find the steady-state current i in the circuit shown in the figure when vs(t)=50cos(200t) v . the steady-state current i in the circuit is cos(200t ( °)) a.

Answer: 00.99m

Explanation:

because

Answer: 0.099

Explanation: Khan

Planet Gu, located approximately 2 AU from its host star, completes one orbit in approximately 4.43 Earth years.

The time taken by a planet to complete one orbit, known as its orbital period, can be determined using Kepler's third law of planetary motion. This law states that the square of a planet's orbital period is proportional to the cube of its average distance from the host star. In this case, Planet Gu is located approximately 2 AU from its host star.

To calculate the orbital period, we can use the equation:

\(T^2 = (4\pi ^2/GM) * r^3\)

where T represents the orbital period, G is the gravitational constant, M is the mass of the host star, and r is the average distance between the planet and the star.

Since the planet is moving along its orbit at a constant speed, we can assume that it has a roughly circular orbit. Therefore, the average distance between the planet and the star is equal to its distance of 2 AU.

Plugging in the values and solving for T, we find:

\(T^2 = (4\pi ^2/GM) * (2 AU)^3\)

Using the appropriate values for G, M, and converting AU to kilometers, we can calculate the orbital period T. The result is approximately 4.43 Earth years.

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According to the big bang theory, we live in a universe that is made of almost entirely of matter rather than antimatter because of a slight excess of matter over antimatter that occurred during the early universe.

This excess is thought to be due to a process called baryogenesis, which involves the production of baryons (such as protons and neutrons) from an initial state of pure energy during the first fractions of a second after the big bang.

The exact mechanism by which baryogenesis occurred is not well understood, but several possible theories have been proposed, including the idea that it is related to the violation of CP symmetry (which refers to the combination of charge conjugation and parity) in the early universe.

In any case, the slight excess of matter over antimatter meant that when matter and antimatter particles collided and annihilated each other during the early universe, there were more matter particles left over, which eventually led to the formation of the structures we see in the universe today.

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Answer:

This is basically Simple Harmonic Motion - where the wave disturbance is in the same direction as the wave direction.

That describes (B).

note that y = A cos ω t          where the disturbance is y and ω the the angular frequency and is in the same direction as the disturbance y

This seems the make (D) a satisfactory answer

The projection of the disturbance y is perpendicular (sinusoidal) to the time axis, but the disturbance is still in the same direction as the wave motion

The wave generated by a spring is a transverse wave where, the particles oscillate in a direction perpendicular to the the wave motion.

Mechanical waves are energy transfer through a medium. Unlike electromagnetic waves, mechanical waves cannot transfer through vacuum.

There are two types of mechanical waves namely, transverse waves and longitudinal waves. Transverse waves are those in which the oscillation of particles or disturbance is created perpendicular to the wave motion.

In longitudinal waves, the particle motion or disturbance is created along the wave motion. The wave generated in a spring is transverse wave thus, the disturbance created by moving it up and down will be perpendicular to the wave motion.

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Test variable in this experiment would be the type of object being tested for attraction to negatively charged balloon ; Outcome variable would be whether or not the object is attracted to negatively charged balloon ; Control variable in this experiment would be negatively charged balloon.

Test Variable: The test variable in this experiment would be the type of object being tested for attraction to negatively charged balloon. Marianne would likely test a variety of objects with different materials and shapes to see which ones are attracted to balloon.

Outcome Variable: The outcome variable would be whether or not object is attracted to negatively charged balloon. Marianne would observe each object and note whether it is attracted to balloon or not.

Control Variable: The control variable in this experiment would be negatively charged balloon. Marianne would use same balloon for each test to ensure that any differences in attraction are due to test variable (type of object) and not the balloon itself.

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Answer:

Renewable energy sources can come again, but nonrenewable is gone forever. For example, coal and gasoline are both nonrenewable.

Explanation:

The electric potential at the point (3.0 cm, 1.0 cm) is 6.35 × \(10^6\) V and the work done by the electric force when a 0.20-C charge is moved from the point (3.0 cm, 1.0 cm) to the point (4.0 cm, 6.0 cm) is -6.37 × \(10^5\) J.

The electric potential at the point (3.0 cm, 1.0 cm) is given by

V = kq / r,

where k is Coulomb's constant (9 × \(10^9\) N·\(m^2\) / \(C_2\)),

q is the charge, and

r is the distance between the point and the charge.

Let's assume that there is a charge of +2 μC at the origin (0, 0), then the electric potential at the point (3.0 cm, 1.0 cm) can be calculated as follows:

r = √[\((3.0 cm - 0 cm)^2 + (1.0 cm - 0 cm)^2\)] = √(9 + 1) = √10 cm\(C_2\)

V = (9 × \(10^9\) N·\(m^2\)/) × (2 μC) / (√10 cm) = 6.35 × 106 V

To find the work done by the electric force when a 0.20 - C charge is moved from the point (3.0 cm, 1.0 cm) to the point (4.0 cm, 6.0 cm),

we can use the formula

W = qΔV,

where

ΔV is the change in electric potential.

ΔV = \(V_f\) - \(V_i\),

where \(V_f\) is the final electric potential and

\(V_i\) is the initial electric potential.

\(V_i\)= (9 × \(10^9\) N·\(m^2\)/\(C_2\)) × (2 μC) / (√10 cm) = 6.35 × \(10^6\) V (from the previous calculation)

\(V_f\) = (9 × \(10^9\) N·\(m^2\)/\(C_2\)) × (2 μC) / (√61 cm) = 3.16 × \(10^6\) V (using the same formula as before)

r = √[\((4.0 cm - 3.0 cm)^2 + (6.0 cm - 1.0 cm)^2\)] = √(1 + 25) = √26 cm

W = (0.20 C) × (3.16 × \(10^6\) V - 6.35 × \(10^6\) V)

W = -6.37 × \(10^5\) J (negative sign indicates that work is done against the electric force)

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Answer:

Total resistance = 96 Ohms

Explanation:

Given the following data;

Resistance = 12 Ohms

Number of resistors = 8

To find the total resistance;

Method I.

Since the resistors are connected in series, we would simply multiply the resistance by the number of resistors.

Total resistance = 12 * 8

Total resistance = 96 Ohms.

Method II.

We would add the resistance of all the eight resistors together.

Total resistance = 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12

Total resistance = 96 Ohms.

The total resistance of the circuit will be "96 Ω".

Resistance: The amount of resistance to current flow throughout an electrical circuit.

Current: The movement of electrical charge carriers such as electrons has been referred to as current. The flow of current seems to be from negative (-) to positively (+) locations.

According to the question,

Resistance = 12 Ω

No. of resistor = 8

The total resistance be:

= \(Resistance\times Number \ of \ resistors\)

By substituting the values,

= \(12\times 8\)

= \(96 \ \Omega\)

Thus the above answer is right.

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To evaluate the line integral ∫c xy^4 ds, where c is the right half of the circle x^2 + y^2 = 16 oriented counterclockwise, we can use parametric equations to represent the curve and calculate the integral.

The given curve is the right half of a circle with radius 4 centered at the origin. To evaluate the line integral, we can parameterize the curve using the equation x = 4cos(t) and y = 4sin(t), where t ranges from 0 to π.

The line integral can be expressed as ∫c xy^4 ds = ∫c (4cos(t))(4sin(t))^4 ds. To calculate ds, we use the arc length formula ds = sqrt(dx/dt^2 + dy/dt^2) dt. Substituting the parametric equations,

We have curve equations ds = sqrt((-4sin(t))^2 + (4cos(t))^2) dt. Simplifying, ds = sqrt(16sin^2(t) + 16cos^2(t)) dt = 4 dt.

Substituting ds = 4 dt into the line integral, we have ∫c xy^4 ds = ∫c (4cos(t))(4sin(t))^4 (4 dt). Now, we can simplify the integral and evaluate it over the given parameter range, from 0 to π.

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Answer:

I believe the answer would be kinetic energy to thermal energy.

Explanation:

Thermal energy is the heat of the brakes, and the kinetic energy would be when the car is in motion before stopping.

Given:

The uses of LASER light

To find:

Which is not an application of LASER light

Explanation:

When cutting stainless steel or aluminium, LASER beams are used.

To remove warts, moles, sunspots, and tattoos in human bodies LASER lights are used.

LASER is used in communication also. Laser communication in space is the use of free-space optical communication in outer space.

One of the most important uses for lasers in astronomy is to reduce distortion on images taken with ground-based telescopes. So directly we cannot say that LASER is used for the calibration of telescopes.

Hence, calibration of telescopes is not an application of LASER light.

Explanation:

According to Bohr's model, the electron in a hydrogen atom is in a circular orbit around the nucleus, and its angular momentum is quantized in integer multiples of Planck's constant h. The radius of the ground-state orbit is given by:

r1 = a0 = (4πε0ħ^2)/(me^2)

where ε0 is the permittivity of vacuum, me is the mass of the electron, and e is the elementary charge.

(a) The orbital speed of the electron can be computed as:

v1 = ħ/(m*r1)

where m is the mass of the electron. Substituting the values, we get:

v1 = (ħe^2)/(4πε0ħ^2m) = (e^2)/(4πε0ħ*m)

Plugging in the numerical values for the constants and mass, we get:

v1 = (9.0 x 10^9 m/s)

Therefore, the orbital speed of the electron in the ground state of hydrogen is approximately 9.0 x 10^9 m/s.

(b) The kinetic energy of the electron can be computed as:

KE1 = (1/2)mv1^2

Substituting the values, we get:

KE1 = (1/2)me*(e^2)/(4πε0ħ*m)^2

Plugging in the numerical values for the constants and mass, we get:

KE1 = (2.2 x 10^-18 J) = (13.6 eV)

Therefore, the kinetic energy of the electron in the ground state of hydrogen is approximately 13.6 electronvolts (eV).

(c) The electrical potential energy of the atom can be computed as:

PE1 = - (1/4πε0)*(e^2)/r1

Substituting the value of r1, we get:

PE1 = - (me^4)/(8ε0^2ħ^2)

Plugging in the numerical values for the constants and mass, we get:

PE1 = - (2.2 x 10^-18 J) = - (13.6 eV)

Therefore, the electrical potential energy of the ground state of hydrogen is approximately -13.6 eV. Note that the negative sign indicates that the electron is bound to the nucleus and that energy is required to remove it from the atom.

Answer:

electric current is derived unit.

Explanation:

According to the definition of electric current, it appears to be a derived quantity. Charge on the other hand seems more fundamental than electric current.

the frequency bandwidth in hz = 70,00,00,000 hz

1GHz = 1000MHz

Bandwidth = 1000mhz - 300mhz

Bandwidth = 700mhz

The frequency in hertz can be converted to hertz by multiplying by 1,000,000.

= 700 × 1000000

= 70,00,00,000 hz

Bandwidth of a channel is referred to as the range of frequencies available for transmission of data through that channel. It is the difference of maximum and minimum frequency contained in the composite signals.

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SWOT Analysis Strengths- Paley’s Products has a low overhead cost with the company operating at a high level of efficiency, resulting in competitive pricing.- They have a team of experienced employees who have worked in the industry for several years.- They have a variety of products in the portfolio that can satisfy customers from different sectors.- They are reputable and have a loyal customer base.Weaknesses- They have been slow to adopt new technology, and this may be a disadvantage to the company.- Limited marketing and sales promotion are affecting their sales revenue.-

They depend on a few key customers for the bulk of their sales revenue, leaving them vulnerable to market changes.Opportunities- Expansion of the product line to include unique products.- The establishment of strategic partnerships with other businesses in the industry.- Exploration of new markets, such as international markets.- Improvement of marketing techniques to increase brand awareness.Threats- Changes in consumer preferences towards environmentally friendly products.- Increase in competition from other businesses in the industry.- Fluctuating market prices for raw materials that may lead to price increases.

Strategic Actions to be taken by Paley Products1. Development of an E-commerce platform to allow online transactions with customers. The E-commerce platform will enable Paley to reach a wider customer base, expand its reach, and increase sales revenue.2. Investment in the research and development of new environmentally friendly products. Paley will remain competitive and cater to the needs of consumers who prefer green products.3. Establishment of strategic partnerships with other businesses in the industry to leverage the strength of other companies in the industry and to develop new products or increase market share.4. Improvement of marketing techniques to increase brand awareness and improve visibility. A marketing strategy that incorporates social media and other digital channels can help promote the brand to potential customers.5. Expansion into international markets. This will enable Paley to diversify its customer base and generate more revenue. Paley can start by targeting nearby countries, then expand globally as they gain more experience and financial stability.

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The value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.

When an object collides with another object, they exchange energy. For example, a baseball and bat collision or a car collision. When two objects collide, the force of the collision has to be equal on both sides of the collision according to Newton's Third Law. So, to find the value of force, we will apply the equation:

F = ΔP / ΔT

where F is the force, ΔP is the change in momentum, and ΔT is the time of collision. The equation represents the impulse momentum theorem.

Now, let's apply the given values to the above equation.

Final momentum (p2) = mass × final velocity (v2)

p2 = 0.15 kg × (-50 m/s)

p2 = -7.5 kg.m/s

Initial momentum (p1) = mass × initial velocity (v1)

p1 = 0.15 kg × (40 m/s)

p1 = 6 kg.m/s

Change in momentum (ΔP) = p2 - p1

ΔP = -7.5 kg.m/s - 6 kg.m/s

ΔP = -13.5 kg.m/s

Time of collision (ΔT) = 8.0 × 10³ s

Now, putting the values of ΔP and ΔT in the equation of impulse momentum theorem, we get:

F = ΔP / ΔT

F = -13.5 kg.m/s ÷ 8.0 × 10³ s

F = -1.7 × 10⁻³ N

Thus, the value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.

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The heating of air inside the balloon causes the volume to expand (Charles's Law), resulting in a decrease in the pressure compared to the surrounding air (Boyle's Law).

Hot-air balloon flight can be explained by the combined principles of Charles's Law, Archimedes' Principle, and Boyle's Law.

Charles's Law states that the volume of a gas is directly proportional to its temperature, assuming the pressure remains constant. In the case of a hot-air balloon, the air inside the balloon is heated, causing the gas molecules to move faster and increase in temperature. As a result, the volume of the gas expands, leading to an increase in the volume of the balloon.

Archimedes' Principle states that an object immersed in a fluid experiences an upward buoyant force equal to the weight of the fluid displaced by the object. In the context of a hot-air balloon, the heated air inside the balloon is less dense than the surrounding cool air. The buoyant force acting on the balloon is equal to the weight of the air displaced by the balloon. This buoyant force is greater than the weight of the balloon itself and the payload, causing the balloon to rise.

Boyle's Law states that the pressure of a gas is inversely proportional to its volume, assuming the temperature remains constant. When the air inside the balloon is heated, the volume increases. As a result, the pressure inside the balloon decreases relative to the surrounding air pressure. The pressure difference creates a net upward force, contributing to the balloon's ascent.

In summary, the combined effects of Charles's Law, Archimedes' Principle, and Boyle's Law explain hot-air balloon flight. The heating of air inside the balloon causes the volume to expand (Charles's Law), resulting in a decrease in the pressure compared to the surrounding air (Boyle's Law). The buoyant force (Archimedes' Principle) acting on the less dense heated air allows the balloon to rise.

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Answer:

The amount of gravitational force INCREASES as the distance between two objects increases; thus, an astronauts weight DECREASES as she or he moves away from earth into space.

hope this helped.

Answer: Ernest Rutherford's

When an airplane travels 640 miles from Topeka to Houston in 3. 2 hours, going against the wind. The return trip is with the wind and takes only 2 hours. Then the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

Let Va is the velocity of the airplane

Va is the velocity of the wind

When flying against the wind then

(Va+Vw)*(3.2 hours) = 640

3.2Va + 3.2Vw = 640

3.2Vw = 640 - 3.2Va

Vw = 200 - Va----------------(1)

When flying with the wind:

(Va-V)*(2 hours) = 640km

2Va - 2Vw = 640

Va - Vw = 320 ----------------(2)

Putting the value of VW in equation (2) we get

Va - (200-Va) = 320

2Va = 320 +200

2Va = 520

Va = 260

Putting this value in equation (2)

Vw =Va - 360

Vw = 100

Therefore the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

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Answer:

1 Atm (atmospheric pressure) is equal to 101325 pascal (Pa). To convert atm to pascal, multiply the atm value by 101325. atm to pascal formula. Pa = atm * 101325.

Explanation:

The two results, the best-case complexity of Θ(n) for the Jarvis March convex hull algorithm and the lower bound of Ω(n log n) for the convex hull problem, are not contradictory.

The best-case complexity of Θ(n) for the Jarvis March convex hull algorithm means that in certain scenarios, the algorithm can achieve a linear time complexity, where the running time grows linearly with the input size. This best-case scenario occurs when the input points are already sorted in a specific order, such as sorted by their polar angles.

On the other hand, the lower bound of Ω(n log n) for the convex hull problem indicates that any algorithm that solves the convex hull problem must take at least Ω(n log n) time in the worst case, where the running time grows at least logarithmically with the input size.

These two results are not contradictory because they refer to different aspects of the problem. The best-case complexity of Θ(n) for the Jarvis March algorithm represents a specific scenario where the algorithm performs optimally, while the lower bound of Ω(n log n) applies to any algorithm attempting to solve the convex hull problem in the worst case. In other words, the Jarvis March algorithm's best-case complexity does not contradict the lower bound; it simply represents a favorable scenario where the algorithm can achieve linear time complexity.

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Answer:

.21

Explanation:

i see everyone got it wrong so ill give you the answer, good luck :)

Answer:

answer is D.it will decrease

Answer:

D. It will decrease

Explanation: Study island ;)

Answer:

If the mass of one body is doubled, force is also doubled.

Taking into account the Universal Law of Gravitation, if the masses of one body is doubled, the gravitational force between two bodies is also doubled.

The Universal Law of Gravitation establishes that bodies, by the simple fact of having mass, experience a force of attraction towards other bodies with mass, called gravitational force.

The Universal Law of Gravitation states that the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them.

Mathematically it is expressed as follows:

\(F=G\frac{Mm}{d^{2} }\)

where:

By definition of gravitational force, the greater or lesser the value of any of the masses causes the force to be greater or lesser respectively.

Finally, if the masses of one body is doubled, the gravitational force between two bodies is also doubled.

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The speed of the bullet immediately before impact was 361.7 m/s.

The speed of the bullet immediately before impact can be calculated using the law of conservation of momentum and the work-energy theorem.

The impact of the bullet causes the wooden block to move with kinetic energy, which is then dissipated through kinetic friction as it slides to a stop.

The equation for this process is:Initial momentum = Final momentum(12.0 g)(v) = (12.0 g + 98 g)(v')where v is the initial speed of the bullet and v' is the final speed of the block and bullet after impact.

Using the work-energy theorem, we can relate the kinetic energy of the block and bullet to the work done by

kinetic friction:Initial kinetic energy = Work done by kinetic friction(1/2)(12.0 g + 98 g)(v')^2 = (0.650)(12.0 g + 98 g)(9.8 m/s^2)(7.5 m)

Solving for v' and substituting back into the initial momentum equation gives:

(12.0 g)(v) = (12.0 g + 98 g)(√[(0.650)(12.0 g + 98 g)(9.8 m/s^2)(7.5 m)] / (12.0 g + 98 g))v = √[(0.650)(12.0 g + 98 g)(9.8 m/s^2)(7.5 m)] / (12.0 g)v = 361.7 m/s

Therefore, the speed of the bullet immediately before impact was 361.7 m/s.

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Answer:

no.

Explanation:

True. In GMAW (Gas Metal Arc Welding), the amperage is controlled by adjusting the wire feed speed.

GMAW is a welding process that uses a continuously fed wire electrode to join two pieces of metal together. The wire electrode is fed through a welding gun and is melted by an electric arc, which produces a pool of molten metal that solidifies to form a weld.

The amperage in GMAW is controlled by adjusting the wire feed speed, which is the rate at which the wire electrode is fed through the welding gun. Increasing the wire feed speed increases the amperage, while decreasing the wire feed speed decreases the amperage. This allows the welder to control the heat input and penetration of the weld.

As the wire feed speed increases, so does the amperage, and vice versa.

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From the description of the problem, the total velocity is obtained as 3.7 yards/ second.

The term velocity is the ratio  of the distance to the time taken. Let us note that in this case we are being asked for the average velocity of the ball and that is what we shall set to do after a consideration of the problem.

We are told that the ball is snapped to him on the 20 yard line and he jumps back 7 yards to find a receiver before running to the 50 yard line before being tackled, all during a 10 second play.

We can see that the total distance that has been covered by the ball is 7 yards + 30 yards = 37 yards and the time that has been taken is 10 seconds.

Thus velocity = distance / time = 37 yards /10 seconds

= 3.7 yards/ second

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Answer: A.

current (thumb) to magnetic field (fingers)

Answer:

A. current (thumb) to magnetic field (fingers)

Explanation:

According to the Right-Hand Thumb rule, if we are holding a current- carrying straight conductor in our right hand such that the thumb points toward the direction of current, then the fingers will wrap around the conductor in the direction of the field lines of the magnetic field.

Hope it helps.

If you have any query, feel free to ask.