For the following equation, write two more equations, using
:-11 + x=7
Type your answer here...

The value of x from the given equation is -9.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true.

The given equation is 7-3x=34

Transpose 7 to the other side of the given equation, we get

-3x=34-7

-3x=27

Transpose -3 to the other side of the given equation, we get

x= -27/3

x=-9

Therefore, the value of x is -9.

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Definition of Relation:

Let A and B be sets. A relation R from A to B is a subset of Ax B

Definition of Function:

A function f from a set A (domain) to a set B (codomain) is a relation that satisfies the following properties:

1) Every element in A there is an element y in B such that (x,y) F

2) For all elements z in A there exist a unique element y in B.

The cartesian product of the sets A (a, b) and B (r,y) is

A x B {(a,z) (a,y).(b,),(b,s)}

Step 2

1. T ((a,x), (a,y))

Since T-((a,z), (a,y)) is a subset of (a, b) x (x,y).

so T is a relation from (a,b) to (x,y).

But for the element a in domain, there exist two different images x and y in co-domain.

This violates the definition of function.

Therefore, T_{1} = \{(a, x), (a, y)\} is a relation but not a function.

Step 3

2. T_{2} = \{(b, x), (b, y)\}

Since T_{2} - \{(b, x), (b, y)\} is a subset of \{a, b\}\{x, y\} .

so T_{1} is a relation from \{a, b\} to \{x, y\}

But for the element b in domain, there exist two different images x and y in co-domain

This violates the definition of function

Therefore, T_{2} = \{(b, x), (b, y)\} is a relation but not a function.

Step 4

,T 1 =\ (a,z)\

Since 7-((a,z)) is a subset of \{a, b\}\{x, y\}

so Ty is a relation from \{a, b\} * to (x,y\

But the element & in domain does not map with any element in co-domain

This violates the definition of function

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Component 3 must be started on day 197 to meet the delivery date of day 200.

To illustrate the backward schedule, we need to start from the delivery date (day 200) and work our way backward, taking into account the lead times and dependencies of each operation.

(a) Backward schedule:

Operation    |  Work Center  |  Time (hours)  |  Start Day

--------------------------------------------------------

Final Assembly |   Work Center 1  |        1       |     200

Sub-assembly 1 |   Work Center 2  |        2       |     199

Component 4     |   Work Center 3  |        3       |     197

Component 2     |   Work Center 4  |        4       |     196

Component 3     |   Work Center 5  |        3       |     ????

(b) To identify when component 3 must be started to meet the delivery date, we need to consider its dependencies and lead times.

From the backward schedule, we see that component 3 is required for sub-assembly 1, which is scheduled to start on day 199. The time required for sub-assembly 1 is 2 hours, which means it should be completed by the end of day 199.

Since component 3 is needed for sub-assembly 1, we can conclude that component 3 must be started at least 2 hours before the start of sub-assembly 1. Therefore, component 3 should be started on day 199 - 2 = 197 to ensure it is completed and ready for sub-assembly 1.

Hence, component 3 must be started on day 197 to meet the delivery date of day 200.

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To solve the initial value problem y'' - 2y' - 3y = 0, with y(0) = 1 and y'(0) = 2, we can use the method of Laplace transforms.

First, we take the Laplace transform of the given differential equation to obtain an algebraic equation in terms of the Laplace transform of the unknown function y(t). Then, we solve the algebraic equation for the Laplace transform of y(t) using standard algebraic techniques. Finally, we take the inverse Laplace transform to obtain the solution y(t) in the time domain.

Applying the Laplace transform to the given differential equation, we have s²Y(s) - sy(0) - y'(0) - 2(sY(s) - y(0)) - 3Y(s) = 0, where Y(s) represents the Laplace transform of y(t). Simplifying this equation, we get (s² - 2s - 3)Y(s) - (s - 2) = s²Y(s) - 3s - 4. Rearranging the equation, we have Y(s) = (s - 2) / (s² - 2s - 3).

To solve this equation for Y(s), we can decompose the expression into partial fractions, which yields Y(s) = 1 / (s - 3) - 1 / (s + 1). Taking the inverse Laplace transform of Y(s), we obtain y(t) = e^(3t) - e^(-t), which is the solution to the initial value problem.

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Answer:

m∠C = 110.9° (1 dp)

Step-by-step explanation:

The largest angle in a triangle is opposite the longest side.

Therefore, from inspection of the diagram, angle C is the largest angle since length AB is the longest side length.

To find angle C, use the cosine rule:

\(\sf c^2=a^2+b^2-2ab \cos C\)

(where a, b and c are the sides, and C is the angle opposite side c)

Given:

Substituting the given values into the formula and solving for C:

\(\implies \sf c^2=a^2+b^2-2ab \cos C\)

\(\implies \sf 15^2=11^2+7^2-2(11)(7) \cos C\)

\(\implies \sf 225=170-154 \cos C\)

\(\implies \sf \cos C=\dfrac{225-170}{-154}\)

\(\implies \sf \cos C=-\dfrac{5}{14}\)

\(\implies \sf C=\cos ^{-1}\left(-\dfrac{5}{14}\right)\)

\(\implies \sf C=110.9248324...^{\circ}\)

Therefore, m∠C = 110.9° (1 dp)

Answer:

see photo for detailed analysis

Answer:

a.2×1= 2 + 3×1=3 +4×2=8 now we have to put this ans and the ans is 13.

b. 5×1×2=10 + 3×1×2=6+ 7×2×2=28 now also we have to put this ans and this ans is 13

Answer:

Apple: $2.50

Orange: $1.75

Step-by-step explanation:

Let A represent apples and Y represent Orange

We have equations

9A + 6Y = $33

18A  + 20 Y = $80

Let's find out the cost of oranges first. Multiply the first equation by -2

-18A - 12Y = $-66

18A + 20 Y = $80

8Y = $14

Y = $1.75

Now let's put 1.75 back in the Y to find the cost of apple

18A  + 20(1.75) = $80

18A + 35 = $80

18A = $45

A = $2.50

Answer:2 50

Step-by-step explanation:

Bill has a total of 3 one-piece jumpsuits, 5 pairs of work pants, and 8 work shirts. To find the number of possible outfits he can wear to work, we can use the multiplication principle.

First, we need to determine how many choices Bill has for his top and bottom. He can either wear a jumpsuit or a combination of pants and a shirt. Therefore, he has 3 + (5 x 8) = 43 choices for his top and bottom.

Next, we can use the multiplication principle to determine the total number of possible outfits he can wear. Since he has 43 choices for his top and bottom, and each outfit combination is independent of the others, we can multiply the number of choices for his top and bottom by the number of one-piece jumpsuits he has.

Therefore, Bill has a total of 43 x 3 = 129 possible outfits he can wear to work.

In summary, Bill has 3 one-piece jumpsuits, 5 pairs of work pants, and 8 work shirts. He can wear either a jumpsuit or pants and a shirt to work. Using the multiplication principle, we determined that he has a total of 129 possible outfits he can wear.

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If a line passes through a point , the it means that the point represents the solution of the equation .

An Equation is defined as a mathematical statement that is made up of two or more expressions which are connected by an equal sign .

If the graph of the equation passes through the point , then that point represents the solution of the equation .

Let us understand by an Example .

Let the equation be 3x + y = 0 ;

the graph of the given equation passes through the point (1,-3) ,

Therefore , the point (1,-3) is called as the solution of the equation .

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Answer:

92 I think because in my class I heard my friend tell me

The difference in their current ages is 18 years.

One of the most crucial mathematical operations, which is obtained by removing two integers, produces difference in mathematics. It reveals how much one number deviates from another. To determine how many numbers are between the two supplied numbers is the goal of finding the difference in math. One of the most crucial mathematical operations, which is obtained by removing two integers, produces difference in mathematics.

Let jack's current age is ab = 10a+b

Bill's current age is ba = 10b+a

After 5 years jack's age = 10a+b+5

after 5 years Bill's age = 10b+a+5

as per given

10a+b+5 = 2(10b+a+5)

a = (19b+5)/8

only solution is (a,b) = (3,1)

Difference in current age = (10*3+1) - (10*1+3)

= 18 years

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4 balls in each group.

Step-by-step explanation:

you just divide 20 by 5, or add 5 times until you get 20.

Answer:

5 group of 4 balls

Step-by-step explanation:

Red balls : 20

5 Gym baskets

20 - 5      15

15 divided by 5    3

3 divided by 20     0.15

0.15 divided by 5     0.03

0.03 x 15   0.45

0.45 x 55 24.75

24.75 - 4.75    20

20 divided by 5   4

Answer is 4

BRAINLIEST PLS

Adding the polynomials (6x^2y - 11xy - 10) and (-4x^2y + xy + 8) results in 2x^2y - 10xy - 2.

To add the polynomials, we combine like terms by adding the coefficients of the corresponding terms. The resulting polynomial will have the same degree as the highest degree term among the given polynomials.

Given polynomials:

(6x^2y - 11xy - 10) and (-4x^2y + xy + 8)

Step 1: Combine the coefficients of the like terms:

6x^2y - 4x^2y = 2x^2y

-11xy + xy = -10xy

-10 + 8 = -2

Step 2: Assemble the terms with the combined coefficients:

The combined polynomial is 2x^2y - 10xy - 2.

Therefore, the sum of the given polynomials is 2x^2y - 10xy - 2. The degree of the resulting polynomial is 2 because it contains the highest degree term, which is x^2y.

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Manuel will attend the quarter in 9 weeks.

Given,

In the question:

Total taken quizzes is 90

Manuel took a total of 20 quizzes over the course of 2 weeks.

To find the how many weeks of school will Manuel have to attend this quarter ?

Now, According to the question:
Based on the given conditions :

Formulate:

Let the no. of weeks be x

Total quizzes = 90

Here, The relationship is directly proportional.​

20/2 = 90/x

If the fraction is defined, the denominator cannot be equal 0.

Solve the equation:

10 = 90/x

10x = 90

x = 9

Hence, Manuel will attend the quarter in 9 weeks.

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Answer:

b. MNL, NPM, and LMP

Explanation:

Since the rest of the choices include a no-M-point arc, choice b is the most reasonable.

Answer:

Option B

Step-by-step explanation:

In Option B, All the arcs contain the point M and all of them are major arcs. While in other options, there are some minor arcs as well as those arcs which don't contain the point M.

The statement "If the conclusion of an argument is a tautology, then the counterexample set of that argument must be inconsistent" is true.

Let's understand why?

Explanation:

An argument with a tautology conclusion is an argument that arrives at a conclusion that is always true, regardless of the truth values of the premises. In other words, it is impossible for the premises to be true while the conclusion is false.

This means that any attempt to find a counterexample that disproves the conclusion will always fail, as there is no possible scenario in which the conclusion is false.

The counterexample set of an argument is the set of all possible scenarios in which the premises are true but the conclusion is false. If the conclusion is a tautology, then there is no possible scenario in which the conclusion is false, and thus the counterexample set is empty. An empty counterexample set is equivalent to an inconsistent counterexample set, as it means that there is no consistent scenario in which the conclusion is false.

Therefore, if the conclusion of an argument is a tautology, then the counterexample set of that argument must be inconsistent.

Hence, the statement is true.

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The probability that the number of homicide deaths for a randomly selected day is:

a) 0: 0.18,

b) 1: 0.35,

c) 2: 0.27

The Poisson distribution is used to simulate the likelihood that a certain number of events will occur within a predetermined window of time or space.

In this instance, the Poisson distribution can be used to simulate the number of homicide deaths that occurred in Richmond, Virginia over the course of a year.

The Poisson distribution can be used to determine the likelihood of 0, 1, and 2 homicides happening on any given day.

One homicide occurs on a randomly chosen day with a 0.18 percent chance, one homicide occurs on a randomly chosen day with a 0.35 percent chance, and two homicides occur on a randomly selected day with a 0.27 percent chance.

Complete Question:

In one year, there were 116 homicide deaths in Richmond, Virginia. Using the Poisson distribution, find the probability that the number of homicide deaths for a randomly selected day is:

a) 0

b) 1

c) 2

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The expected number of customers in the system is 0.96.

Given that the arrivals to the drive-up teller window occur at a rate of 0.4 customers per minute, and the service times are exponentially distributed, we can use queuing theory to determine the operating characteristics of the system.

What is the expected number of customers waiting in line?

We can use the queuing formula Lq = (λ^2) / (μ(μ-λ)), where λ is the arrival rate and μ is the service rate. Here, λ = 0.4 and μ is the reciprocal of the average service time, which we need to calculate.

Assuming the bank tellers can serve customers in an average of 2 minutes, then μ = 1/2 = 0.5.

Plugging these values into the formula, we get:

Lq = (0.4^2) / (0.5(0.5-0.4)) = 0.16 customers

Therefore, the expected number of customers waiting in line is 0.16.

What is the expected time a customer spends in the system?

We can use the queuing formula W = (1/μ) + (Lq/λ), where μ is the service rate and λ is the arrival rate, and Lq is the expected number of customers waiting in line.

Using the same values of λ and μ as before, we can calculate Lq as 0.16 customers. Plugging these values into the formula, we get:

W = (1/0.5) + (0.16/0.4) = 2.4 minutes

Therefore, the expected time a customer spends in the system is 2.4 minutes.

What is the expected number of customers in the system (i.e., both waiting and being served)?

We can use the queuing formula L = λW, where λ is the arrival rate and W is the expected time a customer spends in the system.

Plugging in the values of λ and W that we calculated earlier, we get:

L = 0.4 x 2.4 = 0.96 customers

Therefore, the expected number of customers in the system is 0.96.

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Answer:

9.3. your ans. nabsbss

To meet the stopping sight distance (SSD) requirements for a highway section with a grade change, the minimum length of the equal tangent vertical curve needs to be determined.

Given the design speed of 65 mph, the height of eye and height of the object, and the grades of +(X4/2)% and -(X3/2)%, the minimum curve length can be calculated based on the AASHTO Guidelines.

The minimum length of the equal tangent vertical curve can be determined using the formula:

L = [(V^2 * f) / (30 * g * (H + h))]

Where:

L = Length of the curve

V = Design speed in ft/s

f = Rate of grade change in percentage (difference between the two grades)

g = Acceleration due to gravity (32.17 ft/s^2)

H = Height of eye

h = Height of object

By substituting the given values and solving the equation, the minimum length of the curve can be calculated to meet the SSD requirements.

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The total sum of the squares is the sum of residual sum of squares and the explained sum of squares.

Simple regression analysis means that there is 1 dependent variable and 1 independent variable.

In this, there is 3 types of sum of squares:

They are related to each other as:

TSS = RSS + ESS

That is the total sum of the squares will be equal to the residual sum of squares plus the explained sum of squares.

Therefore, we get that, the total sum of the squares is the sum of residual sum of squares and the explained sum of squares.

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Answer:

20-12= x

8=x

x=8

Step-by-step explanation:

I think check once to confirm tho

Answer:

8

Step-by-step explanation:

20 = x + 12                           Subtract 12 from both sides to get x on it's own.

20-12= x                               Simplify

8 = x

x = 8                                     Here is your answer!

Hope this helps,

Please mark me the brainliest!

Answer:

The Answer is 34 Feet

Step-by-step explanation:

If you do 50 minus 16 you get 34. Add a negative sign and there you go.

a). The distance between A and C is derived to be 42° to the nearest degree.

b). The bearing of the point C with respect to A is equal to 72°

Bearing is usually measured in degrees, with 0° indicating the reference direction (usually North), and increasing clockwise to 360°. It refers to the direction or angle between a reference direction and a point or object.

Let ∆ABC be the triangle formed with bearings so that:

angle B = 30° + 90° + 15°

angle B = 135°

AB = 20km

BC = 25km

a). The distance between A and C is calculated using the cosine rule as follows:

AC² = 20² + 25² - 2(20)(25)cos135° {cosine rule}

AC² = 1025 + 707.1068

AC = √1732.1068 {take square root of both sides}

AC = 41.6186 approximately 42°

b). The bearing of the point C with respect to A is the angle from the north of A to the line AC, so;

bearing of the point C with respect to A = 30° + 42° = 72°

Therefore, the distance between A and C is derived to be 42° to the nearest degree and the bearing of the point C with respect to A is equal to 72°

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Answer:

Time taken by the ball to reach the maximum height = 5/32 seconds

Step-by-step explanation:

To find the time at which maximum height is reached , we will differentiate the given equation  with respect to t

\(\frac{db_{(t)}}{dt} = -32t + 5 = 0\\t = \frac{5}{32} \\\)

Substituting this value of t in formula of b(t), we get

\(-16 * (\frac{5}{32})^2 + 5 * \frac{5}{32} + 15 \\= 15.390\)

Option C and Option D has infinite number of solutions

Option A: -2(x - 2) + 3x = x - 4

Simplify the equation;

-2x + 4 + 3x = x - 4

x + 4 = x - 4

LHS ≠ RHS

Thus, equation does not have infinite solutions.

Option B: 2x + 4(x - 1) = 3(2x + 1) - 2(x - 1)

Simplify the equation;

2x + 4x - 4 = 6x + 3 - 2x + 2

6x - 4 = 4x + 5

6x - 4x = 5 + 4

2x = 9

Obtained equation has only one solution.

Thus, equation does not have infinite solutions.

Option C: 3x + 2(x - 2) + 6 = 2(2x + 3) + x - 4

Simplify the equation;

3x + 2x - 4 + 6 = 4x + 6 + x - 4

5x + 2 = 5x + 2

LHS =RHS

Thus, this equation has infinite solutions.

Option D: 4(x + 2) + x + 1 = 2x - 3 + 3(x + 4)

Simplify the equation;

4x + 8 + x + 1 = 2x - 3 + 3x + 12

5x + 9 = 5x + 9

LHS =RHS

Thus, this equation has infinite solutions.

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The correct question is-

Which equations have an infinite number of solutions?

Select all that apply.

A -2(x - 2) + 3x = x - 4

B 2x + 4(x - 1) = 3(2x + 1) - 2(x - 1)

C 3x + 2(x - 2) + 6 = 2(2x + 3) + x - 4

D 4(x + 2) + x + 1 = 2x - 3 + 3(x + 4)