find volume of cylinder d= 42cm h= 7cm​

There are 2.47105 acres in 1 hectare.

An acre is a common unit of measurement in the United States and other countries. One acre equals 43,560 square feet (4,047 square metres).

In contrast, a hectare is a metric unit of area that is widely used in many countries. One hectare equals 10,000 square metres (2.47105 acres).

You can use the conversion factor of 1 acre = 0.4047 hectares or 1 hectare = 2.47105 acres to convert acres to hectares.

Simply multiply the number of acres by 0.4047 to convert from acres to hectares. Similarly, multiply the number of hectares by 2.47105 to convert the number of hectares to acres.

To convert a given number of acres to hectares using mathematical terms, you can use the formula:

Hectares = Acres × 0.4047

In this formula, "Acres" is the number of acres you want to convert to hectares, and "Hectares" is the equivalent area in hectares.

Similarly, to convert a given number of hectares to acres using mathematical terms, you can use the formula:

Acres = Hectares × 2.47105

In this formula, "Hectares" is the number of hectares you want to convert to acres, and "Acres" is the equivalent area in acres.

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The partial derivatives of the function \(\(f(x, y) = 6x^4y^3\)\) evaluated at the given points are:

\(\[\begin{aligned}f_x(x, y) &= 24x^3y^3 \\f_x(-2, y) &= -192y^3 \\f_x(x, 4) &= 3072x^3 \\f_x(-2, 4) &= -3072 \\f_y(x, y) &= 18x^4y^2 \\f_y(-2, y) &= 144y^2 \\f_y(x, 4) &= 288x^4 \\f_y(-2, 4) &= 1152 \\\end{aligned}\]\)

To find the partial derivatives of the function \(\(f(x, y) = 6x^4y^3\)\), we differentiate with respect to each variable while treating the other variable as a constant.

\(\[f_x(x, y) = \frac{\partial f}{\partial x} = 24x^3y^3\]\)

To evaluate \(\(f_x(-2, y)\)\), we substitute x = -2 into the expression:

\(\[f_x(-2, y) = 24(-2)^3y^3 = -192y^3\]\)

Next, we find \(\(f_x(x, 4)\)\) by substituting y = 4 into the expression:

\(\[f_x(x, 4) = 24x^34^3 = 3072x^3\]\)

For \(\(f_x(-2, 4)\)\), we substitute x = -2 and y = 4:

\(\[f_x(-2, 4) = 24(-2)^34^3 = -3072\]\)

Moving on to the partial derivative with respect to y:

\(\[f_y(x, y) = \frac{\partial f}{\partial y} = 18x^4y^2\]\)

For \(\(f_y(-2, y)\)\), we substitute x = -2:

\(\[f_y(-2, y) = 18(-2)^4y^2 = 144y^2\]\)

Similarly, for (\(f_y(x, 4)\)), we substitute y = 4:

\(\[f_y(x, 4) = 18x^44^2 = 288x^4\]\)

Finally, for \(\(f_y(-2, 4)\)\), we substitute x = -2 and y = 4:

\(\[f_y(-2, 4) = 18(-2)^44^2 = 1152\]\)

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Complete Question:

Let \(\( f(x, y)=6 x^{4} y^{3} \)\). Then find

\(f_{x}(x, y), f_{x}(-2, y) , f_{x}(x, 4) , f_{x}(-2,4), f_{y}(x, y), f_{y}(-2, y), f_{y}(x, 4), f_{y}(-2,4)\).

If the front suspension system of a car has coiled springs of spring constant(k) of about 82,000N/m attached to the front wheels, then the force required to compress this spring by 1.2 cms will be  984N.

As per the question statement, the front suspension system of a passenger car has coiled springs attached to the front wheels and a typical spring has a spring constant "k" of about 82,000 k/m.

We are required to calculate the force required to compress this spring by 1.2 cms

To solve this question, we will need to apply the formula to calculate the force to compress a spring, which is known as the Hooke's Law. So, as per the Hooke's Law, the force (F) required to compress a spring of spring constant (k) by "x" units, can be represented as

[F = (k * x)]

Now comparing the RHS of the Hooke's Law equation with the data provided in the question statement, we get, (k = 82000 N/m) and

(x = 0.012 m), and using these values in the Hooke's law equation, we get, the force required to compress a spring of spring constant(k) of about 82,000N/m by 1.2 cms will be (82000 * 0.012)N = 984 N.

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Answer: 21/572

\(\frac{5.5}{10 . 22} - \frac{4}{52}\)

The dots stand for multiplication

Between the two satellites is an estimated distance of around 4.2 times 10-4 metres, which is an extremely large distance.

The distance that separates the two spacecraft may be calculated using the following formula: distance = speed time. This will allow us to know how far away the two spacecraft are. In this particular instance, the speed of the radio transmission is identical to the speed of light, which is around 3,108 metres per second. The amount of time it takes for a signal to get from one satellite to another is approximately 1.4 times 10 to the fourth of a second.

By applying the method, we are able to arrive at the following conclusion on the total distance that separates us:

distance = (3×10^8 m/s) × (1.4×10^(-4) s) = 4.2×10^4 meters.

As a direct result of this fact, the distance that exists between the two spacecraft is approximately similar to 4.2 x 10-4 metres.

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The rate at which the wage earners and rural households should save is 21%.

Given that:

Depreciation (δ) = 0.03

Capital output ratio (c) = 3

Profit share of income (π/Y) = 0.5

Savings out of capital income (sπ) = 25% = 0.25

We know that the modified Harrod-Domar growth model is given as:

c(g+δ) = (sπ - sW)(Yπ) + sW

We can rearrange the above equation to find the value of savings out of wage income as follows:

sW = c(g+δ - sπ(Yπ))/ (sπ - π/Y)

Plugging in the given values:

sW = 3(0.04 + 0.03 - 0.25(0.5))/ (0.25 - 0.5)

On solving the above equation, we get:

sW = 0.21 or 21%

Hence, the rate at which the wage earners and rural households should save is 21%. Therefore, the required answer is 21%.

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Answer:

330 miles

Step-by-step explanation:

We can use a ratio to solve

33 miles          x miles

------------  = ----------------

3/5 hour          6 hours

Using cross product

33 *6 = 3/5 x

198 = 3/5x

Multiply each side by 5/3

198*5/3 = 5/3 * 3/5x

330 =x

The Chi-square test is a statistical test used to determine if there is a significant difference between observed and expected frequencies in categorical data. In this example, the test is used to assess whether there is a significant difference in the mean breaking strengths of two types of cables.

The Chi-square test of significance is employed when dealing with categorical or nominal data. It compares the observed frequencies with the frequencies that would be expected if the variables were independent. In this case, the breaking strengths of the two cables are the variables of interest.

To perform the test, the first step is to define the null hypothesis (H0) and the alternative hypothesis (Ha). In this example, H0 assumes that there is no difference in the mean breaking strengths of the two cables, while Ha suggests that there is a difference.

Next, the test statistic, denoted by X2 (chi-square), is calculated using the formula X2 = Σ[(O - E)²/E], where O represents the observed frequencies and E represents the expected frequencies under the assumption of independence.

To determine the expected frequencies, we need to estimate the means and variances of the breaking strengths. Here, x = 1925 and sigma = 40 for the first cable, and x = 1905 and sigma = 30 for the second cable.

Once the test statistic is calculated, it is compared to a critical value from the Chi-square distribution with degrees of freedom equal to (r - 1)(c - 1), where r is the number of rows and c is the number of columns in the contingency table. The significance level of 0.01 determines the critical value.

If the calculated X2 value is greater than the critical value, we reject the null hypothesis and conclude that there is sufficient evidence to indicate a difference in the mean breaking strengths of the two cables. Conversely, if the calculated X2 value is less than or equal to the critical value, we fail to reject the null hypothesis and conclude that there is no significant difference.

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Answer:

Step-by-step explanation:

8d+2d+6d+9-6d = 0

First, combine like terms, so it would become;

10d+9 = 0

Then, separate anything without a variable;

10d = -9

Then you divide;

d= -0.9

Answer:

10d + 9 = 0

Step-by-step explanation:

Simple explanation:

1.  8d + 2d + 6d + 9 - 6d = 0

2. 16d + 9 - 6d = 0

3. Ans: 10d + 9 = 0

Thorough explanation

1. Solve the equation using BIMDAS OR BEDMAS - whatever acronym you were taught

2. Since there are addition and subtraction in this equation we need to solve it from left to right.

3. Re-arrange the equation by putting like terms together - if that makes sense:

So 8d + 2d + 6d + 9 - 6d = 0

Becomes  8d + 2d + 6d - 6d + 9 = 0

4. Then you simply simplify the equation (Remember, go from left to right)

5. (8+2+6)d - 6d + 9 = 0

6. 16d - 6d + 9 = 0

7. (16-6)d + 9 = 0

8. Ans: 10d + 9 = 0

You can leave it at here because you only need to solve the equation. However, if the question says to "solve for d" (which is not the question being asked rn), then take 9 from both sides: 10d + 9 - 9 = 0 - 9

Which gives you: 10d = -9

Then divide by 10

                         10d/10= -9/10

             Ans:            d = -9/10

d would equal negative nine over ten

The Appalachian Trail is a continuous hiking trail that passes through 14 states in the US.

The histogram shows the length of the trail through each state. 

Frequency

What interval contains the 50th percentile for this data?

Options

a) 0 to 0 100 miles

b) 100 to 200 miles

c) 200 to 300 miles

d) 500 to 600 miles

14 states, the 50th percentile = 7/14

_____________________

Answer

The 50th percentile for this data 0 to 0 100 miles

___________________________

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The cost of a toy train is Rs. 175. The total amount paid by him is Rs.1000. Hence, the change that he got is Rs.215.

Given that the cost of a toy car is Rs. 130And the cost of a toy train is Rs. 45 more than the cost of a toy car.Thus the cost of a toy train can be calculated as follows:Cost of a toy train = Cost of a toy car + Rs.45= Rs. 130 + Rs.45= Rs.175Given that Ajay bought 2 toy cars and 3 toy trains.Thus the total cost of the toys can be calculated as follows:Total cost of the toys = (Cost of 2 toy cars) + (Cost of 3 toy trains)= (2 × Rs.130) + (3 × Rs.175)= Rs.260 + Rs.525= Rs.785Given that he gave the cashier two Rs.500 notes.

Then the total amount paid by Ajay is:Total amount paid = 2 × Rs.500= Rs.1000Thus, the change that he got can be calculated as:Change = Total amount paid − Total cost of the toys= Rs.1000 − Rs.785= Rs.215Therefore, the change that Ajay got was Rs.215. Thus, the cost of a toy train is Rs.175. Given that Ajay bought 2 toy cars and 3 toy trains. The total cost of the toys is Rs.785. He gave the cashier two Rs.500 notes. Thus, the total amount paid by him is Rs.1000. Hence, the change that he got is Rs.215.

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Answer:

A and D

Step-by-step explanation:

Given that EFGH is a scaled copy of ABCD, EFGH is similar to ABCD. The ratio of the corresponding lenght of their segments are equal, and therefore have the same scale factor.

This means: \( \frac{EF}{AB} = \frac{FG}{BC} = \frac{GH}{CD} = \frac{EH}{AD} \)

We are given only the length of segment GH = 12. GH corresponds with segment CD = 6, therefore:

Scale factor = \( \frac{GH}{CD} = \frac{12}{6} = 2 \).

This implies that all length segments of ABCD was increased by 2 to get a scale copy of EFGH.

Angles in EFGH will have the same measures of degree as the corresponding angles in ABCD, because, it would have the same shape but only different in size.

The following statements are therefore true:

A. Segment EF is twice as long as segment AB. (Scale factor = 2)

D. The length of segment EH is 16 units. (EH = 2*AD = 2*8 = 16)

Angela's use 6 cups of flour and Jaleel's use 19/3 cups of flour.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The graph shows the relationship between the number of cups of flour and the number of cups of sugar in Angela's brownie recipe.

And, The table shows the same relationship for Jaleel's brownie recipe.

Hence, The equation for Angela's brownie recipe is,

Two points on graph are (4, 2) and (2, 1)

⇒ y - 2 = (2 - 1)/ (4 - 2) (x - 4)

⇒ y - 2 = 1/2 (x - 4)

⇒ y - 2 = 1/2x - 2

⇒ y = 1/2x

And, The equation for Jaleel's brownie recipe is,

Two points on graph are (3/2, 1) and (3, 2)

⇒ y - 1 = (2 - 1)/ (3 - 3/2) (x - 4)

⇒ y - 1 = 2/3 (x - 4)

⇒ y - 1 = 2/3x - 8/3

⇒ y = 2/3x - 8/3 + 1

⇒ y = 2/3x - 5/3

So, For Jaleel and Angela buy a 12-cup bag of sugar.

The equation for Angela's brownie recipe is,

⇒ y = 1/2x

⇒ y = 1/2 × 12

⇒ y = 6

The equation for Jaleel's brownie recipe is,

⇒ y = 2/3x - 5/3

⇒ y = 2/3 × 12 - 5/3

⇒ y = 19/3

Thus, Angela's use 6 cups of flour and Jaleel's use 19/3 cups of flour.

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Answer:

Lololololo9lolo9lkiujyhgdfbhjkifewkjuhgsdvcgfh

Step-by-step explanation:

Option D is correct-  1/25 should be added to complete the square of the expression.

Quadratics can be defined as a polynomial equation of a second degree, which implies that it comprises a minimum of one term that is squared. It is also called quadratic equations.

Expression

Expressions in math are mathematical statements that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between.

we have to add the 1/25 to the square of the equation, x^2 - 2/5x

by adding 1/25 in the equation, we get

x ^2 -2/5x +1/25

= (x)^2 - 2* x* 1/5 + (1/5)^2

= (x - 1/5)^2

so, 1/25 must be added.

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The probability that a randomly selected household with a savings account has no checking account is approximately 0.149, or 14.9%.

To compute the probability that a randomly selected household with a savings account has no checking account, we can use Bayes' theorem. Let S denote the event that a household has a savings account, and C denote the event that a household has no checking account.

We want to find P(C | S), the probability that a household with a savings account has no checking account.

Using Bayes' theorem, we have:

P(C | S) = P(S | C) * P(C) / P(S)

We know that 40% of households with no checking accounts have savings accounts, so P(S | C) = 0.4. We also know that 21.5% of households have no checking accounts, 66.9% have regular checking accounts, and 11.6% have NOW accounts, so P(C) = 0.215.

Finally, we can use the law of total probability to find P(S), the overall probability of a household having a savings account:

P(S) = P(S | C) * P(C) + P(S | regular checking) * P(regular checking) + P(S | NOW) * P(NOW)

= 0.4 * 0.215 + 0.716 * 0.669 + 0.793 * 0.116

≈ 0.576

Substituting these values into the equation for Bayes' theorem, we get:

P(C | S) = 0.4 * 0.215 / 0.576

≈ 0.149

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Complete question is:

A survey revealed that 21.5% of the households had no checking account, 66.9% had regular checking accounts, and 11.6% had NOW accounts. Of those households with no checking account 40% had savings accounts. Of the households with regular checking accounts 71.6% had a savings account. Of the households with NOW accounts 79.3% had savings accounts.

Compute the probability that a randomly selected household with a savings account has no checking account.

Answer:

d. 11.6

Step-by-step explanation:

11.6 is the answer. Hope that hels

\(\huge\text{Hey there!}\)

\(\mathsf{p^2 + 24 = 159}\)

\(\large\text{SUBTRACT 24 to BOTH SIDES}\)

\(\mathsf{p^2+24-24=159-24}\)

\(\large\text{Cancel out: 24 - 24 because that gives you 0}\)

\(\large\text{Keep: 159 - 24 because it helps you solve for p}\)

\(\mathsf{159 - 24 = \bf 135}\)

\(\large\text{New equation: }\mathsf{p^2 =135}\)

\(\large\text{TAKE your SQUARE ROOT}\)

\(\mathsf{p=\pm 3\sqrt{135}}\)

\(\mathsf{\sqrt{135}=3\sqrt{15} \ OR\ -\sqrt{135} = -3\sqrt{15}}\)

\(\large\text{Original answer: }\mathsf{\underline{p=3\sqrt{15}\ or\ p = -\sqrt{15}}}\)

\(\boxed{\boxed{\large\text{Answer: \huge\bf D. 11.6}}}\huge\checkmark\)

\(\text{Good luck on your assignment and enjoy your day!}\)

~\(\frak{Amphitrite1040:)}\)

Answer:

Force, F = 51300 N

Step-by-step explanation:

We have,

Mass of a car is 1350 kg

Acceleration of the car is 38 m/s².

It is required to find the force required to accelerate the car. The force acting on the object is given by the formula as follows:

\(F=ma\\\\F=1350\ kg\times 38\ m/s^2\\\\F=51300\ N\)

So, the force of 51300 N is required to accelerate the car.

Fritz et al. (2019) conducted an experimental study where high school students were randomly assigned to either write weekly gratitude letters or list their daily activities each week.

The study conducted by Fritz et al. (2019) involved randomly assigning high school students to either write weekly gratitude letters or list their daily activities each week. To determine the type of study conducted, we need to consider the answer choices: correlational, naturalistic, experimental, and observational.
In this case, the study can be classified as an experimental study. This is because the researchers assigned participants to specific conditions (gratitude letters or daily activity lists) and observed the effects of these conditions on the participants' outcomes.

By randomly assigning the participants to the different groups, the researchers aimed to minimize any pre-existing differences between the groups, making it possible to draw causal conclusions about the impact of the intervention (gratitude letters or daily activity lists).
In conclusion, Fritz et al. (2019) conducted an experimental study where high school students were randomly assigned to either write weekly gratitude letters or list their daily activities each week.

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Answer: x^2+10x+5x+50    =    x^2+15x+50

Step-by-step explanation:

Basically, use something called FOIL. It stands for first, outer, inner, last. Basically multiply the first x, by the first x in the second parenthesis. Then multiply that x by the outer x in the second parenthesis. After that, multiply the 5 by the inner x. Then the five by the ten.

Answer

x²+15x+50

Step-by-step explanation:

You start with the left side of the equation. Multiply the right binomial by x

{ x (x) + x(10) }  = x² + 10x

Then multiply the right side of the equation by 5

{  5 (x) + 5 (10)  =  5x + 50

Add both the (x² + 10x) and the (5x+50)

This will give you an answer of x²+15x+50

The information provided indicates that 188 teachers and staff members own vehicles.

An arithmetic value used to compute and describe a quantity is, in fact, a number. In writing, numerical symbols like "3" are used to represent numbers. Using numerals or symbols to symbolize numbers, a numbering system seems to be a logical approach to convey numbers.

27% of students (s) 94 percent are teachers and workers (t).

The ratio between these two variables is 10:1, which suggests that there is only one employee for every 10 pupils, meaning that students outnumber teachers and other workers by a factor of 10.

Thus, 27% of 10 pupils is equal to 2.7 students, and 94% of 1 employee is equal to 0.94 employees and teachers. Therefore, if there are 2000 pupils, there must be 200 teachers. The number of students who own automobiles is 0.27(2000)=540, whereas 0.94(200)=188 is the number of teachers and staff who own cars.

You can see from this ratio and percentages that more pupils drive themselves to school than do teachers and other staff members. Roger's assertion is accurate for this reason.

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The committee's preference is determined by majority voting. Each committee member has their own preference ranking for the options. Using the given preferences of Rita, Sid, and Tina, we can derive a utility function representing the committee's preference. However, when Rita is replaced by Ray, the new committee's preference may not be representable by a utility function.

To represent the committee's preference with a utility function, we assign utility levels to the options based on the given preferences. Let's denote the options as A, B, C, and D. From Rita's preference (ABD > C), we can assign a higher utility to options A, B, and D compared to option C. Sid's preference (B > D > A > C) implies that B has the highest utility, followed by D, A, and then C. Tina's preference (C > B > A > D) suggests that C has the highest utility, followed by B, A, and then D. Combining these preferences, we can assign utility levels to the options: U(A) > U(B) > U(C) > U(D).

When Rita is replaced by Ray, Ray's preference (A > D >> B) introduces a change in the committee's decision. To determine the new committee's preference, we need to consider all possible pairs of options and determine the majority preference in each case. For example, for the pair (A, B), Sid prefers B, Tina prefers A, and Ray prefers A. Thus, the majority preference is A > B. Similarly, we can analyze the preferences for other pairs and determine the committee's preference. However, it is important to note that the new committee's preference may not be representable by a utility function since it might not satisfy rationality properties such as transitivity or completeness. Utility functions are typically used to represent rational preferences, and in this case, the committee's preference might not adhere to rationality assumptions.

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A) There are 12 elements in the sample space.

B) The required probability is 1/4 or 0.25.

C) Yes, the events are mutually exclusive.

Probability

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true. The probability of an event is a number between 0 and 1, where, roughly speaking, 0 indicates impossibility of the event and 1 indicates certainty

Part(A)

An experiment consists of first rolling a die and then tossing a coin.

Thus the sample space is:

(1,H), (2,H) (3,H) (4,H) (5,H), (6,H)

(1,T), (2,T) (3,T) (4,T) (5,T), (6,T)

Hence, there are 12 elements in the sample space.

Part(B) Let A be the event that either a 2, 3 or 4 is rolled first, followed by landing a head on the coin toss.

Now consider the above sample space. There are 3 possible case in which 2, 3 or 4 is rolled first, followed by landing a head on the coin toss.

i.e (2,H) (3,H) (4,H)

The required probability is: P(A)= 3/12 = 1/4 = 0.25

Hence, the required probability is 1/4 or 0.25.

Part(C)

Mutually exclusive, means that they cannot occur at the same time.

From part (B) Event A = (2,H) (3,H) (4,H)

Let B be the event that a number less than 2 is rolled, followed by landing a head on the coin toss.

Thus, the Event B = (1,H).

Therefore, Event A and B can't be occur at the same time as P(A and B)=0.

Hence, yes, the events are mutually exclusive.

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By eliminating the parameter t and evaluating the function at x = -1 we conclude that the parametric equations contains the point (x, y) = (-1, 0).

In this case we must determine if a point in rectangular format belongs to  a set formed by two parametric functions. The functions are parametric as they are based in a parameter t. A quick approach consist in reduce the number of equations by eliminating the parameter.

The first equation is represented below:

t = x/3

And the parameter is substituted in the second equation:

y = 18 · (x/3)² + 12 · (x/3) + 2

y = 2 · x² + 4 · x + 2

If we know that x = -1, then the y-value is:

y = 2 · (- 1)² + 4 · (- 1) + 2

y = 0

By eliminating the parameter t and evaluating the function at x = -1 we conclude that the parametric equations contains the point (x, y) = (-1, 0).

The statement is incomplete, the complete definition is presented below:

Which of the following is a point on the plane curve defined by the parametric equations?

x = 3 · t, y = 18 · t² + 12 · t + 2

A. (-1, 0)

B. (-3, -28)

C. (-1, 8)

D. (-3, 128)

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The \(275th\) digit after the decimal point in the repeating decimal \(0.6295\) will be \(9.\)

Decimal is one of the types of numbers, which has a whole number and the fractional part is separated by a decimal point.

It is given that \(0.6295\) is a repeating decimal.

i.e. \(0.6295\) repeats after \(4th\) digit,

So, divide \(275\) by \(4\),

We get,

   \(=\frac{275}{4}\)

We get, \(68\) and \(3\) as remainder.

So, the \(275th\) number after the decimal point will be \(3rd\) digit in \(0.6295\) after decimal.

i.e. \(275th\) number will be \(9\).

Hence, we can say that the \(275th\) digit after the decimal point in the repeating decimal \(0.6295\) will be \(9.\)

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Answer:

one combination could be 6 girls and 4 boys

The population means may be the same

So, option D is correct.

What is meant by confidence interval?

In statistics, the probability that a population parameter will fall between a set of values a predefined percentage of the time is known as the confidence interval. Analysts typically use confidence intervals that cover 95% or 99% of the expected observations while assessing data. In frequentist statistics, an estimation range for an unknown parameter is referred to as a confidence interval. The most common confidence level for computing confidence intervals is 95%, however other levels, such 90% or 99%, are also occasionally employed. The conclusion is reached that the result is statistically significant if the confidence interval eliminates the value of zero effect.

If (μ₁- μ₂=0) is included in the confidence interval, that means this two means have the same difference that is zero.

Therefore, they may be nearly same,

So, The population means may be the same

Hence, option D is correct.

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Answer:

 ∠b = 88 - 5x

Step-by-step explanation:

If a and b are complementary, then sum of two angles is 90

∠a + ∠b = 90

5x + 2 + ∠b = 90

             ∠b = 90 - 5x - 2

             ∠b = 88 - 5x