000\times 9.8\times 380\\\\P=3.72\times 10^6\ Pa\)
Force exerted,
F = P/A
So,
\(F=\dfrac{3.72\times 10^6\ Pa}{A}\ N\)
Where
A is the area of crosss section
Hence, this is the required solution.
Using the CER, write an essay describing what might influence some teens to choose a sedentary lifestyle. 1. suggest ways to encourage these teens to become more physically active. 2. Use correct spelling and punctuation. Use no less than 8 sentences. *
Answer:
Sedentary lifestyle is the lifestyle by which most physical activity is abandoned, performing activities that do not require energy consumption or large muscle movements on a large scale, such as using a computer, driving a car or playing video games.
Today, most young people have gradually turned towards sedentary lifestyles, mainly motivated by the increase in technological availability, and the extensive dependence generated on technology both to communicate with their peers (cell phones, social networks, etc. .) and for leisure time (video games, etc.).
Some ways to promote physical activity in young people and prevent sedentary lifestyle can be to create sports groups, where young people can establish social relationships without depending on networks or technological devices, or establish tasks of physical activity during study or work hours.
How dose bohr’s work demonstrate the importance of communication in science?
Bohr's work demonstrates the importance of communication in science by making use of works communicated by other scientists.
About Bohr's workBohr's work on atomic structure and the quantization of energy demonstrated the importance of communication in science by highlighting the need for clear and effective communication between scientists from different fields.
Bohr's theory was based on the work of other scientists, including Planck and Einstein, and required collaboration and communication between physicists, chemists, and mathematicians.
By effectively communicating his ideas and working with others, Bohr was able to develop a groundbreaking theory that revolutionized the understanding of atomic structure and paved the way for future advances in physics and chemistry.
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A 80kg stone falls from the top of the 360 meter cliff. Neglecting friction, how fast will the stone be moving just before it hits the ground?
The stone will be moving at a speed of approximately 84.4 meters per second just before it hits the ground, neglecting friction.
To find how fast will the stone be moving just before it hits the ground?This problem can be solved using the laws of kinematics and conservation of energy. The potential energy of the stone at the top of the cliff is converted to kinetic energy as it falls. We can equate the potential energy at the top of the cliff to the kinetic energy just before hitting the ground.
Potential energy = mgh,
Where
m is the mass of the stone g is the acceleration due to gravity (9.8 m/s^2) h is the height of the cliff (360 meters)Kinetic energy = (1/2)mv^2,
Where
v is the velocity of the stone just before hitting the ground.Equating these two expressions and solving for v, we get:
mgh = (1/2)mv^2
v^2 = 2gh
v = sqrt(2gh)
Plugging in the given values, we get:
v = sqrt(2 x 9.8 m/s^2 x 360 m) = 84.4 m/s
Therefore, the stone will be moving at a speed of approximately 84.4 meters per second just before it hits the ground, neglecting friction.
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What is the average speed of the bicyclist's ride?
A.45m/s
B.7.5m/s
C45mi/hr
D.7.5mi/hr
A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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two identical loudspeakers 2.50 m m apart are emitting sound waves into a room where the speed of sound is 340 m/s m / s . abby is standing 4.00 m m in front of one of the speakers, perpendicular to the line joining the speakers, and hears a maximum in the intensity of the sound.
The lowest possible frequency of sound for which this is possible is 85.0 Hz.
To work out the least conceivable recurrence of sound for which Abby hears a greatest in the power of the sound, we first need to find the frequency of the sound waves, which is 4.00 m. Utilizing the distance among Abby and the speaker, we can find the point between the line associating Abby to the speaker and the line interfacing the two speakers, which is 68.2 degrees. Utilizing geometry, we find the stage contrast between the waves from the two speakers that arrives at Abby is 2π. Consequently, the most minimal conceivable recurrence of sound is v/λ = 85.0 Hz.
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The complete question is:
Two identical loudspeakers 2.00 m apart are emitting sound waves into a room where the speed of sound is 340 m/s. Abby is standing 5.50 m in front of one of the speakers perpendicular to the line joining the speakers, and hears a maximum in the intensity of the sound. calculate the lowest possible frequency of sound for which this is possible? Express your answer with the appropriate units.
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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There is a bell at the top of a tower that is 45 m high. The bell weighs 15 kg. The bell has energy. Calculate it.
Answer:
6621.75J
Explanation:
In this case, the bell is not in motion. So we are going to calculate its potential energy rather than its kinetic energy since kinetic energy is the energy a body possesses in motion.
The formula for the potential energy is m*g*h, meaning the mass * acceleration due to gravity * height. Here the mass, m = 15kg, the acceleration due to gravity = 9.81m/s^2, and the height, h = 45m
Substituting our values, the answer becomes 15 * 9.81 * 45 = 6621.75J. Hope you understood my explanation?
what is the pressure of a tank of uniform cross sectional area 4.0m2 when the tank is filled with water a depth of 6m when given that 1 atm=1.013 x 10^5pa density of water=1000kgm-3 g=9.8m/s2
The pressure of a tank of uniform cross-sectional area 4.0m2 when the tank is filled with water at a depth of 6m is 58800 Pa.
Pressure calculationTo find the pressure in the tank, we can use the formula for pressure:
Pressure = density x gravity x height
Density of water (ρ) = 1000 kg/m³
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) = 6 m
Thus:
Pressure = 1000 kg/m³ x 9.8 m/s² x 6 m
Pressure = 58800 kg/(m·s²)
Since the unit of pressure is Pascal (Pa), which is equivalent to kg/(m·s²), the pressure in the tank is:
Pressure = 58800 Pa
Therefore, the pressure in the tank when it is filled with water to a depth of 6 m is 58800 Pascal.
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1. At a location in Europe, it is necessary to supply 1000 kW of 60-Hz power. Only power sources available operate at 50 Hz. It is decided to generate the power by means of a motor-generator set consisting of a 20- pole synchronous motor (its electrical rotating frequency is 50 Hz) driving a synchronous generator. How many poles should the synchronous generator have in order to convert 50-Hz power to 60-Hz power
Answer:
Explanation:
From the given information:
The speed of a synchronous motor in relation to its frequency can be represented with the formula:
\(n_{sm}= \dfrac{120f_{se}}{P}\)
where,
the electrical frequency \(f_{se}\) is measured in Hz
the number of poles = P
For us to estimate the number of poles to have 50 Hz - 60 Hz Power, then we need to relate the frequencies of the above equation.
i.e
\(\dfrac{120(50 \ Hz)}{P_1}= \dfrac{120( 60 \Hz)}{P_2} \\ \\ \dfrac{6000 \ Hz}{P_1}= \dfrac{7200 \ Hz}{P_2} \\ \\ \dfrac{P_2}{P_1}=\dfrac{7200}{6000} \\ \\ \\ \dfrac{P_2}{P_1}= \dfrac{12}{10}\)
Thus, we can conclude that 10 poles synchronous motor is attached with 12 poles synchronous generator in order to convert 50 Hz to 60 Hz power.
I need help in this pls i really need a answer
Answer:
In terms of distance, average speed is 20 km/h
In terms of displacement, average speed is 0 km/h.
Explanation:
Total distance:
\( = (40.0 - 10.0) + (20.0 - 10.0) + (40.0 - 20.0) \\ = 30.0 + 10.0 + 20.0 \\ = 60.0 \: km\)
Total time is 3.0 hours
but:
\(average \: speed = \frac{total \: distance}{total \: time} \\ \)
In terms of distance.
substitute:
\(average \: speed = \frac{60.0}{3.0} \\ \\ = 20 \: {kmh}^{ - 1} \)
\(displacement = ( - 30.0) + 10 .0+ 20.0 \\ = 0\)
In terms of displacement:
\(speed = \frac{0}{3} \\ \\ = 0 \: {kmh}^{ - 1} \)
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Please write the processes and tectonic plate interactions that are causing the geological event to occur. Include an explanation of convection currents.
Answer:
Explanation:
These tectonic plates rest upon the convecting mantle, which causes them to move. The movements of these plates can account for noticeable geologic events such as earthquakes, volcanic eruptions, and more subtle yet sublime events, like the building of mountains.
Answer:
Tectonic plates recurring over and over again cause a rupture in the Earth's crust. This agitates the magma in volcanoes, causing the volcano to erupt.
Explanation:
2. A crane can lift a 500 kg mass to height of 30 m in 2 minutes. The power at which the crane is operating is
A. 125 Watts
B. 1225 Watts
C.) 7500 Watts
D. 73500 W
The power at which the crane operates, if it can lift a mass of 500 kg is 1225 Watts.
What is power?Power is the rate at which work is done.
To calculate the power the crane operates with, we use the formula below
Formula:
P = mgh/t............................... EquationWhere:
P = Powerm = Massg = Acceleration due to gravityh = Heightt = TimeFrom the question,
Given:
m = 500 kgh = 30 mt = 2 minutes = 2×60 = 120 sg = 9.8 m/s²Substitute these values into equation 1
P = (500×30×9.8)/120P = 1225 WHence, the right option is B. 1225 Watts.
Learn more about power here: https://brainly.com/question/25864308
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