Answer:
Option D is correct.
Step-by-step explanation:
Given, the side of a cube is 7 cm.
Total surface area of cube side = \(6 {s}^{2} \)
\( = 6 \times 7 \times 7\)
\( = 294\)
∴ the total surface area of cube is \(294 {cm}^{2} \)
Hope it is helpful....1. Write the dual for each of the following primal LPs:
a) Maximize z=−5x₁+2x₂
Subject to −x₁+x2₂≤−2
2x₁+3x₂≤5
x₁,x₂≥0
b) Minimize z=6x₁+3x₂
Subject to 6x1₁−3x₂+x₃≥2
3x₁+4x₂+x3₃≥5
x1₁,x₂,x3₃≥0
c) Maximize z=x1₁+x₂
Subject to 2x₁+x₂=5
3x₁−x₂ unrestricted
1. Minimize w = -2y₁ - 5y₂
2. Maximize w = 2y₁ + 5y₂
3. Minimize w = 5y₁
1. Dual of primal LP:
a) The primal LP is:
Maximize z = -5x₁ + 2x₂
Subject to:
-1x₁ + 1x₂ ≤ -2
2x₁ + 3x₂ ≤ 5
x₁, x₂ ≥ 0
To write the dual LP, we need to change the objective function and constraints. The objective function of the dual LP is to minimize the sum of the products of the dual variables and the primal constraint coefficients.
The constraints of the dual LP correspond to the primal LP's objective coefficients.
The dual LP for the given primal LP is:
Minimize w = -2y₁ - 5y₂
Subject to:
-y₁ + 2y₂ ≥ -5
y₁ + 3y₂ ≥ 2
y₁, y₂ ≥ 0
b) The primal LP is:
Minimize z = 6x₁ + 3x₂
Subject to:
6x₁ - 3x₂ + x₃ ≥ 2
3x₁ + 4x₂ + x₃ ≥ 5
x₁, x₂, x₃ ≥ 0
The dual LP for the given primal LP is:
Maximize w = 2y₁ + 5y₂
Subject to:
6y₁ + 3y₂ ≤ 6
-3y₁ + 4y₂ ≤ 3
y₁ + y₂ ≥ 1
y₁, y₂ ≥ 0
c) The primal LP is:
Maximize z = x₁ + x₂
Subject to:
2x₁ + x₂ = 5
3x₁ - x₂ unrestricted
The dual LP for the given primal LP is:
Minimize w = 5y₁
Subject to:
2y₁ + 3y₂ ≥ 1
y₁ - y₂ unrestricted
y₁, y₂ ≥ 0
These are the dual LPs for the given primal LPs.
The dual LPs are obtained by changing the objective function and constraints of the primal LPs.
The objective function of the dual LP is the opposite of the primal LP's objective function, and the constraints of the dual LP correspond to the primal LP's objective coefficients.
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???????????????????????
Answer:
D is the answer
Step-by-step explanation:
because it has high probability of success 70 %
so
A bird flies down from a higher elevation to a lower elevation at a rate of 3 meters per second. Which equation models the bird's change in elevation, in meters, after 120 seconds?
O A. (-120)(-3) = -360
O B. 120. 3 = 360
O C. 120(-3) = 360
O D. 120(-3) = -360
No links please
Answer:
D
Step-by-step explanation:
Answer: The answer is 120(-3)= -360
Step-by-step explanation:
A. P. E. X.
(0.802) The coordinate grid shows the plot of four equations. Which set of equations has (-1,5) as its solution? (4points)
Answer: A and B (first answer choice)
Explanation:
Start at the origin (0,0) where the x and y axis cross. Then move left 1 and up 5 to arrive at (-1,5). The two lines A and B cross at this location, so (-1,5) is the solution to the system formed by just these two equations alone. We ignore lines C and D.
How many unique triangles are there in the regular hexagon?
Answer:
Step-by-step explanation: There are 6 equilateral triangles in a regular hexagon by connecting the opposite vertices of a regular hexagon.
Determine if segment XY is tangent to circle Z.
Answer:
XY is not tangent to circle Z
Step-by-step explanation:
if ∠WXY = 90°, then XY is tangent to circle Z
test using Pythagorean theorem:
WX = 2(ZX) = 17
is 20² = 5² + 17²?
400 ≠ 25 + 289, so not tangent
heyy! i’ll give brainliest please help thanks
Answer:
I think its A
hope this helps
have a good day :)
Step-by-step explanation:
Help no links please please hurry make sure it’s correct
Michael buy a baket of mangoe on ale for \$ 4$4 before tax.
The ale tax i 12%.
What i the total price Michael pay for the baket of mangoe?
Total price paid by Michael for the basket of mangoes is $4.48.
For the calculation of total price, price of sales tax will be added with selling price. Forming the equation -
Total price = 4 + 12%×4
Calculating the percentage of sales tax on Right Hand Side of the equation
Total price = 4 + 12×4/100
Solving the percentage part on Right Hand Side of the equation
Total price = 4 + 0.48
Performing addition on Right Hand Side of the equation
Total price = $4.48
Hence, Michael has to pay $4.48 after addition of sales tax for the basket of mangoes.
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Learn more
The number of ways of arranging all trials to be failures in a binomial distribution is:?
In a binomial distribution, the number of ways of arranging all trials to be failures is 1. This means that there is only one way to have all trials result in failures, as each trial can only have one possible outcome - a failure.
1. In a binomial distribution, each trial can result in either a success or a failure. Let's assume that there are n trials in total.
2. To arrange all trials to be failures, we need to ensure that no trial results in a success. Therefore, for each trial, there is only one possible outcome - a failure.
3. The number of ways of arranging all trials to be failures can be calculated using combinations. In this case, we need to select 0 successes from n trials. The number of ways to do this is given by the combination formula: C(n, 0) = 1, where C represents the combination.
Therefore, the number of ways of arranging all trials to be failures in a binomial distribution is given by the combination formula, C(n, k) = n! / (k! * (n-k)!).
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The number of ways of arranging all trials to be failures in a binomial distribution is always 1. This is because there is only one way to have no successes in a set of trials.
Regardless of the number of trials or the probability of success, the number of ways of arranging all trials to be failures in a binomial distribution is always 1.
The number of ways of arranging all trials to be failures in a binomial distribution can be determined using the formula for the binomial coefficient.
The binomial coefficient, often denoted as nCk or n choose k, represents the number of ways to choose k items from a set of n items, without considering their order. In the context of a binomial distribution, n represents the total number of trials and k represents the number of successes (in this case, 0).
To find the number of ways of arranging all trials to be failures, we can use the binomial coefficient formula:
nCk = n! / (k!(n-k)!)
In this case, since we want all trials to be failures, k is equal to 0. Thus, the formula simplifies to:
nC0 = n! / (0!(n-0)!) = n! / (0! * n!) = 1
For example, if we have 5 trials and we want all of them to be failures, there is only one possible arrangement: FFFFF, where F represents a failure.
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Which of the following represents the strongest correlation? a. +.80 b. - 45 c. +45 ed.-92
Translate this sentence into an algebraic inequality.
3 more than the product of x and 12 is less than 25.
Select one:
a. 12x + 3 < 25
b. 3 > 12x – 25
c. 3 > 12(x - 25)
Answer:
Option A
Step-by-step explanation:
Lets convert each sentence into algebric inequality.
3 more than product of x & 12 :-\( = > 12x + 3\)
Now , 12x + 3 is less than 25 :-\( = > 12x + 3 < 25\)
1. A relation contains the ordered pairs shown. One of the ordered pairs is missing an x-coordinate. {(-1,4),(0,4),(2,5),(3,-6),(?,7)} What could be the missing x-coordinate if the relation is not a function?
Answer:
There are 4 possible scenarios where given relation could not be a function:
i) \((-1, 4), (0,4), (2,5), (3,-6), (-1, 7)\)
ii) \((-1, 4), (0,4), (2,5), (3,-6), (0, 7)\)
iii) \((-1, 4), (0,4), (2,5), (3,-6), (2, 7)\)
iv) \((-1, 4), (0,4), (2,5), (3,-6), (3, 7)\)
Step-by-step explanation:
From Function Theory, we remember that a relation is not a function when at least one element from domain (x-coordinate) is related to one or more elements from range (y-coordinate). Hence, there are four possibilities of making the relation not a function:
i) \((-1, 4), (0,4), (2,5), (3,-6), (-1, 7)\)
ii) \((-1, 4), (0,4), (2,5), (3,-6), (0, 7)\)
iii) \((-1, 4), (0,4), (2,5), (3,-6), (2, 7)\)
iv) \((-1, 4), (0,4), (2,5), (3,-6), (3, 7)\)
Select one correctly for brainliest!
A. 60
B. 75
C. 65
D. 50
The m ∠SPR of the rhombus with sides PQRS is 65, option C.
How to find the angle of a rhombus?Only the opposite angles of a rhombus are equal. A rhombus's diagonal angle is 90 degrees.
There are two ways to find the angle SPR of the rhombus, PQRS;
If ∠PQR = 50° then, ∠PQR = ∠PSR (opposite sides)
∠OSR = 1/2 x 50° = 25° where SQ bisects ∠PSR
∠ORS + ∠ROS + ∠OSR = 180°
∠ORS + 25° + 90° = 180°
∠ORS = 180° - 115°
∠ORS = 65°
Also, it can be calculated thus:
Because rhombus adjacent sides are supplementary, it can be written as; ∠QRS + ∠PQR = 180°
∠QRS = 180° - ∠PQR
∠QRS = 180° - 50°
∠QRS = 130°
Even though a rhombus' diagonal is an angular bisector, the ∠PRS is half of the ∠QRS.
Therefore ∠SPR = ∠QRS/2
∠SPR = 130°/2
∠SPR = 65°
The value of ∠SPR is half the angle because the opposite angles are equal therefore each side has 65°.
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Answer Both Parts and I will give u Brainiest and 20 Points!
The table shows the distance traveled by two hikers on a mountain trail. Use this information for Parts A and B below. Ill give brainiest if u answer both parts!
PART A: Choose the equation to represent the relationship between distance and time.
Options:
1. d=t+1.5
2. t=1.5(d)
3. d=1.5(t)
4. m=t+0.5
2. PART B: How far did the hikers travel after 7 hours?
Answer:
2. t=1.5(d)
Step-by-step explanation:
Part A- t=1.5(d)
Part B- 10.5
Answer:
I don't know, but thanks for the freee points and stuff
PLEASE ANSWER WITH NO LINKS THIS IS MY 3RD TIME ASKING THE SAME QUESTION Shopping at Savers Mart, Lisa buys her children 4 shirts and 3 pairs of pants for $85.50. She returns the next day and buys 3 shirts and 5 pairs of pants for $115.00. What is the price of each shirt and each pair of pants.
Need help with this is geometry
The length of the radius AB is 6 units.
How to find the length of an arc?The angle ∠BAC is 90 degrees. The length of arc BC is 3π. The length of
radius AB can be found as follows:
Hence,
length of arc = ∅ / 360 × 2πr
where
r = radius∅ = central angleTherefore,
length of arc = 90 / 360 × 2πr
3π = 1 / 4 × 2πr
cross multiply
12π = 2πr
divide both sides by 2π
r = 6 units
Therefore,
radius AB = 6 units
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Identify the graph of the equation and find (h,k).
x²-2x-²-2-36=0
a.
ellipse, (-1,-1)
b. hyperbola, (-1,1)
c.hyperbola, (1,-1)
d.
ellipse, (1,-1)
The graph of the equation is a hyperbola, (-1, 1).
We have,
To identify the graph of the equation x² - 2x - 2 - 36 = 0 and find the point (h,k), we need to rearrange the equation into a standard form and analyze the coefficients.
x² - 2x - 38 = 0
By comparing this equation to the general form of an ellipse and a hyperbola, we can determine the correct graph.
The equation for an ellipse in standard form is:
((x - h)² / a²) + ((y - k)² / b²) = 1
The equation for a hyperbola in standard form is:
((x - h)² / a²) - ((y - k)² / b²) = 1
Comparing the given equation to the standard forms, we see that it matches the equation of a hyperbola.
Therefore,
The graph of the equation is a hyperbola, (-1, 1).
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How many different 7-place license plates are possible if the first 2 places are for letters and the other 5 for numbers probability?
The total number of possible 7-place license plates are 67600000.
Given: A 7-plate license plate. 2 places are for letters and 5 places are for numbers. To find how many different 7-plate license plates are possible
Let's solve the given problem:
The license plate has 7 places. 2 places are for letters and the remaining 5 places are for numbers.
Combination of letters: As there are no restrictions given in the question, so the first letter can be any alphabet out of the 26 alphabets (A, B, C, D, ......... Z). So the first place for the letter can be filled in ²⁶C₁ ways that are 26 ways. Also for the second place, as the letters can repeat so it can be filled in ²⁶C₁ ways too which are 26 ways. Therefore, the possible ways in which the place for two letters can be filled is 26 × 26 ways = 676 ways.Combination of numbers: As there are no restrictions given in the question so the first number can be any of the numbers out of the 10 numbers (10, 1, 2, 3, ....... 9). So the first number can be filled in ¹⁰C₁ = 10 ways. Similarly, as the numbers can repeat so the 2nd, 3rd, 4th and 5th numbers can be filled in ¹⁰C₁ ways that all the other places can be filled in 10 ways each. Therefore the total number of ways in which the place for 5 numbers can be filled is 10 × 10 × 10 × 10 × 10 ways = 100000 ways.Therefore, the total number of ways in which the 7-place license plate can fill are: Total possible ways in which the two letters can be filled × Total possible ways in which the 5 number places can be filled
= 676 × 100000
= 67600000 ways
Hence the total number of possible 7-place license plates are 67600000.
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Karen rents a paddle boat at Pirates Cove water park. She is charged $0.20 per minute plus a rental fee of $12. What is the maximum number of minutes that Karen can rent a paddle boat if she has $20?
The maximum number of minutes that Karen can rent a paddle boat if she has $20 is 40 minutes.
The given charges for renting a paddle boat at Pirates Cove water park is $0.20 per minute plus a rental fee of $12. The maximum number of minutes that Karen can rent a paddle boat if she has $20 is 40 minutes.
Steps to find the maximum number of minutes that Karen can rent a paddle boat
Step 1: Set up an equation
Let the number of minutes that Karen can rent a paddle boat be x. Maximum amount Karen can spend is $20
Equation: $0.20x + $12 ≤ $20
Step 2: Solve for x$0.20x + $12 ≤ $20Subtract $12 from both sides $0.20x ≤ $8
Divide both sides by $0.20x ≤ $40
Thus, the maximum number of minutes that Karen can rent a paddle boat if she has $20 is 40 minutes.
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Please help If you know the answer!!
Answer:
-3 +8a
Step-by-step explanation:
(3-8a) *(-1)
Distribute
3*-1 -8a*-1
-3 +8a
I need help ASAP this has to be 20 characters long- oops?
Answer:
10. 700,000L greater than 70 kL
11. 6 gal less than 30 qt
12. 54 kL equals 540,000 dL
13. 10pt equal 5pt
14. 500mL less than 50L
15. 14c less than 4qt
Step-by-step explanation: Conversionssssss :)
i dont know the asnwer
Answer:
C. is the correct answer.
Step-by-step explanation:
l = -0.275t + 81
or, 70 = -0.275×40+81
or, 70 = -11+81
so, 70 = 70 (which is true)
Find f. f ''(theta) = sin(theta) + cos(theta), f(0) = 4, f '(0) = 1
The function f(theta) is:
f(theta) = sin(theta) + cos(theta) + 3
To find the function f, we will integrate the given second derivative with respect to theta twice, and use the initial conditions to determine the constants of integration.
First, integrating f ''(theta) = sin(theta) + cos(theta) with respect to theta gives:
f '(theta) = -cos(theta) + sin(theta) + C1
where C1 is a constant of integration.
Next, integrating f '(theta) = -cos(theta) + sin(theta) + C1 with respect to theta gives:
f(theta) = sin(theta) + cos(theta) + C1*theta + C2
where C2 is another constant of integration.
To determine the values of C1 and C2, we use the initial conditions:
f(0) = 4 gives us:
4 = sin(0) + cos(0) + C1*0 + C2
4 = 1 + C2
so C2 = 3.
f '(0) = 1 gives us:
1 = -cos(0) + sin(0) + C1
1 = 1 + C1
so C1 = 0.
Therefore, the function f(theta) is:
f(theta) = sin(theta) + cos(theta) + 3
Note that there are other ways to express this function, such as using trigonometric identities to simplify the expression, but this is the most general form.
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When tossing two coins, consider the following events: A1 = "obtain heads on the first coin", A2 = "obtain tails on the second coin", A3 = "obtain heads and tails". The events A1, A2, A3 are not 3-independent. Find the partition of the set S containing the three events.
The partition of set S containing the three events is { {HH}, {HT}, {TH}, {TT} }.
When tossing two coins, we have the following events:
A1 = "obtain heads on the first coin"
A2 = "obtain tails on the second coin"
A3 = "obtain heads and tails"
These events are not 3-independent. To find the partition of the set S containing these three events, let's first list all possible outcomes when tossing two coins:
1. Heads on the first coin, Heads on the second coin (HH)
2. Heads on the first coin, Tails on the second coin (HT)
3. Tails on the first coin, Heads on the second coin (TH)
4. Tails on the first coin, Tails on the second coin (TT)
Now, let's identify the outcomes that correspond to each event:
A1: {HT, HH}
A2: {TH, TT}
A3: {HT}
The partition of the set S is as follows:
S = {A1 ∩ A2, A1 ∩ A3, A2 ∩ A3, A1 ∩ A2 ∩ A3}
S = { {HH}, {HT}, {TH}, {TT} }
So, the partition of the set S containing the three events is { {HH}, {HT}, {TH}, {TT} }.
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HURRY MY TEACHER NEEDS ME TO TURN IT IN OR ILL GET A REFERAALL
Consider the points K(1,2) and L(3,5).
What possible coordinates for Point J will make Figure JKL a right triangle with the right angle at Point J?
Enter the correct answers in the boxes.
Answer:
im really not sure and its probs wrong but (3,2)??
Step-by-step explanation:
Answer:
J(3,2)
Step-by-step explanation:
consider the following discrete probability distribution. x −10 0 10 20 p(x = x) 0.35 0.10 0.15 0.40 what is the probability that x is less than 5?
The probability that x is less than 5 = 0.45
Discrete probability distribution:
It is a type of probability distribution that displays all the possible values of a discrete random variable accompanying the affiliated probabilities. We can also say that a discrete probability distribution provides the chance of occurrence of every possible value of a discrete random variable.
Discrete probability distribution:
x = -10 0 10 20
P(X=x) = 0.35 0.10 0.15 0.40
The probability that x is less than 5:
P(X<5) = 1 - P (X = 10) - P(X= 20)
1 - 0.15 - 0.40 = 0.45
The probability that x is less than 5 is = 0.45
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16 = -7v - 8 + 3v Solve for v.
Simplify your answer as much as possible.
To solve for v, isolate the variable by dividing each side by factors that don't contain the variable.
Solve for v.
\(16=-7v-8+3v\)\(v = -6\) ← Our SolutionHope this helps!
Assume that there is a statistically significant bivariate relationship between the amount of texting during driving and the number of accidents. Scientists later investigate whether or not this bivariate relationship is moderated by age.
Age 16-20: r = 0.6 p = 0.01
Age 21+: r = 0.2 p = 0.05
T or F: Based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.
It is False that based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.
In the given scenario, it is not completely true that based only on the r and p values listed above, you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.
Let's first understand what is meant by the term "moderator.
"Moderator: A moderator variable is a variable that changes the strength of a connection between two variables. If there is a statistically significant bivariate relationship between the amount of texting during driving and the number of accidents, scientists investigate whether this bivariate relationship is moderated by age.
Therefore, based on the values of r and p, it is difficult to determine if age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.
As we have to analyze other factors also to determine whether the age is a moderator or not, such as the sample size, the effect size, and other aspects to draw a meaningful conclusion.
So, it is False that based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.
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A ball is dropped from a 75 foot tall tower, and the height of the ball (in feet) can be represented by the equation h = —16t^2 + 75 where t is time (in seconds). Determine the amount of time it will take for the ball to hit the ground. Round your answer to the nearest hundredth of second. (Show Work)
Answer:
The ball will take approximately 2.165 seconds.
Step-by-step explanation:
The height of the ball is represented by the function \(h(t) = -16\cdot t^{2}+75\), the time taken by the ball to hit the ground is a value of \(t\) such that \(h(t) = 0\), we proceed to solve the following equation for \(t\):
\(-16\cdot t^{2}+75 = 0\) (1)
\(16\cdot t^{2} = 75\)
\(t = \sqrt{\frac{75}{16} }\)
\(t \approx 2.165\,s\)
The ball will take approximately 2.165 seconds.