for a constant a > 0, random variables x and y have joint pdf fx,y (x,y) = { 1 a2if 0 < x,y ≤a, 0 otherwise. let w = max (x y , y x ). then find the range, cdf and pdf of w.
Answers
To find the range, CDF, and PDF of the random variable W = max(X,Y), where X and Y are random variables with the given joint PDF, we can proceed as follows:
1. Range of W:
The maximum value of two variables X and Y can be at most the maximum of their individual values. Since both X and Y have a range from 0 to a, the range of W will also be from 0 to a.
2. CDF of W:
To find the CDF of W, we need to calculate the probability that W is less than or equal to a given value w, P(W ≤ w).
We have two cases to consider:
a) When 0 ≤ w ≤ a:
P(W ≤ w) = P(max(X,Y) ≤ w)
Since W is the maximum of X and Y, it means both X and Y must be less than or equal to w. Therefore, the joint probability of X and Y being less than or equal to w is given by:
P(X ≤ w, Y ≤ w) = P(X ≤ w) * P(Y ≤ w)
Using the joint PDF fx,y(x,y) =\(1/(a^2)\) for 0 < x,y ≤ a, and 0
otherwise, we can evaluate the probabilities:
P(X ≤ w) = P(Y ≤ w)
= ∫[0,w]∫[0,w] (1/(a^2)) dy dx
Integrating, we get:
P(X ≤ w) = P(Y ≤ w)
= \(w^2 / a^2\)
Therefore, the CDF of W for 0 ≤ w ≤ a is given by:
F(w) = P(W ≤ w)
= \((w / a)^2\)
b) When w > a:
For w > a, P(W ≤ w)
= P(X ≤ w, Y ≤ w)
= 1, as both X and Y are always less than or equal to a.
Therefore, the CDF of W for w > a is given by:
F(w) = P(W ≤ w) = 1
3. PDF of W:
To find the PDF of W, we differentiate the CDF with respect to w.
a) When 0 ≤ w ≤ a:
F(w) =\((w / a)^2\)
Differentiating both sides with respect to w, we get:
f(w) =\(d/dw [(w / a)^2\)]
= \(2w / (a^2)\)
b) When w > a:
F(w) = 1
Since the CDF is constant, the PDF will be zero for w > a.
Therefore, the PDF of W is given by:
f(w) =\(2w / (a^2)\) for 0 ≤ w ≤ a
0 otherwise
To summarize:
- The range of W is from 0 to a.
- The CDF of W is given by F(w) =\((w / a)^2\) for 0 ≤ w ≤ a,
and F(w) = 1 for w > a.
- The PDF of W is given by f(w) = \(2w / (a^2)\) for 0 ≤ w ≤ a,
and f(w) = 0 otherwise.
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Related Questions
This is due tonight please help!
Answers
D. 49/9 . or in simplest form 5 4/9 . or in decimal form 5.4
What is the lowest common denominator for these fractions?
3/5 and 1/10
15
5
10
Answers
Answer:
10
Multiply both parameters by the least common multiple of each.\(\frac{3*2}{5 * 2} = \frac{6}{10}\)
\(\frac{1*1}{10*1} = \frac{1}{10}\)
The lowest denominator cannot be 5, because that would mean you would have to reduce 1/10, and you cannot since 1/10 is a unit fraction, meaning it has a numerator of 1. However, 3/5 in that scenario would remain the same, since it already has a denominator of 5, but 10 does not have both parameters divisible by 5, therefore, eliminate option B.It is also not A. because A. is too high, option A. would actually be the highest denominator you can go for in this situation, which we are not going for. We are going for the lowest denominator logically possible.________________________________________________________
With that information, the correct answer is option C, 10
________________________________________________________
What have we learned?We learned how to find the least common denominator of fractions whose parameters are not the same.
Questions related to this topic? Ask me in the comments box.
Pete has a fever. His temperature rose from 98.6 degrees
to 101.1 degrees. How much did his temperature rise?
Answers
Answer:
2.5
Step-by-step explanation:
101.1 - 98.6 = 2.5
(1 point) Consider a window the shape of which is a rectangle of height h surmounted by a triangle having a height T that is 1.5 times the width w of the rectangle (as shown in the figure below).
Window W If the cross-sectional area is A, determine the dimensions of the window which minimize the perimeter.
h=
w =
Answers
The dimensions of the window that minimize the perimeter are h = 1.40625w and T = 1.5w.
Given that the window is in the shape of a rectangle of height h surmounted by a triangle having a height T that is 1.5 times the width w of the rectangle.
Let the width of the rectangle be ‘w’.We have to find the height of the rectangle ‘h’ and the width of the rectangle ‘w’ that minimize the perimeter of the window.
Using the given diagram, the height of the rectangle is h and the base of the triangle is 1.5w, therefore the height of the triangle is 1.5w/2 = 0.75w.
Area of the rectangle = hw and area of the triangle = 0.5 (1.5w) × 0.75w = 0.5625w²
The total area A is given by A = hw + 0.5625w² = w(h+0.5625w) …….(1)
Let the perimeter of the window be P. Then P = 2l + 2w + T …….(2)
Substitute T = 1.5w in (2) to get, P = 2l + 4.5w + 2h …….(3)
Solve (1) for h to get, h = (A/w) – 0.5625w …….(4)
Substitute (4) into (3) to get, P = 2l + 4.5w + 2((A/w) – 0.5625w) …….(5)
Differentiating (5) w.r.t ‘w’ and equating to zero to get the minimum value,
∂P/∂w = 4.5 – 2A/w² + 0.5625 = 0 ⇒ 2A/w² = 4.5 – 0.5625 = 3.9375 ⇒ A/w² = 1.96875
From (1), A = w(h+0.5625w)
Substitute A/w² = 1.96875 in the above equation to get,
1.96875w² = w(h+0.5625w) ⇒ h = 1.96875w – 0.5625w = 1.40625w
Therefore the dimensions of the window that minimize the perimeter are h = 1.40625w and T = 1.5w.
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Suppose that e and f are events in a sample space and p(e)=2∕3, p(f)=3∕4, and p(f∣e)=5∕8. find p(e∣f)
Answers
On solving the provided question we cans ay that - probability, using Bayes' Theorem, \(p(e/f) = 5/9.\)
What is probability?A probability is a numerical representation of the possibility or probability that a specific event will take place. Probabilities can alternatively be stated as percentages ranging from 0% to 100%, or as percentages from 0 to 1. the likelihood that a given occurrence will take place. (2): The proportion of the number of outcomes in an exhaustive set of equally likely options that result in a certain event to all conceivable outcomes. The probability that something will occur is the foundation for it. The foundation of theoretical probability is the justification of probability. For instance, the theoretical likelihood of receiving heads while tossing a coin is 1/2.
The equation to obtain a probability
\(P(A|B) = P(A) * P(B|A) / P(A)\)
Now, as
\(p(e|f) = (2/3 * 5/8)/3/4\\p(e|f) = 2/3 * 5/8 * 4/3\\p(e|f) = 5/9.\\\)
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The relationship between temperature in degrees Fahrenheit and degrees Celsius is shown in the graph below.What is the meaning of the y-intercept
Answers
The y-intercept of the graph represents the Temperature in degrees Celsius when the temperature in degrees Fahrenheit is zero, which is approximately -17.8 degrees Celsius.
The y-intercept of a graph represents the value of the dependent variable when the independent variable is zero. In this case, the y-intercept of the graph represents the temperature in degrees Celsius when the temperature in degrees Fahrenheit is zero.
Looking at the graph, we can see that the y-intercept occurs at the point where the line intersects the y-axis. The y-axis represents the temperature in degrees Celsius, so the y-intercept represents the temperature in degrees Celsius when the temperature in degrees Fahrenheit is zero.
To find the y-intercept, we can look for the point where the line intersects the y-axis. From the graph, we can see that the y-intercept occurs at the point (0, -17.8). This means that when the temperature in degrees Fahrenheit is zero, the temperature in degrees Celsius is -17.8 degrees.
The y-intercept is also known as the Celsius equivalent of absolute zero. Absolute zero is the theoretical temperature at which all matter would have zero thermal energy. It is equivalent to -273.15 degrees Celsius. The fact that the y-intercept of the graph is approximately -17.8 degrees Celsius means that the Celsius scale is offset from the Fahrenheit scale by approximately 255.35 degrees (the difference between -273.15 and -17.8). This is because the Fahrenheit scale is based on a different reference point than the Celsius scale.
the y-intercept of the graph represents the temperature in degrees Celsius when the temperature in degrees Fahrenheit is zero, which is approximately -17.8 degrees Celsius.
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A ladder of length 8m rests against a wall so that the angle bsetween the ladder and wall is 45 degree .How far is the base of the ladder from the wall?
Answers
Explanation: Use the 45-45-90 theorem to solve.
45 45 90
s s s√2
8√2 8√2 8
Find the measures of HQE and AQG
Answers
Answer:
HQE= 42
AQG= 21
Step-by-step explanation:
90+3y+27=180
117+3y=180
3y=63
y=21
I need help pleaseee
Answers
Answer: 1/10th
Step-by-step explanation:
20 different lengths, 2 are 21.5 = 2/20 reduce to 1/10 so 10%
A box contains 18 green marbles and 8 white marbles. If the first marble chosen was a white marble, what is the probability of choosing, without replacement, another white marble?
Answers
Answer:
7/25
Step-by-step explanation:
Original contents of the box:
18 green marbles
8 white marbles
Contents of the box after drawing 1 white marble:
18 green marbles
7 white marbles
Total: 25 marbles
p(white) = (number of white marbles)/(total number of marbles)
p(white) = 7/25
I cut an 8.64 meter length of string into 6 equal parts. How long was each part of
string? *
Answers
Answer:
1.44m
Step-by-step explanation:
:p
what is the order from least toe greatest with the numbers 0.75,0.3215,2/8,9/16
Answers
Answer:2/8, 0.3215, 9/16, 0.75
Step-by-step explanation:
2/8 = 0.25 0.3215 is higher then 9/16 =0.5625 next is 0.75
Beverly's average mark for nine examination papers was 89.5. How many marks did she score altogether?
Answers
Answer:
805.5 out of 900
Step-by-step explanation:
A test is out of 100 and because there are 9 tests: 9 x 100 which equals 900.
To get the average we add up each test mark and divide by the number of tests. The same can be applied here but reversed. So because there were 9 tests we can multiply 89.5 by 9 which gives us 805.5. Beverly scored 805.5 marks out of 900 which makes her average 89.5% for 9 tests.
For every two-dimensional set C contained in R^2 for which the integral exists, let Q(C)=∬c(x^2+y^2dxdy)
If C1={(x,y) : −1 ≤ x ≤ 1, −1 ≤ y ≤ 1} C2 ={(x,y):−1≤x≤1,−1≤y≤1} and C3 = {(x,y):x^2 + y^2 ≤1}, find Q (C1), Q(C2), Q (C3)
Answers
The values of Q(C1), Q(C2), and Q(C3) are 4, 4, and π, respectively.
The concept of the integral is a fundamental part of calculus and it is used to calculate the area under a curve or the volume of a 3-dimensional object. In this context, we will be exploring the integral of a two-dimensional set in the R^2 plane.
For every two-dimensional set C contained in R^2 for which the integral exists, the function Q(C) is defined as the double integral of the function (x^2 + y^2) over the set C. The double integral is a mathematical tool for finding the total volume under a surface.
Let's consider the three sets C1, C2, and C3 and find Q(C1), Q(C2), and Q(C3).
C1={(x,y) : −1 ≤ x ≤ 1, −1 ≤ y ≤ 1}
Q(C1) = ∬C1 (x^2 + y^2) dxdy = ∫^1_{-1}∫^1_{-1} (x^2 + y^2) dxdy = ∫^1_{-1} [(x^2 + y^2)/2]^1_{-1} dx = 4.
C2 ={(x,y):−1≤x≤1,−1≤y≤1}
Q(C2) = Q(C1) = 4.
C3 = {(x,y):x^2 + y^2 ≤1}
Q(C3) = ∬C3 (x^2 + y^2) dxdy = π.
In conclusion, the values of Q(C1), Q(C2), and Q(C3) are 4, 4, and π, respectively.
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assume that the probability of rain tomorrow is 0.20. what is the probability that the system will function tomorrow?
Answers
The probability that the system will function tomorrow is 0.2495 or 24.95%.
To find the probability that the system will function tomorrow, we need to find the probability that at least 4 out of the 6 components will function.
On a rainy day, the probability of 4 components functioning is given by:
P(rainy day and 4 components functioning) = C(6, 4) × (0.5)⁴ × (0.5)² = 15 × 0.0625 × 0.25 = 0.2344
On a non-rainy day, the probability of 4 components functioning is given by:
P(non-rainy day and 4 components functioning) = C(6, 4) × (0.8)⁴ × (0.2)² = 15 × 0.4096 × 0.04 = 0.2534
Now we can find the overall probability of the system functioning tomorrow by using the law of total probability:
P(system functioning tomorrow) = P(rainy day and 4 components functioning) × P(rain) + P(non-rainy day and 4 components functioning) × P(non-rain)
= 0.2344 × 0.20 + 0.2534 × 0.80
= 0.0468 + 0.2027
= 0.2495
Therefore, the probability that the system will function tomorrow is 0.2495 or 24.95%.
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--The given question is incomplete; the complete question is
"A k out of n system is one in which there is a group of n components, and the system will function if at least k of the components function. For a certain 4 out of 6 systems, assume that on a rainy day, each component has a probability of 0.5 of functioning and that on a non-rainy day, each component has a probability of 0.8 of functioning.
Assume that the probability of rain tomorrow is 0.20. What is the probability that the system will function tomorrow?"--
How far west has the sailboat traveled in 26 min ? A sailboat runs before the wind with a constant Express your answer using two significant figures. speed of 3.8 m/s in a direction 37
∘
north of wost You may want to review (Pages 89 - 92) Part B How far north has the salboat traveled in 26 min ? Express your answer using two significant figures.
Answers
The sailboat has traveled approximately 1.6 km west in 26 min, and approximately 1.6 km north in the same time period.
To determine the distance traveled in each direction, we can use the given constant speed and the time of 26 min.
For the westward distance, we can use the formula: distance = speed × time.
Distance west = (3.8 m/s) × (26 min × 60 s/min) = 5928 m = 5.93 km ≈ 1.6 km (rounded to two significant figures).
Therefore, the sailboat has traveled approximately 1.6 km west in 26 min.
For the northward distance, we can use the same formula.
Distance north = (3.8 m/s) × (26 min × 60 s/min) = 5928 m = 5.93 km ≈ 1.6 km (rounded to two significant figures).
Therefore, the sailboat has traveled approximately 1.6 km north in 26 min.
Both distances are the same because the sailboat is running before the wind with a constant speed. The direction of the wind does not affect the distances traveled in the westward and northward directions.
In summary, the sailboat has traveled approximately 1.6 km west and approximately 1.6 km north in 26 min.
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Solve the equation. 8,000g = 48,000
60
600
6
40,000
Answers
Answer:
6 or C
Step-by-step explanation:
Answer:
60=460
600=4600
6=46
40000=80000
A 2-column table with 6 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2. The second column is labeled f of x with entries negative 16, negative 1, 2, negative 1, negative 4, negative 1.
Analyze the table of values for the continuous function, f(x), to complete the statements.
A local maximum occurs over the interval
.
A local minimum occurs over the interval
.
Answers
Answer:
what is the place value of the 5 in this number 3.659
Answer:
Step-by-step explanation:
1. 1,0
2. -1,2
Ast week, Shelly rode her bike a total of 30 miles over a three-day period. On the second day, she rode 4 5 the distance she rode on the first day. On the third day, she rode 3 2 the distance she rode on the second day. How many miles did Shelly ride on each day? Select your answers from the drop-down lists. On the first day, Shelly rode miles. On the second day, Shelly rode miles. On the third day, Shelly rode miles.
Answers
Answer: On the first day, Shelly rode 10 miles on first day.
On the second day, Shelly rode 8 miles.
On the third day, Shelly rode 12 miles.
Step-by-step explanation:
Let x = distance rod eon first day.
Shelly rode her bike a total of 30 miles over a three-day period.
Then as per given,
Distance rode on second day = \(\dfrac45x\)
Distance rode on third day \(=\dfrac32\times\text{ Distance rode on second day}\)
\(=\dfrac32\times\dfrac45x=\dfrac{6}{5}x\)
Total distance rode = \(x+\dfrac45 x+\dfrac65x=30\)
\(\Rightarrow\ \dfrac{5x+4x+6x}{5}=30\\\\\Rightarrow\ \dfrac{15x}{5}=30\\\\\Rightarrow\ 3x=30\\\\\Rightarrow\ x=\dfrac{30}{3}\\\\\Rightarrow\ x=10\)
Hence, She rode 10 miles on first day.
Distance rode on second day = \(\dfrac45\times10=4\times2=8\text{ miles}\)
Distance rode on third day \(=\dfrac{3}{2}\times8=3\times4=12\text{ miles}\)
You are considering purchasing a consol that promises annual payments of $4. a. If the current interest rate is 3 percent, what is the price of the consol? Instructions: Round your answer to the nearest penny (2 decimal places). The price of the consol is $ b. You are concerned that the interest rate may rise to 4 percent. Compute the percentage change in the price of the consol and the percentage change in the interest rate. Compare them. Instructions: Round your answer for dollar amounts to the nearest penny (2 decimal places ) and answers for percentages to the nearest tenth (1 decimal place) The new price of the consol would be $ The price of the consol falls by 7% and the interest rises by 7% c. Your investment horizon is one year. You purchase the consol when the interest rate is 5 percent and sell it a year later, following a rise in the interest rate to 6 percent. What is your holding period return? Instructions: Round your answer to the nearest tenth (1 decimal place) Your holding period return is %
Answers
a. The price of the consol is approximately $133.33.
b. The new price of the consol would be $100. The price of the consol falls by 24.99% and the interest rate rises by 1%.
c. Your holding period return is approximately -49.99%.
a. The price of the consol can be calculated using the formula for the present value of a perpetuity:
Price = Annual Payment / Interest Rate
In this case, the annual payment is $4 and the interest rate is 3%. Substituting these values into the formula:
Price = $4 / 0.03 ≈ $133.33
Therefore, the price of the consol is approximately $133.33.
b. To calculate the new price of the consol if the interest rate rises to 4%, we use the same formula:
New Price = Annual Payment / New Interest Rate
Substituting the values, we get:
New Price = $4 / 0.04 = $100
The percentage change in the price of the consol can be calculated using the formula:
Percentage Change = (New Price - Old Price) / Old Price * 100
Substituting the values, we have:
Percentage Change in Price = ($100 - $133.33) / $133.33 * 100 ≈ -24.99%
The percentage change in the interest rate is simply the difference between the old and new interest rates:
Percentage Change in Interest Rate = (4% - 3%) = 1%
Comparing the two percentages, we can see that the price of the consol falls by approximately 24.99%, while the interest rate rises by 1%.
c. The holding period return can be calculated using the formula:
Holding Period Return = (Ending Value - Initial Value) / Initial Value * 100
The initial value is the purchase price of the consol, which is $133.33, and the ending value is the price of the consol after one year with an interest rate of 6%. Using the formula for the present value of a perpetuity, we can calculate the ending value:
Ending Value = Annual Payment / Interest Rate = $4 / 0.06 = $66.67
Substituting the values into the holding period return formula:
Holding Period Return = ($66.67 - $133.33) / $133.33 * 100 ≈ -49.99%
Therefore, the holding period return is approximately -49.99%.
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(11.52 x) = (3.6 x) + (1.8 x ) =
+
Answers
Answer:
\(x=0\)
Step-by-step explanation:
STEP 1: Since x is on the right side of the equation, switch the sides so it is on the left side of the equation.
\(3.6x+1.8x=11.52x\)
STEP 2: Add 3.6x and 1.8x.
\(5.4x=11.52x\)
STEP 3: Move all terms containing x to the left side of the equation.
\(-6.12x=0\)
STEP 4: Divide each term by −6.12 and simplify.
\(x=0\)
What is E + 8 =12 what is E in this question
Answers
Answer:
E = 4
Step-by-step explanation:
E + 8 = 12
Subtract 8 from both sides.
E + 8 - 8 = 12 - 8
E = 4
Write an inequality to represent this graph.
Answers
Answer:
Answer choices?
Step-by-step explanation:
hree different nonzero vectors ⇀u , ⇀v , and ⇀w in r3so that proj⇀w ⇀u = proj⇀w ⇀v = 〈0,2,5〉.
Answers
These three vectors satisfy proj_w u = proj_w v = ⟨0, 2, 5⟩.
To find three different nonzero vectors u, v, and w in R^3 such that proj_w u = proj_w v = ⟨0, 2, 5⟩, we can use the properties of vector projection and the given information.
Let's start by finding u and v.
We know that the projection of vector u onto vector w is ⟨0, 2, 5⟩, so we can write:
proj_w u = (u · w) / ||w||² * w = ⟨0, 2, 5⟩
Since the dot product (u · w) is involved, we can choose any vector u that is orthogonal to ⟨0, 2, 5⟩. For simplicity, let's choose u = ⟨1, 0, 0⟩.
Now, let's find v.
We know that the projection of vector v onto vector w is also ⟨0, 2, 5⟩, so we can write:
proj_w v = (v · w) / ||w||² * w = ⟨0, 2, 5⟩
Again, we can choose any vector v that is orthogonal to ⟨0, 2, 5⟩. Let's choose v = ⟨0, 1, 0⟩.
Now, we have u = ⟨1, 0, 0⟩ and v = ⟨0, 1, 0⟩. To find vector w, we need to ensure that the projections of both u and v onto w are equal to ⟨0, 2, 5⟩.
For proj_w u, we have:
(1a + 0b + 0c) / (a² + b² + c²) * ⟨a, b, c⟩ = ⟨0, 2, 5⟩
Simplifying, we get:
a / (a² + b² + c²) * ⟨a, b, c⟩ = ⟨0, 2, 5⟩
From the x-component, we have:
a / (a² + b² + c²) * a = 0
This equation suggests that a must be 0 since we want a non-zero vector. Therefore, a = 0.
Now, we have:
0 / (0² + b² + c²) * ⟨0, b, c⟩ = ⟨0, 2, 5⟩
From the y-component, we have:
b / (b² + c²) = 2
From the z-component, we have:
c / (b² + c²) = 5
Solving these two equations simultaneously, we can find suitable values for b and c. One possible solution is b = 1 and c = 5.
Therefore, we have the following vectors:
u = ⟨1, 0, 0⟩
v = ⟨0, 1, 0⟩
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25% of $4 = $_____
I need help I don’t get how to do it
Answers
Answer:
it would be one dollar
Step-by-step explanation:
25%= 0.25
0.25 times 4
equals $1
Answer:
$1 would be the answer
Step-by-step explanation:
= 4/4, quarterly
= 1
find the least number which is divisible by each of the number
4,8,12
Answers
Answer:
24
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
2 is divisible by 4 without a remainder
2 is also divisible by 8 without a reminder
2 is also divisible by 12 without a reminder
Jim is experimenting with a new drawing program on his computer. He created quadrilateral TEAM with coordinates T(- 2, 3), E(- 5, - 4), A(2, - 1) , and M(5, 6) . Jim believes that he has created a rhombus but not a square. Prove that Jim is correct.
Answers
Answer: yes Jim is correct
Each side of the quadrilateral is congruent. Then the quadrilateral is known as the rhombus.
What is a quadrilateral?The quadrilateral has four sides and four angles. The sum of internal angles is 360 degrees.
If all the sides of the quadrilateral are congruent then the quadrilateral may be a square or rhombus.
If none of the angles of that quadrilateral is equal to 90 degrees. Then the quadrilateral is known as a rhombus.
Jim is experimenting with a new drawing program on his computer. He created quadrilateral TEAM with coordinates T(- 2, 3), E(- 5, - 4), A(2, - 1) , and M(5, 6) .
The diagram is given below.
From the diagram, each side of the quadrilateral is congruent. Then the quadrilateral is known as the rhombus.
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Maths question.
Solve
4(x - 1) = 2(6 - 2x)
Answers
4x - 4 = 12 - 4x
8x = 16
X = 2
Answer:
x = 2
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDASEquality PropertiesStep-by-step explanation:
Step 1: Define equation
4(x - 1) = 2(6 - 2x)
Step 2: Solve for x
Distribute: 4x - 4 = 12 - 4xAdd 4x on both sides: 8x - 4 = 12Add 4 to both sides: 8x = 16Divide 8 on both sides: x = 2Step 3: Check
Plug in x into the original equation to verify it's a solution.
Substitute in x: 4(2 - 1) = 2(6 - 2(2))Multiply: 4(2 - 1) = 2(6 - 4)Subtract: 4(1) = 2(2)Multiply: 4 = 4Here we see that 4 does indeed equal 4.
∴ x = 2 is a solution of the equation.
HELP FOR BRAINLIEST & 100
please
Answers
Answer:
Hi,
Step-by-step explanation:
1) PC=PD since PC*PA=PD*PB
2)25 since PO²=PA²+r² PO=14.5, PB=14.5+10.5=25
3)
6²=3*x==> x=12
chris has 50 books on his shelves. Jenny has 12% more books. How many books has jenny got
Answers
Answer:
A number
Step-by-step explanation:
maths
jenny has 56 books
Step-by-step explanation:
So she has six more or 12% more
