for an m/g/1 system with λ = 20, μ = 35, and σ = 0.005. find the probability the system is idle.

Answer sunlight, water and carbon dioxide

Explanation:

Plants absorb sunlight, water and carbon dioxide for photosynthesis, using solar energy to split the water molecule into hydrogen and oxygen and power a chemical reaction that assimilates carbon dioxide, producing carbohydrates used to fuel the plants' survival.

saitama is the strongest

Answer:

Yes.

Explanation:

Yes, the electron charge is equal in mode to the proton charge because electrons are opposite to the charge of proton due to which they cancel the effect of each other. Proton has positive charge whereas election has negative charge which cancel the effect of each other if they are present in the same number. If the electron is losses by an atom, positive charge appears on the atom due to more number of proton as compared to electron while on the other hand, negative charge appears on atom if electron is accepted by the atom.

Unguarded live parts operating at 30,000 volts located above a working space must be elevated at least 9.5' above the working space.

The voltage is the potential difference between the end of the conductor.
The place where electricity supply wires and power stations are present, the lives must protected. They must live far above the working space.

Thus, it must be 9.5' above the working space.

Learn more about voltage.

https://brainly.com/question/13521443

#SPJ1

Consider the following system, where F = 120 N, m = 1 kg, and M = 5 kg. Force exerted by the lighter block on the heavier block is F_2=20N

F = 120N

m = 1kg

M = 5kg

Generally, the equation for acceleration is mathematically given as

\(a=\frac{F}{m+M} \\\\a=\frac{120}{1+5} \\\)

a=20m/s^2

Let's formulate the heavier block's equation of motion.

F_1=F-F_2

Ma=F-F_2

It is estimated that the lighter block will exert the following force on the heavier block:

\(&F_2=\mathrm{F}-\mathrm{Ma} \\&F_2=120-(5 *20) \\\)

F_2=20N

Read more about the magnitude

https://brainly.com/question/14452091

#SPJ1

Given :

Two cylinders contain pistons that are connected by fluid in a hydraulic system.

A force of 1,300 N is exerted on one piston with an area of 0.05 m².

To Find :

The force exerted on the other piston that has an area of 0.08 m.

Solution :

Since, force is exerted between two cylinder, it means pressure is constant.

So,

\(P_1 = P_2\\\\\dfrac{F_1}{A_1} = \dfrac{F_2}{A_2}\\\\\dfrac{1300\ N}{0.05 \ m^2} = \dfrac{F_2}{0.08\ m^2}\\\\F_2 = \dfrac{1300\times 0.08}{0.05}\ N\\\\F_2 = 2080\ N\)

Hence, this is the required solution.

Answer:

v = 31.89 m/s

Explanation:

p = m × v

1,850 = 58 × v

58v = 1,850

v = 1,850/58

v = 31.89 m/s

The magnitude of the average induced emf in the loop during this time is 56 mV.

To determine the magnitude of the average induced electromotive force (emf) in the loop during the given time, we can apply Faraday's law of electromagnetic induction.

According to Faraday's law, the induced emf in a conducting loop is equal to the rate of change of magnetic flux through the loop.

Given that the loop is circular and the magnetic field points into the page, the magnetic flux through the loop is given by:

Φ = B * A

where B is the magnitude of the magnetic field and A is the area of the loop. Initially, when the loop has a non-zero area, the magnetic flux is Φ₁ = B * A₁, where A₁ is the initial area of the loop.

Finally, when the loop's area is nearly zero, the magnetic flux becomes Φ₂ = B * A₂, where A₂ is the final area of the loop.

The change in magnetic flux during the time interval Δt is given by:

ΔΦ = Φ₂ - Φ₁ = B * A₂ - B * A₁

Since we want to find the average induced emf, we divide the change in magnetic flux by the time interval:

emf = (ΔΦ) / Δt

Now, let's calculate the values using the given information:

Radius of the loop, r = 11.0 cm = 0.11 m

Magnetic field, B = 0.160 T

Time interval, Δt = 0.160 s

Initially, the area of the loop is given by the formula for the area of a circle:

A₁ = π * r² = π * (0.11 m)²

Finally, when the area becomes nearly zero, we have A₂ ≈ 0.

Therefore, the change in magnetic flux is:

ΔΦ = B * A₂ - B * A₁ = B * (A₂ - A₁)

Since A₂ is nearly zero, we can ignore that term:

ΔΦ ≈ B * (0 - A₁) = -B * A₁

Now, we can calculate the magnitude of the average induced emf:

emf = (ΔΦ) / Δt = (-B * A₁) / Δt

Substituting the given values:

emf = (-0.160 T) * (π * (0.11 m)²) / (0.160 s)

emf ≈ -0.056 T * m² / s

To convert this to millivolts (mV), we multiply by 1000:

emf ≈ -56 mV

Therefore, the magnitude of the average induced emf in the loop during this time is approximately 56 millivolts.

For more such questions on magnitude, click on:

https://brainly.com/question/24468862

#SPJ11

Answer:

v = 49.05 m/s^2

Explanation:

Let's use the uniform acceleration equation to find our final velocity.

\(v = u + at\)

v = final velocity

u = initial velocity

a = gravitational acceleration

t = time taken

Assuming the rock is at rest initially, u becomes zero.

\(v = 0 + 9.81(5)\)

\(v = 49.05 m/s^2\)

Answer:

The acceleration of the object decreases I think

Explanation:

The change in the momentum of the cart,given the data is 0.06 Kgm/s (Option D)

Momentum is defined as the product of mass and velocity. It is expressed as

Momentum = mass × velocity

Change in momentum = mass (final velocity - initial velocity)

From the data given above, the following data were obtained:

Change in momentum = m(v + u) (renounce)

Change in momentum = 0.5 (-0.24 + 0.36)

Change in momentum = 0.5 × 0.12

Change in momentum = 0.06 Kgm/s

Learn more about momentum:

https://brainly.com/question/250648

#SPJ1

Under reversed polarity, we found the results to be exactly in current direction, while the current maximums were 0, negative, positive, opposite and the same.

What is reversed polarity?

Reversed polarity refers to a situation where the positive and negative terminals of an electrical circuit are connected in reverse order. This can happen accidentally due to improper wiring, or intentionally as a means of reversing the direction of current flow.

Reversed polarity can cause electrical equipment to malfunction, overheat, or fail altogether. It can also create safety hazards such as electric shock, fire, or explosion. Therefore, it is important to ensure proper polarity in electrical circuits and devices.

To learn more about reversed polarity, visit: https://brainly.com/question/16979824

#SPJ1

Answer:

Explanation:

0
negative
positive
opposite
the same

(B)

Explanation:

\(pe = \frac{1}{2} k {x}^{2} \)

The equation of the elastic potential energy stored in the spring can be represented as: EPE = (1/2)kx². Therefore, option (B) is correct.

The elastic potential energy can be described as the total energy obtained as a result of deformation in the shape of an object. The elastic potential energy implies any object which is capable of regaining its actual shape and size after deformation.

The deformation is only possible as a result of the gained potential energy which is called the elastic potential energy. The elastic potential energy can be stored energy of a compressible or stretchable in other words stored energy of perfectly elastic materials.

The mathematical equation of the elastic potential energy formula is given by:

U = 1/2 (Force × Displacement)

U = (1/2) (kx) (x)

U = (1/2)kx²

Where k is the spring constant and x is the displacement as a result of applied external force.

Learn more about elastic potential energy, here:

https://brainly.com/question/14687790

#SPJ2

The correct answer is "a billion times fainter." The reason it is difficult to see a planet around another star is that the reflected light from a planet is at least a billion times fainter than the star.

Planets are relatively small compared to stars and they do not produce any light of their own. They only reflect the light of the star around which they orbit. As a result, the light from a planet is very dim and gets drowned out by the much brighter light of the star. To observe an exoplanet directly, astronomers have to use advanced techniques such as blocking out the star's light or using telescopes that can detect infrared light. The statement "Seeing a planet around another star is difficult in part because the reflected light from a planet is at least 10,000 times fainter than the star" is correct to fill in the blank. Seeing a planet around another star is difficult in part because the reflected light from a planet is at least 10,000 times fainter than the star.

Planets do not emit light of their own, they merely reflect light from their parent stars. The fact that planets reflect the light of their parent star makes it difficult to observe them because the parent star's light is so much more intense. The amount of light a planet reflects is determined by its albedo, which is the ratio of light it reflects to light it absorbs. A planet's albedo varies depending on its atmospheric composition and surface characteristics.

To know more about planet visit:-

https://brainly.com/question/26756957

#SPJ11

Answer:

a black or dark viscous substance obtained as a residue in the distillation of organic materials and especially tars

Explanation:

(1) The force of gravity between the Earth and the satellite is 8.91 * 10^6 N.

(2)  The orbital period of the satellite is 6,132 seconds i.e. 1 hour and 42 minutes.

(3) The tangential velocity required to keep the satellite in orbit is approximately 7.94 km/s.

(4) The angular velocity of the satellite is 0.0011 radians per second.

(1)  The force of gravity between two objects can be calculated using Newton's law of universal gravitation. The formula is F = (G * m1 * m2) / \(r^2\), where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between their centers. In this case, the mass of the Earth is much larger than the mass of the satellite, so we can consider the satellite's mass negligible compared to the Earth's mass. Plugging in the values, we get\(F = (6.67 \times 10^{-11} N m^2/kg^2) \times (5.97 \times 10^{24} kg) \times (900 kg) / (6,371,000 m)^2 = 8.91 \times 10^6 \ Newtons\)

(2) The orbital period of a satellite can be determined using Kepler's third law of planetary motion, which states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit. Since the satellite is orbiting at a radius equal to one Earth radius above the surface, the semi-major axis is the sum of the Earth's radius and the altitude of the satellite. Using the formula \(T = 2\pi \times\sqrt{(a^3 / (G \times M)}\), where T is the orbital period, a is the semi-major axis, G is the gravitational constant, and M is the mass of the Earth, we can calculate the value. Plugging in the values, we get \(T = 2\pi \times\sqrt{6,371,000}\) meters +\((6,371,000 \ m)^3 / (6.67 \times 10^{-11} N m^2/kg^2 \times 5.97 \times 10^{24} kg)\) = 6,132 seconds.

(3) The tangential velocity required to keep a satellite in orbit can be determined using the formula \(v = \sqrt{G \times M / r\) where v is the tangential velocity, G is the gravitational constant, M is the mass of the Earth, and r is the distance between the center of the Earth and the satellite. Plugging in the values, we get v = √((6.67 x 10^-11 N m^2/kg^2 * 5.97 x 10^24 kg) / \(v = \sqrt{\frac{(6.67 \times 10^{-11} N m^2/kg^2 \times 5.97 \times 10^{24} kg) }{(6,371,000 m + 6,371,000 m)}\)) = 7,906 m/sec.

(4) The angular velocity of a satellite in orbit can be calculated using the formula ω = v / r, where ω is the angular velocity, v is the tangential velocity, and r is the distance between the center of the Earth and the satellite. Plugging in the values, we get ω = 7,906 meters per second / (6,371,000 meters + 6,371,000 meters) = 0.0011 radians per second.

To know more about force of gravity here https://brainly.com/question/2537310

#SPJ4

Answer:

its 4 right

i hope it is

Answer:

im pretty positive its 4 , if not its 1

The magnitude of the necessary lifting force of the jet flying on the banks will be 9.42 × 10⁵ Newtons.

The lifting force can be simply defined as the force which is used to lift an object. Lifting force is the sum of all the forces on an object that force it to move perpendicular to the direction of flow of bank.

Necessary lifting face (F) = ms²

F = 2.06 × 10⁵ × (132)²/ 3810

F = 2.06 × 10⁵ × (132)²/ 3810

F = 2.06 × 10⁵ × 132 × 132 / 3810

F = 35893.44 × 10⁵/ 3810

F = 9.42 × 10⁵ N

Therefore, the necessary lifting force will be 9.42 × 10⁵ Newtons.

Learn more about Force here:

https://brainly.com/question/13191643

#SPJ1

Answer:

Since there is more centrifugal force at the equator to cancel gravity, your overall weight at the equator versus at the poles is even less

Explanation:

Answer:

1350N

Explanation:

Given data

mass= 75kg

velocity= 6m/s

distance= 2m

The expression for the applied force is given as

F= mv^2/d

Substitute

F= 75*(6)^2/ 2

F= 75*36/2

F= 2700/2

F= 1350N

Hence the force is 1350N

The potential difference across the ends of a wire is doubled in magnitude. If ohm’s law is obeyed, the resistance is not changed. Thus, option A is correct.

The current is the stream of charges which flow inside the conductors when connected across the end of voltage.

From Ohm's law, V =IR

Here, R is the proportionality constant called the resistance of the resistor.

The complete question is given in the image attached.

The potential difference across the ends of a wire is doubled in magnitude.2V = IRR =2 V/IAs, the resistance is a constant value, it does not change.

The following statements concerning the resistance of the wire true is :

The resistance is not changed

Thus, the correct option is A.

Learn more about current, here:

https://brainly.com/question/13076734

#SPJ1

The type of mirror required will be a concave mirror with a focal length of 0.657 m.

The mirror is positioned relative to the object at 0.767m in front of the mirror.

(a) The type of mirror required to form an image that is six times as tall as the object is a concave mirror.

This is because a concave mirror is capable of producing both real and virtual images, depending on the position of the object relative to the focal point.

In this case, since the image is larger than the object, a concave mirror with a focal length of the appropriate value can produce the desired image.

(b) The distance between the mirror and the object can be calculated using the mirror formula:

1/f = 1/do + 1/di

where f is the focal length of the mirror, do is the distance between the object and the mirror, and di is the distance between the image and the mirror.

Given that the image is six times as tall as the object and the screen is 4.6 m from the mirror, we can determine the position of the image:

h/i = -di/do = -6/1

Thus, the image is 6 times as tall as the object, and since it is real and inverted, the value of di is negative. Substituting the known values into the mirror formula and solving for do, we get:

1/0.657 = 1/do - 1/4.6

Solving for do, we get do = 0.767 m. Therefore, the mirror should be positioned 0.767 m in front of the object.

For more such answers on mirrors

https://brainly.com/question/1126858

#SPJ11

Answer:

Approximately \(240\; {\rm Hz}\).

Explanation:

Consider how the motion of the boat (the source) affects the period of the sound wave as it appears to the observer.

The sound wave from this boat travels at the speed of sound \(v(\text{sound})\). At the same time, the boat (the source) is moving away from the observer at a speed of \(v(\text{boat})\). Let \(T_{s}\) denote the period of this wave, and let \(f_{s}\) denote the frequency.

The boat emits a wave crest after every interval of \(T_{s}\). During that time, the boat would have moved \(v(\text{boat})\, T_{s}\) further away from the observer. As a result, each subsequent crest would require an additional time of \(\Delta T\) to reach the observer:

\(\begin{aligned}\Delta T &= \frac{(\text{extra distance})}{(\text{wave speed})} = \frac{v(\text{boat})\, T_{s}}{v(\text{sound})}\end{aligned}\).

The source continues emitting crests with an interval of \(T_{s}\). However, because of the extra distance, it would appear to the observer that crests are arriving with an interval of:

\(\begin{aligned}T_{o} &= T_{s} + \Delta T \\ &=T_{s} + \frac{v(\text{boat})\, T_{s}}{v(\text{source})} \\ &= \left(1 + \frac{v(\text{boat})}{v(\text{source}}\right)\, T_{s}\end{aligned}\).

As it appears to the observer, the frequency of this wave would be:

\(\begin{aligned}f_{o} &= \frac{1}{T_{o}}\\ &= \frac{1}{\displaystyle \left(1 + \frac{v(\text{boat})}{v(\text{source}}\right)\, T_{s}} \\ &= \frac{f_{s}}{\displaystyle \left(1 + \frac{v(\text{boat})}{v(\text{source}}\right)} \\ &= \frac{250\; {\rm Hz}}{\displaystyle \left(1 + \frac{15\; {\rm m\cdot s^{-1}}}{342\; {\rm m\cdot s^{-1}}}\right)} \\ &\approx 240\; {\rm Hz}\end{aligned}\).

When the mirror is moved so that the tree is between the focus point F and the mirror, the image appears shorter and on the same side of the mirror.This happens because of the phenomenon known as Reflection of Light. The mirror reflects light in such a way that it appears as if the light is coming from behind the mirror.

For such more question on Concave

https://brainly.com/question/30225075

#SPJ8

Large-scale winds are generated on Earth primarily because of atmospheric pressure differences.

The primary cause of large-scale winds on Earth is the uneven heating of the Earth's surface by solar radiation, which creates variations in atmospheric pressure.

The sun's energy heats the Earth's surface unevenly, with different regions receiving different amounts of heat. As a result, the air above these regions becomes warmer and expands, leading to a decrease in air pressure.

In contrast, areas with cooler temperatures have denser air, resulting in higher atmospheric pressure. The difference in pressure between these regions creates a pressure gradient, which drives the movement of air from high-pressure areas to low-pressure areas. This movement of air is what we perceive as wind.

The Earth's rotation also plays a significant role in shaping wind patterns. The Coriolis effect, caused by the planet's rotation, deflects moving air to the right in the Northern Hemisphere and to the left in the Southern Hemisphere.

This deflection further influences the direction and patterns of large-scale winds, creating phenomena like trade winds, prevailing westerlies, and polar easterlies.

Learn more about winds

brainly.com/question/23369600

#SPJ11

All materials that enter or leave the cell must pass across the cell membrane. The cell membrane is a selectively permeable barrier that regulates the movement of substances in and out of the cell.

The cell membrane consists of a phospholipid bilayer embedded with various proteins and other molecules. It controls the passage of molecules and ions by different mechanisms:

Passive Diffusion: Small, non-polar molecules such as oxygen and carbon dioxide can passively diffuse across the cell membrane. This occurs due to the concentration gradient, where substances move from an area of higher concentration to an area of lower concentration.

Facilitated Diffusion: Larger or charged molecules, such as glucose or ions, require the assistance of specific membrane proteins called transporters or channels to move across the cell membrane. Facilitated diffusion also occurs along the concentration gradient but relies on protein-mediated transport.

Active Transport: Some molecules need to move against the concentration gradient, from an area of lower concentration to an area of higher concentration. Active transport involves the use of energy (ATP) and specific carrier proteins to pump molecules across the membrane, allowing the cell to accumulate substances or maintain concentration gradients.

Endocytosis and Exocytosis: Large molecules, such as proteins or cellular waste, can be transported across the cell membrane through processes called endocytosis and exocytosis. Endocytosis involves the cell engulfing substances by forming vesicles from the cell membrane, while exocytosis releases substances by fusing vesicles with the cell membrane.

Overall, the cell membrane plays a crucial role in maintaining the internal environment of the cell by selectively allowing the passage of specific molecules while preventing the entry or exit of others. This regulation ensures proper functioning and survival of the cell.

To learn more about Facilitated diffusion, visit:

https://brainly.com/question/14852229

#SPJ11

the resistance of the silver wire at 160°C is approximately 5.725 Ω.

The resistance of a silver wire at a different temperature can be calculated using the formula:

R2 = R1 * (1 + α * (T2 - T1))

where R2 is the resistance at the new temperature, R1 is the resistance at the initial temperature, α is the temperature coefficient of silver, T2 is the new temperature, and T1 is the initial temperature.

In this case, the initial resistance (R1) is 5 Ω at 15°C, and we want to find the resistance (R2) at 160°C. The temperature coefficient of silver (α) is given as 3.8 x 10^-3 (°C)^-1.

Using the formula, we can calculate:

R2 = 5 Ω * (1 + (3.8 x 10^-3 (°C)^-1) * (160°C - 15°C))

R2 ≈ 5 Ω * (1 + 0.145)

R2 ≈ 5 Ω * 1.145

R2 ≈ 5.725 Ω

Therefore, the resistance of the silver wire at 160°C is approximately 5.725 Ω.

Learn more about resistance here : brainly.com/question/29427458

#SPJ11

The frequency heard by an observer in the moving car as they approach the police car is approximately 541 Hz.

To determine the frequency heard by an observer in the moving car as they approach the police car, we need to consider the Doppler effect. The Doppler effect is the change in frequency of a wave as a result of relative motion between the source of the wave and the observer.

The speed of sound in air is given as 343 m/s.

The velocity of the car approaching the police car is 36 m/s.

The frequency of the siren (relative to the police car) is 500 Hz.

The observed frequency (heard by the moving observer) can be calculated using the Doppler effect equation for sound:

observed frequency = (speed of sound + velocity of observer) / (speed of sound + velocity of source) * source frequency.

Plugging in the given values:

observed frequency = (343 m/s + 36 m/s) / (343 m/s) * 500 Hz

≈ 1.181 * 500 Hz

≈ 590.5 Hz.

Note: The velocity of the observer (moving car) is positive since they are approaching the source.

However, we need to consider that the observed frequency is affected not only by the motion of the observer but also by the motion of the source (siren) relative to the observer. In this case, the source (siren) is also stationary relative to the police car.

Since both the observer and the source are in motion, we need to take into account the relative motion between them. As the observer approaches the source, the effective relative velocity is the sum of their velocities. In this case, the effective relative velocity is 36 m/s.

To account for the relative motion between the observer and the source, we need to adjust the observed frequency. The observed frequency is increased when the observer approaches the source.

By applying the Doppler effect equation again with the adjusted relative velocity, we get:

observed frequency = (343 m/s + 36 m/s) / (343 m/s) * 590.5 Hz

≈ 1.181 * 590.5 Hz

≈ 696.5 Hz.

Note: The adjusted observed frequency is higher than the initial observed frequency due to the relative motion of the observer and the source.

Therefore, the frequency heard by an observer in the moving car as they approach the police car is approximately 541 Hz.

For more such questions on frequency, click on:

https://brainly.com/question/254161

#SPJ8