For each chemical equation below, write the number of product molecules that will form from the reaction. Then highlight the limfting reactant. (Note: The coefficients in front of the reactants indicate the number of reactant molecules or atoms present.) 5C + 60, 99a 5CO B. 4Na + 8C1, 9a 4NCI A c. 300, + 4H, 09a 3H,CO; D. 7N, + 9H, Q6NH, E. 10Zn + 16HCI P7ZnCl2 + 3H2

Answer

Oxygen gas would have the highest entropy

Explanation

Entropy is the measure of degree of disorderliness or randomness of a system. Gaseous substances have higher entropy than liquid substances followed by solids.

Answer:

1. Materials: One of the biggest challenges in making better batteries is finding the right materials that can store more energy and last longer. The materials need to be efficient in terms of energy density, cost, and environmental impact.

2. Manufacturing: The production of batteries is a complex and expensive process that requires specialized knowledge and equipment. Scaling up production can be a challenge, and the cost of manufacturing high-quality batteries is still relatively high.

3. Safety: The safety of batteries is a major concern. The risk of fire or explosion is always present, particularly with lithium-ion batteries. Improvements in battery safety are needed to reduce the risk of accidents and increase confidence in battery technology.

4. Environmental impact: The production and disposal of batteries can have a significant environmental impact. The mining of metals and other materials used in batteries can have negative environmental consequences, and the disposal of used batteries can lead to pollution.

5. Performance: The performance of batteries can be affected by temperature, humidity, and other environmental factors. Improving battery performance in extreme conditions and increasing their durability is a priority for the industry.

Answer:

There are two moles HCl formed for each mole of Cl2, hence 2 x 0.141 = 0.282 moles HCl is produced. = 0.282 x (1.008 + 35.45) = 10.3 g. (1.)

One mole of aluminum oxide or Al₂O₃ is 102 g/mol  . It contains 54 g of Al metal. Thus, 25.5 tones of aluminum oxide contains 13.5 tones of Al. Therefore, the maximum mass of aluminum that can be extracted is 13.5 tones.

Aluminum is 13 the element in periodic table. It is an electropositive element and exhibit metallic properties. Aluminum easily forms its oxides by reacting with atmospheric oxygen.

The molar mass of aluminum oxide Al₂O₃ is 102 g/mol. The atomic mass of Al is 27 g/mol. Thus 102 g of Al₂O₃ contains 54 g of Al. Therefore, the mass of Al in 25.5 tones or 25.5 ×10⁶ g of Al₂O₃ is calculated as follows:

mass of Al = (25.5 ×10⁶ g × 54 g) / 102 g

                  = 13.5  ×10⁶ g = 13.5 tones.

Therefore, the maximum mass of aluminum that can be extracted is 13.5 tones

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The highest boiling point based on the data is option 4

Compared to alcohols of comparable molecular weight, carboxylic acids often have higher boiling temperatures. Between the hydrogen atoms of adjacent molecules and the oxygen in the carboxyl group of carboxylic acids, strong intermolecular hydrogen bonds can develop. Because it takes more energy to break the intermolecular interactions and change the substance from a liquid to a gas during boiling, these hydrogen bonds help materials have higher boiling temperatures.

Although carboxylic acids and alcohols are both capable of forming hydrogen bonds, carboxylic acids have higher boiling temperatures due to the extra carboxyl group that they contain.

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Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\\)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 1.505 × 10²³ Na atoms

We have

\(n = \frac{1.505 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{1}{4} \\ \)

We have the final answer as

Hope this helps you

Answer:

\(\Huge \boxed{x =\frac{4}{3} }\)

\(\rule[225]{225}{2}\)

Explanation:

\(3x+2=6\)

Subtracting 2 from both sides.

\(3x=4\)

Dividing both sides by 3.

\(\displaystyle x =\frac{4}{3}\)

\(\rule[225]{225}{2}\)

2 moles of \(O_{2}\) gas and 1 mole of \(NO_{2}\) gas would be produced from 2 moles of \(HNO_{3}\) during electrolysis.

What is an electrolysis?

Electrolysis of nitric acid using graphite electrodes would result in the following reactions at the anode and cathode:

At the anode (oxidation):

\(2HNO_{3}\) + 4 e- → \(O_{2}\) + \(2NO_{2}\) + \(2H_{2}O\)

At the cathode (reduction):

\(2H^{+}\) + 2 e- → \(H_{2}\)(g)

Overall reaction:

\(2HNO_{3}\) (aq) +\(2H^{+}\)(aq) + 4 e- →  \(O_{2}\)(g) + \(2NO_{2}\)(g) + \(2H_{2}O\)(l)

This means that for every 2 moles of nitric acid, 1 mole of \(O_{2}\) gas is produced. The products of the electrolysis are  \(O_{2}\) gas, \(NO_{2}\) gas, and \(H_{2}O\).

The concentration of the nitric acid (4 mol/L) indicates that there are 4 moles of \(HNO_{3}\) in 1 liter of solution. To calculate the number of moles of  \(HNO_{3}\) in a given volume of solution, we can use the following formula:

moles of solute = concentration × volume (in liters)

For example, if we have 500 mL (0.5 L) of the 4 mol/L nitric acid solution, the number of moles of \(HNO_{3}\) present would be:

moles of \(HNO_{3}\) = 4 mol/L × 0.5 L = 2 moles

Therefore, 2 moles of \(O_{2}\) gas and 1 mole of \(NO_{2}\) gas would be produced from 2 moles of \(HNO_{3}\) during electrolysis.

It's worth noting that the oxidation of nitric acid to form nitrogen dioxide is an exothermic reaction that can produce heat, so the electrolysis may need to be performed under controlled conditions to prevent overheating. Additionally, nitrogen dioxide is a toxic gas that should be handled with care in a well-ventilated area.

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Complete question is: An aqueous solution of 4mol/L nitric acid is electrolysed in an electronic cell using graphite electrodes produced 2 moles of \(O_{2}\) gas and 1 mole of \(NO_{2}\) gas from 2 moles of \(HNO_{3}\) during electrolysis.

Mia is a nanny for three small children their parents have laid out dinner, including broiled chicken tenders, broccoli, and steamed carrots when Mia puts the plates in front of them, one of the kids makes a face and announces, “I don’t eat broccoli!” then best way for Mia to respond is “Why don’t you at least take one bite?”

Here according to the given data mia is a nanny for three small children. their parents have laid out dinner, including broiled chicken tenders, broccoli, and steamed carrots when Mia puts the plates in front of them, one of the kids makes a face and announces, “I don’t eat broccoli!” then mia respond is “Why don’t you at least take one bite?” because mia is encouraging the small children to eat the broccoli because broccoli is the good for our health and it is packed with vitamins and minerals and it has a good source of calcium

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Answer:

Conduction

Explanation:

The handle is touching the pot.

And I got it wrong

Answer:

compound ahhhhhhhhhhhhhgh

Answer:

an aqueous solution of HNO3

✔ pH = 2.5

an aqueous solution of NaCl

✔ pH = 7

an aqueous solution of NaOH

✔ pH = 13

Explanation:

The answer is that the  pH will be <7 , =7 , >7 for the respective solutions.

pH is an expression of hydrogen ion concentration in water.

pH is the negative logarithm of hydrogen ion (H+) concentration (mol/L) in an aqueous solution:

pH = -log₁₀(H+)

The term is used to indicate basicity or acidity of a solution on a scale of 0 to 14, with pH 7 being neutral.

As the concentration of H⁺ ions in solution increases, acidity increases and pH gets lower, below 7

When pH is above 7, the solution is basic.

For the above solutions mentioned

1. An aqueous solution of HNO3

This will be an acidic solution so

pH < 7

2. An aqueous solution of NaCl

As NaCl is a salt therefore , it will be a neutral solution

pH=7

3. An aqueous solution of NaOH

This will be an alkaline solution

pH>7

Therefore the  pH will be <7 , =7 , >7 for the respective solutions.

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Answer:

39.119 g

Explanation:

1 mole of S has 32.065 g

=> 1.22 x 32.065 = 39.1193 or 39.119 g

B. silver tarnishing

Answer:

1) 0.261 M, 2) 0.662 M

Explanation:

1. We must calculate the molarity of 0.300 mol of Na₂S in 1.15 L of solution.

We know, Molarity = moles of solute/ volume of solution

= 0.300 mol/ 1.15 L
= 0.261 M

2. We must calculate the molarity of 34.7 g of MgS (56 u) in 935 mL of solution.

We know, Molarity = moles of solute/ volume of solution
Moles of MgS = 34.7/56 = 0.619
Volume of solution = 935 mL = 0.935 L

= 0.619 mol/ 0.935  L
= 0.662 M

The heat will flow from the system at 40°C to a system at 293 Kelvin.

If two systems at different temperatures have contact with each other, heat will flow from the system at 40°C to a system at 293 Kelvin because temperatures moves from hotter body to cold body.

We know that 293 kelvin is equals to 20° Celsius which is lower than 40° Celsius so the heat energy moves from the body having 40° Celsius temperature to the body having 293 kelvin temperature so we can conclude that the heat will flow from the system at 40°C to a system at 293 Kelvin.

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Answer: I was doing hw and this question is one of them

Explanation:

Answer:

Explanation:

Steps mention in question are as follow.

Step 1: 2A <----> B ( fast)

Step 2: B + C ----> D (slow)

Overall: 2A + C ----> D

The slowest step is as follows

2A <----> B

Since the rate law is written as concentrations of reactants raised to power their stoichiometric coefficient multiplied by rate constant. Thus, rate law for this reaction can be written as follow.

Answer: :)

The temperature of a gas is directly proportional to the average kinetic energy of the particles of the gas. But the total kinetic energy of the molecules of a gas is a measure of the internal energy or thermal energy of the gas.

Explanation:

Answer:

f = 8×10¹⁴ s

Explanation:

λ × f = c ⇒ f = c/λ

(c = speed of light [3×10⁸ m/s])

(λ = wavelength)

1. Convert 375 nm to meters in order to multiply by speed of light unit (m/s)

375 nm × \(\frac{1 meter}{10 ^{9} nm}\) = 3.75 × 10⁻⁷ m

2. Plug in converted wavelength to top equation

f = (3×10⁸ m/s)/(3.75 × 10⁻⁷ m)

f = 8×10¹⁴ s

Answer:  60 g/mban

Explanation:  I don't know what an "mban" is, but the density of this alien rock would be 60 grams/mban.  Density = Mass/Volume

Answer:

There are \(5.408\times 10^{22}\) grams contained in all the seawater in the world.

Explanation:

At first let is determinate the total mass of seawater (\(m_{sw}\)), measured in grams, in the world by definition of density and considering that mass is distributed uniformly:

\(m_{sw} = \rho_{sw}\cdot V_{sw}\)

Where:

\(\rho_{sw}\) - Density of seawater, measured in grams per liters.

\(V_{sw}\) - Volume of seawater, measured in liters.

If \(V_{sw} = 1.5\times 10^{21}\,L\) and \(\rho_{sw} = 1030\,\frac{g}{L}\), then:

\(m_{sw}=\left(1030\,\frac{g}{L} \right)\cdot (1.5\times 10^{21}\,L)\)

\(m_{sw} = 1.545\times 10^{24}\,g\)

The total mass of sodium chloride is determined by the following ratio:

\(r = \frac{m_{NaCl}}{m_{sw}}\)

\(m_{NaCl} = r\cdot m_{sw}\)

Given that \(m_{sw} = 1.545\times 10^{24}\,g\) and \(r = 0.035\), the total mass of sodium chloride in all the seawater in the world is:

\(m_{NaCl} = 0.035\cdot (1.545\times 10^{24}\,g)\)

\(m_{NaCl} = 5.408\times 10^{22}\,g\)

There are \(5.408\times 10^{22}\) grams contained in all the seawater in the world.

Following are the calculation to the total mass of sodium chloride in grams:

Given:

Seawater volume\(= 1.5 \times 10^{21}\ L\\\\\)

Seawater density \(= 1.03\ \frac{g}{mL}\\\\\)

\(\%\) of sodium chloride in seawater \(= 3.5\ \%\)

To find:

The total mass of sodium chloride in grams=?

Solution:

The total volume of seawater \(= 1.5 \times 10^{21}\ L= 1.5 \times 10^{24}\ mL\\\\\)

The density of seawater \(= 1.03 \frac{g}{mL}\)

\(\therefore\\\\\)

Seawater mass = Seawater volume \(\times\) density

                           \(= 1.5 \times 10^{24}\times 1.03 \ g\\\\= 1.545 \times 10^{24}\ g\\\\\)

\(\%\) of sodium chloride in seawater \(= 3.5\ \%\)

\(\therefore\\\\\)

Calculating the sodium chloride mass in Seawater:

\(= 3.5\% \ \ of\ \ 1.545 \times 10^{24} \ g\\\\ =\frac{3.5}{100} \times 1.545 \times 10^{24}\ g\\\\= 5.4075 \times 10^{22} \ g\\\\\)

Calculating the sodium chloride mass \(= 5.4075 \times 10^{22} \ g\\\\\)

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Answer:

B.0

Explanation:

Without the diagram or more information on the chemical reaction, it is not possible to provide a definitive answer to this question. The answer would depend on the specific equilibrium constant (K) for the reaction and the initial concentrations of the reactants and products.

However, based on the answer choices provided, the most likely answer would be (D) The amount of O2(g) will decrease, because >K-1. This is because if the initial concentrations of the reactants and products are not at equilibrium, the reaction will proceed in the direction that minimizes the reaction quotient (Q) and approaches the equilibrium constant (K). If Q < K, the reaction will proceed in the forward direction to increase the concentration of products and decrease the concentration of reactants, which would lead to a decrease in [O2(g)] and an increase in [O3(g)].

The amount of O\(_2\)(g) will decrease, because >K. - 1. Therefore, the correct option is option D.

During a reversible chemical process, chemical equilibrium is the state in which there is no net change in the quantity of reactants or products. When a chemical reaction is reversible, the products react with the original reactants as soon as they are created.

At this point, the reaction may well be deemed to be finished, meaning that the maximum amount of products and reactants has been converted under the given reaction conditions. The quantity of O\(_2\) will decrease as >K-1, (g) will drop. This is due to the fact that the reaction will go in a direction that reduces its reaction quotient (Q) therefore approach the equilibrium constant if the starting concentrations of a reactants and their byproducts do not reach equilibrium (K).

Therefore, the correct option is option D.

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The pressure inside the tire, converted to pascals, is approximately 8,555 N/m^2, or 8.56 × 10^3 Pa, using the appropriate number of significant figures.

To convert the pressure from pounds per square inch (psi) to pascals (Pa), we need to use the given conversion factors:

1 pound = 4.45 newtons

1 inch^2 = 6.45 centimeters^2 = (6.45/100)^2 square meters

First, let's convert psi to newtons per square inch (N/in^2):

28.0 psi * 4.45 N = 124.6 N/in^2

Now, let's convert newtons per square inch to pascals:

124.6 N/in^2 * ((6.45/100)^2) m^2 = 8,555.4125 N/m^2 (approximately)

To express the answer to the correct number of significant figures, we need to determine the number of significant figures in the given pressure value. Since the pressure is given as "28.0," it implies that there are three significant figures. Therefore, the pressure inside the tire, converted to pascals, is approximately 8,555 N/m^2, or 8.56 × 10^3 Pa, using the appropriate number of significant figures.

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Solids are the state of matter that is defined by the no spacing in particles. The two solids that look the same can be differentiated by electrical conductivity and solubility.

Electrical conductivity is one of the physical properties of matter that is fundamental and tells about the ability of the valence electron of the matter to move freely to carry the charge across the field. All solids are not conductors and hence can be used to compare.

Solubility is defined as the physical characteristic that allows the solids to get dissolved into solvents for the formation of the solutions. Some solids are insoluble while some are soluble and can be used to differentiate the two solids.

Therefore, electrical conductivity and solubility can be performed to contrast two solids.

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Answer:

protons: 6

neutrons: 8

electrons:6

Due to presence of impurities further purification is needed.

A further purification is needed of the final product because of the presence of impurities in the final product. Further purification can also be done in order to gain pure product. There are various ways and methods which can be used for the purification such as Sublimation, Crystallization, Distillation, Differential Extraction and Chromatography.

These methods can be used for further purification and helps in the extraction of pure solution of final product so we can conclude that due to presence of impurities further purification is needed.

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