Find the specific heat of a substance that requires 8000 J of energy to heat up 400g by 20 C?

The length of the incline is 65 meter.

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Initial speed is = 2 m/s

Final speed is = 15 m/s

Acceleration  of the skier is = gsin10° = 9.8 × sin10° m/s² = 1.7 m/s

Let the  length of the incline is l

Hence,

15² = 2² + 2×1.7×s

s = 65

Hence, the length of the incline is 65 meter.

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Annular and penumbra are terms that are associated with Solar and lunar eclipses. Option C is the correct answer

An eclipse is a result of a shadow cast by one heavenly body on another. There are eclipse of the sun or solar eclipse and eclipse of the moon or lunar eclipse.

Annular and penumbra actually refer, respectively, to the phenomenon known as solar and lunar eclipses.

Penumbra is a region of outer light or grey area of a shadow cast by an object or heavenly body.

While Annular can be formed under condition where the extreme rays at the moon's edge intersect before reaching the earth.

Therefore, Annular and penumbra refer to the solar and lunar eclipses respectively.

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Answer: EASY BROOOOOOOOOOOOOOOOOOOOOOOOO

Take a look inside your heart

Is there any room for me?

I would have to hold my breath

'Til you get down on one knee

Because you only want to hold me

When I'm looking good enough

Did you ever fault me?

Would you ever picture us?

Every time I pull my hair out

Was only out of fear

That'd you find me ugly

And one day you'll disappear

Because what's the point of crying?

It was never even love

Did you ever want me?

Was I ever good enough?

The molecules of O2 that are  present in 3.90 L flask at  a temperature of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules  of O2

Step  1:  used the ideal gas equation to calculate the moles of O2

that is Pv=n RT  where;

P(pressure)= 1.00 atm

V(volume) =3.90 L

n(number of moles)=?

R(gas constant) = 0.0821 L.atm/mol.K

T(temperature) = 273 k

by  making n the subject of the formula by  dividing  both side by RT

n= Pv/RT

n=[( 1.00 atm x 3.90 L)  /(0.0821 L.atm/mol.k  x273)]=0.174  moles

Step 2: use the Avogadro's  law constant  to calculate  the number of molecules

that  is  according to Avogadro's law

                          1  mole =  6.02 x10^23  molecules

                            0.174 moles=? molecules

by  cross  multiplication

the number of  molecules

= (0.174  moles x  6.02 x10^23  molecules)/ 1 mole  =1.047 x 10^23 molecules of O2

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The displacement at which the kinetic energy and potential energy of a particle executing SHM will be equal when the amplitude is 3cm is 1.5cm.

The amplitude of simple harmonic motion affects the ratio of kinetic to potential energy at a specific displacement in the following way: as the amplitude increases, the ratio of kinetic to potential energy decreases. This is because the amplitude represents the maximum displacement from the equilibrium position, and as the amplitude increases, the potential energy of the particle increases, while the kinetic energy remains constant. Therefore, at a specific displacement, a particle with a larger amplitude will have a greater proportion of its energy in the form of potential energy, while a particle with a smaller amplitude will have a greater proportion of its energy in the form of kinetic energy.

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Answer:

B. 0.45

Explanation:

You just need to plug this into a calculator.

elections are shared, molecules are produced, the correct answer is option

C.  A covalent compound

What is covalent compound?

Covalent compounds are composed of atoms that are linked via covalent bonds i.e. bonds formed by mutual sharing of electrons. This is in complete contrast to ionic compounds which are held together by ionic bonds, i.e. bonds formed by complete transfer of electrons from one atom to the other.

In the given examples we have:

Barium nitrate: Ba(NO3)2 - Ionic

Dinitrogen tetroxide: N2O4- Covalent

Strong intramolecular linkages characterise covalent substances. This is due to the atoms within covalent molecules being very securely bound together. Each molecule is certainly distinct, and the attraction between individual molecules in a covalent complex is typically modest.

To split the molecules, we simply require a minimal amount of energy. This is owing to the molecules' attraction forces as well as a lack of total electric charge. Covalent compounds are typically gaseous molecules at ambient temperature and pressure. They could be liquids with extremely low boiling points.

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Answer:

Seafloor spreading occurs at divergent plate boundaries. As tectonic plates slowly move away from each other, heat from the mantle's convection currents makes the crust more plastic and less dense. The less-dense material rises, often forming a mountain or elevated area of the seafloor. Eventually, the crust cracks.

Explanation:

eventually the crust cracks.

Answer:

highest point

Explanation:

Potential energy is greatest when the most energy is stored. This could be when an object reaches its highest point in the air before falling, a rollercoaster just before it drops, or when a rubber band is stretched as far back as possible before it snaps.

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;

Take moment about the joint to determine the magnitude of the force along part BC.

120 kN x 750 mm  =  F x 1000 mm

F = ( 120 kN x 750 mm ) / ( 1000 mm )

F = 90 kN

Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.

Stress in AB = 2 times stress in BC

P/A₁  = 2F/A₂

where;

A₁ =  πd²/4  =  π(50 x 10⁻³)²/4

A₁ = 1.96 x 10⁻⁵ m²

A₂ = πd²/4  =  π(75 x 10⁻³)²/4

A₂ = 4.42 x 10⁻³ m²

P/A₁ = 2F/A₂

P = (2F x A₁) / (A₂)

P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = 798.2 N

P = 0.798 kN

P ≈ 0.8 kN

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The magnitude of object's acceleration is 3.26m/s².

The mass of the body is 4.10 lg.

The two forces that are acting on the object are F₁ = -6i + 7.9j newton and F₂ = 6.8i + 5.3j Newton.

We know that the force acting on an object is,

F = Ma

Where,

F is the force acting,

M is the mass of the object and,

a is the acceleration of the object.

As we can see, two forces are acting on the body,

We can simplify the forces in x direction and y direction,

The forces are  F₁ = -6i + 7.9j N and F₂ = 6.8i + 5.3j N.

So, the total force in x-direction,

Fₓ = (-6+6.8)i

Fₓ = 0.8i

Fᵧ = (7.9+5.3)j

Fᵧ = 13.2j

So, the net force Fₙ on the object is Fₙ = (0.8i + 13.2j) N

Now, putting value of force and mass in the formula,

F = Ma

0.8i + 13.2j = 4.1a

a = 0.19i + 3.21j m/s².

The magnitude of acceleration is,

|a| = √[(0.19)²+(3.21)²]

|a| = 0.361 +10.3

|a| = 3.26m/s².

So, the magnitude of acceleration is 3.26m/s².

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Answer:

\(\mathbf{\alpha = 25.88 \ rad/s^2 }\)

Explanation:

Consider the force due to friction:

\(F = \mu_kN -------- (1)\)

where;

N = normal reaction

\(\mu_k\) = coefficient of kinetic friction.

Via the horizontal direction, the forces of equilibrium are:

\(\sum F_x = \sum(F_x) _{eff} \\ \\ N- F_{AB} \ cos \theta = 0 \\ \\ F_{AB} \ cos \theta = N ------ (2)\)

where;

\(\theta\) = angle of AB is associated with the horizontal;

\(F_{AB}\) = force exerted by AB

Let's take a look at the equilibrium of forces along the vertical direction.

\(\sum F_y = \sum (F_y)_{eff} \\ \\ F+F_{AB} sin \theta - W = 0\\ \\ \mu_k N + F_{AB} sin \theta -mg =0 \\ \\ F_{AB} sin \theta = mg - \mu_kN-------(3)\)

By dividing (3) by (2), we get:

\(\dfrac{F_{AB} sin \theta }{F_{AB} cos \theta} = \dfrac{mg - \mu_k N}{N} \\ \\ tan \theta = \dfrac{mg-\mu_kN}{N} \\ \\ Ntan \theta = mg - \mu_kN \\ \\ N(tan \theta + \mu_k ) = mg \\ \\ N = \dfrac{mg}{tan \theta + \mu_k}\)

By replacing the obtained value of N into:

\(F = \mu_k N\)

we have:

\(F = \mu_k (\dfrac{mg}{tan \theta + \mu_k}) \\ \\ \\ F = \dfrac{mg \mu_k}{tan \theta + \mu_k}\)

Moment about center A can be expressed as:

\(\sum M_A = \sum (M_A) _{eff} \\ \\ Fr = I \alpha\\ \\ \alpha = \dfrac{Fr}{I}\)

where;

\(\alpha\) = angular acceleration of the disc

I = mass moment of inertia

r = radius of disc

By replacing F and I; ∝ becomes:

\(\alpha = \dfrac{\bigg( \dfrac{mg \mu_k}{tan \theta + \mu_k} \bigg) r}{\dfrac{1}{2}mr^2}\)

\(\alpha = \dfrac{2g}{r} \dfrac{\mu_k}{tan \ \theta + \mu_k}------- (4)\)

where;

g = 9.8 m/s²

r = 0.18 m

\(\mu_k = 0.54\)

θ = 60°

\(\alpha = \dfrac{2(9.8)}{0.18} (\dfrac{0.54}{tan \ 60+ 0.54})\)

\(\mathbf{\alpha = 25.88 \ rad/s^2 }\)

Answer:

We can use the formula:

q = mcΔT

where q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

The heat transferred from the gold bar to the water is equal to the heat transferred from the water to the gold bar, since they reach thermal equilibrium. Therefore:

q_gold = q_water

We can solve for the temperature change of the gold bar:

q_gold = mcΔT_gold

q_water = mcΔT_water

Since the heat transferred is equal:

mcΔT_gold = mcΔT_water

Rearranging and solving for ΔT_gold:

ΔT_gold = ΔT_water(m_water/m_gold)

ΔT_water is the temperature change of the water, which is 17°C. m_water is 0.220 kg, and m_gold is 3 kg. c_gold is given as 129 J/kg K.

ΔT_gold = 17°C(0.220 kg/3 kg)(1/129 J/kg K) = 0.025°C

Therefore, the temperature change of the gold bar is 0.025°C when it is placed into 0.220 kg of water and thermal equilibrium is reached.

The concept of time in space can be different from time on Earth due to the effects of time dilation. Time dilation occurs due to differences in gravitational fields and relative motion.

If we consider an astronaut who is in a relatively low-gravity environment and not traveling at a significant fraction of the speed of light, the time experienced by the astronaut in space would be very similar to the time experienced on Earth. In this scenario, one hour in space would be approximately the same as one hour on Earth.

However, if we consider extreme cases, such as an astronaut near a black hole or traveling at near-light speeds, time dilation effects would become significant. In these situations, the time experienced by the astronaut would be different from the time on Earth.

It's important to note that the magnitude of time dilation effects depend on the specific conditions and relative velocities involved. For most common space travel scenarios, the difference in time between space and Earth is negligible, and one hour in space would correspond to one hour on Earth.

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Answer:

D

Explanation:

In a series circuit there is only one path for the current to complete the path....so D

Answer:

75kg

Explanation:

\(F=mg\)

\(m=\frac{F}{g}\)

\(m=\frac{735}{9.8}\)

\(m=75kg\)

Therefore, the answer is the third option 75 kg

Answer:

i think its D

Explanation:

Answer:

The highness or lowness of a sound is perceived as pitch. Pitch is a perceptual property of sound that allows us to distinguish between sounds that have the same loudness and duration, but differ in their frequency content. The pitch of a sound is determined by the frequency of the sound wave, with higher frequencies producing higher pitches and lower frequencies producing lower pitches. The pitch is what makes a sound distinguishable and is important in music, language, and communication.

Answer:

It is important to conduct research using both male and female participants because gender identity can influence a participant's perspective on a topic. Including both male and female participants can inform researchers if gender plays a role in the issue they are researching

Explanation:

Although gender is technically a social construct, it does play a significant role in how we experience and interact with society. Consider how every person's background influences the way they think and act. For instance, people who identify as female tend to have more experiences feeling unsafe on the street

Answer:

I believe that number 1 is correct I am not sure about the others

Sorry for not being more helpful

Explanation:

Answer:

All your answers are correct

Explanation:

I took the test and got a 100

(1) The speed of the projectile at each point from greatest to least is A, B = D, C.

option B is the correct answer.

(2) The acceleration of the projectile at each point from greatest to least is A = B = C = D

option D is the correct answer.

During a projectile motion, the vertical velocity of a projectile decreases as the projectile moves upwards and eventually become zero as the object reaches the maximum height.

As the object begins move downwards, the vertical velocity of the projectile increases and eventually becomes maximum before the object hits the ground.

During the horizontal motion of a projectile, the horizontal velocity of the projectile does not change. That is the initial horizontal velocity of the projectile equals the final horizontal velocity of the projectile.

a = v - u/t

where;

Since, final horizontal velocity = initial horizontal velocity, then horizontal acceleration = 0 m/s²

In summary, the greatest velocity of a projectile is at the point of projection (A) and the least velocity is at maximum height (C). The magnitude of upward and downward acceleration is constant.

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If the mass of the object is high then there will be less acceleration and vice verse. mass is offers inertia and resistance to motion of the object. high mass leads to high force to produce acceleration.

Force is responsible for the motion of an object. it produces acceleration in the body. According to newton's second law force is mass times acceleration i.e. F =ma. Its SI unit is N which is equivalent to kg.m/s². There are two types of forces, balanced force and unbalanced force. Balanced forces are those forces which are opposite in direction and equal in magnitude. When Net force acting on a body is zero then we call it as balanced force. Balanced force is not responsible for the motion of the body. ex. when two persons pulling rope on both end with equal magnitude which cause them to be balanced force have 0 net force.

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The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.

Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.

The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:

P = ρgh + Po

where:

P is the absolute pressure at the given depth

ρ is the density of the water

g is the acceleration due to gravity (assumed to be 9.81 m/s²)

h is the depth of the ocean

Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)

Substituting the given values, we get:

P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa

P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa

P = 1.002 x 10^8 Pa.

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Two lenses, one converging with a focal length of 10.0 cm and one diverging with a focal length of -5.0 cm, are placed 13.0 cm apart, the position of the final image formed is mathematically given as

u=70.645

Generally, the equation for the convex lens is mathematically given as

I/f=1/u-1/v

Therefore

1/20=1/u-(1/-61)

u=29.76cm

In conclusion, For concave lens

1/-10=1/u-1/8.76

u=87.6/1.2

u=70.645

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Roll a skateboard on sand, then roll it on gravel. - this experiment could answer this question. Hence, option (B) is correct.

An experiment is a technique used to confirm or deny a hypothesis, as well as assess the likelihood or effectiveness of something that has never been tried before. Experiments show what happens when a specific factor is modified, which sheds light on cause-and-effect relationships.

The purpose and scope of experiments vary widely, but they all rely on a repeatable process and a logical examination of the outcomes. Natural experimental experiments are also a thing.

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The type of energy that creates the electrical energy is Option D) The electrical energy comes from the attraction between charges in the cloud and the ground creating an electric potential.

Lightning is a natural electrical discharge of very high voltage that occurs in the atmosphere. It is a result of the buildup of charges in the atmosphere. The atmosphere contains different types of gases, including water vapor. As warm and cold air masses mix, they create turbulence and water vapor rises, forming clouds. These clouds contain millions of water droplets, ice crystals, and other particles. Within these clouds, there are electrical charges that build up.

The electrical energy in lightning comes from the attraction between the positive and negative charges in the cloud and the ground. When there is a large enough charge separation between the positive and negative charges in the cloud, an electric potential is created. This electric potential can build up to a point where it overcomes the insulating properties of the atmosphere and a lightning bolt is discharged. The lightning bolt is essentially a giant spark of electricity that bridges the gap between the cloud and the ground, creating a flow of electrical energy.

In summary, the electrical energy in lightning is created by the attraction between the positive and negative charges in the cloud and the ground, creating an electric potential that can discharge as a lightning bolt. Therefore, Option D is Correct.

The question was Incomplete, Find the full content below :

Lightning is a very large flow of electrical energy. Describe the type of energy that creates the electrical energy.

A) The electrical energy comes from the thermal energy stored up in the water molecules.

B) The electrical energy comes from the gravitational potential energy of the water molecules.

C) The electrical energy comes from the chemical potential energy of the water molecules in the clouds.

D) The electrical energy comes from the attraction between charges in the cloud and the ground creating an electric potential.

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After the impact, the two players are moving side by side at a speed of roughly 4.12 m/s.

Momentum is never created or destroyed inside a problem domain, according to the principle of momentum conservation. Momentum is only changed by the action of forces as they are described by Newton's equations of motion.

\(p1 = m1 * v1 + m2 * v2\)

\(p1 = 165 kg * 0 m/s + 178 kg * 8 m/s = 1424 kg*m/s\)

\(p2 = (m1 + m2) * v\)

Substituting the values, we get:

\(p2 = (165 kg + 178 kg) * v = 343 kg * v\)

Since the total momentum is conserved, we can equate p1 and p2:

p1 = p2

\(165 kg * 0 m/s + 178 kg * 8 m/s = 343 kg * v\)

\(v = (165 kg * 0 m/s + 178 kg * 8 m/s) / 343 kg ≈ 4.12 m/s\)

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Answer:

he lower part of the curve     N = M (g + v² / r)

upper part of the curve          N = m (v² /r -g)

Explanation:

In a roller coaster there is a long climb that allows the car to acquire gravitational potential energy, when this energy is converted into kinetic energy, there is a raven, in these curves we have two parts the lower part, where you have a feeling of great weight and another in the upper part where you have a feeling of weightlessness.

These sensations can be explained using Newton's second law, let's apply it to the lower part of the curve

         N-W = m a

acceleration is centripetal

        a = v² / r

we substitute

        N = mg + m v² / r

        N = M (g + v² / r)

In this part the apparent weight is increased by the speed of the body squared, it feels like a lot of fart.

In the upper part of the curve the force of gravity continues to act downwards, the normal that is the reaction of the surface also goes downwards, the centripetal acceleration pointing towards the center of the curve has a vertical downward direction

        -N -W = -m a

         N = ma -W

         N = m (v² / r -g)

In this case we see that the normal that gives the sensation decreases, which is why we feel a loss of weight, in the case of v2 / r = g, the request is total and the sensation of weightlessness.

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