Find your mass if a scale on Earth reads 560 N when you stand on it

The given statement "after you have driven through standing water, you should apply heavy brake pedal pressure for a short distance to make sure your brakes are still working properly" is false.  

After you have driven through standing water, it is not recommended to apply heavy brake pedal pressure for a short distance. Here's why:

1. When you drive through standing water, your brakes can get wet and become less effective. This is because water can get into the brake components, such as the brake pads and rotors, causing them to become slippery.                      

2. Applying heavy brake pedal pressure immediately after driving through standing water can cause your wheels to lock up and skid. This can lead to a loss of control of your vehicle and potentially result in an accident.                          

3. Instead of applying heavy brake pedal pressure, it is advisable to lightly tap your brakes a few times after driving through standing water. This will help to remove any excess water from the brake components and restore their effectiveness.                                                                  

4. Additionally, it is important to drive at a slower speed and maintain a safe distance from other vehicles after driving through standing water. This will give your brakes more time to dry out and regain their normal functionality.                    

In conclusion, after driving through standing water, it is not recommended to apply heavy brake pedal pressure for a short distance. Instead, lightly tap your brakes a few times to remove excess water and drive at a slower speed until your brakes have dried out. This will help ensure that your brakes are working properly and maintain your safety on the road.

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False. After driving through standing water, you should not apply heavy brake pedal pressure. Instead, you should gently and lightly tap the brakes a few times to dry them out.

False. After driving through standing water, you should not apply heavy brake pedal pressure. Instead, you should gently and lightly tap the brakes a few times to dry them out. This helps to remove any excess water from the brake pads or shoes, allowing them to work effectively. Applying heavy brake pedal pressure can cause the brakes to lock up and potentially lead to a loss of control.

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The given problem involves calculating the definite integral of a function f(x) over a specific range. The function f(x) is defined differently for different values of x, and the final result of the definite integral \(1^2\)₁ f(x) dx, where x ≤ n, is -cos(n) - (-cos(1)) + 3cos(T) - 3cos(n) + infinity.

To calculate the definite integral 1²₁ f(x) dx, where x ≤ n, we need to evaluate the integral of the given function f(x) over the specified range. The function f(x) has different definitions depending on the value of x. For x ≤ n, the function is sin(x), and for x > n, the function is -3sin(x). Additionally, the function is defined as 2x for values of x greater than a certain threshold T.

To solve this problem, we need to consider the different intervals of the range separately. First, we integrate sin(x) over the interval 1 to n. The integral of sin(x) is -cos(x), so the value of this part of the integral becomes -cos(n) - (-cos(1)).

Next, we need to integrate -3sin(x) over the interval n to T. The integral of -3sin(x) is 3cos(x), so this part of the integral becomes 3cos(T) - 3cos(n).

Lastly, we integrate 2x over the interval T to infinity. The integral of 2x is \(x^2\), so this part of the integral becomes infinity.

Combining these three parts, the final result of the definite integral \(1^2\)₁ f(x) dx, where x ≤ n, is -cos(n) - (-cos(1)) + 3cos(T) - 3cos(n) + infinity.

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SWOT Analysis: Apple Inc. has a strong brand image and innovative product portfolio, but faces challenges such as high product prices and intense competition.

PESTEL Analysis: Apple Inc. is influenced by global political stability, economic conditions, changing consumer preferences, rapid technological advancements, environmental sustainability practices, and legal regulations.

Porter's Five Forces Analysis: Apple Inc. faces moderate threats of new entrants and supplier bargaining power, high buyer bargaining power and threats of substitute products, and intense competitive rivalry.

Value Chain Analysis: Apple Inc.'s value chain includes primary activities like logistics, operations, marketing, and support activities such as procurement, technology development, and human resource management.

SWOT Analysis of Apple Inc.:

PESTEL Analysis of Apple Inc.:

Porter's Five Forces Analysis of Apple Inc.:

Value Chain Analysis of Apple Inc.:

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A satellite travels at a constant speed, its shape is a circle.

An integrated receiver and transmitter of radio signals known as a transponder, a satellite is essentially a self-contained communications system that can receive signals from Earth and retransmit those signals back to Earth.

The three primary parts of a satellite are the propulsion system, which includes the rockets that move the satellite, the power system, which includes the solar panels that supply power, and the communications system, which includes the antennae and transponders that receive and retransmit signals. To enter into the proper orbit and periodically adjust its position, a satellite needs a propulsion system of its own.

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Answer:

0.00176

Explanation:

Credit to the person above.

Answer: Pharos just bossed people around. They killed anyone who refused to work. In the end the many people died and the pyramids were created.

Explanation:

Low beam headlights allow drivers to see about 160 feet (50 meters) ahead of their vehicle at night. The light beams are angled downward to prevent blinding oncoming drivers and also illuminate the road immediately ahead of the car, giving the driver enough time to react to any obstacles or hazards.

It is important to note that the distance that low beam headlights can illuminate depends on several factors, including the quality of the headlights, the condition of the lenses, and weather conditions. Poorly maintained headlights or those with cloudy lenses can significantly reduce the distance that one can see at night. Similarly, fog, rain, or snow can scatter the light and reduce visibility, making it more challenging to see distant objects. It is always advisable to drive at a safe speed and with caution, particularly in low-light conditions.

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Answer:

It helps prevents falls and supports your body. So having a strong core is beneficial to everyone because it allows your body to function properly. Improved Balance and Stability. Core exercises train the muscles in your pelvis, lower back, hips and abdomen to work together.

Answer:

2 ammeter

Explanation:

=current=charge/time

=20/10

=2

A hydraulic lift's input pressure is 1200 Pa. If the output force on the other side is 800 N, the output surface area is 0.67m^2

Given the input pressure (P1) = 1200Pa

Output force (F2) = 800N

We know that P= F/A where A is area of cross section

Let the input force be F1 and area is A1

Then by pascals law we say that:

F1/A1 = F2/A2

1200 = 800/A2 (since P1= F1/A1)

A2 = 8/12 = 0.67m^2

Hence the area of other side = 0.67m^2

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Answer:

C,B,A

Explanation:

Answer:

first one C

second one B

third one A

Explanation:

i hope you have a good day ;0

Answer:

2 m

Explanation:

The following data were obtained from the question:

Time 1 = 3 s

Time 2 = 3.5 s

Velocity = 4 m/s (constant)

Displacement =?

Next, we shall determine the change in time. This can be obtained as follow:

Time 1 = 3 s

Time 2 = 3.5 s

Change in time = 3.5 – 3

Change in time = 0.5 s

Finally, we shall determine the displacement of the bird between 3 s and 3.5 s as follow:

Velocity = 4 m/s

Time = 0.5 s

Displacement =?

Velocity = Displacement /Time

4 = Displacement /0.5

Cross multiply

Displacement = 4 × 0.5

Displacement = 2 m

Therefore, the displacement of the birth between 3 and 3.5 s is 2 m.

Answer:

what is the question?

Answer:

Explanation:

Given data:

* The distance to the Grandma house is d = 120 miles.

* The value of the speed limit is v = 60 mph.

* The time for the dinner is t = 5 p.m.

Solution:

The time taken to reach the Grandma house while moving in the speed limit is,

Substituting the known values,

The time of leaving is,

Thus, the time at which the person should leave for grandma's house is 3 p.m.

Answer:

four covalent bonds is the answer

It was discovered by Edwin Hubble that the electromagnetic spectrum changes when galaxies travel away from our galaxy. Redshift refers to this occurrence.

The distance between galaxies increases as the universe enlarges, and this causes the apparent velocity for the farther away galaxies to appear to be greater. The fact that all galaxies appear to be revolving away from us does not make the Earth or the Milky Way unique in this regard.

High-frequency EMR waves having the shortest wavelengths. High energy, only emitted during nuclear reactions. from the Big Bang, leftover energy.

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Answer:

The velocity of the wave is, v = 180,000 m/s

Explanation:

Given data,

The frequency of the wave, f = 900 Hz

The wavelength of the wave, λ = 200 m

The formula for the speed of the wave when the frequency and wavelength are known,

                               v = λ x f

Substituting the given values in the above equation,

                               v = 200 m x 900 Hz

                                v = 180000 m/s

Hence, the velocity of the wave is, v = 180,000 m/s

The value "z = 1.0" is given to a galaxy redshift, which is a measurement of how much the galaxy's light's wavelength has been distorted as it travels through the expanding cosmos.

Redshift is expressed as a fractional value "z", where z = (λ observed - λ emitted) / λ emitted. In this case, "z = 1.0" means that the observed wavelength of light from the galaxy has been stretched by a factor of 1 (i.e., the wavelength has doubled). Redshift is typically measured using spectroscopy, which involves splitting the light from the galaxy into its individual spectral lines and comparing the observed wavelengths to the wavelengths of the same spectral lines in a laboratory or a theoretical reference spectrum. By measuring the redshift of a galaxy, astronomers can determine its distance from us and its motion relative to us. The interpretation of a redshift as a measure of distance is based on the idea that the universe is expanding, and that the farther away a galaxy is from us, the faster it will be moving away from us due to the expansion of the universe. This leads to an increase in the observed wavelength of its light (i.e., redshift), which can be used to estimate the galaxy's distance.

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Answer:

d)

\({ \rm{F = kx}}\)

e)

\({ \tt{2 = (k \times 3.5)}} \\ { \tt{k = 0.571}}\)

The virtual image of the object appears to be located at the focal point.

When an object is located at a very large distance from a diverging mirror, the light rays coming from the object will be nearly parallel.

These parallel light rays will be incident on the diverging mirror at different angles, and the mirror will cause them to reflect away from each other, thus creating the illusion that the rays are diverging from a point. This point is called the virtual focus, or the focal point, of the mirror.

The focal length of a diverging mirror is defined as the distance between the mirror and its focal point. Since the image formed by a diverging mirror is always virtual, meaning it cannot be projected onto a screen, the image location is also measured from the mirror.

Thus, when an object is very far away, the image formed by a diverging mirror will always be located at a distance equal to the focal length of the mirror from the mirror itself, on the same side as the object.

This phenomenon can be explained using the ray diagram of a diverging mirror. A ray diagram is a diagram that shows the path of light rays as they pass through an optical system, such as a mirror.

In the case of a diverging mirror, the ray diagram shows that light rays coming from the object are reflected away from the mirror as if they were diverging from the focal point.

Therefore, the virtual image of the object appears to be located at the focal point.

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The horizontal x-axis represents the frequency and the vertical y-axis represents the amplitude of sound waves in a graph.

Visually, sound waves are represented as a waveform with the x-axis denoting time and the y-axis denoting amplitude. Sound waves do various tasks. On these graphs, there is one y and one x. A waveform can be used to analyse the frequency (pitch) and amplitude ('loudness' or intensity) of a sound.

The number of cycles on a periodic waveform with a repeating pattern can be used to compute frequency. The frequency and perceived pitch increase with the number of cycles per second. Hertz is typically used to express frequency (Hz). By examining a waveform's amplitude, we may determine how loud or strong a sound is as well as how much the airborne particles oscillate. Traditionally, decibels are used to express it (dB).

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A subtype discriminator is the attribute in the supertype entity that determines to which entity subtype each supertype occurrence is related. Option (a) is correct.

The entity supertype is a concept in a database schema that represents a group of entities that share the same attributes or characteristics. A subtype is a subset of entities that possess specific distinguishing characteristics or attributes that are not present in the supertype. A subtype will have at least one different attribute or relationship, apart from all of the characteristics that the supertype contains.

A subtype is a refinement of a supertype entity. An entity type, known as the supertype, has multiple subtypes that can be derived from it. Subtypes may be exclusive (disjoint) or nonexclusive (overlapping). Exclusive subtypes contain nonoverlapping entities, whereas nonexclusive subtypes have overlapping entities.

Supertype and subtype entities can be used in conjunction with the entity-relationship model. A subtype is a distinct entity that has one or more attributes that are specific to it but not present in its supertype. The subtype of an entity is said to be derived from its supertype by extension or specialization.

Therefore, option (a) is correct.

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Answer:

Explanation:

p.E=mgh

P.E=0.124*10*11.2

p.E=13.888j

The repulsion force between the two Arkon nuclei when the distance between them is 1x10⁻³μm is approximately 7.4x10⁻¹⁴N. The correct option is d. 7.4x10⁻¹⁴N.

The formula for repulsion force between two Arkon nuclei when the distance between them is given by Coulomb's law. Coulomb's law states that the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, the law can be expressed as F=kq1q2/r²,

Where F is the force, q1 and q2 are the charges, r is the distance between the charges, and k is the Coulomb's constant.The electric charge of one electron is 1.6x10⁻¹⁹C.

Therefore, the charge of the Arkon nucleus with 18 protons = 18(1.6x10⁻¹⁹) C = 2.88x10⁻₈⁸ CThe force between the two Arkon nuclei can be calculated using the formula above.

F=kq1q2/r²

Substituting the values we have;F = (9x10⁹)(2.88x10⁻¹⁸ C)2/(1x10⁻³ m)2F ≈ 7.4x10⁻¹⁴ N. Therefore, the repulsion force between the two Arkon nuclei when the distance between them is 1x10-3μm is approximately 7.4x10⁻¹⁴N. The correct option is d. 7.4x10⁻¹⁴N.

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The equivalent resistance between points A and B in the diagram is 22 Ω

We shall begin by obtaining the equivalent resistance in parallel (i,e the three 6 Ω resistor). Details below:

1/Rₜ = 1/R₁ + 1/R₂ + 1/R₃

1/Rₜ = 1/6 + 1/6 + 1/6

1/Rₜ = 3/6

1/Rₜ = 1/2

Rₜ = 2 Ω

Finally, we shall determine the equivalent resistance between A and B (i.e series arrangement). Details below:

R = R₁ + R₂ + R₃ + R₄ + R₅ + R₆ + R₇ + R₈ + R₉ + R₁₀ + R₁₁

R = 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2

R = 22Ω

Thus, we can conclude that the equivalent resistance is 22 Ω

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Answer:

450N

Explanation:

Impulse = mv    --->   180kgm/s = (0.5kg)v

v = 360 m/s

Acceleration = v/t    --->   a = (360 m/s)/(0.4s) = 900 m/s^2

Force = ma   --->   F = (0.5kg)(900 m/s^2) = 450N

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In the Battle of Waterloo, the angularity of the figures and rough paint surface contributed to the save nature of the scene.  

Performance art has nearly always been used as a means of subverting the norms of conventional visual arts like painting and sculpture. Today, there are many different ways for artists to interact with and work with audiences. By allowing people to observe their creative process, they cede some degree of control over their output and place their faith in chance and the viewer-turned-participant.

And the artwork itself turns into a two-way conversation.  Environmental art not only offers a place for the expression of the beauty of the natural world, but it also generates a space for the dissemination of critical information and the arousal of public consciousness of ecological and environmental problems like global warming and climate change.

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Correct Question:

In ____, the angularity of the figures and rough paint surface contributed to the save nature of the scene.

If the separation distance is doubled, then the electric field decreases by a factor of 4.

We know that the electric field strength is known to depend on the magnitude of the charge and the distance of separation. We know that the electric field refers to the region in which the influence of a charge is felt. Recall that a charge is a specie that is positively or negatively charged. The charge on a specie must always be shown by its sign.

We know that the electric field is the region in space where the influence of a charge can be felt. If a charge is placed in the vicinity of another charge, the second charge would experience a force due to the presence of the first charge. This is because the second charge was brought into the electric field of the first charge.

Thus we know that;

E = Kq/r^2

Where;

E = electric field strength

q = magnitude of charge

r = distance of separation

Now;

E = 9.0* 10^9 * 3.052 * 10^-6/(8.22 * 10^-2)^2

E = 4 N/C

Given that the electric filed strength is inversely proportional to the distance of separation, when the distance between the charges is doubled, the electric field decreases by a factor of 4.

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