Find the value of k such that a is singular. (enter your answers as a comma-separated list.) 0 k 1 k 5 k 1 k 0

Answer:

i think it is c hope this help's

pic is Step-by-step explanation:

Answer:

quadrant III

Step-by-step explanation:

if 2 ordered pairs are (-x, -y)

that means they are in the quadrant III

the x-coordinate is negative and the y-coordinate is negative in an ordered pair: (−x, −y). For example: (−3, −5)

The integral ∫[-2, 3] x^4 dx is convergent, and its value is 55. It is essential to identify the given integral, determine its convergence or divergence, find the antiderivative of the integrand, apply the Fundamental Theorem of Calculus, and simplify the result. These steps will help us to solve any integrals, and it is important to understand and practice these steps to succeed in calculus.

The given problem is to determine whether the integral ∫[-2, 3] x^4 dx is convergent or divergent and evaluate it if it is convergent. To solve this problem, we need to follow a few steps.

Firstly, we need to identify the given integral, which is a definite integral with lower limit -2 and upper limit 3, and the function is x^4.

Secondly, we need to determine if the integral is convergent or divergent. Since the integrand x^4 is a continuous and well-defined function over the interval [-2, 3], the integral is convergent.

Thirdly, we need to evaluate the convergent integral. To do this, we find the antiderivative of x^4 with respect to x, which is (x^5)/5.

Fourthly, we apply the Fundamental Theorem of Calculus and substitute the limits -2 and 3 into the antiderivative to get [(3^5)/5 - (-2^5)/5] = [243/5 + 32/5] = [275/5].

Finally, we simplify the result, and the final answer is 55. Therefore, the integral ∫[-2, 3] x^4 dx is convergent, and its value is 55.

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Three labeled points on the line are (-2, -2m), (0, 0), and (2, 2m), where m is the slope of the line.

A line passing through the origin but not contained in any of the three coordinate planes can be represented by the equation y = mx, where m is the slope of the line. Since the line passes through the origin, the y-intercept is 0.

To find labeled points on the line, we can choose different values for x and calculate the corresponding y-values using the equation y = mx. Let's choose three values for x: -2, 0, and 2.

For x = -2:

y = m(-2) = -2m

So, one labeled point on the line is (-2, -2m).

For x = 0:

y = m(0) = 0

Another labeled point on the line is (0, 0).

For x = 2:

y = m(2) = 2m

So, the third labeled point on the line is (2, 2m).

These three labeled points (-2, -2m), (0, 0), and (2, 2m) lie on the line passing through the origin, and they are not contained in any of the coordinate planes.

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A.) The rate of change of the water level with respect to time is (1/4) times the rate of change of the radius with respect to time. B.) The water level h as a function of time t is given by the equation h = 50t. C.) The rate of change of the radius of the cone with respect to time when the water is 8 meters deep is 200.

A.) To find the rate of change of the water level with respect to time, we need to use similar triangles. Let's denote the water level as h (the height of the water in the tank) and let's denote the radius of the water surface as r.

Since the tank is in the shape of a cone, we know that the ratio of the change in radius to the change in height is constant. Therefore, we can write:

(r/40) = (h/10)

To find the rate of change of the water level with respect to time (dh/dt), we differentiate both sides of the equation with respect to time:

(d(r/40)/dt) = (d(h/10)/dt)

Now, let's express the rate of change of the radius with respect to time (dr/dt) in terms of the rate of change of the water level with respect to time:

(dr/dt) = (40/10) * (dh/dt)

Simplifying this expression, we get:

(dr/dt) = 4 * (dh/dt)

Therefore, the rate of change of the water level with respect to time (dh/dt) is (1/4) times the rate of change of the radius with respect to time (dr/dt).

B.) To find the water level h as a function of time t, we need to integrate the rate of change of the water level with respect to time (dh/dt) over time. Since water is flowing into the tank at a constant rate of 50m^3/min, we can write:

dh/dt = 50

Integrating both sides with respect to time, we get:

∫dh = ∫50 dt

h = 50t + C

Since we are given that the tank is initially empty at t = 0, we can substitute h = 0 and t = 0 into the equation:

0 = 50(0) + C

C = 0

Therefore, the equation for the water level h as a function of time t is:

h = 50t

C.) To find the rate of change of the radius of the cone with respect to time when the water is 8 meters deep (h = 8), we can use the relationship we derived earlier:

(dr/dt) = 4 * (dh/dt)

We know that the rate of change of the water level with respect to time is dh/dt = 50. Substituting this into the equation, we get:

(dr/dt) = 4 * 50

(dr/dt) = 200

Therefore, the rate of change of the radius of the cone with respect to time when the water is 8 meters deep is 200.

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Answer:

La mayor tiene 61 años.

Step-by-step explanation:

Sea x,y,z la edad de la mayor, intermedio y la menor respectivamente.

Tenemos las siguientes ecuaciones:

\(x+y+z=127\) (la suma de las edades es 127)

\(x = z+30\) (la mayor tiene 30 años más que la menor)

La frase "y la del intermedio 26 menos que la menor" no tiene sentido, puesto que esto implicaría que la del intermedio es menor que la menor. Luego se asume que la frase ha de ser "y la del intermedio 26 menos que la mayor"

\(x-26 = y\) (la del intermedio tiene 26 menos que la mayor).

La segunda ecuación se traduce a x-30 =z. Si reemplazamos todo en la primera ecuación obtenemos

\(x+(x-26)+(x-30) = 127\)

Obtenemos la ecuación

\(3x-56 = 127\)

Sumando 56 a ambos lados y dividiendo por 3, obtenemos

\( x = \frac{127+56}{3} = 61\)

Es decir la mayor tiene 61 años.

Answer:

15

Step-by-step explanation:

that is the answer

(a) The amount in the account at the end of 1 year is $3330

(b) The amount in the account at the end of 2 year is $3696.3

It is given that Deon deposit $3000 that pays 11% interest compounded each year .

(a) Putting P = $3000, R =  11%  , T = 1 year in equation (1) , we get

           \(A=3000(1+\frac{11}{100} )^1\\\\A=3000(1+0.11)\\A=3000(1.11)\\A=3330\)

(b) Putting P = $3000, R =  11%  , T = 2 year in equation (1) , we get

       \(A=3000(1+\frac{11}{100} )^2\\\\A=3000(1+0.11)^2\\A=3000(1.11)^2\\A=3000\times1.23\\A=3696.3\)

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Answer:

b

Step-by-step explanation:

Answer:

The answer is the Last one

The percentage of people who filed their taxes during the week of tax day is 10%

I can estimate how many people filed their taxes during the week of April 15th using a percentage of 100 is a/b * 100.

A percentage is a portion of a sum divided into 100 equal parts.

Calculate (Number of persons who submitted their taxes during the week of April 15th / total people who filed their taxes that year) times 100 to get the percentage of people who filed during that week.

Let :

a represents the total number of taxpayers during the week of April 15th.

b represents the total number of taxpayers for that year.

The original equation is reduced to

a/b× 100

As an illustration, 100 individuals submitted their taxes the week of April 15th and

Let's say that year, 1000 persons filed their taxes.

= 100/1000 = 10%

Thus, 10% of Americans submitted their taxes during the week of April 15th, or 100 out of 1,000.

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Answer:

\(\boxed{(f~.~g)(x) = 2n^4 + 2n^3 - 4n^2 -4n}\)

.

Step-by-step explanation:

We know that

\(f(n) = n^3 - 2n\)

\(g(n) = 2n + 2\)

.

So

\((f~.~g)(x) = f(n)~.~g(n)\)

\((f~.~g)(x) = (n^3-2n)(2n + 2)\)

\((f~.~g)(x) = n^3(2n + 2) - 2n(2n + 2)\)

\((f~.~g)(x) = 2n^4 + 2n^3 - 4n^2 -4n\)

Answer:

2jj2j wnqj qkwk abaia aow w wka a9w wjw a8uaaia sks sis s8siwobsisi shkahza a

Step-by-step explanation:

bs ak la ya s dyua youa au ab fusn aigska

The answer is SSW = 84.MSA is the Mean Square Error for the analysis of variance test of hypothesis for comparing means.

Given, A single factor with six groups and three values in each group. Degrees of freedom = 17.

a) If SSA = 140 and SST = 224,

SSW = SST - SSA = 224 - 140 = 84

b) MSA = SSA / (k - 1) = 140 / (6 - 1) = 28

c) MSW = SSW / (n - k) = 84 / (3 * 6 - 6) = 4.67

d) FSTAT = MSA / MSW = 28 / 4.67 = 6.00

Therefore, SSW = 84, MSA = 28, MSW = 4.67 and FSTAT = 6.00

First we have to find SSW = SST - SSA = 224 - 140 = 84

This is the value of within-group variation.

Hence the answer is SSW = 84.

MSA is the Mean Square Error for the analysis of variance test of hypothesis for comparing means.

Experiment has single factor with 6 groups with 3 values in each group, hence k = 6.MSA = SSA / (k - 1) = 140 / (6 - 1) = 28.

MSW is Mean Square Error which is the variance of the errors in the model.

MSW = SSW / (n - k) = 84 / (3 * 6 - 6) = 4.67

FSTAT = MSA / MSW = 28 / 4.67 = 6.00

Therefore, SSW = 84, MSA = 28, MSW = 4.67 and FSTAT = 6.00.

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The sequence of natural numbers that leaves a remainder of 3 when divided by 10 is:

3, 13, 23, 33, 43, 53, 63, 73, 83, 93, 103, 113, ...

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

The colour of your eyes and your shoe size.

Option B is the correct answer.

x(t) = \(c_1e^1^4^t+c_2e^-^t\)  , y(t) = \(2c_1e^1^4^t-c_2e^-^t\)   is the general solution of the sytem of differention eqution dx/dt = 4x+ 5y , dy/dt = 10x + 9y .

given  dx/dt = 4x+ 5y  and dy/dt = 10x + 9y

X'(t) = \(\left[\begin{array}{ccc}4&5\\10&9\end{array}\right]\)  X

where X = \(\left[\begin{array}{ccc}x\\y\\\end{array}\right]\)

so A = \(\left[\begin{array}{ccc}4&5\\10&9\end{array}\right]\)

now we need to find eigen value of the matrix and the corresponding eigen vector.

| A- λI | = 0

so after equation the value to zero

λ = 14 and λ = -1

now for the  λ = 14 corresponding eigen vector = \(\left[\begin{array}{ccc}1\\2\\\end{array}\right]\)

for λ = -1 corresponding eigen vector =  \(\left[\begin{array}{ccc}1\\-1\\\end{array}\right]\)

So general equation is given by:

X(t) = \(c_1e^1^4^t\)  \(\left[\begin{array}{ccc}1\\2\\\end{array}\right]\)  +  \(c_2e^-^t\)   \(\left[\begin{array}{ccc}1\\-1\\\end{array}\right]\)

after solving this

x(t) = \(c_1e^1^4^t+c_2e^-^t\)

y(t) = \(2c_1e^1^4^t-c_2e^-^t\)

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Answer:

I am not sure sowwy i hope you get it tho!!

Step-by-step explanation:

1_2_3_

Answer:

50º

Step-by-step explanation:

A triangles angles = 180º

Angle A = 40º

Angle C = 90º  (this is a right triangle)

40º + 90º = 130º

180º - 130 º = 50º

All solutions to the given problem regarding matrices have been explained and answered below.

We have been given the equations,

x + y - z = 2

x + 2y + z = 3

x + y + (k²-5) z = k

the augmented matrix for the given equations will be,

\(\left[\begin{array}{ccc|c}1&1&-1&2\\1&2&1&3\\1&1&(k^{2}-5)&k\end{array}\right]\)

After applying row operations we get the row-reduced form of the matrix, i.e.

\(\left[\begin{array}{ccc|c}1&0&0&\frac{5+k}{2+k} \\0&1&0&\frac{k}{2+k} \\0&0&1&\frac{1}{2+k}\end{array}\right]\)

For a matrix to be no solutions the rank of the matrix has to be lesser than the rank of the augmented matrix,

If we put k = -2, we get

\(\left[\begin{array}{ccc|c}1&0&-3&0\\0&1&2&0 \\0&0&0&1\end{array}\right]\)

∴ for k = -2, we get no solutions for the equations.

For a matrix to be having infinitely many solutions, the rank of the matrix has to be lesser than the no. of variables,

but for no values of k this condition is satisfied for the given equations,

∴ for no values of k, we get infinitely many solutions for the equations.

And for any other of k, the solutions will be unique.

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Answer:

9

Step-by-step explanation:

-77+5=-72

-72 divided by -8 = 9

Answer: k = √27-i

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

yes they are correct

Answer:

No

Step-by-step explanation:

|-138| = 138

|5/2| = |2.5| = 2.5

|9 5/8| = |9.625| = 9.625

|18.45| = 18.45

|113| = 113

Correct order would be:

|-138|, |113|, |18.45|, |9 5/8|, |5/2|

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

Step-by-step explanation:

The equation of an ellipse centered at the origin with height 8 units and width 16 units is (x² / 64) + (y² / 16) = 1.

To write the equation of an ellipse centered at the origin with height 8 units and width 16 units, we need to determine the semi-major axis (a) and the semi-minor axis (b). The width corresponds to the horizontal axis, and the height corresponds to the vertical axis.

In this case, the width is 16 units, so half of the width, or the semi-major axis, is 8 units. Thus, a = 8. The height is 8 units, so half of the height, or the semi-minor axis, is 4 units. Therefore, b = 4.

Now, we can use the standard equation for an ellipse centered at the origin:

(x² / a²) + (y² / b²) = 1

Plugging in the values of a and b, we get:

(x² / 8²) + (y² / 4²) = 1
(x² / 64) + (y² / 16) = 1

This is the equation of the ellipse centered at the origin with height 8 units and width 16 units.

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Answer:

I love algebra anyways

The ans is in the picture with the  steps how i got it

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

Experiment: Rolling three dice simultaneously

No of possible outcomes: 6*6*6 = 216

The Sample space is shown below:

(1,1,1) (1,1,2) (1,1,3) (1,1,4) (1,1,5) (1,1,6)

(1,2,1) (1,2,2) (1,2,3) (1,2,4) (1,2,5) (1,2,6)

(1,3,1) (1,3,2) (1,3,3) (1,3,4) (1,3,5) (1,3,6)

(1,4,1) (1,4,2) (1,4,3) (1,4,4) (1,4,5) (1,4,6)

(1,5,1) (1,5,2) (1,5,3) (1,5,4) (1,5,5) (1,5,6)

(1,6,1) (1,6,2) (1,6,3) (1,6,4) (1,6,5) (1,6,6)

(2,1,1) (2,1,2) (2,1,3) (2,1,4) (2,1,5) (2,1,6)

(2,2,1) (2,2,2) (2,2,3) (2,2,4) (2,2,5) (2,2,6)

(2,3,1) (2,3,2) (2,3,3) (2,3,4) (2,3,5) (2,3,6)

(2,4,1) (2,4,2) (2,4,3) (2,4,4) (2,4,5) (2,4,6)

(2,5,1) (2,5,2) (2,5,3) (2,5,4) (2,5,5) (2,5,6)

(2,6,1) (2,6,2) (2,6,3) (2,6,4) (2,6,5) (2,6,6)

(3,1,1) (3,1,2) (3,1,3) (3,1,4) (3,1,5) (3,1,6)

(3,2,1) (3,2,2) (3,2,3) (3,2,4) (3,2,5) (3,2,6)

(3,3,1) (3,3,2) (3,3,3) (3,3,4) (3,3,5) (3,3,6)

(3,4,1) (3,4,2) (3,4,3) (3,4,4) (3,4,5) (3,4,6)

(3,5,1) (3,5,2) (3,5,3) (3,5,4) (3,5,5) (3,5,6)

(3,6,1) (3,6,2) (3,6,3) (3,6,4) (3,6,5) (3,6,6)

(4,1,1) (4,1,2) (4,1,3) (4,1,4) (4,1,5) (4,1,6)

(4,2,1) (4,2,2) (4,2,3) (4,2,4) (4,2,5) (4,2,6)

(4,3,1) (4,3,2) (4,3,3) (4,3,4) (4,3,5) (4,3,6)

(4,4,1) (4,4,2) (4,4,3) (4,4,4) (4,4,5) (4,4,6)

(4,5,1) (4,5,2) (4,5,3) (4,5,4) (4,5,5) (4,5,6)

(4,6,1) (4,6,2) (4,6,3) (4,6,4) (4,6,5) (4,6,6)

(5,1,1) (5,1,2) (5,1,3) (5,1,4) (5,1,5) (5,1,6)

(5,2,1) (5,2,2) (5,2,3) (5,2,4) (5,2,5) (5,2,6)

(5,3,1) (5,3,2) (5,3,3) (5,3,4) (5,3,5) (5,3,6)

(5,4,1) (5,4,2) (5,4,3) (5,4,4) (5,4,5) (5,4,6)

(5,5,1) (5,5,2) (5,5,3) (5,5,4) (5,5,5) (5,5,6)

(5,6,1) (5,6,2) (5,6,3) (5,6,4) (5,6,5) (5,6,6)

(6,1,1) (6,1,2) (6,1,3) (6,1,4) (6,1,5) (6,1,6)

(6,2,1) (6,2,2) (6,2,3) (6,2,4) (6,2,5) (6,2,6)

(6,3,1) (6,3,2) (6,3,3) (6,3,4) (6,3,5) (6,3,6)

(6,4,1) (6,4,2) (6,4,3) (6,4,4) (6,4,5) (6,4,6)

(6,5,1) (6,5,2) (6,5,3) (6,5,4) (6,5,5) (6,5,6)

(6,6,1) (6,6,2) (6,6,3) (6,6,4) (6,6,5) (6,6,6)

Favorable outcome (three similar numbers, i.e. getting an identical number in all the three dice) : 6

Probability = No of favorable outcomes/Total no of outcomes = 6/216 = 0.0278

Answer:

182

Step-by-step explanation:

260 x 30% = 78

260 - 78 = 182

The Solution.

By Trigonometrical Ratios, we have,

SOH, CAH, TOA

Where S

Where in the case at hand,

H = 11

To find the value of x in the given problem,

Taking 25 degrees as our angle of interest, we have,

One of the required expressions is:

Similarly, taking 65 degrees as the angle of interest, we have

The other required expression for finding x is:

The correct answers are;

x = 11 sin 65 degrees

x = 11 cos25 degrees

one cyclist travels faster than the other. Therefore, the rate of the faster cyclist is (distance between towns) / (2 * hours) and the rate of the slower cyclist is also (distance between towns) / (2 * hours).

Let x = the rate of the faster cyclist, and y = the rate of the slower cyclist.

We can set up the equation:

x + y = (distance between towns) / (time they met)

x + y = (distance between towns) / (hours)

We can solve for x and y:

x = (distance between towns) / (2 * hours)

y = (distance between towns) / (2 * hours)

Therefore, the rate of the faster cyclist is (distance between towns) / (2 * hours) and the rate of the slower cyclist is also (distance between towns) / (2 * hours).

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