Find the slope of the line that is parallel to y = -x = 1
A. -1
B. 5/4
C.1
D.-5/4

Answer:

Option D

Step-by-step explanation:

Use shortcut trick:-

Mark the change in y axis

Starting point is same (-2,4)

Ending points

Change:-

Hence decay rate is three fourth

Answer:

Step-by-step explanation:

The diameter of a pearl is

The diameter of an atom is

How much larger than an atom is a pearl?

Correct option is D

Answer:

z = 7

Step-by-step explanation:

We know that, sum of the exterior angles of a quadrilateral is added up to 360°.

Accordingly,

115 + 7z + 12z + 16z = 360

Combine like terms.

115 + 35z = 360

Subtract 115 from both sides.

35z = 360 - 115

35z = 245

Divide both sides by 35.

z = 7

The total number of routes possible is 6227020800, under the given condition that a overnight express company must include thirteen cities on its route, assuming that it does matter in which order the cities are included.

For this given question in order to find the accurate answer we have to perform calculations based on the principles of factorial operation.
The total  number of different routes possible, considering  that it matters in which order the cities are included  is 13!
The factorial of 13 is evaluated
13! = 13 x 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
= 6227020800
The total number of routes possible is 6227020800, under the given condition that a overnight express company must include thirteen cities on its route, assuming that it does matter in which order the cities are included.

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Answer:

Answer below :)

Step-by-step explanation:

Ei = n*pi

= 140*0.5

= 70

Hope this helps. <3

The expected frequency, Ei, for the given values of n = 140 and pi = 0.5 is 70.

The expected frequency represents the number of events that would be expected to occur based on the given probability and sample size.

To find the expected frequency, Ei, given the values of n (total sample size) and pi (probability), we multiply the total sample size by the probability.

In this case, n = 140 and pi = 0.5. To calculate the expected frequency, we multiply these values:

Ei = n * pi = 140 * 0.5 = 70.

Therefore, the expected frequency, Ei, for the given values of n = 140 and pi = 0.5 is 70. The expected frequency represents the number of events that would be expected to occur based on the given probability and sample size.

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The process capability index gauges how much variance a process encounters in comparison to its specification parameters.

We might compare various procedures in terms of the ideal circumstance or whether they live up to our expectations. In the event that the process is not centered, the capability ratio formula is employed.

Process capability uses capability indices to compare an in-control process output to the specification's upper and lower bounds.

Calculated for steady, non-automated processes is the process capability index. The operator is then instructed to check samples at random and center the process.

The processing capability declined.

One would expect to find that the process capability has gotten worse.

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Answer:

No because 3x is variable and 3 is constant

Answer:

No

Step-by-step explanation:

Like terms is when a variable is raised in the same power. In this case 3xx and 3 are not like terms. An example of a like term would be 3x and 6x because they have both x.

Answer:

Percent Error = 37.5%

Step-by-step explanation:

We know that Michael's prediction was 5 laps and the actual amount was 8 laps, therefore we can use the formula to find the percent error.

\(\frac{|Prediction-Actual|}{|Actual|}*100\)

\(\frac{|5-8|}{|8|}*100\)

\(\frac{3}{8}*100\)

\(\frac{300}{8}\)

\(37.5\%\)

So, Michael's percent error was 37.5%

The trigonometric function gives the ratio of different sides of a triangle. The option that is not an example of trigonometric reciprocals of sine, cosine, and tangent is theorem.

The trigonometric function gives the ratio of different sides of a right-angle triangle.

\(\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\Cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\Tan \theta=\dfrac{Perpendicular}{Base}\\\\\\Cosec \theta=\dfrac{Hypotenuse}{Perpendicular}\\\\\\Sec \theta=\dfrac{Hypotenuse}{Base}\\\\\\Cot \theta=\dfrac{Base}{Perpendicular}\\\\\\\)

where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite the 90° angle.

The trigonometric reciprocal of sine, cosine, and tangent are cosecant, secant, and cotangent, respectively. Therefore, the option that is not an example of trigonometric reciprocals of sine, cosine, and tangent is theorem.

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Answer:

is the answer 14

Step-by-step explanation:

If you are using a calculator, simply enter 28÷100×50 which will give you 14 as the answer.

hope it helps

mark me brainliest pls

Answer:

\(x \geqslant - 3\)

Step-by-step explanation:

\(x \geqslant - 3\)

The mean measurement is the average value of the leaves

The possible measurement of the 6th leaf is 13.3

The dataset is given as:

14.2, 13.8, 12.6, 13.4 and 11.5

Sort the data elements

11.5, 12.6, 13.4, 13.8 and 14.2

Calculate the mean

\(\bar x = \frac{11.5 + 12.6 + 13.4 + 13.8 + 14.2}{5}\)

\(\bar x = \frac{65.5}{5}\)

\(\bar x = 13.1\)

So the mean is 13.1 and the median is 13.4

For the mean to increase, the 6th dataset must be greater than 13.1.

For the median to decrease, the 6th dataset must be less than 13.4

From the list of given options, the element that satisfy the above highlights is 13.3

Hence, the possible measurement of the 6th leaf is 13.3

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30-12=p

p= 18

just make p the subject and you will get to ur answer.

Answer:

18

Step-by-step explanation:

subtract 12from both sides

p+12-12=30-12

p=30-12=18

The space of continuous functions on [0, 1] equipped with L²-norm 1/3 || f || = (S²151³) ¹/³ is also complete.

To determine if the space of continuous functions on [0, 1] equipped with L²-norm 1/3 || f || = (S²151³) ¹/³ is complete, we need to check if every Cauchy sequence in this space converges to a function in the same space.

Let {f_n} be a Cauchy sequence in the space of continuous functions on [0, 1] with respect to the given norm. Then, for any ε > 0, there exists an integer N such that for all m,n ≥ N, we have:

1/3 || f_m - f_n || < ε

Since this norm is equivalent to the standard L²-norm on [0, 1], it follows that {f_n} is also a Cauchy sequence in the space of continuous functions on [0, 1] equipped with the standard L²-norm.

Now, since the space of continuous functions on [0, 1] equipped with the standard L²-norm is complete, there exists a continuous function f on [0, 1] such that f_n → f in the L²-norm as n → ∞. Moreover, by the equivalence of norms, we know that f_n → f with respect to the given norm as well.

Therefore, the space of continuous functions on [0, 1] equipped with L²-norm 1/3 || f || = (S²151³) ¹/³ is also complete.

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Answer:

Step-by-step explanation:

To find the equation with a slope of 3 through the point (9, -4), we can substitute the values into the equation and solve for 'b'.

We have the slope, m = 3, and the point (9, -4), which means x = 9 and y = -4.

Using the point-slope form of the equation: y - y1 = m(x - x1), we substitute the values:

y - (-4) = 3(x - 9)

Simplifying:

y + 4 = 3(x - 9)

y + 4 = 3x - 27

Now, rearranging the equation to slope-intercept form:

y = 3x - 27 - 4

y = 3x - 31

Therefore, the equation in slope-intercept form that represents a line with slope 3 through the point (9, -4) is y = 3x - 31.

Answer:

(4, 3)

Step-by-step explanation:

Your vertex is at (h, k). h is 4 and k is 3 in the equation. Alternatively, you could graph this and trace the graph to find the vertex.

the area of the triangle ABC is found by using the formula 1/2 * (base * height). Here, the base is 0 and the height is 1. Thus, the area of the triangle ABC = 0.5.

Let x = 0, y = 1 in 5x2y = 31

31 = 0

Thus, the point B is (0, 0).

The area of the triangle ABC = 1/2 * (0 * 1) + (0 * 1) + (1 * 0) = 0.5.

The equation of line L is given as 5x2y = 31. To find the point B, we need to substitute x = 0 in the equation. Doing so, we get 31 = 0, which means that the point B lies on the y-axis at (0, 0).

Next, since the line M is perpendicular to L and passes through A, we can assume that it is a horizontal line passing through (0, 1). Thus, the point C is the point of intersection of L and M, which is (1, 0).

Finally, the area of the triangle ABC is found by using the formula 1/2 * (base * height). Here, the base is 0 and the height is 1. Thus, the area of the triangle ABC = 0.5.

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The division of the polynomial 2x⁴ - 3x³ - 6x² + 11x + 8 by x - 2 will give a quotient of  2x³ + x² - 4x + 3 +(14 / x - 2)

The quotient of polynomials is the result of dividing one polynomial by another. It is a mathematical expression representing the ratio of two polynomials, often written as a fraction. The numerator of the fraction is the dividend polynomial, and the denominator is the divisor polynomial. The quotient of polynomials can be found using long division or synthetic division methods.

In the polynomial division between 2x⁴ - 3x³ - 6x² + 11x + 8 and x - 2

2x⁴ - 3x³ - 6x² + 11x + 8 ÷ x - 2 = 2x³ + x² - 4x + 3 +(14 / x - 2)

The quotient of the division is 2x³ + x² - 4x + 3 +(14 / x - 2) while the divisor is x - 2.

The remainder of the polynomial division is 14

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Solution. To graph f, we graph the equation y=f(x).

To this end, we use the techniques outlined in Section 1.2.1. Specifically, we check for intercepts, test for symmetry, and plot additional points as needed. To find the x -intercepts, we set y=0. Since y=f(x), this means f(x)=0.

\($$\begin{aligned}f(x) & =x^2-x-6 \\0 & =x^2-x-6 \\0 & =(x-3)(x+2) \quad \text { factor } \\x-3=0 & \text { or } x+2=0 \\x & =-2,3\end{aligned}$$\)

So we get (-2,0) and (3,0) as x-intercepts. To find the y-intercept, we set x=0. Using function notation, this is the same as finding f(0) and f(0)=0^2-0-6=-6. Thus the y-intercept is (0,-6). As far as symmetry is concerned, we can tell from the intercepts that the graph possesses none of the three symmetries discussed thus far. (You should verify this.) We can make a table analogous to the ones we made in Section 1.2.1, plot the points and connect the dots in a somewhat pleasing fashion to get the graph below on the right.

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Answer:

median

Step-by-step explanation:

the median is literally the middle number--half the numbers are higher, half the numbers are lower.

The initial age of 10 years and the spaceship speed of 0.60•c, gives the Andrea's age at the end of the trip as 18 years.

The time dilation using the Lorentz transformation formula is presented as follows;

\(t' = \frac{t}{ \sqrt{1 - \frac{ {v}^{2} }{ {c}^{2} } } } \)

From the question, we have;

The spaceship's speed, v = 0.6•c

∆t = Rest frame, Courtney's time, change = 10 years

Therefore;

\(\delta t' =\delta t \times \sqrt{1 - \frac{ {(0.6 \cdot c)}^{2} }{ {c}^{2} } } = 8\)

The time that elapses as measured by Andrea = 8 years

Andrea's age, A, at the end of the trip is therefore;

A = 10 years + 8 years = 18 years

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Answer:

Step-by-step explanation:

{z - some integer}

2z+1  - the smallest number

7(2z+1)  - seven times the smallest number

2z+1+2=2z+3  - the middle number

2z+3+2 = 2z+5 - the largest number

2(2z+5) - twice the largest number

7(2z+1) + 2(2z+5)  - the sum of 7 times the smallest and twice the largest

7(2z+1) + 2(2z+5)   = -91

14z + 7 + 4z + 10 = -91

              -17              -17

      18z   = -108

       ÷18        ÷18

        z = -6

2z+1 = 2(-6)+1 = -12 + 1 = -11  

2z+3 = 2(-6)+3 = -12 + 3 = -9

2z+5 = 2(-6)+5 = -12 + 5 = -7        

Answer:

³√343 = 7 .....ans .....

your query :

\( \sqrt[3]{343} \)

Answer:

hey there,

here,

=

\( \sqrt[3]{7 \times 7 \times 7 } \)

=

\(7\)

hence, the solution is

7

i hope it helped...........

the given differential equation dR/dx = a(R² + 16), where a is a non-zero constant, is R = -4/√\((16 - e^(2ax + C))\), where C is the constant of integration.

In the first part, the solution to the differential equation is R = -4/√\((16 - e^(2ax + C)).\)

In the second part, let's solve the differential equation step by step. We start by separating variables:

dR/(R² + 16) = a dx.

Next, we integrate both sides:

∫(1/(R² + 16)) dR = ∫a dx.

To integrate the left side, we can use a substitution. Let u = R² + 16, then du = 2R dR. This gives us:

(1/2) ∫(1/u) du = ∫a dx.

Simplifying the left side and integrating, we have:

(1/2) ln|u| = ax + C.

Substituting back for u and rearranging, we get:

ln|R² + 16| = 2ax + 2C.

Taking the exponential of both sides, we have:

|R² + 16| = \(e^(2ax + 2C).\)

Considering the absolute value, we can rewrite it as:

R² + 16 = \(e^(2ax + 2C).\)

Solving for R, we get:

R = ±√(e^(2ax + 2C) - 16).

Simplifying further:

R = ±√(e^(2ax + C) - 16).

Finally, we can rewrite it as:

R = -4/√(16 - e^(2ax + C)).

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Answer:

Step-by-step explanation:

it is given by the formula=4× 90/ n

where n = number of sides

exterior angle= 4 x 90/13

=360/13=\(27.7\)°

Answer:

g = 239 25/48

Step-by-step explanation:

To solve for g, we need to isolate g on one side of the equation. We can start by adding 156 to both sides:

2/3g = 3 13/24 + 156

2/3g = 159 17/24

Next, we can multiply both sides of the equation by 3/2 to cancel out the denominator of 2/3:

g = (159 17/24) * (3/2)

g = 239 25/48

So the solution for g is g = 239 25/48

(Please give brainlist)

The function is not a pdf because c is not defined.It is not bounded either.

a) f(x) = x3 / 4 for 0 < x < c(i) For f(x) to be a pdf, it must satisfy two conditions:It must be non-negative for all xIt must integrate to 1 between the limits of the random variable. That is,It is given that f(x) = x3 / 4 for 0 < x < c

For the above function, we have to find c.c = [4 / (c^4/4)](c^4/4) = 4

Now, the pdf is given by f(x) = x^3 / 4c = 4

(ii) The cdf is given by F(x) = P(X ≤ x)

The limits are from 0 to x. Hence we have

\(F(x) = ∫ f(x) dx = ∫ x^3 / 4c dx = [x^4 / (16c)] from 0 to x\)

Therefore,F(x) = x^4 / (16c)

(iii) The graph of the pdf and cdf can be sketched as below.(iv) Mean of the given pdf is given byμ =

∫x.f(x) dx = ∫0c x.x^3 / 4c dx = ∫0c x^4 / 4c dx= [x^5 / 20c] from 0 to c= c^4 / 80

Therefore,μ = c^4 / 80

Variance of the given pdf is given by

\(σ^2 = ∫(x - μ)^2 . f(x) dx = ∫0c (x - c^4 / 80)^2 . x^3 / 4c dx\)

On evaluating,

\(σ^2 = c^8 / 1280 - (c^4 / 16) + (3c^4 / 80) = c^8 / 1280 + (c^4 / 60)\)

b) f(x) = (3/16)x2 for -c < x < c

(i) For f(x) to be a pdf, it must satisfy two conditions:It must be non-negative for all xIt must integrate to 1 between the limits of the random variable. That is,It is given that f(x) = (3/16)x2 for -c < x < c

For the above function, we have to find c.∫(3/16)x2 dx = 1

Integrating within the limits, we get3/16 [x3 / 3] from -c to c = 1

On solving we getc3 = 16 / 3c = (16 / 3)1/3

Now, the pdf is given by f(x) = (3/16)x2 / c

(ii) The cdf is given by F(x) = P(X ≤ x)

The limits are from -c to x.

Hence we haveF(x) = ∫ f(x) dx = ∫ (3/16)x2 / c dx = [(x3 / 16c)] from -c to x

Therefore,F(x) = (x3 + c3) / 16c

(iii) The graph of the pdf and cdf can be sketched as below.

(iv) Mean of the given pdf is given byμ = ∫x.f(x) dx = ∫(-c)c x.(3/16)x2 / c dx = ∫(-c)c (3/16)x3 / c dx= 0

Therefore,μ = 0

Variance of the given pdf is given byσ^2 = ∫(x - μ)^2 . f(x) dx = ∫(-c)c (x - 0)^2 . (3/16)x2 / c dx

On evaluating,σ^2 = 3c4 / 80

Therefore,σ^2 = c4 / 26c) f(x) = c/student submitted image, transcription available belowfor 0 < x < 1.

Is this pdf bounded?(i) For f(x) to be a pdf, it must satisfy two conditions:It must be non-negative for all xIt must integrate to 1 between the limits of the random variable. That is,It is given that f(x) = c/student submitted image, transcription available belowfor 0 < x < 1Now, we have to find the value of c so that f(x) is a pdf.∫c/student submitted image, transcription available belowdx = 1Integrating within the limits, we getc [ln |x|] from 0 to 1 = 1On solving we getc = 1 / ln (1) = undefined

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