Flaked soybeans are to be leached with hexane to remove the soybean oil in a continuous countercurrent stagewise operation. Experiments show that the flakes retain solution to an extent depending upon the oil content of the solution as follows:
Kg oil/kg solution retained 0 0.20 0.30
Kg sol'n retained/kg insoluble solid 0.58 0.66 0.70
The soybean flakes enter containing 20% oil (and no hexane) and are to be leached to 0.5% oil (on a solvent-free basis). The solvent is fed at 1.0 kg fresh solvent per kilogram flakes (including oil), and the fresh solvent is free of oil. How many stages are required? State all of your assumptions clearly. Determine graphically and using Excel.

The balanced reaction equation is;

\(2LiI + Pb(NO_{3} )_{2} --- > 2LiNO_{3} + PbI_{2}\) as we can see from the equation that is written here.

In the balancing of the reaction equation, we have to make sure that the number of the reacting atoms on the reactant and the product side are the same for each of the elements.

On both sides of the equation, tally the atoms of each element. First, balance the polyatomic ion or the most complicated molecule. One element at a time, balance the other atoms of the reactants and products. Make sure that every atom is now evenly distributed on both sides of the equation.

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Answer:

the hydrogen and the oxygen are the reactants while the H20(water) formed is the product

Mohr's method is a titration technique used to determine the amount of chloride present in a sample.

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The reason a mole of carbon dioxide (CO2) extracted from air weighs slightly more than 44.01 grams is due to the presence of the isotopes of carbon, specifically carbon-13 (13C) and carbon-14 (14C), which have slightly higher atomic masses than carbon-12 (12C).

In nature, carbon exists as a mixture of these isotopes, with carbon-12 being the most abundant. The atomic mass of carbon reported on the periodic table is an average of the masses of these isotopes, taking into account their relative abundances. Since carbon-13 and carbon-14 have higher masses, they contribute to the overall molecular weight of carbon dioxide.

When carbon dioxide is extracted from air, it contains a small proportion of carbon-13 and carbon-14 isotopes. These isotopes, although present in much smaller quantities compared to carbon-12, contribute to a slightly higher molecular weight for a mole of carbon dioxide. This is why the actual weight of a mole of extracted carbon dioxide is slightly greater than the calculated molecular weight of 44.01 grams.

It is worth noting that the difference in weight due to the isotopic composition is relatively small and does not significantly impact most practical applications. However, for precise measurements or certain scientific studies, isotopic composition and its effect on molecular weight may need to be considered.

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Answer:

1.7 mol/dm3

Explanation:

working out in the image

To determine the number of moles of hydrogen needed to crack one mole of the long saturated hydrocarbon chain (C40H82), we can analyze the reactants and products involved in the cracking reaction.

The cracking reaction is given as: C40H82 -> 3 C8H18 + n C2H6. From the equation, we can see that one mole of the long hydrocarbon chain (C40H82) produces three moles of octane (C8H18) and n moles of ethane (C2H6). Since the cracking process involves breaking the carbon-carbon bonds and forming new carbon-hydrogen bonds, the number of hydrogen atoms in the products should remain the same as in the reactant.

The long hydrocarbon chain (C40H82) contains 82 hydrogen atoms, and the products, 3 moles of octane (C8H18), contain (3 moles) * (18 hydrogen atoms/mole) = 54 hydrogen atoms. Therefore, the number of moles of hydrogen needed for cracking one mole of the long hydrocarbon chain can be calculated as: Number of moles of hydrogen = 82 - 54 = 28 moles. Hence, 28 moles of hydrogen are required to crack one mole of the long saturated hydrocarbon chain (C40H82).

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The reaction equation is:

HI(aq) + KOH(aq) → KI(aq) + H2O

1 mol HI reacts with 1 mol KOH

In your problem you have:

Mol HI in 10 mL of 1M solution = 10mL/ 1000 mL/L * 1 mol /L = 0.01 mol HI

Mol KOH in 5 mL of 1 M solution = 5 mL / 1000 mL/L * 1 mol /L = 0.005 mol HI

The 0.005 mol of KOH will neutralise 0.005 mol of HI - leaving 0.005 mol HI unreacted in 15 mL solution

This solution will be acidic

I guess that that answers your question - But you may be interested in calculating the pH of the solution

Have a great day!

Temperature stays the same during state of matter change. After plotting the graph of temperature vs time and the curve is outlined, the moment the graph plateaus read the temperature that is constant(repeatedly occurs).

From the points given in the table of value, am sure the melting point is 78°C.

All the best!

Answer:

When sleeping the energy exhibited is Potential energy. When I wake up and I’m preparing for the day I use kinetic energy which is the energy exhibited during motion.

Eating before leaving the house means I used chemical energy for replenishment of nutrients to aid the performance of more activities for the day. The food eaten and the physical activities also give rise to thermal energy which is why we sweat.

Explanation:

Metal is a better conductor than wood, so a metal spoon could burn

Paul's hand.  So, Sue is incorrect. The metal being good conductor of heat, heats up faster than wood spoon and thus, could burn Paul's hand.

Answer:

Neptune and Saturn although Neptune isn't on there so just Saturn.

hope it'll help ya out!

Answer:

B.A Solution with a pH greater than 7

Answer:

A

Explanation:

A "Basic solution" Or a base solution is a solution that has less than a level 7 of pH levels

So the answer would be A

Scientific theories are testable. A theory may be changed as a result of new lines of evidence that change their assumptions.

A Scientific theory is a well sustained explanation about a given question of the real world that is based on testable (i.e., verifiable through experimentation and or observation) information that was obtained by using the scientific method.

Therefore, with this data, we can see that Scientific theories are testable because they can be proved or refuted by experimentation and or observational procedures, which are fundamental parts of the scientific method.

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A gas occupies 900.0 mL at a temperature of 27.0°C. What is the volume if the temperature is 105°C ?

Explanation:

\( \frac{V _{1} }{T _{1}} = \frac{V _{2} }{T _{2}} \\ \frac{(900)}{(27 + 273)} = \frac{V _{2}}{(105 + 273)} \\ V _{2} = \frac{340200}{300} \\ V _{2} = 1134 \: ml\)

A scientific law is different from a scientific theory because it describes something in nature without attempting to explain it, this statement is true.

A scientific law foretells the outcomes of particular beginning circumstances. It may tell you what color hair your unborn kid would have or how far a baseball will go when fired at a specific angle.In contrast, a theory seeks to offer the best plausible justification for why events take place the way they do.

A scientific law often describes an observable phenomena. It doesn't explain the phenomenon's existence or its origins. A scientific theory is the explanation for a phenomena. It is untrue that with enough study, hypotheses become laws.

Thus, a scientific law is different from a scientific theory because it describes something in nature without attempting to explain it, this statement is true.

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Answer:

Explanation:

NaClO3

Atomic masses:

Na =23

Cl=35.5

O=16

Molar mass=(23)+(35.5)+(3×16) =106.5g/mol

Both statements are correct. The pH calculation at the equivalence point of a weak acid titrated with a strong base is based on the reaction of the conjugate base A- with water.

To calculate the pH at various points during the titration of a weak acid against a strong base, you should consider the following statements: 1. At the equivalence point, the pH calculation is based on the reaction of the conjugate base A- with H2O. 2. The initial [H3O+] is calculated from [HA] and Ka.

This is because at the equivalence point, all of the weak acid has reacted with the strong base to form its conjugate base A-. This conjugate base can react with water to produce OH- ions and the weak acid HA.

The resulting OH- ions increase the pH of the solution. Before the equivalence point, the initial [H3O+] can be calculated using the concentration of the weak acid HA and its acid dissociation constant Ka.

This is because the weak acid partially dissociates in water to produce H3O+ ions and its conjugate base A-. The Ka value represents the equilibrium constant for this dissociation reaction.

By using the Ka value and the initial concentration of HA, the concentration of H3O+ ions can be calculated using the equation for the acid dissociation constant.

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The molarity of the calcium chloride solution is 2.408 M. To calculate the molarity of an aqueous solution of calcium chloride, we need to first determine the mass of calcium chloride present in 1 liter of the solution, using the given density and percentage by mass.

Let's assume we have 1 liter of the solution:

Mass of solution = volume x density = 1 L x 1.20 g/mL = 1200 g

Mass of calcium chloride in the solution = 22.3% of 1200 g = 267.6 g

Now we can calculate the molarity of the solution using the molar mass of calcium chloride, which is 110.98 g/mol:

Molarity = moles of solute / volume of solution in liters

moles of calcium chloride = mass / molar mass = 267.6 g / 110.98 g/mol = 2.408 mol

volume of solution = 1 L

Molarity = 2.408 mol / 1 L = 2.408 M

Therefore, the molarity of the calcium chloride solution is 2.408 M.

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Answer:

Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons. Thomson's plum pudding model of the atom had negatively-charged electrons embedded within a positively-charged "soup."

Explanation:

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Answer:

The materials are opaque or crystalline from a client to the orientation and type of union between their atoms, forming two types of structures.

These two structures can be crystalline or amorphous.

In the case of being crystalline, these unions do not allow light to pass through the medium of the object or body of said compound, making it totally refract and giving the appearance of OPAQUE.

On the other hand, in those compounds that we call amorphous, the atoms are located in a different way that makes light pass through them, without absorbing or identifying any light beam, so they look transparent.

Explanation:

Example: A glass cup has an amorphous structure, while a porcelain or porcelain plate has a crystalline structure.

Answer:

To dissolve an ionic compound

Explanation:

the water molecules must be able to stabilize the ions that result from breaking the ionic bond. They do this by hydrating the ions. Water is a polar molecule. ... When you place an ionic substance in water, the water molecules attract the positive and negative ions from the crystal.

Answer:

What is the charge on the barium ion and what is the charge of the hydroxide ion.

Explanation:

To get the correct formula they have to add to zero over all.

The grams of SO₂ that would be dissolved in 100 g of 40 degree water to make a saturated solution can be calculated by making solubility curve.

Mass is the quantity of matter of a physical body.

If you want to calculate the mass of Sulfur dioxide in 100 g of 40 degree, you have to make a solution curve.

With the increase in temperature, the solubility increases as well

Thus, the grams of SO₂ that would be dissolved in 100 g of 40 degree water to make a saturated solution can be calculated by making a solubility curve.

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The composition of the vapor and liquid phases is 0.37 and  the operating temperature is 98 degree celcius.

The term subcooling( also called undercooling) refers to a liquid being at a temperature below its normal boiling point. For illustration, water boils at 373 K; at room temperature( 293 K) the water is nominated" subcooled".

A subcooled liquid is the accessible state in which, say, refrigerants may suffer the remaining stages of a refrigeration cycle. typically, a refrigeration system has a subcooling stage, allowing technicians to be certain that the quality, in which the refrigerant reaches the coming step on the cycle, is the asked one.

Mole fraction benzene in liquid is 0.14 and mole fraction fraction toluene in liquid as 0.86

The mole fraction of benzene in liquid and vapor at 100 is 0.24 and 0.46

0.30 x 1 mol = 0.46 x 0.24

Total mole balance:

n = nv + n1

1 = nv + n1

n1 = 0.30x1 - 0.46x1/0.24 - 0.46

n1 = 0.73 mol

So nv = 0.27 mol

nv/n1 = 0.27/0.73 = 0.37

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Approximately 148.59 grams of carbon dioxide could be made.The remaining reactant, since \(O_2\)is the limiting reactant, all the CO will not be completely consumed. There would be no CO leftover as it is completely consumed in the reaction.

To determine the grams of carbon dioxide produced, we need to identify the limiting reactant first. The balanced chemical equation for the reaction is:

2 CO +\(O_2\) -> 2 \(CO_2\)

To find the limiting reactant, we compare the number of moles of each reactant and determine which one is present in a lower amount relative to the stoichiometry of the reaction.

First, we convert the given volumes of gases to moles using the ideal gas law equation:

n = PV / RT

where:

n = number of moles

P = pressure

V = volume

R = ideal gas constant

T = temperature

Assuming the reaction takes place at standard temperature and pressure (STP), which is 273.15 K and 1 atm, we can use the values to convert the volumes to moles:

For carbon monoxide (CO):

n(CO) = (75.3 L) / (22.414 L/mol) = 3.36 moles

For oxygen (O2):

n(O2) = (38.0 L) / (22.414 L/mol) = 1.69 moles

According to the balanced equation, the stoichiometry of the reaction is 2:1 for CO to \(O_2\)This means that for every 2 moles of CO, we need 1 mole of \(O_2\). In this case, the ratio of moles is 3.36:1.69, which shows an excess of CO.

To find the limiting reactant, we compare the mole ratio to the stoichiometry ratio. Since there is a surplus of CO, it is the excess reactant, and\(O_2\)is the limiting reactant.

To determine the amount of carbon dioxide produced, we use the stoichiometry of the reaction. From the balanced equation, we know that for every 2 moles of CO, 2 moles of CO2 are produced.

Since\(O_2\) is the limiting reactant, we use its moles to calculate the moles of \(Co_2\)produced:

n(\(CO_2\)) = 2 * n(\(O_2\)) = 2 * 1.69 moles = 3.38 moles

Finally, we convert the moles of\(CO_2\) to grams using the molar mass of carbon dioxide, which is 44.01 g/mol:

mass(\(CO_2\)) = n(\(CO_2\)) * molar mass(\(CO_2\) = 3.38 moles * 44.01 g/mol ≈ 148.59 grams

Therefore, approximately 148.59 grams of carbon dioxide could be made.

As for the remaining reactant, since \(O_2\)s the limiting reactant, all the CO will not be completely consumed. To determine the amount of CO leftover, we subtract the moles of CO used from the initial moles of CO:

Remaining moles of CO = Initial moles of CO - Moles of CO used

Remaining moles of CO = 3.36 moles - 2 * 1.69 moles ≈ 0 moles

Thus, there would be no CO leftover as it is completely consumed in the reaction.

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Equilibrium is a state in a chemical reaction where the rate of the forward reaction is equal to the rate of the reverse reaction, resulting in no net change in the concentrations of reactants and products. It is represented by a double arrow (⇌) in chemical equations. In the given equation: H₂O (g) + CO (g) ⇌ H₂(g) + CO₂(g) + 42 KJ

To shift the equilibrium to the right, one or more of the following could occur:

Increasing the concentration of H₂ or CO₂

Decreasing the concentration of H₂O or CO

Increasing the pressure

Removing some of the products (H₂ and CO₂)

Decreasing the temperature

To shift the equilibrium to the left, one or more of the following could occur:

Decreasing the concentration of H₂ or CO₂

Decreasing the pressure

Increasing the temperature

If pressure is increased, the equilibrium will shift in the direction that produces fewer moles of gas. In this case, since there are fewer moles of gas on the right side of the equation (H₂ and CO₂), the equilibrium will shift to the right. If heat is added, the equilibrium will shift in the endothermic direction to absorb the additional heat. In this case, the forward reaction is endothermic (42 KJ on the right side), so the equilibrium will shift to the right to consume the added heat.

If CO is added, the equilibrium will shift to the right to consume the additional CO.The concentration of H₂O and CO₂ will increase, while the concentrations of H₂ and CO will decrease until a new equilibrium is reached.

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A dihalide in which the halogens are attached on adjacent carbons is called a vicinal dihalide.

Dihalides are organic compounds that contain two halogen atoms in a molecule. In particular, they are compounds containing two halogen atoms in the same molecule. They are also known as geminal dihalides because the two halogens are on the same carbon atom. Some examples of dihalides include ethylene dichloride, ethylene dibromide, and carbon tetrachloride. The halogens that make up dihalides are fluorine, chlorine, bromine, and iodine.

Vicinal dihalides: A vicinal dihalide is a type of organic compound with the molecular formula CnH2n-2X2, where X is a halogen atom and n is an integer. It is a compound with two halogen atoms attached to adjacent carbons. As a result, it is known as a vicinal dihalide. This type of compound is also known as 1,2-dihalides, as the halogen atoms are on the first and second carbons. Examples of vicinal dihalides include 1,2-dichloroethane, 1,2-dibromobutane, and 1,2-difluoroethylene. Therefore, option A is the correct answer.

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The atomic number of an element represents the number of protons in an atom of that element. Since the isotope given is Mn-59, the atomic number of manganese (Mn) remains the same, which is 25.

If an atom of Mn-59 has a charge of +5, it means that it has lost 5 electrons. The number of protons in an atom is equal to its atomic number, and the number of electrons is equal to the number of protons in a neutral atom. Therefore, if the atom has lost 5 electrons, the number of protons remains the same, which is 25.

So, an atom of Mn-59 with a charge of +5 has 25 protons.

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