Answer:
1
Step-by-step explanation:
I used DESMOS and to find this answer
Hope this Helped
Solve for x and then answer
Answer:
Value of x = 70'
Step-by-step explanation:
Given:
Given quadrilateral is a cyclic quadrilateral, in a cyclic quadrilateral sum of opposite angle is 180' .
Find:
Value of x
Computation:
x' + 110' = 180'
x' = 180' - 110'
Value of x = 70'
What is the m∠1? *
45°
17°
135°
180
the title pattern shown was used in pompeii for paving. if the diagonals of each rhombus are 2 and 3 inches, what area makes up each cube in the pattrn
Each cube in the pattern has an area of 3 square inches.
To determine the area of each cube in the pattern, we need to find the area of each rhombus formed by the pattern.
The pattern consists of rhombuses, and we know that the diagonals of each rhombus are 2 inches and 3 inches.
The formula to find the area of a rhombus is given by:
Area = (d1 * d2) / 2,
where d1 and d2 are the lengths of the diagonals.
In this case, d1 = 2 inches and d2 = 3 inches.
Plugging the values into the formula, we get:
Area = (2 * 3) / 2
= 6 / 2
= 3 square inches.
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How do I write the polynomial -10xy^5+2x^3y^2-6x^2y^2 in standard form??
Will give brainliest if you provide the steps and answer
Answer:
-8xy^5-6xy^4
Step-by-step explanation:
-10xy^5+(2x^3)(y^2)-(6x^2)(y^2)
-10xy^5+2xy^5 -6xy^4
-8xy^5-6xy^4
This should be good but if your teacher requires it just put 0 with the exponent in descending order
Answer:
Answering on an Alt account to give brainliest :p
Step-by-step explanation:
Evaluate the series 1 + 2 + 4 + 8 to S10.
The series to 10 term is
1 + 2 + 4 + 8 + 16 + 32 + 64 + 128 + 256 + 512
What is recurrent relation?An equation that represents a sequence based on a rule is called a recurrence relation.
Finding the following term, which is dependent upon the prior phrase, is made easier (previous term). We can readily predict the following term in a series if we know the preceding term.
The term is predicted by multiplying the preceding term by 2
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How do equations or inequalities help us understand how to interpret whether a solution is possible for a particular real world situation
The volume of a sphere is 36 cubic inches. What is the radius of the sphere?
Answer:
2.05 inches
Step-by-step explanation:
V = 4/3 x πr³
36=4πr³/3
36x3= 4πr³
108= 4πr³
108/4 = πr³
27= πr^3
27/π =r³
r=
\( \sqrt[3]{27 \div \pi} \)
r= 2.048in
round off to 2.05in
PROOF
V = 4÷3 x πr³
V= 4/3 x π(2.05)³
V=4/3 x π8.6
V=4×π×8.6/3
V=108/3
V=36in³
Therefore: radius= 2.05 inches
please help quickly !
Answer:
x = 256
Step-by-step explanation:
-5/8x = -160
Multiply each side by -8/5 to isolate x
-8/5*-5/8x = -160*-8/5
x = 256
What is 9/12a = 1 ? Also what is 6/5b = 1 ? And Finaly what is 12c = 1 ?
Step-by-step explanation:
hope I understand your question
a = 9/12
b = 6/5
c = 1/12
please simplify the fractions by yourself
3. Four race cars are travelling on a 2.5-mile tri-oval track. The four cars are travelling at constant speeds of 195 mph, 190 mph, 180 mph, and 175 mph, respectively. A person is standing at a point on the track for a period of 45 minutes and are recording the instantaneous speed of each vehicle as it passes him (her). What is the time-mean speed and space-mean speed for these vehicles for this time period?
The time-mean speed and space-mean speed of the four race cars can be calculated based on their constant speeds and the time it takes for each car to pass the person standing on the track. The time-mean speed is the average of the individual speeds, while the space-mean speed is the average of the distances covered by each car during the time period.
To calculate the time-mean speed, we need to find the average of the individual speeds of the four race cars. The time period is given as 45 minutes. We convert this time into hours by dividing it by 60: 45 minutes ÷ 60 = 0.75 hours.
Now we calculate the time taken for each car to pass the person based on their speeds and the length of the track. The track length is given as 2.5 miles. We use the formula: time = distance ÷ speed.
For the first car with a speed of 195 mph, the time taken to cover the track is: 2.5 miles ÷ 195 mph = 0.0128 hours.
Similarly, for the other cars:
Car 2: 2.5 miles ÷ 190 mph = 0.0132 hours
Car 3: 2.5 miles ÷ 180 mph = 0.0139 hours
Car 4: 2.5 miles ÷ 175 mph = 0.0143 hours
Next, we calculate the time-mean speed by taking the average of these individual speeds:
Time-mean speed = (195 mph + 190 mph + 180 mph + 175 mph) ÷ 4 = 185 mph.
To find the space-mean speed, we calculate the distances covered by each car during the 45-minute period. Multiply the speed of each car by the time taken for that car to pass the person:
Car 1: 195 mph × 0.0128 hours = 2.496 miles
Car 2: 190 mph × 0.0132 hours = 2.508 miles
Car 3: 180 mph × 0.0139 hours = 2.502 miles
Car 4: 175 mph × 0.0143 hours = 2.502 miles
Now we find the average of these distances:
Space-mean speed = (2.496 miles + 2.508 miles + 2.502 miles + 2.502 miles) ÷ 4 = 2.502 miles.
Therefore, the time-mean speed for the four race cars during the 45-minute period is 185 mph, and the space-mean speed is 2.502 miles.
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The time-mean speed and space-mean speed of the four race cars can be calculated based on their constant speeds and the time it takes for each car to pass the person standing on the track.
The time-mean speed is the average of the individual speeds, while the space-mean speed is the average of the distances covered by each car during the time period. To calculate the time-mean speed, we need to find the average of the individual speeds of the four race cars. The time period is given as 45 minutes. We convert this time into hours by dividing it by 60: 45 minutes ÷ 60 = 0.75 hours.
Now we calculate the time taken for each car to pass the person based on their speeds and the length of the track. The track length is given as 2.5 miles. We use the formula: time = distance ÷ speed. For the first car with a speed of 195 mph, the time taken to cover the track is: 2.5 miles ÷ 195 mph = 0.0128 hours.
Similarly, for the other cars:
Car 2: 2.5 miles ÷ 190 mph = 0.0132 hours
Car 3: 2.5 miles ÷ 180 mph = 0.0139 hours
Car 4: 2.5 miles ÷ 175 mph = 0.0143 hours
Next, we calculate the time-mean speed by taking the average of these individual speeds:
Time-mean speed = (195 mph + 190 mph + 180 mph + 175 mph) ÷ 4 = 185 mph.
To find the space-mean speed, we calculate the distances covered by each car during the 45-minute period. Multiply the speed of each car by the time taken for that car to pass the person:
Car 1: 195 mph × 0.0128 hours = 2.496 miles
Car 2: 190 mph × 0.0132 hours = 2.508 miles
Car 3: 180 mph × 0.0139 hours = 2.502 miles
Car 4: 175 mph × 0.0143 hours = 2.502 miles
Now we find the average of these distances:
Space-mean speed = (2.496 miles + 2.508 miles + 2.502 miles + 2.502 miles) ÷ 4 = 2.502 miles. Therefore, the time-mean speed for the four race cars during the 45-minute period is 185 mph, and the space-mean speed is 2.502 miles.
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hhhhhheeeeeelllllllllpppppp
34.Imagine you're playing a board game that involves an hourglass filled with sand. Once all of the sand falls to the bottom, your turn is up and it's the next player's turn. If the sand falls at a rate of 16 cubic millimeters per second, how much time do you have for your turn
If the sand falls at a rate of 16 cubic millimeters per second, a player would have approximately 6.25 seconds for their turn.
The rate of sand falling from the hourglass is given as 16 cubic millimeters per second. We need to find out the time available for a turn. Let's assume that the hourglass is filled with 'x' cubic millimeters of sand.
We can use the formula:
Volume = Rate x Time
Here, the volume of sand is 'x' cubic millimeters, the rate is 16 cubic millimeters per second, and we need to find the time available for a turn, which we can represent as 't' seconds.
So,
x = 16t
We can rearrange this equation to find 't':
t = x/16
This means that the time available for a turn is equal to the volume of sand in the hourglass divided by the rate at which the sand falls.
We don't know the exact volume of sand in the hourglass, but let's assume it's 100 cubic millimeters.
Then,
t = 100/16
t = 6.25 seconds
So, in this case, a player would have approximately 6.25 seconds for their turn before all of the sand falls to the bottom of the hourglass.
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-0.2 + 7/10 Enter the answer as an exact decimal or simplified fraction.
Answer:
.5 or 1/2
Step-by-step explanation:
Plsss help meeee :))
Answer:
i think 6(k)^2 ?
Step-by-step explanation:
answer both A and B please
Answer:
3 and - 10
Step-by-step explanation:
(a)
when x = 0 in the interval x ≤ 0 then y = \(\frac{3}{2}\) x + 3 , so
y = \(\frac{3}{2}\) (0) + 3 = 0 + 3 = 3
when x = 0, the value of the function is 3
(b)
when x = 5 in the interval x > 0 then y = - 2x , so
y = - 2(5) = - 10
when x = 5 the value of the function is - 10
Answer: a. when x=0, the value of the function is 3
b. when x=5, the value of the function is -10
Step-by-step explanation:
\(\displaystyle\\y=\left \{ {{\frac{3}{2}x+3,\ if\ x\leq 0 } \atop {-2x,\ if\ x > 0}} \right.\)
\(\displaystyle\\x=0\\\\Hence,\\\\y=\frac{3}{2} (0)+3\\\\y=0+3\\\\y=3\)
\(x=5\\\\Hence,\\\\y=-2(5)\\\\y=-10\)
What does the 6 in 2/6 mean?
Hey there!
Here we have a fraction
2/6.
The 2 is the numerator, and 6 is the denominator.
How to remember where the numerator and the denominator is?
Well, please remember the following:
The Denominator is Down
Hence, 6 is the denominator of this fraction.
Hope everything is clear.
Let me know if you have any questions!
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:-)
-4x 3 y 2(7xy 4) i need help
Answer:
−672x2y2
Step-by-step explanation:
The answer is:
-28x^4y^6
CAN SOMEONE PLS HELP MEE
Two triangles are graphed in the xy-coordinate plane.
Which sequence of transformations will carry △QRS
onto △Q′R′S′?
A. a translation left 3 units and down 6 units
B. a translation left 3 units and up 6 units
C. a translation right 3 units and down 6 units
D. a translation right 3 units and up 6 units
Answer:
the answer should be, A. im pretty good at this kind of thing so It should be right but if not, sorry.
Step-by-step explanation:
how many seconds are there in a month of 30 days express it in scientific notation
A lecture hall has 50 seats.
43 seats are occupied and 7 seats are empty.
Use this information to answer the questions below.
Answer:14% of the seats are empty
Step-by-step explanation:
7/50 = ?/100
50×2=100
so 7×2=?
?=14
14/100=14%
*16 (b)
(√3-1) cm
A
75°
B
You are given that sin 75º =
5√2 cm
√3+1
2√2
Show that the area of triangle ABC is 2½ cm²
Nof
acc
C
Answer:
Step-by-step explanation:
78 sin
(+0
how many 4-digit positive integers are there for which there are no repeated digits or for which there may be repeated digits
According to the question, the number of 4-digit positive integers for which there are no repeated digits or for which there may be repeated digits is 14,536.
Case 1: No repeated digits:
For the first digit, we have 9 choices (excluding zero), as it cannot be zero. For the second digit, we have 9 choices (including zero but excluding the digit already chosen for the first digit). Similarly, for the third digit, we have 8 choices, and for the fourth digit, we have 7 choices. Therefore, the total number of 4-digit positive integers with no repeated digits is \(\(9 \times 9 \times 8 \times 7\)\).
Case 2: Repeated digits allowed:
For each digit, we have 10 choices (including zero), as repeated digits are allowed. Therefore, the total number of 4-digit positive integers with or without repeated digits is \(\(10 \times 10 \times 10 \times 10\)\).
Hence, the number of 4-digit positive integers for which there are no repeated digits or for which there may be repeated digits is \(\(9 \times 9 \times 8 \times 7 + 10 \times 10 \times 10 \times 10\)\).
Simplifying the expression, we get the final answer:
\(\[9 \times 9 \times 8 \times 7 + 10 \times 10 \times 10 \times 10 = 4536 + 10000 = 14536\]\)
Therefore, the number of 4-digit positive integers for which there are no repeated digits or for which there may be repeated digits is 14,536.
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√57^2 = x
Please find x.
Answer:
x = 57
Hope it helped :)
Answer:
x=57
Step-by-step explanation:
Solve for x by simplifying both sides of the equation, then isolating the variable.
Please write legibly.
4. There are 12 products randomly tested in a factory floor for quality control (faulty or not). a. Which distribution it may fit into? (5pt) b. What is the mean and standard deviation of this distrib
a. The distribution that may fit the scenario of randomly testing 12 products for quality control is the binomial distribution.
b. The mean (μ) of a binomial distribution is given by μ = n * p, where n is the number of trials and p is the probability of success in each trial. The standard deviation (σ) is given by σ = √(n * p * (1 - p)).
a. The binomial distribution is appropriate when there are a fixed number of independent trials (testing each product) and each trial has two possible outcomes (faulty or not). In this case, the 12 products are being randomly tested for quality control, which aligns with the conditions for a binomial distribution.
b. To determine the mean and standard deviation, we need the probability of success in each trial. Let's assume the probability of a product being faulty is 0.1 (10% chance of being faulty) and the probability of it being non-faulty is 0.9 (90% chance of being non-faulty).
Mean (μ) = n * p = 12 * 0.1 = 1.2
Standard Deviation (σ) = √(n * p * (1 - p)) = √(12 * 0.1 * 0.9) = √(1.08) ≈ 1.04
The scenario of randomly testing 12 products for quality control fits the binomial distribution. The mean of this distribution is 1.2, indicating an expected value of 1.2 faulty products out of the 12 tested. The standard deviation is approximately 1.04, representing the variability in the number of faulty products we might expect to find in repeated tests.
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What is the slope represented in the table ?
Answer:
slope:2
Step-by-step explanation:
Slope is rise/run, or change in y/change in x.
With that being said, we only need two points to solve this.
Let's take the points (0,7) and (1,9)
The formula for finding the slope from two points is m=(y2-y1)/(x2-x1).
M is the slope.
y2 would be the y-value of the second point,9. y1 would be the y-value of the first point, 7.
x2 would be the x-value of the second point, 1. x1 would be the x-value of the first point, 0.
Plugging those values in to the formula, we get m=(9-7)/(1-0)
Simplifying, we get m=2/1, which is m=2.
Ella is going to invest $18,000 and leave it in an account for 8 years. Assuming til
interest is compounded continuously, what interest rate, to the nearest hundredth of
a percent, would be required in order for Ella to end up with $22,000?
Answer:
90
Step-by-step explanation:
Answer:2.51
Step-by-step explanation:
The supplement of an acute angle is an obtuse angle. True or false?
Vertical angles are always supplementary. True or False?
Answer:
yes, it is true because a supplimentary angle is 180 degrees and if their is an acute angle then it is less than 90 degrees which means you subtract that by 180 and you get a number over 90 and an obtuse angle is over 90 which means the other side of the acute angle is obtuse. And the suppliment to an acute angle is always over 90 degrees
Hope it helps!
can I get brainliest?
Express in the form 1 : n . Give n as a decimal. 16 : 12
Answer:
16.12
Step-by-step explanation: hope this helps
Find the value of x.
Answer:
your answer will be x=80°
Step-by-step explanation:
hope it helps you
have a great day!!!
4. Calculate the values for the ASN curves for the single sampling plan \( n=80, c=3 \) and the equally effective double sampling plan \( n_{1}=50, c_{1}=1, r_{1}=4, n_{2}=50, c_{2}=4 \), and \( r_{2}
Single Sampling Plan: AQL = 0, LTPD = 3.41, AOQ = 1.79 Double Sampling Plan: AQL = 0, LTPD = 2.72, AOQ = 1.48
The values for the ASN (Average Sample Number) curves for the given single sampling plan and double sampling plan are:
Single Sampling Plan (n=80, c=3):
ASN curve values: AQL = 0, LTPD = 3.41, AOQ = 1.79
Double Sampling Plan (n1=50, c1=1, r1=4, n2=50, c2=4, r2):
ASN curve values: AQL = 0, LTPD = 2.72, AOQ = 1.48
The ASN curves provide information about the performance of a sampling plan by plotting the average sample number (ASN) against various acceptance quality levels (AQL). The AQL represents the maximum acceptable defect rate, while the LTPD (Lot Tolerance Percent Defective) represents the maximum defect rate that the consumer is willing to tolerate.
For the single sampling plan, the values n=80 (sample size) and c=3 (acceptance number) are used to calculate the ASN curve. The AQL is 0, meaning no defects are allowed, while the LTPD is 3.41. The Average Outgoing Quality (AOQ) is 1.79, representing the average quality level of outgoing lots.
For the equally effective double sampling plan, the values n1=50, c1=1, r1=4, n2=50, c2=4, and r2 are used. The AQL and LTPD values are the same as in the single sampling plan. The AOQ is 1.48, indicating the average quality level of outgoing lots in this double sampling plan.
These ASN curve values provide insights into the expected performance of the sampling plans in terms of lot acceptance and outgoing quality.
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