The expression for the output current of a single-phase half-bridge inverter feeding an RL load can be derived. The maximum and minimum values of the load current can also be determined.
In a single-phase half-bridge inverter, the output current flowing through the RL load can be obtained by analyzing the circuit dynamics. The load current can be expressed as the sum of the steady-state component and the transient component. The steady-state component is determined by the average value of the output voltage and the load impedance, while the transient component is influenced by the switching behavior of the inverter. To determine the maximum and minimum values of the load current, one needs to consider the voltage waveform generated by the inverter and the characteristics of the RL load. The maximum value of the load current occurs when the output voltage is at its peak value, while the minimum value occurs when the output voltage is at its lowest value It is important to note that the load current waveform in an RL load can exhibit variations and distortions due to the effects of inductive reactance and the switching nature of the inverter. Proper design and control of the inverter circuit are necessary to mitigate these effects and ensure stable and reliable operation.
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A venture tube is used to measure the flow rate of a liquid in a pipe (liquid density is 800 kg/m3). The pipe has a diameter of 10 cm and the smallest diameter of the venture has a diameter of 4 cm. A manometer with a manometer fluid of mercury (specific weight of 133 kN/m3) is used to calculate the flow rate which is connected to the venture section such that one leg is far upstream and the second leg is at the minimum diameter of the venture tube. If the flow rate is 0.05 m3/s determine the elevation change in the manometer fluid.
a. 14.6 m
b. 9.28 m
c. 4.64 m
d. 2.32 m
Answer:
\(\triangle h=4.935m\)
Explanation:
From the question we are told that:
Liquid density \(\rho=800\)
Diameter of pipe \(d=4cm \approx 0.004m\)
Diameter of venture \(d=10cm \approx 0.010m\)
Specific weight of mercury P_mg \(133 kN/m^3\)
Flow rate \(r=0.05 m^3/s\)
Area A:
\(A_1=\frac{\pi}{4}0.1^2\\A_1=0.00785m^2\\A_2=\frac{\pi}{4}0.04^2\\A_2=0.001256m^2\\\)
Generally the Bernoulli's equation is mathematically given by
\(\frac{P_1}{\rho_1g}+\frac{V_1^2}{2g}=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}\\\)
Where
\(V_1=\frac{r}{A_1} \\\\ &V_1=\frac{r}{A_2}\)
Therefore
\(P_1-P_2=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)
Generally the equation for pressure difference b/w manometer fluid is given as
\(P_1-P_2=(p_mg-pg)\triangle h\)
Therefore
\((p_mg-pg)\triangle h=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)
\(\triangle h=\frac{\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})}{(p_mg-pg)}\)
\(\triangle h=\frac{\frac{(800)(0.05)^2}{2}(\frac{(0.1)^2-(0.4)^2}{(0.1)^2(0.04)^2})}{(1.33*10^3-800*9.81)}\)
\(\triangle h=4.935m\)
Therefore elevation change is mathematically given by
\(\triangle h=4.935m\)
a 0.505-in.diameter metal bar with a 2-in. gauge length l0 is subjected to a tensile test. the following measurements are made in the plastic region. determine the strain hardening exponent for the metal.
The strain hardening exponent for the metal can be determined based on the given measurements in the plastic region of the tensile test conducted on the 0.505-inch diameter metal bar with a 2-inch gauge length.
How can the strain hardening exponent be calculated using the measurements from the plastic region of the tensile test?The strain hardening exponent characterizes the relationship between the true stress and true strain in the plastic region of a material. To determine the strain hardening exponent for the metal, we need to analyze the measurements obtained during the tensile test. The true stress and true strain can be calculated using the following formulas:
True Stress = Load / Area
True Strain = ln(Original Gauge Length / Final Gauge Length)
By plotting the true stress and true strain data on a logarithmic scale, we can determine the slope of the resulting curve. This slope represents the strain hardening exponent, denoted by "n." The strain hardening exponent indicates how the material's strength increases as deformation occurs. By analyzing the given measurements in the plastic region, we can calculate the strain hardening exponent for the metal bar.
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2. a wheel tractor-scraper is operating on a level grade. assume no power derating is required for equipment condition, altitude, and temperature. use equipment data from figure 6.10. a) disregarding traction limitations, what is the maximum value of rolling resistance (in lb/ton) over which the fully loaded unit can maintain a speed of 15 mph? b) what minimum value of coefficient of traction between the tractor wheels and the traveling surface is needed to satisfy the requirements of part a? for the fully loaded condition, 52% of the weight is distributed to the drive axle. the operating weight of the empty scraper is 74,946 lb.
We can see here that the maximum value of rolling resistance over which a loaded scraper can maintain is: 780 lb/ton
What is a maximum rolling resistance?Rolling resistance is the force that resists the motion of a rolling object on a surface. Maximum rolling resistance refers to the highest level of resistance that an object can encounter while rolling on a particular surface.
For a fully loaded condition:
15mph speed, 52% resistanceGrade resistance = 0%The total resistance = (gross + rolling) resistance
52% = 0% - rolling resistance
rolling resistance = 52%
The maximum rolling resistance = rolling resistance percentage × speed
The maximum rolling resistance = 52% (15 lb/ton)/(1% resistance)
The maximum rolling resistance = 780 lb/ton
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What hardware and peripherals are you using right now to take this course? What software and operating system (OS)? Describe the basic details of how the things you write for this course are sent through the internet, including the role of packets, an ISP, and a server.
The hardware that I am using to take this course is a Laptop computer running on windows operating system.
What are the basic details of how the things written for this course are sent through the internet, including the role of packets, an ISP, and a server.When you send a query, like your previous message, your laptop's operating system breaks it into smaller units called packets. These packets contain parts of your message, destination address, and other metadata.
They're sent over the internet through your Internet Service Provider (ISP), which directs them through routers and switches. These network devices ensure packets take the most efficient path.
They reach the server where I'm hosted. The server processes your query, generates a response, divides it into packets, sends them back through the same process, and your laptop reassembles them to display my answer.
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A piston–cylinder device contains 0.8 kg of steam at 300°C and at pressure of 800 kPa. Steam is cooled at constant pressure until one-half of the mass condenses. The final temperature is
a.
178°C
b.
184°C
c.
195°C
d.
None of these
e.
167°C
f.
170°C
Answer:
d
Explanation:
d.
None of these
which other factors do you need to consider when preparing to move gondolas?
The factors that you need to consider when preparing to move gondolas are:
Heightwidthlength color. How do you move a gondola?In choosing gondola one need to look at some factor in decisions such as height.
Know that it is good to consider the construction material and also the center wall configuration for its building also.
The factors that you need to consider when preparing to move gondolas are:
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For an electrical system, short dashed lines indicate?
A solid line around a component indicates that the component is complete. A dashed line around the component indicates that the component is being shown is not complete.
An industrial overhead door has sprocket and chain system designed to reduce the force needed by an operator to open and close the door. the system consists of two individual systems that are connected through a live axle shaft. to operate the door, the operator pulls a continuous loop of chain over a fixed 22-tooth sprocket that is attached to a live axle shaft (system 1). a second 22-tooth sprocket is attached to the live axle shaft and uses a chain connected to a 48-tooth sprocket that is attached to a drum that drives the door.
The overall system gear ratio is 24 : 11.
The comic strip approximately annotating the power education has been attached.
Gear systems incorporate numerous gears and are the primary additives of many engineering packages along with using trains in cars. In working tools systems, non-easy dynamics along with tools hammering or high-frequency oscillations can also additionally occur.
Gear has the characteristic to switch movement and torque among gadget additives in mechanical devices. Gears can alternate the course of motion and/or beautify the end result pace or torque.
To determine the overall system gear ratio we can use the formula below:
GR = 48 : 22
GR = 24 : 11
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8. What are two ways SpaceX plans to change personal travel?
Answer:
as all the people should go near stratosphere
diffrerentiate y=cos^{4} (3x+1)
Answer:
-6sin(6x+2)cos²(3x+1)dx.
Explanation:
\(dy=4*cos^3(3x+1)*3*(-sin(3x+1))dx=-6sin(6x+2)cos^2(3x+1)dx.\)
A hydroelectric turbine passes 1.7 million gal/min through its blades. If the average velocity of the flow in the circular cross-sectional conduit leading to the turbine is not to exceed 34 ft/s, determine the minimum allowable diameter of the conduit.
Answer:
11.87 ft
Explanation:
Volumetric flow rate of the turbine Q = 1.7 million gal/min
Q = 1.7 x \(10^{6}\) gal/min
1 gal = 0.00378541 m^3
1 min = 60 sec
1.7 x \(10^{6}\) gal/min = (1.7 x \(10^{6}\) x 0.00378541)/60 = 107.25 m^3
average velocity of flow through turbine = 34 ft/s
1 ft = 0.3048 m
34 ft/s = 34 x 0.3048 = 10.36 m/s
According to continuity equation, Q = AV
where Q = volumetric flow rate
A = Area of conduit
V = velocity of flow through turbine
A = Q/V = 107.25/10.36 = 10.35 m^2
Area of conduit = \(\pi r ^{2}\)
radius r = \(\sqrt{\frac{area}{\pi } }\) = \(\sqrt{\frac{10.35}{3.142} }\) = 1.81 m
diameter = 2 x radius = 2 x 1.81 = 3.62 m
diameter = 3.62 m = 3.62 x 3.28084 = 11.87 ft
A high compression ratio may result in;
A high compression ratio may result in compressor failure.
What is a compressor?A compressor refers to a mechanical device that is designed and developed to provide power to refrigerators, especially by increasing the pressure on air or other applicable gases.
According to heating, ventilation, and air conditioning (HVAC) information, a high compression ratio of 8: 1 or higher is most likely to result in compressor failure.
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5 page paper about the government and how it’s decisions affects the world.
The government, through its decisions and policies, wields significant influence that extends beyond national borders and directly affects the world. Government decisions can have far-reaching impacts on various aspects, including politics, economics, social issues, and the environment.
In the realm of politics, government decisions on international relations, diplomacy, and foreign policy shape global alliances, conflicts, and cooperation. They determine how a country engages with other nations, resolves disputes, and participates in international organizations and agreements.
Economically, government decisions on trade policies, regulations, taxation, and fiscal management impact global markets, investments, and economic stability. Changes in the economic policies of major economies can have ripple effects on other countries, affecting trade flows, exchange rates, and overall global economic conditions.
Government decisions also play a crucial role in addressing global challenges such as climate change, public health crises, and human rights issues. Policies on environmental regulations, international agreements, healthcare initiatives, and human rights advocacy can influence global efforts and cooperation in addressing these pressing issues.
Moreover, government decisions on security and defense policies have implications for global peace and stability. Actions related to arms control, military interventions, and peacekeeping operations can shape geopolitical dynamics and impact international security.
In summary, government decisions have a profound impact on the world by shaping international relations, influencing global economies, addressing global challenges, and affecting peace and security. The interconnectedness of nations and the shared nature of global issues highlight the significance of government decisions in shaping the course of the world.
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who is the strongest avenger i say hulk but who knows at this point
Answer:
or is the strongest evenger she hulk
Explanation:
?????????
Answer:
Thor!
Explanation:
In Thor: Ragnarok he beat the Hulk in order for Hulk to win thor had to be electrocuted and in Avengers: Endgame Thor is seen holding open the "Floodgates" and withstanding the radiation from a dying star, also the fact that Thor is a god means that he is all powerful and the rightful heir to the throne to Asgard, plus the fact that he has defeated Loki multiple times a feat that not even the Hulk has done.
Steam locomotives with a 4-6-2 wheel arrangement were usually classified as what?.
the answer Under the Whyte notation for the classification of steam locomotives it is called 4-6-2 Pacific type
a butterfly or poppet-type valve that allows exhaust gases to bypass the turbine wheel is called a(n) .
A butterfly or poppet-type valve that allows exhaust gases to bypass the turbine wheel is called a: wastegate valve.
What is a wastegate valve?A wastegate is a channel that allows the fumes from the exhaust pipes to be easily discharged without choking the vehicle from which the waste comes off.
The wastegate valve is important because it releases pressure from the turbine's wheel and allows for optima functionality in the course of use. So, the answer to the question about poppet-type valves is waste gate valves.
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Thermoplastics that exhibit a definite TM point have this kind of crystalline structure:
A. semi-crystalline
B. isotactic
C.amorphous
D. syndiotactic
Answer:
The correct option is A
Explanation:
Thermoplastics are polymers that can be recycled. They can be melted with heat and moulded into any shape which becomes hard when cooled. The heat applied to it in the process of recycling does not affect its chemical composition.
There are two main classes of thermoplastics; semi-crystalline and amorphous.
An amorphous thermoplastic has a disorderly arranged molecular structure which makes it difficult to have a definite melting temperature (Tm). However, a semi-crystalline thermoplastic has a well arranged molecular structure which makes it melt after a certain/definite amount of heat is absolved. Hence, the correct answer is A
norton's theorem and thevenin's theorem related linearity property
Norton's theorem in regards to linearity property is known to be one that employ the use of a current source while the Thevenin's theorem is known to be one that employ the use of a voltage source.
Thevenin's theorem make use of a resistor in a kind of series, but Norton's theorem is known to use a resister set in a kind of parallel way in line with the source.
What is Norton's Theorem?
Norton's Theorem is known to be a law that states that one can be able to simplify any form of linear circuit, no matter how difficult or hard that it may be, to an equivalent circuit through the use of only one current source and also the use of a parallel resistance linked to a load.
Note that, Norton's theorem in regards to linearity property is known to be one that employ the use of a current source while the Thevenin's theorem is known to be one that employ the use of a voltage source.
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The National Weather Service has issued an alert for a severe storm that will bring 100 mm of rainfall in one hour. A farmer in the area is trying to decide whether to sand bag the creek that drains the 40 acres of row crops. The soil for the drainage area is a sandy clay loam and has a porosity of 0.398, effective porosity of 0.330, suction pressure of 52.3 cm, a hydraulic conductivity of 0.25 cm/hr and an effective saturation of 90%. Assuming that ponding occurs instantaneously, estimate the total depth of direct runoff in mm from the event using the Green-Ampt infiltration model.
a. 80
b. 89
c. 76
d. 72
-0-1"
-0
-20
-15
-10
0
-5
75743366
Explanation:
What is the approximate Brinell hardness of a 1040 steel having a yield strength of 620 MPa (90,000 psi)
The Brinell hardness test is commonly used to measure the hardness of a material. For a 1040 steel with a yield strength of 620 MPa, the approximate Brinell hardness is determined to be 207.
The Brinell hardness test is the most commonly used method for determining the hardness of a material. The Brinell hardness test measures the resistance of a material to indentation under load.
A ball indenter with a known diameter is pressed into the surface of the test piece, and the diameter of the resulting impression is measured.
The load used and the diameter of the indenter are related to the Brinell hardness number (BHN) by the following formula:
BHN = 2P/πD(HD – √HD² – d²), Where:
BHN = Brinell hardness numberP = load applied in kgD = diameter of the ball indenter in mmHD = Brinell hardness diameter in mm,which is the diameter of the impression left in the test piece by the indenterd = diameter of the ball indenter in mm
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Q3
a. A binary search tree may be balanced or unbalanced based on the arrangement
of the nodes of the tree. With you knowledge in Binary search tree:
i. Explain the best and worst case scenarios of the time and space complexity of
both type of binary trees above. (AP)15 marks
b. A program accepts natural numbers N and M as inputs into an integer array A[ ]
and B[ ], each consisting of N and M of elements respectively. Sort the arrays A[ ]
and b[ ] in descending order of magnitude. Use the sorted array to generate a merged
array C[ ]. Array C[ ] should be generated in descending order. Assume the input
arrays comprise a maximum of 20 elements each, with no duplicates. Common
elements should be included in the merged array only once
The best case scenarios of the time and space complexity of binary search is simply the time complexity of the binary search algorithm which is O(log n).
However, this balanced scenarios complexity would be O(1) when the central index would directly match the desired value.
On the other end, for an unbalanced scenarios of binary search tree, the running time of a binary search would be O(n). which will represent a linked list
What is binary search tree?The binary search tree simply refers to an advanced algorithm used for analyzing the node, its left and right branches, which are eventually modeled in a tree structure and returning the value.
So therefore, the best case scenarios of the time and space complexity of binary search is simply the time complexity of the binary search algorithm which is O(log n).
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a uniform disc of mass 20kg and radius 0.15m, starting from rest rotates with uniform angular acceleration of 0.7 rad/s^2 about axis through its center find a.) moment of inertia? b.) angular velocity after 10s? c.) kinetic energy after 10s? d.) angular momentum after 10s?
Hãy tính phản lực liên kết tại ngàm A, bản lề C và gói di động D biết p=400N/m
P1=100N
P2=200
P3=300
M1=100N/m
N2=200N/m
Answer:
say in English plz I don't understand
The basic building block of digital technology is the
Select one:
a. flip-flop
b. binary adder
c. gate
d. truth table
The basic building block of digital technology is the gate (Option c). It makes reference to logic gates.
What are logic gates?A logic gate is a computer model that uses logical mathematical equations based on Boolean function.
A logic gate can be considered as a unit block for all used types of digital devices and/or circuits.
Digital technologies use logic gates that allow them to perform different functions (digital functions).
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tech a says that semi-floating wrist pins can be pressed into the rods. tech b says that a rod heater can be used to install semi-floating wrist pins. who is correct?
The correct answer is both the tech are right that a rod heater can be used to install semi-floating wrist pins and semi-floating wrist pins can be pressed into the rods.
After some kind of friction secures the pin to the connecting, the piston can freely pivot inside the bosses of the piston pin. The most common method of attaching the semi-floating wrist pins to the rod is by press-fitting. The little end of the connecting rod is heated, which expands the metal and the diameter of the hole.If you're using high-level forced induction, nitrous oxide injection, high rpm or heavy sustained loading on your performance engine, upgraded semi-floating wrist pins represent the insurance deal of the century. Wall thickness is a critical factor based on application.
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In a certain chemical plant, a closed tank contains ethyl alcohol to a depth of 71 ft. Air at a pressure of 17 psi fills the gap at the top of the tank. Determine the pressure at a closed valve attached to the tank 10 ft above its bottom.
Answer:
the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi
Explanation:
Given that;
depth 1 = 71 ft
depth 2 = 10 ft
pressure p = 17 psi = 2448 lb/ft²
depth h = 71 ft - 10 ft = 61 ft
we know that;
p = P_air + yh
where y is the specific weight of ethyl alcohol ( 49.3 lb/ft³ )
so we substitute;
p = 2448 + ( 49.3 × 61 )
= 2448 + 3007.3
= 5455.3 lb/ft³
= 37.88 psi
Therefore, the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi
he crimping tool is used to crimp the end of the wire E. If a force of 25.6 lb is applied to the handles, determine the average shear stress (in ksi) in the pin at B. The pin is subjected to single shear and has a diameter of 0.28 in. Only vertical force is exerted on the wire. Note: You answer should include requested units and be to 3 decimal places.
Answer:
Shear Stress = 0.415 ksi
Explanation:
In order to find the shear stress we first need to find the cross sectional area of pin B. The area is given as follows:
A = πd²/4
where,
A = Area of cross section of pin = ?
d = diameter of pin = 0.28 in
Therefore,
A = π(0.28 in)²/4
A = 0.0615 in²
Now, the shear stress is given as:
Shear Stress = Shear Force/Area
Shear Stress = 25.6 lb/0.0615 in²
Shear Stress = 415.8 psi
Shear Stress = 0.415 ksi
If the two 304-stainless-steel carriage bolts of the clamp each have a diameter of 10 mmmm, and they hold the cylinder snug with negligible force against the rigid jaws, determine the temperature at which the average normal stress in either the magnesium or the steel first becomes 12.0 MPaMPa .
Answer: hello some data related to your question is missing attached below is the missing data
answer:
T2 = 265°C
Explanation:
First step : calculate sum of vertical forces
∑ y = 0
Fmg - 2(0.5 Fst ) = 0
∴Fmg = ( 12 * 10^6 ) ( 2 * π/4 (0.01)^2 )
= 1884.96 N
Also determine the Compatibility equation in order to determine the change in Temperature
ΔT = 250°C
therefore Temperature at which average normal stress becomes 12.0 MPa
ΔT = T2 - T1
250°C = T2 - 15°C
T2 = 250 + 15 = 265°C
attached below is the detailed solution
In a single-family residence, a line-voltage thermostat is primarily used to control _____.
Answer:
In a single-family residence, a line-voltage thermostat is primarily used to control heating and cooling systems.