Find the pH of each of the following solutions of mixtures of acids.
8.0×10−2 M in HNO3 and 0.185 M in HC7H5O2,
1.5×10−2 M in HBr and 2.0×10−2 M in HClO4,
9.5×10−2 M in HF and 0.230 M in HC6H5O,
0.100 M in formic acid and 5.5×10−2 M in hypochlorous acid
pl

Answers

Answer 1

1. The pH of 8.0×10−2 M in HNO3 and 0.185 M in HC7H5O2 is 2.12.

To calculate the pH of this mixture, first, calculate the total concentration of the acid. This can be done using the following equation:

Total concentration = 8.0 × 10−2 + 0.185 = 0.193 M

Next, calculate the hydrogen ion concentration (H+) using the following equation:

H+ = 10−2.12 = 5.8 × 10−3 M

Finally, calculate the pH using the following equation:

pH = −log[H+] = −log(5.8 × 10−3) = 2.12

2. The pH of 1.5×10−2 M in HBr and 2.0×10−2 M in HClO4 is 1.76.

To calculate the pH of this mixture, first, calculate the total concentration of the acid. This can be done using the following equation:

Total concentration = 1.5 × 10−2 + 2.0 × 10−2 = 3.5 × 10−2 M

Next, calculate the hydrogen ion concentration (H+) using the following equation:

H+ = 10−1.76 = 5.6 × 10−2 M

Finally, calculate the pH using the following equation:

pH = −log[H+] = −log(5.6 × 10−2) = 1.76

3. The pH of 9.5×10−2 M in HF and 0.230 M in HC6H5O is 0.77.

To calculate the pH of this mixture, first calculate the total concentration of the acid. This can be done using the following equation:

Total concentration = 9.5 × 10−2 + 0.230 = 0.329 M

Next, calculate the hydrogen ion concentration (H+) using the following equation:

H+ = 10−0.77 = 2.3 × 10−1 M

Finally, calculate the pH using the following equation:

pH = −log[H+] = −log(2.3 × 10−1) = 0.77

4. The pH of 0.100 M in formic acid and 5.5×10−2 M in hypochlorous acid is 1.25.

To calculate the pH of this mixture, first, calculate the total concentration of the acid. This can be done using the following equation:

Total concentration = 0.100 + 5.5 × 10−2 = 0.105 M

Next, calculate the hydrogen ion concentration (H+) using the following equation:

H+ = 10−1.25 = 8.0 × 10−2 M

Finally, calculate the pH using the following equation:

pH = −log[H+] = −log(8.0 × 10−2) = 1.25

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Related Questions

12. Imagine that you are a particle of a perfume. Describe what happens to you when the bottle is opened and eventually someone smells you on the other side of the room. Your description should include, how you move, what other particles you might meet and where you go.​

Answers

The process by which the molecules of the gas can be able to move is the process of diffusion.

What is diffusion?

We know that according to the Graham's law, the rate of the diffusion  of the gas is inversely proportional to the molar mass of the gas. When we open the bottles, the molecules of the perfume would begin to move.

As the bottle is opened, the molecules would escape from the bottle and then be able to travel through the room and get to where you are by the principle of diffusion.

Hence, the movement of the perfume is according to the Graham's law of diffusion in gases.

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Determine the total kilojoules in two tablespoons of crunchy peanut butter that contains 6 g of carbohydrate, 11 g of fat, and 9 g of protein.

Answers

Answer:

  665 kJ

Explanation:

We assume that carbohydrates and protein each have 4 kilocalories per gram, and that fat has 9 kilocalories per gram. Then the number of kilocalories in the peanut butter is ...

  4(6 +9) +9(11) = 159 . . . . kilocalories

Each kilocalorie translates to 4.184 kilojoules, so the total is ...

  (159 kCal)(4.184 kJ/kCal) = 665.256 kJ

2 Tbsp of crunchy peanut butter contains about 665 kJ of energy.

The number of kilojoules in two table spoons of crunchy peanut butter obtained by adding the amount of kilojoules in each food type is 673kJ

From the table given ; the amount of kilojoules per gram of each food type is :

Carbonhydrate __17Fat ___________38Protein ________17

I gram of Carbonhydrate = 17 kJ

6 grams of Carbonhydrate = (6 × 17) = 102 kJ

I gram of Fat = 38 kJ

11 grams of Carbonhydrate = (11 × 38) = 418 kJ

I gram of Protein = 17 kJ

9 grams of Carbonhydrate = (9 × 17) = 153 kJ

Therefore, the total kilojoules present is (102 + 408 + 153)kJ = 673 kJ

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Determine the total kilojoules in two tablespoons of crunchy peanut butter that contains 6 g of carbohydrate,

Determine the [OH−] of a solution that is 0.115 M in CO32−. For carbonic acid (H2CO3), Ka1=4.3×10−7 and Ka2=5.6×10−11.

Answers

Answer:

[OH⁻] = 4.3 x 10⁻¹¹M in OH⁻ ions.

Explanation:

Assuming the source of the carbonate ion is from a Group IA carbonate salt (e.g.; Na₂CO₃), then 0.115M Na₂CO₃(aq) => 2(0.115)M Na⁺(aq) + 0.115M CO₃²⁻(aq). The 0.115M CO₃²⁻ then reacts with water to give 0.115M carbonic acid; H₂CO₃(aq) in equilibrium with H⁺(aq) and HCO₃⁻(aq) as the 1st ionization step.

Analysis:

            H₂CO₃(aq)     ⇄     H⁺(aq)    +    HCO₃⁻(aq); Ka(1) = 4.3 x 10⁻⁷

C(i)          0.115M                      0                  0

ΔC              -x                        +x                  +x

C(eq)    0.115M - x                   x                    x

            ≅ 0.115M

Ka(1) = [H⁺(aq)][HCO₃⁻(aq)]/[H₂CO₃(aq)] = [(x)(x)/(0.115)]M = [x²/0.115]M

= 4.3 x 10⁻⁷  => x = [H⁺(aq)]₁ = SqrRt(4.3 x 10⁻⁷ · 0.115)M = 2.32 x 10⁻⁴M in H⁺ ions.

In general, it is assumed that all of the hydronium ion comes from the 1st ionization step as adding 10⁻¹¹ to 10⁻⁷ would be an insignificant change in H⁺ ion concentration. Therefore, using 2.32 x 10⁻⁴M in H⁺ ion  concentration, the hydroxide ion concentration is then calculated from

[H⁺][OH⁻] = Kw => [OH⁻] = (1 x 10⁻¹⁴/2.32 x 10⁻⁴)M = 4.3 x 10⁻¹¹M in OH⁻ ions.

________________________________________________________

NOTE: The 2.32 x 10⁻⁴M  value for [H⁺] is reasonable for carbonic acid solution with pH ≅ 3.5 - 4.0.

The concentration of hydroxide ion of given solution is 4.3 x 10⁻¹¹M.

How we calculate the [OH⁻]?

We can calculate the concentration of hydroxide ions as follow:

[OH⁻][H⁺] = 10⁻¹⁴

Given chemical reaction with ICE table shown as below:

                H₂CO₃(aq)     ⇄     H⁺(aq)    +    HCO₃⁻(aq)

Initial:             0.115                      0                    0

Change:           -x                        +x                  +x

Equilibrium:  0.115-x                   +x                  +x

Given that, Ka = 4.3 x 10⁻⁷

Equilibrium constant for this reaction is written as:

Ka = [H⁺][HCO₃⁻]/[H₂CO₃]

4.3 x 10⁻⁷ = x² / 0.115

x = 2.32 x 10⁻⁴M = [H⁺]

Now we calculate the concentration of hydroxide ion as:

[OH⁻][H⁺] = 10⁻¹⁴

[OH⁻] = 10⁻¹⁴ / 2.32 x 10⁻⁴ = 4.3 x 10⁻¹¹M

Hence, value of [OH⁻] is 4.3 x 10⁻¹¹M.

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A 2.40 kg block of ice is heated with 5820 J of heat. The specific heat of water is 4.18 J•g^-1•C^-1. By how much will it’s temperature rise, assuming it does not melt?

Answers

Answer: The temperature rise is \(0.53^0C\)

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

\(Q=m\times c\times \Delta T\)

Q = Heat absorbed by ice = 5280 J

m = mass of ice = 2.40 kg = 2400 g   (1kg=1000g)

c = heat capacity of water = \(4.18J/g^0C\)

Initial temperature  = \(T_i\)

Final temperature = \(T_f\)  

Change in temperature ,\(\Delta T=T_f-T_i=?\)

Putting in the values, we get:

\(5280J=2400g\times 4.18J/g^0C\times \Delta T\)

\(\Delta T=0.53^0C\)

Thus the temperature rise is \(0.53^0C\)

Answer: 0.580 C

Explanation: On Ck-12 I got it right sooo...

Please please help please help me please please help me

Please please help please help me please please help me

Answers

Answer: the left group is the alkali metals while in the right side its the halogens... up to you to pick. either A or D

Explanation:

Units for slope = units for vertical axis over units for horizontal axis

Answers

On a graphic axis, we should alter the units' size, interval, starting and ending points, among other things. amphoteric Alter the Vertical Axis Units in the Sections.

What do numbers on an axis represent?

The units into that an axis is subdivided define its scale. Grid lines, labels, and ticks are used to identify the units. The ticking, labels, plus grid lines alter depending on the scale of the axis. Each category itself is unit on a category axis, which has a relatively straightforward scale.

How can I modify the vertical axis's units?

Change any or all of the following settings underneath Value axis scale by clicking Scale with in Format Axis dialogue box: Enter a different amount in the minimum and maximum boxes, respectively, to modify the value where the vertical (valued) axis begins or stops.

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Calculate the pH of a solution having the following ion concentrations at 298 K. [H+] = 4.6 × 10^-2 M

Answers

Answer:

The pH of the solution is 1.34, being an acidic pH.

Explanation:

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.   The acronym pH stands for hydrogen potential.

The pH scale ranges from 0 to 14. Values ​​less than 7 indicate the acidity range and those greater than 7 indicate alkalinity or basicity. Value 7 is considered neutral. Mathematically, pH is the negative logarithm of the molar concentration of hydrogen or proton ions (H⁺) or hydronium ions (H₃O⁺).

pH= - log [H⁺] = - log [H₃O⁺]

In this case, [H⁺]= 4.6*10⁻² M. Replacing:

pH= - log 4.6*10⁻²

Solving:

pH= 1.34

The pH of the solution is 1.34, being an acidic pH.

How are fusion and fission similar? Click the two answers that apply.

a
Both produce large amounts of energy.
b
Both occur in the stars.
c
Both are used to create electricity.
d
Both involve changes in the nucleus of atoms.
e
Both create radioactive waste.

Answers

Both product large amounts of energy

Sodium metal (Na) reacts explosively with water to form sodium hydroxide (NaOH) and hydrogen gas. How many moles of sodium are needed to produce 154 moles of hydrogen gas? (Hint: Balance the equation.)

Answers

Answer:

308 moles of sodium

Explanation:

The balanced equation for the chemical reaction between sodium metal (Na) and water (H₂O) is the following:

2 Na(s) + 2 H₂O → 2 NaOH(aq) + H₂(g)

From the equation, we can see that 2 moles of Na react with 2 moles of H₂O to give 2 moles of NaOH and 1 mol of H₂ (hydrogen gas). So the stoichiometric mole ratio between Na and H₂ is: 2 mol Na/1 mol H₂. Thus, we multiply the mole ratio by the moles of H₂ to be produced to obtain the moles of Na required:

moles of Na required =  2 mol Na/1 mol H₂ x 154 moles H₂ = 308 moles Na

Therefore, 308 moles of sodium are needed to produce 154 moles of hydrogen gas.

For reactions in the gas phase, an equilibrium constant may be written in terms of molarity (Kc) or in terms of partial pressures (Kp).
The value of Kc for the reaction shown below is equal to 2.9×10⁻⁴ at 298K.
2 NOBr(g) ⇄ 2NO(g) + Br₂(g)
What is the value for Kp at 298K for the reaction represented by the equation shown below? The value for the gas constant, R, is 0.08206 L . atm/mol. K.
NOBr(g) ⇄ NO}(g) + 1/2 Br₂(g)

For reactions in the gas phase, an equilibrium constant may be written in terms of molarity (Kc) or in

Answers

The equilibrium constant of the reaction on the basis of concentration is  1.2 * 10^-7.

What is the Kc?

We know that the equilibrium constant has to do with the value that shows the extent to which the reactants can be converted into products in the reaction as shown. We have been given in the question, the equilibrium constant that is based on the partial pressures of the reactants.

We then have the formula that we have to use to solve the problem as;

Kp = Kc(RT)^Δn

Kp = Equilibrium constant based on partial pressure

Kc = Equilibrium constant based on concentration

R = Gas constant

T = temperature

n = Number of moles

Thus we have;

Kc = Kp/(RT)^Δn

Kc =  2.9×10⁻⁴/(8.314 * 298)^(3-2)

Kc = 2.9×10⁻⁴ /2477.57

Kc = 1.2 * 10^-7

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which is the graph of the function g(x) = f(-x)​

Answers

To graph the function g(x) = f(-x), you can start with the graph of f(x) and then reflect it about the y-axis.

What is a graph of the function g(x) = f(-x)?

To find the graph of the function g(x) = f(-x), we can start with the graph of the function f(x) and then reflect it about the y-axis.

If the graph of f(x) is symmetric with respect to the y-axis, meaning it is unchanged when reflected, then g(x) = f(-x) will have the same graph as f(x).

However, if the graph of f(x) is not symmetric with respect to the y-axis, then g(x) = f(-x) will be a reflection of f(x) about the y-axis.

In either case, the resulting graph of g(x) = f(-x) will be symmetric with respect to the y-axis.

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which is the graph of the function g(x) = f(-x)

A wooden block has the following measured dimensions: height 1.25 cm; width 2.5 cm and length of 15.956 cm. Calculate its volume in ml with the proper number of significant figures.

Answers

Answer:

\(V=50mL\)

Explanation:

Hello,

In this case, by knowing that the volume of an object is computed by considering its dimensions, width, length and height, for the given measurements, we obtain:

\(V=W*H*L=1.25cm*2.5cm*15.956cm\\\\V=49.86cm^3\)

Moreover, since one cubic centimetre equals one millilitre, the required volume is:

\(V=49.86cm^3*\frac{1mL}{1cm^3}\\ \\V=49.86mL\)

Finally, since 2.5 cm has the fewest significant figures (2), the proper result is:

\(V=50mL\)

Regards.

Which of the following best describes the structure of a protein?

a
Carbon ring(s)
b
Hydrocarbon(s)
c
Single or double helix
d
Globular or fibrous

Answers

Answer:

I'm pretty sure its d.

Explanation:

because a gbular protein is a protein that is round in shape, and a fibrous is a long a thin shaped protein. Which those are two kinds of proteins.

how many bond can boron make without hybridization

Answers

Without hybridization, boron can form 4 bonds

What is hybridization?

Hybridisation is phenomenon of combining two atomic orbitals to give a new degenerate hybrid orbital which have same energy levels. Hybridization increases the stability of bond formation than unhybridized orbitals. We can predict the shape of molecules by its hybridization.

With hybridization , boron can form 3 bonds.

Hence, without hybridization, Boron donates the lone pair of electrons to form the fourth bond. In addition to that Boron is a second period element hence, which makes it small in size and d-orbitals are unavailable as well. Hence, Boron can only form 4 bonds with hybridization.

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3.31 grams of hydrogen nitrate is mixed with 750.0 ml of water to make a solution.
a. What is the molarity of this solution?
b. Calculate both the hydronium ion and hydroxide ion concentrations of this solution.
c. Find both the pH and the pOH of this solution.
d. Is this solution an acid or a base?
c. Write the balanced chemical equation for when this solution is mixed with sodium hydroxide.
f. Label the acid, base, conjugate acid, and conjugate base for this reaction.

Answers

a)The molarity of this solution is 0.07 M.

b)The hydronium ion concentration is 0.07 M, and the hydroxide ion concentration is approximately 1.43 x 10^(-13) M.

c)The pH ≈ 1.15 & pOH ≈ 12.85

d)This solution is an acid.

e)HNO₃ + NaOH → NaNO₃ + H₂O

f)HNO₃ is the acid.

NaOH is the base.

NaNO₃ is the conjugate acid of the base NaOH.

H₂O is the conjugate base of the acid HNO₃.

To find the molarity (M) of the solution, we need to calculate the number of moles of solute (hydrogen nitrate) and divide it by the volume of the solution in liters.

a.The molar mass of hydrogen nitrate (HNO3) is 63.01 g/mol.Moles of HNO3 = 3.31 g / 63.01 g/mol = 0.0526 mol

Volume of solution in liters = 750.0 mL / 1000 mL/L = 0.750 L

Molarity (M) = Moles of solute / Volume of solution in liters

M = 0.0526 mol / 0.750 L ≈ 0.070 M

b. Hydrogen nitrate (HNO3) dissociates in water to form hydronium ions (H3O+) and nitrate ions (NO3-). Since the compound is a strong acid, it fully dissociates. Thus, the concentration of hydronium ions and nitrate ions is the same as the molarity of the solution, which is 0.070 M.

c. The pH and pOH can be calculated using the formulas: pH = -log[H3O+] and pOH = -log[OH-]. Since the solution is acidic, [H3O+] = 0.070 M.

pH = -log(0.070) ≈ 1.155

pOH = 14 - pH ≈ 14 - 1.155 ≈ 12.845

d. This solution is an acid since it contains hydronium ions (H3O+), which are characteristic of acidic solutions.

e. The balanced chemical equation for the reaction between hydrogen nitrate (HNO3) and sodium hydroxide (NaOH) is:

HNO3 + NaOH -> NaNO3 + H2O

f. In this reaction, HNO3 acts as the acid (donates a proton, H+), NaOH acts as the base (accepts a proton, OH-), NaNO3 is the conjugate base of HNO3, and H2O is the conjugate acid of OH-.

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jfvbgbgvcfxfhhgIhhjj

Answers

Answer: what?

Explanation:

Answer: Huh?

Explanation:

Mr. Juan is husband of Maria, before they get married Maria knows that her husband cannot make a baby since he cant produce sperm. But during their 2 years in marriage, Maria got pregnant. Is Juan can file a case to Maria? What it is? Support your answer?​

Answers

Answer:

yes but first he need to check himself

Explanation:

bcoz if he cannot produce a sperm than she might have cheated him and the baby might be of someone other.

Two hydrogen atoms form a hydrogen molecule by which?Loosing electrons Sharing protons Gaining electrons Sharing electrons

Answers

Step 1 - Deciding between ionic and covalent bond

In the ionic bond, atoms gain or lose electrons, forming ions, which attract themselves thus resulting in a very strong chemical bond. In the covalent bond, on the other hand, electrons are shared by two atoms, resulting in a molecule.

The ionic bond usually happens between a metal (low ionization energies) and a non-metal (high electron affinities), while covalent bond happens between two or more non-metal atoms.

Therefore, looking at the atoms in the substance we can discover whether it is an ionic or covalent substance.

Step 2 - Using this information to answer the exercise

Note that hydrogen gas (H2) is a molecule. Therefore, its bonds must be covalent. That is so because H is a non-metal. Whenever two non-metals bond, be they different or the same, a covalent bond arises.

Since a covalent bond is the sharing of electrons between atoms, the correct answer is item d) sharing electrons.

A 29.3-g sample of an alloy at 93.00 °C is placed into 50.0 g of water at 22.00 °C in an insulated coffee-cup calorimeter with a heat capacity of 9.20
K. If the final temperature of the system is 31.10 °C, what is the specific heat capacity of the alloy?

Answers

The specific heat capacity of the alloy is 0.120 J/g°C.

What is Specific heat capacity?

Specific heat capacity, also known as specific heat, is the amount of heat required to raise the temperature of a unit mass (usually one gram) of a substance by one degree Celsius or Kelvin. Each substance has its own specific heat capacity, which depends on its chemical composition and physical state. The SI unit of specific heat is joules per gram per degree Celsius (J/g°C).

First, we need to calculate the heat absorbed by the water:

q_water = m_water * C_water * ∆T

where m_water is the mass of water, C_water is the specific heat capacity of water, and ∆T is the change in temperature of the water.

m_water = 50.0 g

C_water = 4.18 J/g°C

∆T = 31.10°C - 22.00°C = 9.10°C

q_water = (50.0 g) * (4.18 J/g°C) * (9.10°C) = 1911.5 J

Next, we need to calculate the heat released by the alloy:

q_alloy = - q_water

Since the calorimeter is insulated, the heat lost by the alloy is equal to the heat gained by the water.

q_alloy = m_alloy * C_alloy * ∆T

where m_alloy is the mass of the alloy, C_alloy is the specific heat capacity of the alloy, and ∆T is the change in temperature of the alloy.

m_alloy = 29.3 g

∆T = 31.10°C - 93.00°C = -61.90°C (note the negative sign)

q_alloy = (29.3 g) * C_alloy * (-61.90°C)

Finally, we can solve for the specific heat capacity of the alloy:

C_alloy = - q_water / (m_alloy * ∆T)

C_alloy = - (1911.5 J) / ((29.3 g) * (-61.90°C))

C_alloy = 0.120 J/g°C

Therefore, the specific heat capacity of the alloy is 0.120 J/g°C.

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A 0.470 g sample of a metal, M, reacts completely with sulfuric acid according to M(s)+H2SO4(aq)⟶MSO4(aq)+H2(g) A volume of 217 mL of hydrogen is collected over water; the water level in the collecting vessel is the same as the outside level. Atmospheric pressure is 756.0 Torr, and the temperature is 25 °C. The vapor pressure of water at 25 °C is 23.8 Torr. Calculate the molar mass of the metal.

Answers

The molar mass when rected with sulphuric acid to liberate 249 mL of hydrogen gas is 48 g/mol

The volume (V) = 249 mL = 249 / 1000 = 0.249 L

Pressure (P) = 1.0079 – 0.03167 = 0.97623 bar

The temperature (T) = 25.0 °C = 25 + 273 = 298 K

Gas constant (R) = 8.314×10¯² bar.L/Kmol

Number of mole (n) =?

n = PV / RT

n = (0.97623 × 0.249) / (8.314×10¯² × 298)

n = 0.0098 mole

How to determine the mole of the metal

Balanced equation

M(s) + H₂SO₄(aq) —> MSO₄(aq) + H₂(g)

From the balanced equation above,

1 mole of M reacts to produce 1 mole of H₂.

Therefore,

Mole of metal = 0.0098 mole

Mass of metal = 0.539 g

Molar mass is given as mass upon mole

Molar mass of metal = 0.470 / 0.0098

Molar mass of metal = 48 g/mol

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5. Where would you find the focus of an earthquake?



Earth Science .

Answers

Answer:

below the surface

Explanation:

below the surface is the answer

A baseball strikes the roof of a car and dents it. The paint on the roof begins to crack and chip, exposing the metal. The exposed metal on the roof rusts, eventually causing a small hole in the roof. 17. Which event is a chemical change? The baseball strikes the roof The roof of the car dents The paint cracks and chips The exposed metal rusts​

Answers

Answer:

The exposed metal rusts is an example of a chemical change because rust is an example of a chemical change in objects for example bicycles, scooters, etc.

The exposed metal rust

1. What process occurs along divergent plate boundary?

2. What geologic features formed when two plates moved away from each other?
3. Compare rift valley from mid-ocean ridge. Explain your answer. PIVOT 4A CALABARZON 24​

Answers

Answer:

1. Earthquakes and Eruptions (volcanoes)

2. Divergent plate boundary

3. Apart from a widening valley, it equally contributes to steep mountain sides spreading. A mid-oceanic ridge is naturally produced if two oceanic plates naturally start moving away from each other.

Explanation:

1. When a divergent boundary occurs beneath oceanic lithosphere, the rising convection current below lifts the lithosphere, producing a mid-ocean ridge. Extensional forces stretch the lithosphere and produce a deep fissure. When the fissure opens, pressure is reduced on the super-heated mantle material below. It responds by melting, and the new magma flows into the fissure. The magma then solidifies and the process repeats itself.

2. When two plate diverge from each other also known as divergent (di-apart, vergere- to inclined) plate margin .

Two plate diverge along oceanic ridges where new lithosphere is created.

Now come to the main point: Geological Features

When two oceanic plate diverge then new sea floor is created by a process called sea floor spreading and features like Mid oceanic ridges, volcanoes & Young lava flows forms. Ex. East Pacific Rise, Mid-Adlantic Ridge.

When two continental plates diverge by continental rifting then features like Rift valley, volcanoes are found. Ex of continent continent -East Africa rift vally, Red sea.

3. The major difference between different types is what type of plate the divergent boundary is between. If the boundary is found between two continental plates you are left with a rift valley. ... If two oceanic plates begin moving away from each other it creates a mid-oceanic ridge.

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What happens when a high pressure system goes towards a low pressure system?

Answers

The water caper within condenses and forms clouds and precipitation

3) A car traveling at a constant velocity of 35 km/h North comes to a full stop 15 seconds
after the driver applies the brakes. What is the acceleration of the car?
A. 2.3 m/s 2
B. -2.3 m/s 2
C. -0.43 m/s 2
D. 0.43 m/s 2

3) A car traveling at a constant velocity of 35 km/h North comes to a full stop 15 secondsafter the driver

Answers

The acceleration of the car is -2.3m/s².

Explain what an acceleration is.

Acceleration is the rate at which the direction and speed of motion change over time. It is said to have been accelerated when something changes its direction and moves faster or slower. Motion on a circle accelerates even when the speed is constant because the direction is constantly changing.

Velocity is the rate at which displacement changes. The rate at which speed changes is known as acceleration. Because it consists of both magnitude and direction, velocity is a vector quantity. Since acceleration is merely the rate at which velocity changes, it too is a vector quantity.

v = u +at

0 = 35 + a×15

15a = -35

a = -35/15

a = -2.3m/s².

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Answer:

B. -2.3 m/s²

Explanation:

To answer this question, we have to use the following formula:
\(\boxed{a = \frac{v - u}{t}}\),

where:

• a ⇒ acceleration

• v ⇒ final velocity

• u ⇒ initial velocity

• t ⇒ time taken for the change in velocity to occur

From the question, we know that initially, the car was travelling at 35 km/h. Therefore, u = 35 km/h. The question also tells us that the car comes to a full stop, meaning its final velocity is 0 m/s. Therefore, v = 0 km/h. It takes the car 15 seconds to stop, so t = 15 s.

Using the information above and substituting it into the formula, we can calculate the acceleration of the car:

\(a = \frac{0 - 35}{15}\)

  = -2.3 m/s²

Therefore, the acceleration of the car is -2.3 m/s², and the correct answer is B.

QA49 (N13/13/Q9)
Use of the Data Booklet is relevant to this question.
When an evacuated fluorescent light tube of volume 300 cm^3 is filled with a gas at 300K and
101 kPa, the mass of the tube increases by 1.02g. The gas obeys the ideal gas equation
What is the identity of the gas?

A argon
B krypton
C neon
D nitrogen

Answers

Nitrogen gas is the Answer
D, nitrogen is the correct answer

What amount of a 75 % m/v solution will be made if 50 g of solute are dissolved? Thank you po in advance.

Answers

The mass by volume percentage is an important method which is used to calculate the concentration of a solution. This type of concentration is usually expressed as a percentage. Here the amount of solute is

The mass by volume percentage of a solution is defined as the ratio of the mass of solute that is present in a solution relative to the volume of the solution as a whole.

The equation used to calculate the mass by volume percentage is:

m / v = Mass of solute / Volume (mL) of solution × 100 %

m / v = 50 g / 75 mL + 25 mL = 0.5  × 100 % = 50%

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Liquid nitrogen is obtained from liquefied air and is used to prepare frozen goods and in low-temperature research. The density of the liquid at its boiling point (−196°C or 77 K) is 0.808 g/cm3. Convert the density to units of kg/m3.

Answers

Answer:

The density of the liquid is \(808\ kg/m^3\).

Explanation:

It is given that,

The density of liquid is 0.808 g/cm³

We need to convert the density into kg/m³

We know that,

1 kg = 1000 g

And 1 m = 100 cm

So,

\(d=0.808\ \dfrac{g}{cm^3}\\\\=0.808 \dfrac{(1/1000)\ kg}{(1//100\ cm)^3}\\\\d=808\ kg/m^3\)

So, the density of the liquid is \(808\ kg/m^3\).

The density of the liquid nitrogen in Kg/m³ is 808 Kg/m³

From the question given above, the following data were obtained:

Density (g/cm³) = 0.808 g/cm³

Density (Kg/m³) =?

We'll begin by converting 0.808 g/cm³ to Kg/cm³

1 g/cm³ = 0.001 Kg/cm³

Therefore,

0.808 g/cm³ = 0.808 × 0.001

0.808 g/cm³ = 0.000808 Kg/cm³

Finally, we shall convert 0.000808 Kg/cm³ to Kg/m³. This can be obtained as described below:

1 Kg/cm³ = 10⁶ Kg/m³

Therefore,

0.000808 Kg/cm³ = 0.000808 × 10⁶

0.000808 Kg/cm³ = 808 Kg/m³

Thus, 0.808 g/cm³ is equivalent to 808 Kg/m³

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The data in the table below represents the pressure of the gas as the temperature changes. Plot a graph of this data, using the blank graph provided below. Draw a trend line and calculate its slope. How are the variables related? What will the pressure of the gas be at 0°C?

Answers

Answer: A

Explanation:

How many valence electrons does Al have

Answers

Answer:

3 valence electrons

Explanation :

How many valence electrons does Al have?

3 valence electrons

Aluminium has 3 valence electrons. Valence electrons are located in the outermost shell of an element.

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